Different Form Submit Actions for Different Forms

Different Form Submit Actions for Different Forms - javascript

Super basic javascript question incoming...
I have two forms, one for uploading a file and one for providing text. I want to have a unique submit action for each of these forms. For the former, to upload the file, and for the latter, to serialize the form into JSON and POST it.
To attempt to accomplish this, I have one function called submit and another called submit2. The file upload form, which invokes submit works just fine.
The problem is with the second form, which invokes submit2. In particular, when I load the page, I get the following errors:
Query.Deferred exception: undefined is not a function (near '...$('form').submit2...').
TypeError: undefined is not a function (near '...$('form').submit2...')
Here's my HTML.
Upload an image
<form method="POST" enctype="multipart/form-data" action="upload">
<input id="img" name="file" type="file" accept=".jpeg,.jpg,.png">
<input class="btn btn-primary" type="submit" value="Submit">
</form>
Paste a URL
<form method="POST" name="urlForm" onclick="submit2()">
<input id="imgurl" name="url" type="text">
<input class="btn btn-primary" value="Submit">
</form>
And here's my javascript.
function ConvertFormToJSON(form){
var array = jQuery(form).serializeArray();
var json = {};
console.log(array)
jQuery.each(array, function() {
json[this.name] = this.value || '';
});
return json;
}
$(document).ready(function () {
var $status = $('.status');
$('#img').change(function (event) {
var obj = $(this)[0];
console.log(obj)
$status.html('');
if (obj.files && obj.files[0]) {
console.log(obj.files)
var fileReader = new FileReader();
fileReader.onload = function (event) {
$('.img-area').html(
`<img class='loaded-img' src='${event.target.result}' style="width:500px;height:500px;"/>`
);
}
fileReader.readAsDataURL(obj.files[0]);
}
});
$('#imgurl').change(function (event) {
var obj = $('#imgurl').val()
console.log(obj)
$('.img-area').html(
`<img class='loaded-img' src='${obj}' style="width:500px;height:500px;"/>`
);
});
$('form').submit(function (event) {
event.preventDefault();
var imageData = new FormData($(this)[0]);
console.log(imageData)
$status.html(
`<span class='eval'>Evaluating...</span>`
);
$.ajax({
url: 'some_api_endpoint',
type: 'POST',
processData: false,
contentType: false,
dataType: 'json',
data: imageData,
success: function (responseData) {
console.log(responseData)
if (responseData.error != null) {
$status.html(
`<span class='result failure'>Failed</span>`
);
} else {
$status.html(
`<span class='result success'>${responseData.message}</span>`
);
}
},
error: function () {
$status.html(
`<span class='eval'>Something went wrong, try again later.</span>`
);
}
});
});
$('form').submit2(function (event) {
event.preventDefault();
var json = ConvertFormToJSON($('form'))
console.log(json)
$status.html(
`<span class='eval'>Evaluating...</span>`
);
$.ajax({
url: 'some_api_endpoint',
type: 'POST',
processData: false,
contentType: 'application/json',
dataType: 'json',
data: JSON.stringify(json),
success: function (responseData) {
console.log(responseData)
if (responseData.error != null) {
$status.html(
`<span class='result failure'>Failed</span>`
);
} else {
$status.html(
`<span class='result success'>${responseData.message}</span>`
);
}
},
error: function () {
$status.html(
`<span class='eval'>Something went wrong, try again later.</span>`
);
}
});
});
});
Edit: Added the ConvertFormToJSON function for completeness, although I think that's orthogonal to the issue I'm facing.

Problem in there Jquery Object dont have submit2 method and when you want to access submit2 method this is return undefined and when call this is return undefined is not function.

