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split method to return only values split by a comma not quotes in comma [closed]

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I want to split the string below by a default comma which is , and ignore the "," part.
Has anyone come up with a solution for this? Tried a bunch of solutions, but doesn't work.
My string: (testing","a framework), hello world, testing","antother_framework
expected result:
["testing","a framework", "hello world", "testing","antother_framework]

not the nicest way, with regex you could grouped the replace but it works
const str = '(testing","a framework), hello world, testing","antother_framework';
let arr = str.split(',');
console.log(arr);
for (let i = 0; i < arr.length; i++) {
arr[i] = arr[i].replaceAll('(', '');
arr[i] = arr[i].replaceAll(')', '');
arr[i] = arr[i].replaceAll('\"', '');
arr[i] = arr[i].trim();
}
console.log(arr);

You could use this function:
function splitByCommas(str) {
return str.split(/,(?=(?:[^"]*"[^"]*")*[^"]*$)/);
}
Explanation:
/,(?=(?:[^"]"[^"]")[^"]$)/ -> match the comma outside of the quotes
(?:[^"]"[^"]")* -> match the quotes and the text inside the quotes
[^"]*$ -> match the remaining text after the last quote
If you run the function like this:
console.log(splitByCommas('(testing","a framework), hello world, testing","antother_framework'));
It will give the following output:
[
'(testing","a framework)',
' hello world',
' testing","antother_framework'
]
If you want to also trim the whitespaces, you can use this:
function splitByCommas(str) {
return str.split(/,(?=(?:[^"]*"[^"]*")*[^"]*$)/).map(function (item) {
return item.trim();
}
);
}
For the same input giving you:
[
'(testing","a framework)',
'hello world',
'testing","antother_framework'
]

Extracting a string from another string Javascript [closed]

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I have this particular string :
TOYIN KEMIOGS/OYO/2277TGOGSLAGOS
from this string containing 2 '/'
I want it to extract from wherever we have OGS and stop at wherever we have OGS. OGS always start and end my extracted string
I want an extracted result like this
OGS/OYO/2277TGOGS
Thanks so much

You can achieve it but as a string between first occurrence and last occurrence of OGS as follows:
var a = 'TOYIN KEMIOGS/OYO/2277TGOGSLAGOS';
console.log(a.slice(a.indexOf("OGS"),a.lastIndexOf("OGS")) +"OGS");

You can use match method of string to extract the data required.
const str = "TOYIN KEMIOGS/OYO/2277TGOGSLAGOS";
const result = str.match(/OGS.*OGS/); // Its greedy in nature so you can also use /OGS.*?OGS/
console.log(result[0]);

let str = "TOYIN KEMIOGS/OYO/2277TGOGSLAGOS";
let phrase = "OGS";
let start = str.indexOf(phrase);
let end = str.lastIndexOf(phrase) + phrase.length;
let newStr = str.slice(start, end);
console.log(newStr);

You can treat the start/stop sequences as non-matching groups:
const str = 'TOYIN KEMIOGS/OYO/2277TGOGSLAGOS';
const [match] = str.match(/(?:OGS).+(?:OGS)/);
console.log(match); // "OGS/OYO/2277TGOGS"
If you don't want to keep the start/stop sequences ("OGS"), you can treat them as positive lookbehind/lookaheads:
const str = 'TOYIN KEMIOGS/OYO/2277TGOGSLAGOS';
const [match] = str.match(/(?<=OGS).+(?=OGS)/);
console.log(match); // "/OYO/2277TG"
Here is a string manipulation version, which captures the first and last index.
const extractBetween = (str, marker) =>
str.slice(str.indexOf(marker),
str.lastIndexOf(marker) + marker.length);
const str = 'TOYIN KEMIOGS/OYO/2277TGOGSLAGOS';
const match = extractBetween(str, 'OGS');
console.log(match); // "OGS/OYO/2277TGOGS"

Print all the characters separated by a space js [closed]

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i have a variable and I want to separate the name whit a space letter by letter and then UpperCase the letters
var name = "Tom Hanks";
console.log(name) has to be equal to "T O M H A N K S"

var name = "Tom Hanks";
var result = name.toUpperCase().split("").join(" ").replace(/\s+/g, " ");
console.log(result);

First you must split the string to separate the letters of the word and save 'em in a array object. For that you can use the String.split() function:
const myString = 'Tom Hanks';
const splittedString = myString.split('');
Then you can use Array.join() function to create a new string with spaces between the letters of the previous array:
const stringWithSpaces = splittedString.join(' ');
Finally you can use the String.toUpperCase() to set the "caps lock" on:
stringWithSpaces.toUpperCase();
So, here is the complete snippet:
const myString = 'Tom Hanks';
const splittedString = myString.split('');
const stringWithSpaces = splittedString.join(' ');
const upperCaseStringWithSpaces = stringWithSpaces.toUpperCase();
console.log(upperCaseStringWithSpaces);

replace (_)underscore all dot continue by space (. ) in javascript [closed]

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I need to replace all the dot continue by space with underscore(_).
example:
I/P: 'test. test1. test2'
O/P: 'test_test1_test2'
I tried but i can remove dot and space alone only.
//Input
var str = 'test. test1. test2';
//What I have tried
str = str.replace(/\./g,'_');
console.log(str);
//Outputs "test_ test1_ test2"
How to write the regex for this?

For a dot followed by a single space... use str.replace(/\. /g, "_");
For a dot followed by multiple spaces... use str.replace(/\.( )+/g, "_");

You missed the space char:
let IP = 'test. test1. test2'
let OP = IP.replace(/(\.\s+)/g, '_');
console.log(OP)

Here:
var input = 'test. test1. test2';
//Delete only ". "
var output = input.replace(/(\.\s)/g, '_');
//Output
console.log(output);
If you want only the "space" character, use this instead:
var input = 'test. test1. test2';
//Delete only ". "
var output = input.replace(/(\. )/g, '_');
//Output
console.log(output);

Without RegEx:
let str = "test. test1. test2"
let res = str.split(" ").map(el => el.trim().replace(".", "_")).join("")
console.log(res)
With RegEx:
let str = "test. test1. test2"
let re = /\.\s+/g
let res = str.replace(re, "_")
console.log(res)

Regular expression for remove last n characters [closed]

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I have a requirement to remove last n characters from string or remove 'page' from a particular string.
Eg:
var string = 'facebookpage';
Expected output string = 'facebook'
I would like to remove 'page' from the string.
Done it using substring.
var str = "facebookpage";
str = str.substring(0, str.length - 4);
Could you help me to find some better way to do it.

Regex for this:
//str - string;
//n - count of symbols, for return
function(str, n){
var re = new RegExp(".{" + n + "}","i");
return str.match(re);
};
EDIT:
For remove last n characters:
var re = new RegExp(".{" + n + "}$","i");
return str.replace(re, "");
UPDATE:
But use regex for this task, not good way; For example, AVG Runtime for 100000 iterations:
Str length solution = 63.34 ms
Regex solution = 172.2 ms

Use javascript replace function
var str = "facebookpage";
str = str.replace('page','');

You can use this regular expression :
(.*)\\w{4}
code :
var regex =(new RegExp("(.*)\\w{4}"))
val output = regex .exec("facebookpage")
// output is : ["facebookpage", "facebook"]
// output[1] is the Expected output which you want.
Hope this helps.