Difference between two times (not dates) in format (hh:mm) - javascript

For example I have these two times as string:
Time_A = "07:35" (means 7 hours and 35 minutes)
Time_B = "15:00" (means 15 hours and 00 minutes)
Now I would like to substract the Time_B from Time_A. This should return "-07:25" (means minus 7 hours and 25 minutes) Therefore I tried using the following function:
function time_diff(Time_A,Time_B ) {
var t1parts = t1.split(':');
var t1cm = Number(t1parts[0]) * 60 + Number(t1parts[1]);
var t2parts = t2.split(':');
var t2cm = Number(t2parts[0]) * 60 + Number(t2parts[1]);
var hour = Math.floor((t1cm - t2cm) / 60);
var min = Math.floor((t1cm - t2cm) % 60);
return (hour + ':' + min + ':00');
}
But this function is returning: -8:-25:00 instead of -07:25:00. Any idea how to fix this?

It's because you are rounding a negative number down:
Math.floor(-455/60) = Math.floor(-7.4166667) = -8
You could do:
var diff = Math.abs(t1cm - t2cm);
var hour = Math.floor(diff / 60);
var min = diff % 60;
return (t1cm < t2cm ? '-' : '') + hour + ':' + min + ':00';

Related

Time to Seconds and Seconds to Time in Javascript

I have My Code below,
Before=document.getElementsByName("beforehr[]");
After=document.getElementsByName("afterhr[]");
MonthTotal=0
for(i=0;i<Before.length;i++){
BeforeInSeconds= // Convert Before[i].value to Seconds
AfterInSeconds= // Convert After[i].value to Seconds
MonthTotal=parseInt(MonthTotal)+ parseInt(BeforeInSeconds)+parseInt(AfterInSeconds);
}
MonthTotalHRS= // Convert MonthTotal value to Time
document.getElementById("txtMonthTotal").value=MonthTotal;
document.getElementById("Mthtotal").innerHTML=MonthTotalHRS;
I need to convert the Before Hours to Seconds, After Hours to Seconds, sum All the Seconds and convert to Time and put it into Mthtotal
Assuming that variables Before and After are arrays.
var Before = [1, 2]; //180 Secs
var After = [3, 4]; // 420 Secs
var MonthTotal=0;
function secondsToHms(d) { // Function to convert Secs to H:m:s
d = Number(d);
var h = Math.floor(d / 3600);
var m = Math.floor(d % 3600 / 60);
var s = Math.floor(d % 3600 % 60);
var hDisplay = h > 0 ? h + (h == 1 ? " hour " : " hours ") : "";
var mDisplay = m > 0 ? m + (m == 1 ? " minute " : " minutes ") : "";
var sDisplay = s > 0 ? s + (s == 1 ? " second" : " seconds") : "";
return hDisplay + mDisplay + sDisplay;
}
for(i=0;i<Before.length;i++)
{
BeforeInSeconds= Before[i] * 60;
AfterInSeconds= After[i] * 60;
MonthTotal=parseInt(MonthTotal)+ parseInt(BeforeInSeconds)+parseInt(AfterInSeconds);
}
console.log(MonthTotal); //600 Secs
var convertedop=secondsToHms(MonthTotal);
alert(convertedop);
You can use .split(':') to split up your time format into an array. Where index 0 is the hour, index 1 is the minutes and index 2 is the seconds. You can then convert each time unit into seconds.
Hours to seconds: hour*3600
Minutes to seconds: minutes*60
Seconds to seconds: seconds*1 so just seconds
Doing all of this will give you your total result:
var before = [...document.getElementsByName("beforehr[]")];
var after = [...document.getElementsByName("afterhr[]")];
var monthTotal = 0
for (i = 0; i < before.length; i++) {
var beforeTime = before[i].value.split(':');
var afterTime = after[i].value.split(':');
var hourSeconds = +beforeTime[0] * 3600; // Convert the hours to seconds
var minuteSeconds = +beforeTime[1] * 60; // Convert the mins to secs
var seconds = +beforeTime[2]; // No conversions needed for secs to secs
var beforeInSeconds = hourSeconds + minuteSeconds + seconds;
// The above can be compresed into one line. I'll repeat the above for the afterTime on one line as an example:
var afterInSeconds = (+afterTime[0] * 3600) + (+afterTime[1] * 60) + (+afterTime[2])
monthTotal += parseInt(beforeInSeconds) + parseInt(afterInSeconds);
}
console.log("Month total in seconds", monthTotal)
// Hours, minutes and seconds (round down)
var hrs = ~~(monthTotal / 3600);
var mins = ~~((monthTotal % 3600) / 60);
var secs = ~~monthTotal % 60;
console.log("Month total in H:M:S", hrs +':' +mins + ':' + secs);
<input type="text" value="1:0:0" name="beforehr[]" />
<input type="text" value="1:0:0" name="beforehr[]" />
<br />
<input type="text" value="4:0:0" name="afterhr[]" />
<input type="text" value="4:0:0" name="afterhr[]" />
Also, note the unary + operator is similar to parseInt (it acts a little differently however).
