I have a string want those product hubs vendor matched properly with their respective position and digit between them must digit but.digits can vary in numbers.
pattern: /products/8236/hubs/1/vendor
url="https://d3skctyxg9sfpd.cloudfront.net/sadassdsad/products/8236/hubs/1/vendor"
this.tests = "products/8236/hubs/1/vendor";
var fields = this.tests.split('_qa_current');
console.log(fields, "fielding values fetched");
/products/.test(fields);
console.log(/products/.test(this.tests), "url getting");
/^products\[0-9]\\hubs\[0-9]\\vendors$/.test(fields[1]);
This should be your regex
^\/products\/\d+\/hubs\/\d+\/vendor$
The slashes are not escaped correctly in your regex.
Code
this.tests = "https://d3skctyxg9sfpd.cloudfront.net/milkbasket_qa_current/products/8236/hubs/1/vendor";
var fields = this.tests.split('_qa_current');
console.log(fields, "fielding values fetched");
/products/.test(fields);
console.log(/products/.test(this.tests), "url getting");
/^\/products\/\d+\/hubs\/\d+\/vendor$/.test(fields[1]);
Regex: /-\/products\/\d+\/hubs\/\d+\/vendor/g
You can replace the digit with the \d+ meaning there can be one or more numbers in this place.
Here's the website to try the pattern and see for yourself: https://regexr.com/.
There are also explanations on the bottom of the screen to help you understand better what the rules do.
Related
I currently have the following string :
AAAAA/BBBBB/1565079415419-1564416946615-file-test.dsv
But I would like to split it to only get the following result (removing all tree directories + removing timestamp before the file):
1564416946615-file-test.dsv
I currently have the following code, but it's not working when the filename itselfs contains a '-' like in the example.
getFilename(str){
return(str.split('\\').pop().split('/').pop().split('-')[1]);
}
I don't want to use a loop for performances considerations (I may have lots of files to work with...) So it there an other solution (maybe regex ?)
We can try doing a regex replacement with the following pattern:
.*\/\d+-\b
Replacing the match with empty string should leave you with the result you want.
var filename = "AAAAA/BBBBB/1565079415419-1564416946615-file-test.dsv";
var output = filename.replace(/.*\/\d+-\b/, "");
console.log(output);
The pattern works by using .*/ to first consume everything up, and including, the final path separator. Then, \d+- consumes the timestamp as well as the dash that follows, leaving only the portion you want.
You may use this regex and get captured group #1:
/[^\/-]+-(.+)$/
RegEx Demo
RegEx Details:
[^\/-]+: Match any character that is not / and not -
-: Match literal -
(.+): Match 1+ of any characters
$: End
Code:
var filename = "AAAAA/BBBBB/1565079415419-1564416946615-file-test.dsv";
var m = filename.match(/[^\/-]+-(.+)$/);
console.log(m[1]);
//=> 1564416946615-file-test.dsv
How can I use regex in javascript to match the phone number and only the phone number in the sample string below? The way I have it written below matches "PHONE=9878906756", I need it to only match "9878906756". I think this should be relatively simple, but I've tried putting negating like characters around "PHONE=" with no luck. I can get the phone number in its own group, but that doesn't help when assigning to the javascript var, which only cares what matches.
REGEX:
/PHONE=([^,]*)/g
DATA:
3={STATE=, SSN=, STREET2=, STREET1=, PHONE=9878906756,
MIDDLENAME=, FIRSTNAME=Dexter, POSTALCODE=, DATEOFBIRTH=19650802,
GENDER=0, CITY=, LASTNAME=Morgan
The way you're doing it is right, you just have to get the value of the capture group rather than the value of the whole match:
var result = str.match(/PHONE=([^,]*)/); // Or result = /PHONE=([^,]*)/.exec(str);
if (result) {
console.log(result[1]); // "9878906756"
}
In the array you get back from match, the first entry is the whole match, and then there are additional entries for each capture group.
You also don't need the g flag.
