general programming problem here.
I have this array called SPACES
[
{
_id: 5e1c4689429a8a0decf16f69,
challengers: [
5dfa24dce9cbc0180fb60226,
5dfa26f46719311869ac1756,
5dfa270c6719311869ac1757
]
},
{
_id: 5e1c4eb9c9461510407d5e81,
challengers: [ 5dfa24dce9cbc0180fb60226, 5dfa26f46719311869ac1756 ],
}
]
And this array called USERS
[
{
_id: 5dfa24dce9cbc0180fb60226,
name: 'Account 1',
email: 'account1#gmail.com',
spaces: [ 5e1c4689429a8a0decf16f69, 5e1c4eb9c9461510407d5e81 ],
},
{
_id: 5dfa26f46719311869ac1756,
name: 'Account 2',
email: 'account2#gmail.com',
spaces: [ 5e1c4689429a8a0decf16f69, 5e1c4eb9c9461510407d5e81 ]
},
{
_id: 5dfa270c6719311869ac1757,
name: 'Account 3',
email: 'account3#gmail.com',
spaces: [ 5e1c4689429a8a0decf16f69 ]
}
]
What I want to do, is go through both, and instead of having the SPACES.challengers array be just IDS, I would like the array to contain each USER object.
So for example, if the USER has an ID that is inside the SPACES.challengers array, then push the user into that array (which will then be the entire object).
SO FAR I have tried this (I am not very good yet):
users.map( ( user ) => {
spaces.map( ( space ) => {
if ( user.spaces.includes( space._id ) ) {
space.challengers.push(user)
}
} );
} );
However, I am not getting inside the IF block. (Even if I did, not sure if it would work OR if this is even how to do it). It feels Odd doing double maps, as I get so many iterations, and it duplicates my push (cause I have no logic to see if it just has been pushed).
Assuming every entry in the Users array has a unique ID, we can build a Hashmap to store (id, index) pairs in order to search efficiently for an ID from Users array while looping through Spaces array.
let spaces = [{_id: '5e1c4689429a8a0decf16f69',challengers: ['5dfa24dce9cbc0180fb60226', '5dfa26f46719311869ac1756', '5dfa270c6719311869ac1757']},{_id: '5e1c4eb9c9461510407d5e81',challengers: [ '5dfa24dce9cbc0180fb60226', '5dfa26f46719311869ac1756' ],}]
let users = [{_id: '5dfa24dce9cbc0180fb60226',name: 'Account 1',email: 'account1#gmail.com',spaces: [ '5e1c4689429a8a0decf16f69', '5e1c4eb9c9461510407d5e81' ],},{_id: '5dfa26f46719311869ac1756',name: 'Account 2',email: 'account2#gmail.com',spaces: [ '5e1c4689429a8a0decf16f69', '5e1c4eb9c9461510407d5e81' ]},{_id: '5dfa270c6719311869ac1757',name: 'Account 3',email: 'account3#gmail.com',spaces: [ '5e1c4689429a8a0decf16f69' ]}]
let IDIndexMapping = {} // To store (_id, index) pairs, in order to improve search efficiency
for(let index in users) // Iterate through Users array using index
IDIndexMapping[users[index]._id] = index; // store (_id, index) pair in IDIndexMapping
// I'm avoiding using `map` and using vanilla `for` loop for space efficiency
// as map returns a new array but with `for` loop, we can perform changes in-place
for(let outerIndex in spaces){ // Iterate through `spaces` array using index
let challengers = spaces[outerIndex].challengers; // Get challengers array
for(let innerIndex in challengers){ // Iterate through challengers array using index
let ID = challengers[innerIndex]; // Get ID
if(ID in IDIndexMapping) // If ID exists in IDIndexMapping
spaces[outerIndex].challengers[innerIndex] = users[IDIndexMapping[ID]]; // Change ID to actual User object
}
}
console.log(spaces)
Output
[ { _id: '5e1c4689429a8a0decf16f69',
challengers: [ [Object], [Object], [Object] ] },
{ _id: '5e1c4eb9c9461510407d5e81',
challengers: [ [Object], [Object] ] } ]
.map and .find should work here. keep it simple.
