How to show content timezone specific using javascript & html - javascript

My website currently displays the .pastTV div during the hours of
12:00pm-12:30pm EST. However, the code is not time-zone specific, capturing the local time of anyone visiting site.
Is there a way to make this specific to a UTC offset or timezone so that everyone is seeing (or not seeing) the same element?
My code works as expected when a visitor is in the Eastern timezone, otherwise it reads the local user time.
Update: Used this code instead for the same effect
var NYDate = new Date(new Date().toLocaleString("en-US", {timeZone: "America/New_York"}));
var NYHour = NYDate.getHours();
var NYMins = NYDate.getMinutes()
//12pm
if (NYHour >= 12 && NYHour <= 12 &&
NYMins > 0 && NYMins < 30) {
$('.pasttv, .life2').toggle();
}
var Now = new Date();
var CurrentDay = Now.getDay();
// opening time - 24 hours so 12:00pm is 12, 00
var OpeningTime = new Date(Now.getFullYear(), Now.getMonth(), Now.getDate(), 12, 00);
// closing time - 24 hours so 12:30pm is 12, 30
var ClosingTime = new Date(Now.getFullYear(), Now.getMonth(), Now.getDate(), 12, 30);
var Open = (Now.getTime() > OpeningTime.getTime() && Now.getTime() < ClosingTime.getTime())
// days 0.sun 1.mon 2.tues 3.wed 4.thur 5.fri 6.sat
// CurrentDay !== 0 && the # is the day to eclude, so if I want to be closed on Sat6, Sun0, Wed3
// CurrentDay !== 6 && CurrentDay !== 0 && CurrentDay !== 3 && Open
if (CurrentDay !== 0 && CurrentDay !== 6 && Open) {
$('.pasttv').toggle();
}
.hours {
display: none;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div class="hours pasttv">
<font class="show-title">Past TVense</font><br> The first shows of the television medium
</div>

Have you tried using this? Date.prototype.getTimezoneOffset()
More info below:
"The time-zone offset is the difference, in minutes, from local time to UTC. Note that this means that the offset is positive if the local timezone is behind UTC and negative if it is ahead. For example, for time zone UTC+10:00 (Australian Eastern Standard Time, Vladivostok Time, Chamorro Standard Time), -600 will be returned."
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Date/getTimezoneOffset

Related

How to display today's date and time as 9 am and continue till next day?

I am doing a react project.I want to display today's date and time as "9 am" .This has to be remained unchanged till time is 9 am on next day. After that it should display time as 9 am along with date of that day and continue this till next day 9 am and so on.
<span>Last Updated: {moment().format('MMMM Do YYYY,') + " 9:00 am"}</span>
The above code displays the time as 9 am even before the time is 9 am on the nextday. It should look like current time and date gets updated only at 9 am everyday.
This code creates a function that retrieves the formatted date at a given hour. If the hour is not specified, it will use the current hour. It will return today's date, unless the hour is before 9, in which case it will return yesterday's date. The format will use the current user's native formatting for a "long" date. The HTML shows the desired result, the console logs what happens before 9 on the current day, and the current hour. The hour is determined by the user's time zone.
function getDateAtNine(forceHour) {
let now = new Date();
const hour = forceHour == null ? now.getHours() : forceHour;
if (hour < 9) {
now = new Date(now.getFullYear(), now.getMonth(), now.getDate() - 1);
}
return new Intl.DateTimeFormat(undefined, {
dateStyle: 'long'
}).format(now);
}
console.log(getDateAtNine(8)); // shows what will print at 8 am on today's date
console.log(getDateAtNine()); // shows what will print at the current hour on today's date
document.querySelector('#dateat9').textContent = getDateAtNine();
<span id="dateat9"></span><span id="nineam">, 9:00 am</span>
Is that what you are looking for? ;)
const getLastStartOfDay = (startOfDayHour) => {
let todayStartOfDay = new Date();
todayStartOfDay.setHours(startOfDayHour, 0, 0, 0);
let yesterdayStartOfDay = new Date(todayStartOfDay);
yesterdayStartOfDay.setDate(yesterdayStartOfDay.getDate() - 1);
let dt = new Date();
const displayDate =
dt.getHours() < startOfDayHour ? yesterdayStartOfDay : todayStartOfDay;
return displayDate;
};
console.log("LastStartOfDay: ", getLastStartOfDay(9));

