Develop Reference

How do I create an unique dataset of json object literal in Javascript?

I want to get an output as an unique set of Categories array with the following output [Men,Woman].
Is there any way to do it in Javascript?
For example this my data
{
"products:"[
{
"id": 1,
"categories": {
"1": "Men",
},
},
{
"id": 2,
"categories": {
"1": "Men",
},
}, {
"id": 3,
"categories": {
"1": "Woman",
},
}
];
}

A simple 1 line answer would be
new Set(input.products.map(p => p.categories["1"]))
This is if you're expecting only key "1" in the categories object.
If it can have multiple categories then you can always do
const uniqueCategories = new Set();
input.products.forEach(p => uniqueCategories.add(...Object.values(p.categories)))
Now you can convert a Set into an array
PS: This is not a ReactJs problem but a pure JS question. You might want to remove the ReactJs tag from this question altogether.

Is there a way to de-dupe a javascript array and combine values of the data?

I'm using an ajax request to grab some XML data which I then need to push into a chart in fusioncharts.
The XML data is formatted as [time taken], [work done], [which team done for], [who did it] (see below).
I'm iterating over the XML and then building the array using the code below:
//Time Recorded
if (columnidchecker == 7781) {
timearray.push($j(this).find('displayData').text());
temp1 = $j(this).find('displayData').text();
}
//Type of Activity
if (columnidchecker == 7782) {
activityarray.push($j(this).find('displayData').text());
temp2 = $j(this).find('displayData').text();
}
//Team Done For
if (columnidchecker == 7783) {
subjectarray.push($j(this).find('displayData').text());
temp3 = $j(this).find('displayData').text();
}
//Name
if (columnidchecker == 7777) {
internalclientarray.push($j(this).find('displayData').text());
temp4 = $j(this).find('userDisplayName').text();
}
});
//PUSH INTO A NEW ARRAY WHICH CAN THEN BE SORTED AND DE-DUPED WITH TIME COMBINED AGAINST ACTIVITY / TEAM.
objectarray.push([temp1, temp2, temp3, temp4]);
This builds an array of entries from the XML which basically outputs to something which looks like this:
0: (4) ["1.50", "Ad-hoc queries or calls", "Team 1", "James"]
1: (4) ["2.50", "Ad-hoc queries or calls", "Team 1", "James"]
2: (4) ["1.00", "Advice", "Team 2", "James"]
3: (4) ["3.50", "Meeting (External 3rd Party)", "Team 1", "James"]
4: (4) ["1.20", "Administration", Team 2", "James"]
5: (4) ["5.50", "Advice", "Team 1", "John"]
I'm trying to build a chart in fusioncharts which needs the format as shown below (ignore foot stuffs - it's taken straight from the fusioncharts help pages!).
{
"chart": {
"theme": "fusion",
"caption": "Revenue split by product category",
"subCaption": "For current year",
"xAxisname": "Quarter",
"yAxisName": "Revenues (In USD)",
"showSum": "1",
"numberPrefix": "$"
},
"categories": [
{
"category": [
{
"label": "Q1"
},
{
"label": "Q2"
},
{
"label": "Q3"
},
{
"label": "Q4"
}
]
}
],
"dataset": [
{
"seriesname": "Food Products",
"data": [
{
"value": "11000"
},
{
"value": "15000"
},
{
"value": "13500"
},
{
"value": "15000"
}
]
},
{
"seriesname": "Non-Food Products",
"data": [
{
"value": "11400"
},
{
"value": "14800"
},
{
"value": "8300"
},
{
"value": "11800"
}
]
}
]
}
The problem i'm having is that I cannot work out how to take the array of data with times, activity, team, name and push them into categories.
I think the first step is to create a new array of names which can be pushed into the "Category" data field in fusioncharts.
I then need a way in which to take the times being recorded against each activity and for each team and make sure it's assigned to the right person within the stacked bar chart and combine the amount of time spent. (i.e. "James" spent a total of 4 hours doing "Ad Hoc Queries and Calls" for Team 1 but this is split across two time entries so I need a way in which to combine them into one.)
Any help on this would be massively appreciated.
I can de-dupe the names to create a new array by using the following code:
namesarray.push(temp4);
uniq = [...new Set(namesarray)];
but after that it starts getting pretty complicated.

