Async/Await confusion in JS - javascript

I was learning asynchrony in JS and came across Async/Await. Then, I came across this code:
function scaryClown() {
return new Promise(resolve => {
setTimeout(() => {
resolve('🤡');
}, 2000);
});
}
async function msg() {
const msg = await scaryClown();
console.log('Message:', msg);
}
msg(); // Message: 🤡 <-- after 2 seconds
Thus, I have questions on the above code. Firstly, how can async function msg() return message value if the function itself returns only undefined Promise, that is, the function does not explicitly use return keyword. Secondly, does await returns Promise or value itself having been unwrapped from Promise?

function scaryClown() {
return new Promise(resolve => {
setTimeout(() => {
resolve('🤡');
}, 2000);
});
}
The above function is a function which returns a promise when it is called, but will only be resolved after 2 seconds.
async function msg() {
const msg = await scaryClown();
console.log('Message:', msg);
}
the above function is asynchronous function which awaits for the promise to be resolved (in your case, after 2 seconds) and then only the console.log() triggers.
Note: any lines of code below the function msg() gets executed irrespective of the promise and the asynchronous function.
Running code snippet
function scaryClown() {
return new Promise(resolve => {
setTimeout(() => {
resolve('🤡');
}, 2000);
});
}
async function msg() {
console.log(scaryClown()); // try without await, so it will not wait for the result and prints first, but an unresolved promise
const msg = await scaryClown(); // actual result which is resolved, because we awaited
console.log('Message:', msg); // Prints once the resolved value is available.
}
msg(); //executes first but only prints the value once it is resolved.
console.log('I will continue executing irrespective of async func msg()');

async function msg() {
const msg = await scaryClown();
console.log('Message:', msg);
}
await resolves promise and return resolved value. so above code with then can be written like below. hope this makes you understand async await.
function msg() {
scaryClown().then(msg => {
console.log('Message:', msg);
});
}

This is what happens:
When the async function (i.e. msg) is invoked, it creates a promise object (let's call it P), which it will return when it deals with an await expression. scaryClown() executes, which sets the timer and returns yet another promise object; let's call it Q. Then await is processed: at that moment the function returns the promise P. This promise is not resolved at that moment; it is pending.
If then there is any other code that followed the call of msg(), then that is executed like would be the case after any function call. Execution continues until the call stack is empty.
Then, some time later the timer event that was scheduled by scaryClown() will fire, and the corresponding promise Q resolves. Because this promise Q was in an await expression, this resolution triggers a restoration of the execution context of msg(), where the await expression is now evaluated to be Q's resolved value, i.e. "🤡".
The variable msg gets this value assigned, and it is displayed with console.log. Then the function completes, in this particular case without any explicit return. Remember that the function had already returned, so this is not really a normal return: code execution really ends here, as there is nothing on the call stack. This makes the promise P resolve. If there had been an explicit return statement, with a value, the promise P would have been resolved with that value. But since there is no such return statement in your example, promise P resolves with undefined.
As you don't do anything with the value returned by msg(), you don't really see what it returns. If you would have done:
msg().then(console.log);
... you would have seen undefined in the console.
Your questions:
how can async function msg() return message value if the function itself returns only undefined Promise, that is, the function does not explicitly use return keyword.
The msg() call does currently not provide you with the message value. Instead it uses console.log to output it, but that is not the value returned by msg(). The returned value is a promise. Even if it had an explicit return keyword, it would still not make msg() return something else than a promise. The only difference would be what value that promise would eventually resolve to.
does await returns Promise or value itself having been unwrapped from Promise?
await does two things at two different moments in time. First it makes the function return to the caller. Then, when the promise that it awaits resolves, it makes the function continue to run again, and await represents at that moment the promised value, which can therefore be assigned to a variable (or used in another way).
I personally don't use the verb "unwrapped" when talking about promises. But yes, the expression await promise evaluates (asynchronously) to the value that promise fulfils to.

