Develop Reference

Can't Use MAP data structure in Node.js

I have getting some issue in map program in node.js. I am trying to use MAP into node.js program and I am not getting value.I have write some code to use map however I think it not working as its not go into the loop to fetch the key-value.
Please find below program
async CreateProduceMVPRateAsset(data, callback) {
var ProducePRICE = {};
var MVPPRICE =[];
var MVPPRICE_BS ={};
var MVPPRICE_LB ={};
//var ASKINGPRICE= {}// put all the things which need to go to blockchain
const walletPath = path.join(process.cwd(), 'wallet');
const wallet = new FileSystemWallet(walletPath);
console.log(`Wallet path: ${walletPath}`);
console.log('Data', data);
console.log('Username', data.username);
var PRODUCENAME = data.PRODUCE
console.log('PRODUCENAME', PRODUCENAME);
var COUNTRY = data.COUNTRY;
console.log('COUNTRY', COUNTRY);
var STATE = data.STATE;
console.log('STATE', STATE);
var MVPRATES = data.MVPRATES;
console.log('MVPRATERATE', MVPRATES);
const MVPRATE = new Map(MVPRATES);
// program could not go inside the for loop
for (const [k, v] of MVPRATE.entries()) {
console.log("Inside map", k, v)
MVPPRICE = v.RATE // should go in MVPPRICE
var Value = MVPPRICE[0].value // want to get first element value from MVPPRICE array
console.log('Value', Value);
var value_lb = Value/40;
console.log('value_lb', value_lb);
value_lb = Number((value_lb).toFixed(4));
console.log('If the value of BS provided controller come here');
MVPPRICE_LB.Value = value_lb
MVPPRICE_LB.QuantityUnit = 'LB'
MVPPRICE_LB.uidisplay = false
MVPPRICE_LB.CurrencyUnit = 'USD'
MVPPRICE.push(MVPPRICE_LB);
ProducePRICE.MVPPRICE = MVPPRICE
console.log('MVPPRICE',MVPPRICE);
console.log('ProducePRICE',ProducePRICE);
// mvpprice.totalPrice = totalPrice;
console.log('for pricing',totalPrice);
// ProducePRICE.VARIETY = VARIETY;
ProducePRICE.PRODUCENAME = PRODUCENAME;
ProducePRICE.STATE = STATE;
ProducePRICE.COUNTRY = COUNTRY;
}
JSON structure which I am sending using postman
{
"username": "admin2",
"PRODUCE": "Apple",
"STATE": "MI",
"COUNTRY": "US",
"MVPRATES": {
"fuji": {
"VARIETY": "fuji",
"RATE": [
{
"UNIT": "Bussel",
"CURRENCY": "USD",
"VALUE": 10.25,
"UIDISPLAY": true
}
]
},
"gala": {
"VARIETY": "gala",
"RATE": [
{
"UNIT": "Bussel",
"CURRENCY": "USD",
"VALUE": 10.25,
"UIDISPLAY": true
}
]
}
}
}
Output which I am getting:

Seems like you may want to do the following, this creates a Map with two entries, fuji and gala
const MVPRATES = {
"fuji": {
"VARIETY": "fuji",
"RATE": [{
"UNIT": "Bussel",
"CURRENCY": "USD",
"VALUE": 10.25,
"UIDISPLAY": true
}]
},
"gala": {
"VARIETY": "gala",
"RATE": [{
"UNIT": "Bussel",
"CURRENCY": "USD",
"VALUE": 10.25,
"UIDISPLAY": true
}]
}
}
const MVPRATE = new Map(Object.entries(MVPRATES));
for (const [k, v] of MVPRATE.entries()) {
console.log("Inside map", k, v)
}
Though, the need for Map is still unclear, as you can achieve the above with
const MVPRATES = {
"fuji": {
"VARIETY": "fuji",
"RATE": [{
"UNIT": "Bussel",
"CURRENCY": "USD",
"VALUE": 10.25,
"UIDISPLAY": true
}]
},
"gala": {
"VARIETY": "gala",
"RATE": [{
"UNIT": "Bussel",
"CURRENCY": "USD",
"VALUE": 10.25,
"UIDISPLAY": true
}]
}
}
for (const [k, v] of Object.entries(MVPRATES)) {
console.log("Inside map", k, v)
}

How to filter an array of objects based on another array of objects?

