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how can get particular day of date when you have start and end date

I have a start date 4/10/2021 and end date 4/12/2021
I want get Tuesday, Thursday and Friday date in jquery
I found this solution:
var x = new Date();
//set the financial year starting date
x.setFullYear(2021, 10, 04);
//set the next financial year starting date
var y = new Date();
y.setFullYear(2021, 12, 04);
var j = 1;
var count = 0;
//getting the all fridays in a financial year
for ( var i = 0; x<y; i += j) {
if (x.getDay() == 5) {
$("#append_text").append("Date : " + x.getDate() + "/"
+ (x.getMonth() + 1) + "<br>");
x = new Date(x.getTime() + (7 * 24 * 60 * 60 * 1000));
j = 7;
count++;
} else {
j = 1;
x = new Date(x.getTime() + (24 * 60 * 60 * 1000));
}
}
$("#append_text").append("total fridays : " + count + "<br>");
but it return only Friday and i think it doesn't work truly
The result is:
Date : 5/11
Date : 12/11
Date : 19/11
Date : 26/11
Date : 3/12
Date : 10/12
Date : 17/12
Date : 24/12
Date : 31/12
total fridays : 9
The solution link is here:
Get Friday Dates of Year in javascript using jquery
do you have any solution for that?

As mentioned in getDay() docs:
The getDay() method returns the day of the week for the specified date according to local time, where 0 represents Sunday.
So, clearly
if (x.getDay() == 5)
5 here stands for Friday. So, if you also need Tuesday as 2 & Thursday as 4, you simply need to modify for loop like:
var day = x.getDay();
if (day === 2 || day === 4 || day === 5)
Demo:
var x = new Date();
//set the financial year starting date
x.setFullYear(2021, 10, 04);
//set the next financial year starting date
var y = new Date();
y.setFullYear(2021, 12, 04);
var html = '';
var count = 0;
//getting the all fridays in a financial year
for (var i = 0; x < y; i++) {
var day = x.getDay();
if (day === 2 || day === 4 || day === 5) {
html += "Date : " + x.getDate() + "/" + (x.getMonth() + 1) + "<br>";
if (day === 5)count++;
}
x.setDate(x.getDate() + 1)
}
$("#append_text").append(html);
$("#append_text").append("total fridays : " + count + "<br>");
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div id=append_text></div>

Try this.
var start = new Date(2021, 10, 04);
var end = new Date(2021, 12, 04);
var tuesdays = [], thursdays = [], fridays = [];
for (var current = start; current <= end; current.setDate(current.getDate() + 1)) {
var day = current.getDay();
switch (day) {
case 2: // tuesdays
tuesdays.push(formatDate(current));
break;
case 4: // thursdays
thursdays.push(formatDate(current));
break;
case 6: // fridays
fridays.push(formatDate(current));
break;
default: //other dates
break;
}
}
function formatDate(d) { // formats date to dd/mm/yyy
return d.getDate() + '/' + (d.getMonth() + 1) + '/' + d.getFullYear();
}
console.log(tuesdays.length + " Tuesdays: ", tuesdays.join('\t'));
console.log(thursdays.length + " Thursdays: ", thursdays.join('\t'));
console.log(fridays.length + " Fridays: ", fridays.join('\t'));

You can do this by iterating over every date between the two dates and saving the ones that fit some criterion, or you can get the first of the required dates, then add 7 days to get each weekly until the end date, e.g.
// Parse date in day/month/year format
function parseDMY(s) {
let [d, m, y] = s.split(/\D/);
return new Date(y, m-1, d);
}
// Get next day by dayNumber on or after date, default today
function getDayOfWeek(day, date) {
let d = date? new Date(+date) : new Date();
d.setDate(d.getDate() - d.getDay() + day +
(day < d.getDay()? 7 : 0));
return d;
}
// Format date as dd/mm/yyyy
function formatDMY(date) {
return date.toLocaleString('en-GB', {
year : 'numeric', // remove if year not required
month: '2-digit',
day : '2-digit'
});
}
// Given start and end date, get days by day number between
// dates inclusive
function getDaysBetweenDates(d0, d1, ...days){
let dStart = parseDMY(d0);
let dEnd = parseDMY(d1);
// Guard against endless loop
if (dEnd < dStart) return;
let dates = [];
while (dStart <= dEnd) {
days.forEach(day => {
let d = getDayOfWeek(day, dStart);
if (d <= dEnd) dates.push(formatDMY(d));
});
dStart.setDate(dStart.getDate() + 7);
}
return dates.sort(
(a, b) => a.split(/\D/).reverse().join('').localeCompare(
b.split(/\D/).reverse().join(''))
);
}
// Get all Tue, Thu and Fri between 4 Oct 2021 and 4 Dec 2021 inclusive
console.log(getDaysBetweenDates('4/10/2021', '4/12/2021', 2, 4, 5));
I've left the year in the date, it's easily removed by removing year: 'numeric', from the formatting options.
Note that in the OP:
y.setFullYear(2021, 12, 04);
creates a Date for 4 Jan, 2022 not 4 Dec 2021 because months are zero indexed, so December is 11. A month value of 12 rolls over to January of the following year.

