I'm trying to open a nested Route from within a nav element.
The App itself runs under /app (as such I redirect any non existing URL to /app).
Within the rendered Layout Component inside the /app Route I'm creating the main navigation as well as the Routes which should ultimately be the content. However once I click on Search or View, the URL gets changed to the correct path, but immediately redirects me to the /app it's as if the Routes "search" and "view" themself were non existent.
Minimal Example:
https://codesandbox.io/s/fragrant-field-ygwbf
App.tsx
<BrowserRouter>
<Routes>
<Route path="/app" element={<Layout />} />
<Route path="*" element={<Navigate to="/app" />} />
</Routes>
</BrowserRouter>
Layout.tsx
const Layout = () => {
const navigate = useNavigate();
const handleSearchClick = (e: any) => {
e.preventDefault();
// do some tasks
navigate("inventory/search");
};
const handleViewClick = (e: any) => {
e.preventDefault();
// do some tasks
navigate("inventory/view");
};
return (
<div>
<nav>
<button onClick={handleSearchClick}>Search</button>
<button onClick={handleViewClick}>View</button>
</nav>
<Routes>
<Route path="/users">
<Route path="about" element={<p>example</p>} />
</Route>
<Route path="/inventory">
<Route path="search" element={<Search />} />
<Route path="view" element={<View />} />
</Route>
</Routes>
The content of search / view should now be displayed below the
Buttons
</div>
);
};
Thanks for any advice
The Problem
Take a look at the browser console, it shows you:
You rendered descendant (or called useRoutes()) at "/app" (under ) but the parent route path has no trailing "*". This means if you navigate deeper, the parent won't match anymore and therefore the child routes will never render.
So, the nested routes (deeper navigation according to the documentation) will never render and you cant see the Search and View sub-routes.
update (Thanks to Drew Reese):
in v6 all route paths are always exactly matched, no more path prefix matching like in v4/5. The parent/root paths need to specify the * wildcard so they can now "prefix" match.
The Solution
Please change the parent <Route path="/app"> to <Route path="/app/*">.
So in the App.tsx:
<BrowserRouter>
<Routes>
<Route path="/app/*" element={<Layout />} />
<Route path="*" element={<Navigate to="/app" />} />
</Routes>
</BrowserRouter>
Edit on codesandbox
I set up my react router like this:
<Route exact path="/users">
<component/>
</Route>
<Route exact path="/users/:id">
<component/>
</Route>
And it wasn't working correctly (url was changing but content wasn't)
after I changed the order of Route in my Routes.js (the one with :id first) it started working. Do it matters or there is other problem somewhere in my code?
Yes you need to check
Route and
Switch
<Switch> is unique in that it renders a route exclusively. In contrast, every <Route> that matches the location renders inclusively.
Read and explore more at https://reactrouter.com/web/api/Switch
Yes, nested routes should be above its parent.
So in the following code, about/user has to be above /about. If its beneath then only /about will render
<Route path='about/user' />
<Router path='about/' />
Basic React Router Setup
<Router>
<Switch>
<Route path="/about">
<About />
</Route>
<Route path="/users">
<Users />
</Route>
<Route path="/">
<Home />
</Route>
</Switch>
</Router>
I need to show different components in one route.
My router with authorization looks like:
<Route authorize={['admin']} component={Authorization}>
<Route path='/home' component={Home} />
</Route>
And in Authorization component I have to check if the user has a access to this route.
But the question is how to show different components on the same route?
Something like this doesn't work:
<Route authorize={['admin']} component={Authorization}>
<Route path='/home' component={AdminHome} />
</Route>
<Route authorize={['manager']} component={Authorization}>
<Route path='/home' component={MangerHome} />
</Route>
Define only one route and create a wrapper component, inside wrapper component check the condition and render different component.
Like this:
<Route authorize={['manager', 'admin']} component={Authorization}>
<Route path='/home' component={WrapperComponent} />
</Route>
Now from Authorization component pass some bool to WrapperComponent to decide between which component do you want to render.
Inside WrapperComponent:
render(){
if(this.props.isAdmin)
return <Home />
return < MangerHome />
}
fI currently have the following routes defined in my application:
/
/selectSteps
/steps
/steps/alpha
/steps/beta
/steps/charlie
Which could also be visualised like this:
- (home)
- selectSteps
- steps
- alpha
- beta
- charlie
My root component looks like this:
<Route path="/" exact component={Home} />
<Route path="/select-steps" render={() => <StepSelectorContainer />} />
<Route path="/steps" component={StepsContainer} />
My Steps component does this:
steps.map(step => (
<Route
path={fullPathForStep(step.uid)}
key={shortid.generate()}
render={() => <StepContainer step={step} />}
/>
This all works nicely, but I don't want steps to exist as route in its own right. Only its child routes should be visitable. So I'm looking to lose the /steps route to leave my routes as:
/
/selectSteps
/steps/alpha
/steps/beta
/steps/charlie
How should I configure my routes for this? Ideally, hitting /steps would redirect to the first child route.
