Passing item.name in StackNavigator React Native - javascript

So i have a flatList that display names using Fetch api,
<FlatList
data={this.state.data}
keyExtractor={item => item.id}
renderItem={({item}) => <TouchableOpacity onPress {()=>NavigationService.navigate('Med') }>
<Text> {item.name}</Text>)}
on the click on one of the name i navigate to another screen where i wil have to use "item.name", how can i pass this param.on that screen code i'm using a class and i don't want to use a function.
class search extends React.Component {
constructor(props){
super(props);
}.....
thanks in advance

check hope it will work
now here is pass your item.name in this navigate action
<FlatList
data={this.state.data}
keyExtractor={item => item.id}
renderItem={({item}) => <TouchableOpacity onPress {()=>NavigationService.navigate(`${item.name}`) }>
<Text> {item.name}</Text>)}

Since your NavigationService handle navigate function with params as below,
export function navigate(name, params) {
navigationRef.current?.navigate(name, params);
}
You can pass your params as
<TouchableOpacity onPress {() => NavigationService.navigate('Med', {name: item.name})}>
Once you navigate to the specific screen you can access you name params as
this.props.route.params.name
Hope this helps you. Feel free for doubts.

Related

Pass function from one screen to another in react native

Im trying to pass a function handleNewFavourite (which updates my favouriteList state array) from my HomeScreen to my DetailsScreen via navigation params but Im getting the following error: Non-serializable values were found in the navigation state
How should I pass functions that modified the state between different stack screens?
HomeScreen code:
<FlatList
data={checkCategory()}
renderItem={({item}) => (
<TouchableOpacity
onPress={() =>
navigation.navigate('Details', {
item,
handleNewFavourite,
})
}>
<LessonCard lesson={item} />
</TouchableOpacity>
)}
/>
DetailScreen code:
const LessonDetails = ({lesson, handleNewFavourite}: LessonProps) => {
const [favourite, setFavourite] = useState<boolean>(lesson.favourite);
return (
<LessonDetailsContainer>
<LessonDetailsInfoContainer>
<LessonDetailsCategoryHead>
<LessonDetailsCategory>{lesson.category}</LessonDetailsCategory>
<TouchableOpacity
onPress={() => {
setFavourite(!favourite);
handleNewFavourite(lesson);
}}>
<LessonDetailsFavouriteIcon>
{favourite ? '❤️' : '🤍'}
</LessonDetailsFavouriteIcon>
</TouchableOpacity>
</LessonDetailsCategoryHead>
<LessonDetailsTitle>{lesson.title}</LessonDetailsTitle>
<LessonDetailsAuthor>{lesson?.author}</LessonDetailsAuthor>
</LessonDetailsInfoContainer>
<LessonDetailsCardImage
source={{
uri: lesson.image,
}}
/>
<LessonDetailsContentContainer>
<LessonDetailsDescriptionText>
{lesson.content}
</LessonDetailsDescriptionText>
</LessonDetailsContentContainer>
</LessonDetailsContainer>
);
};
export default LessonDetails;
For situation like this, you should learn global state management. ( Context API - Redux etc. )
I think you are disrupting in the wrong way the parameters passed to DetailScreen it should be something like this:
const LessonDetails = ({route}: LessonProps) => {
const {lesson, handleNewFavourite} = route.params;
// The rest of your component here
}
As the documentation here suggested. But as #omerfarukose mentioned is not a bad idea to use state management in this particular scenario

Displaying a Flatlist Data to Flatlist Props

im having an issue with passing my Flatlist data to my Flatlist props which is 'ListHeaderComponent'. here's my code:
<FlatList
ListHeaderComponent={
<View>
<Text>{}</Text>
</View>
}
data={displayedPhoto}
keyExtractor={(item) => item.id}
renderItem={renderPhotoItem}
numColumns={2}
/>
is there any possible to pass my Flatlist Data inside the Text Component? Help me please
ListHeaderComponent is a prop which use to render the component as Header of the FlatList which scrolls with the FlatList. ListHeaderComponent can't have the item of the FlatList. You can use like
renderHeader = () => {
return (
<View>
<Text>Employees</Text>
</View>
);
};
<FlatList
ListHeaderComponent={this.renderHeader}
data={displayedPhoto}
keyExtractor={(item) => item.id}
renderItem={renderPhotoItem}
numColumns={2}
/>

