Develop Reference

JavaScript regex inline validation for basic calculation string with one operator

I've written a basic 2 operand calculator app (+ - * /) that uses a couple of inline regex validations to filter away invalid characters as they are typed.
An example looks like:
//check if operator is present
if(/[+\-*\/]/.test(display1.textContent)){
//validate the string each time a new character is added
if(!/^\d+\.?\d*[+\-*\/]?\d*\.?\d*$/.test(display1.textContent)){
console.log('invalid')
return false
}
//validate the string character by character before operator
} else {
if(!/^\d+\.?\d*$/.test(display1.textContent)){
console.log('invalid')
return false
}
}
In the above, a valid character doesn't return false:
23.4x0.00025 (no false returned and hence the string is typed out)
But, if an invalid character is typed the function returns false and the input is filtered away:
23.4x0.(x) x at the end returns a false so is filtered (only one operator allowed per calculation)
23.4x0. is typed
It works pretty well but allows for the following which I would like to deal with:
2.+.1
I would prefer 2.0+0.1
My regex would need an if-then-else conditional stating that if the current character is '.' then the next character must be a number else the next char can be number|.|operator. Or if the current character is [+-*/] then the next character must be a number, else the next char can be any char (while following the overall logic).
The tricky part is that the logic must process the string as it is typed character by character and validate at each addition (and be accurate), not at the end when the string is complete.
if-then-else regex is not supported in JavaScript (which I think would satisfy my needs) so I need to use another approach whilst remaining within the JS domain.
Any suggestions about this specific problem would be really helpful.
Thanks
https://github.com/jdineley/Project-calculator

Thanks #trincot for the tips using capturing groups and look around. This helped me write what I needed:
https://regex101.com/r/khUd8H/1
git hub app is updated and works as desired. Now just need to make it pretty!

For ensuring that an operator is not allowed when the preceding number ended in a point, you can insert a positive look behind in your regex that requires the character before an operator to always be a digit: (?<=\d)
Demo:
const validate = s => /^(\d+(\.\d*)?((?<=\d)[+*/-]|$))*$/.test(s);
document.querySelector("input").addEventListener("input", function () {
this.style.backgroundColor = validate(this.value) ? "" : "orange";
});
Input: <input>

Using regex to place dashes at specific indexes of a string containing numbers and letters

So the formatted code needs looks like this:
"US-XXX-12-12345"
So that's two letters, followed by 3 letters/numbers, followed by 2 numbers, then followed by 5 letters/numbers.
I was able to get it to work using only numbers with the following:
return testString
.replace(/(\d{2})(\d)/, '$1-$2')
.replace(/(\d{3})(\d)/, '$1-$2')
.replace(/(\d{2})(\d{2})/, '$1-$2')
.replace(/(\d{4})(\d{2})/, '$1-$2')
This returns:
"12-345-67-89012"
I tried switching the lowercase d's for uppercase ones (representing letters) and it adds all sorts of extra dashes and does not let me backspace. Any and all help is much appreciated!
EDIT:
Ended up solving it like this:
const clean = new RegExp(/[^a-zA-Z0-9]/, 'gi')
return testString
.replace(clean, '')
.replace(/([a-zA-Z0-9]{2})([a-zA-Z0-9])/, '$1-$2')
.replace(/(-[a-zA-Z0-9]{3})([a-zA-Z0-9])/, '$1-$2')
.replace(/(-[a-zA-Z0-9]{3})(-[a-zA-Z0-9]{2})([a-zA-Z0-9])/, '$1$2-$3')
Thanks to all who tried to help, I really appreciate it <3

I would use a function like this:
function mask(string, model){
let i = 0;
return model.replace(/#/g, () => string[i++] || "");
}
use:
mask("USXXX1212345", "##-###-##-#####") => 'US-XXX-12-12345'
the first parameter of the function is the string you want to format, and the next parameter is how it will be formatted

This isn't quite what you asked for but regex probably isn't the best solution to this question. A better option would probably be to use something like react-input-mask because you mentioned using this in real time in a React form.
import { useState } from "react";
import InputMask from "react-input-mask";
const Example = () => {
const [inputText, setInputText] = useState("");
return (
<InputMask
mask="aa-***-99-*****"
value={inputText}
onChange={(e) => setInputText(e.target.value)}
/>
);
};
And here's a CodeSandbox example because I can't for the life of my embed a functional example in a SO answer: https://codesandbox.io/s/react-input-mask-example-554lcn?file=/src/App.js

If the string is known to have the correct pattern, you can replace matches of the following regular expression with a hyphen.
(?<=^.{2})|(?<=^.{5})|(?<=^.{7})
If lowercase letters are permitted the case-indifferent flag (i) needs to be set.
This expression contains an alternation comprised of three positive lookbehind expressions. It reads, "match the position following the second, fifth or (|) seventh character of the string. Think of (?<=^.{2}) as matching the location between the second and third character of the string. Because it does not match any characters it is referred to as a zero-width match.
Demo
If the string is not known to have the correct pattern, I suggest the string be first matched against the following regular expression to confirm its pattern is correct.
^[A-Z]{2}[A-Z\d]{3}\d{2}[A-Z\d]{5}$
Demo
This regular expression (with the case-indifferent flag is set) can be broken down as follows.
^ # match the beginning of the string
[A-Z]{2} # match two letters
[A-Z\d]{3} # match three letters or digits
\d{2} # match two digits
[A-Z\d]{5} # match five letters or digits
$ # match end of string
The first regular expression can be modified to also confirm that the string has the correct pattern but it complicates the expression considerably. If you would like to see that please let me know.