The ~~ is simply just a fancy way of saying Math.floor(number)
Solution Simplified
<script>
function CalOt(){
Before=document.getElementsByName("beforehr[]");
After=document.getElementsByName("afterhr[]");
TodayOt=document.getElementsByName("txtTodayOt[]");
MonthTotal=0
for(i=0;i<Before.length;i++){
//alert(TimetoSec(Before[i].value));
BeforeInSeconds=TimetoSec(Before[i].value); //Convert Before[i].value to Seconds
AfterInSeconds=TimetoSec(After[i].value);//Convert After[i].value to Seconds
Daytot=parseInt(BeforeInSeconds)+parseInt(AfterInSeconds);
TodayOt[i].value=SecToTime(Daytot);
MonthTotal=parseInt(MonthTotal)+parseFloat(Daytot);
}
MonthTotalHRS=SecToTime(MonthTotal);// Convert MonthTotal value to Time
document.getElementById("txtMonthTotal").value=MonthTotal;
document.getElementById("Mthtotal").innerHTML=MonthTotalHRS;
}
function TimetoSec(Time){
TimeSplit=Time.split(":");
HoursSeconds=TimeSplit[0]*60*60;
Minutes=TimeSplit[1]*60;
TotalSec=parseFloat(HoursSeconds)+parseFloat(Minutes)+parseFloat(TimeSplit[2]);
console.log(TotalSec+"\n");
return TotalSec;
}
function SecToTime(Seconds){
Hr=Math.floor(Seconds/(60*60));
Mn=Seconds % (60*60);
Min=Math.floor(Mn/(60));
Sec=Mn % (60);
return Hr+":"+Min+":"+Sec;
}
</script>

Converting Float to Time in Javascript

I am having a three String or Float values say 9.30, 8.00 and 0.40 as Total_hour, Paid_hour, Extra_hour
These should be actually 9 hours 30 minutes, 8 hours 0 minutes, 0 hours 40 minutes.
Question 1) How to convert 9.30 to 9 hours 30 minutes
Question 2) Later want to Subtract and get Remaining Hour = Total_hour-Paid_Hour-Extra_hour
Later the answer Remaining Hour should be in float
This should work.
You just need to convert to ms:
let timefloat = 9.3;
function convertToMs(timefloat) {
// Get the minutes portion
let remainder = timefloat % 1;
// Convert into ms
let minutes = remainder * 100 * 60 * 1000;
// Get the number of hours and convert to ms
let hours = (timefloat - remainder) * 60 * 60 * 1000;
return minutes + hours;
}
// Convert back to float format
function convertToFloat(date) {
let hours = date.getUTCHours();
let mins = date.getUTCMinutes();
return hours + (mins / 100);
}
// Log the result
console.log(new Date(convertToMs(9.3)).toUTCString());
console.log(new Date(convertToMs(8.0)).toUTCString());
console.log(new Date(convertToMs(9.3) - convertToMs(8.0)).toUTCString());
let diff = convertToMs(9.3) - convertToMs(8.0);
console.log(convertToFloat(new Date(diff)))
The following javascript snippet converts a given float to hours and minutes. Source float to time
function convertNumToTime(number) {
// Check sign of given number
var sign = (number >= 0) ? 1 : -1;
// Set positive value of number of sign negative
number = number * sign;
// Separate the int from the decimal part
var hour = Math.floor(number);
var decpart = number - hour;
var min = 1 / 60;
// Round to nearest minute
decpart = min * Math.round(decpart / min);
var minute = Math.floor(decpart * 60) + '';
// Add padding if need
if (minute.length < 2) {
minute = '0' + minute;
}
// Add Sign in final result
sign = sign == 1 ? '' : '-';
// Concate hours and minutes
time = sign + hour + ':' + minute;
return time;
}
console.log(convertNumToTime(11.15));
Output
11:09
First convert the number in minutes and then do your subtraction. Then convert your output to hours.
var Total_hour = '9.30',
Paid_hour = '8.00',
Extra_hour = '0.40';
var conversionInMinutes = hour => Math.floor(hour) * 60 + (hour - (Math.floor(hour))) * 100;
var conversionInHours = min => Math.floor( min/60 ) + min % 60 / 100;
var Remaining_hour = conversionInMinutes(Total_hour) - conversionInMinutes(Paid_hour) - conversionInMinutes(Extra_hour);
console.log(conversionInHours(Remaining_hour).toFixed(2));
function doTime(input)
{
input = input.toString()
inputs = input.split(".")
return (inputs[0] + "Hour and" + inputs[1] + "minutes")
}
doTime("9:22")
function substract2
function subtract2(a , b){
a = input.toString()
arrayA = input.split(".")
b = input.toString()
arrayB = input.split(".")
h = parseInt(arrayB[0]) - parseInt(arrayA[0])
h <0 ? h+=12/*or 24*/ :h=h
m = parseInt(arrayB[1]) - parseInt(arrayA[1])
if(m<0){h-- ; m+=60}
return h.toString() + ":" + m.toString()
}

String to date conversion not working correctly in Javascript

I need to get time difference in this format: "HH:MM:SS" using a Javascript.