How to get current week number in javascript? [duplicate]

How do I get the current weeknumber of the year, like PHP's date('W')?
It should be the ISO-8601 week number of year, weeks starting on Monday.

You should be able to get what you want here: http://www.merlyn.demon.co.uk/js-date6.htm#YWD.
A better link on the same site is: Working with weeks.
Edit
Here is some code based on the links provided and that posted eariler by Dommer. It has been lightly tested against results at http://www.merlyn.demon.co.uk/js-date6.htm#YWD. Please test thoroughly, no guarantee provided.
Edit 2017
There was an issue with dates during the period that daylight saving was observed and years where 1 Jan was Friday. Fixed by using all UTC methods. The following returns identical results to Moment.js.
/* For a given date, get the ISO week number
*
* Based on information at:
*
* THIS PAGE (DOMAIN EVEN) DOESN'T EXIST ANYMORE UNFORTUNATELY
* http://www.merlyn.demon.co.uk/weekcalc.htm#WNR
*
* Algorithm is to find nearest thursday, it's year
* is the year of the week number. Then get weeks
* between that date and the first day of that year.
*
* Note that dates in one year can be weeks of previous
* or next year, overlap is up to 3 days.
*
* e.g. 2014/12/29 is Monday in week 1 of 2015
* 2012/1/1 is Sunday in week 52 of 2011
*/
function getWeekNumber(d) {
// Copy date so don't modify original
d = new Date(Date.UTC(d.getFullYear(), d.getMonth(), d.getDate()));
// Set to nearest Thursday: current date + 4 - current day number
// Make Sunday's day number 7
d.setUTCDate(d.getUTCDate() + 4 - (d.getUTCDay()||7));
// Get first day of year
var yearStart = new Date(Date.UTC(d.getUTCFullYear(),0,1));
// Calculate full weeks to nearest Thursday
var weekNo = Math.ceil(( ( (d - yearStart) / 86400000) + 1)/7);
// Return array of year and week number
return [d.getUTCFullYear(), weekNo];
}
var result = getWeekNumber(new Date());
document.write('It\'s currently week ' + result[1] + ' of ' + result[0]);
Hours are zeroed when creating the "UTC" date.
Minimized, prototype version (returns only week-number):
Date.prototype.getWeekNumber = function(){
var d = new Date(Date.UTC(this.getFullYear(), this.getMonth(), this.getDate()));
var dayNum = d.getUTCDay() || 7;
d.setUTCDate(d.getUTCDate() + 4 - dayNum);
var yearStart = new Date(Date.UTC(d.getUTCFullYear(),0,1));
return Math.ceil((((d - yearStart) / 86400000) + 1)/7)
};
document.write('The current ISO week number is ' + new Date().getWeekNumber());
Test section
In this section, you can enter any date in YYYY-MM-DD format and check that this code gives the same week number as Moment.js ISO week number (tested over 50 years from 2000 to 2050).
Date.prototype.getWeekNumber = function(){
var d = new Date(Date.UTC(this.getFullYear(), this.getMonth(), this.getDate()));
var dayNum = d.getUTCDay() || 7;
d.setUTCDate(d.getUTCDate() + 4 - dayNum);
var yearStart = new Date(Date.UTC(d.getUTCFullYear(),0,1));
return Math.ceil((((d - yearStart) / 86400000) + 1)/7)
};
function checkWeek() {
var s = document.getElementById('dString').value;
var m = moment(s, 'YYYY-MM-DD');
document.getElementById('momentWeek').value = m.format('W');
document.getElementById('answerWeek').value = m.toDate().getWeekNumber();
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.18.1/moment.min.js"></script>
Enter date YYYY-MM-DD: <input id="dString" value="2021-02-22">
<button onclick="checkWeek(this)">Check week number</button><br>
Moment: <input id="momentWeek" readonly><br>
Answer: <input id="answerWeek" readonly>

You can use momentjs library also:
moment().format('W')

Not ISO-8601 week number but if the search engine pointed you here anyway.
As said above but without a class:
let now = new Date();
let onejan = new Date(now.getFullYear(), 0, 1);
let week = Math.ceil((((now.getTime() - onejan.getTime()) / 86400000) + onejan.getDay() + 1) / 7);
console.log(week);