End of Month using javascript [duplicate]

If you provide 0 as the dayValue in Date.setFullYear you get the last day of the previous month:
d = new Date(); d.setFullYear(2008, 11, 0); // Sun Nov 30 2008
There is reference to this behaviour at mozilla. Is this a reliable cross-browser feature or should I look at alternative methods?
var month = 0; // January
var d = new Date(2008, month + 1, 0);
console.log(d.toString()); // last day in January
IE 6: Thu Jan 31 00:00:00 CST 2008
IE 7: Thu Jan 31 00:00:00 CST 2008
IE 8: Beta 2: Thu Jan 31 00:00:00 CST 2008
Opera 8.54: Thu, 31 Jan 2008 00:00:00 GMT-0600
Opera 9.27: Thu, 31 Jan 2008 00:00:00 GMT-0600
Opera 9.60: Thu Jan 31 2008 00:00:00 GMT-0600
Firefox 2.0.0.17: Thu Jan 31 2008 00:00:00 GMT-0600 (Canada Central Standard Time)
Firefox 3.0.3: Thu Jan 31 2008 00:00:00 GMT-0600 (Canada Central Standard Time)
Google Chrome 0.2.149.30: Thu Jan 31 2008 00:00:00 GMT-0600 (Canada Central Standard Time)
Safari for Windows 3.1.2: Thu Jan 31 2008 00:00:00 GMT-0600 (Canada Central Standard Time)
Output differences are due to differences in the toString() implementation, not because the dates are different.
Of course, just because the browsers identified above use 0 as the last day of the previous month does not mean they will continue to do so, or that browsers not listed will do so, but it lends credibility to the belief that it should work the same way in every browser.
I find this to be the best solution for me. Let the Date object calculate it for you.
var today = new Date();
var lastDayOfMonth = new Date(today.getFullYear(), today.getMonth()+1, 0);
Setting day parameter to 0 means one day less than first day of the month which is last day of the previous month.
I would use an intermediate date with the first day of the next month, and return the date from the previous day:
int_d = new Date(2008, 11+1,1);
d = new Date(int_d - 1);
In computer terms, new Date() and regular expression solutions are slow! If you want a super-fast (and super-cryptic) one-liner, try this one (assuming m is in Jan=1 format). I keep trying different code changes to get the best performance.
My current fastest version:
After looking at this related question Leap year check using bitwise operators (amazing speed) and discovering what the 25 & 15 magic number represented, I have come up with this optimized hybrid of answers (note the parameters m & y must obviously be integers for this to work):
function getDaysInMonth(m, y) {
return m===2 ? y & 3 || !(y%25) && y & 15 ? 28 : 29 : 30 + (m+(m>>3)&1);
}
Given the bit-shifting this obviously assumes that your m & y parameters are both integers, as passing numbers as strings would result in weird results.
JSFiddle: http://jsfiddle.net/TrueBlueAussie/H89X3/22/
JSPerf results: http://jsperf.com/days-in-month-head-to-head/5
For some reason, (m+(m>>3)&1) is more efficient than (5546>>m&1) on almost all browsers.
The only real competition for speed is from #GitaarLab, so I have created a head-to-head JSPerf for us to test on: http://jsperf.com/days-in-month-head-to-head/5
It works based on my leap year answer here: javascript to find leap year this answer here Leap year check using bitwise operators (amazing speed) as well as the following binary logic.
A quick lesson in binary months:
If you interpret the index of the desired months (Jan = 1) in binary you will notice that months with 31 days either have bit 3 clear and bit 0 set, or bit 3 set and bit 0 clear.
Jan = 1 = 0001 : 31 days
Feb = 2 = 0010
Mar = 3 = 0011 : 31 days
Apr = 4 = 0100
May = 5 = 0101 : 31 days
Jun = 6 = 0110
Jul = 7 = 0111 : 31 days
Aug = 8 = 1000 : 31 days
Sep = 9 = 1001
Oct = 10 = 1010 : 31 days
Nov = 11 = 1011
Dec = 12 = 1100 : 31 days
That means you can shift the value 3 places with >> 3, XOR the bits with the original ^ m and see if the result is 1 or 0 in bit position 0 using & 1. Note: It turns out + is slightly faster than XOR (^) and (m >> 3) + m gives the same result in bit 0.
JSPerf results: http://jsperf.com/days-in-month-perf-test/6
My colleague stumbled upon the following which may be an easier solution
function daysInMonth(iMonth, iYear)
{
return 32 - new Date(iYear, iMonth, 32).getDate();
}
stolen from http://snippets.dzone.com/posts/show/2099
A slight modification to solution provided by lebreeze:
function daysInMonth(iMonth, iYear)
{
return new Date(iYear, iMonth, 0).getDate();
}