var spaces = [
{
_id: "5e1c4689429a8a0decf16f69",
challengers: [
"5dfa24dce9cbc0180fb60226",
"5dfa26f46719311869ac1756",
"5dfa270c6719311869ac1757"
]
},
{
_id: "5e1c4eb9c9461510407d5e81",
challengers: ["5dfa24dce9cbc0180fb60226", "5dfa26f46719311869ac1756", "some non existent"]
}
],
users = [
{
_id: "5dfa24dce9cbc0180fb60226",
name: "Account 1",
email: "account1#gmail.com",
spaces: ["5e1c4689429a8a0decf16f69", "5e1c4eb9c9461510407d5e81"]
},
{
_id: "5dfa26f46719311869ac1756",
name: "Account 2",
email: "account2#gmail.com",
spaces: ["5e1c4689429a8a0decf16f69", "5e1c4eb9c9461510407d5e81"]
},
{
_id: "5dfa270c6719311869ac1757",
name: "Account 3",
email: "account3#gmail.com",
spaces: ["5e1c4689429a8a0decf16f69"]
}
],
result = spaces.map(({ _id, challengers }) => ({
_id,
challengers: challengers.map(challenger =>
users.find(user => user._id === challenger)
).filter(row => row)
}));
console.log(JSON.stringify(result, null, 2));
You can create a map of challengers for look-up and then put them in spaces.
//create user map for look-up
userMap = users.reduce((res, val) => ({
...res,
[val._id]: val
}), {});
//change challenger id with user object
inflatedSpaces = spaces.map(s => ({ ...s, challengers: s.challengers.map(c => userMap[c]) }));
You could map the users with a Map.
Beside the destructuring of the object for mapping this answer uses for this part
challengers: challengers.map(
Map.prototype.get, // cb with a prototype and using `this`
new Map(users.map(o => [o._id, o])) // thisArg
)
the above mentioned Map in two parts.
The lower part generates an instance of Map where _id of the users items is used as key and the whole object as value. This instance is uses as thisArg of Array#map, the second parameter.
The upper part is a prototype of Map, used as callback. And while an this object is supplied, a binding (Function#bind) is not necessary.
var spaces = [{ _id: '5e1c4689429a8a0decf16f69', challengers: ['5dfa24dce9cbc0180fb60226', '5dfa26f46719311869ac1756', '5dfa270c6719311869ac1757'] }, { _id: '5e1c4eb9c9461510407d5e81', challengers: ['5dfa24dce9cbc0180fb60226', '5dfa26f46719311869ac1756'] }],
users = [{ _id: '5dfa24dce9cbc0180fb60226', name: 'Account 1', email: 'account1#gmail.com', spaces: ['5e1c4689429a8a0decf16f69', '5e1c4eb9c9461510407d5e81'] }, { _id: '5dfa26f46719311869ac1756', name: 'Account 2', email: 'account2#gmail.com', spaces: ['5e1c4689429a8a0decf16f69', '5e1c4eb9c9461510407d5e81'] },{ _id: '5dfa270c6719311869ac1757', name: 'Account 3', email: 'account3#gmail.com', spaces: ['5e1c4689429a8a0decf16f69'] }],
result = spaces.map(({ _id, challengers }) => ({
_id,
challengers: challengers.map(
Map.prototype.get,
new Map(users.map(o => [o._id, o]))
)
}));
console.log(result);
.as-console-wrapper { max-height: 100% !important; top: 0; }
Related
How can i sort and rearrange an array that looks like this
fields = [
{
uid: '2c2162cc-37d0-f1e3-96c2-6d9ccb50f38d',
field: new ObjectId("627f816d8443318c6aaa1220"
},
{
uid: '2aa60f96-135b-e179-2b46-516c87a877cc',
field: new ObjectId("6283cb3ca573a56e11587c46"),
}
]
to match the arrangement of this array:
order = [ '6283cb3ca573a56e11587c46', '627f816d8443318c6aaa1220' ]
Here is the output I’m looking for:
[
{
uid: '2aa60f96-135b-e179-2b46-516c87a877cc',
field: new ObjectId("6283cb3ca573a56e11587c46"),
},
{
uid: '2c2162cc-37d0-f1e3-96c2-6d9ccb50f38d',
field: new ObjectId("627f816d8443318c6aaa1220"),
}
]
findIndex and sort but I am very confused
fields.sort((a: any, b: any) => order.indexOf(a.field) - order.indexOf(b.field)) // It does not work
You need to use sort method on the array. And then compare the index of field on the order array.
