I have a dataset that looks like this:
[
{
"name": "Item1",
"section": "section1",
"total": 3,
}, {
"name": "Item1",
"section": "section2",
"total": 4,
}{
"name": "Item1",
"section": "section3",
"total": 7,
}, {
"name": "Item2",
"section": "section1",
"total": 1,
}, {
"name": "Item2",
"section": "section2",
"total": 2,
}, {
"name": "Item2",
"section": "section3",
"total": 3,
}
]
I need to sort the array by only the total value in the section 3 item, but maintain the order (section1, section2, then section 3) per name. So for this example Item2 should move all 3 of it's rows above Item1. I've tried sorting by multiple items, but that doesn't maintain the ordering that I need. Should I just get the smallest/biggest, grab the related items and put them into a new array and repeat or is there a more logical way to accomplish this?
I'm also using angular and primeng grid if there's something I can leverage in there.
I would create a map using the name as the key and the total as the value for items where section equals section3. You can then sort using the map.
This will sort all items by the value of the total in section3, and preserve the original sort order where the sort value matches.
const map = new Map<string, number>(this.data
.filter(x => x.section === 'section3')
.map(x => [ x.name, x.total ]));
this.sorted = this.data.slice()
.sort((a, b) => map.get(a.name) - map.get(b.name));
This does rely on the data being structured and ordered as your have specified in your question.
DEMO: https://stackblitz.com/edit/angular-fsswdq
You could
collect all object of the same group and get the total for sorting,
sort by the groups total value,
get a flat array of all objects.
const
data = [{ name: "Item1", section: "section1", total: 3 }, { name: "Item1", section: "section2", total: 4 }, { name: "Item1", section: "section3", total: 7 }, { name: "Item2", section: "section1", total: 1 }, { name: "Item2", section: "section2", total: 2 }, { name: "Item2", section: "section3", total: 3 }],
result = Object
.values(data.reduce((r, o) => {
r[o.name] = r[o.name] || { payload: [] };
r[o.name].payload.push(o);
if (o.section === 'section3') r[o.name].total = o.total;
return r;
}, {}))
.sort(({ total: a }, { total: b }) => a - b)
.flatMap(({ payload }) => payload);
console.log(result);
.as-console-wrapper { max-height: 100% !important; top: 0; }
Priority sort
const data = [{"name":"Item1","section":"section1","total":3},{"name":"Item1","section":"section2","total":4},{"name":"Item1","section":"section3","total":7},{"name":"Item2","section":"section1","total":1},{"name":"Item2","section":"section2","total":2},{"name":"Item2","section":"section3","total":3}];
console.log(
data.sort((a, b) => {
const diff = a.total - b.total;
if (diff) return diff;
return b.section.localeCompare(a.section);
})
);
.as-console-row {color: blue!important}
var array = [
{
"name": "Item1",
"section": "section1",
"total": 3,
}, {
"name": "Item1",
"section": "section2",
"total": 4,
},{
"name": "Item1",
"section": "section3",
"total": 7,
}, {
"name": "Item2",
"section": "section1",
"total": 1,
}, {
"name": "Item2",
"section": "section2",
"total": 2,
}, {
"name": "Item2",
"section": "section3",
"total": 3,
}
];
array = array.sort((o1, o2)=>{
if(o1.section === o2.section && o1.section === 'section3') {
return o1.total - o2.total;
} else {
return o1.section === 'section3' ? 1 : -1;
}
});
console.log(array);
Here's the output
[
{
"name": "Item1",
"section": "section1",
"total": 3
},
{
"name": "Item1",
"section": "section2",
"total": 4
},
{
"name": "Item2",
"section": "section1",
"total": 1
},
{
"name": "Item2",
"section": "section2",
"total": 2
},
{
"name": "Item2",
"section": "section3",
"total": 3
},
{
"name": "Item1",
"section": "section3",
"total": 7
}
]
You first need to "Group" the data set by name and then do the sorting by total.