I recently had to do something similar, this is what I came up with:
/**
* Returns a date set to the begining of the month
*
* #param {Date} myDate
* #returns {Date}
*/
function beginningOfMonth(myDate){
let date = new Date(myDate);
date.setDate(1)
date.setHours(0);
date.setMinutes(0);
date.setSeconds(0);
return date;
}
/**
* Returns a date set to the end of the month
*
* #param {Date} myDate
* #returns {Date}
*/
function endOfMonth(myDate){
let date = new Date(myDate);
date.setDate(1); // Avoids edge cases on the 31st day of some months
date.setMonth(date.getMonth() +1);
date.setDate(0);
date.setHours(23);
date.setMinutes(59);
date.setSeconds(59);
return date;
}
Pass it in a date, and it will return a date set to either the beginning of the month, or the end of the month.
The begninngOfMonth function is fairly self-explanatory, but what's going in in the endOfMonth function is that I'm incrementing the month to the next month, and then using setDate(0) to roll back the day to the last day of the previous month which is a part of the setDate spec:
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Date/setDate
https://www.w3schools.com/jsref/jsref_setdate.asp
I then set the hour/minutes/seconds to the end of the day, so that if you're using some kind of API that is expecting a date range you'll be able to capture the entirety of that last day. That part might go beyond what the original post is asking for but it could help someone else looking for a similar solution.
Edit: You can also go the extra mile and set milliseconds with setMilliseconds() if you want to be extra precise.
How NOT to do it
Beware of any answers for the last of the month that look like this:
var last = new Date(date)
last.setMonth(last.getMonth() + 1) // This is the wrong way to do it.
last.setDate(0)
This works for most dates, but fails if date is already the last day of the month, on a month that has more days than the following month.
Example:
Suppose date is 07/31/21.
Then last.setMonth(last.getMonth() + 1) increments the month, but keeps the day set at 31.
You get a Date object for 08/31/21,
which is actually 09/01/21.
So then last.setDate(0) results in 08/31/21 when what we really wanted was 07/31/21.
try this one.
lastDateofTheMonth = new Date(year, month, 0)
example:
new Date(2012, 8, 0)
output:
Date {Fri Aug 31 2012 00:00:00 GMT+0900 (Tokyo Standard Time)}
This works for me.
Will provide last day of given year and month:
var d = new Date(2012,02,0);
var n = d.getDate();
alert(n);
This one works nicely:
Date.prototype.setToLastDateInMonth = function () {
this.setDate(1);
this.setMonth(this.getMonth() + 1);
this.setDate(this.getDate() - 1);
return this;
}
You can get the First and Last Date in the current month by following the code:
var dateNow = new Date();
var firstDate = new Date(dateNow.getFullYear(), dateNow.getMonth(), 1);
var lastDate = new Date(dateNow.getFullYear(), dateNow.getMonth() + 1, 0);
or if you want to format the date in your custom format then you can use moment js
var dateNow= new Date();
var firstDate=moment(new Date(dateNow.getFullYear(),dateNow.getMonth(), 1)).format("DD-MM-YYYY");
var currentDate = moment(new Date()).format("DD-MM-YYYY"); //to get the current date var lastDate = moment(new
Date(dateNow.getFullYear(), dateNow.getMonth() + 1, 0)).format("DD-MM-YYYY"); //month last date
This will give you current month first and last day.
If you need to change 'year' remove d.getFullYear() and set your year.
If you need to change 'month' remove d.getMonth() and set your year.
var d = new Date();
var days = ["Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"];
var fistDayOfMonth = days[(new Date(d.getFullYear(), d.getMonth(), 1).getDay())];
var LastDayOfMonth = days[(new Date(d.getFullYear(), d.getMonth() + 1, 0).getDay())];
console.log("First Day :" + fistDayOfMonth);
console.log("Last Day:" + LastDayOfMonth);
alert("First Day :" + fistDayOfMonth);
alert("Last Day:" + LastDayOfMonth);
Try this:
function _getEndOfMonth(time_stamp) {
let time = new Date(time_stamp * 1000);
let month = time.getMonth() + 1;
let year = time.getFullYear();
let day = time.getDate();
switch (month) {
case 1:
case 3:
case 5:
case 7:
case 8:
case 10:
case 12:
day = 31;
break;
case 4:
case 6:
case 9:
case 11:
day = 30;
break;
case 2:
if (_leapyear(year))
day = 29;
else
day = 28;
break
}
let m = moment(`${year}-${month}-${day}`, 'YYYY-MM-DD')