I have two array of objects like below
conditions= [
{
'condition': 'Expert',
'value': 'All'
},
{
'condition': 'Coach',
'value': 'willaim'
},
{
'condition': 'manager',
'value': 'Brandy Lovings'
},
{
'condition': 'site',
'value': 'ALL'
},
{
'condition': 'client',
'value': 'ALL'
}
]
data=[
{
"Date": "11/6/2018",
"client": "Verizon",
"Expert": "Ellison, Lauren",
"Coach": "willaim",
"manager": "Brandy Lovings",
"site": "Sundance",
"Metric": "STR"
},
{
"Date": "11/6/2018",
"client": "Amzaon",
"Expert": "Ellison, Lauren",
"Coach": "Dash Williamson",
"manager": "David",
"site": "abc",
"Metric": "STR"
}
]
I want to filter data array with the conditions array, like if condition property in conditions array contain Expert then I need to filter data array based on data.Expert = conditions[Expert Conditionindex].value then I need to return all the data with this conditions.
Another thing is, If value: 'ALL' then no need of filtering in that particular condition.
The desired output is like
filteredData = [
{
"Date": "11/6/2018",
"client": "Verizon",
"Expert": "Ellison, Lauren",
"Coach": "willaim",
"manager": "Brandy Lovings",
"site": "Sundance",
"Metric": "STR"
}
]
How do I solve this problem?

You could filter with a subset of conditions without ALL flag.
var conditions = [{ condition: "Expert", value: "All" }, { condition: "Coach", value: "willaim" }, { condition: "manager", value: "Brandy Lovings" }, { condition: "site", value: "ALL" }, { condition: "client", value: "ALL" }],
data = [{ Date: "11/6/2018", client: "Verizon", Expert: "Ellison, Lauren", Coach: "willaim", manager: "Brandy Lovings", site: "Sundance", Metric: "STR" }, { Date: "11/6/2018", client: "Amzaon", Expert: "Ellison, Lauren", Coach: "Dash Williamson", manager: "David", site: "abc", Metric: "STR" }],
filters = conditions.filter(({ value }) => value.toUpperCase() !== 'ALL'),
result = data.filter(o =>
filters.every(({ condition, value }) => o[condition] === value));
console.log(result);
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This should work for you:
const conditionsObj={}
conditions.filter(({value})=>value.toLowerCase()!=='all').forEach((condition)=>{
conditionsObj[condition.condition]=condition.value
})
const results=data.filter((item)=>{
let match=false;
Object.keys(conditionsObj).forEach((_key)=>{
if(conditionsObj[_key]===item[_key]){
match=true;
}
})
return match;
})
console.log(results)

How to separate array of objects with specific array prefix in typescript

I planed to prepare this array by separate those kind of array with index specification
Default data format
[{
"Emp_code": "EM-00001",
"Emp_title": "11",
"Emp_firstName": "22",
"Emp_lastName": "33",
"Emp_dateOfBirth": "20-10-1985",
"Con_title": "title",
"Con_email": "email",
"Con_addres": "address",
"Con_phone": "phone"
}]
Wanted format
[{
"emp": {
"code": "EM-00001",
"title": "11",
"firstName": "22",
"lastName": "33",
"dateOfBirth": "20-10-1985",
},
"con": {
"Con_title": "title",
"Con_email": "email",
"Con_addres": "address",
"Con_phone": "phone"
}
}]

You can reduce the property names to a starting accumulator of [{ emp: {} }, { con: {} }] and each iteration you can add the property to the corresponding item in the accumulator.
const data = [{
"Emp_code": "EM-00001",
"Emp_title": "11",
"Emp_firstName": "22",
"Emp_lastName": "33",
"Emp_dateOfBirth": "20-10-1985",
"Con_title": "title",
"Con_email": "email",
"Con_addres": "address",
"Con_phone": "phone"
}];
const format = obj =>
Object.getOwnPropertyNames(obj[0]).reduce(
(acc, prop) => {
if (prop.startsWith('Emp_')) {
acc[0].emp[prop.replace('Emp_', '')] = obj[0][prop];
} else {
acc[1].con[prop] = obj[0][prop];
}
return acc;
},
[{ emp: {} }, { con: {} }]
);
console.log(format(data));

var item = {
"Emp_code": "EM-00001",
"Emp_title": "11",
"Emp_firstName": "22",
"Emp_lastName": "33",
"Emp_dateOfBirth": "20-10-1985",
"Con_title": "title",
"Con_email": "email",
"Con_addres": "address",
"Con_phone": "phone"
}
var data = [item, item];
var res = []
for (var item of data) {
var temp = {};
res.push(temp);
for (var prop in item) {
var parts = prop.split('_');
var prefix = parts[0].toLowerCase();
temp[prefix] = temp[prefix] || {};
temp[prefix][prefix === 'emp' ? parts[1] : prop] = item[prop]
}
}
console.log(res);