I have tried this:
var diff = Date.parse( time2) - Date.parse( time1 );
var total_time = (diff / 1000 / 60 / 60) + ":" + (diff / 1000 / 60) + ":" + (diff / 1000);
and this:
var diff = new Date( time2) - new Date( time1 );
var total_time = (diff / 1000 / 60 / 60) + ":" + (diff / 1000 / 60) + ":" + (diff / 1000);
These are the values of time2 and time1:
time1: "2012-11-07 15:20:32.161"
time2: "2012-11-07 17:55:41.451"
And result I am getting in both cases is:
total_time= 0.5250819444444444:31.504916666666666:1890.295
Which you can see is not correct
I think you are getting wrong diff value because of the millisecond part in the date delimited by .. Its not being accepted correctly by the data parser.
Try using the date and time part excluding the milliseconds as below:
var diff = Date.parse(time2.split(".")[0]) - Date.parse( time1.split(".")[0]);
Also while you are getting wrong difference diff, your time computation is also wrong.
It should be:
var second = Math.floor(diff /1000);
//convert the seconds into minutes and remainder is updated seconds value
var minute = Math.floor(second /60);
second = second % 60;
//convert the minutes into hours and remainder is updated minutes value
var hour = Math.floor(minute/60);
minute = minute %60;
var total_time= hour+":" minute+":"+second;
You forgot to remove the number of milliseconds you already calculated from diff. Here is a very verbose example on how you do it in a propper way.
var time1 = "2012-11-07 15:20:32.161",
time2 = "2012-11-07 17:55:41.451",
SECOND = 1000,
MINUTE = SECOND* 60,
HOUR = MINUTE* 60;
var diff = new Date(time2) - new Date(time1);
var hours = Math.floor(diff / HOUR); // Calculate how many times a full hour fits into diff
diff = diff - (hours * HOUR); // Remove hours from difference, we already caluclated those
var minutes = Math.floor(diff / MINUTE); // Calculate how many times a full minute fits into diff
diff = diff - (minutes * MINUTE); // Remove minutes from difference
var seconds = Math.floor(diff / SECOND); // As before
diff = diff - (seconds * SECOND);
var rest = diff;
var total_time = hours + ":" + minutes + ":" + seconds + " " + rest ;
DEMO

How to convert seconds to DD:HH:MM:SS [duplicate]

How can I convert seconds to an HH-MM-SS string using JavaScript?
You can manage to do this without any external JavaScript library with the help of JavaScript Date method like following:
const date = new Date(null);
date.setSeconds(SECONDS); // specify value for SECONDS here
const result = date.toISOString().slice(11, 19);
Or, as per #Frank's comment; a one liner:
new Date(SECONDS * 1000).toISOString().slice(11, 19);
Updated (2020):
Please use #Frank's one line solution:
new Date(SECONDS * 1000).toISOString().substring(11, 16)
If SECONDS<3600 and if you want to show only MM:SS then use below code:
new Date(SECONDS * 1000).toISOString().substring(14, 19)
It is by far the best solution.
Old answer:
Use the Moment.js library.
I don't think any built-in feature of the standard Date object will do this for you in a way that's more convenient than just doing the math yourself.
hours = Math.floor(totalSeconds / 3600);
totalSeconds %= 3600;
minutes = Math.floor(totalSeconds / 60);
seconds = totalSeconds % 60;
Example:
let totalSeconds = 28565;
let hours = Math.floor(totalSeconds / 3600);
totalSeconds %= 3600;
let minutes = Math.floor(totalSeconds / 60);
let seconds = totalSeconds % 60;
console.log("hours: " + hours);
console.log("minutes: " + minutes);
console.log("seconds: " + seconds);
// If you want strings with leading zeroes:
minutes = String(minutes).padStart(2, "0");
hours = String(hours).padStart(2, "0");
seconds = String(seconds).padStart(2, "0");
console.log(hours + ":" + minutes + ":" + seconds);
I know this is kinda old, but...
ES2015:
var toHHMMSS = (secs) => {
var sec_num = parseInt(secs, 10)
var hours = Math.floor(sec_num / 3600)
var minutes = Math.floor(sec_num / 60) % 60
var seconds = sec_num % 60
return [hours,minutes,seconds]
.map(v => v < 10 ? "0" + v : v)
.filter((v,i) => v !== "00" || i > 0)
.join(":")
}
It will output:
toHHMMSS(129600) // 36:00:00
toHHMMSS(13545) // 03:45:45
toHHMMSS(180) // 03:00
toHHMMSS(18) // 00:18
As Cleiton pointed out in his answer, moment.js can be used for this:
moment().startOf('day')
.seconds(15457)
.format('H:mm:ss');
Here's a simple function for converting times that might help
function formatSeconds(seconds) {
var date = new Date(1970,0,1);
date.setSeconds(seconds);
return date.toTimeString().replace(/.*(\d{2}:\d{2}:\d{2}).*/, "$1");
}
This does the trick:
function secondstotime(secs)
{
var t = new Date(1970,0,1);
t.setSeconds(secs);
var s = t.toTimeString().substr(0,8);
if(secs > 86399)
s = Math.floor((t - Date.parse("1/1/70")) / 3600000) + s.substr(2);
return s;
}
(Sourced from here)
var timeInSec = "661"; //even it can be string
String.prototype.toHHMMSS = function () {
/* extend the String by using prototypical inheritance */
var seconds = parseInt(this, 10); // don't forget the second param
var hours = Math.floor(seconds / 3600);
var minutes = Math.floor((seconds - (hours * 3600)) / 60);
seconds = seconds - (hours * 3600) - (minutes * 60);
if (hours < 10) {hours = "0"+hours;}
if (minutes < 10) {minutes = "0"+minutes;}
if (seconds < 10) {seconds = "0"+seconds;}
var time = hours+':'+minutes+':'+seconds;
return time;
}
alert("5678".toHHMMSS()); // "01:34:38"
console.log(timeInSec.toHHMMSS()); //"00:11:01"
we can make this function lot shorter and crisp but that decreases the readability, so we will write it as simple as possible and as stable as possible.
