Using regex to validate given password has alphabetic, numeric, and special characters not - javascript

I am trying to use regex in JavaScript to verify if a given password has alphabetic, numeric, and a special character. However, everything I have tried doesn't work
I have tried using
/^(?=.*?[A-Z])(?=.*?[a-z])(?=.*?[0-9])(?=.*?[!#"#%$&])[A-Za-z0-9!#"#%$&]{8,30}$/gm
and creating separate regex variables for alphabetic, numeric, and special characters:
let alpha = /^[A-Za-z]+$/i
let numer = /^[0-9]+$/i
let special = /^[!##$%^&*(),.?;":{}|<>']/i
Picture of My Code
When I log the password.match(regex) to the console I always see null


Try this:
^(?=.*[a-z])(?=.*[A-Z])(?=.*\d)(?=.*[^\da-zA-Z]).{8,15}$
This is from a post a long time ago. There are probably others as well. A simple search of SO will find more examples.1
Here is a visualisation of the regular expression:
Debuggex Demo


I would personally go for separate regexes, the issue with your current regexes is that you have ^ at the start and $ at the end. Which means that the password must only contain [A-Za-z] from start to finish. Then you check if the password only contains [0-9] from start to finish.
const regexes = {
alpha: /[A-Za-z]/,
number: /[0-9]/,
special: /[!##$%^&*(),.?;":{}|<>']/,
length: /^.{8,30}$/
};
["dgXHUYuDdp", "zMv4qQfZj3", "4JXyrsq!J0", "a5Z!"].forEach(password => {
let valid = Object.values(regexes).every(regex => password.match(regex));
console.log(
"password: " + JSON.stringify(password) + "\n" +
"valid: " + valid
);
});


While I suspect it may be possible to write a regex which will do position/seuqnce independent matching, my head hurts just thinking about. So even if I could work out a way of doing it, I would not implement it - code needs to be readable and parseable by human beings. Looking at what you have presented here, I think I'm a lot more familiar with regexes than you are - so even more reason not to do this.
Your alpha / numer / special regexes will only match a string containing letters, numbers or special characters, not a mixture. If you change them thus, then you can check for a match of all three (and escape the meta characters in the special regex):
let alpha = /[A-Za-z]/i;
let numer = /[0-9]/;
let special = /[!##$%\^&*(),\.?;":{}|<>\']/;
if (password.match(alpha) && password.match(numer) && password.match(speicial)) {

Related

Check strings equality without direction? [duplicate]

How can I remove non-printable unicode characters in a multi-language input?
When users with different localizations paste strings they will sometimes unintentionally embed non-printing characters. For example:
var weird = "%E2%80%AA%E2%80%8ETest%E2%80%AC"
var displaysAs = decodeURI(weird); // Users see only "Test"
But I can't figure out how to strip the non-printing characters in a way that doesn't impact other languages like these:
encodeURI("شنط") = "%D8%B4%D9%86%D8%B7"
encodeURI("戦艦帝国") = "%E6%88%A6%E8%89%A6%E5%B8%9D%E5%9B%BD"
For example, the following attempt to repair the weird example above doesn't work:
var weird = "%E2%80%AA%E2%80%8ETest%E2%80%AC";
var displaysAs = decodeURI(weird);
var stillWeird = encodeURI(displaysAs.replace(/\s/g, ""));
// value is again "%E2%80%AA%E2%80%8ETest%E2%80%AC"
console.log('before:', weird);
console.log('after:', displaysAs);
console.log('again:', stillWeird);
.as-console-wrapper{min-height:100%}
As noted in the comments, this is largely a specification problem. I don't have an enumeration of non-printing unicode expressions. I can only observe that one can paste a unicode string into a browser Input and not be aware that it has undisplayed characters in it. I assume that some logic in the browser determines whether each unicode character will display something. This problem would be solved if I can apply that same logic to the underlying string in order to get the "display string."
Put another way: For any two unicode strings that look identical on the browser, I need a transformation that guarantees that their values are identical.

