I am trying to get the key of a JS Object in Typescript from an input value, the problem is that the values are inside an Array.
This is what I have seen in the case that the value is not in an array:
const exampleObject = {
key1: 'Geeks',
key2: 'Javascript'
};
function getKeyByValue(object, value) {
for (var prop in object) {
if (object.hasOwnProperty(prop)) {
if (object[prop] === value)
return prop;
}
}
}
console.log(getKeyByValue(exampleObject,'Geeks')) // key1
This is an example of my object that I want to get the key from:
const exampleObject = {
key1: ['Geeks','test1','test2'],
key2: ['Javascript','test3','test4']
};
function getKeyByValue(object, value) {
for (var prop in object) {
if (object.hasOwnProperty(prop)) {
if (object[prop] === value)
return prop;
}
}
}
console.log(getKeyByValue(exampleObject,'Geeks')) // undefined
I need to get the key without using Array.prototype.includes(), because typing the resulting variable as String gives me an error that it may be undefined.
My problem: I don't know how to go through the array inside the function to find the value and get the key
Update:
What I want is to avoid the possibility of returning an undefined, since the input value will always be inside the object, how can I achieve this?
#segmet
You can use my code
const exampleObject = {
key1: ['Geeks', 'test1', 'test2'],
key2: ['Javascript', 'test3', 'test4']
};
function getKeyByValue(object, value) {
var output = "";
for (var prop in object) {
// finding and removing element from array
object[prop].find(i => {
if (i === value) {
output = prop;
return prop;
}
}
)
}
return output
}
console.log(getKeyByValue(exampleObject, 'Geeks'))
You can achieve this with a single line of code by using 3 JavaScript methods - Object.keys(), Array.find() & Array.indexOf() :
const exampleObject = {
key1: ['Geeks','test1','test2'],
key2: ['Javascript','test3','test4']
};
function getKeyByValue(object, value) {
const res = Object.keys(exampleObject).find(key => exampleObject[key].indexOf(value) !== -1);
return res || ''
}
console.log(getKeyByValue(exampleObject,'Geeks'))
function getKeyByValue(object, value) {
const key = Object.entries(object).filter(([key, val]) => val.includes(value));
return Object.fromEntries(key);
}
Try this function instead
You will get the object matching your keys
You can do something like this and then check for null
const getKeyFromValue = (obj:Object, value:string | string[]) => {
for (let key in obj) {
if (typeof value === 'string') {
if (obj[ key ].includes(value)) {
return key;
}
}
else if (Array.isArray(value)) {
if (obj[ key ].every(val => value.includes(val))) {
return key;
}
}
}
return null;
}
One more try:
const exampleObject = {
key1: ['Geeks','test1','test2'],
key2: ['Javascript','test3','test4']
};
function getKeyByValue(obj, data) {
for (const [key, value] of Object.entries(obj)) {
return (~value.indexOf(data)) ? key : false
}
}
console.log(getKeyByValue(exampleObject,'Geeks'))
I am trying to convert a nested object to a string indexed object, so I can use Vue to display all properties in an object. For example:
var obj = {
key1: 'value1',
key2: {
key3: {
key5: 'value5',
key6: 'value6'
},
key4: 'value4'
}
};
Should be convert to this:
var obj = {
'key1': 'value1',
'key2.key3.key5': 'value5',
'key2.key3.key6': 'value6',
'key2.key4': 'value4'
}
I tried to walk recursively through the object, but I didn't figure out how to get the correct index value and return both the index and the object at the same time.