Accordily http://javascript.about.com/library/blweekyear.htm
Date.prototype.getWeek = function() {
var onejan = new Date(this.getFullYear(), 0, 1);
var millisecsInDay = 86400000;
return Math.ceil((((this - onejan) / millisecsInDay) + onejan.getDay() + 1) / 7);
};
let d = new Date(2020,11,30);
for (let i=0; i<14; i++) {
console.log(`${d.toDateString()} is week ${d.getWeek()}`);
d.setDate(d.getDate() + 1);
}

Jacob Wright's Date.format() library implements date formatting in the style of PHP's date() function and supports the ISO-8601 week number:
new Date().format('W');
It may be a bit overkill for just a week number, but it does support PHP style formatting and is quite handy if you'll be doing a lot of this.

The code below calculates the correct ISO 8601 week number. It matches PHP's date("W") for every week between 1/1/1970 and 1/1/2100.
/**
* Get the ISO week date week number
*/
Date.prototype.getWeek = function () {
// Create a copy of this date object
var target = new Date(this.valueOf());
// ISO week date weeks start on Monday, so correct the day number
var dayNr = (this.getDay() + 6) % 7;
// ISO 8601 states that week 1 is the week with the first Thursday of that year
// Set the target date to the Thursday in the target week
target.setDate(target.getDate() - dayNr + 3);
// Store the millisecond value of the target date
var firstThursday = target.valueOf();
// Set the target to the first Thursday of the year
// First, set the target to January 1st
target.setMonth(0, 1);
// Not a Thursday? Correct the date to the next Thursday
if (target.getDay() !== 4) {
target.setMonth(0, 1 + ((4 - target.getDay()) + 7) % 7);
}
// The week number is the number of weeks between the first Thursday of the year
// and the Thursday in the target week (604800000 = 7 * 24 * 3600 * 1000)
return 1 + Math.ceil((firstThursday - target) / 604800000);
}
Source: Taco van den Broek
If you're not into extending prototypes, then here's a function:
function getWeek(date) {
if (!(date instanceof Date)) date = new Date();
// ISO week date weeks start on Monday, so correct the day number
var nDay = (date.getDay() + 6) % 7;
// ISO 8601 states that week 1 is the week with the first Thursday of that year
// Set the target date to the Thursday in the target week
date.setDate(date.getDate() - nDay + 3);
// Store the millisecond value of the target date
var n1stThursday = date.valueOf();
// Set the target to the first Thursday of the year
// First, set the target to January 1st
date.setMonth(0, 1);
// Not a Thursday? Correct the date to the next Thursday
if (date.getDay() !== 4) {
date.setMonth(0, 1 + ((4 - date.getDay()) + 7) % 7);
}
// The week number is the number of weeks between the first Thursday of the year
// and the Thursday in the target week (604800000 = 7 * 24 * 3600 * 1000)
return 1 + Math.ceil((n1stThursday - date) / 604800000);
}
Sample usage:
getWeek(); // Returns 37 (or whatever the current week is)
getWeek(new Date('Jan 2, 2011')); // Returns 52
getWeek(new Date('Jan 1, 2016')); // Returns 53
getWeek(new Date('Jan 4, 2016')); // Returns 1

getWeekOfYear: function(date) {
var target = new Date(date.valueOf()),
dayNumber = (date.getUTCDay() + 6) % 7,
firstThursday;
target.setUTCDate(target.getUTCDate() - dayNumber + 3);
firstThursday = target.valueOf();
target.setUTCMonth(0, 1);
if (target.getUTCDay() !== 4) {
target.setUTCMonth(0, 1 + ((4 - target.getUTCDay()) + 7) % 7);
}
return Math.ceil((firstThursday - target) / (7 * 24 * 3600 * 1000)) + 1;
}
Following code is timezone-independent (UTC dates used) and works according to the https://en.wikipedia.org/wiki/ISO_8601

Get the weeknumber of any given Date
function week(year,month,day) {
function serial(days) { return 86400000*days; }
function dateserial(year,month,day) { return (new Date(year,month-1,day).valueOf()); }
function weekday(date) { return (new Date(date)).getDay()+1; }
function yearserial(date) { return (new Date(date)).getFullYear(); }
var date = year instanceof Date ? year.valueOf() : typeof year === "string" ? new Date(year).valueOf() : dateserial(year,month,day),
date2 = dateserial(yearserial(date - serial(weekday(date-serial(1))) + serial(4)),1,3);
return ~~((date - date2 + serial(weekday(date2) + 5))/ serial(7));
}
Example
console.log(
week(2016, 06, 11),//23
week(2015, 9, 26),//39
week(2016, 1, 1),//53
week(2016, 1, 4),//1
week(new Date(2016, 0, 4)),//1
week("11 january 2016")//2
);

