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How can I use a url string parameter when the url doesn't use /

How can I use a url string parameter when the url doesn't use /? I'm used to using /:parameter_here, but how can I use that variable syntax when using ? and &?
URL (Doesn't Work)
www.test.com/users?status=ACCEPTED&party_id=:partyId

www.test.com/users/parameter_here?status=ACCEPTED&party_id=partyId
parameter_here will be parameter_here
status will be ACCEPTED
and party_id will be partyId
You don't need the &, ? or = for parameters in the URL.

Passing encoded url as parameter javascript function

JS fiddle created at https://jsfiddle.net/ankitwasankar/sc50ecyf/ demonstrates, how the url sent as a parameter decode itself inside function. Is it the expected behaviour. Do I need to encode url passed as parameter again inside function. Currently when URL is opened with window.location.href it doesn't contain %26 instead contains &. So on server, HttpServletRequest.getParameterNames() returns two parameters instead of one.

What about split %26 in-between, like:
<a href='javascript:print_me("https://www.google.co.in/search?query=a%2" + "6b=26")'>Click</a>
This prevents the auto-decoding, although it's a little bit hacky.

jQuery can't encode a parameter which is a URL

I have a GET request that takes a parameter, this parameter is also a URL. So normally I just encode the URL and then decode it in my server, this works pefectly from Java, but now I am on jQuery and I have a problem with it.
This is the value of that parameter:
http://www.BookOntology.com/bo#ania
When I encode it like this:
encodeURI(userURI)
I get the same value, while i thought that i should have gotten this
http%3A%2F%2Fwww.BookOntology.com%2Fbo%23ania
To show you what is the wrong
My current approach (which is using econdeURI) brings this final URL (note that I just want to encode the paramter not the whole URL).
http://bla bla bla?userURI=http://www.BookOntology.com/bo#ania
But in the server when i read the value of the userURI parameter i get:
http://www.BookOntology.com/bo
It is definitely a problem with the way i encode that value of that parameter because, again, the value after and before encoding is the same though the value contains some characters that should be changed.
Could you help me pass that please?

Try with encodeURIComponent function , which encodes a Uniform Resource Identifier (URI)
DEMO: encode input value
Read the MDN DOCS for more info.

encodeURI only changes characters that can't appear in a URL at all.
You're looking for encodeURIComponent which encodes all characters with special meaning in a URL as well (and makes it suitable for inserting in a query string).

encodeURI doesn't escape `equals` - why?

I have an URI like that:
http://client.dev/dap/module/hdfs-web/api/v1.0/clusters/Cluster%201%20-%20CDH4?operation=copy&to=/user/hdfs/year=2016/partial.txt&overwrite=true
I use encodeURI function to escape string. I'm wondering why spaces are encoded with %20 while equals characters are not?

encodeURI encodes a full URI, and URIs can contain = characters. For instance, if a user types in a URI, a first step to resolve it would be to call encodeURI on it.
If on the other hand you are the one constructing the URI, and the input just determines one field (for instance a search query, when given E=mc² you want to resolve https://www.google.com/search?q=E%3Dmc%C2%B2), then you are not encoding a full URI, but a URI component. Use encodeURIComponent for that:
> encodeURIComponent('= ')
'%3D%20'

The encodeURI() function is used to encode a URI.
This function encodes special characters, except:, / ? : # & = + $ # (Use encodeURIComponent() to encode these characters).
Tip: Use the decodeURI() function to decode an encoded URI.
SOURCE: W3Schools

How to prepare encoded POST data on javascript?

I need to send data by POST method.
For example, I have the string "bla&bla&bla". I tried using encodeURI and got "bla&bla&bla" as the result. I need to replace "&" with something correct for this example.
What kind of method should I call to prepare correct POST data?
UPDATED:
I need to convert only charachters which may broke POST request. Only them.