You can use the regular expression found in this other answer.
Example with array of the three strings provided in the question:
let weird = [
"%E2%80%AA%E2%80%8ETest%E2%80%AC",
"%D8%B4%D9%86%D8%B7",
"%E6%88%A6%E8%89%A6%E5%B8%9D%E5%9B%BD"
];
const expr = /[\0-\x1F\x7F-\x9F\xAD\u0378\u0379\u037F-\u0383\u038B\u038D\u03A2\u0528-\u0530\u0557\u0558\u0560\u0588\u058B-\u058E\u0590\u05C8-\u05CF\u05EB-\u05EF\u05F5-\u0605\u061C\u061D\u06DD\u070E\u070F\u074B\u074C\u07B2-\u07BF\u07FB-\u07FF\u082E\u082F\u083F\u085C\u085D\u085F-\u089F\u08A1\u08AD-\u08E3\u08FF\u0978\u0980\u0984\u098D\u098E\u0991\u0992\u09A9\u09B1\u09B3-\u09B5\u09BA\u09BB\u09C5\u09C6\u09C9\u09CA\u09CF-\u09D6\u09D8-\u09DB\u09DE\u09E4\u09E5\u09FC-\u0A00\u0A04\u0A0B-\u0A0E\u0A11\u0A12\u0A29\u0A31\u0A34\u0A37\u0A3A\u0A3B\u0A3D\u0A43-\u0A46\u0A49\u0A4A\u0A4E-\u0A50\u0A52-\u0A58\u0A5D\u0A5F-\u0A65\u0A76-\u0A80\u0A84\u0A8E\u0A92\u0AA9\u0AB1\u0AB4\u0ABA\u0ABB\u0AC6\u0ACA\u0ACE\u0ACF\u0AD1-\u0ADF\u0AE4\u0AE5\u0AF2-\u0B00\u0B04\u0B0D\u0B0E\u0B11\u0B12\u0B29\u0B31\u0B34\u0B3A\u0B3B\u0B45\u0B46\u0B49\u0B4A\u0B4E-\u0B55\u0B58-\u0B5B\u0B5E\u0B64\u0B65\u0B78-\u0B81\u0B84\u0B8B-\u0B8D\u0B91\u0B96-\u0B98\u0B9B\u0B9D\u0BA0-\u0BA2\u0BA5-\u0BA7\u0BAB-\u0BAD\u0BBA-\u0BBD\u0BC3-\u0BC5\u0BC9\u0BCE\u0BCF\u0BD1-\u0BD6\u0BD8-\u0BE5\u0BFB-\u0C00\u0C04\u0C0D\u0C11\u0C29\u0C34\u0C3A-\u0C3C\u0C45\u0C49\u0C4E-\u0C54\u0C57\u0C5A-\u0C5F\u0C64\u0C65\u0C70-\u0C77\u0C80\u0C81\u0C84\u0C8D\u0C91\u0CA9\u0CB4\u0CBA\u0CBB\u0CC5\u0CC9\u0CCE-\u0CD4\u0CD7-\u0CDD\u0CDF\u0CE4\u0CE5\u0CF0\u0CF3-\u0D01\u0D04\u0D0D\u0D11\u0D3B\u0D3C\u0D45\u0D49\u0D4F-\u0D56\u0D58-\u0D5F\u0D64\u0D65\u0D76-\u0D78\u0D80\u0D81\u0D84\u0D97-\u0D99\u0DB2\u0DBC\u0DBE\u0DBF\u0DC7-\u0DC9\u0DCB-\u0DCE\u0DD5\u0DD7\u0DE0-\u0DF1\u0DF5-\u0E00\u0E3B-\u0E3E\u0E5C-\u0E80\u0E83\u0E85\u0E86\u0E89\u0E8B\u0E8C\u0E8E-\u0E93\u0E98\u0EA0\u0EA4\u0EA6\u0EA8\u0EA9\u0EAC\u0EBA\u0EBE\u0EBF\u0EC5\u0EC7\u0ECE\u0ECF\u0EDA\u0EDB\u0EE0-\u0EFF\u0F48\u0F6D-\u0F70\u0F98\u0FBD\u0FCD\u0FDB-\u0FFF\u10C6\u10C8-\u10CC\u10CE\u10CF\u1249\u124E\u124F\u1257\u1259\u125E\u125F\u1289\u128E\u128F\u12B1\u12B6\u12B7\u12BF\u12C1\u12C6\u12C7\u12D7\u1311\u1316\u1317\u135B\u135C\u137D-\u137F\u139A-\u139F\u13F5-\u13FF\u169D-\u169F\u16F1-\u16FF\u170D\u1715-\u171F\u1737-\u173F\u1754-\u175F\u176D\u1771\u1774-\u177F\u17DE\u17DF\u17EA-\u17EF\u17FA-\u17FF\u180F\u181A-\u181F\u1878-\u187F\u18AB-\u18AF\u18F6-\u18FF\u191D-\u191F\u192C-\u192F\u193C-\u193F\u1941-\u1943\u196E\u196F\u1975-\u197F\u19AC-\u19AF\u19CA-\u19CF\u19DB-\u19DD\u1A1C\u1A1D\u1A5F\u1A7D\u1A7E\u1A8A-\u1A8F\u1A9A-\u1A9F\u1AAE-\u1AFF\u1B4C-\u1B4F\u1B7D-\u1B7F\u1BF4-\u1BFB\u1C38-\u1C3A\u1C4A-\u1C4C\u1C80-\u1CBF\u1CC8-\u1CCF\u1CF7-\u1CFF\u1DE7-\u1DFB\u1F16\u1F17\u1F1E\u1F1F\u1F46\u1F47\u1F4E\u1F4F\u1F58\u1F5A\u1F5C\u1F5E\u1F7E\u1F7F\u1FB5\u1FC5\u1FD4\u1FD5\u1FDC\u1FF0\u1FF1\u1FF5\u1FFF\u200B-\u200F\u202A-\u202E\u2060-\u206F\u2072\u2073\u208F\u209D-\u209F\u20BB-\u20CF\u20F1-\u20FF\u218A-\u218F\u23F4-\u23FF\u2427-\u243F\u244B-\u245F\u2700\u2B4D-\u2B4F\u2B5A-\u2BFF\u2C2F\u2C5F\u2CF4-\u2CF8\u2D26\u2D28-\u2D2C\u2D2E\u2D2F\u2D68-\u2D6E\u2D71-\u2D7E\u2D97-\u2D9F\u2DA7\u2DAF\u2DB7\u2DBF\u2DC7\u2DCF\u2DD7\u2DDF\u2E3C-\u2E7F\u2E9A\u2EF4-\u2EFF\u2FD6-\u2FEF\u2FFC-\u2FFF\u3040\u3097\u3098\u3100-\u3104\u312E-\u3130\u318F\u31BB-\u31BF\u31E4-\u31EF\u321F\u32FF\u4DB6-\u4DBF\u9FCD-\u9FFF\uA48D-\uA48F\uA4C7-\uA4CF\uA62C-\uA63F\uA698-\uA69E\uA6F8-\uA6FF\uA78F\uA794-\uA79F\uA7AB-\uA7F7\uA82C-\uA82F\uA83A-\uA83F\uA878-\uA87F\uA8C5-\uA8CD\uA8DA-\uA8DF\uA8FC-\uA8FF\uA954-\uA95E\uA97D-\uA97F\uA9CE\uA9DA-\uA9DD\uA9E0-\uA9FF\uAA37-\uAA3F\uAA4E\uAA4F\uAA5A\uAA5B\uAA7C-\uAA7F\uAAC3-\uAADA\uAAF7-\uAB00\uAB07\uAB08\uAB0F\uAB10\uAB17-\uAB1F\uAB27\uAB2F-\uABBF\uABEE\uABEF\uABFA-\uABFF\uD7A4-\uD7AF\uD7C7-\uD7CA\uD7FC-\uF8FF\uFA6E\uFA6F\uFADA-\uFAFF\uFB07-\uFB12\uFB18-\uFB1C\uFB37\uFB3D\uFB3F\uFB42\uFB45\uFBC2-\uFBD2\uFD40-\uFD4F\uFD90\uFD91\uFDC8-\uFDEF\uFDFE\uFDFF\uFE1A-\uFE1F\uFE27-\uFE2F\uFE53\uFE67\uFE6C-\uFE6F\uFE75\uFEFD-\uFF00\uFFBF-\uFFC1\uFFC8\uFFC9\uFFD0\uFFD1\uFFD8\uFFD9\uFFDD-\uFFDF\uFFE7\uFFEF-\uFFFB\uFFFE\uFFFF]/g;
weird.map(decodeURI).forEach(el => {
let trimmed = el.replace(expr, '')
console.log(trimmed, trimmed.length);
});
If you only want to trim these non-printable characters from the beginning and/or end of the string, you'll need to assert start (^) and end ($) in the regular expression.

Is there any way to validate emojis without using regex with an unicode flag? [duplicate]

I need help for how to detect if an input contains a Japanese emoji/emoticon.
Currently my character set is charset=utf-8. On inputting text, the user can enter Japanese characters/alpanumerics/symbols but if they insert an emoji, onsubmit JavaScript will check if there is an emoji, error message will display.
I can't get this to work because I have no idea on how to detect an emoji in JavaScript?

The answers might work but are terrible because they rely on unicode ranges that are unreadable and somewhat "magic" because it's not always clear where do they come from and why they work, not to mention they're not resilient to new emojis being added to the spec.
Major browsers now support unicode property escape which allows for matching emojis based on their belonging in the Emoji unicode category: \p{Emoji} matches an emoji, \P{Emoji} matches a non-emoji.
Note that officially, 0123456789#* and other characters are emojis too, so the property escape you might want to use is not Emoji but rather Extended_Pictographic which denotes all the characters typically understood as emojis!
Make sure to include the u flag at the end.
console.log(
/\p{Emoji}/u.test('flowers'), // false :)
/\p{Emoji}/u.test('flowers 🌼🌺🌸'), // true :)
/\p{Emoji}/u.test('flowers 123'), // true :(
)
console.log(
/\p{Extended_Pictographic}/u.test('flowers'), // false :)
/\p{Extended_Pictographic}/u.test('flowers 🌼🌺🌸'), // true :)
/\p{Extended_Pictographic}/u.test('flowers 123'), // false :)
)
This works fine for detecting emojis, but if you want to use the same regex to extract them, you might be surprised with its behavior, since some emojis that appear as one character are actually several characters. They're what we call emoji sequences, more about them in this question
const regex = /\p{Extended_Pictographic}/ug
const family = '👨‍👩‍👧' // "family
console.log(family.length) // not 1, but 8!
console.log(regex.test(family)) // true, as expected
console.log(family.match(regex)) // not [family], but [man, woman, girl]