Maybe this can help you along the way. It's probably not exactly in the form you want it, but it demonstrates how you could break the problem down into smaller parts.
Pseudo-code:
get the unique names.
get the unique "task" names (for lack of a
better word)
for each unique person name:
3.1. get the data rows for that person
3.2 for each of all unique tasks names:
find the person data rows matching the task name
sum the duration of those data rows
const testData = [
[
"1.50",
"Ad-hoc queries or calls",
"Team 1",
"James"
],
[
"2.50",
"Ad-hoc queries or calls",
"Team 1",
"James"
],
[
"1.00",
"Advice",
"Team 2",
"James"
],
[
"3.50",
"Meeting (External 3rd Party)",
"Team 1",
"James"
],
[
"1.20",
"Administration",
"Team 2",
"James"
],
[
"5.50",
"Advice",
"Team 1",
"John"
]
];
const columnIndexByName = {
TASK_DURATION: 0,
TASK_NAME: 1,
FOR_WHICH_TEAM: 2,
PERSON_DOING_TASK: 3
};
const sum = (acc, next) => acc + next;
const uniqueNames = [...new Set(testData.map(row => row[columnIndexByName.PERSON_DOING_TASK])) ];
const uniqueTaskNames = [...new Set(testData.map(row => row[columnIndexByName.TASK_NAME])) ];
let result = {};
uniqueNames.forEach(personName => {
const personDataRows = testData.filter(row => row[columnIndexByName.PERSON_DOING_TASK] === personName);
let taskDurationsByTaskName = {};
uniqueTaskNames.forEach(taskName => {
const taskRows = personDataRows.filter(row => row[columnIndexByName.TASK_NAME] === taskName);
const taskDurations = taskRows.map(row => Number.parseFloat( row[columnIndexByName.TASK_DURATION] ));
const taskTotalDuration = taskDurations.reduce(sum, 0);
taskDurationsByTaskName[taskName] = taskTotalDuration;
})
result[personName] = taskDurationsByTaskName;
})
const renderData = data => document.querySelector("#output").innerHTML = JSON.stringify(data, null, 2);
renderData(result);
<pre id="output"></pre>

How to get all values of given specific keys (for e.g: name) without loop from json?

I want to fetch all the names and label from JSON without loop. Is there a way to fetch with any filter method?
"sections": [
{
"id": "62ee1779",
"name": "Drinks",
"items": [
{
"id": "1902b625",
"name": "Cold Brew",
"optionSets": [
{
"id": "45f2a845-c83b-49c2-90ae-a227dfb7c513",
"label": "Choose a size",
},
{
"id": "af171c34-4ca8-4374-82bf-a418396e375c",
"label": "Additional Toppings",
},
],
},
]
}

When you say "without loops" I take it as without For Loops. because any kind of traversal of arrays, let alone nested traversal, involve iterating.
You can use the reduce method to have it done for you internally and give you the format you need.
Try this :
const data = {
sections: [
{
id: "62ee1779",
name: "Drinks",
items: [
{
id: "1902b625",
name: "Cold Brew",
optionSets: [
{
id: "45f2a845-c83b-49c2-90ae-a227dfb7c513",
label: "Choose a size"
},
{
id: "af171c34-4ca8-4374-82bf-a418396e375c",
label: "Additional Toppings"
}
]
}
]
}
]
};
x = data.sections.reduce((acc, ele) => {
acc.push(ele.name);
otherName = ele.items.reduce((acc2, elem2) => {
acc2.push(elem2.name);
label = elem2.optionSets.reduce((acc3, elem3) => {
acc3.push(elem3.label);
return acc3;
}, []);
return acc2.concat(label);
}, []);
return acc.concat(otherName);
}, []);
console.log(x);
Go ahead and press run snippet to see if this matches your desired output.
For More on info reduce method

In the context of cJSON
yes, we can fetch the key value for any of the object.
1 - each key value is pointed by one of the objects. will simply fetch that object and from there will get the key value.
In the above case for
pre-requisition: root must contain the json format and root must be the cJSON pointer. if not we can define it and use cJSON_Parse() to parse the json.
1st name object is "sections" will use
cJSON *test = cJSON_GetObjectItem(root, "sections");
char *name1 = cJSON_GetObjectItem(test, "name" )->valuestring;
2nd name key value
cJSON *test2 = cJSON_GetObjectItem(test, "items");
char *name2 = cJSON_GetObjectItem(tes2, "name")->valuestring;
likewise, we can do for others as well to fetch the key value.

Fetch data from a nested array

I would like to know if there is a way to get the length from a nested array.
My data is a JSON file like this:
{
"data" :[
"item1" :'',
"item2" :[{
"id" :1,
"text":'text'
},{
"id" :2,
"text" : 'text
}]
]
}
I'm using angular 6 and ngx-restangular.
Is possible to get the item 2 length?

The main problem is the question does not provide a valid json. A valid json for the same would be like as under :
{
"data": {
"item1": "",
"item2": [{
"id": 1,
"text": "text"
},
{
"id": 2,
"text": "text"
}
]
}
}
Now you can fetch the second element size simply by
data["item2"].length
or
data.item2.length

To extend the Answer from #AurA
If you had to work with a valid array:
[
[ "item0.0", "item0.1" ],
[ "item1.0", "item1.1" ]
]
you could access the length of the nested arrays like this:
let a = [
["item0.0", "item0.1"],
["item1.0", "item1.1"]
];
let lengthA0 = a[0].length;
let lengthA1 = a[1].length;
console.log("length of a0: ", lengthA0);
console.log("length of a1: ", lengthA1);