Actually, it's pretty straightforward...
Use Redirect component to... well, redirect.
<Redirect from="/steps" exact to="/steps/whatever" />
exact prop guarantees you won't be redirected from sub-route.
Edit: after all, Redirect does support exact (or strict) props. No need to wrap in Route. Answer updated to reflect that.
Pedr,
I think that this will solve your problem.
<Route path="/" exact component={Home} />
<Route path="/select-steps" render={() => <StepSelectorContainer />} />
<Route path="/steps" component={StepsComponent} />
And then in your StepsComponent render method, you can do this.
<Switch>
{steps.map(step => (
<Route
path={fullPathForStep(step.uid)}
key={shortid.generate()}
render={() => <StepContainer step={step} />}
/>}
<Redirect from="/steps" exact to="/steps/alpha" />
</Switch>
What this will do is render your steps component because it the route begins with /steps. After that is rendered, then it will render one of the nested routes based off the url. If the url is just "/steps", then it will redirect to the initial route listed here, in this case "/steps/alpa" by rendering the redirect. The Switch will make it so that it only renders one of the routes.
Credit to Andreyco for the redirect code.
I hope this helps.
Consider the following:
var AppRoutes = [
<Route handler={App} someProp="defaultProp">
<Route path="/" handler={Page} />
</Route>,
<Route handler={App} someProp="defaultProp">
<Route path="/" handler={Header} >
<Route path="/withheader" handler={Page} />
</Route>
</Route>,
<Route handler={App} someProp="defaultProp">
<Route path=":area" handler={Area} />
<Route path=":area/:city" handler={Area} />
<Route path=":area/:city/:locale" handler={Area} />
<Route path=":area/:city/:locale/:type" handler={Area} />
</Route>
];
I have an App Template, a HeaderTemplate, and Parameterized set of routes with the same handler (within App template). I want to be able to serve 404 routes when something is not found. For example, /CA/SanFrancisco should be found and handled by Area, whereas /SanFranciscoz should 404.
Here's how I quickly test the routes.
['', '/', '/withheader', '/SanFranciscoz', '/ca', '/CA', '/CA/SanFrancisco', '/CA/SanFrancisco/LowerHaight', '/CA/SanFrancisco/LowerHaight/condo'].forEach(function(path){
Router.run(AppRoutes, path, function(Handler, state){
var output = React.renderToString(<Handler/>);
console.log(output, '\n');
});
});
The problem is /SanFranciscoz is always being handled by the Area page, but I want it to 404. Also, if I add a NotFoundRoute to the first route configuration, all the Area pages 404.
<Route handler={App} someProp="defaultProp">
<Route path="/" handler={Page} />
<NotFoundRoute handler={NotFound} />
</Route>,
What am I doing wrong?
Here's a gist that can be downloaded and experimented on.
https://gist.github.com/adjavaherian/aa48e78279acddc25315
DefaultRoute and NotFoundRoute were removed in react-router 1.0.0.
I'd like to emphasize that the default route with the asterisk has to be last in the current hierarchy level to work. Otherwise it will override all other routes that appear after it in the tree because it's first and matches every path.
For react-router 1, 2 and 3
If you want to display a 404 and keep the path (Same functionality as NotFoundRoute)
<Route path='*' exact={true} component={My404Component} />
If you want to display a 404 page but change the url (Same functionality as DefaultRoute)
<Route path='/404' component={My404Component} />
<Redirect from='*' to='/404' />
Example with multiple levels:
<Route path='/' component={Layout} />
<IndexRoute component={MyComponent} />
<Route path='/users' component={MyComponent}>
<Route path='user/:id' component={MyComponent} />
<Route path='*' component={UsersNotFound} />
</Route>
<Route path='/settings' component={MyComponent} />
<Route path='*' exact={true} component={GenericNotFound} />
</Route>
For react-router 4 and 5
Keep the path
<Switch>
<Route exact path="/users" component={MyComponent} />
<Route component={GenericNotFound} />
</Switch>
Redirect to another route (change url)
<Switch>
<Route path="/users" component={MyComponent} />
<Route path="/404" component={GenericNotFound} />
<Redirect to="/404" />
</Switch>
The order matters!
In newer versions of react-router you want to wrap the routes in a Switch which only renders the first matched component. Otherwise you would see multiple components rendered.
