I am trying to build a tree recursively from an array of objects. I am currently using the reduce() method to iterate through the items in the array and figure out which children belong to a particular item and populating it, then recursively populating the children of those children and so on. However, I have been unable to take the last nodes(e.g persian and siamese in this case) and put them in array(see expected and current output below)
let categories = [
{ id: 'animals', parent: null },
{ id: 'mammals', parent: 'animals' },
{ id: 'cats', parent: 'mammals' },
{ id: 'dogs', parent: 'mammals' },
{ id: 'chihuahua', parent: 'dogs' },
{ id: 'labrador', parent: 'dogs' },
{ id: 'persian', parent: 'cats' },
{ id: 'siamese', parent: 'cats' }
];
const reduceTree = (categories, parent = null) =>
categories.reduce(
(tree, currentItem) => {
if(currentItem.parent == parent){
tree[currentItem.id] = reduceTree(categories, currentItem.id);
}
return tree;
},
{}
)
console.log(JSON.stringify(reduceTree(categories), null, 1));
expected output:
{
"animals": {
"mammals": {
"cats": [ // <-- an array of cat strings
"persian",
"siamese"
],
"dogs": [ // <-- an array of dog strings
"chihuahua",
"labrador"
]
}
}
}
current output:
{
"animals": {
"mammals": {
"cats": { // <-- an object with cat keys
"persian": {},
"siamese": {}
},
"dogs": { // <-- an object with dog keys
"chihuahua": {},
"labrador": {}
}
}
}
}
How should I go about solving the problem?
I put a condition to merge the result as an array if a node has no child. Try this
let categories = [
{ id: 'animals', parent: null },
{ id: 'mammals', parent: 'animals' },
{ id: 'cats', parent: 'mammals' },
{ id: 'dogs', parent: 'mammals' },
{ id: 'chihuahua', parent: 'dogs' },
{ id: 'labrador', parent: 'dogs' },
{ id: 'persian', parent: 'cats' },
{ id: 'siamese', parent: 'cats' }
];
const reduceTree = (categories, parent = null) =>
categories.reduce(
(tree, currentItem) => {
if(currentItem.parent == parent){
let val = reduceTree(categories, currentItem.id);
if( Object.keys(val).length == 0){
Object.keys(tree).length == 0 ? tree = [currentItem.id] : tree.push(currentItem.id);
}
else{
tree[currentItem.id] = val;
}
}
return tree;
},
{}
)
console.log(JSON.stringify(reduceTree(categories), null, 1));
NOTE: if your data structure changes again this parser might fail for some other scenarios.
Here is a solution without recursion:
const categories = [{ id: 'animals', parent: null },{ id: 'mammals', parent: 'animals' },{ id: 'cats', parent: 'mammals' },{ id: 'dogs', parent: 'mammals' },{ id: 'chihuahua', parent: 'dogs' },{ id: 'labrador', parent: 'dogs' },{ id: 'persian', parent: 'cats' },{ id: 'siamese', parent: 'cats' }];
// Create properties for the parents (their values are empty objects)
let res = Object.fromEntries(categories.map(({parent}) => [parent, {}]));
// Overwrite the properties for the parents of leaves to become arrays
categories.forEach(({id, parent}) => res[id] || (res[parent] = []));
// assign children to parent property, either as property of parent object or as array entry in it
categories.forEach(({id, parent}) => res[parent][res[id] ? id : res[parent].length] = res[id] || id);
// Extract the tree for the null-entry:
res = res.null;
console.log(res);
Related
I'm trying to convert my data from API to my needs. Would like to create a nested array from plain array. I would like to group elements by parentId property, if parentId would not exist I would put it as a root. id value is unique. Like so (raw data):
[
{id: 1, name: 'sensor'},
{id: 2, name: 'sensor', parent: 1},
{id: 3, name: 'sensor', parent: 1},
{id: 4, name: 'sensor', parent: 3},
{id: 5, name: 'sensor'},
{id: 6, name: 'sensor', parent: 5}
]
Converted Data:
const results = [
{
id: 1,
name: "sensor",
children: [
{ id: 2, name: "sensor", parent: 1 },
{
id: 3,
name: "sensor",
parent: 1,
children: [{ id: 4, name: "sensor", parent: 3 }]
}
]
},
{ id: 5, name: "sensor", children: [{ id: 6, name: "sensor", parent: 5 }] }
];
I found this recursive method but it assumes that the parent property exist for every element in an array. In my example root level element would not have parent property.
