I have 2 dates: startdate and enddate. End date is always a day less than the startdate. So if my start day is 19th, the end date would be on the 18th of next month.
I am trying to create an array of number of days in between the 2 dates.
(It goes from 19th to 18th and then 18th to 18th of every month to calculate the difference)
Example
8/19/2018 - 9/18/2018 = 30 days
9/18/2018 - 10/18/2019 = 30 days
10/18/2018 - 11/18/2018 = 31 days
array = [30,30,31]
I am using the following code to calculate days difference between the dates.
function daysBetweenArrears (date1, date2){
date1.setDate(date1.getDate() );
date2.setDate(date2.getDate() - 1);
var Diff = Math.abs(date2.getTime() - date1.getTime());
var TimeDifference = Math.round(Diff / (1000 * 3600 * 24));
return TimeDifference;
}
The following code for creating the array
if (document.getElementById("endDate"))
y = document.getElementById("endDate").value;
if (document.getElementById("startDate"))
z = document.getElementById("startDate").value;
var dateArr = getDateArray(z, y);
var dayCountArr = "";
var b = [];
for (var x = 0; x < dateArr.length-1; x++)
{
dayCountArr += daysBetweenArrears(dateArr[x], dateArr[x+1], ",");
b.push(daysBetweenArrears(dateArr[x], dateArr[x+1]));
}
The issue is that when i set the date as following, it is giving me incorrect output. The problem is that it is setting the dates incorrectly whenever it goes to the next month. I am not sure what i am doing wrong here. Any help is greatly appreciated. Thank you.
date2.setDate(date2.getDate() - 1);
You can do this using moment. Hope this helps.
const start = "8/19/2018";
const end = "11/18/2018 ";
const dates = [];
const mstart = moment(new Date(start));
const mend = moment(new Date(end));
for (let i = 0; mstart < mend ; i++) {
const daysInMonth = mstart.daysInMonth() + (i === 0 ? -1 : 0);
dates.push(daysInMonth);
mstart.add(1, 'M');
}
console.log(dates);
<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.22.2/moment.min.js"></script>
You can update your function daysBetweenArrears
const daysBetweenArrears = (date1, date2) => {
const time1 = new Date(date1).getTime();
const time2 = new Date(date2).getTime();
const diff = Math.abs(time2 - time1);
return Math.round(diff/(1000*60*60*24));
};
console.log(daysBetweenArrears('8/18/2018', '9/18/2018'));
console.log(daysBetweenArrears('6/18/2018', '7/18/2018'));
I am trying to check if the date i.e. (07/02/2018 ) is more than year from current date and if the date i.e. (07/02/2018 ) is less than year from current date using JavaScript tried with following code
var x = new Date('JUN-2016');
var y = new Date('MAY-2016');
console.log(+x < +y);
Your question is not very clear to me but this may help you:
var now = new Date();
var then = new Date('07/02/2018');
var diffInDays = Math.round((then-now) / (1000*60*60*24));
console.log('then is', diffInDays, 'days more than now.');
Note: If diffInDays is a positive number then the then is more than now, otherwise it's less.
You can simply add 1000*60*60*24*365 milliseconds to your first date and compare it to your second date :
var x = new Date('APR-2015');
var y = new Date('MAY-2016');
console.log(+x + 1000*60*60*24*365 < +y);
var x2 = new Date('SEP-2015');
console.log(+x2 + 1000*60*60*24*365 < +y);
You can get the year with the getFullYear()method (Date doc).
let x = new Date();
let y = new Date();
x_year = x.getFullYear();
y_year = y.getFullYear();
// The you just have to compare the year
One way to do it, although I'd be surprised if there wasn't a better way:
var x = new Date();
x = x.setFullYear(x.getFullYear() + 1);
x = new Date(x);
var y = (new Date('2018-04-08'));
var z = (new Date('2019-04-08'));
if (y < x) {
console.log('Y is less than a year from now');
} else {
console.log('Y is more or exactly a year from now');
}
if (z < x) {
console.log('Z is less than a year from now');
} else {
console.log('Z is more or exactly a year from now');
}
Your question is not clear this is based on my assumption.