You can use the following regex:
/(?:[\u2700-\u27bf]|(?:\ud83c[\udde6-\uddff]){2}|[\ud800-\udbff][\udc00-\udfff]|[\u0023-\u0039]\ufe0f?\u20e3|\u3299|\u3297|\u303d|\u3030|\u24c2|\ud83c[\udd70-\udd71]|\ud83c[\udd7e-\udd7f]|\ud83c\udd8e|\ud83c[\udd91-\udd9a]|\ud83c[\udde6-\uddff]|\ud83c[\ude01-\ude02]|\ud83c\ude1a|\ud83c\ude2f|\ud83c[\ude32-\ude3a]|\ud83c[\ude50-\ude51]|\u203c|\u2049|[\u25aa-\u25ab]|\u25b6|\u25c0|[\u25fb-\u25fe]|\u00a9|\u00ae|\u2122|\u2139|\ud83c\udc04|[\u2600-\u26FF]|\u2b05|\u2b06|\u2b07|\u2b1b|\u2b1c|\u2b50|\u2b55|\u231a|\u231b|\u2328|\u23cf|[\u23e9-\u23f3]|[\u23f8-\u23fa]|\ud83c\udccf|\u2934|\u2935|[\u2190-\u21ff])/g
If you just want to remove it from the string, you can do something like this.
function removeEmojis (string) {
var regex = /(?:[\u2700-\u27bf]|(?:\ud83c[\udde6-\uddff]){2}|[\ud800-\udbff][\udc00-\udfff]|[\u0023-\u0039]\ufe0f?\u20e3|\u3299|\u3297|\u303d|\u3030|\u24c2|\ud83c[\udd70-\udd71]|\ud83c[\udd7e-\udd7f]|\ud83c\udd8e|\ud83c[\udd91-\udd9a]|\ud83c[\udde6-\uddff]|\ud83c[\ude01-\ude02]|\ud83c\ude1a|\ud83c\ude2f|\ud83c[\ude32-\ude3a]|\ud83c[\ude50-\ude51]|\u203c|\u2049|[\u25aa-\u25ab]|\u25b6|\u25c0|[\u25fb-\u25fe]|\u00a9|\u00ae|\u2122|\u2139|\ud83c\udc04|[\u2600-\u26FF]|\u2b05|\u2b06|\u2b07|\u2b1b|\u2b1c|\u2b50|\u2b55|\u231a|\u231b|\u2328|\u23cf|[\u23e9-\u23f3]|[\u23f8-\u23fa]|\ud83c\udccf|\u2934|\u2935|[\u2190-\u21ff])/g;
return string.replace(regex, '');
}

A simple function that returns true if your string contains one or more emojis.
function isEmoji(str) {
var ranges = [
'(?:[\u2700-\u27bf]|(?:\ud83c[\udde6-\uddff]){2}|[\ud800-\udbff][\udc00-\udfff]|[\u0023-\u0039]\ufe0f?\u20e3|\u3299|\u3297|\u303d|\u3030|\u24c2|\ud83c[\udd70-\udd71]|\ud83c[\udd7e-\udd7f]|\ud83c\udd8e|\ud83c[\udd91-\udd9a]|\ud83c[\udde6-\uddff]|[\ud83c[\ude01-\ude02]|\ud83c\ude1a|\ud83c\ude2f|[\ud83c[\ude32-\ude3a]|[\ud83c[\ude50-\ude51]|\u203c|\u2049|[\u25aa-\u25ab]|\u25b6|\u25c0|[\u25fb-\u25fe]|\u00a9|\u00ae|\u2122|\u2139|\ud83c\udc04|[\u2600-\u26FF]|\u2b05|\u2b06|\u2b07|\u2b1b|\u2b1c|\u2b50|\u2b55|\u231a|\u231b|\u2328|\u23cf|[\u23e9-\u23f3]|[\u23f8-\u23fa]|\ud83c\udccf|\u2934|\u2935|[\u2190-\u21ff])' // U+1F680 to U+1F6FF
];
if (str.match(ranges.join('|'))) {
return true;
} else {
return false;
}
}