function getNestedChildren(arr, parent) {
var out = []
for(var i in arr) {
if(arr[i].parent == parent) {
var children = getNestedChildren(arr, arr[i].id)
if(children.length) {
arr[i].children = children
}
out.push(arr[i])
}
}
return out
}
You could take an approach which uses both relations, one from children to parent and vice versa. At the end take the children of the root node.
This approach works for unsorted data.
var data = [{ id: 1, name: 'sensor' }, { id: 2, name: 'sensor', parent: 1 }, { id: 3, name: 'sensor', parent: 1 }, { id: 4, name: 'sensor', parent: 3 }, { id: 5, name: 'sensor' }, { id: 6, name: 'sensor', parent: 5 }],
tree = function (data, root) {
var t = {};
data.forEach(o => {
Object.assign(t[o.id] = t[o.id] || {}, o);
t[o.parent] = t[o.parent] || {};
t[o.parent].children = t[o.parent].children || [];
t[o.parent].children.push(t[o.id]);
});
return t[root].children;
}(data, undefined);
console.log(tree);
.as-console-wrapper { max-height: 100% !important; top: 0; }
Given the limited amount of information (will update if more info is added).
The algorithm would be, given an array of data entries, check if entry has a parent and if that parent exists, in which case we want to add the entry to the array of children of the parent entry otherwise add the entry as a parent.
var dataFromAPI = [
{id: 1, name: 'sensor'},
{id: 2, name: 'sensor', parent: 1},
{id: 3, name: 'sensor', parent: 1},
{id: 4, name: 'sensor', parent: 3},
{id: 5, name: 'sensor'},
{id: 6, name: 'sensor', parent: 5}
];
var transformedData = { };
dataFromAPI.forEach(function(entry){
if(entry.parent !== undefined && entry.parent in transformedData) {
transformedData[entry.parent].children.push(entry);
} else {
entry["children"] = [];
transformedData[entry.id] = entry;
}
});
console.log(transformedData);
Please note:
there are a couple assumptions made within this algorithm/code. It assumes that all parent entries exist before their child entry. It also only accounts for two levels (parent or child), meaning a child cannot act as the parent (otherwise you'd have to store the children as an object and not an array)
use a for loop to go through each item.
check if parent property exists (or has value).
If not its a child item. Attach it to appropriate parent.
to check if property exists:
var myProp = 'prop';
if (myObj.hasOwnProperty(myProp)) {
alert("yes, i have that property");
}
try
let h={}, r=[]; // result in r
d.forEach(x=> (h[x.id]=x, x.children=[]) );
d.forEach(x=> x.parent ? h[x.parent].children.push(x) : r.push(x) );
let d = [
{id: 1, name: 'sensor'},
{id: 2, name: 'sensor', parent: 1},
{id: 3, name: 'sensor', parent: 1},
{id: 4, name: 'sensor', parent: 3},
{id: 5, name: 'sensor'},
{id: 6, name: 'sensor', parent: 5}
];
let h = {},r = []; // result in r
d.forEach(x => (h[x.id] = x, x.children = []));
d.forEach(x => x.parent ? h[x.parent].children.push(x) : r.push(x));
console.log(r);
If you want that parent element should not have a parent , than you can manually check and remove fields of an object in an array that has null parent. than you can make a tree... here is an example...