onClick() doesn't trigger function in React-Native App

In my react-native mobile app I have written a component called Row in row.js that contains a TouchableOpacity with an onClick() event handler. However when the component is clicked the function doesn't run.
The Row component displays some text about a particular film and should run the handlePress() function when clicked:
const Row = props => (
<TouchableOpacity onClick={() => props.handlePress(props.imdbID)} style={styles.row}>
<Text>Some text</Text>
</TouchableOpacity>
)
In a separate app.js file, the handlepress function has been written and is passed to the Row component as a prop. The imdbID variable is also passed to the component from the film object:
handlePress = imdbID => {
// do something with imdbID
}
<Row handlePress={this.handlePress} {...film} />
Please can someone tell me what I am doing wrong and why the function doesn't run.
If you take a look at the docs, it doesnt have onClick.
You should use onPress.
const Row = props => (
// using onPress
<TouchableOpacity onPress={() => props.handlePress(props.imdbID)} style={styles.row}>
<Text>Some text</Text>
</TouchableOpacity>
)
React-Native doesnt provide onClick functionality , it gives onPress instead , so replace onClick with onPress
const Row = props => (
<TouchableOpacity onPress={() => props.handlePress(props.imdbID)} style={styles.row}>
<Text>Some text</Text>
</TouchableOpacity>
)
hope this helps ,feel free for doubts
Use onPress() instead of of onClick()
improved code
const Row = props => (
<TouchableOpacity onPress={()=> props.handlePress(props.imdbID)} style={styles.row}>
<Text>Some text</Text>
</TouchableOpacity>
)
Use onPress instead of onClick and be sure you are importing touchable from react-native not gesture-handler
React native does not have onClick for TouchableOpacity.
Use onPress instead.