const data = [
{
uid: '2aa60f96-135b-e179-2b46-516c87a877cc',
field: "6283cb3ca573a56e11587c46",
value: 'test val 6'
},
{
uid: '2c2162cc-37d0-f1e3-96c2-6d9ccb50f38d',
field: "627f816d8443318c6aaa1220",
value: ''
}
]
const order = [ '6283cb3ca573a56e11587c46', '627f816d8443318c6aaa1220' ];
data.sort((a,b) => order.indexOf(a.field) - order.indexOf(b.field));
console.log(data);
Notice: ObjectId class is not defined here, so I changed it to string here for simplicity.
I have this data
var data = [
{
title: "App development summary",
category: [],
},
{
title: "to experiment 2",
category: [],
},
{
title: "Some of these books I have read",
category: [
{
_id: "5f7c99faab20d14196f2062e",
name: "books",
},
{
_id: "5f7c99faab20d14196f2062f",
name: "to read",
},
],
},
{
title: "Quora users and snippets",
category: [
{
_id: "5f7c99feab20d14196f20631",
name: "quora",
},
],
},
{
title: "Politics to research",
category: [
{
_id: "5f7c9a02ab20d14196f20633",
name: "politics",
},
],
},
];
Say I want to get all the entries with the category of books. I tried doing this:
var bookCat = data.map(note => {
return note.category.map(cat => {
if(cat.name === "books" ) return note
})
})
But the result comes back with some empty and undefined arrays.
I was able to filter the empty arrays (at one point) but not the undefined
Edit
In plain English "if the object ha category.name "books", give me the title"
Filter by whether the array's category contains at least one name which is books:
var data=[{title:"App development summary",category:[]},{title:"to experiment 2",category:[]},{title:"Some of these books I have read",category:[{_id:"5f7c99faab20d14196f2062e",name:"books"},{_id:"5f7c99faab20d14196f2062f",name:"to read"}]},{title:"Quora users and snippets",category:[{_id:"5f7c99feab20d14196f20631",name:"quora"}]},{title:"Politics to research",category:[{_id:"5f7c9a02ab20d14196f20633",name:"politics"}]}];
const output = data
.filter(item => item.category.some(
({ name }) => name === 'books'
));
console.log(output);
If there's guaranteed to be only a single matching object, use .find instead:
var data=[{title:"App development summary",category:[]},{title:"to experiment 2",category:[]},{title:"Some of these books I have read",category:[{_id:"5f7c99faab20d14196f2062e",name:"books"},{_id:"5f7c99faab20d14196f2062f",name:"to read"}]},{title:"Quora users and snippets",category:[{_id:"5f7c99feab20d14196f20631",name:"quora"}]},{title:"Politics to research",category:[{_id:"5f7c9a02ab20d14196f20633",name:"politics"}]}];
const output = data
.find(item => item.category.some(
({ name }) => name === 'books'
));
console.log(output);
customerProducts: [
{
name: "foo",
id: 123
},
{
name: "test",
id: 44
}
]
otherProducts: [
{
name: "other",
id: 44
},
{
name: "test",
id: 21
}
]
I want to iterate through customerProducts, which is an array of objects. I want to filter the customerProducts that have an ID that another array of objects, otherProducts, has. So for examople, I'd want the returned result in this case to be:
{
name: "test",
id: 44
}
since otherProducts has an id of 44.
I was thinking of mapping through otherProducts and just returning an array of IDs, then running a forEach on that but that seems like a long way of doing it.