Related

reCAPTCHA form submitting twice on second submit

I am creating a form using reCAPTCHA v2 and want the form to be able to be submitted again without reloading the page. When I submit the form for the first time, it works as expected. However, when I submit the form again without reloading the page, my CaptchaValidate function will be called twice, first returning false, then returning true. Why is this happening? Any help would be brilliant, thanks.
HTML
<form id="form" method="POST">
<label for="name">Name</label>
<input class="form-control" id="name" name="name">
<label for="age">Age</label>
<input class="form-control" id="age" name="age">
<button class="g-recaptcha" data-sitekey="myKey" data-callback="onSubmit" type="submit">Submit</button>
</form>
Javascript
function onSubmit(response) {
$('#form').submit(function (e) {
e.preventDefault();
const formData = $(this).serializeArray();
$.ajax({
url: '/Home/CaptchaValidate',
type: 'POST',
dataType: 'text',
data: { dataToken: response },
success: function (resultData) {
if (resultData == 'true') {
//do something
}
else {
$('.error-message').html('could not submit form');
}
},
error: function (err) {
console.log(err);
}
})
}).submit();
grecaptcha.reset();
}
Controller
[HttpPost]
public async Task<string> GetCaptchaData(string dataToken)
{
HttpClient httpClient = new HttpClient();
string secretKey = "mySecretKey";
var res = httpClient.GetAsync("https://www.google.com/recaptcha/api/siteverify?secret=" + secretKey + "&response=" + dataToken).Result;
if (res.StatusCode != HttpStatusCode.OK)
return "false";
string JSONres = res.Content.ReadAsStringAsync().Result;
dynamic JSONdata = JObject.Parse(JSONres);
if (JSONdata.success != "true")
return "false";
return "true";
}

try use e.stopImmediatePropagation();
it stops the rest of the event handlers from being executed.
function onSubmit(response) {
$('#form').submit(function (e) {
e.preventDefault();
e.stopImmediatePropagation(); // new line
const formData = $(this).serializeArray();
$.ajax({
url: '/Home/CaptchaValidate',
type: 'POST',
dataType: 'text',
data: { dataToken: response },
success: function (resultData) {
if (resultData == 'true') {
//do something
}
else {
$('.error-message').html('could not submit form');
}
},
error: function (err) {
console.log(err);
}
})
}).submit();
grecaptcha.reset();
}

Sending form data and action to wordpress admin-ajax.php

I have a form that I want to send its data to admin-ajax:
<form method="POST" id="form">
<input type="text" name="name">
<input type="number" name="phone">
<input type="email" name="email">
<textarea name="overview"></textarea>
<input type="submit" name="submit" id="submit" value="Submit">
</form>
Javascript/jQuery code to send the data using Ajax:
document.getElementById('submit').addEventListener('click', function(e){
e.preventDefault();
var form_data = $('#form').serialize();
$.ajax('http://mywebsite.com/wordpress/wp-admin/admin-ajax.php', {
method: "POST",
data: form_data + {action: 'my_action'},
success: function (response) {
console.log(response);
},
error: function (err) {
console.log('Error:' + err);
}
});
});
Also tried formData:
var form_data = new FormData();
form_data.append('form', $('#custom').serialize());
form_data.append('action', 'my_action');
How to send the form data and the action my_action?

you need to change this line from data: form_data + {action: 'my_action'}, to data: {action: 'my_action', form_data:form_data},
jQuery(document).on("click","#submit", function(){
e.preventDefault();
var form_data =jQuery('#form').serializeArray();
jQuery.ajax('http://mywebsite.com/wordpress/wp-admin/admin-ajax.php', {
method: "POST",
data: {action: 'my_action', form_data:form_data},
success: function (response) {
console.log(response);
},
error: function (err) {
console.log('Error:' + err);
}
});
});
and change input type submit to button.

In general i prefer to use this way, like in your case you are using submit type button:
$(document).on('click', '#submit', function(){ // the id of your submit button
var form_data = $('#your_form_data_id'); // here is the id of your form
form_data.submit(function (e) {
var my_action = "my_action";
e.preventDefault();
$.ajax({
type: form_data.attr('method'), // use this if you have declared the method in the form like: method="POST"
url: form_data.attr('action'), // here you have declared the url in the form and no need to use it again or you can also use the path like in your code
data: form_data.serialize() +'&'+$.param({ 'my_action': my_action}), // here you are sending all data serialized from the form and appending the action value you assing when declare var my_action
success: function (data) {
// after the success result do your other stuff like show in console, print something or else
},
});
});
});
Hope it helps you. if anything is not clear feel free to ask, i try to explain in the comments.