Related

How to access value from a promise in typescript? [duplicate]

I am trying to wrap my head around promise object in JavaScript. So here I have this little piece of code. I have a promise object and two console.log() on either side of the promise object. I thought it would print
hi
There!
zami
but it printed
hi
zami
There!
Why it is like that? I have zero understanding on how promise works, but I understand how asynchronous callback works in JavaScript. Can any one shed some light on this topic?
console.log('hi');
var myPromise = new Promise(function (resolve, reject) {
if (true) {
resolve('There!');
} else {
reject('Aww, didn\'t work.');
}
});
myPromise.then(function (result) {
// Resolve callback.
console.log(result);
}, function (result) {
// Reject callback.
console.error(result);
});
console.log('zami');
Summary:
A promise in Javascript is an object which represent the eventual completion or failure of an asynchronous operation. Promises represent a proxy for a value which are getting in some point in the future.
A promise can have 3 states which are the following:
Pending: This is the initial state of the promise, the promise is now waiting for either to be resolved or rejected. For example, when are reaching out to the web with an AJAX request and wrapping the request in a promise. Then the promise will be pending in the time window in which the request is not returned.
Fulfilled: When the operation is completed succesfully, the promise is fulfilled. For example, when we are reaching out to be web using AJAX for some JSON data and wrapping it in a promise. When we are succesfully getting data back the promise is said to be fulfilled.
Rejected: When the operation has failed, the promise is rejected. For example, when we are reaching out to be web using AJAX for some JSON data and wrapping it in a promise. When we are getting a 404 error the promise has been rejected.
Promise Constructor:
We can create a promise in the following manner:
let prom = new Promise((res, rej) => {
console.log('synchronously executed');
if (Math.random() > 0.5) {
res('Success');
} else {
rej('Error');
}
})
prom.then((val) => {
console.log('asynchronously executed: ' + val);
}).catch((err) => {
console.log('asynchronously executed: ' + err);
}).finally(() => {
console.log('promise done executing');
});
console.log('last log');
Points of interest:
The code inside the promise constructor is synchronously executed.
then method takes as a first argument a callback which is asynchronously executed on promise fulfillment.
then method takes as a second argument a callback which is asynchronously executed on promise rejection. However we are usually using the catch method for this (because this is more verbose), which also takes a callback which is asynchronously executed on promise rejection. catch is essentially the same as then(null, failCallback).
The then callback receives as a first argument the resolved value (the string 'success' in this case).
The catch callback receives as a first argument the rejected value (the string 'Error' in this case).
The finally method receives a callback which is executed on both promise fulfillment and rejection. Here we can write 'cleanup' code which need to be executed always regardless of promise outcome.
Your example:
In your code 'Zami' was printed before 'there' because the log which logged 'there' was in a then callback function. We earlier pointed out that these callbacks are executed asynchronously and thus will be executed last.
Promise execution is asynchronous, which means that it's executed, but the program won't wait until it's finished to continue with the rest of the code.
Basically, your code is doing the following:
Log 'Hi'
Create a promise
Execute the promise
Log 'zami'
Promise is resolved and logs 'There'.
If you want it to print 'Hi there, zami', you will have to