Lodash: filter a nested object by multiple properties

Consider the following example:
var products = {
"Products": [{
"Title": "A",
"Categories": [{
"Name": "Type",
"Properties": ["Type 1", "Type 2", "Type 3"]
}, {
"Name": "Market",
"Properties": ["Market 1", "Market 2", "Market 3", "Market 4"]
}, {
"Name": "Technology",
"Properties": ["Tech 1", "Tech 2"]
}]
}, {
"Title": "B",
"Categories": [{
"Name": "Type",
"Properties": ["Type 1", "Type 3"]
}, {
"Name": "Market",
"Properties": "Market 1"
}, {
"Name": "Technology",
"Properties": ["Tech 1", "Tech 3"]
}]
}, {
"Title": "C",
"Categories": [{
"Name": "Type",
"Properties": ["Type 1", "Type 2", "Type 3"]
}, {
"Name": "Market",
"Properties": ["Market 2", "Market 3"]
}, {
"Name": "Technology",
"Properties": ["Tech 2", "Tech 3"]
}]
}]
}
I'm trying to filter products by their properties so consider I'm using an array to keep track of my selected filters:
var filters = ['Type 3', 'Tech 1'];
With these filters I would like to return product A and product B.
I currently have this:
var flattenedArray = _.chain(products).map('Categories').flatten().value();
var result= _.some(flattenedArray , ['Properties', 'Tech 1']);
But I'm stuck on how to combine the properties for a combined search.

Use _.filter() to iterate the products. For each product combine the list of properties using _.flatMap(), and use _.intersection() and _.size() to find the amount of filters that exist in the categories. Compare that to the original number of filters, and return comparison's response.
var products = {"Products":[{"Title":"A","Categories":[{"Name":"Type","Properties":["Type 1","Type 2","Type 3"]},{"Name":"Market","Properties":["Market 1","Market 2","Market 3","Market 4"]},{"Name":"Technology","Properties":["Tech 1","Tech 2"]}]},{"Title":"B","Categories":[{"Name":"Type","Properties":["Type 1","Type 3"]},{"Name":"Market","Properties":"Market 1"},{"Name":"Technology","Properties":["Tech 1","Tech 3"]}]},{"Title":"C","Categories":[{"Name":"Type","Properties":["Type 1","Type 2","Type 3"]},{"Name":"Market","Properties":["Market 2","Market 3"]},{"Name":"Technology","Properties":["Tech 2","Tech 3"]}]}]};
var filters = ['Type 3', 'Tech 1'];
var result = _.filter(products.Products, function(product) {
return filters.length === _(product.Categories)
.flatMap('Properties')
.intersection(filters)
.size();
});
console.log(result);
<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.2/lodash.min.js"></script>

If I understand you question correctly, this code may help:
_.filter(
products.Products,
product => _.difference(
filters,
_.chain(product.Categories).map(category => category.Properties).flatten().value()
).length === 0
);
It calculates a union of all properties for each product:
_.chain(product.Categories).map(category => category.Properties).flatten().value()
And then checks that it contains all filters array elements, using _.difference method.
Hope it helps.

another fancy way through _.conforms
var res = _.filter(
products.Products,
_.conforms({'Categories': function(categories) {
return _.chain(categories)
.flatMap('Properties') // flat arrays
.uniq() // remove dublicates
.keyBy() // transform to objects with Properties keys
.at(filters) // get objects values by filters
.compact() // remove undefineds
.size() // get size
.eq(filters.length) // compare to filters size
.value();
}
}))

This will work for a list of items where the givenProperty you want to filter on is either a string like 'doorColour' or an array of strings representing the path to the givenProperty like ['town', 'street', 'doorColour'] for a value nested on an item as town.street.doorColour.
It also can filter on more than one value so you could you just need pass in an array of substrings representing the string values you want to keep and it will retain items that have a string value which contains any substring in the substrings array.
The final parameter 'includes' ensures you retain these values if you set it to false it will exclude these values and retain the ones that do not have any of the values you specified in the substrings array
import { flatMap, path } from 'lodash/fp';
const filteredListForItemsIncludingSubstringsOnAGivenProperty = (items, givenProperty, substrings, including=true) => flatMap((item) =>
substrings.find((substring) => path(givenProperty)(item) && path(givenProperty)(item).includes(substring))
? including
? [item]
: []
: including
? []
: [item])(items);
E.g. fLFIISOAGP(contacts, ['person','name'], ['Joh','Pau',Pet']);
with items of structure {contact, business:null, personal:{name:'John'}}.
For the original question - this will also work - I would use this repeatedly on a list of items to filter with different keys to filter on more than one property.
const firstFilteredResult = filteredListForItemsIncludingSubstringsOnAGivenProperty(
products.Products,
["Categories", "0", "Properties"],
["Type 3"]);
const secondFilteredResult = filteredListForItemsIncludingSubstringsOnAGivenProperty(
firstFilteredResult,
["Categories", "2", "Properties"],
["Tech 1"]);
expect(secondFilteredResult[0]['Title']).to.equal( "A");
expect(secondFilteredResult[1]['Title']).to.equal( "B");
expect(secondFilteredResult.length).to.equal(2);