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Does one push everytime creates array inside of array? [closed]

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I created button that is generate a random number every time , but in the console log it shows it like this:
small project i have been working on during course of javascript
I tried to make one array of random numbers and when it reach above 4 random numbers i will use Shift method to erase one. ( I also tried to use for loop )
What actually happen that is it kind of creates me new array inside of the orginal array
let randomArr = [];
if (randomArr.length >= 4) {
randomArr.shift();
lastNumbers.textContent -= randomArr + ",";
return randomArr;
} else {
randomArr.push(randomNumber);
// randomArr.length = randomArr;
lastNumbers.textContent += randomArr + ",";
// return randomArr;
}
Ty for helping!

Can i convert math.js object into JavaScript function? [closed]

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I'm developing simple js neural network and need to create javascript function (derivative of entered by user) before learning starts.
I know about evaluate(), but i think it'll be slowly than simple function.
That is what i want:
const derivative = math.derivative('x^2/sin(2x)', 'x');
const derivative_func = derivative.please_stay_func();
...
while(1) alert(derivate_func(12)) //:) alert result of (2 * 12 * Math.sin(2*12) - 2 * Math.pow(12, 2) * Math.cos(2*12)) / Math.pow(sin(2*12), 2)
Is it real? And maybe i'm not right about speed. Maybe there is some better ways - write here.

i am on mobile, please edit this
maybe this is want you want to do
const countThings = (customValue) ==>{
let x = 'x^2/sin(x)';
let y = 'x';
x = math.parse(x)
y = math.parse(y)
return math.derivative(x, y).evaluate({x:customValue});}
console.log(countThings(12))
and don't do while(1) alert because it will keep alerting

Javascript - Sum solution [closed]

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I am getting below line in my source file and I would like to sum those values separated by pipe ("|")
There is no limit for the values coming in the line (might be 100 values)
10|20|30|40|[no limit for values] - Separator is pipe "|"
The ouptput would be 100
Please help to write a javascript function for the above query.
Regards
Jay

You should take a look at JavaScript's built-in functions: With split you can split your string into an array, with reduce you can 'reduce' your array to a single value, in that case via summation. These two links should provide you enough information for building your code.

You could try something like below:
function sum(value){
var total = 0;
var array = value.split(",").map(Number);
for( var i = 0; i < array.length; i++) {
total += array[i];
}
alert(total);
}
var value = "10|20|30|40".replace(/\|/g, ',');
console.log(sum(value));
https://jsfiddle.net/f7uqw7cL/

Need idea how to implement it [closed]

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Can you give me an idea may be using javascript, jquery or angular
I am generating three random array
for eg:
(This values are generating using random array =['member', 'medical', 'rx', 'disability'];)
and output
member disability medical disability
medical member disability rx
disability disability medical member
disability member member disability
how do i calculate whether which value is in all column and maximum occured
for example disability is the answer
thanks

In JS you can use JSON to count the number of occurring of a word in your arrays:
var countArr = [
{"word":"member", "occur":0},
{"word":"disability ", "occur":0}
];
var All = random1.concat(random2).concat(random3);
for(i = 0; i < All.length; i++){
count(All[i]);
}
function count(word){
var x = countArr.findIndex(function(elm){ return elm.word == word;});
if(x != -1){
++countArr[x].occur;
}
else{
countArr.push({"word":word, "occur":0});
}
}
and you can easily add more details to your JSON about your word for example the index of occurring a word in your arrays.

How do I rearrange an array with similar items so that similar items will never neighbor each other? [closed]

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So for example if I have this array:
var input = [1,1,2,4,6,7,7,1];
I want the output to be something like:
[1,2,1,4,6,7,1,7]
The order of the new array does not matter, as long as similar items will never (or at least as seldom as possible) neighbor each other.
I can use plain JavaScript as well as underscore.js.

Try the following:
var input = [1,1,2,4,6,7,7,1];
input.sort()
var output = [];
var len = input.length;
for (var i = 0; i < Math.floor((len / 2)); i++) {
output.push(input[i]);
output.push(input[len - i - 1]);
}
if (len % 2) {
var left_over = input[Math.floor(len / 2)];
if (left_over == output[0]) {
output.push(left_over);
} else {
output.unshift(left_over);
}
}
Or see http://jsfiddle.net/d0j3Lfa3/1.
The solution sorts the numbers then alternates high and low. It deals with an odd number of elements, including corner cases such as [1,1,2] and [1,2,2] where it needs to push the middle element differently to pass. Since the input is sorted, input order doesn't affect the output.
This answer may help simplify things a bit.