I found useful the Java SE's SimpleDateFormat class described on Oracle's specification:
http://goo.gl/7MbCh5. In my case in Google Apps Script it worked like this:
function getWeekNumber() {
var weekNum = parseInt(Utilities.formatDate(new Date(), "GMT", "w"));
Logger.log(weekNum);
}
For example in a spreadsheet macro you can retrieve the actual timezone of the file:
function getWeekNumber() {
var weekNum = parseInt(Utilities.formatDate(new Date(), SpreadsheetApp.getActiveSpreadsheet().getSpreadsheetTimeZone(), "w"));
Logger.log(weekNum);
}

This adds "getWeek" method to Date.prototype which returns number of week from the beginning of the year. The argument defines which day of the week to consider the first. If no argument passed, first day is assumed Sunday.
/**
* Get week number in the year.
* #param {Integer} [weekStart=0] First day of the week. 0-based. 0 for Sunday, 6 for Saturday.
* #return {Integer} 0-based number of week.
*/
Date.prototype.getWeek = function(weekStart) {
var januaryFirst = new Date(this.getFullYear(), 0, 1);
if(weekStart !== undefined && (typeof weekStart !== 'number' || weekStart % 1 !== 0 || weekStart < 0 || weekStart > 6)) {
throw new Error('Wrong argument. Must be an integer between 0 and 6.');
}
weekStart = weekStart || 0;
return Math.floor((((this - januaryFirst) / 86400000) + januaryFirst.getDay() - weekStart) / 7);
};

If you are already in an Angular project you could use $filter('date').
For example:
var myDate = new Date();
var myWeek = $filter('date')(myDate, 'ww');

The code snippet which works pretty well for me is this one:
var yearStart = +new Date(d.getFullYear(), 0, 1);
var today = +new Date(d.getFullYear(),d.getMonth(),d.getDate());
var dayOfYear = ((today - yearStart + 1) / 86400000);
return Math.ceil(dayOfYear / 7).toString();
Note:
d is my Date for which I want the current week number.
The + converts the Dates into numbers (working with TypeScript).

With Luxon (https://github.com/moment/luxon) :
import { DateTime } from 'luxon';
const week: number = DateTime.fromJSDate(new Date()).weekNumber;

This week number thing has been a real pain in the a**. Most trivial solutions around the web didn't really work for me as they worked most of the time but all of them broke at some point, especially when year changed and last week of the year was suddenly next year's first week etc. Even Angular's date filter showed incorrect data (it was the 1st week of next year, Angular gave week 53).
Note: The examples are designed to work with European weeks (Mon first)!
getWeek()
Date.prototype.getWeek = function(){
// current week's Thursday
var curWeek = new Date(this.getTime());
curWeek.setDay(4);
// current year's first week's Thursday
var firstWeek = new Date(curWeek.getFullYear(), 0, 4);
firstWeek.setDay(4);
return (curWeek.getDayIndex() - firstWeek.getDayIndex()) / 7 + 1;
};
setDay()
/**
* Make a setDay() prototype for Date
* Sets week day for the date
*/
Date.prototype.setDay = function(day){
// Get day and make Sunday to 7
var weekDay = this.getDay() || 7;
var distance = day - weekDay;
this.setDate(this.getDate() + distance);
return this;
}
getDayIndex()
/*
* Returns index of given date (from Jan 1st)
*/
Date.prototype.getDayIndex = function(){
var start = new Date(this.getFullYear(), 0, 0);
var diff = this - start;
var oneDay = 86400000;
return Math.floor(diff / oneDay);
};
I have tested this and it seems to be working very well but if you notice a flaw in it, please let me know.

