I have a form to submit and send data to 2 pages via POST.
I have tried the code with javascript. One form submit is working but other submit is not working
<form id="add">
<input type="text" name="test">
<input type="submit" onclick="return Submit();">
</form>
javascript
function SubmitForm()
{
document.forms['add'].action='filecreate.php';
document.forms['add'].submit();
document.forms['add'].action='filecreate.fr.php';
document.forms['add'].submit();
return true;
}
The first submission is not working but 2nd submission is working.
Since you appear to send the exact same data to two different handlers, you can flip the coin - and say that you just submit one form, and process them both in filecreate.php.
As you are sending a form, you cannot send two separate forms in the same HTTP request - so you can either do them both through asynchronous methods, or process them both backend after the submission of one form.
Since you haven't shown any PHP code, I'm making some assumptions and writing some pseudo-code, but it should be enough to get you started.
So first off, set a static action-property to your form.
<form id="add" action="filecreate.php">
<input type="text" name="test">
<input type="submit">
</form>
If you are sending it over POST, then you need to specify the method as well,
<form id="add" action="filecreate.php" method="POST">
Then, in PHP, you can get both files executed if you include it to the other. Meaning, in your filecreate.php, you include the filecreate.fr.php. Once you do that, the contents of that file will be executed as well.
<?php
// Once you require the file, it will be executed in place
require "filecreate.fr.php";
// .. handle the rest of your normal execution here.
That said, if you are doing the very similar thing multiple times, just with different data, you may want to create functions for it instead - going with the DRY principle ("Don't Repeat Yourself"), you can probably create a function that handles the structure and processing, then send the data separately through that function.
Try this :
<form id="add">
<input type="text" name="test">
<input type="button" onclick="return SubmitForm();">
</form>
function SubmitForm()
{
if(document.forms['add'].onsubmit())
{
document.forms['add'].action='filecreate.php';
document.forms['add'].submit();
document.forms['add'].action='filecreate.fr.php';
document.forms['add'].submit();
}
return true;
}
Related
I want to submit 2 forms from the same page with one button, so I tried to use the Javascript technic described in this post.
Here is my code:
send.php:
<form action="receive.php" method="post" id="form1">
<input type="text" value="2nd Form" name="q1" />
</form>
<form action="receive.php" method="post" id="form2">
<input type="text" value="3rd Form" name="q2" />
</form>
<input type="button" value="Click Me!" onclick="submitForms()" />
<script>
submitForms = function(){
document.getElementById("form1").submit();
document.getElementById("form2").submit();
}
</script>
receive.php:
echo $_POST['q1'];
echo $_POST['q2'];
But when it redirects to receive.php only the value of $_POST['q2'] appears, and not the value from the 1st input.
I can't see why is it so. Thank you.
Unfortunately I cannot setup an example because it's pretty long. But this is what is happening to me.
You move inside your code two submit requests, one after the other to the same PHP file, but with two different forms.
Supposing this is your PHP code:
echo $_POST['q1'];
echo $_POST['q2'];
When you actually make the first request, q1 gets printed. But immediately after you send the second submit, which "overrides" the first step and you see only the output of the second submit.
You can verify it in two ways:
1) Invert the order of the submits:
submitForms = function(){
document.getElementById("form2").submit();
document.getElementById("form1").submit();
}
and you should see only q1 printed.
2) Try adding a timeout to the second request, and you should see both the echo:
submitForms = function(){
document.getElementById("form1").submit();
setTimeout(function() {
document.getElementById("form2").submit(); }, 10000);
}
so after 10 seconds you should see the second output too.
So actually your requests do happen. If you log values to a file instead of the echo, you should see both the requests happening with your code.
Although this should be the reason to me, I strongly suggest you to change your logic. There is no obvious need to start ALWAYS two submit requests to the same PHP file.
Group the two forms and send just one request, maybe adding an input hidden field in order to detect which fields have been sent or which case are you in.
There is no need for two forms. Move "name="q2"" to first form.
Moreover, you are trying to call same form action. That is not appreciated.
I have two forms. I want to submit both forms with 1 button. Is there any method that can help me do it?
Example:
<form method="post" action="">
<input type="text" name="something">
</form>
<form method="post" action="">
<input type="text" name="something">
<input type="submit" value="submit" name="submit">
</form>
I want both forms to be submitted with 1 submit button. Any help would be appreciated.
The problem here is that when you submit a form, the current page is stopped. Any activity on the page is stopped. So, as soon as you click "submit" for a form or use JavaScript to submit the form, the page is history. You cannot continue to submit another page.
A simplistic solution is to keep the current page active by having the form's submission load in a new window or tab. When that happens, the current page remains active. So, you can easily have two forms, each opening in a window. This is done with the target attribute. Use something unique for each one:
<form action='' method='post' target='_blank1'>
The target is the window or tab to use. There shouldn't be one named "_blank1", so it will open in a new window. Now, you can use JavaScript to submit both forms. To do so, you need to give each a unique ID:
<form id='myform1' action='' method='post' target='_blank1'>
That is one form. The other needs another ID. You can make a submit button of type button (not submit) that fires off JavaScript on click:
<submit type='button' onclick="document.getElementById('myform1').submit();document.getElementById('myform2').submit();" value='Click to Submit Both Forms'>
When you click the button, JavaScript submits both forms. The results open in new windows. A bit annoying, but it does what you specifically asked for. I wouldn't do that at all. There are two better solutions.