or you can check this working here:
I think the most general (and cryptic) solution could be this
function hms(seconds) {
return [3600, 60]
.reduceRight(
(pipeline, breakpoint) => remainder =>
[Math.floor(remainder / breakpoint)].concat(pipeline(remainder % breakpoint)),
r => [r]
)(seconds)
.map(amount => amount.toString().padStart(2, '0'))
.join('-');
}
Or to copy & paste the shortest version
function hms(seconds) {
return [3600, 60]
.reduceRight(
(p, b) => r => [Math.floor(r / b)].concat(p(r % b)),
r => [r]
)(seconds)
.map(a => a.toString().padStart(2, '0'))
.join('-');
}
Some example outputs:
> hms(0)
< "00-00-00"
> hms(5)
< "00-00-05"
> hms(60)
< "00-01-00"
> hms(3785)
< "01-03-05"
> hms(37850)
< "10-30-50"
> hms(378500)
< "105-08-20"
How it works
Algorithm
To get hours you divide total seconds by 3600 and floor it.
To get minutes you divide remainder by 60 and floor it.
To get seconds you just use the remainder.
It would also be nice to keep individual amounts in an array for easier formatting.
For example given the input of 3785s the output should be [1, 3, 5], that is 1 hour, 3 minutes and 5 seconds.
Creating pipeline
Naming the 3600 and 60 constants "breakpoints" you can write this algorithm into function as this
function divideAndAppend(remainder, breakpoint, callback) {
return [Math.floor(remainder / breakpoint)].concat(callback(remainder % breakpoint));
}
It returns an array where first item is the amount for given breakpoint and the rest of the array is given by the callback.
Reusing the divideAndAppend in callback function will give you a pipeline of composed divideAndAppend functions. Each one of these
computes amount per given breakpoint and append it to the array making your desired output.
Then you also need the "final" callback that ends this pipeline. In another words you used all breakpoints and now you have only the remainder.
Since you have already the answer at 3) you should use some sort of identity function, in this case remainder => [remainder].
You can now write the pipeline like this
let pipeline = r3 => divideAndAppend(
r3,
3600,
r2 => divideAndAppend(
r2,
60,
r1 => [r1]));
> pipeline(3785)
< [1, 3, 5]
Cool right?
Generalizing using for-loop
Now you can generalize with a variable amount of breakpoints and create a for-loop that will compose individial divideAndAppend functions into
the pipeline.
You start with the identity function r1 => [r1], then use the 60 breakpoint and finally use the 3600 breakpoint.
let breakpoints = [60, 3600];
let pipeline = r => [r];
for (const b of breakpoints) {
const previousPipeline = pipeline;
pipeline = r => divideAndAppend(r, b, previousPipeline);
}
> pipeline(3785)
< [1, 3, 5]
Using Array.prototype.reduce()
Now you can rewrite this for-loop into reducer for shorter and more functional code. In other words rewrite function composition into the reducer.
let pipeline = [60, 3600].reduce(
(ppln, b) => r => divideAndAppend(r, b, ppln),
r => [r]
);
> pipeline(3785)
< [1, 3, 5]
The accumulator ppln is the pipeline and you are composing it using the previous version of it. The initial pipeline is r => [r].
You can now inline the function divideAndAppend and use Array.prototype.reduceRight which is the same as [].reverse().reduce(...) to make the breakpoints
definitions more natural.
