I have the following three php files:
reports.php, bwdates-reports-details.php and visitor-detail.php
reports.php contains my form which inputs the from and to date (erased some parts for brevity):
<form method="post" action="bwdates-reports-details.php">
...
<input type="date" id="fromdate" name="fromdate">
...
<input type="date" id="todate" name="todate">
<button type="submit" name="submit">Submit</button></p>
</form>
bwdates-reports-details.php outputs whatever parameters inputted in "fromdate" and "todate" of reports.php, see image below
As you can see in the image, there is an option to view the details of a transaction by clicking the "View Details" icon - i class="fa fa-edit fa-1x".
In view details (visitor-detail.php), There is a "Go Back" button.
<div align="center">
<button onclick="goBack()">Go Back</button>
</div>
There is also a goBack javascript function:
<script>
function goBack() {
window.history.back();
}
</script>
But when the go back button is clicked, I am getting Confirm Form Resubmission error. What I wanted to achieve with the "go back" button is to be able to go back to bwdates-reports-details.php with all the variables I passed through in reports.php. How do I achieve what I wanted to do? Please take note that this isn't a purchase related website. php or javascript will do. Thanks!
If a form is submitted (probably with the POST method), you send this data to the new page that is then opened. This page is also added to the history not only with the URL but also the sent data.
If you then leave this page and want to navigate back to this previous page you will get an "Resubmission" error, because the browser would need to send the data again to do so, but that is probaby a bad thing to do, because the data of the form would be sent twice. (Imagine that was a purchase form and the client would buy everything again.)
To make your goBack function work there are no other ways than get rid of that form submission page somehow or put a page in between that is not a form-data-receiver.
The best way would be to not go back in the browser history if you don't know from what pages the user navigated to this. Instead just navigate to an overview or dashboard.
Edit:
If that page your working on is only accessible by that response page of the form, maybe going two pages back will fix your error: history.back(2);
Because your form is using POST method and when you click on goBack button, it goes on previous page without variables. You may use put dates variable with goBack button and also use
if(isset($_GET['your variable name'];
{`fetch your variables`}
on your previous page.
Desired result was achieved by using the GET method instead of POST method (see https://www.tutorialspoint.com/php/php_get_post.htm). reports.php form code was replaced from:
<form method="post" action="bwdates-reports-details.php">
to:
<form method="get" action="bwdates-reports-details.php">
In bwdates-reports-details.php where I have the following variables:
$fdate=$_POST['fromdate'];
$tdate=$_POST['todate'];
Instead I replaced it with:
$fdate=$_GET['fromdate'];
$tdate=$_GET['todate'];
The goback javascript function I have in visitor-detail.php stays the same. And works like a charm. Thanks and cheers!
Related
I have searched Unbounce and Google for documentation, but can't find a way to make this work. Any help is greatly appreciated!
Use case:
I have a test page setup in Unbounce and it would be great when a user lands on the page and submits the form that the value being generated through the script below in the hidden field is added to the current URL upon submission.
It's important that if the user lands on the page from an advertising campaign that the value is added to URL and does not replace it.
Example:
User lands on testpage.com or testpage.com?qs=3134728&pcd=THANKS20&dclid=CNi4wvCv39cCFZdFNwodE_wALA
Unique ID is created with the following JavaScript and added to a hidden field:
<script type="text/javascript">
$(document).ready(function() {
var id = new Date().toISOString().replace(/[-tTzZ:.]/g, '');
$('#lead_id').val(id);
});
</script>
User clicks submit and and is redirected to a thankyou page with the value of the hidden field passed in the URL:
testpage.com/thank-you?lead_id=1234
testpage.com/thankyou?qs=3134728&pcd=THANKS20&dclid=CNi4wvCv39cCFZdFNwodE_wALA&lead_id=1234
I should also mention that I can not edit the html of the form so this would need to happen with JavaScript as Unbounce provides a space to add custom code.
Is the form method get? If it is post it wont append that to the URL for the hidden field.
Your approach seems right however if this is the HTML on page:
<form action="http://example.com" method="get" id="theForm">
<input type="hidden" value="xyz" />
<button type="submit">Send</button>
</form>
You can use some JS code like one of the following to modify this...however you'll want to verify that everything still works as expected:
document.getElementById('theForm').action = "http://another.example.com";
document.getElementById('theForm').method = "get";
My Form Works Successfully But in website URL it only Shows the address to a Form.I have multiple Pages in which the Form button shown.All I want when a user click on The Form for Page A for that Particular page it should shown as
"www.form.com?test=page A" - this should displayed on website URL
or when the Form is submitted the receiver should view that this form coming from Page A..In the Form field I hidden this fields name 'Test' so the user cannot see it but only the receiver can view it that its coming from Page A
On my Html code I have redirected to the Build in Form.