React-Native another VirtualizedList-backed container

After upgrading to react-native 0.61 i get a lot of warnings like that:
VirtualizedLists should never be nested inside plain ScrollViews with the same orientation - use another VirtualizedList-backed container instead.
What is the other VirtualizedList-backed container that i should use, and why is it now advised not to use like that?
If someone's still looking for a suggestion to the problem that #Ponleu and #David Schilling have described here (regarding content that goes above the FlatList), then this is the approach I took:
<SafeAreaView style={{flex: 1}}>
<FlatList
data={data}
ListHeaderComponent={ContentThatGoesAboveTheFlatList}
ListFooterComponent={ContentThatGoesBelowTheFlatList} />
</SafeAreaView>
You can read more about this here: https://facebook.github.io/react-native/docs/flatlist#listheadercomponent
Hopefully it helps someone. :)
Just in case this helps someone, this is how I fixed the error in my case.
I had a FlatList nested inside a ScrollView:
render() {
return (
<ScrollView>
<Text>{'My Title'}</Text>
<FlatList
data={this.state.myData}
renderItem={({ item }) => {
return <p>{item.name}</p>;
}}
/>
{this.state.loading && <Text>{'Loading...'}</Text>}
</ScrollView>
);
}
and I got rid of the ScrollView by using the FlatList to render everything I needed, which got rid of the warning:
render() {
const getHeader = () => {
return <Text>{'My Title'}</Text>;
};
const getFooter = () => {
if (this.state.loading) {
return null;
}
return <Text>{'Loading...'}</Text>;
};
return (
<FlatList
data={this.state.myData}
renderItem={({ item }) => {
return <p>{item.name}</p>;
}}
ListHeaderComponent={getHeader}
ListFooterComponent={getFooter}
/>
);
}
The best way is to disable that warning because sometimes Flatlist need to be in ScrollView.
UPDATE RN V0.63 ABOVE
YellowBox is now changed and replace with LogBox
FUNCTIONAL
import React, { useEffect } from 'react';
import { LogBox } from 'react-native';
useEffect(() => {
LogBox.ignoreLogs(['VirtualizedLists should never be nested']);
}, [])
CLASS BASED
import React from 'react';
import { LogBox } from 'react-native';
componentDidMount() {
LogBox.ignoreLogs(['VirtualizedLists should never be nested']);
}
UPDATE RN V0.63 BELOW
FUNCTIONAL
import React, { useEffect } from 'react';
import { YellowBox } from 'react-native';
useEffect(() => {
YellowBox.ignoreWarnings(['VirtualizedLists should never be nested']);
}, [])
CLASS BASED
import React from 'react';
import { YellowBox } from 'react-native';
componentDidMount() {
YellowBox.ignoreWarnings(['VirtualizedLists should never be nested']);
}
Data
// dummy data array
const data = [
{id: 1, name: 'Tom'},
{id: 2, name: 'Jerry'},
]
Solution #1
You can make a custom component for that like this
const VirtualizedList = ({children}) => {
return (
<FlatList
data={[]}
keyExtractor={() => "key"}
renderItem={null}
ListHeaderComponent={
<>{children}</>
}
/>
)
}
then use this VirtualizedList as parent component:
...
return (
<VirtualizedList>
<FlatList
data={data}
keyExtractor={(item, index) => item.id + index.toString()}
renderItem={_renderItem}
/>
<AnyComponent/>
</VirtualizedList>
)
Solution #2
If you use FlatList inside the ScrollView it gives warning which is annoying, so you can use array's map property, like this -
NOTE: It is not recommended way to show list. If you have small amount of that then you can use it that's totally fine, but if you want to show a list which get data from api and have lot's of data then you can go with other solutions. if you use map with large data then it affect your app performance
<ScrollView>
{data.map((item, index) => (
<View key={index}>
<Text>{item.name}</Text>
</View>
))}
</ScrollView>
Solution #3
if you make your FlatList horizontal (as per your need) then also warning will disappear
<ScrollView>
<FlatList
data={data}
keyExtractor={(item, index) => item.id + index.toString()}
horizontal={true}
/>
</ScrollView>
Solution #4
you can add header and footer component
In ListHeaderComponent and ListFooterComponent you can add any component so you don't need parent ScrollView
<FlatList
data={data}
keyExtractor={(item, index) => item.id + index.toString()}
ListHeaderComponent={headerComponent}
ListFooterComponent={footerComponent}
ListEmptyComponent={emptyComponent}
ItemSeparatorComponent={separator}
/>
// List components
const headerComponent = () => (
<View>
<Header/>
<Any/>
</View>
)
const footerComponent = () => (
<View>
<Footer/>
<Any/>
</View>
)
const emptyComponent = () => (
<View>
<EmptyView/>
<Any/>
</View>
)
const separator = () => (
<View style={{height: 0.8, width: '100%', backgroundColor: '#fff'}} />
)
The warning appears because ScrollView and FlatList share the same logic, if FlatList run inside ScrollView, it's duplicated
By the way SafeAreaView doesn't work for me, the only way to solve is
<ScrollView>
{data.map((item, index) => {
...your code
}}
</ScrollView>
The error disappears
Looking at the examples in docs I've changed container from:
<ScrollView>
<FlatList ... />
</ScrollView>
to:
<SafeAreaView style={{flex: 1}}>
<FlatList ... />
</SafeAreaView>
and all those warnings disappeared.