return m.unix() + constants.DAY - 1;
}
function _leapyear(year) {
return (year % 100 === 0) ? (year % 400 === 0) : (year % 4 === 0);
}
const today = new Date();
let beginDate = new Date();
let endDate = new Date();
// fist date of montg
beginDate = new Date(
`${today.getFullYear()}-${today.getMonth() + 1}-01 00:00:00`
);
// end date of month
// set next Month first Date
endDate = new Date(
`${today.getFullYear()}-${today.getMonth() + 2}-01 :23:59:59`
);
// deducting 1 day
endDate.setDate(0);
Below function gives the last day of the month :
function getLstDayOfMonFnc(date) {
return new Date(date.getFullYear(), date.getMonth(), 0).getDate()
}
console.log(getLstDayOfMonFnc(new Date(2016, 2, 15))) // Output : 29
console.log(getLstDayOfMonFnc(new Date(2017, 2, 15))) // Output : 28
console.log(getLstDayOfMonFnc(new Date(2017, 11, 15))) // Output : 30
console.log(getLstDayOfMonFnc(new Date(2017, 12, 15))) // Output : 31
Similarly we can get first day of the month :
function getFstDayOfMonFnc(date) {
return new Date(date.getFullYear(), date.getMonth(), 1).getDate()
}
console.log(getFstDayOfMonFnc(new Date(2016, 2, 15))) // Output : 1
Here is an answer that conserves GMT and time of the initial date
var date = new Date();
var first_date = new Date(date); //Make a copy of the date we want the first and last days from
first_date.setUTCDate(1); //Set the day as the first of the month
var last_date = new Date(first_date); //Make a copy of the calculated first day
last_date.setUTCMonth(last_date.getUTCMonth() + 1); //Add a month
last_date.setUTCDate(0); //Set the date to 0, this goes to the last day of the previous month
console.log(first_date.toJSON().substring(0, 10), last_date.toJSON().substring(0, 10)); //Log the dates with the format yyyy-mm-dd
function getLastDay(y, m) {
return 30 + (m <= 7 ? ((m % 2) ? 1 : 0) : (!(m % 2) ? 1 : 0)) - (m == 2) - (m == 2 && y % 4 != 0 || !(y % 100 == 0 && y % 400 == 0));
}
set month you need to date and then set the day to zero ,so month begin in 1 - 31 in date function then get the last day^^
var last = new Date(new Date(new Date().setMonth(7)).setDate(0)).getDate();
console.log(last);
I know it's just a matter of semantics, but I ended up using it in this form.
var lastDay = new Date(new Date(2008, 11+1,1) - 1).getDate();
console.log(lastDay);
Since functions are resolved from the inside argument, outward, it works the same.
You can then just replace the year, and month / year with the required details, whether it be from the current date. Or a particular month / year.
If you need exact end of the month in miliseconds (for example in a timestamp):
d = new Date()
console.log(d.toString())
d.setDate(1)
d.setHours(23, 59, 59, 999)
d.setMonth(d.getMonth() + 1)
d.setDate(d.getDate() - 1)
console.log(d.toString())
The accepted answer doesn't work for me, I did it as below.
$( function() {
$( "#datepicker" ).datepicker();
$('#getLastDateOfMon').on('click', function(){
var date = $('#datepicker').val();
// Format 'mm/dd/yy' eg: 12/31/2018
var parts = date.split("/");
var lastDateOfMonth = new Date();
lastDateOfMonth.setFullYear(parts[2]);
lastDateOfMonth.setMonth(parts[0]);
lastDateOfMonth.setDate(0);
alert(lastDateOfMonth.toLocaleDateString());
});
});
<!doctype html>
<html lang="en">
<head>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width, initial-scale=1">
<link rel="stylesheet" href="//code.jquery.com/ui/1.12.1/themes/base/jquery-ui.css">
<link rel="stylesheet" href="/resources/demos/style.css">
<script src="https://code.jquery.com/jquery-1.12.4.js"></script>
<script src="https://code.jquery.com/ui/1.12.1/jquery-ui.js"></script>
</head>
<body>
<p>Date: <input type="text" id="datepicker"></p>
<button id="getLastDateOfMon">Get Last Date of Month </button>
</body>
</html>
This will give you last day of current month.
notes: on ios device include time.
#gshoanganh
var date = new Date();
console.log(new Date(date.getFullYear(), date.getMonth() + 1, 0, 23, 59, 59));
if you just need to get the last date of a month following worked out for me.
var d = new Date();
const year = d.getFullYear();
const month = d.getMonth();
const lastDay = new Date(year, month +1, 0).getDate();
console.log(lastDay);
try it out here https://www.w3resource.com/javascript-exercises/javascript-date-exercise-9.php
In my case, this code was useful
end_date = new Date(2018, 3, 1).toISOString().split('T')[0]
console.log(end_date)