let pipeline = [3600, 60]
.reduceRight(
(ppln, b) => r => [Math.floor(r / b)].concat(ppln(r % b)),
r => [r]
);
Which is the final form. Then you just appy mapping to string with padded 0's on left and join the strings with : separator;
More generalizations
Wrapping the reducer into function
function decompose(total, breakpoints) {
return breakpoints.reduceRight(
(p, b) => r => [Math.floor(r / b)].concat(p(r % b)),
r => [r]
)(total);
}
> decompose(3785, [3600, 60])
< [1, 3, 5]
you now have very general algorithm you can work with. For example:
Convert easily (the weird) us length standards
Given the standards
Unit
Divisions
1 foot
12 inches
1 yard
3 feet
1 mile
1760 yards
> decompose(123_456, [1760 * 3 * 12, 3 * 12, 12])
< [1, 1669, 1, 0]
123456 in = 1 mi, 1669 yd, 1 feet and 0 in
Or you can somewhat convert to decimal or binary representations
> decompose(123_456, [100_000, 10_000, 1000, 100, 10])
< [1, 2, 3, 4, 5, 6]
> decompose(127, [128, 64, 32, 16, 8, 4, 2])
< [0, 1, 1, 1, 1, 1, 1, 1]
Works also with floating point breakpoints
Since Javascript supports mod operator with floating point numbers, you can also do
> decompose(26.5, [20, 2.5])
< [1, 2, 1.5]
The edge case of no breakpoints is also naturally covered
> decompose(123, [])
< [123]
Try this:
function toTimeString(seconds) {
return (new Date(seconds * 1000)).toUTCString().match(/(\d\d:\d\d:\d\d)/)[0];
}
Here is an extension to Number class. toHHMMSS() converts seconds to an hh:mm:ss string.
Number.prototype.toHHMMSS = function() {
var hours = Math.floor(this / 3600) < 10 ? ("00" + Math.floor(this / 3600)).slice(-2) : Math.floor(this / 3600);
var minutes = ("00" + Math.floor((this % 3600) / 60)).slice(-2);
var seconds = ("00" + (this % 3600) % 60).slice(-2);
return hours + ":" + minutes + ":" + seconds;
}
// Usage: [number variable].toHHMMSS();
// Here is a simple test
var totalseconds = 1234;
document.getElementById("timespan").innerHTML = totalseconds.toHHMMSS();
// HTML of the test
<div id="timespan"></div>
Easy to follow version for noobies:
var totalNumberOfSeconds = YOURNUMBEROFSECONDS;
var hours = parseInt( totalNumberOfSeconds / 3600 );
var minutes = parseInt( (totalNumberOfSeconds - (hours * 3600)) / 60 );
var seconds = Math.floor((totalNumberOfSeconds - ((hours * 3600) + (minutes * 60))));
var result = (hours < 10 ? "0" + hours : hours) + ":" + (minutes < 10 ? "0" + minutes : minutes) + ":" + (seconds < 10 ? "0" + seconds : seconds);
console.log(result);
This function should do it :
var convertTime = function (input, separator) {
var pad = function(input) {return input < 10 ? "0" + input : input;};
return [
pad(Math.floor(input / 3600)),
pad(Math.floor(input % 3600 / 60)),
pad(Math.floor(input % 60)),
].join(typeof separator !== 'undefined' ? separator : ':' );
}
Without passing a separator, it uses : as the (default) separator :
time = convertTime(13551.9941351); // --> OUTPUT = 03:45:51
If you want to use - as a separator, just pass it as the second parameter:
time = convertTime(1126.5135155, '-'); // --> OUTPUT = 00-18-46
See also this Fiddle.
Chiming in on this old thread -- the OP stated HH:MM:SS, and many of the solutions work, until you realize you need more than 24 hours listed. And maybe you don't want more than a single line of code. Here you go:
d=(s)=>{f=Math.floor;g=(n)=>('00'+n).slice(-2);return f(s/3600)+':'+g(f(s/60)%60)+':'+g(s%60)}
It returns H+:MM:SS. To use it, simply use:
d(91260); // returns "25:21:00"
d(960); // returns "0:16:00"
...I tried to get it to use the least amount of code possible, for a nice one-liner approach.
For the special case of HH:MM:SS.MS (eq: "00:04:33.637") as used by FFMPEG to specify milliseconds.
[-][HH:]MM:SS[.m...]
HH expresses the number of hours, MM the number of minutes for a
maximum of 2 digits, and SS the number of seconds for a maximum of 2
digits. The m at the end expresses decimal value for SS.
