Develop Reference

Unchecked Radio Button Two Cicks

I need to check the first radio button (value = "option1") by default. But after adding "checked" attributes, the radio button with value "option2" needs two click to get checked. Any idea whats wrong here?
Based on other posts i have included the code in between form tag, i have also tried changing "checked" to 'checked="checked"', tried with different "name" attribute, removing the div around radio button.
This is my code:
HTML
<div class="action">
<div class="...">{label...}</div>
<div class="...">
<input type="radio" tabindex="0" aria-label={...} name="preview" value="option1" onclick={getPreview} checked></input>
<label>{...}</label>
</div>
<div class="...">
<input type="radio" tabindex="0" aria-label={...} name="preview" value="option2" onclick={getPreview} ></input>
<label>{...}</label>
</div>
</div>
JS
getPreview(event) {
if(event.target.value == "option1") {
...
} else {
...
}
}
But nothing seems to be working.

You input have some issues with input closing and also with your JS.
This is how you can close input element />
Also, if you are calling getPrevious on input click you can use getPrevious(this) and get the value of the onclick input like this simplified method.
Just run snippet below to see it action.
function getPreview(event) {
if (event.value == "option1") {
console.log('option 1 checked')
} else {
console.log('option 2 checked')
}
}
<div class="action">
<div class="...">{label...}</div>
<div class="...">
<input type="radio" tabindex="0" aria-label={...} name="preview" value="option1" onclick="getPreview(this)"/>
<label>{...}</label>
</div>
<div class="...">
<input type="radio" tabindex="0" aria-label={...} name="preview" value="option2" onclick="getPreview(this)" />
<label>{...}</label>
</div>
</div>

Given two yes/no fields, how can I use JavaScript to make the field 2 value checked "Yes" whenever the field 1 value is checked "Yes"?

If Field 1 is checked "Yes" then Field 2 should be checked "Yes"
This is what I've been trying so far:
Field 1:
<div class="entire">
<div class="col3"><label class="label-right">||FIELDTAG Field1||Question15||ENDFIELDTAG|| </label></div>
<div class="col9"><input type="radio" name="Field1" id="Question15yes" value="Yes" onclick="Check()">Yes <input type="radio" name="Field1" value="No" onclick="Check()">No</div>
Field 2:
<div class="entire">
<div class="col3"><label class="label-right">||FIELDTAG Field2||Question16||ENDFIELDTAG|| </label></div>
<div class="col9"><input type="radio" name="Field2" id="Question16yes" value="Yes" onclick="Check()">Yes <input type="radio" name="Field2" value="No" onclick="Check()">No</div>
I was trying something as simple as this js below, but I'm definitely missing something. Any help would be greatly appreciated!
<script language="JavaScript">
function Check() {
$("#Question15yes").click(function(){
if ($(this).is(':checked'))
{
$("#Question16yes").val("Yes");
}
}
});
}
</script>

Make sure you are including JQuery in your page.
To bind your event, you need to wait that the DOM is fully loaded, else you would try to use an element that doesn't exist yet.
<script language="JavaScript">
$(function() {
$(".question-checkbox").click(function(){
if ($(this).is(':checked'))
{
console.log($(this));
}
});
});
</script>
Also, you might want to change the JQuery selector from ID to class, so that you can use the same code for all similar checkboxes.
Put a .question-checkbox class on the inputs, and remove all onclicks.

You don't have to call check on every click. Once document loads, call it once.
window.addEventListener("load", function(){
$("input[type='radio']").on("click", function(){
if($("#Question15yes").is(':checked'))
$("#Question16yes").prop("checked", true);
});
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div class="entire">
<div class="col3">
<label class="label-right">||FIELDTAG Field1||Question15||ENDFIELDTAG|| </label>
</div>
<div class="col9">
<input type="radio" name="Field1" id="Question15yes" value="Yes">
Yes
<input type="radio" name="Field1" value="No" >No
</div>
<div class="entire">
<div class="col3">
<label class="label-right">||FIELDTAG Field2||Question16||ENDFIELDTAG|| </label>
</div>
<div class="col9">
<input type="radio" name="Field2" id="Question16yes" value="Yes">
Yes
<input type="radio" name="Field2" value="No">
No
</div>