First of all, you cannot rely on ECMAScript 2018+ compliant \p{Emoji} (at least at the time of writing). It really matches some 0123456789#* non-emoji chars (see Nino Filiu's answer). See Why do Unicode emoji property escapes match numbers? for more details.
To test if there are any emoji chars in a string in JavaScript, you can use the following ECMAScript 2018+ compliant solution (mind the u flag):
const regex_emoji = /[\p{Extended_Pictographic}\u{1F3FB}-\u{1F3FF}\u{1F9B0}-\u{1F9B3}]/u;
console.log( regex_emoji.test('flowers 123') ); // => false
console.log( regex_emoji.test('flowers 🌼🌺🌸') ); // => true
You can even extract one or more emoji char sequences using this pattern (note the added g flag to find all occurrences and + to match one or more consecutive occurrences of the character class pattern):
const regex_emoji = /[\p{Extended_Pictographic}\u{1F3FB}-\u{1F3FF}\u{1F9B0}-\u{1F9B3}]+/gu;
console.log( 'flowers 123'.match(regex_emoji) ); // => null
console.log( 'flowers 🌼🌺🌸'.match(regex_emoji) ); // => [ "🌼🌺🌸" ]
In a nutshell, the Extended_Pictographic Unicode category class matches most emoji chars except for some Emoji_Components, that is, light skin to dark skin mode chars (\u{1F3FB}-\u{1F3FF}) and red-haired to white-haired chars (\u{1F9B0}-\u{1F9B3}).
To count, or extract emojis as an array of single chars or consecutive sequences (like in the second code snippet from above) from longer texts and perform other actions on emojis, you can use a custom regex (like in Scott Weaver's answer). It is safer to use the longer, escaped version. However, there are 4702 emoji characters defined in the Emoji Keyboard/Display Test Data for UTR #51 (Version: 14.0) file. Thus, the (ES5 compliant, works even in IE) regex to match a single emoji char is
var EmojiPattern = /[#*0-9]\uFE0F?\u20E3|\u00A9\uFE0F?|[\u00AE\u203C\u2049\u2122\u2139\u2194-\u2199\u21A9\u21AA]\uFE0F?|[\u231A\u231B]|[\u2328\u23CF]\uFE0F?|[\u23E9-\u23EC]|[\u23ED-\u23EF]\uFE0F?|\u23F0|[\u23F1\u23F2]\uFE0F?|\u23F3|[\u23F8-\u23FA\u24C2\u25AA\u25AB\u25B6\u25C0\u25FB\u25FC]\uFE0F?|[\u25FD\u25FE]|[\u2600-\u2604\u260E\u2611]\uFE0F?|[\u2614\u2615]|\u2618\uFE0F?|\u261D(?:\uD83C[\uDFFB-\uDFFF]|\uFE0F)?|[\u2620\u2622\u2623\u2626\u262A\u262E\u262F\u2638-\u263A\u2640\u2642]\uFE0F?|[\u2648-\u2653]|[\u265F\u2660\u2663\u2665\u2666\u2668\u267B\u267E]\uFE0F?|\u267F|\u2692\uFE0F?|\u2693|[\u2694-\u2697\u2699\u269B\u269C\u26A0]\uFE0F?|\u26A1|\u26A7\uFE0F?|[\u26AA\u26AB]|[\u26B0\u26B1]\uFE0F?|[\u26BD\u26BE\u26C4\u26C5]|\u26C8\uFE0F?|\u26CE|[\u26CF\u26D1\u26D3]\uFE0F?|\u26D4|\u26E9\uFE0F?|\u26EA|[\u26F0\u26F1]\uFE0F?|[\u26F2\u26F3]|\u26F4\uFE0F?|\u26F5|[\u26F7\u26F8]\uFE0F?|\u26F9(?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?|\uFE0F(?:\u200D[\u2640\u2642]\uFE0F?)?)?|[\u26FA\u26FD]|\u2702\uFE0F?|\u2705|[\u2708\u2709]\uFE0F?|[\u270A\u270B](?:\uD83C[\uDFFB-\uDFFF])?|[\u270C\u270D](?:\uD83C[\uDFFB-\uDFFF]|\uFE0F)?|\u270F\uFE0F?|[\u2712\u2714\u2716\u271D\u2721]\uFE0F?|\u2728|[\u2733\u2734\u2744\u2747]\uFE0F?|[\u274C\u274E\u2753-\u2755\u2757]|\u2763\uFE0F?|\u2764(?:\u200D(?:\uD83D\uDD25|\uD83E\uDE79)|\uFE0F(?:\u200D(?:\uD83D\uDD25|\uD83E\uDE79))?)?|[\u2795-\u2797]|\u27A1\uFE0F?|[\u27B0\u27BF]|[\u2934\u2935\u2B05-\u2B07]\uFE0F?|[\u2B1B\u2B1C\u2B50\u2B55]|[\u3030\u303D\u3297\u3299]\uFE0F?|\uD83C(?:[\uDC04\uDCCF]|[\uDD70\uDD71\uDD7E\uDD7F]\uFE0F?|[\uDD8E\uDD91-\uDD9A]|\uDDE6\uD83C[\uDDE8-\uDDEC\uDDEE\uDDF1\uDDF2\uDDF4\uDDF6-\uDDFA\uDDFC\uDDFD\uDDFF]|\uDDE7\uD83C[\uDDE6\uDDE7\uDDE9-\uDDEF\uDDF1-\uDDF4\uDDF6-\uDDF9\uDDFB\uDDFC\uDDFE\uDDFF]|\uDDE8\uD83C[\uDDE6\uDDE8\uDDE9\uDDEB-\uDDEE\uDDF0-\uDDF5\uDDF7\uDDFA-\uDDFF]|\uDDE9\uD83C[\uDDEA\uDDEC\uDDEF\uDDF0\uDDF2\uDDF4\uDDFF]|\uDDEA\uD83C[\uDDE6\uDDE8\uDDEA\uDDEC\uDDED\uDDF7-\uDDFA]|\uDDEB\uD83C[\uDDEE-\uDDF0\uDDF2\uDDF4\uDDF7]|\uDDEC\uD83C[\uDDE6\uDDE7\uDDE9-\uDDEE\uDDF1-\uDDF3\uDDF5-\uDDFA\uDDFC\uDDFE]|\uDDED\uD83C[\uDDF0\uDDF2\uDDF3\uDDF7\uDDF9\uDDFA]|\uDDEE\uD83C[\uDDE8-\uDDEA\uDDF1-\uDDF4\uDDF6-\uDDF9]|\uDDEF\uD83C[\uDDEA\uDDF2\uDDF4\uDDF5]|\uDDF0\uD83C[\uDDEA\uDDEC-\uDDEE\uDDF2\uDDF3\uDDF5\uDDF7\uDDFC\uDDFE\uDDFF]|\uDDF1\uD83C[\uDDE6-\uDDE8\uDDEE\uDDF0\uDDF7-\uDDFB\uDDFE]|\uDDF2\uD83C[\uDDE6\uDDE8-\uDDED\uDDF0-\uDDFF]|\uDDF3\uD83C[\uDDE6\uDDE8\uDDEA-\uDDEC\uDDEE\uDDF1\uDDF4\uDDF5\uDDF7\uDDFA\uDDFF]|\uDDF4\uD83C\uDDF2|\uDDF5\uD83C[\uDDE6\uDDEA-\uDDED\uDDF0-\uDDF3\uDDF7-\uDDF9\uDDFC\uDDFE]|\uDDF6\uD83C\uDDE6|\uDDF7\uD83C[\uDDEA\uDDF4\uDDF8\uDDFA\uDDFC]|\uDDF8\uD83C[\uDDE6-\uDDEA\uDDEC-\uDDF4\uDDF7-\uDDF9\uDDFB\uDDFD-\uDDFF]|\uDDF9\uD83C[\uDDE6\uDDE8\uDDE9\uDDEB-\uDDED\uDDEF-\uDDF4\uDDF7\uDDF9\uDDFB\uDDFC\uDDFF]|\uDDFA\uD83C[\uDDE6\uDDEC\uDDF2\uDDF3\uDDF8\uDDFE\uDDFF]|\uDDFB\uD83C[\uDDE6\uDDE8\uDDEA\uDDEC\uDDEE\uDDF3\uDDFA]|\uDDFC\uD83C[\uDDEB\uDDF8]|\uDDFD\uD83C\uDDF0|\uDDFE\uD83C[\uDDEA\uDDF9]|\uDDFF\uD83C[\uDDE6\uDDF2\uDDFC]|\uDE01|\uDE02\uFE0F?|[\uDE1A\uDE2F\uDE32-\uDE36]|\uDE37\uFE0F?|[\uDE38-\uDE3A\uDE50\uDE51\uDF00-\uDF20]|[\uDF21\uDF24-\uDF2C]\uFE0F?|[\uDF2D-\uDF35]|\uDF36\uFE0F?|[\uDF37-\uDF7C]|\uDF7D\uFE0F?|[\uDF7E-\uDF84]|\uDF85(?:\uD83C[\uDFFB-\uDFFF])?|[\uDF86-\uDF93]|[\uDF96\uDF97\uDF99-\uDF9B\uDF9E\uDF9F]\uFE0F?|[\uDFA0-\uDFC1]|\uDFC2(?:\uD83C[\uDFFB-\uDFFF])?|[\uDFC3\uDFC4](?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|[\uDFC5\uDFC6]|\uDFC7(?:\uD83C[\uDFFB-\uDFFF])?|[\uDFC8\uDFC9]|\uDFCA(?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|[\uDFCB\uDFCC](?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?|\uFE0F(?:\u200D[\u2640\u2642]\uFE0F?)?)?|[\uDFCD\uDFCE]\uFE0F?|[\uDFCF-\uDFD3]|[\uDFD4-\uDFDF]\uFE0F?|[\uDFE0-\uDFF0]|\uDFF3(?:\u200D(?:\u26A7\uFE0F?|\uD83C\uDF08)|\uFE0F(?:\u200D(?:\u26A7\uFE0F?|\uD83C\uDF08))?)?|\uDFF4(?:\u200D\u2620\uFE0F?|\uDB40\uDC67\uDB40\uDC62\uDB40(?:\uDC65\uDB40\uDC6E\uDB40\uDC67|\uDC73\uDB40\uDC63\uDB40\uDC74|\uDC77\uDB40\uDC6C\uDB40\uDC73)\uDB40\uDC7F)?