myPromise.then(function (result) {
// Resolve callback.
console.log(result);
console.log('zami');
}, function (result) {
// Reject callback.
console.error(result);
});
Even though you resolved the promised synchronously, the handlers you pass into then get called asynchronously. This is according to the defined specification:
onFulfilled and onRejected execute asynchronously, after the event loop turn in which then is called, and with a fresh stack
I would recommend you to understand how event loop works in JavaScript.
take time and watch this Video.
It will clear your doubts.
A Promise is an object representing the eventual completion or failure of an asynchronous operation.
Below is the example of promise:
const post = new Promise((resolve, reject) => {
resolve("Appended from getPostWithPromise()");
});
const getPostWithPromise = function () {
post
.then(function (fulfilled) {
$("body").append("<div>" + fulfilled + "</div>");
})
.catch(function (error) {
console.log(error);
});
}
function getPostWithoutPromise() {
$("body").append("<div>Appended from getPostWithoutPromise()</div>");
}
$(function () {
getPostWithPromise(); // this will print last
getPostWithoutPromise(); // this will print first
$("body").append("<div>Appended directly</div>"); // second
});
you can test it => JavaScript Promises example
for detail understanding you can read this post => https://scotch.io/tutorials/javascript-promises-for-dummies
Promise:
new Promise((resolve, reject) => {
resolve(whateverObject)
reject(whateverErrorObject)
})
It is just object that can be chained with then()
You also can make promise! you can return whatever object in that success parameter (resolve) and error parameter (reject)
so very simple concept bro!
Promises are objects.
Each promise object has a then method.
The then method of the promise object accepts a function as a first parameter.
If we call the then method of a promise, the callback function will be executed once the promise gets resolved.
Flow of execution
const promiseObj = new Promise((res, rej) => {
console.log("Promise constructor are synchronously executed");
res("Hii Developer");
})
const callbackFunction = (resolvedValue) => console.log("Resolved Value ", resolvedValue);
promiseObj.then(callbackFunction);
console.log("I am the executed after the constructor");
In the above example, we have created a promise object using the Promise constructor.
The constructor function is synchronously executed.
After creating the promise object, we are calling the then method of the promise object. We have passed a callback function in the first argument of the then method. This callback function will be executed once the promise gets resolved and the stack of the js engine gets empty.
Promise is a object that represents the completion or failure of a event . Promise is a asynchronous thing in JS which means that it's executed, but the program won't wait until it's finished to continue with the rest of the code. So it wont be executed simultaneously. It would take time to either complete or fail for a given task and then execution.
In your Case
log'Hi'.
First your mypromise variable will store a promise object i.e either rejected or resolved(for this, it would take time)
But JS engine will execute further code first then the asynchronous task. SO u will get 'zami'.
once the promise resolved or rejected. It will be called or used wherever it is used in the code. In this case ,it is resolved and log 'there!' in console.
let prom = new Promise((res, rej) => {
console.log('synchronously executed');
if (Math.random() > 0.5) {
res('Success');
} else {
rej('Error');
}
})
prom.then((val) => {
console.log('asynchronously executed: ' + val);
}).catch((err) => {
console.log('asynchronously executed: ' + err);
}).finally(() => {
console.log('promise done executing');
});
console.log('last log');

