CodeMirror: onChanges - How to detect what the changes are? - javascript

I have an app where I allow the user to tyoe into a CodeMirror textbox.
I have a connection to the server using SignalR and am pushing up the full text of the textbox upon changes event.
The trouble is that changes are being pushed up to the server every time the user types a letter.
I managed to filter out the empty space and new line change with an if statement like this:
editorChanges(doc, changes: any[]) {
if (changes[0].text.some(str => str)) {
this.signalrHub.push(this.editor.value());
}
}
What I think I need is a solution using RxJs.
I am not all to familuar with RxJs.
Does anyone have experiencce with this?
Has anyone had to do this kind of thing before?

You can use a combination of fromEvent, map, debounceTime and distinctUntilChanged operators.
import { of, fromEvent } from 'rxjs';
import { map, debounceTime, distinctUntilChanged } from 'rxjs/operators';
let codeTextBox = document.getElementById('codetextbox');
let sourceStream$ = fromEvent(codeTextBox, 'input')
.pipe(
map((x: any) => x.target.value),
debounceTime(300),
distinctUntilChanged()
);
cont mysubscription = sourceStream$.subscribe(x=>{
console.log(x) //<-- this is the latest text in the textbox
});
//mysubscription.unsubscribe(); <-- add this line when your view is getting destroyed
Also, do take care not to subscribe multiple times. Ideally the subscribe should happen only once, when the textbox is available in DOM. And do NOT forget to unsubscribe else you'll have a memory leak.

Related

Typescript RXJS Subject await async susbscriptions

Suppose I have two completely independent pieces of code in two completely unrelated classes that subscribe to the same Observable in a service class.
class MyService {
private readonly subject = new Subject<any>();
public observe(): Observable<any> {
return this.subject.pipe();
}
}
class A {
constructor(private readonly service: MyService) {
service.observe().subscribe( async (value) => {
await this.awaitAnOperation(value);
console.log('Class A subscription complete', value);
});
}
}
class B {
constructor(private readonly service: MyService) {
service.observe().subscribe( (value) => console.log('Class B subscription complete', value));
}
}
The issue that I am now facing is that when the service emits an event, the log of class B will come before A, even though A subscribed first. What I need is that all methods are ran and finished before going to the next one. I know if A were to be synchronously than my question would be solved, but A does need to run an async operation AND Bcan only log after A has logged.
A and B are completely unaware of eachother and should be as well. In e.g. C# we can run an async method synchrnonously by using GetAwaiter().Wait(); and is not considered a bad practice since when it needs to run on the main thread. An equivalent TS/JS option would be nice.
EDIT
A subscribes before B. It is simply the chronological order of subscribing that should also execute. I know this is by default emitted in that sequence, but the fact remains that running a subscription method on a different thread would continue the main thread to the next subscription. This is what I need to avoid somehow.
I had a similar issue that I solved with an operator I called forkConcat. Instead of subscribing multiple times, I made multiple operators and chained them so that source$.pipe(operatorA) would happen and complete before source$.pipe(operatorB) started, and that would complete before source$.pipe(operatorC) started, and all three completed before dealing with the next value from source$.
My code looked like this...
source$.pipe(
forkConcat(
concat,
operatorA,
operatorB,
operatorC
) )
where forkConcat is defined as
import { merge, Observable, of } from 'rxjs';
import { concatMap, Operator } from 'rxjs/operators';
/*
Creates an operator that will fork several operators from the same input, and not proceed until all those things are done.
First Argument:
If those things should be done in turn, send concat as the first argument.
If each operator should be done in parallel, use merge (or undefined) as the first argument.
To return an array of each operators' final values per value received by forkConcat, use forkJoin.
You could also use combineLatest, etc.
All other arguments are operators.
*/
type Combiner<T> = (...array$: ObservableInput<T>[]) => Observable<T>;
export function forkConcat<T,R>(combiner: Combiner<T> = merge, ...arrayOperators: Operator<T, R>[]) {
return concatMap<T,R>((x) => {
try {
const x$ = of(x);
const o = arrayOperators
.filter(op => !!op) // ignore falsy arguments
.map(op => x$.pipe(op));
return o.length ? combiner(...o) : x$;
} catch (e) {
throw new ForkConcatError(x, e, combiner, arrayOperators);
}
});
}
class ForkConcatError<T> extends Error {
constructor(
readonly receivedValue: T,
readonly innerError: Error,
readonly combiner: Combiner<T>,
readonly arrayOperators: Operator<T, R>[]
) {
super(innerError.message);
}
}
It worked. But I've also got to tell you...
I threw it away
I slowly began to realize that the need for forkConcat was a sign that I should be doing things differently. I haven't seen your code but when you say they shouldn't know about each other yet one affects the other, I highly suspect you should consider the same. If, instead of global/shared variables, you had global/shared subjects and observables where the one that emitted to B was...
source$.pipe(
concatMap(x => concat(
of(x).pipe(
operatorA,
ignoreElwments()
),
of(x) // B should receive the same value A did.
)
)
... then you wouldn't have this issue and your code would be cleaner.
In my case, I went a different route. I made a State interface, and then instead of passing source values through my operators, I passed {source: Source, state: State} objects. This way, there was no longer any global variables at all! Every operator could be a pure function (or pure function plus side effects) using only the combined value/state pairs emitted into them. State errors were much harder to make! To use this tactic, start thinking of your A and B as operators (that don't know about each other) instead of subscribers (that don't know about each other) and your future self will likely be happier.
But just in case I'm wrong about that advice, you now have forkConcat.
You can do that by combining the two Observables using switchMap rxjs operator. it will be guarantied that the second Observable B will not started unless the first one A is done.
Here a good example to this scenario in the section addressed "Combining Observables in series":
https://blog.danieleghidoli.it/2016/10/22/http-rxjs-observables-angular/

