I'm learning Cypress and for that purpose I am using this site: automationpractice.com.
Scenario: Sign up. In the sign up form the app validate the email (1) then it is redirected to another form (2).
In this flow, Cypress throws the following error:
CypressError: Cypress detected a cross origin error happened on page load:
> Blocked a frame with origin "http://automationpractice.com" from accessing a cross-origin frame.
Before the page load, you were bound to the origin policy:
> http://automationpractice.com
A cross origin error happens when your application navigates to a new URL which does not match the origin policy above.
I don't know why of this error, the form 2 is not inside an iframe, is the same url. Anyone knows?
Trying to fix it, "chromeWebSecurity": false was added to cypress.json. Then, after "Register an Account" button is clicked the second form is loaded inside cypress viewport but cypress changes the url to http://automationpractice.com/__/#account-creation, so the form disappears and the fields are not located.
I suppose that avoiding that cypress change the url I can solve this issue. But, I couldn't find any related in the documentation. Anyone knows how to solve it?
// test.spec.js
context('Cypress Training', () => {
beforeEach(() => {
cy.visit('http://automationpractice.com/index.php?controller=authentication&back=my-account')
})
it('Register user', () => {
const email = 'test#test.test.test';
// form 1
cy.get('#email_create').type(email)
cy.get('#SubmitCreate').click();
// form 2
cy.wait(3000)
cy.get('#id_gender1').click()
})
})
The solution is here: https://github.com/cypress-io/cypress/issues/7402
You have to upgrade cypress to version 4.6.0 and add
{
"experimentalSourceRewriting": true
}
to cypress.json
Related
I am new to using Cypress for web automation. I am still scouring through the internet looking for answers to this but I cannot find a solution that works for me.
This is what I'm trying to do in my test:
User clicks a link.
A new tab is opened and a windows prompt appears, requesting user input (username, password). (Since Cypress doesn't allow opening new tabs, I've removed the target attribute.)
Upon logging in successfully, the page has a download button.
User clicks on the download button.
The first struggle - I could not enter values into the windows prompt. In the below code, I was trying to see if the 'Sign In' button on the windows prompt would be clicked, but it was not.
cy.window().then(win => {
cy.get('#documentPassword').then((finalPassword) => {
const stub =cy.stub(win, 'prompt')
stub.returns('test')
cy.get('button#signin').click()
})
})
I got an Assertion Error: Timed out retrying after 25000ms: Expected to find element: button#signin, but never found it.
After no luck with this, I moved on to another suggestion.
The second struggle - I tried putting the username and password into the link, like this: https://username:password#mytestingwebsite.com. Just to note, when I paste the link manually into a browser, it works. To test this out, this what I had done:
cy.visit('https://mailtrap.io')
// ...other steps
cy.forceVisit('https://username:password#mytestingwebsite.com')
I added a custom command forceVisit to the commands.js file:
Cypress.Commands.add('forceVisit', url => {
cy.window().then(win => {
return win.open(url, '_self');
});
});
The result is the second url does not load.
Hoping for any insight from you guys. Thanks in advance.
This works for me:
cy.visit('https://mytestingwebsite.com', {
auth: {
username: 'username',
password: 'password'
}
})
This didn't work for me the first time I tried it because I still passed the credentials in the url.
This is my code
i have set up the client ID correctly
once I click a button with id 'buttonDiv', a pop is shown, if no user account exists, i am asked to login, once i login, i have to choose the email to authenticate with, but i get a blank white space instead
import { Box, Button, Typography } from '#mui/material';
import Divider from 'components/Divider';
function handleCredentialResponse(response) {
console.log("Encoded JWT ID token: " + response.credential);
}
function GoogleComponent({ action, isLoginPage }) {
const classes = useStyles();
window.onload = function () {
window.google.accounts.id.initialize({
client_id: process.env.REACT_APP_CLIENT_ID,
callback: handleCredentialResponse,
scope: 'email',
ux_mode: 'popup',
});
window.google.accounts.id.renderButton(
document.getElementById("buttonDiv"),
{ theme: "outline", size: "large" } // customization attributes
);
window.google.accounts.id.prompt(); // also display the One Tap dialog
}
return (
<Box className={classes.box}>
<div id="buttonDiv"></div>
</Box>
);
}
export default GoogleComponent;
when I change the ux_mode: 'redirect' it works but that's not how I want it.
I need a pop up to return a code and then use the code to make a post request to the backend API
I have added the http://localhost and http://localhost:3000 to the authorised domains on the cloud console.
what could I be missing?
