Hovering over 1 div to change another divs content - javascript

(I have tried tips from multiple posts on here but still no luck)
Essentially I want to hover over div "b" and the content in div "a" to change.
In the actual code diva and dib have different parents so cant be done css only.
simplified html :
$("#divb").hover(function() {
$("#div a").css('content', 'url(img2.png)');
}, function() {
$("#diva").css('content', 'url(img1.png)');
})
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div id="diva">A</div>
<div id="divb">B</div>
Any help would be hugely appreciated :) Ive been trying different methods for hours

You are doing great. You just need to remove the whitespace on div a to diva in order to get it working.

In your html file:
<div id="diva"></div>
<div id="divb"></div>
In your js file:
$('#divb').on('hover', () => {
$("#div a").css('content','url(img2.png)');
$("#diva").css('content','url(img1.png)');
});

$("#divb") will get element with id="divb" you should use # before id not tag name i.e div.Below is demo with example images
$('div#a').hover(function(){
$('div#b').css('content','url(https://www.gettyimages.com/gi-resources/images/CreativeLandingPage/HP_Sept_24_2018/CR3_GettyImages-159018836.jpg)');
},function(){
$('div#b').css('content','url(https://i.pinimg.com/736x/c2/9d/7d/c29d7d7388523342de339fdc2611e80f--flamingo-art-flamingo-beach.jpg?b=t)');
})
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div id="a">A</div>
<div id="b">B</div>

Related

jquery slideToggle opens all divs instead of just the div that is required

I have a page that can have a variable number of <div> the idea is people can click the + symbol which is an <img> then the div that is linked to the img tag will display.
I currently have:
PHP/HTML
$plus = '<img src="images/plus.png" class="clickme" width="20px" height="20px">';
$table .= '<div>'.$plus.'</div>';
$hidden .= '<div class"diary">-Content-</div>';
JS
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.8.2/jquery.min.js"></script>
<script language="javascript" type="text/javascript">
$(document).ready(function(){
$( ".clickme" ).click(function() {
$( ".diary" ).slideToggle( "slow", function() {
});
});
});
</script>
This obviously opens all divs and not just the one that is clicked on. I have looked at other similar questions on here and have tried a number of variations such as:
$(document).ready(function(){
$(".clickme").click(function(){
$(this).next(".diary").toggle();
});
});
However, when I try these it just stops working altogether. i.e. none of the divs slide up or down. I see the examples work on JS Fiddle but as soon as i apply it to my page I get nothing.
I am possibly doing something really dumb for it not to work but can't see what.
thanks for any help.
The HTML output should look like
<div>
<div>
<table>
<img class="clickme">
</table>
</div>
<div class="diary">
<table> content </table>
</div>
<div>
(based on tht HTML provided)
Best way would be to add an attribute with matching indexes to both elements
<div>test toggle
<div class="clickme" data-index="1">click me</div>
<div class="toggle" id="obj_1">toggled field</div>
</div>
and then in the JQuery:
$(function () {
$(".clickme").click(function () {
//get number from clicked element's attribute
var index =$(this).attr('data-index');
//select element with id that matches index and toggle
$('#obj_'+index).toggle();
});
})
After looking at your code, i can see that the slideToggle call is maded on .diary class which is probably applied on each of your elements.
I suggest you to put your diary div inside the $plus div then use jquery children or simply give your .diary divs a unique id and use the id attribute for your
toggle.
EDIT:
Here is a simple html output:
<div class="clickme">
<div class="diary">CONTENT HERE</div>
</div>
Add this in the CSS:
.clickme {
background: url('images/plus.png') no-repeat top left;
min-width: 20px;
min-height: 20px;
cursor: pointer;
}
Script tag:
<script>
$(function() {
$(".clickme").click(function() {
$(this).children().slideToggle("slow");
});
});
</script>
Note that i'd let the diary class for your usage and styling purpose but it's not used anywhere.