|[\uDFF5\uDFF7]\uFE0F?|[\uDFF8-\uDFFF])|\uD83D(?:[\uDC00-\uDC07]|\uDC08(?:\u200D\u2B1B)?|[\uDC09-\uDC14]|\uDC15(?:\u200D\uD83E\uDDBA)?|[\uDC16-\uDC3A]|\uDC3B(?:\u200D\u2744\uFE0F?)?|[\uDC3C-\uDC3E]|\uDC3F\uFE0F?|\uDC40|\uDC41(?:\u200D\uD83D\uDDE8\uFE0F?|\uFE0F(?:\u200D\uD83D\uDDE8\uFE0F?)?)?|[\uDC42\uDC43](?:\uD83C[\uDFFB-\uDFFF])?|[\uDC44\uDC45]|[\uDC46-\uDC50](?:\uD83C[\uDFFB-\uDFFF])?|[\uDC51-\uDC65]|[\uDC66\uDC67](?:\uD83C[\uDFFB-\uDFFF])?|\uDC68(?:\u200D(?:[\u2695\u2696\u2708]\uFE0F?|\u2764\uFE0F?\u200D\uD83D(?:\uDC8B\u200D\uD83D)?\uDC68|\uD83C[\uDF3E\uDF73\uDF7C\uDF93\uDFA4\uDFA8\uDFEB\uDFED]|\uD83D(?:\uDC66(?:\u200D\uD83D\uDC66)?|\uDC67(?:\u200D\uD83D[\uDC66\uDC67])?|[\uDC68\uDC69]\u200D\uD83D(?:\uDC66(?:\u200D\uD83D\uDC66)?|\uDC67(?:\u200D\uD83D[\uDC66\uDC67])?)|[\uDCBB\uDCBC\uDD27\uDD2C\uDE80\uDE92])|\uD83E[\uDDAF-\uDDB3\uDDBC\uDDBD])|\uD83C(?:\uDFFB(?:\u200D(?:[\u2695\u2696\u2708]\uFE0F?|\u2764\uFE0F?\u200D\uD83D(?:\uDC8B\u200D\uD83D)?\uDC68\uD83C[\uDFFB-\uDFFF]|\uD83C[\uDF3E\uDF73\uDF7C\uDF93\uDFA4\uDFA8\uDFEB\uDFED]|\uD83D[\uDCBB\uDCBC\uDD27\uDD2C\uDE80\uDE92]|\uD83E(?:\uDD1D\u200D\uD83D\uDC68\uD83C[\uDFFC-\uDFFF]|[\uDDAF-\uDDB3\uDDBC\uDDBD])))?|\uDFFC(?:\u200D(?:[\u2695\u2696\u2708]\uFE0F?|\u2764\uFE0F?\u200D\uD83D(?:\uDC8B\u200D\uD83D)?\uDC68\uD83C[\uDFFB-\uDFFF]|\uD83C[\uDF3E\uDF73\uDF7C\uDF93\uDFA4\uDFA8\uDFEB\uDFED]|\uD83D[\uDCBB\uDCBC\uDD27\uDD2C\uDE80\uDE92]|\uD83E(?:\uDD1D\u200D\uD83D\uDC68\uD83C[\uDFFB\uDFFD-\uDFFF]|[\uDDAF-\uDDB3\uDDBC\uDDBD])))?|\uDFFD(?:\u200D(?:[\u2695\u2696\u2708]\uFE0F?|\u2764\uFE0F?\u200D\uD83D(?:\uDC8B\u200D\uD83D)?\uDC68\uD83C[\uDFFB-\uDFFF]|\uD83C[\uDF3E\uDF73\uDF7C\uDF93\uDFA4\uDFA8\uDFEB\uDFED]|\uD83D[\uDCBB\uDCBC\uDD27\uDD2C\uDE80\uDE92]|\uD83E(?:\uDD1D\u200D\uD83D\uDC68\uD83C[\uDFFB\uDFFC\uDFFE\uDFFF]|[\uDDAF-\uDDB3\uDDBC\uDDBD])))?|\uDFFE(?:\u200D(?:[\u2695\u2696\u2708]\uFE0F?|\u2764\uFE0F?\u200D\uD83D(?:\uDC8B\u200D\uD83D)?\uDC68\uD83C[\uDFFB-\uDFFF]|\uD83C[\uDF3E\uDF73\uDF7C\uDF93\uDFA4\uDFA8\uDFEB\uDFED]|\uD83D[\uDCBB\uDCBC\uDD27\uDD2C\uDE80\uDE92]|\uD83E(?:\uDD1D\u200D\uD83D\uDC68\uD83C[\uDFFB-\uDFFD\uDFFF]|[\uDDAF-\uDDB3\uDDBC\uDDBD])))?|\uDFFF(?:\u200D(?:[\u2695\u2696\u2708]\uFE0F?|\u2764\uFE0F?\u200D\uD83D(?:\uDC8B\u200D\uD83D)?\uDC68\uD83C[\uDFFB-\uDFFF]|\uD83C[\uDF3E\uDF73\uDF7C\uDF93\uDFA4\uDFA8\uDFEB\uDFED]|\uD83D[\uDCBB\uDCBC\uDD27\uDD2C\uDE80\uDE92]|\uD83E(?:\uDD1D\u200D\uD83D\uDC68\uD83C[\uDFFB-\uDFFE]|[\uDDAF-\uDDB3\uDDBC\uDDBD])))?))?|\uDC69(?:\u200D(?:[\u2695\u2696\u2708]\uFE0F?|\u2764\uFE0F?\u200D\uD83D(?:\uDC8B\u200D\uD83D)?[\uDC68\uDC69]|\uD83C[\uDF3E\uDF73\uDF7C\uDF93\uDFA4\uDFA8\uDFEB\uDFED]|\uD83D(?:\uDC66(?:\u200D\uD83D\uDC66)?|\uDC67(?:\u200D\uD83D[\uDC66\uDC67])?|\uDC69\u200D\uD83D(?:\uDC66(?:\u200D\uD83D\uDC66)?|\uDC67(?:\u200D\uD83D[\uDC66\uDC67])?)|[\uDCBB\uDCBC\uDD27\uDD2C\uDE80\uDE92])|\uD83E[\uDDAF-\uDDB3\uDDBC\uDDBD])|\uD83C(?:\uDFFB(?:\u200D(?:[\u2695\u2696\u2708]\uFE0F?|\u2764\uFE0F?\u200D\uD83D(?:[\uDC68\uDC69]\uD83C[\uDFFB-\uDFFF]|\uDC8B\u200D\uD83D[\uDC68\uDC69]\uD83C[\uDFFB-\uDFFF])|\uD83C[\uDF3E\uDF73\uDF7C\uDF93\uDFA4\uDFA8\uDFEB\uDFED]|\uD83D[\uDCBB\uDCBC\uDD27\uDD2C\uDE80\uDE92]|\uD83E(?:\uDD1D\u200D\uD83D[\uDC68\uDC69]\uD83C[\uDFFC-\uDFFF]|[\uDDAF-\uDDB3\uDDBC\uDDBD])))?|\uDFFC(?:\u200D(?:[\u2695\u2696\u2708]\uFE0F?|\u2764\uFE0F?\u200D\uD83D(?:[\uDC68\uDC69]\uD83C[\uDFFB-\uDFFF]|\uDC8B\u200D\uD83D[\uDC68\uDC69]\uD83C[\uDFFB-\uDFFF])|\uD83C[\uDF3E\uDF73\uDF7C\uDF93\uDFA4\uDFA8\uDFEB\uDFED]|\uD83D[\uDCBB\uDCBC\uDD27\uDD2C\uDE80\uDE92]|\uD83E(?:\uDD1D\u200D\uD83D[\uDC68\uDC69]\uD83C[\uDFFB\uDFFD-\uDFFF]|[\uDDAF-\uDDB3\uDDBC\uDDBD])))?|\uDFFD(?:\u200D(?:[\u2695\u2696\u2708]\uFE0F?|\u2764\uFE0F?\u200D\uD83D(?:[\uDC68\uDC69]\uD83C[\uDFFB-\uDFFF]|\uDC8B\u200D\uD83D[\uDC68\uDC69]\uD83C[\uDFFB-\uDFFF])|\uD83C[\uDF3E\uDF73\uDF7C\uDF93\uDFA4\uDFA8\uDFEB\uDFED]|\uD83D[\uDCBB\uDCBC\uDD27\uDD2C\uDE80\uDE92]|\uD83E(?:\uDD1D\u200D\uD83D[\uDC68\uDC69]\uD83C[\uDFFB\uDFFC\uDFFE\uDFFF]|[\uDDAF-\uDDB3\uDDBC\uDDBD])))?|\uDFFE(?:\u200D(?:[\u2695\u2696\u2708]\uFE0F?|\u2764\uFE0F?\u200D\uD83D(?:[\uDC68\uDC69]\uD83C[\uDFFB-\uDFFF]|\uDC8B\u200D\uD83D[\uDC68\uDC69]\uD83C[\uDFFB-\uDFFF])|\uD83C[\uDF3E\uDF73\uDF7C\uDF93\uDFA4\uDFA8\uDFEB\uDFED]|\uD83D[\uDCBB\uDCBC\uDD27\uDD2C\uDE80\uDE92]|\uD83E(?:\uDD1D\u200D\uD83D[\uDC68\uDC69]\uD83C[\uDFFB-\uDFFD\uDFFF]|[\uDDAF-\uDDB3\uDDBC\uDDBD])))?|\uDFFF(?:\u200D(?:[\u2695\u2696\u2708]\uFE0F?|\u2764\uFE0F?\u200D\uD83D(?:[\uDC68\uDC69]\uD83C[\uDFFB-\uDFFF]|\uDC8B\u200D\uD83D[\uDC68\uDC69]\uD83C[\uDFFB-\uDFFF])|\uD83C[\uDF3E\uDF73\uDF7C\uDF93\uDFA4\uDFA8\uDFEB\uDFED]|\uD83D[\uDCBB\uDCBC\uDD27\uDD2C\uDE80\uDE92]|\uD83E(?:\uDD1D\u200D\uD83D[\uDC68\uDC69]\uD83C[\uDFFB-\uDFFE]|[\uDDAF-\uDDB3\uDDBC\uDDBD])))?))?|\uDC6A|[\uDC6B-\uDC6D](?:\uD83C[\uDFFB-\uDFFF])?|\uDC6E(?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|\uDC6F(?:\u200D[\u2640\u2642]\uFE0F?)?|[\uDC70\uDC71](?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|\uDC72(?:\uD83C[\uDFFB-\uDFFF])?|\uDC73(?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|[\uDC74-\uDC76](?:\uD83C[\uDFFB-\uDFFF])?|\uDC77(?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|\uDC78(?:\uD83C[\uDFFB-\uDFFF])?|[\uDC79-\uDC7B]|\uDC7C(?:\uD83C[\uDFFB-\uDFFF])?|[\uDC7D-\uDC80]|[\uDC81\uDC82](?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|\uDC83(?:\uD83C[\uDFFB-\uDFFF])?|\uDC84|\uDC85(?:\uD83C[\uDFFB-\uDFFF])?|[\uDC86\uDC87](?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|[\uDC88-\uDC8E]|\uDC8F(?:\uD83C[\uDFFB-\uDFFF])?|\uDC90|\uDC91(?:\uD83C[\uDFFB-\uDFFF])?|[\uDC92-\uDCA9]|\uDCAA(?:\uD83C[\uDFFB-\uDFFF])?|[\uDCAB-\uDCFC]|\uDCFD\uFE0F?|[\uDCFF-\uDD3D]|[\uDD49\uDD4A]\uFE0F?|[\uDD4B-\uDD4E\uDD50-\uDD67]|[\uDD6F\uDD70\uDD73]\uFE0F?|\uDD74(?:\uD83C[\uDFFB-\uDFFF]|\uFE0F)?