You will need to set the HTTP Cross-Origin-Opener-Policy to same-origin-allow-popups. It is most likely set to same-origin right now.
Source: https://developers.google.com/identity/gsi/web/guides/get-google-api-clientid#cross_origin_opener_policy
Try looking at the console of the blank popup window (right-click -> Inspect -> Console). It might offer some insights on the reason for its failure to render.
For example, I get "[GSI_LOGGER]: The given origin is not allowed for the given client ID". Your problem is probably something else because 'redirect' works for you (for me it fails with same error), but at least an error might point you in the right direction.
if you are using localhost add http://localhost without port to your Google's client key Authorized JavaScript origins.
I need to run my custom protocol twice but it doesn't work the second time, I got this error ( Not allowed to launch 'cutomProtocol' because user gesture is required. ) I tried to find a solution but I did not find any!
Same problem with chrome, firefox and edge.
I need to see this popup twice
window.location.href = 'my-protocol://${base64}';
and
customProtocolVerify(
`my-protocol://${base64}`,
() => {
// successCb: Callback function which gets called when custom protocol is found.
console.log('My protocol found and opened the file successfully..');
},
() => {
// failCb: Callback function which gets called when custom protocol not found.
console.log('My protocol not found.');
}
);
I tried with these two and didn't work
Clarification
I have a custom protocol.
My scenario:
check if it's installed successfully (I'm using customProtocolVerify method) and that method makes the launch if the protocol is found
run some APIs
launch the protocol again
My problem:
Step 3 doesn't work, I have the error on the console that says " Not allowed to launch... " and of course I can't see my popup to open my protocol.
I'm asking for help to make step 3 work
The only way to bypass this "bug" is to ask the user twice (or in a loop) by showing a OK alert or some sort of user confirm box.
My solution:
OpenLinkInExternalApp(Link);
alerty.alert('', { title: '', okLabel: 'Open Link' }, function () {
OpenLinkInExternalApp(Link);
});
The above code will open the external app, then a OK alert will pop up, after clicking OK, I call the same code again. Do this in a loop if needed.
TIP:
We guide our users to use split screen at this stage. This is where users can dock your web-app on the left and the external app on the right as an example.
Alert Box:
We user Alerty.js https://github.com/undead25/alerty#readme
I have a Cypress test which clicks on an image causing a redirect to a specific url. The test then checks the url contains a specific string.
However, clicking this image causes the tests to stop/fail with a "Whoops, there is no test to run." message when the redirect happens.
The Cypress test is very simple:
/* global describe, it, cy */
import loadStory from '../../../config/cypress/helpers/loadStory'
const component = 'product-card'
const productCardImage = '[data-test=component-product-card_imageContainer]'
describe(`${component} component interaction tests`, () => {
it('clicking the image should open the products page', () => {
loadStory(component, 'Default')
cy.get(productCardImage).should('be.visible')
cy.get(productCardImage).click()
cy.url().should('contain', '/product')
})
})
My tests run on http://localhost:9002 and it seems that redirecting to http://localhost:9002/product/productId while the test suit is running is what causes Cypress to crash/fail and instead Cypress tries to go to https://localhost:9002/__/
I am wondering how I can click this image and redirect to the url without causing this crash/fail in Cypress.
Cross domain is not supported in Cypress.
Example:
step 1: You navigate to google
step 2: Search for Gmail
step 3: clicked on gmail link
You are switching from Google.com to gmail.com - cypress doesn't support this.
Workaround 1:
You can remove set href attribute value to blank as below:
target="_blank"
so that it will open in same page.
Workaround 2:
put step 1 and step 2 in one test iteration
and put step 3 in another iteration
Their is an issue of http to https.
I have an error related to CORs for a test deployment of OpenCPU, which may get its own question, but for now I'd like it to fail without notifying the end user via a popup - is this possible?
The error I see in the browser console is due to the website swapping TLD as you navigate:
XMLHttpRequest cannot load http://104.XX.3.XX/ocpu/library/predict/R/. The 'Access-Control-Allow-Origin' header has a value 'http://www.XXXX.com' that is not equal to the supplied origin. Origin 'http://www.XXXX.dk' is therefore not allowed access.
And a popup appears:
I'd like to ensure if there are possible future errors it doesn't detract for the user experience - in this case OpenCPU is used for a non-essential function of the website.
Found via a non-specific to OpenCPU question
// suppress alerts
window.alert = function ( text ) { console.log( 'tried to alert: ' + text ); return true; };