How to use await with async function without creating a Promise?

I know an async function returns a Promise, so I thought of replacing this code:
const hi = function (delay) {
return new Promise((resolve, reject) => {
setTimeout(() => {
console.log('hi');
resolve();
},delay)
});
};
const bye = async () => {
await hi(1000);
await hi(1000);
await hi(1000);
await hi(1000);
return 'bye';
};
bye().then((msg) => {
console.log(msg);
});
with this code:
const hi = async (delay) => {
setTimeout(() => {
console.log('hi');
},delay);
};
const bye = async () => {
await hi(1000);
await hi(1000);
await hi(1000);
await hi(1000);
return 'bye';
};
bye().then((msg) => {
console.log(msg);
});
The only difference is I'm using an async function instead of a function which returns a Promise, since an async function return a promise. But the second code doesn't work as I expected it too. It just console.logs bye immediately and then after 1s console.logs 'hi' 4 times. Can you please help me understand the reason behind this?
One major difference in both code examples is related to the return value of hi function.
In the first code example, function hi returns a promise whereas in the second code example, function hi does not explicitly returns any value; as a result, the promise returned by the async function is implicitly resolved with the value of undefined without waiting for the setTimeout's callback function to execute.
A promise object doesn't makes anything asynchronous; its just a wrapper around an already asynchronous operation and the promise object notifies whether the asynchronous operation completed successfully or whether it failed.
In the first code example, you have a wrapper promise around the setTimeout. That wrapper promise is not fulfilled until resolve is called from within the callback function of the setTimeout.
In the second code example, the promise returned by the async function isn't automatically bound to the asynchronous code inside the function.
After calling setTimeout, code execution reaches the end of the hi function; As there is no explicit return statement, promise returned by the async function is fulfilled with the value of undefined. This happens before the callback function of the setTimeout is called.
What's confusing you here is the setTimeout, your await hi( will actually await, but there isn't anything to wait for, that promise will almost immediately resolve and return so all 4 of them will execute almost instantaneously, then log "bye", then after 1 second your timeout will trigger and console.log "hi".
This answer adds some additional info to the one provided by Yousaf.
To shortly answer your comment:
Thanks for the explanation. Is there any way to write the hi function without using the 'Promise' keyword?
The answer is no. To convert a function using a callback interface to one that uses a promise you will have to manually create a promise somewhere. Functions using an older interface (usually) don't return promises, therefore you cannot await them. You can only await objects that are thenable (i.e. has a "then" method). If you await a non-thenable value or object, the await statement is essentially ignored.
MDN recommends wrapping callback methods at the lowest level possible:
Creating a Promise around an old callback API
A Promise can be created from scratch using its constructor.
This should be needed only to wrap old APIs.
In an ideal world, all asynchronous functions would already return
promises. Unfortunately, some APIs still expect success and/or failure
callbacks to be passed in the old way. The most obvious example is the
setTimeout() function:
setTimeout(() => saySomething("10 seconds passed"), 10*1000);
Mixing old-style callbacks and promises is problematic. If
saySomething() fails or contains a programming error, nothing
catches it. setTimeout is to blame for this.
Luckily we can wrap setTimeout in a promise. Best practice is to
wrap problematic functions at the lowest possible level, and then
never call them directly again:
const wait = ms => new Promise(resolve => setTimeout(resolve, ms));
wait(10*1000).then(() => saySomething("10 seconds")).catch(failureCallback);
Basically, the promise constructor takes an executor function that
lets us resolve or reject a promise manually. Since setTimeout()
doesn't really fail, we left out reject in this case.
If you would apply this info to your situation, this means wrapping the setTimeout() call within a Promise constructor like shown above.
// The only responsibility of this function is converting the old
// callback interface, to a promise interface.
function wait(ms) {
return new Promise(resolve => setTimeout(resolve, ms));
}
Then use this new function in hi() instead of setTimeout().
async function hi(delay) {
await wait(delay);
console.log('hi');
}
A promise captures the result of an asynchronous processing that just started.
On the version of the code without promises, the asynchronous processing happens the same way as on the first version but there is nobody there waiting for it when it completes.
The second version of the hi() function is synchronous. It completes immediately. The async keyword does not have any effect on it. Also await hi() does not help, the function is still synchronous and it completes immediately.

Typescript/JavaScript - Why does my promise run through after I'll resolved?