Here's a solution that does what you want and works on partial input.
It tolerates strings where the dashes are already in the right spot.
Invalid input is left as is.
const rx = /^(?:(\d{1,2})(?:-?([A-Za-z]{1,3})(?:-?(\d{1,2})(?:-?(\d{1,5}))?)?)?)?/
function addDashes(x) {
return x.replace(rx, function(...args) {
const captures = args.slice(1, 5) // get rid of the cruft
return captures.filter(x => x !== undefined).join("-")
})
}
const test = (x) => console.log(x, addDashes(x))
test("")
test("invalid123")
test("1")
test("12a")
test("12-a")
test("12abc")
test("12-abc")
test("12abc12")
test("12-abc12")
test("12-abc-12")
test("12abc1254")
test("12-abc1254")
test("12abc-1254")
test("12-abc-1254")
test("12abc12543")
test("12-abc12-543")
test("12abc1254321")
The RegExp itself is a bit complex, if you want to see how I built it you can have a look at this flems sandbox, where you can tweak it to your liking.

Is there any way to validate emojis without using regex with an unicode flag? [duplicate]

I need help for how to detect if an input contains a Japanese emoji/emoticon.
Currently my character set is charset=utf-8. On inputting text, the user can enter Japanese characters/alpanumerics/symbols but if they insert an emoji, onsubmit JavaScript will check if there is an emoji, error message will display.
I can't get this to work because I have no idea on how to detect an emoji in JavaScript?

The answers might work but are terrible because they rely on unicode ranges that are unreadable and somewhat "magic" because it's not always clear where do they come from and why they work, not to mention they're not resilient to new emojis being added to the spec.
Major browsers now support unicode property escape which allows for matching emojis based on their belonging in the Emoji unicode category: \p{Emoji} matches an emoji, \P{Emoji} matches a non-emoji.
Note that officially, 0123456789#* and other characters are emojis too, so the property escape you might want to use is not Emoji but rather Extended_Pictographic which denotes all the characters typically understood as emojis!
Make sure to include the u flag at the end.
console.log(
/\p{Emoji}/u.test('flowers'), // false :)
/\p{Emoji}/u.test('flowers 🌼🌺🌸'), // true :)
/\p{Emoji}/u.test('flowers 123'), // true :(
)
console.log(
/\p{Extended_Pictographic}/u.test('flowers'), // false :)
/\p{Extended_Pictographic}/u.test('flowers 🌼🌺🌸'), // true :)
/\p{Extended_Pictographic}/u.test('flowers 123'), // false :)
)
This works fine for detecting emojis, but if you want to use the same regex to extract them, you might be surprised with its behavior, since some emojis that appear as one character are actually several characters. They're what we call emoji sequences, more about them in this question
const regex = /\p{Extended_Pictographic}/ug
const family = '👨‍👩‍👧' // "family
console.log(family.length) // not 1, but 8!
console.log(regex.test(family)) // true, as expected
console.log(family.match(regex)) // not [family], but [man, woman, girl]

You can use the following regex:
/(?:[\u2700-\u27bf]|(?:\ud83c[\udde6-\uddff]){2}|[\ud800-\udbff][\udc00-\udfff]|[\u0023-\u0039]\ufe0f?\u20e3|\u3299|\u3297|\u303d|\u3030|\u24c2|\ud83c[\udd70-\udd71]|\ud83c[\udd7e-\udd7f]|\ud83c\udd8e|\ud83c[\udd91-\udd9a]|\ud83c[\udde6-\uddff]|\ud83c[\ude01-\ude02]|\ud83c\ude1a|\ud83c\ude2f|\ud83c[\ude32-\ude3a]|\ud83c[\ude50-\ude51]|\u203c|\u2049|[\u25aa-\u25ab]|\u25b6|\u25c0|[\u25fb-\u25fe]|\u00a9|\u00ae|\u2122|\u2139|\ud83c\udc04|[\u2600-\u26FF]|\u2b05|\u2b06|\u2b07|\u2b1b|\u2b1c|\u2b50|\u2b55|\u231a|\u231b|\u2328|\u23cf|[\u23e9-\u23f3]|[\u23f8-\u23fa]|\ud83c\udccf|\u2934|\u2935|[\u2190-\u21ff])/g
If you just want to remove it from the string, you can do something like this.
function removeEmojis (string) {
var regex = /(?:[\u2700-\u27bf]|(?:\ud83c[\udde6-\uddff]){2}|[\ud800-\udbff][\udc00-\udfff]|[\u0023-\u0039]\ufe0f?\u20e3|\u3299|\u3297|\u303d|\u3030|\u24c2|\ud83c[\udd70-\udd71]|\ud83c[\udd7e-\udd7f]|\ud83c\udd8e|\ud83c[\udd91-\udd9a]|\ud83c[\udde6-\uddff]|\ud83c[\ude01-\ude02]|\ud83c\ude1a|\ud83c\ude2f|\ud83c[\ude32-\ude3a]|\ud83c[\ude50-\ude51]|\u203c|\u2049|[\u25aa-\u25ab]|\u25b6|\u25c0|[\u25fb-\u25fe]|\u00a9|\u00ae|\u2122|\u2139|\ud83c\udc04|[\u2600-\u26FF]|\u2b05|\u2b06|\u2b07|\u2b1b|\u2b1c|\u2b50|\u2b55|\u231a|\u231b|\u2328|\u23cf|[\u23e9-\u23f3]|[\u23f8-\u23fa]|\ud83c\udccf|\u2934|\u2935|[\u2190-\u21ff])/g;
return string.replace(regex, '');
}