let items = [{
"name": "Item1",
"section": "section1",
"total": 3,
}, {
"name": "Item1",
"section": "section2",
"total": 4,
}, {
"name": "Item1",
"section": "section3",
"total": 7,
}, {
"name": "Item2",
"section": "section1",
"total": 1,
}, {
"name": "Item2",
"section": "section2",
"total": 2,
}, {
"name": "Item2",
"section": "section3",
"total": 3,
}];
let groups = {};
for (let item of items) {
if (!groups[item.name]) {
groups[item.name] = {
data: []
};
}
// Grouping by `name`
groups[item.name].data.push(item);
// Store the `total`
if (item.section == "section3") {
groups[item.name].key = item.total;
}
}
// sort the groups, this will maintain the order of sections (1,2 and 3) in each group
let sortedGroups = Object.values(groups).sort((a, b) => {
return a.key - b.key; // ascending
});
// then flatten the groups
let flatten = [].concat(...sortedGroups.map(x => x.data));
console.log(flatten);
Related
How can i make the cart_items like my expetation.. just it no more.. my problem just it :D
i just wanna make my cart_items like this.. hope you are can help me thanks. did I make the wrong method? and one more thing, i wanna make the qty inside the cart_items
this is my expectation
"cart": [
{
"id": 1,
"date": "12/10/2020",
"store": {
"id": 1,
"name": "Dirumah Aja",
"promo": 1
},
"cart_items": [
{
"id": 1,
"product": {
"id": 1,
"name": "Bakso Urat",
"price": 10000,
"promo": {
"nama": "promo"
}
},
"qty": 5
}
]
}
]
and this is what I got
"cart": [
{
"cart_items": {
"name": "Steak Sapi Impor",
"price": "38000",
"stock": "4",
"image": "https://firebasestorage.googleapis.com/v0/b/francise-fb70a.appspot.com/o/steak.jpg?alt=media&token=46e0d769-96d3-440f-8edb-5fce2481ace0",
"promo": 3,
"id": 8,
"qty": 1
},
"store": {
"name": "Amanda Foods Store",
"email": "amanda#food.com",
"store_image": "https://firebasestorage.googleapis.com/v0/b/francise-fb70a.appspot.com/o/full_hd_retina.jpeg?alt=media&token=3e602e86-661b-48ee-9e9c-af9f94a170d1",
"product": [
5,
7,
8,
2
],
"store_promo": 1,
"location": {
"street_name": "Jl. Kebon Gedang II B",
"province": "Jawa Barat",
"city": "Bandung",
"post_code": "40285"
},
"id": 1
},
"date_order": "Nov 03 2020 08:48:03",
"id": 2
}
]
This is my data
data() {
return {
promo_id: [],
promo_partner: [],
products: {},
qty: 1,
cart_items: [
{}
]
};
and this is my method
addToCart() {
const date = (new Date()).toString().split(' ').splice(1,4).join(' ')
this.products.cart_items = this.product;
this.products.cart_items.qty = this.qty;
this.products.store = this.partner;
this.products.date_order = date;
console.log(this.cart_items)
axios
.post("http://localhost:3000/cart/", this.products)
.then(() => {
swal("Belanja Berhasil!", {
icon: "success",
});
})
.catch((error) => console.log(error));
}
}
You need to use .push() to add items to an array. You're replacing the array with this.product.
if (!this.products.cart_items) { // initialize cart_items if necessary
this.products.cart_items = [];
}
this.products.cart_items.push({id: this.product.id, product: this.product, qty: this.qty});
I have the following data that is an array of nested objects:
"categories": [
{
"id": 1,
"name": "Category 1",
"years": [
{ "id": 1, "name": "1" },
{ "id": 2, "name": "2" }
]
},
{
"id": 2,
"name": "Category 2",
"years": [
{ "id": 2, "name": "2" },
{ "id": 3, "name": "3" }
]
}
]
I want to extract unique years in a separate array (desired output):
[
{ "id": 1, "name": "1" },
{ "id": 2, "name": "2" },
{ "id": 3, "name": "3" },
]
When I map out the years, I'm getting an array of arrays, how should I extract the unique objects for years?