I have this function:
export async function promisePlay(example: someInterface): Promise<string> {
const data = await fetch(example.url)
return new Promise((resolve, reject) => {
resolve("Lets test this")
console.log("This point shouldnt be reached");
})
}
When I run this I'm seeing the text This point shouldnt be reached in the console output. What I want (and thought) was that the resolve() should return and stop from running further.
Could someone please tell me what I'm fundamentally misunderstanding and how to correct?
Thanks.
resolve is a function in a variable.
You are calling the resolve function and passing the return value of the promise as the parameter.
However, that does not stop execution or break out.
If you want to exit the function, you must use return;.
Calling resolve does stop the pending await command of wherever you called the original function.
Whatever you value you pass to return will not be passed to the variable that resolves the promise and it will not stop the pending promise in the await command.
function test(yourWord)
{
return new Promise((resolve, reject) =>
{
// This will allow the command
// let res = await test("hello");
// to continue executing. It will stop executing on that line
// unless you call resolve or reject
resolve("you said: " + yourWord);
// this will continue to execute
console.log("I'm still alive");
// this string return value will be ignored
return "blah blah";
// this will not be executed since the function has returned
console.log("I'm dead");
});
}
(async () =>
{
// this will pause execution until resolve or reject is called and
// whatever value is passed into resolve() will be assigned to res
let res = await test("hello");
// this will echo out "you said hello"
console.log("res: " + res);
})();
You can return the resolve
export async function promisePlay(example: someInterface): Promise<string> {
const data = await fetch(example.url)
return new Promise((resolve, reject) => {
return resolve("Lets test this")
console.log("This point shouldnt be reached");
})
}
Promise body is synchronous, when you resolve the promise, it won't return(stop executing further statements).
I think you are confused between promises resolve and returning from them.
Consider below example,
new Promise((resolve) => {
console.log("inside promise");
resolve("promise resolved");
console.log("after resolving");
}).then(val => console.log(val));
In the above snippet, the console will print inside promise then after removing. It means it will execute all the statement in the promise first then it will wait for the promise to resolve. If you don't want to execute any statement further resolve, you can add return resolve in the function, cause its a normal function anyhow.
A JS promise has 3 states initial, fulfilled and rejected.
When awaiting a promise, the code waits for the state to change from initial to either rejected or resolved before execution continues.
When you await your promisePlay() function, execution will continue after the await as soon as reject() or resolve() is called.
Your case is special because you have code after you have resolved() within your promise.
It appears that during some experimentation of my own, it appears the JS engine waits until all the code is executed after the resolve(), I suppose its a bad idea to rely on this behaviour, as other answers suggest perhaps you should be return the result you want within in the resolve

How to await an asynchronous function?