Use this for a single checkbox with the class name "example":
$('input.example').on('change', function() {
$('input.example').not(this).prop('checked', false);
});

radiobuttons and conditional checkbox

I have 2 radio-buttons and a checkbox.
When the first option is "personalized" the checkbox "hidden" should be automatically checked.
<div class="field-type-list-text field-name-field-main-download-category field-widget-options-buttons form-wrapper" id="edit-field-main-download-category"><div class="form-item form-type-radios form-item-field-main-download-category-und">
<label for="edit-field-main-download-category-und">Main Download Category </label>
<div id="edit-field-main-download-category-und" class="form-radios"><div class="form-item form-type-radio form-item-field-main-download-category-und">
<input type="radio" id="edit-field-main-download-category-und-general" name="field_main_download_category[und]" value="general" class="form-radio" /> <label class="option" for="edit-field-main-download-category-und-general">General </label>
</div>
<div class="form-item form-type-radio form-item-field-main-download-category-und">
<input type="radio" id="edit-field-main-download-category-und-personalized" name="field_main_download_category[und]" value="personalized" class="form-radio" /> <label class="option" for="edit-field-main-download-category-und-personalized">Personalized </label>
</div>
</div>
</div>
</div><div class="field-type-list-boolean field-name-field-hidden field-widget-options-onoff form-wrapper" id="edit-field-hidden"><div class="form-item form-type-checkbox form-item-field-hidden-und">
<input type="checkbox" id="edit-field-hidden-und" name="field_hidden[und]" value="1" class="form-checkbox" /> <label class="option" for="edit-field-hidden-und">Hidden </label>
</div></div>
I've made this script, but it is not working:
jQuery(document).ready(function () {
if ( $('.personalized input').val() = "personalized" ) {
$('.checkbox input').attr('checked');
}
});

You have few problems. As others already pointed out, you are checking document.ready instead of onChange event. So it checks on page load, instead of checking on radio button state change.
Another problem is that you are checking $('.personalized input') value, but you do not have personalized class in your html.
Your radio buttons have common class form-radio. So you can use it as a selector.
$('.form-radio').on("change", function(){
if ( $(this).val() == "personalized" ) {
$('.form-checkbox').prop('checked', true);
}
else{
$('.form-checkbox').prop('checked', false);
}
})
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="field-type-list-text field-name-field-main-download-category field-widget-options-buttons form-wrapper" id="edit-field-main-download-category"><div class="form-item form-type-radios form-item-field-main-download-category-und">
<label for="edit-field-main-download-category-und">Main Download Category </label>
<div id="edit-field-main-download-category-und" class="form-radios"><div class="form-item form-type-radio form-item-field-main-download-category-und">
<input type="radio" id="edit-field-main-download-category-und-general" name="field_main_download_category[und]" value="general" class="form-radio" /> <label class="option" for="edit-field-main-download-category-und-general">General </label>
</div>
<div class="form-item form-type-radio form-item-field-main-download-category-und">
<input type="radio" id="edit-field-main-download-category-und-personalized" name="field_main_download_category[und]" value="personalized" class="form-radio" /> <label class="option" for="edit-field-main-download-category-und-personalized">Personalized </label>
</div>
</div>
</div>
</div><div class="field-type-list-boolean field-name-field-hidden field-widget-options-onoff form-wrapper" id="edit-field-hidden"><div class="form-item form-type-checkbox form-item-field-hidden-und">
<input type="checkbox" id="edit-field-hidden-und" name="field_hidden[und]" value="1" class="form-checkbox" /> <label class="option" for="edit-field-hidden-und">Hidden </label>
</div></div>
This part:
else{
$('.form-checkbox').prop('checked', false);
}
you only need if you want to un-check if not personalized.
Also take care of .prop() which is used for jQuery 1.6+. For lower versions use .attr()

You have to specify when do you want the script to check if the radio is checked or not. If you use just document.ready() function, it will check it only once, when the site is loaded and since it's not checked - the checkbox won't be checked neither.
You can use following approach: check it with every click event on the radio button.
$('.personalized').click(function() {
if ($(this).is(':checked')) {
$('.checkbox').attr('checked', 'checked');
}
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type='radio' class='personalized'>
<input type='checkbox' class='checkbox'>

Simply you need to do it in ready function
jQuery(document).ready(function () {
if ($(".personalized").is(":checked") ) {
$('.checkbox').attr('checked', 'checked');
}
});
if you want them to apply on page load.