const arr2 = [
{id: 1, name: 'gender', parent: null, parent_id: null },
{id: 2, name: 'material', parent: null, parent_id: null },
{id: 3, name: 'male', parent: 1, parent_name: "gender" },
{ id: 5, name: 'female', parent: 1, parent_name: "gender" },
{ id: 4, name: 'shoe', parent: 3, parent_id: "male"},
]
let newarr=[];
for(let i=0 ; i< arr2.length; i++ ){
if(arr2[i].id){
if(newarr[i] != {} ){
newarr[i] = {}
}
newarr[i].id = arr2[i].id
}
if( arr2[i].name ){
newarr[i].name = arr2[i].name
}
if( arr2[i].parent ){
newarr[i].parent = arr2[i].parent
}
if( arr2[i].parent_id ){
newarr[i].parent_id = arr2[i].parent_id
}
}
console.log('newarr', newarr );
let tree = function (data, root) {
var obj = {};
data.forEach(i => {
Object.assign(obj[i.id] = obj[i.id] || {}, i);
obj[i.parent] = obj[i.parent] || {};
obj[i.parent].children = obj[i.parent].children || [];
obj[i.parent].children.push(obj[i.id]);
});
return obj[root].children;
}(newarr, undefined);
console.log('tree ', tree);
I have a data tree structure with children:
{ id: 1,
name: "Dog",
parent_id: null,
children: [
{
id: 2,
name: "Food",
parent_id: 1,
children: []
},
{
id: 3,
name: "Water",
parent_id: 1,
children: [
{
id: 4,
name: "Bowl",
parent_id: 3,
children: []
},
{
id: 5,
name: "Oxygen",
parent_id: 3,
children: []
},
{
id: 6,
name: "Hydrogen",
parent_id: 3,
children: []
}
]
}
]
}
This represents a DOM structure that a user could select an item from to delete by clicking the corresponding button in the DOM.
I have a known text title of the selected item for deletion from the DOM set as the variable clickedTitle. I am having trouble finding an algorithm that will allow me to delete the correct object data from the deeply nested tree.
Here is my code:
function askUserForDeleteConfirmation(e) {
const okToDelete = confirm( 'Are you sure you want to delete the item and all of its sub items?' );
if(!okToDelete) {
return;
}
const tree = getTree(); // returns the above data structure
const clickedTitle = getClickedTitle(e); // returns string title of clicked on item from DOM - for example "Dog" or "Bowl"
const updatedTree = removeFromTree(tree, tree, clickedTitle);
return updatedTree;
}
function removeFromTree(curNode, newTree, clickedTitle) {
if(curNode.name === clickedTitle) {
// this correctly finds the matched data item to delete but the next lines don't properly delete it... what to do?
const index = curNode.children.findIndex(child => child.name === clickedTitle);
newTree = curNode.children.slice(index, index + 1);
// TODO - what to do here?
}
for(const node of curNode.children) {
removeFromTree(node, newTree, clickedTitle);
}
return newTree;
}
I have tried to use the info from Removing matched object from array of objects using javascript without success.
If you don't mind modifying the parameter tree in-place, this should do the job. Note that it'll return null if you attempt to remove the root.
const tree = { id: 1, name: "Dog", parent_id: null, children: [ { id: 2, name: "Food", parent_id: 1, children: [] }, { id: 3, name: "Water", parent_id: 1, children: [ { id: 4, name: "Bowl", parent_id: 3, children: [] }, { id: 5, name: "Oxygen", parent_id: 3, children: [] }, { id: 6, name: "Hydrogen", parent_id: 3, children: [] } ] } ] };
const removeFromTree = (root, nameToDelete, parent, idx) => {
if (root.name === nameToDelete) {
if (parent) {
parent.children.splice(idx, 1);
}
else return null;
}
for (const [i, e] of root.children.entries()) {
removeFromTree(e, nameToDelete, root, i);
}
return tree;
};
console.log(removeFromTree(tree, "Oxygen"));
Your current code is very much on the right track. However:
newTree = curNode.children.slice(index, index + 1);
highlights a few issues: we need to manipulate the parent's children array to remove curNode instead of curNode's own children array. I pass parent objects and the child index recursively through the calls, saving the trouble of the linear operation findIndex.
Additionally, slicing from index to index + 1 only extracts one element and doesn't modify curNode.children. It's not obvious how to go about using newArray or returning it through the call stack. splice seems like a more appropriate tool for the task at hand: extracting one element in-place.
Note that this function will delete multiple entries matching nameToDelete.