/* HH:MM:SS.MS to (FLOAT)seconds ---------------*/
function timerToSec(timer){
let vtimer = timer.split(":")
let vhours = +vtimer[0]
let vminutes = +vtimer[1]
let vseconds = parseFloat(vtimer[2])
return vhours * 3600 + vminutes * 60 + vseconds
}
/* Seconds to (STRING)HH:MM:SS.MS --------------*/
function secToTimer(sec){
let o = new Date(0)
let p = new Date(sec*1000)
return new Date(p.getTime()-o.getTime())
.toISOString()
.split("T")[1]
.split("Z")[0]
}
/* Example: 7hours, 4 minutes, 33 seconds and 637 milliseconds */
const t = "07:04:33.637"
console.log(
t + " => " +
timerToSec(t) +
"s"
)
/* Test: 25473 seconds and 637 milliseconds */
const s = 25473.637 // "25473.637"
console.log(
s + "s => " +
secToTimer(s)
)
Example usage, a milliseconds transport timer:
/* Seconds to (STRING)HH:MM:SS.MS --------------*/
function secToTimer(sec){
let o = new Date(0)
let p = new Date(sec*1000)
return new Date(p.getTime()-o.getTime())
.toISOString()
.split("T")[1]
.split("Z")[0]
}
let job, origin = new Date().getTime()
const timer = () => {
job = requestAnimationFrame(timer)
OUT.textContent = secToTimer((new Date().getTime() - origin) / 1000)
}
requestAnimationFrame(timer)
span {font-size:4rem}
<span id="OUT"></span>
<br>
<button onclick="origin = new Date().getTime()">RESET</button>
<button onclick="requestAnimationFrame(timer)">RESTART</button>
<button onclick="cancelAnimationFrame(job)">STOP</button>
Example usage, binded to a media element
/* Seconds to (STRING)HH:MM:SS.MS --------------*/
function secToTimer(sec){
let o = new Date(0)
let p = new Date(sec*1000)
return new Date(p.getTime()-o.getTime())
.toISOString()
.split("T")[1]
.split("Z")[0]
}
VIDEO.addEventListener("timeupdate", function(e){
OUT.textContent = secToTimer(e.target.currentTime)
}, false)
span {font-size:4rem}
<span id="OUT"></span><br>
<video id="VIDEO" width="400" controls autoplay>
<source src="https://www.w3schools.com/html/mov_bbb.mp4" type="video/mp4">
</video>
Outside the question, those functions written in php:
<?php
/* HH:MM:SS to (FLOAT)seconds ------------------*/
function timerToSec($timer){
$vtimer = explode(":",$timer);
$vhours = (int)$vtimer[0];
$vminutes = (int)$vtimer[1];
$vseconds = (float)$vtimer[2];
return $vhours * 3600 + $vminutes * 60 + $vseconds;
}
/* Seconds to (STRING)HH:MM:SS -----------------*/
function secToTimer($sec){
return explode(" ", date("H:i:s", $sec))[0];
}
After looking at all the answers and not being happy with most of them, this is what I came up with. I know I am very late to the conversation, but here it is anyway.
function secsToTime(secs){
var time = new Date();
// create Date object and set to today's date and time
time.setHours(parseInt(secs/3600) % 24);
time.setMinutes(parseInt(secs/60) % 60);
time.setSeconds(parseInt(secs%60));
time = time.toTimeString().split(" ")[0];
// time.toString() = "HH:mm:ss GMT-0800 (PST)"
// time.toString().split(" ") = ["HH:mm:ss", "GMT-0800", "(PST)"]
// time.toTimeString().split(" ")[0]; = "HH:mm:ss"
return time;
}
I create a new Date object, change the time to my parameters, convert the Date Object to a time string, and removed the additional stuff by splitting the string and returning only the part that need.
I thought I would share this approach, since it removes the need for regex, logic and math acrobatics to get the results in "HH:mm:ss" format, and instead it relies on built in methods.
You may want to take a look at the documentation here: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Date
below is the given code which will convert seconds into hh-mm-ss format:
var measuredTime = new Date(null);
measuredTime.setSeconds(4995); // specify value of SECONDS
var MHSTime = measuredTime.toISOString().substr(11, 8);
Get alternative method from Convert seconds to HH-MM-SS format in JavaScript
var time1 = date1.getTime();
var time2 = date2.getTime();
var totalMilisec = time2 - time1;
alert(DateFormat('hh:mm:ss',new Date(totalMilisec)))
/* ----------------------------------------------------------
* Field | Full Form | Short Form
* -------------|--------------------|-----------------------
* Year | yyyy (4 digits) | yy (2 digits)
* Month | MMM (abbr.) | MM (2 digits)
| NNN (name) |
* Day of Month | dd (2 digits) |
* Day of Week | EE (name) | E (abbr)
* Hour (1-12) | hh (2 digits) |
* Minute | mm (2 digits) |
* Second | ss (2 digits) |
* ----------------------------------------------------------
*/
function DateFormat(formatString,date){
if (typeof date=='undefined'){
var DateToFormat=new Date();
}
else{
var DateToFormat=date;
}
var DAY = DateToFormat.getDate();
var DAYidx = DateToFormat.getDay();
var MONTH = DateToFormat.getMonth()+1;
var MONTHidx = DateToFormat.getMonth();
var YEAR = DateToFormat.getYear();
var FULL_YEAR = DateToFormat.getFullYear();
var HOUR = DateToFormat.getHours();
var MINUTES = DateToFormat.getMinutes();
var SECONDS = DateToFormat.getSeconds();
var arrMonths = new Array("January","February","March","April","May","June","July","August","September","October","November","December");
var arrDay=new Array('Sunday','Monday','Tuesday','Wednesday','Thursday','Friday','Saturday');
var strMONTH;
var strDAY;
var strHOUR;
var strMINUTES;
var strSECONDS;
var Separator;
if(parseInt(MONTH)< 10 && MONTH.toString().length < 2)
strMONTH = "0" + MONTH;
else
strMONTH=MONTH;
if(parseInt(DAY)< 10 && DAY.toString().length < 2)
strDAY = "0" + DAY;
else
strDAY=DAY;
if(parseInt(HOUR)< 10 && HOUR.toString().length < 2)
strHOUR = "0" + HOUR;
else
strHOUR=HOUR;
if(parseInt(MINUTES)< 10 && MINUTES.toString().length < 2)
strMINUTES = "0" + MINUTES;
else
strMINUTES=MINUTES;
if(parseInt(SECONDS)< 10 && SECONDS.toString().length < 2)
strSECONDS = "0" + SECONDS;
else
strSECONDS=SECONDS;
switch (formatString){
case "hh:mm:ss":
return strHOUR + ':' + strMINUTES + ':' + strSECONDS;
break;
//More cases to meet your requirements.