Does check day and hour need to check timezone?

My code to check day and hour like this :
function checkDay() {
var day = new Date();
if (day.getDay() >= 1 && day.getDay() <= 5 && day.getHours() >= 9 && day.getHours() < 17) {
return true;
} else {
return false;
}
}
I want every Monday to Friday 9 to 17, it's true. Apart from that, it is false
I had test it and it works. Is it necessary to check Timezone?
My position at Indonesia (GMT + 7)
If I implement timezone, it like this :
function checkDay() {
const offsetHours = new Date().getTimezoneOffset() / 60;
const day = new Date();
day.setHours(day.getHours() + offsetHours);
return day.getDay() >= 1 && day.getDay() <= 5 && day.getHours() >= 2 && day.getHours() < 10;
}
Is it necessary to check Timezone like that?
Your first piece of code is already correct because getHours and getDay already operate in the local time zone. As per the MDN Date documentation:
Note: It's important to keep in mind that while the time value at the heart of a Date object is UTC, the basic methods to fetch the date and time or its components all work in the local (i.e. host system) time zone and offset.
Likewise the ECMAScript specifications (e.g. ECMA 262, 2015 edition) describe the behaviour as going via the LocalTime abstract operation:
The abstract operation LocalTime with argument t converts t from UTC to local time