I am assuming that you need to check if the given date is one year ahead of the current date.
var x = new Date('1, 1, 2018');
var today = new Date();
var time = Math.abs(today.getTime() - x.getTime());
var days = Math.ceil(time / (1000 * 3600 * 24));
alert("There is a difference of " + days + " days between today and the given date");
I am assuming that you want to know if some arbitrary date is less or more than a year from current date.
We can get a the value for a year this way:
var a_year = Math.abs(new Date('01-01-2018'.replace(/-/g,'/')) - new Date('01-01-2017'.replace(/-/g,'/')));
Then we set two date tests:
var test1 = '01-01-2018';
var test2 = '01-01-2015';
Calculate the diffs:
var diff1 = Math.abs(new Date() - new Date(test1.replace(/-/g,'/')));
var diff2 = Math.abs(new Date() - new Date(test2.replace(/-/g,'/')));
Then you can log the results for testing:
console.log(diff1 > a_year)
console.log(diff1 < a_year)
console.log(diff2 > a_year)
console.log(diff2 < a_year)
Credits to David Hedlund's answer on How to subtract date/time in javascript?
I have got restaurants business startTime and endTime for the todays date .
I have a requirement as such when clicked on Order now button depending on the Restaurants startTime and endTime i need to display a alert meesage
saying services will resume with in next XX Minutes
This is my code
var startTime = '04:00 PM';
var endTime = '5:30 PM';
var now = new Date();
var startDate = dateObj(startTime);
var endDate = dateObj(endTime);
var openorclosed = now < endDate && now > startDate ? 'open' : 'closed';
if(openorclosed=='open')
{
alert('Restaurant is Open');
// do nothing
}
else if(openorclosed=='closed')
{
var diffinMinutes = getMinutesBetweenDates(startDate,now);
var minutes = Math.floor(diffinMinutes);
alert('service not available for the next '+minutes+' min');
}
function dateObj(d) {
var parts = d.split(/:|\s/),
date = new Date();
if (parts.pop().toLowerCase() == 'pm') parts[0] = (+parts[0]) + 12;
date.setHours(+parts.shift());
date.setMinutes(+parts.shift());
return date;
}
function getMinutesBetweenDates(startDate, now) {
var diff = startDate.getTime() - now.getTime();
return (diff / 60000);
}
If the startTime is bigger than the Current time then its working perfectly (Displaying correclty)
However if the startTime is lesser than the Current time then its displaying values in negative values
Could anybody please let me know how to display correclty within minutes incase startTime is lesser ??
This is my jsfiddle
http://jsfiddle.net/wajzvqqx/1/
Thank you very much .
Simple solution:
If your value is negative, add a whole day:
var diffinMinutes = getMinutesBetweenDates(startDate,now);
if (diffinMinutes < 0) diffinMinutes = diffinMinutes + 1440;
var minutes = Math.floor(diffinMinutes);
User this code when the shop is closed:
startDate.setDate(startDate.getDate()+1);
You were calculating start and end date objects from current date.
So if shop is closed for the day, add one more day to the start date.