What I've tried so far:
// let result = objConversion(obj)
objConversion (obj) {
let resultObject = {}
// Walk through the first level
for (let index in obj) {
if (obj.hasOwnProperty(index)) {
let extractedObj = getObjNameRecursive(obj[ index ], index)
resultObject = { ...resultObject, ...extractedObj }
}
}
return resultObject
}
getObjNameRecursive (obj, name) {
let resultObject = {}
if (typeof obj === 'object') {
// Dive into an object
for (let index in obj) {
if (obj.hasOwnProperty(index)) {
if (typeof obj[ 'index' ] === 'object') {
resultObject = { ...resultObject, ...getObjNameRecursive(obj[ 'index' ], name + '.' + index) }
} else {
resultObject = {...resultObject, [name + '.' + index]: obj[index]}
}
}
}
} else {
// Simple assign if not an object
resultObject[ name ] = obj
}
return resultObject
}
But this gives the result like:
obj = {
'key1': 'value1',
'key2.key3.key5': [object Object],
'key2.key3.key6': [object Object],
'key2.key4': 'value4'
}
The answer in Convert string to an attribute for a nested object in javascript is very close to what I want. But what I want is to get the string of attributes of a nested object.
Is there any better way to do this?
Thanks.
Try this
function convert(obj, key, result) {
if(typeof obj !== 'object') {
result[key] = obj;
return result;
}
const keys = Object.keys(obj);
for(let i = 0; i < keys.length; i++){
const newKey = key ? (key + '.' + keys[i]) : keys[i];
convert(obj[keys[i]], newKey, result);
}
return result;
}
call it
convert(obj, '', {});
I have an object:
const oData = {
name: 'Hound',
weapon: 'sword',
likes: 'Chicken, Arya, Revenge',
dislikes: 'Fire, Mountain, Lannisters'
};
which I pass to this function:
fConvertValuesToArrays(obj) {
for (const i in obj) {
obj[i] = Array.isArray(obj[i]) ? obj[i] : [obj[i]];
}
return obj;
},
This works as expected in converting all the values into arrays but I now need this to only execute if the value matches with any of the values in this array:
const aNamesToMatch = [ 'likes', 'dislikes' ];
Is it possible to work this into the function or do I need a separate function for this and call that function inside fConvertValuesToArrays?
If so how would that work?
I tried to add an if statement before the ternary but I did not work as expected:
fConvertValuesToArrays(obj) {
for (const i in obj) {
if ( obj.likes || obj.dislikes ) {
obj[i] = Array.isArray(obj[i]) ? obj[i] : [obj[i]];
}
}
return obj;
},
You can use includes() on the array aNamesToMatch. And check if current key is inside that array.
const oData = {
name: 'Hound',
weapon: 'sword',
likes: 'Chicken, Arya, Revenge',
dislikes: 'Fire, Mountain, Lannisters'
};
const aNamesToMatch = [ 'likes', 'dislikes' ];
function fConvertValuesToArrays(obj,keys) {
for (const i in obj) {
if (keys.includes(i)) {
obj[i] = Array.isArray(obj[i]) ? obj[i] : [obj[i]];
}
}
return obj;
}
console.log(fConvertValuesToArrays({...oData},aNamesToMatch))
Instead of looping through the entire object, you can just loop through aNamesToMatch. Update each of those properties in the object to an array:
const aNamesToMatch=['likes','dislikes'],
oData={name:'Hound',weapon:'sword',likes:'Chicken, Arya, Revenge',dislikes:'Fire, Mountain, Lannisters'};
function fConvertValuesToArrays(obj, keys) {
for (const key of keys) {
if (!Array.isArray(obj[key]))
obj[key] = [obj[key]]
}
return obj;
}
console.log(fConvertValuesToArrays(oData, aNamesToMatch))
If there is a possibility of having a key in the array which doesn't exist in the object, you can check if the key exists in the object first:
if (key in obj && !Array.isArray(obj[key])) {
}
Make this change
if(i == 'likes' || i == 'dislikes')
{
obj[i] = Array.isArray(obj[i]) ? obj[i] : [obj[i]];
}
This will check if the key is likes/dislikes and creates an array only if that is the case.