let years = categories.map( (c) => { return c.years })
You can use a Map to filter duplicate years from the array of values using id as the key, and reduce() on both categories and years using the map as the accumulator:
const categories = [{
"id": 1,
"name": "Category 1",
"years": [
{ "id": 1, "name": "1" },
{ "id": 2, "name": "2" }
]
},
{
"id": 2,
"name": "Category 2",
"years": [
{ "id": 2, "name": "2" },
{ "id": 3, "name": "3" }
]
}
];
const years = categories.reduce(
(map, category) => category.years.reduce(
(map, year) => map.set(year.id, year),
map
),
new Map()
);
console.log([...years.values()]);
You can use reduce and Map
let data = [{"id": 1,"name": "Category 1","years": [{ "id": 1, "name": "1" },{ "id": 2, "name": "2" }]},{"id": 2,"name": "Category 2","years": [{ "id": 2, "name": "2" },{ "id": 3, "name": "3" }]}]
let final = data.reduce((op,{years}) => {
years.forEach(({id, name}) => {
let key = id + '-' + name
op.set(key, op.get(key) || {id, name})
})
return op
},new Map())
console.log([...final.values()])
I want to group By sub-work in array
Here is my array I want to group By sub-work
result = [
{
"date": "10-07-2019",
"data": [
{
"data_id": "20",
"work": "work_1",
"sub-work": "sub_work1",
"sub-data": [
{
"id": 7,
"title": 'subdata-1',
}
]
}
]
},
{
"date": "12-07-2019",
"data": [
{
"data_id": "20",
"work": "work_1",
"sub-work": "sub_work1",
"sub-data": [
{
"id": 7,
"title": 'subdata-1',
}
]
}
]
},
]
Here is what I try
result = _(result)
.map(function(items, data) {
_.groupBy(items.data, function({ sub_work }) {
return sub_work;
});
})
.value();
first I map result into data then I try to groupby but It's return null
Update
I want my output look like this
[
{
"date": "10-07-2019",
sub-work: [{
sub-work : "sub_work1",
sub-data[
{
"id": 7,
"title": 'subdata-1',
}
]
}]
}
]
...........................
It would be better if you could provide your expected result.
Here's what I could infer:
_(result)
.map(function(obj) { // Convert into a 2D array.
return obj.data.map(e => Object.assign(e, {date: obj.date}));
})
.flatten() // We have an array of objects now.
.groupBy('sub-work') // We can call groupBy().
.value();
Here's what you get:
{
"sub_work1": [{
"data_id": "20",
"work": "work_1",
"sub-work": "sub_work1",
"sub-data": [{
"id": 7,
"title": "subdata-1"
}],
"date": "10-07-2019"
}, {
"data_id": "20",
"work": "work_1",
"sub-work": "sub_work1",
"sub-data": [{
"id": 7,
"title": "subdata-1"
}],
"date": "12-07-2019"
}]
}
I have three arrays.
1. Existing viewers array - existingViewers
New viewers array - newViewers
Permitted Viewers array - permittedViewers
permittedViewers is used for rendering the drop-down. And I wish to filter the newViewers and existingViewers entries from the permittedViewers.
I am doing this as three steps. And I am afraid this is not the optimized way. Can someone suggest the ideal way of doing this?
The expected result is
[
{
"id": 4,
"name": "name4"
},
{
"id": 5,
"name": "name5"
},
{
"id": 6,
"name": "name6"
}
]
let existingViewers = [{
"viewerId": 1,
"name": "name1"
},
{
"viewerId": 2,
"name": "name2"
}
],
newViewers = [
{
"viewerId": 3,
"name": "name3"
}
],
permittedViewers = [{
"id": 1,
"name": "name1"
},
{
"id": 2,
"name": "name2"
},
{
"id": 3,
"name": "name3"
},
{
"id": 4,
"name": "name4"
},
{
"id": 5,
"name": "name5"
},
{
"id": 6,
"name": "name6"
}
]
let grouped = [...existingViewers, ...newViewers]
let viewerFilter = grouped.map(viewer => { return viewer.viewerId; });
let filteredPermittedViewers = permittedViewers.filter(viewer => !viewerFilter.includes(viewer.id));
console.log(filteredPermittedViewers)
I'd make a Set of the ids of the first two arrays, and then filter the third by whether the set includes the id. (Sets have O(1) lookup time)