Fiddle
Try modifying the getMinutesBetweenDate function to get the difference like this:
function getMinutesBetweenDates(startDate, now) {
var diff;
if (startDate > now) {
diff = startDate.getTime() - now.getTime();
} else {
diff = now.getTime() - startDate.getTime();
}
return (diff / 60000);
}
Im trying to make a script which calculate the days you live. My idea is the user to select their birthday by clicking buttons. I read some scripts and wrote some questions and finally a good guy sent me this code, but it isn working for me.. JSFIDDLE
function IncrementDay(month,year)
{
var lastDay = new Date(year, month, 0).getDate();
var nDay=document.getElementById("bday").value;
++nDay;
if (nDay > lastDay) {
nDay =1;
}
document.getElementById("bday").value=nDay;
}
function IncrementMonth(from_IncrementDay = false)
{
var nMonth = document.getElementById("bmonth").value;
++nMonth;
if (nMonth==13) {
nMonth =1;
}
document.getElementById("bmonth").value=nMonth;
}
function isValidDate(s) {
var bits = s.split('/');
var y = bits[0], m = bits[1], d = bits[2];
// Assume not leap year by default (note zero index for Jan)
var daysInMonth = [31,28,31,30,31,30,31,31,30,31,30,31];
// If evenly divisible by 4 and not evenly divisible by 100,
// or is evenly divisible by 400, then a leap year
if ( (!(y % 4) && y % 100) || !(y % 400)) {
daysInMonth[1] = 29;
}
return d <= daysInMonth[--m]
}
function days_between(date1, date2) {
// The number of milliseconds in one day
var ONE_DAY = 1000 * 60 * 60 * 24
// Convert both dates to milliseconds
var date1_ms = date1.getTime()
var date2_ms = date2.getTime()
// Calculate the difference in milliseconds
var difference_ms = Math.abs(date1_ms - date2_ms)
// Convert back to days and return
return Math.round(difference_ms/ONE_DAY)
}
function calculate() {
var _bd = document.getElementById('byear').value + "/" + document.getElementById('bmonth').value + "/" + document.getElementById('bday').value;
if (!isValidDate(_bd)) return;
var _days = days_between(new Date(), new Date(_bd));
document.getElementById("days").innerHTML = _days;
}
var cDate= new Date();
var cDay = cDate.getDate();
var cMonth = cDate.getMonth();
var cYear = cDate.getFullYear();
var days_gone = 0;
++cMonth;
document.getElementById("bday").value=cDay;
document.getElementById("bmonth").value=cMonth;
document.getElementById("byear").value=cYear;
Im not very familiar with javascript, can you tell me where's the mistake? thanks.
var oneDay = 24*60*60*1000; // hours*minutes*seconds*milliseconds
var firstDate = new Date(2008,01,12);
var secondDate = new Date();
var diffDays = Math.round(Math.abs((firstDate.getTime() - secondDate.getTime())/(oneDay)));
I like the moment js library for this.
http://momentjs.com/
This is how you would do it with moment.js
var today = moment();
var birthDate = moment([2000, 12, 31]); // 2000 (year), 12 (month), 31 (day)
var daysDiff = today.diff(birthDate, 'days'); //4823
if you want the difference in years
var yearsDiff = today.diff(birthDate, 'years'); //13
I want to get the number of years between two dates. I can get the number of days between these two days, but if I divide it by 365 the result is incorrect because some years have 366 days.
This is my code to get date difference:
var birthday = value;//format 01/02/1900
var dateParts = birthday.split("/");
var checkindate = new Date(dateParts[2], dateParts[0] - 1, dateParts[1]);
var now = new Date();
var difference = now - checkindate;
var days = difference / (1000*60*60*24);
var thisyear = new Date().getFullYear();
var birthyear = dateParts[2];
var number_of_long_years = 0;
for(var y=birthyear; y <= thisyear; y++){
if( (y % 4 == 0 && y % 100 == 0) || y % 400 == 0 ) {
number_of_long_years++;
}
}
The day count works perfectly. I am trying to do add the additional days when it is a 366-day year, and I'm doing something like this:
var years = ((days)*(thisyear-birthyear))
/((number_of_long_years*366) + ((thisyear-birthyear-number_of_long_years)*365) );
I'm getting the year count. Is this correct, or is there a better way to do this?
Sleek foundation javascript function.
function calculateAge(birthday) { // birthday is a date
var ageDifMs = Date.now() - birthday;
var ageDate = new Date(ageDifMs); // miliseconds from epoch
return Math.abs(ageDate.getUTCFullYear() - 1970);
}
Probably not the answer you're looking for, but at 2.6kb, I would not try to reinvent the wheel and I'd use something like moment.js. Does not have any dependencies.
The diff method is probably what you want: http://momentjs.com/docs/#/displaying/difference/
Using pure javascript Date(), we can calculate the numbers of years like below
document.getElementById('getYearsBtn').addEventListener('click', function () {
var enteredDate = document.getElementById('sampleDate').value;
// Below one is the single line logic to calculate the no. of years...
var years = new Date(new Date() - new Date(enteredDate)).getFullYear() - 1970;
console.log(years);
});
<input type="text" id="sampleDate" value="1980/01/01">
<div>Format: yyyy-mm-dd or yyyy/mm/dd</div><br>
<button id="getYearsBtn">Calculate Years</button>
No for-each loop, no extra jQuery plugin needed... Just call the below function.. Got from Difference between two dates in years
function dateDiffInYears(dateold, datenew) {
var ynew = datenew.getFullYear();
var mnew = datenew.getMonth();
var dnew = datenew.getDate();
var yold = dateold.getFullYear();
var mold = dateold.getMonth();
var dold = dateold.getDate();
var diff = ynew - yold;
if (mold > mnew) diff--;
else {
if (mold == mnew) {
if (dold > dnew) diff--;
}
}
return diff;
}
I use the following for age calculation.