}
}
I just wanted to give a little explanation to the nice answer above:
var totalSec = new Date().getTime() / 1000;
var hours = parseInt( totalSec / 3600 ) % 24;
var minutes = parseInt( totalSec / 60 ) % 60;
var seconds = totalSec % 60;
var result = (hours < 10 ? "0" + hours : hours) + "-" + (minutes < 10 ? "0" + minutes : minutes) + "-" + (seconds < 10 ? "0" + seconds : seconds);
On the second line, since there are 3600 seconds in 1 hour, we divide the total number of seconds by 3600 to get the total number of hours. We use parseInt to strip off any decimal. If totalSec was 12600 (3 and half hours), then parseInt( totalSec / 3600 ) would return 3, since we will have 3 full hours. Why do we need the % 24 in this case? If we exceed 24 hours, let's say we have 25 hours (90000 seconds), then the modulo here will take us back to 1 again, rather than returning 25. It is confining the result within a 24 hour limit, since there are 24 hours in one day.
When you see something like this:
25 % 24
Think of it like this:
25 mod 24 or what is the remainder when we divide 25 by 24
None of the answers here satisfies my requirements as I want to be able to handle
Large numbers of seconds (days), and
Negative numbers
Although those are not required by the OP, it's good practice to cover edge cases, especially when it takes little effort.
It's pretty obvious is that the OP means a NUMBER of seconds when he says seconds. Why would peg your function on String?
function secondsToTimeSpan(seconds) {
const value = Math.abs(seconds);
const days = Math.floor(value / 1440);
const hours = Math.floor((value - (days * 1440)) / 3600);
const min = Math.floor((value - (days * 1440) - (hours * 3600)) / 60);
const sec = value - (days * 1440) - (hours * 3600) - (min * 60);
return `${seconds < 0 ? '-':''}${days > 0 ? days + '.':''}${hours < 10 ? '0' + hours:hours}:${min < 10 ? '0' + min:min}:${sec < 10 ? '0' + sec:sec}`
}
secondsToTimeSpan(0); // => 00:00:00
secondsToTimeSpan(1); // => 00:00:01
secondsToTimeSpan(1440); // => 1.00:00:00
secondsToTimeSpan(-1440); // => -1.00:00:00
secondsToTimeSpan(-1); // => -00:00:01
Simple function to convert seconds into in hh:mm:ss format :
function getHHMMSSFromSeconds(totalSeconds) {
if (!totalSeconds) {
return '00:00:00';
}
const hours = Math.floor(totalSeconds / 3600);
const minutes = Math.floor(totalSeconds % 3600 / 60);
const seconds = totalSeconds % 60;
const hhmmss = padTo2(hours) + ':' + padTo2(minutes) + ':' + padTo2(seconds);
return hhmmss;
}
// function to convert single digit to double digit
function padTo2(value) {
if (!value) {
return '00';
}
return value < 10 ? String(value).padStart(2, '0') : value;
}
Here is a function to convert seconds to hh-mm-ss format based on powtac's answer here
jsfiddle
/**
* Convert seconds to hh-mm-ss format.
* #param {number} totalSeconds - the total seconds to convert to hh- mm-ss
**/
var SecondsTohhmmss = function(totalSeconds) {
var hours = Math.floor(totalSeconds / 3600);
var minutes = Math.floor((totalSeconds - (hours * 3600)) / 60);
var seconds = totalSeconds - (hours * 3600) - (minutes * 60);
// round seconds
seconds = Math.round(seconds * 100) / 100
var result = (hours < 10 ? "0" + hours : hours);
result += "-" + (minutes < 10 ? "0" + minutes : minutes);
result += "-" + (seconds < 10 ? "0" + seconds : seconds);
return result;
}
Example use
var seconds = SecondsTohhmmss(70);
console.log(seconds);
// logs 00-01-10
There are lots of options of solve this problem, and obvious there are good option suggested about, But I wants to add one more optimized code here
function formatSeconds(sec) {
return [(sec / 3600), ((sec % 3600) / 60), ((sec % 3600) % 60)]
.map(v => v < 10 ? "0" + parseInt(v) : parseInt(v))
.filter((i, j) => i !== "00" || j > 0)
.join(":");
}
if you don't wants formatted zero with less then 10 number, you can use
function formatSeconds(sec) {
return parseInt(sec / 3600) + ':' + parseInt((sec % 3600) / 60) + ':' + parseInt((sec % 3600) % 60);
}
Sample Code http://fiddly.org/1c476/1
In one line, using T.J. Crowder's solution :
secToHHMMSS = seconds => `${Math.floor(seconds / 3600)}:${Math.floor((seconds % 3600) / 60)}:${Math.floor((seconds % 3600) % 60)}`
In one line, another solution that also count days :
secToDHHMMSS = seconds => `${parseInt(seconds / 86400)}d ${new Date(seconds * 1000).toISOString().substr(11, 8)}`
Source : https://gist.github.com/martinbean/2bf88c446be8048814cf02b2641ba276
var sec_to_hms = function(sec){
var min, hours;
sec = sec - (min = Math.floor(sec/60))*60;
min = min - (hours = Math.floor(min/60))*60;
return (hours?hours+':':'') + ((min+'').padStart(2, '0')) + ':'+ ((sec+'').padStart(2, '0'));
}
alert(sec_to_hms(2442542));
Have you tried adding seconds to a Date object?