>>> encodeURI("bla&bla&bla")
"bla&bla&bla"
>>> encodeURIComponent("bla&bla&bla")
"bla%26bla%26bla"

You can also use escape() function.The escape() function encodes a string.
This function makes a string portable, so it can be transmitted across any network to any computer that supports ASCII characters.This function encodes special characters, with the exception of: * # - _ + . /
var queryStr = "bla&bla&bla";
alert(queryStr); //bla&bla&bla
alert(escape(queryStr)); //bla%26bla%26bla
Use unescape() to decode a string.
var newQueryStr=escape(queryStr);
alert(unescape(newQueryStr)); //bla&bla&bla
Note:
escape() will not encode: #*/+
encodeURI() will not encode: ~!##$&*()=:/,;?+'
encodeURIComponent() will not encode: ~!*()'
After some search on internet, I got the following:
escape()
Don't use it.
encodeURI()
Use encodeURI when you want a working URL. Make this call:
encodeURI("http://www.google.com/a file with spaces.html")
to get:
http://www.google.com/a%20file%20with%20spaces.html
Don't call encodeURIComponent since it would destroy the URL and return
http%3A%2F%2Fwww.google.com%2Fa%20file%20with%20spaces.html
encodeURIComponent()
Use encodeURIComponent when you want to encode a URL parameter.
param1 = encodeURIComponent("http://xyz.com/?a=12&b=55")
Then you may create the URL you need:
url = "http://domain.com/?param1=" + param1 + "&param2=99";
And you will get this complete URL:
http://www.domain.com/?param1=http%3A%2F%2Fxyz.com%2F%Ffa%3D12%26b%3D55¶m2=99
Note that encodeURIComponent does not escape the ' character. A common bug is to use it to create html attributes such as href='MyUrl', which could suffer an injection bug. If you are constructing html from strings, either use " instead of ' for attribute quotes, or add an extra layer of encoding (' can be encoded as %27).
REF:When are you supposed to use escape instead of encodeURI / encodeURIComponent?
Also, as you are using JQuery, take a look at this built-in function.

Use encodeURIComponent() as encodeURI() will not encode: ~!##$&*()=:/,;?+'
This has been explained quite well at the following link:
http://xkr.us/articles/javascript/encode-compare/

More recent DOM APIs for URLSearchParams (and via URL, possibly others too) handle encoding in some cases. For example, create or use an existing URL object (like from an anchor tag) I map entries of an object as key value pairs for URL encoded params (to use for GET/POST/etc in application/x-www-form-urlencoded mimetype). Note how the emoji, ampersand and double quotes are encoded without any special handling (copied from the Chrome devtools console):
var url = new URL(location.pathname, location.origin);
Object.entries({a:1,b:"🍻",c:'"stuff&things"'}).forEach(url.searchParams.set, url.searchParams);
url.search;
"?a=1&b=%F0%9F%8D%BB&c=%22stuff%26things%22"
fetch(url.pathname, {
method: 'POST',
headers: new Headers({
"Content-type": "application/x-www-form-urlencoded"
}),
// same format as GET url search params a&b&c
body: url.searchParams
}).then((res)=>{ console.log(res); return res }).catch((res)=>{ console.warn(res); return res; });

I want POST the javascript-created hidden form.
So the question is if encodeURIComponent() should be used on each POST variable.
I haven't found the answer for Dmitry's (and my) question in this thread.
But I have found the answer in this thread.
In case of form/POST where you have upload field(s) you must use <form enctype="multipart/form-data">, if no upload field is used, you should choose yourself as described here.
Submitting the form should do the job completly, so there is no need to use encodeURIComponent() explicitly.
If you create a Http POST without using a form or without some library which creates a Http POST from your data, then you need choose an enctype= and join data yourselves.
This will be easy for application/x-www-form-urlencoded, where you will use encodeURIComponent() on each value and join them exactly as for GET request.
If you decide use multipart/form-data then ....? You should google more how to encode and join them in such case.