Here is my java script code
<script type="text/javascript" src="http://test.com/form/y.php/test2"></script><no1script>Online Form - </no1script>
How to show it to my Website URL
I understand your question as "How can I redirect with a specific GET parameter?", correct me if I'm wrong.
The solution for that would be quite simple: Append the GET parameter to the forms action:
<form action="target.php">
gets
<form action="target.php?test=page_a">
so that on target.php if you evaluate the GET values, test has the value page_a.
If you're trying to hide the post data, you can try something like:
<form action="https://test.com/forms/discount" style="display:none">
<input type="text" name="couponCode" value="secret">
<input id="myform" type="submit">
</form>
<script>
document.querySelector("#myform").click();
</script>
Note: This won't stop any web ninjas, so you should think of something else, like web tokens that function sortta like private public keys.
I load a webpage in a webView. In onPageFinished(..) i run some javascript code, which finally clicks a submit button. So the webView sends Post data and get an answer and loads a new page. That works fine, but i dont need the new page, its just unnecessary network load. I only need to submit the data.
So is it possible to send only the submit without loading the new page? I know that i can send post data with HTTPConnection, but i dont know the header consistence exactly, so i cant set the params. Is there any possibility with JS/Webview to abort?
Edit: I cant override onPageStarted() in my WebViewClient and perform a view.stopLoading(), because the new URL is still the same. But the site appearance is quite different. So i have to stop loading before
HTML of the submit button:
<input type="submit" name="savechanges" class="btn btn-primary" value="Speichern">
and three aditional lines above
<input type="hidden" name="uid" value="390">
<input type="hidden" name="option" value="com_jevents">
<input type="hidden" name="task" value="dash.listprojects">
which meaning i dont know (site is made by Joomla)
You can simply create a "virtual form" and submit it, like:
var $form = $("");
... on click:
$form.submit();
Hope this helps
Ops its removing my html from inside $form, inside the jQuery selector there should be a form like "form method='post' action='{someurl}'" with angle braces opening and closing properly
I have an address book widget that shows if there are contents.
If there are no contents, an add button will show up. Upon pressing the add button, it will redirect to another page which will show the form.
The initial design of my website is as follows:
When the user click the add button, it will direct to a page using javascript function:
document.location.href="address?addOnly=true";
The form will display.
If successful, there are $.post that will change the div only that will enable user to do CRUD in the address book.
The problem with the variable inside the url which is address?addOnly=true is that when the user refresh it, it will always shows the add form.
That's why i've decided to hide the implementation using $.post
$.post('address', {"listEmty":true}, function (data) {
window.location = "address";
});
The problem with this is that it can't pass the variable at all.
My questions are:
How to handle the page refresh if using the get method, which passes the paramater in the URL,
Are there anyways in javascript/jquery to pass the variable using post method then refresh the page?
Thank you.
<FORM method="post" action="address" id="refresh" style="display: none;">
<DIV>
<INPUT type="hidden" name="addOnly" value="true">
</DIV>
</FORM>
<SCRIPT type="text/javascript">
document.getElementById('refresh').submit();
</SCRIPT>
What this does is create an invisible form, then immediately submits it. You can of course call the submit from within your other javascript code.
I have a very basic form at http://www.happyholidaylites.com/contact.html and it is working great. When you submit the form, the user is brought to the index.html with no message that the form has been sent. I am looking to initiate an alert that says, "your form has been submitted" with an x button. My code looks like this:
<form method="post" id="myForm" action="dynaform.php">
<input type='hidden' name='rec_mailto' value='JBIRD1111#gmail.com'>
<input type='hidden' name='rec_subject' value='New Contact Form'>
<input type='hidden' name='rec_thanks' value='index.html'>
so on and so forth.....
The last line is what is telling the form what to do after the submit button is pressed, but I dont want it to point the browser to the index, rather I want a javascript popup with a success message. Any ideas?
Why not a simple onSubmit?
<form method="post" id="myForm" action="dynaform.php" onSubmit="alert('Thank you for your feedback.');" >
To be honest you are better re-directing to another page in order to avoid the user re-submitting the page on a refresh. Have a look at Post/Redirect/Get Pattern.
Popups can be extremely annoying on websites. You should create a page called "thank-you.html" that you can re-direct the user to on successful submission which has access to the site navigation options or even just do a re-direct back to the form page after a few seconds.
Instead of redirecting to index.html, redirect to thanks.html; your users will thank you because everybody hates popups!
Sounds like your PHP script handles the form submission by processing the input and redirecting the browser to the value in the rec_thanks field.
You can add something like onsubmit="YourJavaScriptFunction()" to the form tag to add client-side behavior prior to actually submitting the form. Within that function you can perform validation, use alert('Thank You!'), etc..