Date.prototype.addSeconds = function(seconds) {
this.setSeconds(this.getSeconds() + seconds);
};
var dt = new Date();
dt.addSeconds(1234);
A sample:
https://jsfiddle.net/j5g2p0dc/5/
Updated:
Sample link was missing so I created a new one.
You can also use below code:
int ss = nDur%60;
nDur = nDur/60;
int mm = nDur%60;
int hh = nDur/60;
For anyone using AngularJS, a simple solution is to filter the value with the date API, which converts milliseconds to a string based on the requested format. Example:
<div>Offer ends in {{ timeRemaining | date: 'HH:mm:ss' }}</div>
Note that this expects milliseconds, so you may want to multiply timeRemaining by 1000 if you are converting from seconds (as the original question was formulated).
I ran into the case some have mentioned where the number of seconds is more than a day. Here's an adapted version of #Harish Anchu's top-rated answer that accounts for longer periods of time:
function secondsToTime(seconds) {
const arr = new Date(seconds * 1000).toISOString().substr(11, 8).split(':');
const days = Math.floor(seconds / 86400);
arr[0] = parseInt(arr[0], 10) + days * 24;
return arr.join(':');
}
Example:
secondsToTime(101596) // outputs '28:13:16' as opposed to '04:13:16'
String.prototype.toHHMMSS = function () {
var sec_num = parseInt(this, 10); // don't forget the second param
var hours = Math.floor(sec_num / 3600);
var minutes = Math.floor((sec_num - (hours * 3600)) / 60);
var seconds = sec_num - (hours * 3600) - (minutes * 60);
if (hours < 10) {hours = "0"+hours;}
if (minutes < 10) {minutes = "0"+minutes;}
if (seconds < 10) {seconds = "0"+seconds;}
return hours+':'+minutes+':'+seconds;
}
Usage Example
alert("186".toHHMMSS());

Javascript: How to turn the time (stored as a fraction) into a readable string?

I have the time stored as a fraction (done so it can be displayed on a graph), e.g. 15.5 is 3.30pm and 23.25 is 11.15pm. I need to turn those numbers into strings in the format HH:MM:SS. Is there a simple way of doing this?
var fraction = 23.5;
var date = new Date(2000, 1, 1); // use any date as base reference
date.setUTCSeconds(fraction * 3600); // add number of seconds in fractional hours
Then use a date formatting script such as this, or Date.js if you're not fond or formatting and padding.
date.format("HH:MM:ss"); // 23:30:00
See an example. I'm using the formatting function from here.
Something like this ?
var fraction = 14.5;
var hours = Math.floor(fraction); // extract the hours (in 24 hour format)
var mins = 60 * (fraction - hours); // calculate the minutes
t = new Date(); // create a date/time object
t.setHours(hours); // set the hours
t.setMinutes(mins); // set the mins
console.log(t.toTimeString()); //show it
or completely manual
var fraction = 14.5;
var hours = Math.floor(fraction);
var mins = 60 * (fraction - hours);
var ampm = ((fraction % 24) < 12) ? 'am' : 'pm';
formatted = ('0' + hours % 12).substr(-2) + ':' + ('0' + mins).substr(-2) + ':00 ' + ampm;
console.log(formatted);
Update
And a version with seconds as well..
var fraction = 14.33;
var hours = Math.floor(fraction);
var allseconds = 3600 * (fraction - hours);
var minutes = Math.floor(allseconds / 60);
var seconds = Math.floor(allseconds % 60);
var ampm = ((fraction % 24) < 12) ? 'am' : 'pm';
formatted = ('0' + hours % 12).substr(-2) + ':' + ('0' + minutes).substr(-2) + ':' + ('0' + seconds).substr(-2) + ' ' + ampm;
console.log(formatted);
Manual function:
var time = function(num) {
if(num < 0 || num >= 24) {throw "Invalid number");}
var x = num > 13 ? num - 12 : num;
var h = Math.floor(x);
var min = x - h;
var ampm = num >= 12 && num < 24 ? "pm" : "am";
return (h + ":" + Math.floor(min * 60) + ampm);
};
Tests:
time(13.40); // 1:24pm
time(11.25); // 11:15pm
time(12.50); // 12:30pm
time(23.50); // 11:30pm
time(0.50); // 0:30am
time(24.00); // error!!

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