You should just pass form to new FormData() so in your case when submitting the form just pass new FormData(e.target);
Hope it helps

No data receive in Jquery from php json_encode

I need help for my code as i have been browsing the internet looking for the answer for my problem but still can get the answer that can solve my problem. I am kind of new using AJAX. I want to display data from json_encode in php file to my AJAX so that the AJAX can pass it to the textbox in the HTML.
My problem is Json_encode in php file have data from the query in json format but when i pass it to ajax success, function(users) is empty. Console.log also empty array. I have tried use JSON.parse but still i got something wrong in my code as the users itself is empty. Please any help would be much appreciated. Thank you.
car_detail.js
$(document).ready(function() {
function $_GET(q,s) {
s = (s) ? s : window.location.search;
var re = new RegExp('&'+q+'=([^&]*)','i');
return (s=s.replace(/^\?/,'&').match(re)) ?s=s[1] :s='';
}
var car_rent_id1 = $_GET('car_rent_id');
car_rent_id.value = car_rent_id1;
$.ajax({
type: 'POST',
url: "http://localhost/ProjekCordova/mobile_Rentacar/www/php/car_detail.php",
dataType: "json",
cache: false,
data: { car_rent_id: this.car_rent_id1 },
success: function(users) {
console.log(users);
$('#car_name').val(users.car_name);
}
});
});
car_detail.php
$car_rent_id = $_GET['car_rent_id'];
$query = mysql_query("SELECT c.car_name, c.car_type, c.car_colour,
c.plate_no, c.rate_car_hour, c.rate_car_day, c.car_status,
r.pickup_location
FROM car_rent c
JOIN rental r ON c.car_rent_id=r.car_rent_id
WHERE c.car_rent_id = $car_rent_id");
$users = array();
while($r = mysql_fetch_array($query)){
$user = array(
"car_name" => $r['car_name'],
"car_type" => $r['car_type'],
"car_colour" => $r['car_colour'],
"plate_no" => $r['plate_no'],
"rate_car_hour" => $r['rate_car_hour'],
"rate_car_day" => $r['rate_car_day'],
"car_status" => $r['car_status'],
"pickup_location" => $r['pickup_location']
);
$users[] = $user;
// print_r($r);die;
}
print_r(json_encode($users)); //[{"car_name":"Saga","car_type":"Proton","car_colour":"Merah","plate_no":"WA2920C","rate_car_hour":"8","rate_car_day":"0","car_status":"","pickup_location":""}]
car_detail.html
<label>ID:</label>
<input type="text" name="car_rent_id" id="car_rent_id"><br>
<label>Car Name:</label>
<div class = "input-group input-group-sm">
<span class = "input-group-addon" id="sizing-addon3"></span>
<input type = "text" name="car_name" id="car_name" class = "form-control" placeholder = "Car Name" aria-describedby = "sizing-addon3">
</div></br>
<label>Car Type:</label>
<div class = "input-group input-group-sm">
<span class = "input-group-addon" id="sizing-addon3"></span>
<input type = "text" name="car_type" id="car_type" class = "form-control" placeholder = "Car Type" aria-describedby = "sizing-addon3">
</div></br>

Remove this in this.car_rent_id1 and cache: false this works with HEAD and GET, in your AJAX you are using POST but in your PHP you use $_GET. And car_rent_id is not defined, your function $_GET(q,s) requires two parameters and only one is passed.
$(document).ready(function() {
function $_GET(q,s) {
s = (s) ? s : window.location.search;
var re = new RegExp('&'+q+'=([^&]*)','i');
return (s=s.replace(/^\?/,'&').match(re)) ?s=s[1] :s='';
}
var car_rent_id1 = $_GET('car_rent_id'); // missing parameter
car_rent_id.value = car_rent_id1; // where was this declared?
$.ajax({
type: 'POST',
url: "http://localhost/ProjekCordova/mobile_Rentacar/www/php/car_detail.php",
dataType: "json",
data: { car_rent_id: car_rent_id1 },
success: function(users) {
console.log(users);
$('#car_name').val(users.car_name);
}
});
});
You can also use $.post(), post is just a shorthand for $.ajax()
$(document).ready(function() {
function $_GET(q,s) {
s = (s) ? s : window.location.search;
var re = new RegExp('&'+q+'=([^&]*)','i');
return (s=s.replace(/^\?/,'&').match(re)) ?s=s[1] :s='';
}
var car_rent_id1 = $_GET('car_rent_id');
car_rent_id.value = car_rent_id1;
$.post('http://localhost/ProjekCordova/mobile_Rentacar/www/php/car_detail.php', { car_rent_id: car_rent_id1 }, function (users) {
console.log(users);
$('#car_name').val(users.car_name);
});
});
and in your PHP change
$car_rent_id = $_GET['car_rent_id'];
to
$car_rent_id = $_POST['car_rent_id'];