A simple function that returns true if your string contains one or more emojis.
function isEmoji(str) {
var ranges = [
'(?:[\u2700-\u27bf]|(?:\ud83c[\udde6-\uddff]){2}|[\ud800-\udbff][\udc00-\udfff]|[\u0023-\u0039]\ufe0f?\u20e3|\u3299|\u3297|\u303d|\u3030|\u24c2|\ud83c[\udd70-\udd71]|\ud83c[\udd7e-\udd7f]|\ud83c\udd8e|\ud83c[\udd91-\udd9a]|\ud83c[\udde6-\uddff]|[\ud83c[\ude01-\ude02]|\ud83c\ude1a|\ud83c\ude2f|[\ud83c[\ude32-\ude3a]|[\ud83c[\ude50-\ude51]|\u203c|\u2049|[\u25aa-\u25ab]|\u25b6|\u25c0|[\u25fb-\u25fe]|\u00a9|\u00ae|\u2122|\u2139|\ud83c\udc04|[\u2600-\u26FF]|\u2b05|\u2b06|\u2b07|\u2b1b|\u2b1c|\u2b50|\u2b55|\u231a|\u231b|\u2328|\u23cf|[\u23e9-\u23f3]|[\u23f8-\u23fa]|\ud83c\udccf|\u2934|\u2935|[\u2190-\u21ff])' // U+1F680 to U+1F6FF
];
if (str.match(ranges.join('|'))) {
return true;
} else {
return false;
}
}