Here is my implementation for calculating the week number in JavaScript. corrected for summer and winter time offsets as well.
I used the definition of the week from this article: ISO 8601
Weeks are from mondays to sunday, and january 4th is always in the first week of the year.
// add get week prototype functions
// weeks always start from monday to sunday
// january 4th is always in the first week of the year
Date.prototype.getWeek = function () {
year = this.getFullYear();
var currentDotw = this.getWeekDay();
if (this.getMonth() == 11 && this.getDate() - currentDotw > 28) {
// if true, the week is part of next year
return this.getWeekForYear(year + 1);
}
if (this.getMonth() == 0 && this.getDate() + 6 - currentDotw < 4) {
// if true, the week is part of previous year
return this.getWeekForYear(year - 1);
}
return this.getWeekForYear(year);
}
// returns a zero based day, where monday = 0
// all weeks start with monday
Date.prototype.getWeekDay = function () {
return (this.getDay() + 6) % 7;
}
// corrected for summer/winter time
Date.prototype.getWeekForYear = function (year) {
var currentDotw = this.getWeekDay();
var fourjan = new Date(year, 0, 4);
var firstDotw = fourjan.getWeekDay();
var dayTotal = this.getDaysDifferenceCorrected(fourjan) // the difference in days between the two dates.
// correct for the days of the week
dayTotal += firstDotw; // the difference between the current date and the first monday of the first week,
dayTotal -= currentDotw; // the difference between the first monday and the current week's monday
// day total should be a multiple of 7 now
var weeknumber = dayTotal / 7 + 1; // add one since it gives a zero based week number.
return weeknumber;
}
// corrected for timezones and offset
Date.prototype.getDaysDifferenceCorrected = function (other) {
var millisecondsDifference = (this - other);
// correct for offset difference. offsets are in minutes, the difference is in milliseconds
millisecondsDifference += (other.getTimezoneOffset()- this.getTimezoneOffset()) * 60000;
// return day total. 1 day is 86400000 milliseconds, floor the value to return only full days
return Math.floor(millisecondsDifference / 86400000);
}
for testing i used the following JavaScript tests in Qunit
var runweekcompare = function(result, expected) {
equal(result, expected,'Week nr expected value: ' + expected + ' Actual value: ' + result);
}
test('first week number test', function () {
expect(5);
var temp = new Date(2016, 0, 4); // is the monday of the first week of the year
runweekcompare(temp.getWeek(), 1);
var temp = new Date(2016, 0, 4, 23, 50); // is the monday of the first week of the year
runweekcompare(temp.getWeek(), 1);
var temp = new Date(2016, 0, 10, 23, 50); // is the sunday of the first week of the year
runweekcompare(temp.getWeek(), 1);
var temp = new Date(2016, 0, 11, 23, 50); // is the second week of the year
runweekcompare(temp.getWeek(), 2);
var temp = new Date(2016, 1, 29, 23, 50); // is the 9th week of the year
runweekcompare(temp.getWeek(), 9);
});
test('first day is part of last years last week', function () {
expect(2);
var temp = new Date(2016, 0, 1, 23, 50); // is the first last week of the previous year
runweekcompare(temp.getWeek(), 53);
var temp = new Date(2011, 0, 2, 23, 50); // is the first last week of the previous year
runweekcompare(temp.getWeek(), 52);
});
test('last day is part of next years first week', function () {
var temp = new Date(2013, 11, 30); // is part of the first week of 2014
runweekcompare(temp.getWeek(), 1);
});
test('summer winter time change', function () {
expect(2);
var temp = new Date(2000, 2, 26);
runweekcompare(temp.getWeek(), 12);
var temp = new Date(2000, 2, 27);
runweekcompare(temp.getWeek(), 13);
});
test('full 20 year test', function () {
//expect(20 * 12 * 28 * 2);
for (i = 2000; i < 2020; i++) {
for (month = 0; month < 12; month++) {
for (day = 1; day < 29 ; day++) {
var temp = new Date(i, month, day);
var expectedweek = temp.getWeek();
var temp2 = new Date(i, month, day, 23, 50);
var resultweek = temp.getWeek();
equal(expectedweek, Math.round(expectedweek), 'week number whole number expected ' + Math.round(expectedweek) + ' resulted week nr ' + expectedweek);
equal(resultweek, expectedweek, 'Week nr expected value: ' + expectedweek + ' Actual value: ' + resultweek + ' for year ' + i + ' month ' + month + ' day ' + day);
}
}
}
});

Here is a slight adaptation for Typescript that will also return the dates for the week start and week end. I think it's common to have to display those in a user interface, since people don't usually remember week numbers.
function getWeekNumber(d: Date) {
// Copy date so don't modify original
d = new Date(Date.UTC(d.getFullYear(), d.getMonth(), d.getDate()));
// Set to nearest Thursday: current date + 4 - current day number Make
// Sunday's day number 7
d.setUTCDate(d.getUTCDate() + 4 - (d.getUTCDay() || 7));
// Get first day of year
const yearStart = new Date(Date.UTC(d.getUTCFullYear(), 0, 1));
// Calculate full weeks to nearest Thursday
const weekNo = Math.ceil(
((d.getTime() - yearStart.getTime()) / 86400000 + 1) / 7
);
const weekStartDate = new Date(d.getTime());
weekStartDate.setUTCDate(weekStartDate.getUTCDate() - 3);
const weekEndDate = new Date(d.getTime());
weekEndDate.setUTCDate(weekEndDate.getUTCDate() + 3);
return [d.getUTCFullYear(), weekNo, weekStartDate, weekEndDate] as const;
}