Below script checks element using loops, then splits them into prefix & suffix. Then checks for whether prefix is present in resulting array or not. If it's not then adds that prefix into array & prepares the result.
var a = [{"Emp_code": "EM-00001", "Emp_title": "11", "Emp_firstName": "22", "Emp_lastName": "33", "Emp_dateOfBirth": "20-10-1985", "Con_title": "title", "Con_email": "email", "Con_addres": "address", "Con_phone": "phone"}];
var b = [];
$.each(a, function(arrKey, arrData){
var tempArr = {};
$.each(arrData, function(key, value){
var arrKey = key.split('_');
var prefix = arrKey[0];
var suffix = arrKey[1];
if( $.inArray(prefix, Object.keys(tempArr)) == -1 ) {
tempArr[prefix] = {};
}
tempArr[prefix][suffix]=value;
});
b.push(tempArr);
});
console.log(b);

Match two object keys and display another object key value in angular 4

i have two objects like this
languages = [
{
"name": "english",
"iso_639_2_code": "eng"
},
{
"name": "esperanto",
"iso_639_2_code": "epo"
},
{
"name": "estonian",
"iso_639_2_code": "est"
}
]
and another is
user = [
{
name: "john",
language: "eng",
country: "US"
}
];
what i have to do is, match iso_639_2_code to language of user then, i have to display Language name not code from languages. basically both are different api, and i have no idea how to do it this in angular 4.
here's a link what i am trying https://stackblitz.com/edit/angular-9k2nff?file=app%2Fapp.component.ts

Use array find:
var languages = [
{"name": "english", "iso_639_2_code": "eng"},
{"name": "esperanto","iso_639_2_code": "epo"},
{"name": "estonian","iso_639_2_code": "est"}
];
var user = [{name: "john",language: "eng",country: "US"}];
var language = languages.find(l => l.iso_639_2_code === user[0].language);
var languageName = language && language.name; // <-- also prevent error when there is no corresponding language found
console.log(languageName);
EDIT:
With multiple user, it will be:
var languages = [
{"name": "english", "iso_639_2_code": "eng"},
{"name": "esperanto","iso_639_2_code": "epo"},
{"name": "estonian","iso_639_2_code": "est"}
];
var users = [
{name: "john",language: "eng",country: "US"},
{name: "john",language: "epo",country: "Esperanto"}
];
var languageNames = languages.filter(
l => users.find(u => l.iso_639_2_code === u.language)
).map(lang => lang.name);
console.log(languageNames);

Use find
var output = languages.find(s => s.iso_639_2_code == user[0].language).name;
Demo
var languages = [{
"name": "english",
"iso_639_2_code": "eng"
},
{
"name": "esperanto",
"iso_639_2_code": "epo"
},
{
"name": "estonian",
"iso_639_2_code": "est"
}
];
var user = [{
name: "john",
language: "eng",
country: "US"
}
];
var output = languages.find(s => s.iso_639_2_code == user[0].language).name;
console.log(output);
Or, if there are multiple users, and you want to find language name for each of them, then use map
var output = user.map(t =>
languages.find(s =>
s.iso_639_2_code == t.language).name);
Demo
var languages = [{
"name": "english",
"iso_639_2_code": "eng"
},
{
"name": "esperanto",
"iso_639_2_code": "epo"
},
{
"name": "estonian",
"iso_639_2_code": "est"
}
];
var user = [{
name: "john",
language: "eng",
country: "US"
}
];
var output = user.map(t =>
languages.find(s =>
s.iso_639_2_code == t.language).name);
console.log(output);