First of all, you cannot rely on ECMAScript 2018+ compliant \p{Emoji} (at least at the time of writing). It really matches some 0123456789#* non-emoji chars (see Nino Filiu's answer). See Why do Unicode emoji property escapes match numbers? for more details.
To test if there are any emoji chars in a string in JavaScript, you can use the following ECMAScript 2018+ compliant solution (mind the u flag):
const regex_emoji = /[\p{Extended_Pictographic}\u{1F3FB}-\u{1F3FF}\u{1F9B0}-\u{1F9B3}]/u;
console.log( regex_emoji.test('flowers 123') ); // => false
console.log( regex_emoji.test('flowers 🌼🌺🌸') ); // => true
You can even extract one or more emoji char sequences using this pattern (note the added g flag to find all occurrences and + to match one or more consecutive occurrences of the character class pattern):
const regex_emoji = /[\p{Extended_Pictographic}\u{1F3FB}-\u{1F3FF}\u{1F9B0}-\u{1F9B3}]+/gu;
console.log( 'flowers 123'.match(regex_emoji) ); // => null
console.log( 'flowers 🌼🌺🌸'.match(regex_emoji) ); // => [ "🌼🌺🌸" ]
In a nutshell, the Extended_Pictographic Unicode category class matches most emoji chars except for some Emoji_Components, that is, light skin to dark skin mode chars (\u{1F3FB}-\u{1F3FF}) and red-haired to white-haired chars (\u{1F9B0}-\u{1F9B3}).
To count, or extract emojis as an array of single chars or consecutive sequences (like in the second code snippet from above) from longer texts and perform other actions on emojis, you can use a custom regex (like in Scott Weaver's answer). It is safer to use the longer, escaped version. However, there are 4702 emoji characters defined in the Emoji Keyboard/Display Test Data for UTR #51 (Version: 14.0) file. Thus, the (ES5 compliant, works even in IE) regex to match a single emoji char is
var EmojiPattern = /[#*0-9]\uFE0F?\u20E3|\u00A9\uFE0F?|[\u00AE\u203C\u2049\u2122\u2139\u2194-\u2199\u21A9\u21AA]\uFE0F?|[\u231A\u231B]|[\u2328\u23CF]\uFE0F?|[\u23E9-\u23EC]|[\u23ED-\u23EF]\uFE0F?|\u23F0|[\u23F1\u23F2]\uFE0F?|\u23F3|[\u23F8-\u23FA\u24C2\u25AA\u25AB\u25B6\u25C0\u25FB\u25FC]\uFE0F?|[\u25FD\u25FE]|[\u2600-\u2604\u260E\u2611]\uFE0F?|[\u2614\u2615]|\u2618\uFE0F?|\u261D(?:\uD83C[\uDFFB-\uDFFF]|\uFE0F)?|[\u2620\u2622\u2623\u2626\u262A\u262E\u262F\u2638-\u263A\u2640\u2642]\uFE0F?|[\u2648-\u2653]|[\u265F\u2660\u2663\u2665\u2666\u2668\u267B\u267E]\uFE0F?|\u267F|\u2692\uFE0F?|\u2693|[\u2694-\u2697\u2699\u269B\u269C\u26A0]\uFE0F?|\u26A1|\u26A7\uFE0F?|[\u26AA\u26AB]|[\u26B0\u26B1]\uFE0F?|[\u26BD\u26BE\u26C4\u26C5]|\u26C8\uFE0F?|\u26CE|[\u26CF\u26D1\u26D3]\uFE0F?|\u26D4|\u26E9\uFE0F?|\u26EA|[\u26F0\u26F1]\uFE0F?|[\u26F2\u26F3]|\u26F4\uFE0F?|\u26F5|[\u26F7\u26F8]\uFE0F?|\u26F9(?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?|\uFE0F(?:\u200D[\u2640\u2642]\uFE0F?)?)?|[\u26FA\u26FD]|\u2702\uFE0F?|\u2705|[\u2708\u2709]\uFE0F?|[\u270A\u270B](?:\uD83C[\uDFFB-\uDFFF])?|[\u270C\u270D](?:\uD83C[\uDFFB-\uDFFF]|\uFE0F)?|\u270F\uFE0F?|[\u2712\u2714\u2716\u271D\u2721]\uFE0F?|\u2728|[\u2733\u2734\u2744\u2747]\uFE0F?|[\u274C\u274E\u2753-\u2755\u2757]|\u2763\uFE0F?|\u2764(?:\u200D(?:\uD83D\uDD25|\uD83E\uDE79)|\uFE0F(?:\u200D(?:\uD83D\uDD25|\uD83E\uDE79))?)?|[\u2795-\u2797]|\u27A1\uFE0F?|[\u27B0\u27BF]|[\u2934\u2935\u2B05-\u2B07]\uFE0F?|[\u2B1B\u2B1C\u2B50\u2B55]|[\u3030\u303D\u3297\u3299]\uFE0F?|\uD83C(?:[\uDC04\uDCCF]|[\uDD70\uDD71\uDD7E\uDD7F]\uFE0F?|[\uDD8E\uDD91-\uDD9A]|\uDDE6\uD83C[\uDDE8-\uDDEC\uDDEE\uDDF1\uDDF2\uDDF4\uDDF6-\uDDFA\uDDFC\uDDFD\uDDFF]|\uDDE7\uD83C[\uDDE6\uDDE7\uDDE9-\uDDEF\uDDF1-\uDDF4\uDDF6-\uDDF9\uDDFB\uDDFC\uDDFE\uDDFF]|\uDDE8\uD83C[\uDDE6\uDDE8\uDDE9\uDDEB-\uDDEE\uDDF0-\uDDF5\uDDF7\uDDFA-\uDDFF]|\uDDE9\uD83C[\uDDEA\uDDEC\uDDEF\uDDF0\uDDF2\uDDF4\uDDFF]|\uDDEA\uD83C[\uDDE6\uDDE8\uDDEA\uDDEC\uDDED\uDDF7-\uDDFA]|\uDDEB\uD83C[\uDDEE-\uDDF0\uDDF2\uDDF4\uDDF7]|\uDDEC\uD83C[\uDDE6\uDDE7\uDDE9-\uDDEE\uDDF1-\uDDF3\uDDF5-\uDDFA\uDDFC\uDDFE]|\uDDED\uD83C[\uDDF0\uDDF2\uDDF3\uDDF7\uDDF9\uDDFA]|\uDDEE\uD83C[\uDDE8-\uDDEA\uDDF1-\uDDF4\uDDF6-\uDDF9]|\uDDEF\uD83C[\uDDEA\uDDF2\uDDF4\uDDF5]|\uDDF0\uD83C[\uDDEA\uDDEC-\uDDEE\uDDF2\uDDF3\uDDF5\uDDF7\uDDFC\uDDFE\uDDFF]|\uDDF1\uD83C[\uDDE6-\uDDE8\uDDEE\uDDF0\uDDF7-\uDDFB\uDDFE]|\uDDF2\uD83C[\uDDE6\uDDE8-\uDDED\uDDF0-\uDDFF]|\uDDF3\uD83C[\uDDE6\uDDE8\uDDEA-\uDDEC\uDDEE\uDDF1\uDDF4\uDDF5\uDDF7\uDDFA\uDDFF]|\uDDF4\uD83C\uDDF2|\uDDF5\uD83C[\uDDE6\uDDEA-\uDDED\uDDF0-\uDDF3\uDDF7-\uDDF9\uDDFC\uDDFE]|\uDDF6\uD83C\uDDE6|\uDDF7\uD83C[\uDDEA\uDDF4\uDDF8\uDDFA\uDDFC]|\uDDF8\uD83C[\uDDE6-\uDDEA\uDDEC-\uDDF4\uDDF7-\uDDF9\uDDFB\uDDFD-\uDDFF]|\uDDF9\uD83C[\uDDE6\uDDE8\uDDE9\uDDEB-\uDDED\uDDEF-\uDDF4\uDDF7\uDDF9\uDDFB\uDDFC\uDDFF]|\uDDFA\uD83C[\uDDE6\uDDEC\uDDF2\uDDF3\uDDF8\uDDFE\uDDFF]|\uDDFB\uD83C[\uDDE6\uDDE8\uDDEA\uDDEC\uDDEE\uDDF3\uDDFA]|\uDDFC\uD83C[\uDDEB\uDDF8]|\uDDFD\uD83C\uDDF0|\uDDFE\uD83C[\uDDEA\uDDF9]|\uDDFF\uD83C[\uDDE6\uDDF2\uDDFC]|\uDE01|\uDE02\uFE0F?|[\uDE1A\uDE2F\uDE32-\uDE36]|\uDE37\uFE0F?|[\uDE38-\uDE3A\uDE50\uDE51\uDF00-\uDF20]|[\uDF21\uDF24-\uDF2C]\uFE0F?|[\uDF2D-\uDF35]|\uDF36\uFE0F?|[\uDF37-\uDF7C]|\uDF7D\uFE0F?|[\uDF7E-\uDF84]|\uDF85(?:\uD83C[\uDFFB-\uDFFF])?|[\uDF86-\uDF93]|[\uDF96\uDF97\uDF99-\uDF9B\uDF9E\uDF9F]\uFE0F?|[\uDFA0-\uDFC1]|\uDFC2(?:\uD83C[\uDFFB-\uDFFF])?|[\uDFC3\uDFC4](?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|[\uDFC5\uDFC6]|\uDFC7(?:\uD83C[\uDFFB-\uDFFF])?|[\uDFC8\uDFC9]|\uDFCA(?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|[\uDFCB\uDFCC](?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?|\uFE0F(?:\u200D[\u2640\u2642]\uFE0F?)?)?|[\uDFCD\uDFCE]\uFE0F?|[\uDFCF-\uDFD3]|[\uDFD4-\uDFDF]\uFE0F?|[\uDFE0-\uDFF0]|\uDFF3(?:\u200D(?:\u26A7\uFE0F?|\uD83C\uDF08)|\uFE0F(?:\u200D(?:\u26A7\uFE0F?|\uD83C\uDF08))?)?|\uDFF4(?:\u200D\u2620\uFE0F?|\uDB40\uDC67\uDB40\uDC62\uDB40(?:\uDC65\uDB40\uDC6E\uDB40\uDC67|\uDC73\uDB40\uDC63\uDB40\uDC74|\uDC77\uDB40\uDC6C\uDB40\uDC73)\uDB40\uDC7F)?|[\uDFF5\uDFF7]\uFE0F?|[\uDFF8-\uDFFF])|\uD83D(?:[\uDC00-\uDC07]|\uDC08(?:\u200D\u2B1B)?|[\uDC09-\uDC14]|\uDC15(?:\u200D\uD83E\uDDBA)?|[\uDC16-\uDC3A]|\uDC3B(?:\u200D\u2744\uFE0F?)?|[\uDC3C-\uDC3E]|\uDC3F\uFE0F?|\uDC40|\uDC41(?:\u200D\uD83D\uDDE8\uFE0F?|\uFE0F(?:\u200D\uD83D\uDDE8\uFE0F?)?)?|[\uDC42\uDC43](?:\uD83C[\uDFFB-\uDFFF])?|[\uDC44\uDC45]|[\uDC46-\uDC50](?:\uD83C[\uDFFB-\uDFFF])?|[\uDC51-\uDC65]|[\uDC66\uDC67](?:\uD83C[\uDFFB-\uDFFF])?|\uDC68(?:\u200D(?:[\u2695\u2696\u2708]\uFE0F?|\u2764\uFE0F?\u200D\uD83D(?:\uDC8B\u200D\uD83D)?\uDC68|\uD83C[\uDF3E\uDF73\uDF7C\uDF93\uDFA4\uDFA8\uDFEB\uDFED]|\uD83D(?:\uDC66(?:\u200D\uD83D\uDC66)?|\uDC67(?:\u200D\uD83D[\uDC66\uDC67])?|[\uDC68\uDC69]\u200D\uD83D(?:\uDC66(?:\u200D\uD83D\uDC66)?|\uDC67(?:\u200D\uD83D[\uDC66\uDC67])?)|[\uDCBB\uDCBC\uDD27\uDD2C\uDE80\uDE92])|\uD83E[\uDDAF-\uDDB3\uDDBC\uDDBD])|\uD83C(?:\uDFF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\uFE0F?|\uDD74(?:\uD83C[\uDFFB-\uDFFF]|\uFE0F)?|\uDD75(?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?|\uFE0F(?:\u200D[\u2640\u2642]\uFE0F?)?)?|[\uDD76-\uDD79]\uFE0F?|\uDD7A(?:\uD83C[\uDFFB-\uDFFF])?|[\uDD87\uDD8A-\uDD8D]\uFE0F?|\uDD90(?:\uD83C[\uDFFB-\uDFFF]|\uFE0F)?|[\uDD95\uDD96](?:\uD83C[\uDFFB-\uDFFF])?|\uDDA4|[\uDDA5\uDDA8\uDDB1\uDDB2\uDDBC\uDDC2-\uDDC4\uDDD1-\uDDD3\uDDDC-\uDDDE\uDDE1\uDDE3\uDDE8\uDDEF\uDDF3\uDDFA]\uFE0F?|[\uDDFB-\uDE2D]|\uDE2E(?:\u200D\uD83D\uDCA8)?|[\uDE2F-\uDE34]|\uDE35(?:\u200D\uD83D\uDCAB)?|\uDE36(?:\u200D\uD83C\uDF2B\uFE0F?)?|[\uDE37-\uDE44]|[\uDE45-\uDE47](?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|[\uDE48-\uDE4A]|\uDE4B(?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|\uDE4C(?:\uD83C[\uDFFB-\uDFFF])?|[\uDE4D\uDE4E](?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|\uDE4F(?:\uD83C[\uDFFB-\uDFFF])?|[\uDE80-\uDEA2]|\uDEA3(?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|[\uDEA4-\uDEB3]|[\uDEB4-\uDEB6](?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|[\uDEB7-\uDEBF]|\uDEC0(?:\uD83C[\uDFFB-\uDFFF])?|[\uDEC1-\uDEC5]|\uDECB\uFE0F?|\uDECC(?:\uD83C[\uDFFB-\uDFFF])?|[\uDECD-\uDECF]\uFE0F?|[\uDED0-\uDED2\uDED5-\uDED7\uDEDD-\uDEDF]|[\uDEE0-\uDEE5\uDEE9]\uFE0F?|[\uDEEB\uDEEC]|[\uDEF0\uDEF3]\uFE0F?|[\uDEF4-\uDEFC\uDFE0-\uDFEB\uDFF0])|\uD83E(?:\uDD0C(?:\uD83C[\uDFFB-\uDFFF])?|[\uDD0D\uDD0E]|\uDD0F(?:\uD83C[\uDFFB-\uDFFF])?|[\uDD10-\uDD17]|[\uDD18-\uDD1F](?:\uD83C[\uDFFB-\uDFFF])?|[\uDD20-\uDD25]|\uDD26(?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|[\uDD27-\uDD2F]|[\uDD30-\uDD34](?:\uD83C[\uDFFB-\uDFFF])?|\uDD35(?