I named it gregorianAge() because this calculation gives exactly how we denote age using Gregorian calendar. i.e. Not counting the end year if month and day is before the month and day of the birth year.
/**
* Calculates human age in years given a birth day. Optionally ageAtDate
* can be provided to calculate age at a specific date
*
* #param string|Date Object birthDate
* #param string|Date Object ageAtDate optional
* #returns integer Age between birthday and a given date or today
*/
gregorianAge = function(birthDate, ageAtDate) {
// convert birthDate to date object if already not
if (Object.prototype.toString.call(birthDate) !== '[object Date]')
birthDate = new Date(birthDate);
// use today's date if ageAtDate is not provided
if (typeof ageAtDate == "undefined")
ageAtDate = new Date();
// convert ageAtDate to date object if already not
else if (Object.prototype.toString.call(ageAtDate) !== '[object Date]')
ageAtDate = new Date(ageAtDate);
// if conversion to date object fails return null
if (ageAtDate == null || birthDate == null)
return null;
var _m = ageAtDate.getMonth() - birthDate.getMonth();
// answer: ageAt year minus birth year less one (1) if month and day of
// ageAt year is before month and day of birth year
return (ageAtDate.getFullYear()) - birthDate.getFullYear()
- ((_m < 0 || (_m === 0 && ageAtDate.getDate() < birthDate.getDate()))?1:0)
}
<input type="text" id="birthDate" value="12 February 1982">
<div style="font-size: small; color: grey">Enter a date in an acceptable format e.g. 10 Dec 2001</div><br>
<button onClick='js:alert(gregorianAge(document.getElementById("birthDate").value))'>What's my age?</button>
Little out of date but here is a function you can use!
function calculateAge(birthMonth, birthDay, birthYear) {
var currentDate = new Date();
var currentYear = currentDate.getFullYear();
var currentMonth = currentDate.getMonth();
var currentDay = currentDate.getDate();
var calculatedAge = currentYear - birthYear;
if (currentMonth < birthMonth - 1) {
calculatedAge--;
}
if (birthMonth - 1 == currentMonth && currentDay < birthDay) {
calculatedAge--;
}
return calculatedAge;
}
var age = calculateAge(12, 8, 1993);
alert(age);
You can get the exact age using timesstamp:
const getAge = (dateOfBirth, dateToCalculate = new Date()) => {
const dob = new Date(dateOfBirth).getTime();
const dateToCompare = new Date(dateToCalculate).getTime();
const age = (dateToCompare - dob) / (365 * 24 * 60 * 60 * 1000);
return Math.floor(age);
};
let currentTime = new Date().getTime();
let birthDateTime= new Date(birthDate).getTime();
let difference = (currentTime - birthDateTime)
var ageInYears=difference/(1000*60*60*24*365)
Yep, moment.js is pretty good for this:
var moment = require('moment');
var startDate = new Date();
var endDate = new Date();
endDate.setDate(endDate.getFullYear() + 5); // Add 5 years to second date
console.log(moment.duration(endDate - startDate).years()); // This should returns 5
getYears(date1, date2) {
let years = new Date(date1).getFullYear() - new Date(date2).getFullYear();
let month = new Date(date1).getMonth() - new Date(date2).getMonth();
let dateDiff = new Date(date1).getDay() - new Date(date2).getDay();
if (dateDiff < 0) {
month -= 1;
}
if (month < 0) {
years -= 1;
}
return years;
}
for(var y=birthyear; y <= thisyear; y++){
if( (y % 4 == 0 && y % 100 == 0) || y % 400 == 0 ) {
days = days-366;
number_of_long_years++;
} else {
days=days-365;
}
year++;
}
can you try this way??