|\uDD75(?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?|\uFE0F(?:\u200D[\u2640\u2642]\uFE0F?)?)?|[\uDD76-\uDD79]\uFE0F?|\uDD7A(?:\uD83C[\uDFFB-\uDFFF])?|[\uDD87\uDD8A-\uDD8D]\uFE0F?|\uDD90(?:\uD83C[\uDFFB-\uDFFF]|\uFE0F)?|[\uDD95\uDD96](?:\uD83C[\uDFFB-\uDFFF])?|\uDDA4|[\uDDA5\uDDA8\uDDB1\uDDB2\uDDBC\uDDC2-\uDDC4\uDDD1-\uDDD3\uDDDC-\uDDDE\uDDE1\uDDE3\uDDE8\uDDEF\uDDF3\uDDFA]\uFE0F?|[\uDDFB-\uDE2D]|\uDE2E(?:\u200D\uD83D\uDCA8)?|[\uDE2F-\uDE34]|\uDE35(?:\u200D\uD83D\uDCAB)?|\uDE36(?:\u200D\uD83C\uDF2B\uFE0F?)?|[\uDE37-\uDE44]|[\uDE45-\uDE47](?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|[\uDE48-\uDE4A]|\uDE4B(?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|\uDE4C(?:\uD83C[\uDFFB-\uDFFF])?|[\uDE4D\uDE4E](?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|\uDE4F(?:\uD83C[\uDFFB-\uDFFF])?|[\uDE80-\uDEA2]|\uDEA3(?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|[\uDEA4-\uDEB3]|[\uDEB4-\uDEB6](?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|[\uDEB7-\uDEBF]|\uDEC0(?:\uD83C[\uDFFB-\uDFFF])?|[\uDEC1-\uDEC5]|\uDECB\uFE0F?|\uDECC(?:\uD83C[\uDFFB-\uDFFF])?|[\uDECD-\uDECF]\uFE0F?|[\uDED0-\uDED2\uDED5-\uDED7\uDEDD-\uDEDF]|[\uDEE0-\uDEE5\uDEE9]\uFE0F?|[\uDEEB\uDEEC]|[\uDEF0\uDEF3]\uFE0F?|[\uDEF4-\uDEFC\uDFE0-\uDFEB\uDFF0])|\uD83E(?:\uDD0C(?:\uD83C[\uDFFB-\uDFFF])?|[\uDD0D\uDD0E]|\uDD0F(?:\uD83C[\uDFFB-\uDFFF])?|[\uDD10-\uDD17]|[\uDD18-\uDD1F](?:\uD83C[\uDFFB-\uDFFF])?|[\uDD20-\uDD25]|\uDD26(?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|[\uDD27-\uDD2F]|[\uDD30-\uDD34](?:\uD83C[\uDFFB-\uDFFF])?|\uDD35(?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|\uDD36(?:\uD83C[\uDFFB-\uDFFF])?|[\uDD37-\uDD39](?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|\uDD3A|\uDD3C(?:\u200D[\u2640\u2642]\uFE0F?)?|[\uDD3D\uDD3E](?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|[\uDD3F-\uDD45\uDD47-\uDD76]|\uDD77(?:\uD83C[\uDFFB-\uDFFF])?|[\uDD78-\uDDB4]|[\uDDB5\uDDB6](?:\uD83C[\uDFFB-\uDFFF])?|\uDDB7|[\uDDB8\uDDB9](?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|\uDDBA|\uDDBB(?:\uD83C[\uDFFB-\uDFFF])?|[\uDDBC-\uDDCC]|[\uDDCD-\uDDCF](?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|\uDDD0|\uDDD1(?:\u200D(?:[\u2695\u2696\u2708]\uFE0F?|\uD83C[\uDF3E\uDF73\uDF7C\uDF84\uDF93\uDFA4\uDFA8\uDFEB\uDFED]|\uD83D[\uDCBB\uDCBC\uDD27\uDD2C\uDE80\uDE92]|\uD83E(?:\uDD1D\u200D\uD83E\uDDD1|[\uDDAF-\uDDB3\uDDBC\uDDBD]))|\uD83C(?:\uDFFB(?:\u200D(?:[\u2695\u2696\u2708]\uFE0F?|\u2764\uFE0F?\u200D(?:\uD83D\uDC8B\u200D)?\uD83E\uDDD1\uD83C[\uDFFC-\uDFFF]|\uD83C[\uDF3E\uDF73\uDF7C\uDF84\uDF93\uDFA4\uDFA8\uDFEB\uDFED]|\uD83D[\uDCBB\uDCBC\uDD27\uDD2C\uDE80\uDE92]|\uD83E(?:\uDD1D\u200D\uD83E\uDDD1\uD83C[\uDFFB-\uDFFF]|[\uDDAF-\uDDB3\uDDBC\uDDBD])))?|\uDFFC(?:\u200D(?:[\u2695\u2696\u2708]\uFE0F?|\u2764\uFE0F?\u200D(?:\uD83D\uDC8B\u200D)?\uD83E\uDDD1\uD83C[\uDFFB\uDFFD-\uDFFF]|\uD83C[\uDF3E\uDF73\uDF7C\uDF84\uDF93\uDFA4\uDFA8\uDFEB\uDFED]|\uD83D[\uDCBB\uDCBC\uDD27\uDD2C\uDE80\uDE92]|\uD83E(?:\uDD1D\u200D\uD83E\uDDD1\uD83C[\uDFFB-\uDFFF]|[\uDDAF-\uDDB3\uDDBC\uDDBD])))?|\uDFFD(?:\u200D(?:[\u2695\u2696\u2708]\uFE0F?|\u2764\uFE0F?\u200D(?:\uD83D\uDC8B\u200D)?\uD83E\uDDD1\uD83C[\uDFFB\uDFFC\uDFFE\uDFFF]|\uD83C[\uDF3E\uDF73\uDF7C\uDF84\uDF93\uDFA4\uDFA8\uDFEB\uDFED]|\uD83D[\uDCBB\uDCBC\uDD27\uDD2C\uDE80\uDE92]|\uD83E(?:\uDD1D\u200D\uD83E\uDDD1\uD83C[\uDFFB-\uDFFF]|[\uDDAF-\uDDB3\uDDBC\uDDBD])))?|\uDFFE(?:\u200D(?:[\u2695\u2696\u2708]\uFE0F?|\u2764\uFE0F?\u200D(?:\uD83D\uDC8B\u200D)?\uD83E\uDDD1\uD83C[\uDFFB-\uDFFD\uDFFF]|\uD83C[\uDF3E\uDF73\uDF7C\uDF84\uDF93\uDFA4\uDFA8\uDFEB\uDFED]|\uD83D[\uDCBB\uDCBC\uDD27\uDD2C\uDE80\uDE92]|\uD83E(?:\uDD1D\u200D\uD83E\uDDD1\uD83C[\uDFFB-\uDFFF]|[\uDDAF-\uDDB3\uDDBC\uDDBD])))?|\uDFFF(?:\u200D(?:[\u2695\u2696\u2708]\uFE0F?|\u2764\uFE0F?\u200D(?:\uD83D\uDC8B\u200D)?\uD83E\uDDD1\uD83C[\uDFFB-\uDFFE]|\uD83C[\uDF3E\uDF73\uDF7C\uDF84\uDF93\uDFA4\uDFA8\uDFEB\uDFED]|\uD83D[\uDCBB\uDCBC\uDD27\uDD2C\uDE80\uDE92]|\uD83E(?:\uDD1D\u200D\uD83E\uDDD1\uD83C[\uDFFB-\uDFFF]|[\uDDAF-\uDDB3\uDDBC\uDDBD])))?))?|[\uDDD2\uDDD3](?:\uD83C[\uDFFB-\uDFFF])?|\uDDD4(?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|\uDDD5(?:\uD83C[\uDFFB-\uDFFF])?|[\uDDD6-\uDDDD](?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|[\uDDDE\uDDDF](?:\u200D[\u2640\u2642]\uFE0F?)?|[\uDDE0-\uDDFF\uDE70-\uDE74\uDE78-\uDE7C\uDE80-\uDE86\uDE90-\uDEAC\uDEB0-\uDEBA\uDEC0-\uDEC2]|[\uDEC3-\uDEC5](?:\uD83C[\uDFFB-\uDFFF])?|[\uDED0-\uDED9\uDEE0-\uDEE7]|\uDEF0(?:\uD83C[\uDFFB-\uDFFF])?|\uDEF1(?:\uD83C(?:\uDFFB(?:\u200D\uD83E\uDEF2\uD83C[\uDFFC-\uDFFF])?|\uDFFC(?:\u200D\uD83E\uDEF2\uD83C[\uDFFB\uDFFD-\uDFFF])?|\uDFFD(?:\u200D\uD83E\uDEF2\uD83C[\uDFFB\uDFFC\uDFFE\uDFFF])?|\uDFFE(?:\u200D\uD83E\uDEF2\uD83C[\uDFFB-\uDFFD\uDFFF])?|\uDFFF(?:\u200D\uD83E\uDEF2\uD83C[\uDFFB-\uDFFE])?))?|[\uDEF2-\uDEF6](?:\uD83C[\uDFFB-\uDFFF])?)/g;
See the regex demo. The g flag at the end means this regex can match all occurrences in the input string.
The pattern is created dynamically from the list of emojis and contracted using a regex trie.
See this JavaScript demo:
var text = 'flowers 🌼🌺🌸';
// Detecting if there is at least one emoji
console.log( emoji_detection_regex.test(text) ); // => true
// Counting emojis
console.log( (text.match(emoji_count_regex) || []).length ); // => 3
// Extracting one by one, single emoji array
console.log( text.match(emoji_count_regex) ); // => ["🌼","🌺","🌸"]
// Extracting emoji sequences
console.log( text.match(emoji_extract_or_remove_regex) ); // => ["🌼🌺🌸"]
// Removing emojis
console.log( text.replace(emoji_extract_or_remove_regex, '') ); // => 'flowers '
<script src="https://gitcdn.link/repo/stribizhev/Emojis/main/ws_emoji_regex.js"></script>
The emoji regex declarations are available in the https://github.com/stribizhev/Emojis/blob/main/ws_emoji_regex.js file.