Based on date and time, show/hide element

I want to show and hide an element on a page based on multiple dates and times. For instance, I have an alert box that I want to show for the following dates 4/28, 4/29, and 4/30 between the hours of 9 am to 12 pm PST. And hide for the remaining hours. The posted code works for an open and closing time but I am unsure how I can add multiple dates. Or I'm just missing something.
Edit: I suck at jQuery/JavaScript.
HTML
<div class="open openstatus">Open</div>
<div class="closed openstatus">Closed</div>
JS
var now = new Date(),
currentDay = now.getDay(),
openTime = new Date(
now.getFullYear(),
now.getMonth(),
now.getDate(),
13,
02
),
closeTime = new Date(
now.getFullYear(),
now.getMonth(),
now.getDate(),
13,
03
),
open = now.getTime() > openTime.getTime() && now.getTime() < closeTime.getTime();
if (currentDay !== 6 && currentDay !== 0 && open) {
$('.openstatus').toggle();
}
I'd do something like this:
HTML
<div id="alertBox">My alert box</div>
JAVASCRIPT
function myFunc(){
var d = new Date(); //client Date
d.setMinutes(d.getMinutes() + d.getTimezoneOffset()); //To get current GMT time
d.setHours(d.getHours() - 8); // This is time in PST
var day = d.getDay(),
month = d.getMonth(),
hours = d.getHours(),
dateOfMonth = d.getDate();
var prohibbittedMonth = 4;
var prohibbittedDates =[28, 29, 30];
var showAlertBox = false;
if(day === 0 || day === 6){
showAlertBox = true; // If the day is Saturday or Sunday
}else if(month = prohibbittedMonth && prohibbittedDates.includes(dateOfMonth) && !(hours >= 0 && hours <9)){
showAlertBox = true;
}
// You may combine the above two condition in a single line. I have just separated them for better readability.
if(!showAlertBox){
document.getElementById('alertBox').style.display = "none"; //You may use your jquery here if you like
}else{
document.getElementById('alertBox').style.display = ""; //You may use your jquery here if you like
}
}
myFunc();
Cant't you add sth like this
currentDate=now.getDate();
if (currentDay !== 6 && currentDay !== 0 && open && (currentDate==28||currentDate==29||currentDate==30))
This checks if the currentDate is either 28 or 29 or 30.

Using JavaScript to change a message depending on the day of the week?

I am adding functionality to a website to change the message depending on if a food truck is open. I was successfully able to make the message change depending on the time, but I'm having trouble implementing getDay() to show the closed message all day on Saturday and Sunday.
Here is the working script that I have so far:
<script language="JavaScript">
var mess1="";
var outmess= "Kendo's Cuisine "
document.write("<center><font size=+1><i><b>")
day = new Date( )
hr = day.getHours( )
if (( hr >= 0 ) && (hr <= 11 ))
mess1= "is closed right now. He's open Mon - Fri 11am - 2pm. "
if (( hr >= 11 ) && (hr < 13))
mess1=" is open right now! Call in your order to have it ready by the time you get here!"
if (( hr >= 13) && (hr <= 14))
mess1= "usually runs out of food by now! Call before you come!"
if (( hr >= 14 ) && (hr <= 24 ))
mess1= "is closed right now. He's open Mon - Fri 11am - 2pm. "
document.write("<blink>")
document.write(outmess)
document.write("</blink>")
document.write(mess1)
document.write("</b></i></font></center>")
</script>
It seems you want to put up a "closed" message outside the hours of 11:00 to 14:00 Monday to Friday, so perhaps:
function isOpen(date) {
var day = date.getDay();
var hour = date.getHours();
if (day == 0 || day == 6 || hour < 11 || hour > 13) {
// shop is closed
return false;
}
// Otherwise, the shop is open
return true;
}
Note however that if the date object is created on the client, it will be local to that timezone, which may not match wherever the shop is. So you probably need to do this based on UTC time, which will be consistent everywhere.
Use getDay() method to get the weekday from date object. It returns a number from 0 - 6 to indicate days from sunday - saturday.
So you have to check like
var day = new Date();
if(day.getDay() == 0 || day.getDay() == 6) {
alert("shop is closed");
}

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