I like #VictorNascimento's answer, but by applying map then filter, each children list would be iterated twice. Here is an alternative with reduce to avoid that:
function removeFromTree(node, name) {
return node.name == name
? undefined
: {
...node,
children: node.children.reduce(
(children, child) => children.concat(removeFromTree (child, name) || []), [])
}
}
In the case you want a way to remove the items in-place, as #ggorlen proposed, I'd recommend the following solution, that is simpler in my opinion:
function removeFromTree(node, name) {
if (node.name == name) {
node = undefined
} else {
node.children.forEach((child, id) => {
if (!removeFromTree(child, name)) node.children.splice(id, 1)
})
}
return node
}
I've built the algorithm as follows:
function omitNodeWithName(tree, name) {
if (tree.name === name) return undefined;
const children = tree.children.map(child => omitNodeWithName(child, name))
.filter(node => !!node);
return {
...tree,
children
}
}
You can use it to return a new tree without the item:
noHydrogen = omitNodeWithName(tree, "Hydrogen")
If it's ok to use Lodash+Deepdash, then:
let cleaned = _.filterDeep([tree],(item)=>item.name!='Hydrogen',{tree:true});
Here is a Codepen
We use object-scan for many data processing tasks. It's powerful once you wrap your head around it. Here is how you could answer your question
// const objectScan = require('object-scan');
const prune = (name, input) => objectScan(['**[*]'], {
rtn: 'bool',
abort: true,
filterFn: ({ value, parent, property }) => {
if (value.name === name) {
parent.splice(property, 1);
return true;
}
return false;
}
})(input);
const obj = { id: 1, name: 'Dog', parent_id: null, children: [{ id: 2, name: 'Food', parent_id: 1, children: [] }, { id: 3, name: 'Water', parent_id: 1, children: [{ id: 4, name: 'Bowl', parent_id: 3, children: [] }, { id: 5, name: 'Oxygen', parent_id: 3, children: [] }, { id: 6, name: 'Hydrogen', parent_id: 3, children: [] }] }] };
console.log(prune('Oxygen', obj)); // return true iff pruned
// => true
console.log(obj);
// => { id: 1, name: 'Dog', parent_id: null, children: [ { id: 2, name: 'Food', parent_id: 1, children: [] }, { id: 3, name: 'Water', parent_id: 1, children: [ { id: 4, name: 'Bowl', parent_id: 3, children: [] }, { id: 6, name: 'Hydrogen', parent_id: 3, children: [] } ] } ] }
.as-console-wrapper {max-height: 100% !important; top: 0}
<script src="https://bundle.run/object-scan#13.8.0"></script>
Disclaimer: I'm the author of object-scan
const item = {
id: 'item1',
children: [
{ id: 'item1-1',
children: [
{ id: 'item1-1-1' },
{ id: 'item1-1-2' },
{ id: 'item1-1-3' },
]
},
{ id: 'item1-2',
children: [
{ id: 'item1-2-1' }
]
}
]
}
Like this,
function getLevelOfId(){
...
}
getLevelOfId('item1') =====> return 1
getLevelOfId('item1-2') =====> return 2
getLevelOfId('item1-1-1') =====> return 3
getLevelOfId('item1-1-2') =====> return 3
How to get specific object's depth with JavaScript?
Not use of id string. like ('item1-2').split('-').length Because each object has randomic id. Is there a simple way?
You need to iterate all objects and if found, take one for each level for the recursion depth.