If I have a flat object then this works:
let stateCopy={...this.state}
Object.entries(dictionary).map(([key,value])=>{
stateCopy.key = value.toString())
})
Is there a way to do this if dictionary contains a nested object. Suppose a dictionary looks like:
dictionary={left:{name:'WORK',
min:2,
sec:0,}
start:true}
I need some way of updating stateCopy, i.e
stateCopy.left.name='WORK'
stateCopy.left.min=2
stateCopy.left.sec=0
stateCopy.start=true
function flattenDictionary(dict) {
if (!dict) {
return {};
}
/** This will hold the flattened keys/values */
const keys = {};
// Perform the flatten
flattenH(dict);
return keys;
function flattenH(obj, prefix) {
Object.keys(obj).forEach((key) => {
const val = obj[key];
/** This is what we pass forward as a new prefix, or is the flattened key */
let passKey;
// Only expect to see this when the original dictionary is passed as `obj`
if (!prefix || prefix === '') {
passKey = key;
} else {
// "Ignore" keys that are empty strings
passKey = ((key === '') ? prefix : `${prefix}.${key}`);
}
if (typeof obj[key] !== 'object') {
keys[passKey] = val;
} else {
flattenH(val, passKey);
}
});
}
}
Seems like you can do this with a little recursive function:
let state = {
left:{
start: "mark",
anotherLevel: {
test: 'leveltest'
}
},
test: "will be replaced"
}
let dictionary={
test2: {
foo: 'bar'
},
left:{
name:'WORK',
min:2,
sec:0,
anotherLevel: {
test_add: 'leveltest_add'
}
},
start:true,
test: 'replaced with me'
}
let stateCopy={...state}
function merge(obj, dict){
Object.entries(dict).forEach(([k, v]) =>{
if (!obj[k] || typeof v !== 'object') obj[k] = v
else merge(obj[k], v)
})
}
merge(stateCopy, dictionary)
console.log(stateCopy)
I have a javascript object width depth.
I need to know the exact path from this key within the object ex: "obj1.obj2.data1"
I already know the key is data1, the value is 123.
My javascript object look like this
{
obj1: {
obj2: {
data1: 213,
data2: "1231",
obj3: {
data: "milf"
}
}
},
obj4: {
description: "toto"
}
}
How could I achieve that ?
here is a jsfiddle : http://jsfiddle.net/3hvav8xf/8/
I am trying to implement getPath.
I think recursive function can help to you (Updated version, to check value)
function path(c, name, v, currentPath, t){
var currentPath = currentPath || "root";
for(var i in c){
if(i == name && c[i] == v){
t = currentPath;
}
else if(typeof c[i] == "object"){
return path(c[i], name, v, currentPath + "." + i);
}
}
return t + "." + name;
};
console.log(path({1: 2, s: 5, 2: {3: {2: {s: 1, p: 2}}}}, "s", 1));
The following finds the path in any level of nested objects. Also with arrays.
It returns all the paths found, which is something you want if you have keys with the same name.
I like this approach because it works with lodash methods get and set out-of-the-box.
function findPathsToKey(options) {
let results = [];
(function findKey({
key,
obj,
pathToKey,
}) {
const oldPath = `${pathToKey ? pathToKey + "." : ""}`;
if (obj.hasOwnProperty(key)) {
results.push(`${oldPath}${key}`);
return;
}
if (obj !== null && typeof obj === "object" && !Array.isArray(obj)) {
for (const k in obj) {
if (obj.hasOwnProperty(k)) {
if (Array.isArray(obj[k])) {
for (let j = 0; j < obj[k].length; j++) {
findKey({
obj: obj[k][j],
key,
pathToKey: `${oldPath}${k}[${j}]`,
});
}
}
if (obj[k] !== null && typeof obj[k] === "object") {
findKey({
obj: obj[k],
key,
pathToKey: `${oldPath}${k}`,
});
}
}
}
}
})(options);
return results;
}
findPathsToKey({ obj: objWithDuplicates, key: "d" })
// ["parentKey.arr[0].c.d", "parentKey.arr[1].c.d", "parentKey.arr[2].c.d"]
Try it here - https://jsfiddle.net/spuhb8v7/1/
If you want the result to be a single key (first encountered), you can change the results to be a string and if defined, then return the function with it.