My case:
let waiting = function () {
return new Promise(resolve => {
console.log('awaiting...');
setTimeout(function () {
resolve();
}, 1000)
});
};
let waitingAsync = async function () {
console.log('start...');
await waiting();
console.log('stop...');
};
waitingAsync();
console.log('done...');
There are 2 things I don't understand in the code:
The first:
await waiting();
waiting is a synchronous function (because it doesn't have async keyword). So, why can I await a synchronous function?
The second:
Why couldn't done... message be awaited after completing waitingAsync function?
And main question: waitingAsync is an asynchronous function, why is await keyword not required when calling it? Just waitingAsync() instead of await waitingAsync().
If I can await waitingAsync(), done... message would be printed last.
This isn't a function but a value that it returns which is awaited with await statement.
async and normal functions aren't different to the caller. async just returns a promise without returning it explicitly when being called. The result of waitingAsync() call is a promise. The result of waiting() call is a promise, too, so it isn't 'synchronous'.
According to the spec, both promises and non-promises can be awaited. Non-promises are converted to promises with Promise.resolve().
console.log('done...') can't be awaited because it isn't called inside async function. And it doesn't have to be awaited because it doesn't return a promise but undefined. awaiting it would be possible within async function. These await usages are equal and equally useless, all they do is 1 tick delay:
async function ... {
...
await console.log('done...');
}
async function ... {
...
console.log('done...');
await undefined;
}
async function ... {
...
await Promise.resolve(console.log('done...'));
}
A async function does return a promise or, when it uses the await keyword, it must wait for a asynchronous function, being a Promise or another async function. In your code, waiting() is a function that returns a Promise. Then, await waiting() is correct (since it is waiting for a asynchronous function).
An async function is called as another basic functions is called. You may mark a function as async when you desire operate it as an asynchronous function and using the 'await' keyword. The 'done...' is printed because when you call asyncFunction(), it must await until waiting promise is finished. But the program is not stopped and go on showing done.... If you want to wait for it, maybe you can use asyncFunction().then( () => console.log('done...') )
Async keyword used to specify that function will be an instance of AsyncFunction so it will return Promise.
Await is used to wait for a promise resolving inside of async function.
According to a mdn - async function can contain an await expression, that pauses the execution of the async function and waits for the passed promise's resolution, and then resumes the async function's execution and returns the resolved value.
When you await a function, if that function returns a promise, its return value will be treated as the promise then value. If the promise will reject, it will be cast to an Error. If the function call returns something ohter than a thenable, well, await then just doesn't nothing.
In the other hand, when you declare an async function, its return value will be returned as a Promise, and any Error thrown from it will be casted to a rejected Promise.
You can use await only within an async declared function.
that's just about async and awaitare, just automatic casting to promises. You don't actually need code using await and async to be really asynchronous (while, well, it's not really useful).
A quick demonstration:
//Will return the string 'Promise' if called through `await`
function getPromise(){
return Promise.resolve('Promise');
}
//Casted to Promise.reject thrught await
function throwError(){
return Promise.reject('error');
}
function get(){
return 'something simple';
}
async function getAsync() {
var response = await getPromise();
return response;
}
//await will cast the rejected Promise to an error
async function getErrorAsync() {
var response = await throwError();
return response;
}
async function simpleGet(){
return get();
}
async function redundantGet(){
return await get();
}
async function catchTheError(){
try{
await throwError();
}
catch(e){
console.log('an error: ' + e );
}
return 'whatever';
}
getAsync().then( console.log ); //Promise