function getLevelOfId(object, id) {
var level;
if (object.id === id) return 1;
object.children && object.children.some(o => level = getLevelOfId(o, id));
return level && level + 1;
}
const item = { id: 'item1', children: [{ id: 'item1-1', children: [{ id: 'item1-1-1' }, { id: 'item1-1-2' }, { id: 'item1-1-3' }] }, { id: 'item1-2', children: [{ id: 'item1-2-1' }] }] };
console.log(getLevelOfId(item, 'item1')); // 1
console.log(getLevelOfId(item, 'item1-2')); // 2
console.log(getLevelOfId(item, 'item1-1-1')); // 3
console.log(getLevelOfId(item, 'item1-1-2')); // 3
console.log(getLevelOfId(item, 'foo')); // undefined
if the structure id & children is fixed, how about search the whole value like "item1-1-1" in the json string:
{"id":"item1","children":[{"id":"item1-1","children":[{"id":"item1-1-1"},{"id":"item1-1-2"},{"id":"item1-1-3"}]},{"id":"item1-2","children":[{"id":"item1-2-1"}]}]}
level = (number of "{") - (number of "}") // before the searched positon of the string
I'm a learner developer, and I'm build a app with a tree menu(react + redux + sagas), but I'm getting some errors of Mutation State, I saw what best practices is stay de state flat as possible, but I didn't finded one menu tree what work with a flat state, so my data is look this:
menuTree: [{
id: 'id-root',
name: 'root',
toggled: true,
children: [
{
id: 'id-parent1',
name: 'parent1',
toggled: true,
children: [
{
id: '123',
name: 'parent1_child1'
},
{
id: '234',
name: 'parent1_child2'
}
]
},
{
id: 'id-loading-parent',
name: 'loading parent',
loading: true,
children: []
},
{
id: 'id-parent2',
name: 'parent2',
toggled: true,
children: [
{
id: 'parent2_children1',
name: 'nested parent2',
children: [
{
id: '345',
name: 'parent2 child 1 nested child 1'
},
{
id: '456',
name: 'parent2 child 1 nested child 2'
}
]
}
]
}
]
}],
And my redux action:
case types.SOLUTION__MENUCURSOR__SET:
// console.log('action payload', action.payload);
// console.log('state', state);
const cursor = action.payload.cursor;
// console.log('set menu cursor action', cursor);
return {
...state,
menuTree: state.menuTree.map(
function buscaIdMenuTree(currentValue, index, arr){
if(currentValue.id){
if(currentValue.id.includes(cursor.id)){
currentValue.toggled = action.payload.toggled;
return arr;
}else{
if(currentValue.children)
{
currentValue.children.forEach(function(currentValue, index, arr){
return buscaIdMenuTree(currentValue, index, arr);
});
}
}
return arr;
}
}
)[0]
};
The code works but I get Mutation State Error, so someone can help me to fix it ?
You can rebuild your menu as a plain list:
let menuTree = [{
id: 'id-root',
name: 'root',
toggled: true,
parent: null
},{
id: 'id-parent1',
name: 'parent1',
toggled: true,
parent: 'id-root'
},{
id: '123',
name: 'parent1_child1',
parent: 'id-parent1'
},{
id: '234',
name: 'parent1_child1',
parent: 'id-parent1'
},
{
id: 'id-loading-parent',
name: 'loading parent',
loading: true,
parent: 'id-root'
},{
id: 'id-parent2',
name: 'parent2',
toggled: true,
parent: 'id-root'
},{
id: 'parent2_children1',
name: 'nested parent2',
parent: 'id-parent2'
},{
id: '345',
name: 'parent2 child 1 nested child 1',
parent: 'parent2_children1'
},
{
id: '456',
name: 'parent2 child 1 nested child 2',
parent: 'parent2_children1'
}]
then if your menu renderer require a tree you can convert the list to a tree so inside the component renderer this.menuTree will be a tree:
const buildTree = (tree, cParent = null) => {
return tree.filter(cNode => cNode.parent == cParent).reduce((curr, next) => {
let cNode = {...next, children: buildTree(tree, next.id)}
delete cNode.parent
return [...curr, cNode]
}, [])
}
function mapStateToProps(state) {
return {
mapTree: builTree(state.mapTree)
};
}
export default connect(mapStateToProps)(YourComponent);
Inside the mutation now you just need to create a list of node that needs to be toggled and then map the state accordingly
case types.SOLUTION__MENUCURSOR__SET:
// console.log('action payload', action.payload);
// console.log('state', state);
const cursor = action.payload.cursor;
// console.log('set menu cursor action', cursor);
const getToggleList = (tree, cursor) => {
let target = tree.find(cNode => cNode.id == cursor.id)
if(target.parent != null){
let parent = tree.find(cNode => cNode.id == target.parent)
return [target.parent, ...getToggleList(tree, parent)]
}else{
return []
}
}
let toggleList = [cursor.id, ...getToggleList(state.menuTree, cursor.id)]
return {
...state,
menuTree: state.menuTree.map(node => ({...node, toggle: toggleList.includes(node.id)}))
};
Below are the three arrays, I want to merge them using a mergelist function.