This is my typescript implementation which I tested against some dates. This implementation allows you to set the first day of the week to any day.
//sunday = 0, monday = 1, ...
static getWeekNumber(date: Date, firstDay = 1): number {
const d = new Date(date.getTime());
d.setHours(0, 0, 0, 0);
//Set to first day of the week since it is the same weeknumber
while(d.getDay() != firstDay){
d.setDate(d.getDate() - 1);
}
const dayOfYear = this.getDayOfYear(d);
let weken = Math.floor(dayOfYear/7);
// add an extra week if 4 or more days are in this year.
const daysBefore = ((dayOfYear % 7) - 1);
if(daysBefore >= 4){
weken += 1;
}
//if the last 3 days onf the year,it is the first week
const t = new Date(d.getTime());
t.setDate(t.getDate() + 3);
if(t.getFullYear() > d.getFullYear()){
return 1;
}
weken += 1;
return weken;
}
private static getDayOfYear(date: Date){
const start = new Date(date.getFullYear(), 0, 0);
const diff = (date.getTime() - start.getTime()) + ((start.getTimezoneOffset() - date.getTimezoneOffset()) * 60 * 1000);
const oneDay = 1000 * 60 * 60 * 24;
const day = Math.floor(diff / oneDay);
return day;
}
Tests:
describe('getWeeknumber', () => {
it('should be ok for 0 sunday', () => {
expect(DateUtils.getWeekNumber(new Date(2015, 0, 4), 0)).toBe(1);
expect(DateUtils.getWeekNumber(new Date(2017, 0, 1), 0)).toBe(1);
expect(DateUtils.getWeekNumber(new Date(2017, 0, 2), 0)).toBe(1);
expect(DateUtils.getWeekNumber(new Date(2017, 0, 8), 0)).toBe(2);
expect(DateUtils.getWeekNumber(new Date(2017, 0, 9), 0)).toBe(2);
expect(DateUtils.getWeekNumber(new Date(2020, 11, 28), 0)).toBe(53);
expect(DateUtils.getWeekNumber(new Date(2020, 11, 29), 0)).toBe(53);
expect(DateUtils.getWeekNumber(new Date(2020, 11, 30), 0)).toBe(53);
expect(DateUtils.getWeekNumber(new Date(2020, 11, 31), 0)).toBe(53);
expect(DateUtils.getWeekNumber(new Date(2022, 0, 3), 0)).toBe(1);
});
it('should be ok for monday 1 default', () => {
expect(DateUtils.getWeekNumber(new Date(2015, 0, 4), 1)).toBe(1);
expect(DateUtils.getWeekNumber(new Date(2017, 0, 1), 1)).toBe(52);
expect(DateUtils.getWeekNumber(new Date(2017, 0, 2), 1)).toBe(1);
expect(DateUtils.getWeekNumber(new Date(2017, 0, 8), 1)).toBe(1);
expect(DateUtils.getWeekNumber(new Date(2017, 0, 9), 1)).toBe(2);
expect(DateUtils.getWeekNumber(new Date(2020, 11, 28), 1)).toBe(53);
expect(DateUtils.getWeekNumber(new Date(2020, 11, 29), 1)).toBe(53);
expect(DateUtils.getWeekNumber(new Date(2020, 11, 30), 1)).toBe(53);
expect(DateUtils.getWeekNumber(new Date(2020, 11, 31), 1)).toBe(53);
expect(DateUtils.getWeekNumber(new Date(2022, 0, 3), 1)).toBe(1);
});
});

I tried a lot to get the shortest code to get the weeknumber ISO-conform.
Date.prototype.getWeek=function(){
var date=new Date(this);
date.setHours(0,0,0,0);
return Math.round(((date.setDate(this.getDate()+2-(this.getDay()||7))-date.setMonth(0,4))/8.64e7+3+(date.getDay()||7))/7)+"/"+date.getFullYear();}
The variable date is necessary to avoid to alter the original this. I used the return values of setDate() and setMonth() to dispense with getTime() to save code length and I used an expontial number for milliseconds of a day instead of a multiplication of single elements or a number with five zeros. this is Date or Number of milliseconds, return value is String e.g. "49/2017".