I ended up with the following function, that works with nested objects/arrays :
function findPath (obj, name, val, currentPath) {
currentPath = currentPath || ''
let matchingPath
if (!obj || typeof obj !== 'object') return
if (obj[name] === val) return `${currentPath}['${name}']`
for (const key of Object.keys(obj)) {
if (key === name && obj[key] === val) {
matchingPath = currentPath
} else {
matchingPath = findPath(obj[key], name, val, `${currentPath}['${key}']`)
}
if (matchingPath) break
}
return matchingPath
}
const treeData = [{
id: 1,
children: [{
id: 2
}]
}, {
id: 3,
children: [{
id: 4,
children: [{
id: 5
}]
}]
}]
console.log(findPath (treeData, 'id', 5))
Here you go!
function getPath(obj, value, path) {
if(typeof obj !== 'object') {
return;
}
for(var key in obj) {
if(obj.hasOwnProperty(key)) {
console.log(key);
var t = path;
var v = obj[key];
if(!path) {
path = key;
}
else {
path = path + '.' + key;
}
if(v === value) {
return path;
}
else if(typeof v !== 'object'){
path = t;
}
var res = getPath(v, value, path);
if(res) {
return res;
}
}
}
}
getPath(yourObject, valueYouWantToFindPath);
Rerutns path if found, else returns undefined.
I have only tested it with objects & comparison is very strict(ie: used ===).
Update:
Updated version that takes key as an argument.
function getPath(obj, key, value, path) {
if(typeof obj !== 'object') {
return;
}
for(var k in obj) {
if(obj.hasOwnProperty(k)) {
console.log(k);
var t = path;
var v = obj[k];
if(!path) {
path = k;
}
else {
path = path + '.' + k;
}
if(v === value) {
if(key === k) {
return path;
}
else {
path = t;
}
}
else if(typeof v !== 'object'){
path = t;
}
var res = getPath(v, key, value, path);
if(res) {
return res;
}
}
}
}
getPath(yourObject, key, valueYouWantToFindPath);
JSON Object can be handled in JavaScript as associative array.
So You can cycle through and store indexes of "parents" in some variables.
Assume the whole object to be stored in variable called obj.
for( var p1 in obj )
{
for( var p2 in obj[ p1 ] )
{
for( var p3 in obj[ p1 ][ p2 ] )
{
// obj[ p1 ][ p2 ][ p3 ] is current node
// so for Your example it is obj.obj1.obj2.data1
}
}
}
Hope answer was helpful.
I would do this job as follows;
Object.prototype.paths = function(root = [], result = {}) {
var ok = Object.keys(this);
return ok.reduce((res,key) => { var path = root.concat(key);
typeof this[key] === "object" &&
this[key] !== null ? this[key].paths(path,res)
: res[this[key]] == 0 || res[this[key]] ? res[this[key]].push(path)
: res[this[key]] = [path];
return res;
},result);
};
var myObj = {
obj1: {
obj2: {
data1: 213,
data2: "1231",
obj3: {
data: "milf"
}
}
},
obj4: {
description: "toto",
cougars: "Jodi",
category: "milf"
}
},
value = "milf",
milfPath = myObj.paths()[value]; // the value can be set dynamically and if exists it's path will be listed.
console.log(milfPath);
A few words of warning: We should be cautious when playing with the Object prototype. Our modification should have the descriptor enumerable = false or it will list in the for in loops and for instance jQuery will not work. (this is how silly jQuery is, since apparently they are not making a hasOwnProperty check in their for in loops) Some good reads are here and here So we have to add this Object method with Object.defineProperty() to make it enumerable = false;. But for the sake of simplicity and to stay in the scope of the question i haven't included that part in the code.
Here is a pretty short, and relatively easy to understand function I wrote for retrieving the JSON Path for every property/field on an Object (no matter how deeply nested, or not).