You have several problems here:
The code as written only runs on page load. Since you said you want the checkbox to be "automatically" checked, you should attach a change handler to the radio array.
.val() called on a radio array returns the value of the first element in the selected set, regardless of which one is checked. You need to add :checked to your selector to filter down to the one selected radio element.
Your single equals sign is the assignment operator and should be replaced with ===.
.attr('checked') returns the value of the checked attribute. There are actually two problems here: attr only looks at the attribute initially assigned to the element; you need to use prop instead to update the checked property. The second problem is that the one-parameter attr function is used to read the attribute. You want the two-parameter function to set it.
Here's a working example:
jQuery(document).ready(function () {
$('input[name="radio"]').on('change',function(){
if ( $('input[name="radio"]:checked').val() === "personalized" ) {
$('#hidden').prop('checked','checked');
} else {
$('#hidden').prop('checked','');
}
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="radio" name="radio" id="personalized" value="personalized"/><label for="personalized">personalized</label><br/>
<input type="radio" name="radio" id="general" value="general"/><label for="general">general</label><br/>
<input type="checkbox" id="hidden" name="hidden"/><label for="hidden">hidden</label>

Set radio button value in javascript

I am trying to set the value of the radio button via javascript. But I am not being able to do so. What I tried to do was have 4 radio buttons one of which is already selected. If I select some other radio button and click on Refresh, default radio button should be selected.
http://jsfiddle.net/ds345/Un8XK/1/
HTML:
<fieldset data-role="controlgroup" data-type="vertical">
<input type="radio" name="radio" id="x" data-theme="a" />
<label for="x" style="color: White">X</label>
<input type="radio" name="radio" id="y" onclick="axisonoff(this)" data-theme="a" />
<label for="y" style="color: White">Y</label>
<input type="radio" name="radio" id="z" data-theme="a" />
<label for="z" >Z</label>
<input type="radio" name="radio" id="none" data-theme="a" />
<label for="none" style="color: White">None</label>
</fieldset>
<button id = "Refresh" value="Refresh">Refresh</button>
JS:
$(document).ready(function () {
$("#none").attr("checked", true).checkboxradio("refresh"); // if this line is not present initially then it works for the 1st refresh.
});
$("#Refresh").click(function(){
$("#x").attr("checked", false).checkboxradio("refresh");
$("#y").attr("checked", false).checkboxradio("refresh");
$("#z").attr("checked", false).checkboxradio("refresh");
$("#none").attr("checked", true).checkboxradio("refresh");
});
I am sure that I have missed something very small but not able to figure out why this approach is not working.
Tools used: Javascript,Jquery 1.9 and JQuery mobile 1.3
Thanks,
Deeksha

You should use prop over attr when dealing with boolean attributes.
.attr("checked", false) will add checked="false" to your element.In HTML, <input checked="false" .../> is the same as <input checked="true" .../> or simply <input checked .../> as the attribute simply needs to be present on the element for it to be active.
See this JSFiddle example.
Change your code to use .prop() instead:
$("#none").prop("checked", false)...
Here is a fixed version of your JSFiddle demo: http://jsfiddle.net/Un8XK/8/

What you have missed is that there is no need for script. Simply use a form with a reset button:
<form>
<input type="radio" name="radio" value="0" checked>0<br>
<input type="radio" name="radio" value="1">1<br>
<input type="radio" name="radio" value="2">2<br>
<input type="radio" name="radio" value="3">3<br>
<input type="reset">
</form>
If you really must use script, you can simply return the radio buttons to their default by adding a button to the form:
<input type="button" onclick="reset(this.form.radio);" value="Script reset">
and a function:
<script>
function reset(els) {
for (var i=0, iLen=els.length; i<iLen; i++) {
els[i].checked = els[i].defaultChecked;
}
}
</script>