For example:
import React from 'react';
import ReactDOM from 'react-dom';
import {
BrowserRouter as Router,
Route,
browserHistory,
Switch
} from 'react-router-dom';
import App from './app/App';
import Welcome from './app/Welcome';
import NotFound from './app/NotFound';
const Root = () => (
<Router history={browserHistory}>
<Switch>
<Route exact path="/" component={App}/>
<Route path="/welcome" component={Welcome}/>
<Route component={NotFound}/>
</Switch>
</Router>
);
ReactDOM.render(
<Root/>,
document.getElementById('root')
);
With the new version of React Router (using 2.0.1 now), you can use an asterisk as a path to route all 'other paths'.
So it would look like this:
<Route route="/" component={App}>
<Route path=":area" component={Area}>
<Route path=":city" component={City} />
<Route path=":more-stuff" component={MoreStuff} />
</Route>
<Route path="*" component={NotFoundRoute} />
</Route>
This answer is for react-router-4.
You can wrap all the routes in Switch block, which functions just like the switch-case expression, and renders the component with the first matched route. eg)
<Switch>
<Route path="/" component={home}/>
<Route path="/home" component={home}/>
<Route component={GenericNotFound}/> {/* The Default not found component */}
</Switch>
When to use exact
Without exact:
<Route path='/home'
component = {Home} />
{/* This will also work for cases like https://<domain>/home/anyvalue. */}
With exact:
<Route exact path='/home'
component = {Home} />
{/*
This will NOT work for cases like https://<domain>/home/anyvalue.
Only for https://<url>/home and https://<domain>/home/
*/}
Now if you are accepting routing parameters, and if it turns out incorrect, you can handle it in the target component itself. eg)
<Route exact path='/user/:email'
render = { (props) => <ProfilePage {...props} user={this.state.user} />} />
Now in ProfilePage.js
if(this.props.match.params.email != desiredValue)
{
<Redirect to="/notFound" component = {GenericNotFound}/>
//Or you can show some other component here itself.
}
For more details you can go through this code:
App.js
ProfilePage.js
For those who are using react router v6
Redirect component has been removed from the react-router version 6.
For react-router-dom v6, simply replace Redirect with Navigate
Migrating up to v6
npm install react-router-dom#6
import {Routes, Route, Navigate } from "react-router-dom";
function App() {
return (
<div>
<Routes>
<Route path="/404" element={<div>Choose the correct path/div>} />
<Route path="*" element={<Navigate replace to="/404" />} />
</Routes>
</div>
);
}
According to the documentation, the route was found, even though the resource wasn't.
Note: This is not intended to be used for when a resource is not found. There is a difference between the router not finding a matched path and a valid URL that results in a resource not being found. The url courses/123 is a valid url and results in a matched route, therefore it was "found" as far as routing is concerned. Then, if we fetch some data and discover that the course 123 does not exist, we do not want to transition to a new route. Just like on the server, you go ahead and serve the url but render different UI (and use a different status code). You shouldn't ever try to transition to a NotFoundRoute.
So, you could always add a line in the Router.run() before React.render() to check if the resource is valid. Just pass a prop down to the component or override the Handler component with a custom one to display the NotFound view.
The above answers are correct and for react 5 before. In React v6, Switch no longer exists. This solution is for react v6:
import {BrowserRouter as Router, Routes, Route, Link} from "react-router-dom";
...
<Router>
<ul>
<li>
<Link to="t1">component1</Link>
</li>
<li>
<Link to="t2">component2</Link>
</li>
</ul>
<Routes>
<Route path="/t1" exact element={<Component1/>}/>
<Route path="/t2" exact element={<Component2/>}/>
<Route path="*" element={<NotFound/>}/>
</Routes>
</Router>
I just had a quick look at your example, but if i understood it the right way you're trying to add 404 routes to dynamic segments. I had the same issue a couple of days ago, found #458 and #1103 and ended up with a hand made check within the render function:
if (!place) return <NotFound />;
hope that helps!
React Router v6
Live Demo: Redirect Default or 404 Routes with React Router
Example code:
<Router>
<Routes>
<Route path="users" element={<Users />} />
<Route path="posts" element={<Posts />} />
</Routes>
</Router>
To redirect and navigate to one of our chosen routes, we can use <Navigate> component from React Router. Now we can declare below our route configuration the case for empty routes, like this:
<Router>
<Routes>
<Route path="users" element={<Users />} />
<Route path="posts" element={<Posts />} />
<Route path="" element={<Navigate to="/users" />} />
</Routes>
</Router>
I had similar issue, instead of using * wild identifier or Default Switch Component. We can simply just use Route Component without defining path.
example:
<Switch>
<Route path="/" component={Root} />
<Route path="/home" component={Home} />
<Route component={NotFoundPage} />
// Default Component To load If none of the path matches.
</Switch>