We can detect all list of surrogate pairs or the Emoji characters in a specific range.
If the issue related with storing the input string to database like MySQL version before 5.5 we need to detect and remove all the surrogate pairs using the below regex
/([\uD800-\uDBFF][\uDC00-\uDFFF])/g.

Update for 2020: Many of these patterns don't match compound emojis or Modifier Sequences correctly, or are simply outdated and do not match the newer emojis.
Consider this kissing couple: 👩🏼‍❤️‍💋‍👩🏽. It's actually 6 (maybe more) other emojis glued together with the ZWJ zero-width joiner. To match this correctly, you have to actually match that sequence.
Thus, by matching the longer sequences first, this brute-force pattern (too long too paste, but it's a simple alternation and runs fast) correctly parses all 3521 combined emojis as of May 2021:
GitHub link: https://github.com/sweaver2112/Regex-combined-emojis
Edit 5/10/2021: If the size of the Unicode escape version of this regex is off-putting to you, you could actually skip the Unicode escape sequences and just use literal emojis, thereby saving tons of space...well, almost. This character, "*️⃣", which starts with an asterisk, will throw a "nothing to quantify" error. Getting rid of just this guy yields a much shorter, still working, copy/pastable regex that matches 3,520/3,521 Emojis at the present date:
Regex 101 Demo (compact, unsafe literal emoji version)
Regex 101 Demo (long, safe unicode escape version)
The demos' input string includes all characters from
https://unicode.org/emoji/charts/full-emoji-list.html (13.1)
https://unicode.org/emoji/charts-13.1/full-emoji-modifiers.html
Working example using the compact version:
/*the pattern*/
var emojiPattern = 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/*compile the pattern string into a regex*/
let emoRegex = new RegExp(emojiPattern, "g")
/*extracting the emojis*/
let emojis = [..."This 😀👩‍⚖️is the 🧗‍♀️text👩🏼‍❤️‍💋‍👩🏽.".matchAll(emoRegex)];
console.log(emojis)
/*count of emojis*/
let emoCount = [..."This 😀👩‍⚖️is the 🧗‍♀️text👩🏼‍❤️‍💋‍👩🏽.".matchAll(emoRegex)].length
console.log(emoCount)
/*strip emojis from text*/
let stripped = "This 😀👩‍⚖️is the 🧗‍♀️text👩🏼‍❤️‍💋‍👩🏽.".replaceAll(emoRegex, "")
console.log(stripped)
/*use the pattern string to build a custom regex*/
let customRegex = new RegExp(".*"+emojiPattern+"{3}$") //match a string ending in 3 emojis
console.log(customRegex.test("yep three here 😀👩‍⚖️👩🏼‍❤️‍💋‍👩🏽")) //true
console.log(customRegex.test("nope 🥣👩🏼‍❤️‍💋‍👩🏽")) //false