Another library-based option: use d3-time-format:
const formatter = d3.timeFormat('%U');
const weekNum = formatter(new Date());

Shortest workaround for Angular2+ DatePipe, adjusted for ISO-8601:
import {DatePipe} from "#angular/common";
public rightWeekNum: number = 0;
constructor(private datePipe: DatePipe) { }
calcWeekOfTheYear(dateInput: Date) {
let falseWeekNum = parseInt(this.datePipe.transform(dateInput, 'ww'));
this.rightWeekNum = (dateInput.getDay() == 0) ? falseWeekNumber-1 : falseWeekNumber;
}

Inspired from RobG's answer.
What I wanted is the day of the week of a given date. So my answer is simply based on the day of the week Sunday. But you can choose the other day (i.e. Monday, Tuesday...);
First I find the Sunday in a given date and then calculate the week.
function getStartWeekDate(d = null) {
const now = d || new Date();
now.setHours(0, 0, 0, 0);
const sunday = new Date(now);
sunday.setDate(sunday.getDate() - sunday.getDay());
return sunday;
}
function getWeek(date) {
const sunday = getStartWeekDate(date);
const yearStart = new Date(Date.UTC(2021, 0, 1));
const weekNo = Math.ceil((((sunday - yearStart) / 86400000) + 1) / 7);
return weekNo;
}
// tests
for (let i = 0; i < 7; i++) {
let m = 14 + i;
let x = getWeek(new Date(2021, 2, m));
console.log('week num: ' + x, x + ' == ' + 11, x == 11, m);
}
for (let i = 0; i < 7; i++) {
let m = 21 + i;
let x = getWeek(new Date(2021, 2, m));
console.log('week num: ' + x, x + ' == ' + 12, x == 12, 'date day: ' + m);
}
for (let i = 0; i < 4; i++) {
let m = 28 + i;
let x = getWeek(new Date(2021, 2, m));
console.log('week num: ' + x, x + ' == ' + 13, x == 13, 'date day: ' + m);
}
for (let i = 0; i < 3; i++) {
let m = 1 + i;
let x = getWeek(new Date(2021, 3, m));
console.log('week num: ' + x, x + ' == ' + 13, x == 13, 'date day: ' + m);
}
for (let i = 0; i < 7; i++) {
let m = 4 + i;
let x = getWeek(new Date(2021, 3, m));
console.log('week num: ' + x, x + ' == ' + 14, x == 14, 'date day: ' + m);
}

now = new Date();
today = new Date(now.getFullYear(), now.getMonth(), now.getDate());
firstOfYear = new Date(now.getFullYear(), 0, 1);
numOfWeek = Math.ceil((((today - firstOfYear) / 86400000)-1)/7);

function getWeek(param) {
let onejan = new Date(param.getFullYear(), 0, 1);
return Math.ceil((((param.getTime() - onejan.getTime()) / 86400000) + onejan.getDay()) / 7);
}

Find the difference between two dates

How can i find the difference between two dates in this format
Year, Month (Must be < 12 if > 12 the Year++), Days ( Must be < 30 if > 30 then month++), Hours (must be < 24 if > 24 then day++)
i wont have a format like this
year 3,
month 34 (i will calc this 34 in years),
dasy 345 ( an this value too)
i have this code
http://jsfiddle.net/AQSWu/
var currentTo = new Date(2015, 6, 1),
currentFrom = new Date(2013,11,1),
year = currentTo.getFullYear() - currentFrom.getFullYear(),
m1 = currentTo.getMonth() + 1,
m2 = currentFrom.getMonth() + 1,
month = m1 <= m2 ? (12 - m2) + m1 : m1 - m2;
alert("From: " + currentFrom);
alert("To :" + currentTo);
if (currentTo.getDate() < currentFrom.getDate()) {
month = month - 1;
}
if (month >= 12){ month = 0; }
alert(year + ' ' + month);
but i have no idea how i can calc days an hours

Don't substract year, month, day etc separately, but just get the difference between the dates (in milliseconds) and then output that in a format (or unit) that you want:
var currentTo = new Date(2015, 6, 1),
currentFrom = new Date(2013,11,1),
difference = currentTo - currentFrom; // number conversion is implicit
var hours = difference / 3600000; // ms -> h
// now do your maths

How can I add n days to a date but exclude Sundays using yyyymmdd format?

I want a date after 'n' days from a given date in 'yyyymmdd' format (output is also in same format).Adding n days should exclude Sundays. Is it possible to do this in javascript?
Here is my code to add n days to a date
function mydate(dateStr,offset)
{
var ymd = dateStr.match(/^(\d{4})(\d{2})(\d{2})$/);
if (ymd)
{
var date = new Date(ymd[1], ymd[2] - 1, ymd[3]);
date.setDate(date.getDate() + offset);
return $.datepicker.formatDate('yymmdd', date);
}
else
{ // parse error
return null;
}
}
for example,
mydate('19890831',10)
will return
19890910
but actually what I need is '19891012' because there are 2 Sundays when we add 10 days to the '19890831'

Simple solution; you can just loop through the days and skip sundays:
while (offset > 0) {
date.setDate(date.getDate() + 1);
if (date.getDay() != 0) offset--;
}