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|\uDD36(?:\uD83C[\uDFFB-\uDFFF])?|[\uDD37-\uDD39](?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|\uDD3A|\uDD3C(?:\u200D[\u2640\u2642]\uFE0F?)?|[\uDD3D\uDD3E](?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|[\uDD3F-\uDD45\uDD47-\uDD76]|\uDD77(?:\uD83C[\uDFFB-\uDFFF])?|[\uDD78-\uDDB4]|[\uDDB5\uDDB6](?:\uD83C[\uDFFB-\uDFFF])?|\uDDB7|[\uDDB8\uDDB9](?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|\uDDBA|\uDDBB(?:\uD83C[\uDFFB-\uDFFF])?|[\uDDBC-\uDDCC]|[\uDDCD-\uDDCF](?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|\uDDD0|\uDDD1(?:\u200D(?:[\u2695\u2696\u2708]\uFE0F?|\uD83C[\uDF3E\uDF73\uDF7C\uDF84\uDF93\uDFA4\uDFA8\uDFEB\uDFED]|\uD83D[\uDCBB\uDCBC\uDD27\uDD2C\uDE80\uDE92]|\uD83E(?:\uDD1D\u200D\uD83E\uDDD1|[\uDDAF-\uDDB3\uDDBC\uDDBD]))|\uD83C(?:\uDFFB(?:\u200D(?:[\u2695\u2696\u2708]\uFE0F?|\u2764\uFE0F?\u200D(?:\uD83D\uDC8B\u200D)?\uD83E\uDDD1\uD83C[\uDFFC-\uDFFF]|\uD83C[\uDF3E\uDF73\uDF7C\uDF84\uDF93\uDFA4\uDFA8\uDFEB\uDFED]|\uD83D[\uDCBB\uDCBC\uDD27\uDD2C\uDE80\uDE92]|\uD83E(?:\uDD1D\u200D\uD83E\uDDD1\uD83C[\uDFFB-\uDFFF]|[\uDDAF-\uDDB3\uDDBC\uDDBD])))?|\uDFFC(?:\u200D(?:[\u2695\u2696\u2708]\uFE0F?|\u2764\uFE0F?\u200D(?:\uD83D\uDC8B\u200D)?\uD83E\uDDD1\uD83C[\uDFFB\uDFFD-\uDFFF]|\uD83C[\uDF3E\uDF73\uDF7C\uDF84\uDF93\uDFA4\uDFA8\uDFEB\uDFED]|\uD83D[\uDCBB\uDCBC\uDD27\uDD2C\uDE80\uDE92]|\uD83E(?:\uDD1D\u200D\uD83E\uDDD1\uD83C[\uDFFB-\uDFFF]|[\uDDAF-\uDDB3\uDDBC\uDDBD])))?|\uDFFD(?:\u200D(?:[\u2695\u2696\u2708]\uFE0F?|\u2764\uFE0F?\u200D(?:\uD83D\uDC8B\u200D)?\uD83E\uDDD1\uD83C[\uDFFB\uDFFC\uDFFE\uDFFF]|\uD83C[\uDF3E\uDF73\uDF7C\uDF84\uDF93\uDFA4\uDFA8\uDFEB\uDFED]|\uD83D[\uDCBB\uDCBC\uDD27\uDD2C\uDE80\uDE92]|\uD83E(?:\uDD1D\u200D\uD83E\uDDD1\uD83C[\uDFFB-\uDFFF]|[\uDDAF-\uDDB3\uDDBC\uDDBD])))?|\uDFFE(?:\u200D(?:[\u2695\u2696\u2708]\uFE0F?|\u2764\uFE0F?\u200D(?:\uD83D\uDC8B\u200D)?\uD83E\uDDD1\uD83C[\uDFFB-\uDFFD\uDFFF]|\uD83C[\uDF3E\uDF73\uDF7C\uDF84\uDF93\uDFA4\uDFA8\uDFEB\uDFED]|\uD83D[\uDCBB\uDCBC\uDD27\uDD2C\uDE80\uDE92]|\uD83E(?:\uDD1D\u200D\uD83E\uDDD1\uD83C[\uDFFB-\uDFFF]|[\uDDAF-\uDDB3\uDDBC\uDDBD])))?|\uDFFF(?:\u200D(?:[\u2695\u2696\u2708]\uFE0F?|\u2764\uFE0F?\u200D(?:\uD83D\uDC8B\u200D)?\uD83E\uDDD1\uD83C[\uDFFB-\uDFFE]|\uD83C[\uDF3E\uDF73\uDF7C\uDF84\uDF93\uDFA4\uDFA8\uDFEB\uDFED]|\uD83D[\uDCBB\uDCBC\uDD27\uDD2C\uDE80\uDE92]|\uD83E(?:\uDD1D\u200D\uD83E\uDDD1\uD83C[\uDFFB-\uDFFF]|[\uDDAF-\uDDB3\uDDBC\uDDBD])))?))?|[\uDDD2\uDDD3](?:\uD83C[\uDFFB-\uDFFF])?|\uDDD4(?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|\uDDD5(?:\uD83C[\uDFFB-\uDFFF])?|[\uDDD6-\uDDDD](?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|[\uDDDE\uDDDF](?:\u200D[\u2640\u2642]\uFE0F?)?|[\uDDE0-\uDDFF\uDE70-\uDE74\uDE78-\uDE7C\uDE80-\uDE86\uDE90-\uDEAC\uDEB0-\uDEBA\uDEC0-\uDEC2]|[\uDEC3-\uDEC5](?:\uD83C[\uDFFB-\uDFFF])?|[\uDED0-\uDED9\uDEE0-\uDEE7]|\uDEF0(?:\uD83C[\uDFFB-\uDFFF])?|\uDEF1(?:\uD83C(?:\uDFFB(?:\u200D\uD83E\uDEF2\uD83C[\uDFFC-\uDFFF])?|\uDFFC(?:\u200D\uD83E\uDEF2\uD83C[\uDFFB\uDFFD-\uDFFF])?|\uDFFD(?:\u200D\uD83E\uDEF2\uD83C[\uDFFB\uDFFC\uDFFE\uDFFF])?|\uDFFE(?:\u200D\uD83E\uDEF2\uD83C[\uDFFB-\uDFFD\uDFFF])?|\uDFFF(?:\u200D\uD83E\uDEF2\uD83C[\uDFFB-\uDFFE])?))?|[\uDEF2-\uDEF6](?:\uD83C[\uDFFB-\uDFFF])?)/g;
See the regex demo. The g flag at the end means this regex can match all occurrences in the input string.
The pattern is created dynamically from the list of emojis and contracted using a regex trie.
See this JavaScript demo:
var text = 'flowers 🌼🌺🌸';
// Detecting if there is at least one emoji
console.log( emoji_detection_regex.test(text) ); // => true
// Counting emojis
console.log( (text.match(emoji_count_regex) || []).length ); // => 3
// Extracting one by one, single emoji array
console.log( text.match(emoji_count_regex) ); // => ["🌼","🌺","🌸"]
// Extracting emoji sequences
console.log( text.match(emoji_extract_or_remove_regex) ); // => ["🌼🌺🌸"]
// Removing emojis
console.log( text.replace(emoji_extract_or_remove_regex, '') ); // => 'flowers '
<script src="https://gitcdn.link/repo/stribizhev/Emojis/main/ws_emoji_regex.js"></script>
The emoji regex declarations are available in the https://github.com/stribizhev/Emojis/blob/main/ws_emoji_regex.js file.