You can use regular expression to detect it in input text:
/([\uE000-\uF8FF]|\uD83C[\uDF00-\uDFFF]|\uD83D[\uDC00-\uDDFF])/g

I wrote the following function: containsEmojis(input, includeBasic=true), which checks an input string for emojis according to the list of emojis defined in the Unicode specification version 13 (see https://unicode.org/Public/emoji/13.0/emoji-sequences.txt), and allows to ignore "basic" emojis that can be represented with only 3 bytes.
The snippet below defines the function and runs a few test cases:
/**
* iterates over the code points of an input string and returns true if an emoji is found.
*
* an emoji is found if the hex code for the character is 5 characters starting with "1F",
* or if #includeBasic is true, the character is 4 and starts with one of the prefixes of
* a basic emoji as defined in the Unicode specification version 13
* see https://unicode.org/Public/emoji/13.0/emoji-sequences.txt
*
* #input the string to check
* #includeBasic include also the basic emojis that only take 3 characters
*/
function containsEmojis(input, includeBasic) {
if (typeof includeBasic == "undefined")
includeBasic = true;
for (var c of input) {
var cHex = ("" + c).codePointAt(0).toString(16);
var lHex = cHex.length;
if (lHex > 3) {
var prefix = cHex.substring(0, 2);
if (lHex == 5 && prefix == "1f") {
return true;
}
if (includeBasic && lHex == 4) {
if (["20", "21", "23", "24", "25", "26", "27", "2B", "29", "30", "32"].indexOf(prefix) > -1)
return true;
}
}
}
return false;
}
// can be tested as follows:
var input;
input = "Hello World!";
console.log(input, containsEmojis(input));
input = "Hello 🌎!";
console.log(input, containsEmojis(input));
console.log(input, containsEmojis(input, false));
// now try a basic emoji
input = "It sparkles ✨ yay!";
console.log(input, containsEmojis(input));
// pass false for includeBasic
console.log(input, containsEmojis(input, false));

another solution I found that worked for me:
const example = '👩‍👩‍👧‍👦🪲';
const regexpEmojiPresentation = /\p{Emoji_Presentation}/gu;
console.log(example.match(regexpEmojiPresentation));

check the emoji like bellow ways
function getEmojiChars(text) {
console.log(text.match(/\ud83c[\udf00-\udfff]|\ud83d[\udc00-\ude4f]|\ud83d[\ude80-\udeff]/g)) ;
}
you will get the array of emoji in the text

Formatting in Javascript

I have a question related to formatting strings.
User should parse a string in the Format XX:XX.
if the string parsed by user is in the format XX:XX i need to return true,
else false:
app.post('/test', (req, res) => {
if (req.body.time is in the format of XX:XX) {
return true
} else {
return false
}
});

You can use the RegExp.test function for this kind of thing.
Here is an example:
var condition = /^[a-zA-Z]{2}:[a-zA-Z]{2}$/.test("XX:XX");
console.log("Condition: ", condition);
The regex that I've used in this case check if the string is composed from two upper or lower case letters fallowed by a colon and other two such letters.
Based on your edits it seems that you're trying to check if a string represents an hour and minute value, if that is the case, a regex like this will be more appropriate /^\d{2}:\d{2}$/. This regex checks if the string is composed of 2 numbers fallowed by a colon and another 2 numbers.

The tool you're looking for is called Regular Expressions.
It is globally supported in almost every development platform, which makes it extremely convenient to use.
I would recommend this website for working out your regular expressions.
/^[a-zA-Z]{2}:[a-zA-Z]{2}&/g is an example of a Regular Expression that will take any pattern of:
[a-zA-Z]{2} - two characters from the sets a-z and A-Z.
Followed by :
Followed by the same first argument. Essentially, validating the pattern XX:XX. Of course, you can manipulate it as to what you want to allow for X.
^ marks the beginning of a string and $ marks the end of it, so ASD:AS would not work even though it contains the described pattern.

try using regex
var str = "12:aa";
var patt = new RegExp("^([a-zA-Z]|[0-9]){2}:([a-zA-Z]|[0-9]){2}$");
var res = patt.test(str);
if(res){ //if true
//do something
}
else{}

Simple Regexp Pattern matching with escape characters

Hopefully a simple one!
I've been trying to get this to work for several hours now but am having no luck, as I'm fairly new to regexp I may be missing something very obvious here and was hoping someone could point me in the right direction. The pattern I want to match is as follows: -
At least 1 or more numbers + "##" + at least 1 or more numbers + "##" + at least 1 or more numbers
so a few examples of valid combinations would be: -
1##2##3
123#123#123
0##0##0
A few invalid combinations would be
a##b##c
1## ##1
I've got the following regexp like so: -
[\d+]/#/#[\d+]/#/#[\d+]
And am using it like so (note the double slashes as its inside a string): -
var patt = new RegExp("[\\d+]/#/#[\\d+]/#/#[\\d+]");
if(newFieldValue!=patt){newFieldValue=="no match"}
I also tried these but still nothing: -
if(!patt.text(newFieldValue)){newFieldValue==""}
if(patt.text(newFieldValue)){}else{newFieldValue==""}
But nothing I try is matching, where am I going wrong here?
Any pointers gratefully received, cheers!

1) I can't see any reason to use the RegExp constructor over a RegExp literal for your case. (The former is used primarily where the pattern needs to by dynamic, i.e. is contributed to by variables.)
2) You don't need a character class if there's only one type of character in it (so \d+ not [\d+]
3) You are not actually checking the pattern against the input. You don't apply RegEx by creating an instance of it and using ==; you need to use test() or match() to see if a match is made (the former if you want to check only, not capture)
4) You have == where you mean to assign (=)
if (!/\d+##\d+##\d+/.test(newFieldValue)) newFieldValue = "no match";

You put + inside the brackets, so you're matching a single character that's either a digit or +, not a sequence of digits. I also don't understand why you have / before each #, your description doesn't mention anything about this character.
Use:
var patt = /\d+##\d+##\d+/;

You should use the test method of the pat regex
if (!patt.test(newFieldValue)){ newFieldValue=="no match"; }
once you have a valid regular expression.

Try this regex :
^(?:\d+##){2}\d+$
Demo: http://regex101.com/r/mE8aG7
With the following regex
[\d+]/#/#[\d+]/#/#[\d+]
You would only match things like:
+/#/#5/#/#+
+/#/#+/#/#+
0/#/#0/#/#0
because the regex engine sees it like on the schema below:

Something like:
((-\s)?\d+##)+\d+

Javascript string validation using the regex object

I am complete novice at regex and Javascript. I have the following problem: need to check into a textfield the existence of one (1) or many (n) consecutive * (asterisk) character/characters eg. * or ** or *** or infinite (n) *. Strings allowed eg. *tomato or tomato* or **tomato or tomato** or as many(n)*tomato many(n)*. So, far I had tried the following:
var str = 'a string'
var value = encodeURIComponent(str);
var reg = /([^\s]\*)|(\*[^\s])/;
if (reg.test(value) == true ) {
alert ('Watch out your asterisks!!!')
}

By your question it's hard to decipher what you're after... But let me try:
Only allow asterisks at beginning or at end
If you only allow an arbitrary number (at least one) of asterisks either at the beginning or at the end (but not on both sides) like:
*****tomato
tomato******
but not **tomato*****
Then use this regular expression:
reg = /^(?:\*+[^*]+|[^*]+\*+)$/;
Match front and back number of asterisks
If you require that the number of asterisks at the biginning matches number of asterisks at the end like
*****tomato*****
*tomato*
but not **tomato*****
then use this regular expression:
reg = /^(\*+)[^*]+\1$/;
Results?
It's unclear from your question what the results should be when each of these regular expressions match? Are strings that test positive to above regular expressions fine or wrong is on you and your requirements. As long as you have correct regular expressions you're good to go and provide the functionality you require.
I've also written my regular expressions to just exclude asterisks within the string. If you also need to reject spaces or anything else simply adjust the [^...] parts of above expressions.
Note: both regular expressions are untested but should get you started to build the one you actually need and require in your code.

If I understand correctly you're looking for a pattern like this:
var pattern = /\**[^\s*]+\**/;
this won't match strings like ***** or ** ***, but will match ***d*** *d or all of your examples that you say are valid (***tomatos etc).If I misunderstood, let me know and I'll see what I can do to help. PS: we all started out as newbies at some point, nothing to be ashamed of, let alone apologize for :)
After the edit to your question I gather the use of an asterisk is required, either at the beginning or end of the input, but the string must also contain at least 1 other character, so I propose the following solution:
var pattern = /^\*+[^\s*]+|[^\s*]+\*+$/;
'****'.match(pattern);//false
' ***tomato**'.match(pattern);//true
If, however *tomato* is not allowed, you'll have to change the regex to:
var pattern = /^\*+[^\s*]+$|^[^\s*]+\*+$/;
Here's a handy site to help you find your way in the magical world of regular expressions.

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