getErrorAsync().catch( console.log ); //error
simpleGet().then( console.log ); //something simple
redundantGet().then( console.log ); //something simple
catchTheError(); //will log 'an error: error'.
So:
waiting is a synchronous function (because it doesn't have async keyword). So, why can I await a synchronous function?
Because you can. The only thing await does is to resolve promise to real values and errors. You don't actually need the function to return a promise.
Why couldn't done... message be awaited after completing waitingAsync function?
async and await only makes your code to behave as it would be synchronous iside asyncdeclared functions. Your last console.log('done') is outside any async function, so it will be just logged before that function ends, since it is asynchronous.
And main question: waitingAsync is an asynchronous function, why is await keyword not required when calling it? Just waitingAsync() instead of await waitingAsync().
Because async keyword casts values to promises -and allows to use await- and nothing more. In fact, since you can only use await inside async functions... you can't expect async functions to be called through await, you would need infinite asyncfunctions :-D.
Before diving in, it's good to notice a few things.
Any reader of the code snippet
let waiting = function () {
return new Promise(resolve => {
console.log('awaiting...');
setTimeout(function () { resolve(); }, 1000);
});
};
let waitingAsync = async function () {
console.log('start...');
await waiting();
console.log('stop...');
};
waitingAsync();
console.log('done...');
may be mislead to believe that the output will be
start...
awaiting...
stop...
done...
while – as you have already noted – done... gets printed before
stop....
The reason is that waitingAsync(); is a call to an asynchronous function,
while console.log('done...'); is just a normal sequential/synchronous
statement that gets carried out right away.
Question 1:
waiting is a synchronous function (because it doesn't have async
keyword) [?]
Answer:
False. The function waiting is asynchronous – it returns
a Promise.
Question 2:
Why couldn't done... message be awaited after completing waitingAsync
function?
Answer:
Because console.log('done...') is not asynchronous.
(It does not return a Promise.)
Question 3:
And main question: waitingAsync is an asynchronous function, why is
await keyword not required when calling it?
Answer:
Well, in your example waitingAsync does not return any value. -
If it would return a value that you care about, then you would need to await
it to get it.
(Hello world! in my Stack Snippet below.)
Question 4:
If I can await waitingAsync(), [the] done... message would be printed
last [?]
Answer:
That depends on what exactly you mean. – See my Stack Snippet below!
As long as the Done! message is printed within the same callback as the call
await waitingAsync(), the answer is Yes!
But if you put console.log('done...?') after the call to the asynchronous
function that encloses await waitingAsync() then the answer is No!
When running the snippet below, pay attention to the order of the output!
Also notice how it takes 1400 ms for Promise resolved! to show up.
function waiting () {
return new Promise(resolve => {
console.log('awaiting...');
setTimeout(function () {
resolve('Hello world!');
console.log('Promise resolved!');
}, 1400);
});
}
async function waitingAsync () {
console.log('start...');
const toBeReturned = await waiting();
console.log('stop...');
return toBeReturned;
}
(async () => {
console.log('Heads up! The next line makes an asynchronous call.');
console.log('Result: ' + await waitingAsync()); // 'Hello world!'
console.log('Done! This will be printed LAST! - Agreed?');
})();
console.log('done...?? This is LAST in the CODE. - I awaited \
"waitingAsync()" above. - So will this be printed at the very end??');
.as-console-wrapper { max-height: 100% !important; top: 0; }
The last asynchronous function is anonymous – without name – and gets
called immediately.
In fact, this is the only function that gets called directly in the snippet.
The function waitingAsync is only called indirectly (by the anonymous
function), and the function waiting is also called indirectly
(by waitingAsync).
A take away lesson
Don't ever put sequential/synchronous code after and outside a call to
an asynchronous function!
You will just confuse yourself if you do. – And even if you don't get
confused, other readers of your code almost certainly will be.