Here is a code skeleton using .done/.fail/.always
<script
src="https://code.jquery.com/jquery-1.12.4.min.js"
integrity="sha256-ZosEbRLbNQzLpnKIkEdrPv7lOy9C27hHQ+Xp8a4MxAQ="
crossorigin="anonymous"></script>
<script>
$(function(){
$.ajax({
url: 'theurl',
dataType: 'json',
cache: false
}).done(function(data){
console.log(data);
}).fail(function(data){
console.log(data);
}).always(function(data){
console.log(data);
});
});
</script>
I've adapted your code, so you can see the error, replace the ajax call with this one
<script>
$.ajax({
url: "theurl",
dataType: "json",
data: { car_rent_id: car_rent_id1 },
success: function(users) {
console.log(users);
$('#car_name').val(users.car_name);
},
error: function(data) {
console.log(data);
alert("I failed, even though the server is giving a 200 response header, I can't read your json.");
}
});
</script>

A couple of recommendations on this, I would follow jQuery API to try an see where the request is failing http://api.jquery.com/jquery.ajax/. Also, I would access the ids for the input fileds with jQuery. e.g.: $("#theID").val().

Access Wikipedia API JSON data in jQuery

$('#searchButton').click(function(){
var searchInput = "";
searchInput = document.getElementById('test');
if(searchInput.value !== ""){
$.getJSON('https://en.wikipedia.org/w/api.php?action=query&list=search&format=json&srsearch='+searchInput+'&utf8=', function(json){
alert(json.query.search[0].title);
});
}
});
I'm confused on why the Json doesnt seem to be loading into the page. It seems like the whole operation stops at the url as even if i enter a string into the alert it doesn't run either...

You got this error because CORS is not enabled for the origin from which you are calling the mediawiki and you can check the same more about here.
https://www.mediawiki.org/wiki/Manual:CORS
You can use jQuery jsonp request as below with dataType: 'jsonp' instead.
Working snippet:
$(document).ready(function() {
$('#searchButton').click(function(){
var searchInput = "";
searchInput = document.getElementById('test');
if(searchInput.value !== ""){
$.ajax( {
url: 'https://en.wikipedia.org/w/api.php',
data: {
action: 'query',
list: 'search',
format: 'json',
srsearch: searchInput.value
},
dataType: 'jsonp'
} ).done( function ( json ) {
alert(json.query.search[0].title);
} );
}
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="text" id="test" />
<input type="button" id="searchButton" value="Search" />

XMLHTTPREQUEST send file and parameters [duplicate]

I'm using jQuery and Ajax for my forms to submit data and files but I'm not sure how to send both data and files in one form?
I currently do almost the same with both methods but the way in which the data is gathered into an array is different, the data uses .serialize(); but the files use = new FormData($(this)[0]);
Is it possible to combine both methods to be able to upload files and data in one form through Ajax?
Data jQuery, Ajax and html
$("form#data").submit(function(){
var formData = $(this).serialize();
$.ajax({
url: window.location.pathname,
type: 'POST',
data: formData,
async: false,
success: function (data) {
alert(data)
},
cache: false,
contentType: false,
processData: false
});
return false;
});
<form id="data" method="post">
<input type="text" name="first" value="Bob" />
<input type="text" name="middle" value="James" />
<input type="text" name="last" value="Smith" />
<button>Submit</button>
</form>
Files jQuery, Ajax and html
$("form#files").submit(function(){
var formData = new FormData($(this)[0]);
$.ajax({
url: window.location.pathname,
type: 'POST',
data: formData,
async: false,
success: function (data) {
alert(data)
},
cache: false,
contentType: false,
processData: false
});
return false;
});
<form id="files" method="post" enctype="multipart/form-data">
<input name="image" type="file" />
<button>Submit</button>
</form>
How can I combine the above so that I can send data and files in one form via Ajax?
My aim is to be able to send all of this form in one post with Ajax, is it possible?
<form id="datafiles" method="post" enctype="multipart/form-data">
<input type="text" name="first" value="Bob" />
<input type="text" name="middle" value="James" />
<input type="text" name="last" value="Smith" />
<input name="image" type="file" />
<button>Submit</button>
</form>