The getPaths(object) function just takes the Object you'd like the JSON Paths for and returns an array of paths. OR, if you would like the initial object to be denoted with a symbol that is different from the standard JSON Path symbol, $, you can call getPaths(object, path), and each JSON Path will begin with the specified path.
For Example: getPaths({prop: "string"}, 'obj'); would return the following JSON Path: obj.prop, rather than $.prop.
See below for a more detailed, in depth example of what getPaths returns, and how it is used.
object = {
"firstName": "John",
"lastName": "doe",
"age": 26,
"fakeData": true,
"address": {
"streetAddress": "fake street",
"city": "fake city",
"postalCode": "12345"
},
"phoneNumbers": [{
"type": "iPhone",
"number": "0123-4567-8888"
}, {
"type": "home",
"number": "0123-4567-8910"
}]
};
function getPaths(object, path = "$") {
return Object.entries(object).flatMap(function(o, i) {
if (typeof o[1] === "object" && !o[1].length) {
return `${getPaths(o[1], path + '.' + o[0])}`.split(',');
} else if (typeof o[1] === "object" && o[1].length) {
return Object.entries(o[1]).flatMap((no, i) => getPaths(no[1], `${path}.${o[0]}[${i}]`));
} else {
return `${path}.${o[0]}`;
}
});
}
console.log(`%o`, getPaths(object));
I really liked Roland Jegorov's answer, but I had a very complex object that I needed to search through and that answer could not account for it.
If you were in a situation like mine you may want to first make sure you have no circular references (or else you'll run into an infinite search). There are a few ways to do this, but I was having to stringify my object to copy it into other windows, so I ended up using this circular replacer: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Errors/Cyclic_object_value
(Update here - I made a small change to the getCircularReplacer function from MDN so it no longer leaves out function references since that is what I was looking for!)
(Update 3 - I also wanted to check on methods of any instances of classes, but I was returning just 'function' too early, so I have adjusted it to include instance methods. I think it finally works as I intended!)
const getCircularReplacer = () => {
const seen = new WeakSet();
return (key, value) => {
if (typeof value === "function") {
if (value?.prototype) {
if (seen.has(value.prototype)) {
return;
}
seen.add(value.prototype)
return value.prototype
}
return "function";
}
if (typeof value === "object" && value !== null) {
if (seen.has(value)) {
return;
}
seen.add(value);
}
return value;
};
};
const nonCyclicObject = JSON.parse(JSON.stringify(myComplexObject, getCircularReplacer()));
Then I used this modified version of Roland's answer:
(Update 2: I had to make sure not to return after the key was found as it would always simply return after only calling the function once if the first level of the object had that key)
function findPathsToKey(options) {
let count = 0;
let results = [];
(function findKey({
key,
obj,
pathToKey,
}) {
count += 1;
if (obj === null) return;
const oldPath = `${pathToKey ? pathToKey + "." : ""}`;
if (Object.hasOwnProperty.call(obj, key)) {
results.push(`${oldPath}${key}`);
}
if (typeof obj === "object" && !Array.isArray(obj)) {
for (const k in obj) {
if (Object.hasOwnProperty.call(obj, k)) {
if (Array.isArray(obj[k])) {
for (let j = 0; j < obj[k].length; j++) {
findKey({
obj: obj[k][j],
key,
pathToKey: `${oldPath}${k}[${j}]`,
});
}
}
if (typeof obj[k] === "object") {
findKey({
obj: obj[k],
key,
pathToKey: `${oldPath}${k}`,
});
}
}
}
}
})(options);
return { count, results };
};
The count was just to troubleshoot a little bit and make sure it was actually running through the amount of keys I thought it was. Hope this helps any others looking for a solution!