We can detect all list of surrogate pairs or the Emoji characters in a specific range.
If the issue related with storing the input string to database like MySQL version before 5.5 we need to detect and remove all the surrogate pairs using the below regex
/([\uD800-\uDBFF][\uDC00-\uDFFF])/g.

Update for 2020: Many of these patterns don't match compound emojis or Modifier Sequences correctly, or are simply outdated and do not match the newer emojis.
Consider this kissing couple: 👩🏼‍❤️‍💋‍👩🏽. It's actually 6 (maybe more) other emojis glued together with the ZWJ zero-width joiner. To match this correctly, you have to actually match that sequence.
Thus, by matching the longer sequences first, this brute-force pattern (too long too paste, but it's a simple alternation and runs fast) correctly parses all 3521 combined emojis as of May 2021:
GitHub link: https://github.com/sweaver2112/Regex-combined-emojis
Edit 5/10/2021: If the size of the Unicode escape version of this regex is off-putting to you, you could actually skip the Unicode escape sequences and just use literal emojis, thereby saving tons of space...well, almost. This character, "*️⃣", which starts with an asterisk, will throw a "nothing to quantify" error. Getting rid of just this guy yields a much shorter, still working, copy/pastable regex that matches 3,520/3,521 Emojis at the present date:
Regex 101 Demo (compact, unsafe literal emoji version)
Regex 101 Demo (long, safe unicode escape version)
The demos' input string includes all characters from
https://unicode.org/emoji/charts/full-emoji-list.html (13.1)
https://unicode.org/emoji/charts-13.1/full-emoji-modifiers.html
Working example using the compact version:
/*the pattern*/
var emojiPattern = 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/*compile the pattern string into a regex*/
let emoRegex = new RegExp(emojiPattern, "g")
/*extracting the emojis*/
let emojis = [..."This 😀👩‍⚖️is the 🧗‍♀️text👩🏼‍❤️‍💋‍👩🏽.".matchAll(emoRegex)];
console.log(emojis)
/*count of emojis*/
let emoCount = [..."This 😀👩‍⚖️is the 🧗‍♀️text👩🏼‍❤️‍💋‍👩🏽.".matchAll(emoRegex)].length
console.log(emoCount)
/*strip emojis from text*/
let stripped = "This 😀👩‍⚖️is the 🧗‍♀️text👩🏼‍❤️‍💋‍👩🏽.".replaceAll(emoRegex, "")
console.log(stripped)
/*use the pattern string to build a custom regex*/
let customRegex = new RegExp(".*"+emojiPattern+"{3}$") //match a string ending in 3 emojis
console.log(customRegex.test("yep three here 😀👩‍⚖️👩🏼‍❤️‍💋‍👩🏽")) //true
console.log(customRegex.test("nope 🥣👩🏼‍❤️‍💋‍👩🏽")) //false