The problem I had was using the wrong jQuery identifier.
You can upload data and files with one form using ajax.
PHP + HTML
<?php
print_r($_POST);
print_r($_FILES);
?>
<form id="data" method="post" enctype="multipart/form-data">
<input type="text" name="first" value="Bob" />
<input type="text" name="middle" value="James" />
<input type="text" name="last" value="Smith" />
<input name="image" type="file" />
<button>Submit</button>
</form>
jQuery + Ajax
$("form#data").submit(function(e) {
e.preventDefault();
var formData = new FormData(this);
$.ajax({
url: window.location.pathname,
type: 'POST',
data: formData,
success: function (data) {
alert(data)
},
cache: false,
contentType: false,
processData: false
});
});
Short Version
$("form#data").submit(function(e) {
e.preventDefault();
var formData = new FormData(this);
$.post($(this).attr("action"), formData, function(data) {
alert(data);
});
});

another option is to use an iframe and set the form's target to it.
you may try this (it uses jQuery):
function ajax_form($form, on_complete)
{
var iframe;
if (!$form.attr('target'))
{
//create a unique iframe for the form
iframe = $("<iframe></iframe>").attr('name', 'ajax_form_' + Math.floor(Math.random() * 999999)).hide().appendTo($('body'));
$form.attr('target', iframe.attr('name'));
}
if (on_complete)
{
iframe = iframe || $('iframe[name="' + $form.attr('target') + '"]');
iframe.load(function ()
{
//get the server response
var response = iframe.contents().find('body').text();
on_complete(response);
});
}
}
it works well with all browsers, you don't need to serialize or prepare the data.
one down side is that you can't monitor the progress.
also, at least for chrome, the request will not appear in the "xhr" tab of the developer tools but under "doc"

I was having this same issue in ASP.Net MVC with HttpPostedFilebase and instead of using form on Submit I needed to use button on click where I needed to do some stuff and then if all OK the submit form so here is how I got it working
$(".submitbtn").on("click", function(e) {
var form = $("#Form");
// you can't pass Jquery form it has to be javascript form object
var formData = new FormData(form[0]);
//if you only need to upload files then
//Grab the File upload control and append each file manually to FormData
//var files = form.find("#fileupload")[0].files;
//$.each(files, function() {
// var file = $(this);
// formData.append(file[0].name, file[0]);
//});
if ($(form).valid()) {
$.ajax({
type: "POST",
url: $(form).prop("action"),
//dataType: 'json', //not sure but works for me without this
data: formData,
contentType: false, //this is requireded please see answers above
processData: false, //this is requireded please see answers above
//cache: false, //not sure but works for me without this
error : ErrorHandler,
success : successHandler
});
}
});
this will than correctly populate your MVC model, please make sure in your Model, The Property for HttpPostedFileBase[] has the same name as the Name of the input control in html i.e.
<input id="fileupload" type="file" name="UploadedFiles" multiple>
public class MyViewModel
{
public HttpPostedFileBase[] UploadedFiles { get; set; }
}

Or shorter:
$("form#data").submit(function() {
var formData = new FormData(this);
$.post($(this).attr("action"), formData, function() {
// success
});
return false;
});

EDIT: with the new version of JQuery (3.6), you could also try using contentType function argument instead of enctype. Try contentType: multipart/form-data.
For me, it didn't work without enctype: 'multipart/form-data' field in the Ajax request. I hope it helps someone who is stuck in a similar problem.
Even though the enctype was already set in the form attribute, for some reason, the Ajax request didn't automatically identify the enctype without explicit declaration (jQuery 3.3.1).
// Tested, this works for me (jQuery 3.3.1)
fileUploadForm.submit(function (e) {
e.preventDefault();
$.ajax({
type: 'POST',
url: $(this).attr('action'),
enctype: 'multipart/form-data',
data: new FormData(this),
processData: false,
contentType: false,
success: function (data) {
console.log('Thank God it worked!');
}
}
);
});
// enctype field was set in the form but Ajax request didn't set it by default.
<form action="process/file-upload" enctype="multipart/form-data" method="post" >
<input type="file" name="input-file" accept="text/plain" required>
...
</form>
As others mentioned above, please also pay special attention to the contentType and processData fields.