⚠️ This code doesn't answer the question but does related: transforms nested object to query object with dot.divided.path as keys and non-object values; compatible with URlSearchParams & qs. Maybe will be useful for someone.
const isPlainObject = (v) => {
if (Object.prototype.toString.call(v) !== '[object Object]') return false;
const prototype = Object.getPrototypeOf(v);
return prototype === null || prototype === Object.prototype;
};
const objectToQueryObject = (obj, path) => {
return Object.entries(obj).reduce((acc, [key, value]) => {
const newPath = path ? `${path}.${key}` : key;
if (isPlainObject(value)) {
return {
...acc,
...objectToQueryObject(value, newPath)
};
}
acc[newPath] = value;
return acc;
}, {})
};
const queryObjectRaw = {
value: {
field: {
array: {
'[*]': {
field2: {
eq: 'foo',
ne: 'bar',
}
}
},
someOtherProp: { in: [1, 2, 3],
ne: 'baz',
}
},
someOtherField: {
gt: 123
},
},
otherValue: {
eq: 2
},
};
const result = objectToQueryObject(queryObjectRaw);
console.log('result', result);
const queryString = new URLSearchParams(result).toString();
console.log('queryString', queryString);
If you know only the value and not the key, and want to find all paths with this value use this.
It will find all property with that value, and print the complete path for every founded value.
const createArrayOfKeys = (obj, value) => {
const result = []
function iter(o) {
Object.keys(o).forEach(function(k) {
if (o[k] !== null && typeof o[k] === 'object') {
iter(o[k])
return
}
if (o[k]=== value) {
result.push(k)
return
}
})
}
iter(obj)
return result
}
function findPath (obj, name, val, currentPath) {
currentPath = currentPath || ''
let matchingPath
if (!obj || typeof obj !== 'object') return
if (obj[name] === val) return `${currentPath}/${name}/${val}`
for (const key of Object.keys(obj)) {
if (key === name && obj[key] === val) {
matchingPath = currentPath
} else {
matchingPath = findPath(obj[key], name, val, `${currentPath}/${key}`)
}
if (matchingPath) break
}
return matchingPath
}
const searchMultiplePaths = (obj, value) => {
const keys = createArrayOfKeys(obj, value)
console.log(keys);
keys.forEach(key => {
console.log(findPath(obj, key, value))
})
}
var data = { ffs: false, customer: { customer_id: 1544248, z_cx_id: '123456' }, selected_items: { '3600196': [{ id: 4122652, name: 'Essential Large (up to 8\'x10\')', selected: true }] }, service_partner: { id: 3486, name: 'Some String', street: '1234 King St.', hop: '123456' }, subject: 'Project-2810191 - Orange Juice Stain (Rug)', description: 'Product Type: \n\nIssue: (copy/paste service request details here)\n\nAction Required:', yes: '123456' };
searchMultiplePaths(data, '123456')
I know the post is old but the answers don't really satisfy me.
A simple solution is to add the object path to each object in the structure. Then you can easily read the path when you need it.
let myObject = {
name: 'abc',
arrayWithObject: [
{
name: "def"
},
{
name: "ghi",
obj: {
name: "jkl"
}
}
],
array: [15, 'mno'],
arrayArrayObject: [
[
{
name: '...'
}
]
]
}
function addPath(obj, path = [], objectPathKey = '_path') {
if (Array.isArray(obj)) {
obj.map((item, idx) => addPath(item, [...path, idx]))
} else if (typeof obj === "object") {
obj[objectPathKey] = path;
for (const key in obj) {
obj[key] = addPath(obj[key], [...path, key])
}
}
return obj
}
myObject = addPath(myObject);
let changeMe = _.cloneDeep(myObject.arrayWithObject[0])
changeMe.newProp = "NEW"
changeMe.newNested = {name: "new", deeper: {name: "asdasda"}}
changeMe = addPath(changeMe, changeMe._path)
_.set(myObject, changeMe._path, changeMe);
When your updates are done sanitize your object and remove your _path property.
Advantages of this solution:
You do the work once
you keep your code simple
no need for own property checks
no cognitive overload
I can highly suggest you to use lodash for this problem.
In their documentation this should help you out
// using "_.where" callback shorthand
_.find(characters, { 'age': 1 });
// → { 'name': 'pebbles', 'age': 1, 'blocked': false }