let existingViewers=[{"viewerId":1,"name":"name1"},{"viewerId":2,"name":"name2"}],newViewers=[{"viewerId":3,"name":"name3"}],permittedViewers=[{"id":1,"name":"name1"},{"id":2,"name":"name2"},{"id":3,"name":"name3"},{"id":4,"name":"name4"},{"id":5,"name":"name5"},{"id":6,"name":"name6"}];
const ids = new Set([...existingViewers, ...newViewers].map(({ viewerId }) => viewerId));
const output = permittedViewers.filter(({ id }) => !ids.has(id));
console.log(output);
You can compress all three statements into a single statement -- just replace the variable name with the statement that creates it:
let existingViewers = [{
"viewerId": 1,
"name": "name1"
},
{
"viewerId": 2,
"name": "name2"
}
],
newViewers = [
{
"viewerId": 3,
"name": "name3"
}
],
permittedViewers = [{
"id": 1,
"name": "name1"
},
{
"id": 2,
"name": "name2"
},
{
"id": 3,
"name": "name3"
},
{
"id": 4,
"name": "name4"
},
{
"id": 5,
"name": "name5"
},
{
"id": 6,
"name": "name6"
}
]
let filteredPermittedViewers = permittedViewers.filter(viewer => ! [...existingViewers, ...newViewers].map(viewer => viewer.viewerId).includes(viewer.id));
console.log(filteredPermittedViewers)
So i have this data:
let data = [
{
"purchase_id": 1,
"product": [
{
"name": "A",
"id": 1,
"transactions": [
{
"price": 5,
"qty": 2
},
{
"price": 10,
"qty": 2
}
]
},
{
"name": "B",
"id": 2,
"transactions": [
{
"price": 3,
"qty": 4
}
]
}
]
},
{
"purchase_id": 2,
"product": [
{
"name": "C",
"id": 3,
"transactions": [
{
"price": 5,
"qty": 2
}
]
},
{
"name": "D",
"id": 4,
"transactions": [
{
"price": 3,
"qty": 4
}
]
}
]
}
]
And i want to flatten array from each data.product.transactions data:
"transactions": [
{
"price",
"qty"
}
]
Expected output is:
[
{
"purchase_id": 1,
"name": "A",
"id": 1,
"price": 5,
"qty": 2
},
{
"purchase_id": 1,
"name": "A",
"id": 1,
"price": 10,
"qty": 2
},
{
"purchase_id": 1,
"name": "B",
"id": 2,
"price": 3,
"qty": 4
},
{
"purchase_id": 2,
"name": "C",
"id": 3,
"price": 5,
"qty": 2
},
{
"purchase_id": 2,
"name": "D",
"id": 4,
"price": 3,
"qty": 4
},
]
I have tried to use object assign, reduce but my code doesn't work. Thank you
Use nested Array.map() to create the objects, and spread into Array.concat() to flatten the sub-arrays at each level:
const data = [{"purchase_id":1,"product":[{"name":"A","id":1,"transactions":[{"price":5,"qty":2},{"price":10,"qty":2}]},{"name":"B","id":2,"transactions":[{"price":3,"qty":4}]}]},{"purchase_id":2,"product":[{"name":"C","id":3,"transactions":[{"price":5,"qty":2}]},{"name":"D","id":4,"transactions":[{"price":3,"qty":4}]}]}];
const result = [].concat(...data.map(({ purchase_id, product }) =>
[].concat(...product.map(({ name, id, transactions }) =>
transactions.map((o) => ({
purchase_id,
name,
id,
...o
})
)))));
console.log(result);
If you want to avoid the temp sub-arrays, and the flattering, use nested Array.forEach() calls, and push the created objects to a predefined array:
const data = [{"purchase_id":1,"product":[{"name":"A","id":1,"transactions":[{"price":5,"qty":2},{"price":10,"qty":2}]},{"name":"B","id":2,"transactions":[{"price":3,"qty":4}]}]},{"purchase_id":2,"product":[{"name":"C","id":3,"transactions":[{"price":5,"qty":2}]},{"name":"D","id":4,"transactions":[{"price":3,"qty":4}]}]}];
const result = [];
data.forEach(({ purchase_id, product }) =>
product.forEach(({ name, id, transactions }) =>
transactions.forEach((o) => result.push({
purchase_id,
name,
id,
...o
})
)));
console.log(result);
var arr = [];
data.forEach(x => {
x.product.forEach(y => {
y.transactions.forEach(z => {
z["name"] = y.name;
z["id"] = y.id;
z["purchase_id"] = x.purchase_id;
arr.push(z);
});
})
});
console.log(arr);