You can refer to answer here to figure out how many sundays are there between two dates once you have that you can simply add that number to your original days diff.
How to determine number Saturdays and Sundays comes between two dates in java script

function pad(n){
if(n < 10){
return "0" + n;
}
return n;
}
function addDays(dt, n){
var matches = dt.match(/^(\d{4})(\d{2})(\d{2})$/);
var year = matches[1];
var month = matches[2];
var day = matches[3];
var dt = new Date(year, month - 1, day);
var weekDay = dt.getDay();
if((weekDay + n) > 6){
n = n + 1;
}
if(weekDay === 0){
n = n + 1;
}
var oneDayInMillis = 1 * 24 * 60 * 60 * 1000;
var newDt = new Date(dt.getTime() + (oneDayInMillis * n));
return "" + newDt.getFullYear() + pad(newDt.getMonth() + 1) + pad(newDt.getDate());
}

Calculate days of the week from Monday to Saturday

In my form I have a datafield where I select the day of the week!
For example if I select today 23-03-2012 Friday, I need to get an array of days from previous Monday to this next Saturday.
array:
[0],[19-03-2012],[Monday]
[1],[20-03-2012],[Monday]
[2],[21-03-2012],[Wednesday]
[3],[22-03-2012],[Monday]
[4],[23-03-2012],[Friday]
[5],[24-03-2012],[Saturday]
How can i do it for any selected day of the week obviously paying attention to changes?
Thanks

This function will return an array of all the dates in the week of date, Monday to Saturday.
function GetDaysOfWeek(date)
{
var days = new Array();
for (var i = 0; i < 6; i++)
{
days[i] = new Date(date.getYear(),
date.getMonth(),
date.getDate() - date.getDay() + 1 + i);
}
return days;
}

mayby try out MomentJs: http://momentjs.com/docs/
some examples:
moment().day(-7); // set to last Sunday (0 - 7)
moment().day(7); // set to next Sunday (0 + 7)
moment().day(10); // set to next Wednesday (3 + 7)
moment().day(24); // set to 3 Wednesdays from now (3 + 7 + 7 + 7)

For display the current day of the week:
var now = new Date();
var dayNames = ["Sunday","Monday","Tuesday","Wednesday","Thursday","Friday","Saturday"];
document.write("Today is " + dayNames[now.getDay()] + ".");

First find todays date
Find the last monday (including today)
Show that date, and the next 5 days after it (Tuesday-Saturday)
var d = new Date();
if (d.getDay()==0){
d.setDate(d.getDate() + 1);
}
​while (d.getDay() != 1){
d.setDate(d.getDate() - 1);
}
var days = new Array();
for (var i = 0; i < 6; i++){
days[i] = d.getDate() + i;
}
return days;

try this :
var dayString = ["Sunday","Monday","Tuesday","Wednesday","Thursday","Friday","Saturday"];
var now = new Date();
var currentDay = now.getDay(); // return 0 for Sunday, 6 for Saturday
var result = [];
var tempDate = new Date(now.getTime());
tempDate.setDate(now.getDate()-(currentDay+6)%7); // now tempDate is previous Monday
while(tempDate.getDay()!=0) {
var currentMonth = tempDate.getMonth()+1;
if(currentMonth<10) currentMonth = "0"+currentMonth;
result.push([tempDate.getDay()-1,tempDate.getDate()+"-"+currentMonth+"-"+tempDate.getFullYear(),dayString[tempDate.getDay()]]);
tempDate.setDate(tempDate.getDate()+1);
}
console.log(result);

Something like the following will do the trick, I"m sure you can get the formatting to where you want it.
// Assuming d is a date object
function getDateArray(din) {
// Add leading zero to one digit numbers
function aZ(n){return (n<10? '0':'') + n;}
var days = ['Sunday','Monday','Tuesday','Wednesday',
'Thursday','Friday','Saturday'];
var d = new Date(din); // Don't wreck input date
var dn = d.getDay();
var a = [];
var i = 6; // length of day array
if (!dn) {
// It's Sunday, what now?
return ['Sunday!'];
}
d.setDate(d.getDate() + 6 - dn); // Next Saturday
do {
a[i--] = i + ' ' + aZ(d.getDate()) +
'-' + aZ(d.getMonth() + 1) +
'-' + d.getFullYear() +
' ' + days[d.getDay()];
d.setDate(d.getDate() - 1);
} while (i);
return a;
}
// Test it
var date = new Date(2012,2,2)
alert( date + '\n\n' + getDateArray(date).join('\n'));
/*
Fri Mar 02 2012 00:00:00
0 27-02-2012 Monday
1 28-02-2012 Tuesday
2 29-02-2012 Wednesday
3 01-03-2012 Thursday
4 02-03-2012 Friday
5 03-03-2012 Saturday
*/