Develop Reference

Insanely slow Mongodb group query

I'm trying to aggregate $sum between 2 dates stored as UTC strings (yyyy-mm-dd-hh). It takes 5+ seconds to get the results. My collection has 5 million+ docs.
{
$match: {
start: {
$gte: '2020-08-01-00',
$lte: '2021-08-01-00'
}
}
},
{
$group: {
_id: {
symbol: '$symbol'
},
unverifiedCount: {
$sum: {
$cond: {
if: { $eq: ['$isVerified', false] }, then: '$count', else: 0
}
}
},
verifiedCount: {
$sum: {
$cond: {
if: { $eq: ['$isVerified', true]}, then: '$count', else: 0
}
}
}
}
}, {
$sort: {
unverifiedCount: -1
}
}
Tried using $toDateString but performance remained the same

How to get grouped data as well as all data using mongodb?

Using the following code, I do get totalAccount and totalBalance. But, no other field/data is showing up. How can I also get all data from my collection that matches my query (brcode)?
const test = await db.collection('alldeposit').aggregate([
{
$match: {
brcode: brcode
}
},
{
$group: {
_id: null,
totalAccount: {
$sum: 1
},
totalBalance: {
$sum: "$acbal"
}
}
}
]).toArray()

You have to specify which fields you want to see in the $group stage
For example:
await db.collection('alldeposit').aggregate([
{
$match: {
brcode: brcode
}
},
{
$group: {
_id : null,
name : { $first: '$name' },
age : { $first: '$age' },
sex : { $first: '$sex' },
province : { $first: '$province' },
city : { $first: '$city' },
area : { $first: '$area' },
address : { $first: '$address' },
totalAccount: {
$sum: 1
},
totalBalance: {
$sum: "$acbal"
}
}
}]);
Edit:
Regarding our chat in the comments, unfortunately I don't know a way to do the operation you asked in a single aggregation.
But with two steps, you can do it:
First step:
db.collection.aggregate([
{
$match: {
brcode: brcode
}
},
{
"$group": {
"_id": null,
totalAccount: {
$sum: 1
},
totalBalance: {
$sum: "$acbal"
}
}
}
])
And second step:
db.collection.update(
{ brcode: brcode }
,{$set : {
"totalAccount": totalAccount,
"totalBalance": totalBalance
}}
)

How to retrieve data from a complex data structure in MongoDB?

Data:
Is there any way to access all of these "lineText" fields from the collection in MongoDB through a single query?

Try this
db.collectionName.aggregate([
{ $unwind: "$text" },
{ $unwind: "$text.paragraphs" },
{
$group: {
_id: null,
result: {
$push: {
$arrayElemAt: ["$text.paragraphs.lineText", 0]
}
}
}
},
{
$project: {
result: {
$reduce: {
input: "$result",
initialValue: "",
in: { "$concat": ["$$value", "$$this"] }
}
}
}
}
]);

How to delete an element in a sub sub document mongoosejs

how to delete the "extras" with "id_extra = 8523" of the "book" "id_book = 8522" of that particular user?, I currently use mongoosejs but I didn't succeed, I tried many stuffs, but whatever I tried was working just till the first level of nested doc.
{
"_id":{
"$oid":"5e32fce08919b53ad66cf694"
},
"user_id":{
"$numberInt":"258787"
},
"username":"daaaa",
"firstname":"davide",
"api_key":"7b031c21edf1237c554867622ad1154f",
"books":[
{
"_id":{
"$oid":"5e356323a0ef6319ebb60162"
},
"id_book":{
"$numberInt":"8522"
},
"blob_annotation":null,
"extra_id":{
"$numberInt":"995176"
},
"extras":[
{
"_id":{
"$oid":"5e356324a0ef6319ebb60163"
},
"id_extra":{
"$numberInt":"8523"
},
"type":"gallery_audio",
"label":"Inverno a Boscodirovo"
},
{
"_id":{
"$oid":"5e356324a0ef6319ebb60164"
},
"id_extra":{
"$numberInt":"8524"
},
"type":"gallery_audio",
"label":"Storia di Primavera"
}
],
"raccolte":[
]
}
],
}

Try using elemMatch in conjunction with $:
db.books.update(
{
books: {
$elemMatch: {
"id_book": 8522,
"extras.id_extra": 8523
}
},
user_id: 258787
},
{
$pull: {
"books.$.extras": {
"id_extra": 8523
}
}
}
)

You may do this trick: Filter "extras" with "id_extra = 8523" of the "book" "id_book = 8522" and save documents again in MongoDB
db.collection.aggregate([
{
$match: {
"books.id_book": 8522
}
},
{
$addFields: {
"books": {
$reduce: {
input: "$books",
initialValue: [],
in: {
$concatArrays: [
"$$value",
[
{
_id: "$$this._id",
id_book: "$$this.id_book",
blob_annotation: "$$this.blob_annotation",
extra_id: "$$this.extra_id",
raccolte: "$$this.raccolte",
extras: {
$filter: {
input: "$$this.extras",
cond: {
$ne: [
"$$this.id_extra",
8523
]
}
}
}
}
]
]
}
}
}
}
}
])
MongoPlayground

MongoDB Aggregation: calculation for every unique/distinct value

I got this data set from collection
{
item: 124001
price: 6
},
{
item: 124001
price: 6
},
{
item: 124121
price: 16
},
{
item: 124121
price: 13
},
{
item:n
price: x
}
from code:
let INDX = [xxx,xxx,xxx,xxx, ..n]
auctions.aggregate([
{
$match: { item: { $in: INDX }}
}
The problem is right after it, in the $group stage. For example I'd like to receive $min, $max or $avg 'price' for every unique/distinct item.
When I'm trying to use:
{
$group: {
min_1: { $min: "$price",}
}
}
I receive just $min from all data,
[ { _id: 0, min_1: 0 } ]
but I need something like:
{ _id: 124119, min_1: 66500 },
{ _id: 124437, min_1: 26398 }

Ok, here is a simple answer:
Just don't forget about _id field and use it, at $group stage, just like:
{
$group: {
_id: "$item",
min_1: {
$min: '$price',
}
}
}