The easiest is to make one form, not two:
<form action='' method='post'>
<input type='text' name='text1'>
<input type='text' name='text2'>
<input type='submit' value='Submit'>
</form>
You can place a lot of HTML between the form tags, so the input boxes don't need to be close together on the page.
The second, harder, solution is to use Ajax. The example is certainly more complicated than you are prepared to handle. So, I suggest simply using one form instead of two.
Note: After I submitted this, Nicholas D submitted an Ajax solution. If you simply cannot use one form, use his Ajax solution.
You have to do something like that :
button :
<div id="button1">
<button>My click text</button>
</div>
js
<script>
$('#button1').click(function(){
form1 = $('#idIFirstForm');
form2 = $('#idISecondForm');
$.ajax({
type: "POST",
url: form1.attr('action'),
data: form1.serialize(),
success: function( response ) {
console.log( response );
}
});
$.ajax({
type: "POST",
url: form2.attr('action'),
data: form2.serialize(),
success: function( response2 ) {
console.log( response2 );
}
});
});
</script>
You could create a pseudo form in the background. No time to write the code, jsut the theory. After clicking submit just stop propagation of all other events and gather all the informations you need into one other form you append to document (newly created via jquery) then you can submit the third form where all the necesary infos are.
Without getting into why you want to use only 1 button for 2 forms being submitted at the same time, these tools that will get the input data available for use elsewhere:
Option 1...
Instead of using <form> - collect the data with the usual Input syntax.
ex: <input type="text" name="dcity" placeholder="City" />
Instead of using the form as in this example:
<form class="contact" method="post" action="cheque.php" name="pp" id="pp">
<label for="invoice">Your Name</label>
<input type="text" id="invoice" name="invoice" />
<button class="button" type="submit" id="submit">Do It Now</button>
</form>
use:
<label for="invoice">Your Name</label>
<input type="text" id="invoice" name="invoice" />
<button type="button" onclick="CmpProc();" style="border:none;"><img src="yourimage.png"/> Do It Now</button>
Then code the function CmpProc() to handle the processing/submittion.
Inside that function use the Javascript form object with the submit() method as in...
<script type="text/javascript">
function submitform() {
document.xxxyourformname.submit();
}
</script>
Somehow I suspect making the two forms into one for the POST / GET is worth reconsidering.
Option 2...
Instead of POST to use the data to the next page consider using PHP's $_SESSION to store each of your entries for use across your multiple pages. (Remember to use the session_start(); at the start of each page you are storing or retrieving the variables from so the Global aspect is available on the page) Also less work.
Look man. This is not possible with only HTML. weither you gether the inputs in one form or else you use jquery to handle this for you.
First of all, let me start off by saying the product I am developing will be used by people that don't inherently have access to HTML5. Some of the individuals will still be using IE8. I have a form like the following:
<form action="ee.cfc?method=xlsupload" enctype="multipart/form-data" method="post"
<input type="file" id="xlsfile" name="xlsfile" required>
<input type="submit" value="Upload XLS">
</form>
and in my .cfc file I have a function that processes the file and translates it to a structure (which will then upload to a database after the user validates the data). Currently I have it set to <cfreturn SerializeJSON(dataset,true)>. However, when I submit the form it opens the cfc file and shows the JSON structure. I have done plenty of form submits, etc. in JQuery before, but is there a way to do this without JQuery? One would hope Coldfusion would have the capability to do this, (though of course I wouldn't be surprised if it didn't).
An asynchronously post is only useful if you want the user to interact with the webpage the form is on while in the background uploading the form. If this is what you want you should/can use jquery.
If synchronously is also an option. Then upload the form to a .cfm file, run the cfc on the .cfm document wait for the response of the component and then redirect the .cfm document using cflocation to a webpage that informs the visitor its upload has been processed. (use cflocation to prevent multiple submits).
e.g.
<form action="upload.cfm" enctype="multipart/form-data" method="post">
<input type="file" id="xlsfile" name="xlsfile" required>
<input type="submit" value="Upload XLS">
</form>
upload.cfm
<cfset yourComponent = createObject('component','/cfc/ee')>
<cfset response = yourComponent.functionName(form.xlsfile)>
<Cflocation url="done.cfm">
done.cfm
<html>....</html>
Hello and thank you for viewing my question. I am a complete beginner and am looking for simple ways to do the following...
What I have in seperate linked documents:
HTML, CSS, Javascript, PHP
What I am having trouble with:
I need to use something like JSON (although I would also accept XML requests or Ajax at this point if they work) to transfer variables from Javascript to PHP. I need the variables to search in a database, so they need to be literally available within PHP (not only seen on a pop-up message or something).