Just use dataAfterRegex.substring(6) to take out the first 6 characters (i.e.: the PHONE= part).
Try
var str = "3={STATE=, SSN=, STREET2=, STREET1=, PHONE=9878906756, MIDDLENAME=, FIRSTNAME=Dexter, POSTALCODE=, DATEOFBIRTH=19650802, GENDER=0, CITY=, LASTNAME=Morgan";
var ph = str.match(/PHONE\=\d+/)[0].slice(-10);
console.log(ph);
I need help with a regex to select this entire string
%2526_ga%253d1.193373933.1506621463.1391436765&
this exact match is always there:
%2526_ga%253d
there's always a random number like this, but don't focus on the period since there's other periods later in the URL similar to this:
1.193373933.1506621463.1391436765&
This is what I have so far:
var str = window.location.search.match('_ga%253d');
alert(str);
If you want your prefix plus any digits full stops until the first etcetera the regex below should do
/_ga%253d'([0-9\.])+&/
I need to allow only numerics, dot and comma in a text field. If the user enters other special characters an alert needs to be thrown.
Please find below the conditions:
The text field should contain atleast one numeric value.
It is not mandatory that the text field should contain dot and comma always.
Thanks for your help.
Here is a start for you: http://jsfiddle.net/KLyy8/1/
Unless you tell us the exact specifics we won't know how to write the regular expression. Sounds like you want numbers with thousands separator and decimals. But how many of each? The fiddle above will work for numbers like this...
123,456.79
12,345.6
1,234.56
etc...
validate=function(){
var str = document.getElementById('test').value;
var patt = new RegExp("^[0-9]{1,3}\,[0-9]{3}\.[0-9]{1,2}$");
var res = patt.test(str);
alert(res);
}
If the field should contain only numeric values with decimal places (for exmaple 3.14, 112358 or 9,81), then you can use only one regex:
function validateString(str){
if(str.match(^[0-9\.,]+$)){
return true;
}else{
return false;
}
However if you want to be precise you will probably want to limit the dots and commas to one, if I understand your situation correctly.
Regex for that can look like this
^[0-9]+(\.|,){0,1}[0-9]+$
That means it starts with a number (^[0-9]+), then it may contain zero or one times one comma or dot ((\.|,){0,1}) and then again ends with a number ([0-9]+$).
What is the best way to capture everything except when faced with two or more new lines?
ex:
name1
address1
zipcode
name2
address2
zipcode
name3
address3
zipcode
One regex I considered was /[^\n\n]*\s*/g. But this stops when it is faced with a single \n character.
Another way I considered was /((?:.*(?=\n\n)))\s*/g. But this seems to only capture the last line ignoring the previous lines.
What is the best way to handle similar situation?
UPDATE
You can consider replacing the variable length separator with some known fixed length string not appearing in your processed text and then split. For instance:
> var s = "Hi\n\n\nBye\nCiao";
> var x = s.replace(/\n{2,}/, "#");
> x.split("#");
["Hi", "Bye
Ciao"]
I think it is an elegant solution. You could also use the following somewhat contrived regex
> s.match(/((?!\n{2,})[\s\S])+/g);
["Hi", "
Bye
Ciao"]
and then process the resulting array by applying the trim() string method to its members in order to get rid of any \n at the beginning/end of every string in the array.
((.+)\n?)*(you probably want to make the groups non-capturing, left it as is for readability)
The inner part (.+)\n? means "non-empty line" (at least one non-newline character as . does not match newlines unless the appropriate flag is set, followed by an optional newline)
Then, that is repeated an arbitrary number of times (matching an entire block of non-blank lines).
However, depending on what you are doing, regexp probably is not the answer you are looking for. Are you sure just splitting the string by \n\n won't do what you want?
Do you have to use regex? The solution is simple without it.
var data = 'name1...';
var matches = data.split('\n\n');
To access an individual sub section split it by \n again.
//the first section's name
var name = matches[0].split('\n')[0];