Jquery how to check checkbox on div click, change class and show div

I am trying to checkbox when the div.menuitem is clicked and then it should change class and show the content in the div with class of hidediv. When the div.menuitem is again clicked it should remove the class and hide the div again and uncheck the checkbox.
Want I want to do:
Only show the content of the hidediv when the menuitem is pressed. (checkbox should be checked)
When the menuitem is pressed the checkbox should be checked
When the menuitem is clicked again the hidediv should be hidden again. (checkbox unchecked)
And the checkbox should be uncheched
Illustration of my menu form:
<div class="menuitem">
1.Company1
</div>
<div class="hidediv">
1.1 Company 1.1
1.2 Company 1.2
</div>
<div class="menuitem">
1.Company2
</div>
<div class="hidediv">
1.1 Company 2.1
1.2 Company 2.2
</div>
My previous Jquery code, which only is trigger when the checkbox is clicked. I want pretty
similar function to this, the checkbox should also be trigghed when the div is clicked:
$('.menuitem input:checkbox').change(function(){
if($(this).is(':checked')) {
$('div.hidediv').addClass('someclass').show(200); // not needed it there is another way of identifying the div later to add to hidediv class again.
$('div.hidediv').removeClass('hidediv');
} else {
$('div.someclass').addClass('hidediv').hide(200);
}
});
});
My Jquery so far(not working):
$('.menuitem').click(function(e){
$(this).addClass('menuclicked');
$('div.hidediv').addClass('clicked').show(200);
$('div.hidediv').removeClass('hidediv');
} else {
$('div.someclass').addClass('hidediv').hide(200);
}
$('.menuclicked').click(function(e){
$('div.someclass').addClass('hidediv').hide(200);
});
My HTML:
<form accept-charset="UTF-8" action="/" method="get"><div style="margin:0;padding:0;display:inline"><input name="utf8" type="hidden" value="✓" /></div>
<div class="menuitem">
<label for="search_company1">company1</label>
<input name="search[company1_is_true]" type="hidden" value="0" /><input id="search_company1_is_true" name="search[company1_is_true]" type="checkbox" value="1" />
</div>
<div class="menuitem">
<label for="search_company3">company3</label>
<input name="search[company3_is_true]" type="hidden" value="0" /><input id="search_company3_is_true" name="search[company3_is_true]" type="checkbox" value="1" />
</div>
<div class="hidediv">
<div class="menuitem">
<label for="search_company2">company2</label>
<input name="search[company2_is_true]" type="hidden" value="0" /><input id="search_company2_is_true" name="search[company2_is_true]" type="checkbox" value="1" />
<div>
</div>
<input id="search_submit" name="commit" style="display:none;" type="submit" value="Submit" />
</form>

I can help. I think you are structuring this wrong. You have three fields in your html, with the third being hidden. I assume when you fill in the first one you want nothing to happen, but clicking the second one should show the third field?
Try this:
//Use toggle instead of .click()
$('.menuitem').toggle(function(){
$('div.hidediv').addClass('clicked').show(200);
}, function(){
$('div.hidediv').removeClass('clicked').hide(200);
});
This will effect all divs with the "menuitem" class, meaning when you click on any of the three it will toggle showing/hiding the div with the "hidediv" class.
edit you have a couple valid answers here, but I think you're approaching this wrong. If you go try the jsfiddle posted by another user, whos' javascript does the same as mine - it reveals the problem I talked about above. You cannot select all three boxes without some clever clicking. Each click will toggle showing/hiding the third check box. Might I suggest modifying your code like so:
//Use toggle instead of .click()
$('.toggleMenuItem').toggle(function(){
$('div.hidediv').addClass('clicked').show(200);
}, function(){
$('div.hidediv').removeClass('clicked').hide(200);
});
<form accept-charset="UTF-8" action="/" method="get">
<div style="margin:0;padding:0;display:inline">
<input name="utf8" type="hidden" value="✓" />
</div>
<div class="menuitem">
<label for="search_company1">company1</label>
<input name="search[company1_is_true]" type="hidden" value="0" />
<input id="search_company1_is_true" name="search[company1_is_true]" type="checkbox" value="1" />
</div>
<div class="menuitem toggleMenuItem">
<label for="search_company3">company3</label>
<input name="search[company3_is_true]" type="hidden" value="0" />
<input id="search_company3_is_true" name="search[company3_is_true]" type="checkbox" value="1" />
</div>
<div class="hidediv">
<div class="menuitem">
<label for="search_company2">company2</label>
<input name="search[company2_is_true]" type="hidden" value="0" />
<input id="search_company2_is_true" name="search[company2_is_true]" type="checkbox" value="1" />
<div>
</div>
<input id="search_submit" name="commit" style="display:none;" type="submit" value="Submit" />
</form>
This will make it so only clicking the checkboxes with the class ".toggleMenuItem" will show the third checkbox.

try something like this:
$('.menuitem').click(function(e){
if($(this).hasClass('menuClicked')){
// Already clicked
$(this)
.removeClass('menuclicked')
.html("");
}else{
// First click
$(this)
.addClass('menuclicked');
.html($('#hidediv').html());
}
})

This may do what you're looking for:
$('.menuitem').click(function(e){
$(this).toggleClass('clicked');
$('div.hidediv').toggle(200);
});
Let me know if it is missing a feature.
http://jsfiddle.net/citizenconn/2bCdR/