A Simple but more effective way:
new FormData() is itself like a container (or a bag). You can put everything attr or file in itself.
The only thing you'll need to append the attribute, file, fileName eg:
let formData = new FormData()
formData.append('input', input.files[0], input.files[0].name)
and just pass it in AJAX request. Eg:
let formData = new FormData()
var d = $('#fileid')[0].files[0]
formData.append('fileid', d);
formData.append('inputname', value);
$.ajax({
url: '/yourroute',
method: 'POST',
contentType: false,
processData: false,
data: formData,
success: function(res){
console.log('successfully')
},
error: function(){
console.log('error')
}
})
You can append n number of files or data with FormData.
and if you're making AJAX Request from Script.js file to Route file in Node.js beware of using
req.body to access data (ie text)
req.files to access file (ie image, video etc)

The code below works for me
$(function () {
debugger;
document.getElementById("FormId").addEventListener("submit", function (e) {
debugger;
if (ValidDateFrom()) { // Check Validation
var form = e.target;
if (form.getAttribute("enctype") === "multipart/form-data") {
debugger;
if (form.dataset.ajax) {
e.preventDefault();
e.stopImmediatePropagation();
var xhr = new XMLHttpRequest();
xhr.open(form.method, form.action);
xhr.onreadystatechange = function (result) {
debugger;
if (xhr.readyState == 4 && xhr.status == 200) {
debugger;
var responseData = JSON.parse(xhr.responseText);
SuccessMethod(responseData); // Redirect to your Success method
}
};
xhr.send(new FormData(form));
}
}
}
}, true);
});
In your Action Post Method, pass parameter as HttpPostedFileBase UploadFile and make sure your file input has same as mentioned in your parameter of the Action Method.
It should work with AJAX Begin form as well.
Remember over here that your AJAX BEGIN Form will not work over here since you make your post call defined in the code mentioned above and you can reference your method in the code as per the Requirement
I know I am answering late but this is what worked for me

Just to remind, in 2022 you don't need to use jquery. Try js standard Fetch API
var formData = new FormData(this);
fetch(url, {
method: 'POST',
body: formData
})
.then(response => {
if(response.ok) {
//success
alert(response);
} else {
throw Error('Server error');
}
})
.catch(error => {
console.log('fail', error);
});

This is a solution that I implemented
var formData = new FormData();
var files = $('input[type=file]');
for (var i = 0; i < files.length; i++) {
if (files[i].value == "" || files[i].value == null) {
return false;
}
else {
formData.append(files[i].name, files[i].files[0]);
}
}
var formSerializeArray = $("#Form").serializeArray();
for (var i = 0; i < formSerializeArray.length; i++) {
formData.append(formSerializeArray[i].name, formSerializeArray[i].value)
}
$.ajax({
type: 'POST',
data: formData,
contentType: false,
processData: false,
cache: false,
url: '/Controller/Action',
success: function (response) {
if (response.Success == true) {
return true;
}
else {
return false;
}
},
error: function () {
return false;
},
failure: function () {
return false;
}
});