You can use regular expression to detect it in input text:
/([\uE000-\uF8FF]|\uD83C[\uDF00-\uDFFF]|\uD83D[\uDC00-\uDDFF])/g

I wrote the following function: containsEmojis(input, includeBasic=true), which checks an input string for emojis according to the list of emojis defined in the Unicode specification version 13 (see https://unicode.org/Public/emoji/13.0/emoji-sequences.txt), and allows to ignore "basic" emojis that can be represented with only 3 bytes.
The snippet below defines the function and runs a few test cases:
/**
* iterates over the code points of an input string and returns true if an emoji is found.
*
* an emoji is found if the hex code for the character is 5 characters starting with "1F",
* or if #includeBasic is true, the character is 4 and starts with one of the prefixes of
* a basic emoji as defined in the Unicode specification version 13
* see https://unicode.org/Public/emoji/13.0/emoji-sequences.txt
*
* #input the string to check
* #includeBasic include also the basic emojis that only take 3 characters
*/
function containsEmojis(input, includeBasic) {
if (typeof includeBasic == "undefined")
includeBasic = true;
for (var c of input) {
var cHex = ("" + c).codePointAt(0).toString(16);
var lHex = cHex.length;
if (lHex > 3) {
var prefix = cHex.substring(0, 2);
if (lHex == 5 && prefix == "1f") {
return true;
}
if (includeBasic && lHex == 4) {
if (["20", "21", "23", "24", "25", "26", "27", "2B", "29", "30", "32"].indexOf(prefix) > -1)
return true;
}
}
}
return false;
}
// can be tested as follows:
var input;
input = "Hello World!";
console.log(input, containsEmojis(input));
input = "Hello 🌎!";
console.log(input, containsEmojis(input));
console.log(input, containsEmojis(input, false));
// now try a basic emoji
input = "It sparkles ✨ yay!";
console.log(input, containsEmojis(input));
// pass false for includeBasic
console.log(input, containsEmojis(input, false));

another solution I found that worked for me:
const example = '👩‍👩‍👧‍👦🪲';
const regexpEmojiPresentation = /\p{Emoji_Presentation}/gu;
console.log(example.match(regexpEmojiPresentation));

check the emoji like bellow ways
function getEmojiChars(text) {
console.log(text.match(/\ud83c[\udf00-\udfff]|\ud83d[\udc00-\ude4f]|\ud83d[\ude80-\udeff]/g)) ;
}
you will get the array of emoji in the text

Formatting in Javascript

I have a question related to formatting strings.
User should parse a string in the Format XX:XX.
if the string parsed by user is in the format XX:XX i need to return true,
else false:
app.post('/test', (req, res) => {
if (req.body.time is in the format of XX:XX) {
return true
} else {
return false
}
});

You can use the RegExp.test function for this kind of thing.
Here is an example:
var condition = /^[a-zA-Z]{2}:[a-zA-Z]{2}$/.test("XX:XX");
console.log("Condition: ", condition);
The regex that I've used in this case check if the string is composed from two upper or lower case letters fallowed by a colon and other two such letters.
Based on your edits it seems that you're trying to check if a string represents an hour and minute value, if that is the case, a regex like this will be more appropriate /^\d{2}:\d{2}$/. This regex checks if the string is composed of 2 numbers fallowed by a colon and another 2 numbers.

The tool you're looking for is called Regular Expressions.
It is globally supported in almost every development platform, which makes it extremely convenient to use.
I would recommend this website for working out your regular expressions.
/^[a-zA-Z]{2}:[a-zA-Z]{2}&/g is an example of a Regular Expression that will take any pattern of:
[a-zA-Z]{2} - two characters from the sets a-z and A-Z.
Followed by :
Followed by the same first argument. Essentially, validating the pattern XX:XX. Of course, you can manipulate it as to what you want to allow for X.
^ marks the beginning of a string and $ marks the end of it, so ASD:AS would not work even though it contains the described pattern.

try using regex
var str = "12:aa";
var patt = new RegExp("^([a-zA-Z]|[0-9]){2}:([a-zA-Z]|[0-9]){2}$");
var res = patt.test(str);
if(res){ //if true
//do something
}
else{}

What's wrong with my JavaScript regex / regex syntax?

I need a regex to use with javascript/jquery that fits these rules...
it will include 10 digits
if there is a leading 1 or +1 it should be ignored
valid characters allowed in the field are... 0-9,(), and -
I found a regex at Snipplr (the first one), but its not working. First of all, I'm not even sure if that regex fits my rules. Secondly, its allowing inputs like &^%$$#%^adfafsd. I believe the error is in my code not the regex. For example, are there supposed to be quotes around the expression?
Here is the code that is supposed to be validating the phone field...
$('#phone').bind('blur', function() {
var pattern = new RegExp("^(?:\+?1\s*(?:[.-]\s*)?)?(?:\(\s*([2-9]1[02-9]|[2-9][02-8]1|[2-9][02-8][02-9])\s*\)|([2-9]1[02-9]|[2-9][02-8]1|[2-9][02-8][02-9]))\s*(?:[.-]\s*)?([2-9]1[02-9]|[2-9][02-9]1|[2-9][02-9]{2})\s*(?:[.-]\s*)?([0-9]{4})$");
if(pattern.test($('#phone').val())){
$("#phone").addClass("error");
return false;
}else{
$("#phone").removeClass("error");
return true;
}
return true;
})

When you're not using the literal form ( /[regex]/ ), you need to escape the regex string. Try this instead:
var regex = /^(?:\+?1\s*(?:[.-]\s*)?)?(?:\(\s*([2-9]1[02-9]|[2-9][02-8]1|[2-9][02-8][02-9])\s*\)|([2-9]1[02-9]|[2-9][02-8]1|[2-9][02-8][02-9]))\s*(?:[.-]\s*)?([2-9]1[02-9]|[2-9][02-9]1|[2-9][02-9]{2})\s*(?:[.-]\s*)?([0-9]{4})$/;
if(regex.test($('#phone').val()){ ... }

if there is a leading 1 or +1 it should be ignored
it will include 10 digits
valid characters allowed in the field are... 0-9,(), and -
That could be matched with an expression like:
/^(?:\+?1)?[()-]*(?:\d[()-]*){10}$/