Make an endless jQuery short and easy

I have an accordion on my WordPress website.
Usually it works fine, adding and removing classes when clicking the different tabs, but there is an issue with one of the accordions on the website: When clicking on one of the tabs - it doesn't close the rest of the opened tabs. So I added this code in and it works fine:
jQuery(document).ready(function($) {
$("#top11").click(function() {
$("#collapse202").removeClass("in");
$("#collapse203").removeClass("in");
});
$("#top12").click(function() {
$("#collapse201").removeClass("in");
$("#collapse203").removeClass("in");
});
$("#top13").click(function() {
$("#collapse201").removeClass("in");
$("#collapse202").removeClass("in");
});
});
I am sure that there is a way to make it shorter, could some one please explain how to do it more compact?
One way is to add data-id to each collapsed element. For example:
<div id="collapse201" data-id="top11"></div>
<div id="collapse202" data-id="top12"></div>
<div id="collapse203" data-id="top13"></div>
And of course you should use a class in your tabs just in case there are lots of tabs in your accordion:
<div id="top11" class="clickingTab"></div>
<div id="top12" class="clickingTab"></div>
<div id="top12" class="clickingTab"></div>
The JS code could look like this then:
jQuery(document).ready(function($) {
$(".clickingTab").click(function() {
var clickedId = $(this).attr("id");
$("element:not([data-id="+clickedId+"])").removeClass("in");
});
});
There of course could be more efficient ways to solve your problem. But for this particular question this could be the particular solution.
If your HTML look like that, you can use the next() function to target the next sibling element:
$("#top11, #top12, #top13").click(function() {
$("#top11, #top12, #top13").next().removeClass("in");
$(this).next().addClass("in");
});
.in {
color:red;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="top11">top11</div>
<div id="collapse201" class="in">collapse201</div>
<div id="top12">top12</div>
<div id="collapse202" class="in">collapse202</div>
<div id="top13">top13</div>
<div id="collapse203" class="in">collapse203</div>

java script to open hidden divs gets too big

i have this code it works fine problem is i need to use it for 60 links
that wil make around 3600 lines of java script code just to be able to see hidden content for 60 divs
sorry it was late, so posted wrong code, it was not working,
forgot to mention my script is menu with two links about and help when page loads the link is shown but not the contens, instead it shows welcome message, when about is clicked it shows its content and when help is clicked it replace the contens with it
ok fixed my example works fine now.
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(function(){
$("#welcome-content").show();
$("#help-content").hide();
$("#about-content").hide();
$("#about-anchor").click(function(){
$("#welcome-content").hide();
$("#help-content").hide();
$("#about-content").show();
});
$("#help-anchor").click(function(){
$("#welcome-content").hide();
$("#help-content").show();
$("#about-content").hide();
});
});
</script>
<div id="anchor-div">
<a id="about-anchor" href="javascript:;">
About
</a>
</br>
<a id="help-anchor" href="javascript:;">
Help
</a>
</br>
</div>
<div id="content-div">
<div id="welcome-content">welcome to help system</div>
<div id="about-content">About=123</div>
<div id="help-content">Help=456</div>
</div>
jsfiddle demo here
Make use of the index of every li to show/hide the corresponding div:
$('#anchor-div a').click(function(e) {
e.preventDefault(); // Dont follow the Link
$('#content-div>div').hide(); // Hide all divs with content
var index = $(this).index('a'); // Get the position of the a relative to other a
$('#content-div>div').eq(index + 1).show(); // Show the div on the same position as the li-element
});
$('#anchor-div a').click(function(e) {
e.preventDefault(); // Dont follow the Link
$('#content-div>div').hide(); // Hide all divs with content
var index = $(this).index('a'); // Get the position of the a relative to other a
$('#content-div>div').eq(index + 1).show(); // Show the div on the same position as the li-element (skip welcome div)
});
#content-div>div {
display: none;
/* Hide all divs */
}
#content-div>div:first-child {
display: block;
/* Show welcome */
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="anchor-div">
About<br />
Help
</div>
<div id="content-div">
<div>Welcome!</div>
<div>About</div>
<div>Help</div>
</div>
This way you neither need ids nor classes
// Edit: I changed the answer to match the new question. I hide the divs using css (not as mentioned in the commets with js)