In my case, I needed to have FlatLists nested in a ScrollView because I am using react-native-draggable-flatlist to move ingredients and steps around in a recipe.
If we read the warning properly, it says that we should use another VirtualizedList-backed container to nest our child FlatList in. What I did is:
/* outside the component */
const emptyArry = []
/* render */
<FlatList
scrollEnabled={false}
horizontal
data={emptyArray}
ListEmptyComponent=(<DraggableList />)
/>
No more warning, and I think this is the pattern recommended by the warning.
<ScrollView horizontal={false} style={{width: '100%', height: '100%'}}>
<ScrollView horizontal={true} style={{width: '100%', height: '100%'}}>
<FlatList ... />
</ScrollView>
</ScrollView>
Below code works perfectly for me to disable annoying error:
VirtualizedLists should never be nested inside plain ScrollViews with the same orientation because it can break windowing and other functionality - use another VirtualizedList-backed container instead.
React Native 0.68.2
<ScrollView horizontal={false} style={{flex: 1}}>
<ScrollView
horizontal={true}
contentContainerStyle={{width: '100%', height: '100%'}}>
<FlatList ... />
</ScrollView>
</ScrollView>
I tried some ways to solve this, including ListHeaderComponent or ListFooterComponent, but it all didn't fit for me.
layout I wanted to achieve is like this, and I wanted to get scrolled in once.
<ScrollView>
<View>I'm the first view</View>
<View>I'm the second view</View>
<MyFlatList />
</ScrollView>
First I want to say thanks to this issue and comments, which gave me bunch of ideas.
I was thinking of ListHeaderComponent places above the Flatlist, but since my Flatlist's direction was column, the header I wanted to place went on the left of the Flatlist :(
Then I had to try on VirtualizedList-backed thing. I just tried to pack all components in VirtualizedList, where renderItems gives index and there I could pass components conditionally to renderItems.
I could have worked this with Flatlist, but I haven't tried yet.
Finally it looks like this.
<View>
<Virtualizedlist
data={[]}
initialNumToRender={1}
renderItem={(props)=>{
props.index===0 ? (1st view here) : props.index===1 ? (2nd view here) : (my flatlist)
}}
keyExtractor={item => item.key}
getItemCount={2}
getItem={ (data, index) => {
return {
id: Math.random().toString(12).substring(0),
}
}}
/>
</View>
(inside which lazyly renders↓)
<View>I'm the first view</View>
<View>I'm the second view</View>
<MyFlatList />
and of course able to scroll the whole screen.
As #Brahim stated above, setting the horizontal property to true seem to resolve the issues for a FlatList embedded in a ScrollView.
So I faced the same problem while using a picker-based component inside <ScrollView> and the one thing that helped me solve the problem was adding
keyboardShouldPersistTaps={true} inside the <ScrollView> as a prop.
This is my code snippet.
<ScrollView keyboardShouldPersistTaps={true}>
<SelectionDD studentstatus={studentStatus}/>
<SearchableDD collegeNames={collegeNames} placeholder='University'/>
</ScrollView>
I have two Flatlist; each of them has many Item also has a feature to collapse and expand.
Because of that, I can't use SafeAreaView.
I saw another solution and found a new way.
I define one Flatlist in the core component ( without Scrollview) and render each Flatlist with a map function inside ListHeaderComponent and ListFooterComponent.
<View style={{flex: 1}}>
<FlatList
style={{backgroundColor: 'white'}}
refreshing={loading}
onRefresh={() => sample()}
ListHeaderComponent = {
<View>
{collapse/expandComponent}
{this.state.sample1&& content1.map((item, index) => this.renderList1(item,index))}
</View>
}
ListFooterComponent = {
<View>
{collapse/expandComponent}
{this.state.sample2 && content2.map((item, index) => this.renderlist2(item,index))}
</View>
}
/>
</View>
In my opinion i can use map instead of FlatList. But in my case i wan't to show large list. Not using FlatList may cause performance issue. so i used this to suppress warning https://github.com/GeekyAnts/NativeBase/issues/2947#issuecomment-549210509
Without hiding YellowBox you still can implement scroollable view inside scrollable view. You can use this library. It replace the default Scrollview from React Native.
This may help someone down the line, be sure you to check how your components are nested. Removing the ScrollView from the top component fixed the issue.
I ran into this issue because I had two components nested like this essentially:
Component 1
<ScrollView>
<OtherStuff />
<ListComponent />
</ScrollView>
My second component 'ListComponent' had a FlatList already wrapped with SafeAreaView.
<SafeAreaView style={styles.container}>
<FlatList
data={todoData}
renderItem={renderItem}
ItemSeparatorComponent={() => <View style={styles.separator} />}
keyExtractor={item => item.id.toString()}
/>
</SafeAreaView>
In the end I replaced the ScrollView from the first component with a View instead.
Use flatList like this ListHeaderComponent and ListFooterComponent:
<FlatList ListHeaderComponent={
<ScrollView
style={styles.yourstyle}
showsVerticalScrollIndicator={false}