I think here is what you need , for output just run the snippet :
var languages = [
{
"name": "english",
"iso_639_2_code": "eng"
},
{
"name": "esperanto",
"iso_639_2_code": "epo"
},
{
"name": "estonian",
"iso_639_2_code": "est"
}
];
var user = [
{
name: "john",
language: "eng",
country: "US"
}
];
user.map(u => {
let flang = languages.filter(lang => lang.iso_639_2_code === u.language);
if(flang) {
u.language = flang[0].name;
}
return u;
})
console.log(user);

var languages=[
{"name":"english","iso_639_2_code":"eng"},
{"name":"esperanto","iso_639_2_code":"epo"},
{"name":"estonian","iso_639_2_code":"est"}
];
var user=[
{name:"john",language:"eng",country:"US"}
];
var languageFound = languages.find(lang => lang.iso_639_2_code === user[0].language);
if(languageFound){
var languageName = languageFound.name;
console.log(languageName);
}

Organise element in a array

i'm searching a smart way to reoganise an array by a element inside it:
In entry i've got:
[{"name": "brevet",
"country": "fr"
},{
"name": "bac",
"country": "fr"
},{
"name": "des",
"country": "ca"
},{
"name": "dep",
"country": "ca"
}{
"name": "other",,
"country": "other"}]
I want to reorganize my array by country to have this in my output:
[{
"name": "fr",
"degrees": [
{
"name": "brevet",
"country": "fr"
},{
"name": "bac",
"country": "fr"
}]
},{
"name": "ca",
"degrees": [{
"name": "des",
"country": "ca"
},{
"name": "dep",
"country": "ca"
}]
},{
"name": "other",
"degrees": [{
"name": "other",
"country": "other"
}]
}]
For this i write a dirty function, but it seems to me there is a better way but i don't see how. If someone can ligth my brain in a better way to do this i'll be helpfull
private organizeDegrees(degrees: Array<SubscriptionFieldInterface>) {
let degreesByCountry = new Array();
let storeIndex = new Array();
degrees.map(degree => {
let index = null;
storeIndex.find((element, idx) => {
if (element === degree.country) {
index = idx;
return true;
}
});
if (index === null) {
index = degreesByCountry.length;
let newEntry = {
'name': degree.country,
'degrees': new Array()
};
storeIndex.push(degree.country);
degreesByCountry.push(newEntry);
}
degreesByCountry[index].degrees.push(degree);
});
return degreesByCountry;
}
thank's

You can group the array and map the object using Object.keys:
var groupBy = function(xs, key) {
return xs.reduce(function(rv, x) {
(rv[x[key]] = rv[x[key]] || []).push(x);
return rv;
}, {});
};
var grouped = groupBy(array, "country");
var mappedArray = Object.keys(grouped).map(key => ( {name: key, degrees: grouped [key]} ));

And one more way:
arr = [ /* your array */ ];
arr = Object.values(arr.reduce((ac, el) => {
if(!ac[el.country]) ac[el.country] = {"name": el.country, "degrees": []}
ac[el.country].degrees.push(el);
return ac
}, {}))
console.log(arr) // formated

Another solution, which also handles 'id' => '#id' mapping:
const a = [{"name":"brevet","country":"fr"},{"name":"bac","country":"fr"},{"id":73,"name":"des","country":"ca"},{"name":"dep","country":"ca"},{"name":"other","country":"other"}];
const r = [...new Set(a.map(({country}) => country))] // list of unique country names
.map(c => Object.assign({name: c}, // for each country
{degrees: a.filter(x => x.country === c).map(y => Object.keys(y).includes('id') // handle 'id' => '#id' mutation
? {'#id': "/subscription_fields/" + y.id, name: y.name, country: y.country}
: y)
}))
console.log(r)

This is purely ES6, and quite terse, but possibly less readable. Also, it doesn't add the "#id": "/subscription_fields/83", which could be added as a post process:
const groupByKey = (arr, key) => [...arr.reduce((acc, deg) =>
acc.set(deg[key], {name: deg[key], degrees: [ ...(acc.get(deg[key]) || {degrees: []}).degrees, deg]})
, new Map()).values()];
console.log(groupByKey(degrees, 'country'));

You could use a hash table and collect all values in an object. For getting the result array, you need to push the object only once.
var data = [{ name: "brevet", country: "fr" }, { name: "bac", country: "fr" }, { id: 73, name: "des", country: "ca" }, { name: "dep", country: "ca" }, { name: "other", country: "other" }],
result = data.reduce(function (hash) {
return function (r, a) {
if (!hash[a.country]) {
hash[a.country] = { name: a.country, degrees: [] };
r.push(hash[a.country]);
}
hash[a.country].degrees.push({ name: a.name, country: a.country });
return r;
};
}(Object.create(null)), []);
console.log(result);
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