Create an indexed Set of the values to filter by (id from otherProducts) then filter customerProducts by that Set
const customerProducts = [{name: "foo",id: 123},{name: "test",id: 44}]
const otherProducts = [{name: "other",id: 44},{name: "test",id: 21}]
const otherProductIds = new Set(otherProducts.map(({ id }) => id))
const filteredCustomerProducts = customerProducts.filter(({ id }) =>
otherProductIds.has(id))
console.info(filteredCustomerProducts)
This can be done by using array methods filter and some.
customerProducts.filter((x)=> otherProducts.some(y=> y.id === x.id));
Explanation:
filter method will call each and every element in the otherProducts array and check if the id of customerProduct is present in otherProducts for at least one element.
declare customerProducts , otherProducts as JS array variable and use JS Array filter find functions
let customerProducts = [
{
name: "foo",
id: 123
},
{
name: "test",
id: 44
}
]
let otherProducts = [
{
name: "other",
id: 44
},
{
name: "test",
id: 21
}
];
let filtered = customerProducts.filter( el => otherProducts.find( e => e.id == el.id) )
console.log(filtered);
I am trying to create a new object based off an existing array. I want to create a new object that show below
{ jack: 'jack', content: 'ocean'},
{ marie: 'marie', content: 'pond'},
{ james: 'james', content: 'fish biscuit'},
{paul: 'paul', content: 'cake'}
const words = ['jack','marie','james','paul']
const myUsers = [
{ name: 'jack', likes: 'ocean' },
{ name: 'marie', likes: 'pond' },
{ name: 'james', likes: 'fish biscuits' },
{ name: 'paul', likes: 'cake' }
]
const usersByLikes = words.map(word => {
const container = {};
container[word] = myUsers.map(user => user.name);
container.content = myUsers[0].likes;
return container;
})
I am not getting the correct object, but instead it returns a list.
[ { jack: [ 'shark', 'turtle', 'otter' ], content: 'ocean'}, { marie: [ 'shark', 'turtle', 'otter' ], content: 'ocean' },
{ james: [ 'shark', 'turtle', 'otter' ], content: 'ocean' },
{ paul: [ 'shark', 'turtle', 'otter' ], content: 'ocean'} ]
What is the role of words array? I think the below code will work.
const result = myUsers.map(user => ({
[user.name]: user.name,
content: user.likes
}));
console.log('result', result);
In case, if want to filter the users in word array then below solution will work for you.
const result = myUsers.filter(user => {
if (words.includes(user.name)) {
return ({
[user.name]: user.name,
content: user.likes
})
}
return false;
});
You can achieve your need with a single loop.
The answer #aravindan-venkatesan gave should give you the result you are looking for. However important to consider:
When using .map() javascript returns an array of the same length, with whatever transformations you told it to inside map().
If you want to create a brand new object, of your own construction. Try using .reduce(). This allows you to set an input variable, i.e: object, array or string.
Then loop over, and return exactly what you want, not a mapped version of the old array.
See here for more details:
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/reduce
I'm using EXTJS framework for my code.
below is my array structure:
data = [{
id: 22,
rows: [{
id: "673627",
name: "ABS",
address: "536street"
}, {
id: "333",
name: "TEST$$",
address: "536street"
}, {
id: "999",
name: "TEST$$",
address: "536street"
}]
}, {
id: 33,
rows: [{
id: "899",
name: "TES",
address: "536street"
}, {
id: "333",
name: "TEST$$",
address: "536street"
}, {
id: "999",
name: "TES673",
address: "536street"
}]
}]
Now I want to filter the name from this array, whose value I'm comparing with say "TEST$$".
I'm doing this;
Ext.each(data, function(item) {
filter = item.rows.filter(function(name) {
return name.name === "TEST$$";
}, this);
}, this);
console.log(filter);
In this case, it returns only 1 match, where as I have 3 matches for this particular value. It returns the match from the last item in the data array and hence I dont get all the matching values, any idea how this can be looped to get all values matching?
thx!
You're reassigning the filter variable on every iteration over the data array:
filter = item.rows.filter(function(name) {
return name.name === "TEST$$";
}, this);
On the last iteration, there is only one match, the one with id of 333, so that's the only one that you see after running the Ext.each. Try pushing to an external array that doesn't get overwritten instead:
const testItems = [];
Ext.each(data, function(item) {
const filtered = item.rows.filter(row => row.name === "TEST$$")
testItems.push(...filtered);
});
console.log(testItems);
Note that there's no need to pass along the this context.
Another option is to flatMap to extract all rows to a single array first:
const output = data
.flatMap(({ rows }) => rows)
.filter(({ name }) => name === 'TEST$$');