I have seen a LOT of different ways to do this, I have even watched tutorials on YouTube, but nothing has worked for me yet. The things I am having the biggest problem with is that when I add a submit button to my form it doesn't submit my form and I don't know why.
Form code snippet:
<form id="form" name="input" method="post" action="javascript:proofLength();">
<input id="userinput" type="text" autofocus />
<input id="submit" type="button" value="submit" onsubmit="post();">
</form>
The second to last line there doesn't work. Do I need javascript to submit the form? Because I really thought that in this case it was part of the functionality of the form just like method="post"...
The other thing is that for JSON, I have no idea what to do because my variables are determined by user input. Therefore, I cannot define them myself. They are only defined by document.getElement... and that doesn't fit the syntax of JSON.
Those are really my main problems at the moment. So if anyone could show me a simple way to get this variable transfer done, that would be amazing.
After this I will need to search/compare in my database with some php/sql (it's already connecting fine), and I need to be able to return information back to a in HTML based on what I find to be true. I saw one example, but I am not sure that was very applicable to what I am doing, so if you are able to explain how to do that, that would be great also.
Thank you very, very much.
April
You don't need ajax to submit this form. You don't even need javscript. Just do this:
<form id="form" name="input" method="post" action="mytarget.php">
<input id="userinput" name="userinput" type="text" autofocus />
<input id="submit" type="submit" value="submit" />
</form>
This will send the form data to mytarget.php (can be changed of course)
See that i have added the name attribute to your text-field in the form and i changed the type of the button to submit.
Now you can work the Data in mytarget.php like this:
<?
$username = $_POST['userinput'];
echo "Your name is: ".$username;
?>
You wanted to have a check for length in the submit. There are two ways to this:
Before the input is send (the server is not bothered)
Let the server Check the input
for 1 you will have to append a event listener, like this:
var form = document.getElementById("form");
form.addEventListener("submit", function(event){
console.log("test");
var name = form.elements['userinput'].value;
if(name.length < 3){
alert("boy your name is short!");
event.preventDefault();
}
});
Enter a name with less then 3 characters and the form will not be submitted. test here: http://jsfiddle.net/NicoO/c47cr/
Test it Serverside
In your mytarget.php:
<?
$username = $_POST['userinput'];
if(strlen($username) > 3)
echo "Your name is: ".$username;
else
echo "your name was too short!";
?>
You may also do all this with ajax. You will find a lot of good content here. But I'd recommend a framework like jQuery to do so.
The problem is in this line
<form id="form" name="input" method="post" action="javascript:proofLength();">
The action should be a PHP page (or any other type of server script) that will process the form.
Or the proofLength function must call submit() on the form
In the php page you can obtain variable values using $_GET["name"] or $_POST["name"]
To summarize; your code should look like this
<form id="form" name="input" method="post" action="yourpage.php">
<input id="userinput" type="text" autofocus />
<input id="submit" type="button" value="submit">
</form>
and for your php page:
<?php
$userinput = $_POST["userinput"];
//Do what ever you need here
?>
If you want to do something in your javascript before submitting the form, refer to this answer
I'm struggling a little to understand the server-side of things using Coldfusion8 and thus far doing client-side stuff only.
Say I have a basic Coldfusion page layout like this:
<script type="text/javascript">
function foo() { docoument.myForm.submit(); }
</script>
<cfif isdefined("sendMyForm")>
... running coldfusion...
... displaying something...
</cfelse>
<form action="nextPage.html" method="post" name="myForm">
<input type="text" name="formContains" />
<input type="hidden" name="sendMyForm" value="yup" />
<input type="button" name="sender" value="send" OnClick="foo() />
</form>
</cfif>
Question:
What actually happens server-side when I submit the form? Is the page getting "re-loaded" and the cfif causes coldfusion to run and display results? Just looking for some basic info so I understand what's happening.
Thanks for hints!
Think of CF and most web servers/systems as accepting input (url/get, form/post, cookie, etc) and returning output (html, json, text, etc). That cycle generally repeats. Someone types in a web address in a browser, request goes to server, page returned with form. User hits submit, request goes to server, page returned with results. User clicks link, request goes to server...and on and on.
You need to have the form action submit back to itself due to the way the if statements are organized. If in form.cfm file then action should be form.cfm. Unless you setup specific mappings in the webserver to have CF handle html files then the file will need to be .cfm
You mention leaving the action attribute out all together submits the form back to the same page but I don't believe this works in every browser.
It is also more common/safer to have form method="post", then check for structkeyexists(form, "fieldname")
Ok. Not the latest links, but valuable information.
http://www.tek-tips.com/viewthread.cfm?qid=523839l
http://cookbooks.adobe.com/post_Email_contact_form_in_ColdFusion-16882.html
I was trying to understand how form submits work in Coldfusion. If the page structure is:
<cf "inputName" = "someValue">
... run the from logic
</cfif>
<cfoutput>
<form>
<input name="inputName" />
... more form
</form>
</cfoutput>
So when I submit the form without action, it gets submitted to the page it's on and therefore the first CF-part can run....