Div fade in after other a href Div's are clicked

I'm trying to have a Div fade in after the user clicks two other divs.
This is what I have so far but I'm pretty sure I'm doing something wrong. I can't seem to get the div to fade in even if only one div is clicked let alone two. Any help would be appreciated! thank you so much.
<script>
$(document).ready(function(){
$('#video_overlays').hide();
$('#video_overlays').fadeIn(9000);
$('#video_overlaysanswer').hide();
$('#video_overlaysanswer').fadeIn(18000);
$('#video_overlaysanswer1').hide();
$('#video_overlaysanswer2').hide();
$('#video_overlaysanswer2').fadeIn(18000); });
</script>
<script type="text/javascript">
$(document).ready(function(){
$("video_overlaysanswer").click(function() {
var index = $(this).closest("li").index();
$("video_overlaysanswer1").eq(index).fadeIn("slow");
return false; // prevents navigation to #
});
})
</script>
<div id="video_overlays">
This is where text is
</div>
<div id="video_overlaysanswer">
answer 1
</div>
<div id="video_overlaysanswer2">
answer 2
</div>
<div id="video_overlaysanswer1">
the answer that I want to fade in once the other two div's are clicked
</div>
$(document).ready(function(){
$('#video_overlays').hide();
$('#video_overlays').fadeIn(500);
$('#video_overlaysanswer').hide();
$('#video_overlaysanswer').fadeIn(500);
$('#video_overlaysanswer1').hide();
$('#video_overlaysanswer2').hide();
$('#video_overlaysanswer2').fadeIn(500);
$("#video_overlaysanswer,#video_overlaysanswer2").click(function() {
$("#video_overlaysanswer1").fadeIn("slow");
return false; // prevents navigation to #
});
});
Try code above.It works fine.Now implement different click event fo buttons.hope this helps.
http://jsfiddle.net/szr9vpv5/

Traversing DOM from span in / out of divs

I'm adding a click event to a span that is within a div. The target of this event, which will become visible, is a first div that is within a div, two divs down. How can I traverse the DOM to find it?
Perhaps it'll be clearer with the code:
<div a>
<h2>
<span id="here">Click</span>
</h2>
</div>
<div></div>
<div>
<div class="targetDiv">This is the div we need to find</div>
<div class="targetDiv">There are other divs with the same id, but we don't need to find those</div>
<div class="targetDiv">Not looking for this one </div>
<div class="targetDiv">Or this one either</div>
</div>
I've searched left and right and cannot find an answer. It's important to restrict the event ONLY to the first div immediately after the span.
Any help would be much appreciated.
As shown, the code would look like this:
$('span#here').on('click', function() {
$(this).closest('div').siblings(':contains(.targetDiv)').children().eq(0).show();
}
Here's a sample of the fish we caught
$(function() {
$('#here').on('click', function() {
var div = $(this) //the element clicked
.closest('div') //find nearest parent div
.nextAll(':eq(1)') //find the second next div
.children(':eq(0)') //find the first child of it
.show(); //remove invisible cloak
});
});​
This works. I provided an example you can just save to a html file and test it yourself
<style>
.targetDiv{display:none;}
</style>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js" type="text/javascript"></script>
<script type="text/javascript">
$(document).ready(function(){
$('#here').click(function(){
$('.targetDiv').first().show(); // or whatever you want
});
});
</script>
<div a>
<h2>
<span id="here">Click</span>
</h2>
</div>
<div></div>
<div>
<div class="targetDiv">This is the div we need to find</div>
<div class="targetDiv">There are other divs with the same id, but we don't need to find those</div>
<div class="targetDiv">Not looking for this one </div>
<div class="targetDiv">Or this one either</div>
</div>

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