RxJs: Update observables inside a subscription correctly

I wondered how to update a observable inside a subscription without triggering to many events.
In this example I subscribe to area: Observable<Area>, if the area changes I'd like to update the theme: Observable<Theme>. distinctUntilChanged() should do that the subscription is only triggered if the value has changed, but everytime the area gets updated, the amount of theme updates increases by one.
observeArea(): void {
this.area
.pipe(distinctUntilChanged())
.subscribe(area => {
this.themeService.updateTheme({primaryColor: area.color}); // should happen only once per area change
})
}
Is there any "correct" way of doing this, without triggering endless theme updates?
I think the problem might be with the way you are updating the theme.
If you are trying to update the theme by calling observeArea() method.
Every time you call the method a new subscription will be created.
Event will be passed to every subscription. So each time you call the method one subscription will be increasing.
Solution
Use an async pipe
area$!: Observable<any>;
observeArea(): void {
this.area$ = this.area
.pipe(
distinctUntilChanged(),
tap(area => this.themeService.updateTheme({primaryColor: area.color});)
)
}
and in html use area$ | async to subscribe.
example:
<ng-container *ngIf="area$ | async">...</ng-container>
Else you should unsubscribe every time your subscription completes
observeArea(): void {
const sub = this.area
.pipe(distinctUntilChanged())
.subscribe(area => {
this.themeService.updateTheme({primaryColor: area.color});
sub.unsubscribe();
})
}
Better to use async pipe.
I believe this solves your issue.

Trigger a function once 2 inputs are set and then afterwards if either of the value changes in Angular

I have a component with 2 inputs (or mor) and I want to:
Trigger a method X the first time, when both value are set and exists
Trigger a method X each time, if either one of the both value changes
<some-cmp [itemid]="activeItemId$ | async" [userId]="activeUserId$ | async"></some-cmp>
Both values can change at any time, so I figured using rxjs to build a stream lets me control everything. My current solution seems a bit hacky and is difficult to test. I use 2 BehaviourSubjects and combineLatest with a debounceTime.
#Input() set itemId (id){this.itemId$.next(id)};
#Input() set userId (id){this.userId$.next(id)};
itemId$ = new BehaviourSubject$(null);
userId$ = new BehaviourSubbject$(null);
ngOnInt(){
combineLatest([
this.itemId$.pipe(filter(item=>item!===null)),
this.userId$.pipe(filter(item=>item!===null))
]).pipe(
debounceTime(10),
switchMap(...)
).subscribe(...)
}
So my question are
Is there a more elegant way to achieve this behavior?
Is there a way to avoid the debounceTime, which makes testing difficult?
The debounceTime is used in case both value do arrive at the same time and I don't want combineLatest to trigger the method twice.
You are right in using combineLatest, it will only emit the first time after each source has emitted once and then will emit any time any source emits.
Is there a way to avoid the debounceTime. [It] is used in case both value do arrive at the same time and I don't want combineLatest to trigger the method twice.
Maybe debounceTime isn't necessary due to the initial behavior of combineLatest; it will not emit the first time until all sources emit. However if you typically receive subsequent emissions from both sources that occur within a short timeframe, use of debounceTime may be an appropriate optimization.
Is there a more elegant way to achieve this behavior?
I think your code is fine. However, it may not be necessary to use BehaviorSubject since you aren't really using the default value. You could use plain Subject or ReplaySubject(1).
You could assign the result of your combineLatest to another variable and subscribe to that inside ngOnInit or use the async pipe in the template:
#Input() set itemId (id){ this.itemId$.next(id) };
#Input() set userId (id){ this.userId$.next(id) };
itemId$ = new Subject<string>();
userId$ = new Subject<string>();
data$ = combineLatest([
this.itemId$.pipe(filter(i => !!i)),
this.userId$.pipe(filter(i => !!i))
]).pipe(
debounceTime(10),
switchMap(...)
);
ngOnInit() {
this.data$.subscribe(...);
}
Angular provides ngOnChanges hook which can be used in this scenario. It'll trigger ngOnChanges method whenever there's a change in any of the inputs of the component.
Below is an example of how this can be achieved:
export class SomeComponent implements OnChanges {
#Input() itemId: any;
#Input() userId: any;
ngOnChanges(changes: SimpleChanges) {
const change = changes.itemId || changes.userId;
if (change && change.currentValue !== change.previousValue) {
this.doSomething();
}
}
private doSomething() {
// Your logic goes here
}
}
Your HTML will now look clean and you can get rid of async as well:
<some-cmp [itemid]="itemId" [userId]="userId"></some-cmp>

Angular, RxJS - How to cancel previous requests using switchMap?