>
<View style={styles.yourstyle}>
</View>
</ScrollView>
}
data={this.state.images}
renderItem={({ item, index }) => {
return (
<View
style={styles.yourstyle}
>
<Image
source={{
uri: item,
}}
style={styles.yourstyle}
resizeMode={"contain"}
/>
<Text
numberOfLines={2}
ellipsizeMode="tail"
style={styles.yourstyle}
>
{item.name}
</Text>
</View>
);
}}
keyExtractor={({ name }, index) => index.toString()}
ListFooterComponent={
<View style={styles.yourstyle}></View>
}
/>
If you use ScrollView and FlatList together you'll get inconsistent scroll behaviour.
So just remove ScrollView and use FlatList in a View.
<View flex={1}>
<FlatList
data={list}
renderItem={({ item }) => this.renderItem(item) }
keyExtractor={item => item.id}
/>
</View>
import React from 'react';
import { FlatList, ScrollViewProps } from 'react-native';
export const ScrollView: React.FC<ScrollViewProps> = props => {
return (
<FlatList
{...props}
data={[]}
renderItem={() => null}
ListHeaderComponent={() => (
<React.Fragment>{props.children}</React.Fragment>
)}
ListEmptyComponent={null}
keyExtractor={() => 'blank'}
/>
);
};
This will essentially work exactly like a ScrollView except without this error.
I was having this issue using a scrollview as parent view, and nesting a SelectBox from react-native-multi-selectbox package. I was able to solve this by adding listOptionProps={{nestedScrollEnabled: true}} like this:
<ScrollView>
<SelectBox
label="Select single"
options={serverData}
listOptionProps={{nestedScrollEnabled: true}}
value={input.elementSelected}
onChange={event =>
inputHandlerLang('elementSelected', event, key)
}
hideInputFilter={false}
/>
</ScrollView>
the error still present but scrolling within SelectBox works as well as within the parent scrollview. I also do have to suppress the error with LogBox. I don't know if there are any drawbacks to this but I'll try to test this more.
Update 1: this used to work in v0.68.2, but since I updated to patch v0.68.5, the warning became an error.
You have to remove ScrollView and enable scroll from FlatList using the property scrollEnabled={true}, you can place the other views inside ListHeaderComponent and ListFooterComponent
<View flex={1}>
<FlatList
data={data}
scrollEnabled={true}
showsVerticalScrollIndicator={false}
renderItem={({ item }) => (
<Text>{item.label}</Text>
)}
keyExtractor={item => item.id}
ListHeaderComponent={() => (
<Text>Title</Text>
)}
ListFooterComponent={() => (
<Text>Footer</Text>
)}
/>
</View>
Actually as I know, using nested VirtualizedLists, caused always performance issues, just the warning to that issue is new. I tried everything I found on the internet, non of them helped. I use now ScrollView or when you just have a normall View with maxHeight then you will be able to scroll if the content-height is bigger then the maxHeight of you View.
So:
<ScrollView>
{items.map((item, index) =>
<YourComponent key={index} item={item} />
)}
</ScrollView>
Or just:
<View style={{maxHeight: MAX_HEIGHT}}>
{items.map((item, index) =>
<YourComponent key={index} item={item} />
)}
</View>
This error disappeared because of using FlatList inside ScrollView. You can write like the following code.
<SafeAreaView style={styles.container}>
<View style={styles.container}>
<View>
<Header />
</View>
{(list.length == 0) &&
<View style={{flex:1, margin: 15}}>
<Text style={{textAlign: 'center'}}>No peripherals</Text>
</View>
}
<FlatList
data={list}
renderItem={({ item }) => this.renderItem(item) }
keyExtractor={item => item.id}
/>
</View>
</SafeAreaView>
You can add horizontal=True and contentContainerStyle={{ width: '100%' }} to the ScrollView parent.
<ScrollView
style={styles.collaborators}
contentContainerStyle={{ width: '100%' }} <--
horizontal <--
>
<FlatList
data={list?.slice(0, 10) || []}
keyExtractor={item => item.cc}
ItemSeparatorComponent={Separator}
renderItem={({ item }) => (
<Collaborator name={item.name} cc={item.cc} />
)}
/>
</ScrollView>
This worked for me (as a bit of a hack). Use a FlatList with empty data and null renderItem props instead of using a ScrollView
const emptyData = [];
const renderNullItem = () => null;
const App = () => {
const ListFooterComponent = (
<FlatList ... />
);
return (
<SafeAreaView>
<FlatList
data={emptyData}
renderItem={renderNullItem}
ListFooterComponent={ListFooterComponent}
/>
</SafeAreaView>
);
};
I had the same issue, and just got rid of it by removing the ScrollView around the FlatList. Because by default FlatList provides Scroll Functionality based on the length of content that it renders. 😊

Is there a way to have "onPress" and "onLongPress" on same "Button/TouchableOpacity"

I am wondering if there is a way to have onPress and onLongPress on the same button/TouchableOpacity, in react-native with javascript,
If so how do I do that?
Yes, according to the docs, you can add an onPress and onLongPress props.
For the record, TouchableOpacity inherits all the props available on TouchableWithoutFeedback.
<TouchableOpacity
onPress={() => { console.log("onPress") }}
onLongPress={() => { console.log("onLongPress") }}
>
...
</TouchableOpacity>

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