Understanding JavaScript promise object

I am trying to wrap my head around promise object in JavaScript. So here I have this little piece of code. I have a promise object and two console.log() on either side of the promise object. I thought it would print
hi
There!
zami
but it printed
hi
zami
There!
Why it is like that? I have zero understanding on how promise works, but I understand how asynchronous callback works in JavaScript. Can any one shed some light on this topic?
console.log('hi');
var myPromise = new Promise(function (resolve, reject) {
if (true) {
resolve('There!');
} else {
reject('Aww, didn\'t work.');
}
});
myPromise.then(function (result) {
// Resolve callback.
console.log(result);
}, function (result) {
// Reject callback.
console.error(result);
});
console.log('zami');
Summary:
A promise in Javascript is an object which represent the eventual completion or failure of an asynchronous operation. Promises represent a proxy for a value which are getting in some point in the future.
A promise can have 3 states which are the following:
Pending: This is the initial state of the promise, the promise is now waiting for either to be resolved or rejected. For example, when are reaching out to the web with an AJAX request and wrapping the request in a promise. Then the promise will be pending in the time window in which the request is not returned.
Fulfilled: When the operation is completed succesfully, the promise is fulfilled. For example, when we are reaching out to be web using AJAX for some JSON data and wrapping it in a promise. When we are succesfully getting data back the promise is said to be fulfilled.
Rejected: When the operation has failed, the promise is rejected. For example, when we are reaching out to be web using AJAX for some JSON data and wrapping it in a promise. When we are getting a 404 error the promise has been rejected.
Promise Constructor:
We can create a promise in the following manner:
let prom = new Promise((res, rej) => {
console.log('synchronously executed');
if (Math.random() > 0.5) {
res('Success');
} else {
rej('Error');
}
})
prom.then((val) => {
console.log('asynchronously executed: ' + val);
}).catch((err) => {
console.log('asynchronously executed: ' + err);
}).finally(() => {
console.log('promise done executing');
});
console.log('last log');
Points of interest:
The code inside the promise constructor is synchronously executed.
then method takes as a first argument a callback which is asynchronously executed on promise fulfillment.
then method takes as a second argument a callback which is asynchronously executed on promise rejection. However we are usually using the catch method for this (because this is more verbose), which also takes a callback which is asynchronously executed on promise rejection. catch is essentially the same as then(null, failCallback).
The then callback receives as a first argument the resolved value (the string 'success' in this case).
The catch callback receives as a first argument the rejected value (the string 'Error' in this case).
The finally method receives a callback which is executed on both promise fulfillment and rejection. Here we can write 'cleanup' code which need to be executed always regardless of promise outcome.
Your example:
In your code 'Zami' was printed before 'there' because the log which logged 'there' was in a then callback function. We earlier pointed out that these callbacks are executed asynchronously and thus will be executed last.
Promise execution is asynchronous, which means that it's executed, but the program won't wait until it's finished to continue with the rest of the code.
Basically, your code is doing the following:
Log 'Hi'
Create a promise
Execute the promise
Log 'zami'
Promise is resolved and logs 'There'.
If you want it to print 'Hi there, zami', you will have to
myPromise.then(function (result) {
// Resolve callback.
console.log(result);
console.log('zami');
}, function (result) {
// Reject callback.
console.error(result);
});
Even though you resolved the promised synchronously, the handlers you pass into then get called asynchronously. This is according to the defined specification:
onFulfilled and onRejected execute asynchronously, after the event loop turn in which then is called, and with a fresh stack
I would recommend you to understand how event loop works in JavaScript.
take time and watch this Video.
It will clear your doubts.
A Promise is an object representing the eventual completion or failure of an asynchronous operation.
Below is the example of promise:
const post = new Promise((resolve, reject) => {
resolve("Appended from getPostWithPromise()");
});
const getPostWithPromise = function () {
post
.then(function (fulfilled) {
$("body").append("<div>" + fulfilled + "</div>");
})
.catch(function (error) {
console.log(error);
});
}
function getPostWithoutPromise() {
$("body").append("<div>Appended from getPostWithoutPromise()</div>");
}
$(function () {
getPostWithPromise(); // this will print last
getPostWithoutPromise(); // this will print first
$("body").append("<div>Appended directly</div>"); // second
});
you can test it => JavaScript Promises example
for detail understanding you can read this post => https://scotch.io/tutorials/javascript-promises-for-dummies
Promise:
new Promise((resolve, reject) => {
resolve(whateverObject)
reject(whateverErrorObject)
})
It is just object that can be chained with then()
You also can make promise! you can return whatever object in that success parameter (resolve) and error parameter (reject)
so very simple concept bro!
Promises are objects.
Each promise object has a then method.
The then method of the promise object accepts a function as a first parameter.
If we call the then method of a promise, the callback function will be executed once the promise gets resolved.
Flow of execution
const promiseObj = new Promise((res, rej) => {
console.log("Promise constructor are synchronously executed");
res("Hii Developer");
})
const callbackFunction = (resolvedValue) => console.log("Resolved Value ", resolvedValue);
promiseObj.then(callbackFunction);
console.log("I am the executed after the constructor");
In the above example, we have created a promise object using the Promise constructor.
The constructor function is synchronously executed.
After creating the promise object, we are calling the then method of the promise object. We have passed a callback function in the first argument of the then method. This callback function will be executed once the promise gets resolved and the stack of the js engine gets empty.
Promise is a object that represents the completion or failure of a event . Promise is a asynchronous thing in JS which means that it's executed, but the program won't wait until it's finished to continue with the rest of the code. So it wont be executed simultaneously. It would take time to either complete or fail for a given task and then execution.
In your Case
log'Hi'.
First your mypromise variable will store a promise object i.e either rejected or resolved(for this, it would take time)
But JS engine will execute further code first then the asynchronous task. SO u will get 'zami'.
once the promise resolved or rejected. It will be called or used wherever it is used in the code. In this case ,it is resolved and log 'there!' in console.
let prom = new Promise((res, rej) => {
console.log('synchronously executed');
if (Math.random() > 0.5) {
res('Success');
} else {
rej('Error');
}
})
prom.then((val) => {
console.log('asynchronously executed: ' + val);
}).catch((err) => {
console.log('asynchronously executed: ' + err);
}).finally(() => {
console.log('promise done executing');
});
console.log('last log');

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