---Solution for DOT NET CORE MVC Implementation---
While looking at this question I though I should right .NET CORE implementation for this because the question is not specific to any backend language.
So guys here is the standalone implementation example.
Objective :- To submit form fields including files and how we can get data in a single model at backend
HTML Code / View Code - Views/Home/Index.cshtml
#{
ViewData["Title"] = "Home Page";
}
<input type="file" id="FileUpload1" multiple />
<div>
<label>Enter First Name :</label>
<input type="text" id="nameText" maxlength="50" />
</div>
<input type="button" id="btnUpload" value="Submit Form with Files" />
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.3/jquery.min.js"></script>
<script>
$(document).ready(function () {
$('#btnUpload').click(function () {
// Checking whether FormData is available in browser
if (window.FormData !== undefined) {
var fileUpload = $("#FileUpload1").get(0);
var files = fileUpload.files;
// Create FormData object
var fileData = new FormData();
// Looping over all files and add it to FormData object
for (var i = 0; i < files.length; i++) {
fileData.append("files", files[i]);
}
// Adding one more key to FormData object
fileData.append('FirstName', $("#nameText").val());
$.ajax({
url: '/Home/UploadFiles',
type: "POST",
contentType: false, // Not to set any content header
processData: false, // Not to process data
data: fileData,
success: function (result) {
alert(result);
},
error: function (err) {
alert(err.statusText);
}
});
} else {
alert("FormData is not supported.");
}
});
});
</script>
Backend Code / Controller action method Controllers/HomeController.cs
public class HomeController : Controller
{
private readonly ILogger<HomeController> _logger;
private readonly IWebHostEnvironment _environment;
public HomeController(ILogger<HomeController> logger, IWebHostEnvironment environment)
{
_logger = logger;
_environment = environment;
}
public IActionResult Index()
{
return View();
}
public IActionResult Privacy()
{
return View();
}
[HttpPost]
public async Task<IActionResult> UploadFiles(MyForm myForm)
{
var files = myForm.Files;
// First Name
string name = myForm.FirstName;
// check All files
foreach (IFormFile source in files)
{
string filename = ContentDispositionHeaderValue.Parse(source.ContentDisposition).FileName.Trim('"');
filename = this.EnsureCorrectFilename(filename);
string fileWithPath = this.GetPathAndFilename(filename);
// Create directory if not exist
Directory.CreateDirectory(Path.GetDirectoryName(fileWithPath));
using (FileStream output = System.IO.File.Create(fileWithPath))
await source.CopyToAsync(output);
}
return Ok("Success");
}
[ResponseCache(Duration = 0, Location = ResponseCacheLocation.None, NoStore = true)]
public IActionResult Error()
{
return View(new ErrorViewModel { RequestId = Activity.Current?.Id ?? HttpContext.TraceIdentifier });
}
public class MyForm
{
public string FirstName { get; set; }
public IList<IFormFile> Files { get; set; }
}
private string EnsureCorrectFilename(string filename)
{
if (filename.Contains("\\"))
filename = filename.Substring(filename.LastIndexOf("\\") + 1);
return filename;
}
private string GetPathAndFilename(string filename)
{
return Path.Combine(_environment.ContentRootPath, "uploadedFiles", filename);
}
}
Full Source Code Repo: https://github.com/rj-learning/DotNetCoreFileUpload

In my case I had to make a POST request, which had information sent through the header, and also a file sent using a FormData object.
I made it work using a combination of some of the answers here, so basically what ended up working was having this five lines in my Ajax request:
contentType: "application/octet-stream",
enctype: 'multipart/form-data',
contentType: false,
processData: false,
data: formData,
Where formData was a variable created like this:
var file = document.getElementById('uploadedFile').files[0];
var form = $('form')[0];
var formData = new FormData(form);
formData.append("File", file);

you can just append them on your formdata, add your files and datas in it.you can read this..
https://developer.mozilla.org/en-US/docs/Web/API/FormData/append
for better understanding. you can separately retrieve them $_FILES for your files and $_POST for your data.

<form id="form" method="post" action="otherpage.php" enctype="multipart/form-data">
<input type="text" name="first" value="Bob" />
<input type="text" name="middle" value="James" />
<input type="text" name="last" value="Smith" />
<input name="image" type="file" />
<button type='button' id='submit_btn'>Submit</button>
</form>
<script>
$(document).on("click", "#submit_btn", function (e) {
//Prevent Instant Click
e.preventDefault();
// Create an FormData object
var formData = $("#form").submit(function (e) {
return;
});
//formData[0] contain form data only
// You can directly make object via using form id but it require all ajax operation inside $("form").submit(<!-- Ajax Here -->)
var formData = new FormData(formData[0]);
$.ajax({
url: $('#form').attr('action'),
type: 'POST',
data: formData,
success: function (response) {
console.log(response);
},
contentType: false,
processData: false,
cache: false
});
return false;
});
</script>
///// otherpage.php
<?php
print_r($_FILES);
?>

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