function getYearDiff(startDate, endDate) {
let yearDiff = endDate.getFullYear() - startDate.getFullYear();
if (startDate.getMonth() > endDate.getMonth()) {
yearDiff--;
} else if (startDate.getMonth() === endDate.getMonth()) {
if (startDate.getDate() > endDate.getDate()) {
yearDiff--;
} else if (startDate.getDate() === endDate.getDate()) {
if (startDate.getHours() > endDate.getHours()) {
yearDiff--;
} else if (startDate.getHours() === endDate.getHours()) {
if (startDate.getMinutes() > endDate.getMinutes()) {
yearDiff--;
}
}
}
}
return yearDiff;
}
alert(getYearDiff(firstDate, secondDate));
getAge(month, day, year) {
let yearNow = new Date().getFullYear();
let monthNow = new Date().getMonth() + 1;
let dayNow = new Date().getDate();
if (monthNow === month && dayNow < day || monthNow < month) {
return yearNow - year - 1;
} else {
return yearNow - year;
}
}
If you are using moment
/**
* Convert date of birth into age
* param {string} dateOfBirth - date of birth
* param {string} dateToCalculate - date to compare
* returns {number} - age
*/
function getAge(dateOfBirth, dateToCalculate) {
const dob = moment(dateOfBirth);
return moment(dateToCalculate).diff(dob, 'years');
};
If you want to calculate the years and keep the remainder of the time left for further calculations you can use this function most of the other answers discard the remaining time.
It returns the years and the remainder in milliseconds. This is useful if you want to calculate the time (days or minutes) left after you calculate the years.
The function works by first calculating the difference in years directly using *date.getFullYear()*.
Then it checks if the last year between the two dates is up to a full year by setting the two dates to the same year.
Eg:
oldDate= 1 July 2020,
newDate= 1 June 2022,
years =2020 -2022 =2
Now set old date to new date's year 2022
oldDate = 1 July, 2022
If the last year is not up to a full year then the year is subtracted by 1, the old date is set to the previous year and the interval from the previous year to the current date is calculated to give the remainder in milliseconds.
In the example since old date July 2022 is greater than June 2022 then it means a full year has not yet elapsed (from July 2021 to June 2022) therefore the year count is greater by 1. So years should be decreased by 1. And the actual year count from July 2020 to June 2022 is 1 year ,... months.
If the last year is a full year then the year count by *date.getFullYear()* is correct and the time that has elapsed from the current old date to new date is calculated as the remainder.
If old date= 1 April, 2020, new date = 1 June, 2022 and old date is set to April 2022 after calculating the year =2.
Eg: from April 2020 to June 2022 a duration of 2 years has passed with the remainder being the time from April 2022 to June 2022.
There are also checks for cases where the two dates are in the same year and if the user enters the dates in the wrong order the new Date is less recent than the old Date.
let getYearsAndRemainder = (newDate, oldDate) => {
let remainder = 0;
// get initial years between dates
let years = newDate.getFullYear() - oldDate.getFullYear();
if (years < 0) {// check to make sure the oldDate is the older of the two dates
console.warn('new date is lesser than old date in year difference')
years = 0;
} else {
// set the old date to the same year as new date
oldDate.setFullYear(newDate.getFullYear());
// check if the old date is less than new date in the same year
if (oldDate - newDate > 0) {
//if true, the old date is greater than the new date
// the last but one year between the two dates is not up to a year
if (years != 0) {// dates given in inputs are in the same year, no need to calculate years if the number of years is 0
console.log('Subtracting year');
//set the old year to the previous year
years--;
oldDate.setFullYear(oldDate.getFullYear() - 1);
}
}
}
//calculate the time difference between the old year and newDate.
remainder = newDate - oldDate;
if (remainder < 0) { //check for negative dates due to wrong inputs
console.warn('old date is greater than new Date');
console.log('new date', newDate, 'old date', oldDate);
}
return { years, remainder };
}
let old = new Date('2020-07-01');
console.log( getYearsAndRemainder(new Date(), old));
Date calculation work via the Julian day number. You have to take the first of January of the two years. Then you convert the Gregorian dates into Julian day numbers and after that you take just the difference.