I was trying to figure out that for a long time by myself but I stuck.
My case: I have a table with data, when user enters the page the request goes to REST API. Above the table there is a form that specify/filters results of the table. When user clicks a button, new request with query parameters goes to a service.
I'm trying to find a way to stop a previous request when user clicked a button, to search a table with specific parameters
Here is what I have done so far stackblitz. Maybe my approach is wrong and someone could show me how to write it better, or maybe there are just few thing to correct.
Thank you for any help
You can use the takeUntil operator inside your pipe, and pass a subject to it, and everytime you apply a new filter you can emit something to that subject to unsubscribe from the previous subscription and subscribe again! let me give you an example on how to use this operator:
regardless if your code was working or not!! I added just the part on how to use the takeUntil operator!
...
unsubscribe = new Subject<boolean>();
constructor(private _service: ServiceConnectService) {}
ngOnInit() {
this.clickStream
.pipe(
map(() => console.log(1)),
switchMap(() => {
return this.getMethodServicesInstances();
}),
takeUntil(this.unsubscribe) // this will be executed once you call next with a value!! and the subscription will be stopped!
)
.subscribe(results => {
console.log(2);
});
}
applyFilter(){
this.unsubscribe.next(true);
/*
you can then rerun the subscription and reset the unsubscribe subject state to null!
*/
}
...

Performance of an angular 2 application with Firebase

I have been creating a web application using angular2 with firebase (angularfire2),
I want to know if my development method is optimized or not.
When user select a group, I check if he is already member of the group.
ngOnInit() {
this.af.auth.subscribe(auth => {
if(auth) {
this.userConnected = auth;
}
});
this.router.params.subscribe(params=>{
this.idgroup=params['idgroup'];
});
this._groupService.getGroupById(this.idgroup).subscribe(
(group)=>{
this.group=group;
this.AlreadyPaticipe(this.group.id,this.userConnected.uid),
}
);
}
this method is work, but when I place the function AlreadyPaticipe(this.group.id,this.userConnected.uid) outside getGroupById(this.idgroup).subscribe() ,I get an error group is undefinded ,I now because angular is asynchrone. I don't khow how I can do it?. How I can optimize my code ?,How I can place the function AlreadyPaticipe(this.group.id,this.userConnected.uid) outside getGroupById(this.idgroup).subscribe()
Thanks in advance.
Everything as stream :
Well first, you shouldn't subscribe that much, the best practice is to combine your observables into one and subscribe to it just once, because everytime you subscribe, you need to cleanup when your component is destroyed (not for http, neither ActivatedRoute though) and you end up managing your subscription imperatively (which is not the aim of RXjs). You can find a good article on this topic here.
You must think everything as a stream, all your properties are observables :
this.user$ = this.af.auth.share(); //not sure of the share, I don't know firebase, don't know what it implies...
this.group$ = this.router.params.map(params => params["idgroup"])
.switchMap(groupID => this.groupService.getGroupById(groupID)).share();
// I imagine that AlreadyPaticipe return true or false, but maybe i'm wrong
this.isMemberOfGroup$ = Observable.combineLatest(
this.group$,
this.user$.filter(user => user !== null)
).flatMap(([group, user]) => this.AlreadyPaticipe(groupID, user.uid));
You don't even have to subscribe ! in your template you just need to use the async pipe. for example:
<span>user: {{user$|async}}</span>
<span>group : {{group$|async}}</span>
<span>member of group : {{isMemberOfGroup$|async}}</span>
Or if you don't want to use the pipe, you can combine all those observable and subscribe only once :
this.subscription = Observable.combineLatest(
this.group$,
this.user$,
this.isMemberOfGroup$
).do(([group, user, memberofGroup]) => {
this.group = group;
this.user = user;
this.isMemberofGroup = memberofGroup;
}).subscribe()
in this case, don't forget to this.subscription.unsubscribe() in ngOnDestroy()
there is a very handy tool on rxJS docs (at the bottom of the page) that helps you to choose the right operator for the right behavior.
I don't care about streams, I want it to work, quick n' dirty :
If You don't want to change your code too much, you could use a Resolve guard that will fetch the data before your component is loaded. Take a look at the docs:
In summary, you want to delay rendering the routed component until all necessary data have been fetched.
You need a resolver.

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