I am new to javascript, Please help me with this.
var list1 = [
{name: 'Parent'},
{name: 'child1', parent: ‘parent’},
{name: 'child2', parent: ‘parent’},
{name: 'child21', parent: 'child2'}
];
var list2 = [
{name: 'child1'},
{name: 'child11', parent: 'child1'},
{name: 'child12', parent: 'child1'}
];
var list3 = [
{name: 'child2'},
{name: 'child22', parent: 'child2'},
{name: 'child23', parent: 'child2'}
];
Implement a function that merges of all of the trees in the array into one combined tree.
Please help me with the code. Thank you
I have tried with this code but I only was able to do it for 2 trees and not exactly what I want.
var list1 = [
{
Parent: 'parent',
children: [
{
parent: 'child1',
children: []
},
{
parent: 'child2',
children: [
{
parent:'child21',
children :[]
}]
}]
}
];
var list2 = [
{
parent: 'child1',
children: [
{
parent: 'child11',
children: []
},
{
parent: 'child12',
children: []
}]
}
];
var list3 = [
{
parent: 'child2',
children: [
{
parent: 'child22',
children: []
},
{
parent: 'child23',
children: []
}]
}
]
var addNode = function(nodeId, array) {
array.push({parent: nodeId, children: []});
};
var placeNodeInTree = function(nodeId, parent, treeList) {
return treeList.some(function(currentNode){
// If currentNode has the same id as the node we want to insert, good! Required for root nodes.
if(currentNode.parent === nodeId) {
return true;
}
// Is currentNode the parent of the node we want to insert?
if(currentNode.parent === parent) {
// If the element does not exist as child of currentNode, create it
if(!currentNode.children.some(function(currentChild) {
return currentChild.parent === nodeId;
})) addNode(nodeId, currentNode.children);
return true;
} else {
// Continue looking further down the tree
return placeNodeInTree(nodeId, parent, currentNode.children);
}
});
};
var mergeInto = function(tree, mergeTarget, parentId) {
parentId = parentId || undefined;
tree.forEach(function(node) {
// If parent has not been found, placeNodeInTree() returns false --> insert as root element
if(!placeNodeInTree(node.parent, parentId, mergeTarget)){
list1.push({parent: node.parent, children:[]});
}
mergeInto(node.children, mergeTarget, node.parent);
});
};
mergeInto(list2, list1);
document.write('<pre>');
document.write(JSON.stringify(list1, null, 4));
console.log(list1);
document.write('</pre>');
It looks like an easy problem, but the data source is misleading with duplicate items sometimes with parent property and sometimes without.
The first part is to clean the data and build a flat array with single name and if possible with parent. The data is stored in data. The first output is this result.
The second part is to build a tree with the data. For every object, a node for name is build and for every given parent a node is created, if it is not already there.
var list1 = [{ name: 'parent' }, { name: 'child1', parent: 'parent' }, { name: 'child2', parent: 'parent' }, { name: 'child21', parent: 'child2' }],
list2 = [{ name: 'child1' }, { name: 'child11', parent: 'child1' }, { name: 'child12', parent: 'child1' }],
list3 = [{ name: 'child2' }, { name: 'child22', parent: 'child2' }, { name: 'child23', parent: 'child2' }],
data = function (data) {
var o = {}, r = [];
data.forEach(function (a) {
if (!o[a.name]) {
r.push(a);
o[a.name] = a;
return;
}
if (!(parent in o[a.name])) {
o[a.name] = a;
}
});
return r;
}([].concat(list1, list2, list3)),
tree = function (data) {
var r, o = {};
document.write('<pre>data: ' + JSON.stringify(data, 0, 4) + '</pre>');
data.forEach(function (a, i) {
a.children = o[a.name] && o[a.name].children;
o[a.name] = a;
if (a.parent === undefined) {
r = a;
return;
}
o[a.parent] = o[a.parent] || {};
o[a.parent].children = o[a.parent].children || [];
o[a.parent].children.push(a);
});
return r;
}(data);
document.write('<pre>tree: ' + JSON.stringify(tree, 0, 4) + '</pre>');