Maybe my function can explain better how to do this in a simple way without loop, calculations and/or libs
function checkYearsDifference(birthDayDate){
var todayDate = new Date();
var thisMonth = todayDate.getMonth();
var thisYear = todayDate.getFullYear();
var thisDay = todayDate.getDate();
var monthBirthday = birthDayDate.getMonth();
var yearBirthday = birthDayDate.getFullYear();
var dayBirthday = birthDayDate.getDate();
//first just make the difference between years
var yearDifference = thisYear - yearBirthday;
//then check months
if (thisMonth == monthBirthday){
//if months are the same then check days
if (thisDay<dayBirthday){
//if today day is before birthday day
//then I have to remove 1 year
//(no birthday yet)
yearDifference = yearDifference -1;
}
//if not no action because year difference is ok
}
else {
if (thisMonth < monthBirthday) {
//if actual month is before birthday one
//then I have to remove 1 year
yearDifference = yearDifference -1;
}
//if not no action because year difference is ok
}
return yearDifference;
}
Bro, moment.js is awesome for this:
The diff method is what you want: http://momentjs.com/docs/#/displaying/difference/
The below function return array of years from the year to the current year.
const getYears = (from = 2017) => {
const diff = moment(new Date()).diff(new Date(`01/01/${from}`), 'years') ;
return [...Array(diff >= 0 ? diff + 1 : 0).keys()].map((num) => {
return from + num;
});
}
console.log(getYears(2016));
<script src="https://momentjs.com/downloads/moment.js"></script>
function dateDiffYearsOnly( dateNew,dateOld) {
function date2ymd(d){ w=new Date(d);return [w.getFullYear(),w.getMonth(),w.getDate()]}
function ymd2N(y){return (((y[0]<<4)+y[1])<<5)+y[2]} // or 60 and 60 // or 13 and 32 // or 25 and 40 //// with ...
function date2N(d){ return ymd2N(date2ymd(d))}
return (date2N(dateNew)-date2N(dateOld))>>9
}
test:
dateDiffYearsOnly(Date.now(),new Date(Date.now()-7*366*24*3600*1000));
dateDiffYearsOnly(Date.now(),new Date(Date.now()-7*365*24*3600*1000))
I went for the following very simple solution. It does not assume you were born in 1970 and it also takes into account the hour of the given birthday date.
function age(birthday) {
let now = new Date();
let year = now.getFullYear();
let years = year - birthday.getFullYear();
birthday = new Date(birthday.getTime()); // clone
birthday.setFullYear(year);
return now >= birthday ? years : years - 1;
}
This one Help you...
$("[id$=btnSubmit]").click(function () {
debugger
var SDate = $("[id$=txtStartDate]").val().split('-');
var Smonth = SDate[0];
var Sday = SDate[1];
var Syear = SDate[2];
// alert(Syear); alert(Sday); alert(Smonth);
var EDate = $("[id$=txtEndDate]").val().split('-');
var Emonth = EDate[0];
var Eday = EDate[1];
var Eyear = EDate[2];
var y = parseInt(Eyear) - parseInt(Syear);
var m, d;
if ((parseInt(Emonth) - parseInt(Smonth)) > 0) {
m = parseInt(Emonth) - parseInt(Smonth);
}
else {
m = parseInt(Emonth) + 12 - parseInt(Smonth);
y = y - 1;
}
if ((parseInt(Eday) - parseInt(Sday)) > 0) {
d = parseInt(Eday) - parseInt(Sday);
}
else {
d = parseInt(Eday) + 30 - parseInt(Sday);
m = m - 1;
}
// alert(y + " " + m + " " + d);
$("[id$=lblAge]").text("your age is " + y + "years " + m + "month " + d + "days");
return false;
});
if someone needs for interest calculation year in float format
function floatYearDiff(olddate, newdate) {
var new_y = newdate.getFullYear();
var old_y = olddate.getFullYear();
var diff_y = new_y - old_y;
var start_year = new Date(olddate);
var end_year = new Date(olddate);
start_year.setFullYear(new_y);
end_year.setFullYear(new_y+1);
if (start_year > newdate) {
start_year.setFullYear(new_y-1);
end_year.setFullYear(new_y);
diff_y--;
}
var diff = diff_y + (newdate - start_year)/(end_year - start_year);
return diff;
}