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how to insert new object in node js array if key not exist

I want to create data structure like that.
Var ans =[{"b":[1,2]},{"g":[100,2]}]
I want to create a new object within list if key not exists in list ans.
Else if key exists in one object of ans list then I want to add new values into the object of ans list
For Example:
Example 1) new data c:{2000}
then
Var ans =[{"b":[1,2]},{"g":[100,2]},{c:[2000]}]
Example 2) new data g:{50}
then
Var ans =[{"b":[1,2]},{"g":[100,2,500]},{c:[2000]}]
I am a beginner in node js, understand array, object concept, but not getting exact logic!
Thanks!

You can try following:
Logic
Filter array based on key
Check if object with mentioned key exists or not.
If yes, push value to this array.
If not, create a dummy object and push this object to original array.
Correction, when you do .push({key: value}), key will be considered as string.
Alternates
If you are using ES6, .push({ [key] : value })
Create a dummy object var o = {}. Set key and value to it o[key] = value and push this object.
Optimisations
Instead of setting value like obj[key] = value, since we will be operating on arrays, try obj[key] = [].concat(value). This will enable you to pass value as number or array of values.
Instead of checking the existence of value in .filter, try Array.isArray to check if value exists and is of type array.
Custom function
function checkAndPush(array, key, value) {
var filteredList = array.filter(function(o) {
return Array.isArray(o[key]);
});
filteredList.length > 0 ? filteredList[0][key].push(value) : array.push({
[key]: [].concat(value)
});
return array;
}
var ans =[{"b":[1,2]},{"g":[100,2]}]
console.log(checkAndPush(ans, "c", [2,3]))
console.log(checkAndPush(ans, "c", 4));
Prototype function
Array.prototype.checkAndPush = function(key, value) {
var filteredList = this.filter(function(o) {
return Array.isArray(o[key]);
});
var dummy = {}
dummy[key] = [].concat(value)
filteredList.length > 0 ? filteredList[0][key].push(value) : this.push(dummy);
// or ES6: this.push({ [key]: [].concat(value) })
return this;
}
var ans =[{"b":[1,2]},{"g":[100,2]}]
console.log(ans.checkAndPush("c", [2,3]))
console.log(ans.checkAndPush("c", 4));

If you are dealing with objects as your values
ans[key] = ans[key] || []
ans[key].push(value)
Note, this works because your values will be an array. If they could be primatives then you would use hasOwnProperty to check.
if (ans.hasOwnProperty(key)) {
// Add this to your key somehow
} else {
// initialize the key with your value
}

Node.js is nothing but a library built on javascript. You can do anything using javascript type of progmming. However push and pop method should be able to help you to deal with nodejs array.
ans[key].push(value)

Return JavaScript object keys that share the same value without knowing key name?

Say I have a simple JavaScript object:
{"omar":"espn.com","omar1":"espn1.com","omar3":"espn.com"}
How do I return all keys that share "espn.com" without knowing the name of the keys?
In this case, only "omar" and "omar3" should be returned.

Just enumerate the properties with Object.keys and Array#filter the ones you want.
Working Example:
var o = {"omar":"espn.com","omar1":"espn1.com","omar3":"espn.com"};
var matched = Object.keys(o).filter(function(key) {
return o[key] === 'espn.com';
});
console.log(matched);

How to check if value existed in array or not?

I dont want to push duplicate values into selectedOwners, so in below code user is selecting owner if owner already existed in selectedOwners array i dont want to push , How can i check that to avoid duplicate values in an array ?
ctrl.js
var selectedOwners = [];
$scope.addProcessOwner = function(dataItem){
var selectedOwner = {
fullName: dataItem.fullName,
workerKey: dataItem.workerKey
}
if(selectedOwners.indexOf(selectedOwner) !== -1) {
selectedOwners.push(selectedOwner);
}
console.log('WORKER DATA',selectedOwners);
}

You can use Array.prototype.some method
The some() method tests whether some element in the array passes the test implemented by the provided function.
var isExists = function(e) {
if (e.fullName == selectedOwner.fullName
&& e.workerKey == selectedOwner.workerKey) {
return true;
}
}
if (!selectedOwners.some(isExists)) {
selectedOwners.push(selectedOwner);
}

The use of Array.indexOf is obvious for simple types like strings and numbers.
However, when you are looking for an object, you have to pass the exact same object. A different object with all the same properties and values will still not work. Think of the array as containing pointers to the objects and you must look for the same pointer.
Instead you will need to write your own method to compare the owners for equality and loop through the array doing this check.

Try wrapping your "if" logic in a for-loop .
Example
//Following code loops through array and check for already existing value
for(var i = 0; i < selectedOwners.length; i++){
if(selectedOwners.indexOf(selectedOwner) !== -1) {
selectedOwners.push(selectedOwner);
}
}

Looping through object in JavaScript

if(properties != undefined)
{
foreach(key in properties)
{
dialogProperty.key = property[key];
}
alert(dialogProperty.close);
}
How can I achieve/fix the above code? I think the above code is self explanatory.

I think you mean for rather than foreach. You should also stop key being global and use Object.prototype.hasOwnProperty:
if(properties != undefined)
{
for (var key in properties)
{
if (properties.hasOwnProperty(key) {
dialogProperty[key] = properties[key]; // fixed this variable name too
}
}
alert(dialogProperty.close);
}
NB Incorporated Kobi's fix too.

Assuming you're trying to copy all properties, you're probably looking for:
dialogProperty[key] = property[key];
dialogProperty.key is not dynamic, it sets the key property each time, the same way dialogProperty["key"] would.

properties && Object.keys(properties).forEach(function(key) {
dialogProperty[key] = properties[key];
});
console.log(dialogProperty.close);
The properties && check is to ensure that properties is not falsy.
The Object.keys call returns an array of all keys that the properties object has.
.forEach runs a function for each element in the array.
dialogProperty[key] = properties[key] set's the value of dialogProperty to be that of properties.

Check if an array item is set in JS

I've got an array
var assoc_pagine = new Array();
assoc_pagine["home"]=0;
assoc_pagine["about"]=1;
assoc_pagine["work"]=2;
I tried
if (assoc_pagine[var] != "undefined") {
but it doesn't seem to work
I'm using jquery, I don't know if it can help
Thanks

Use the in keyword to test if a attribute is defined in a object
if (assoc_var in assoc_pagine)
OR
if ("home" in assoc_pagine)
There are quite a few issues here.
Firstly, is var supposed to a variable has the value "home", "work" or "about"? Or did you mean to inspect actual property called "var"?
If var is supposed to be a variable that has a string value, please note that var is a reserved word in JavaScript and you will need to use another name, such as assoc_var.
var assoc_var = "home";
assoc_pagine[assoc_var] // equals 0 in your example
If you meant to inspect the property called "var", then you simple need to put it inside of quotes.
assoc_pagine["var"]
Then, undefined is not the same as "undefined". You will need typeof to get the string representation of the objects type.
This is a breakdown of all the steps.
var assoc_var = "home";
var value = assoc_pagine[assoc_var]; // 0
var typeofValue = typeof value; // "number"
So to fix your problem
if (typeof assoc_pagine[assoc_var] != "undefined")
update: As other answers have indicated, using a array is not the best sollution for this problem. Consider using a Object instead.
var assoc_pagine = new Object();
assoc_pagine["home"]=0;
assoc_pagine["about"]=1;
assoc_pagine["work"]=2;

var assoc_pagine = new Array();
assoc_pagine["home"]=0;
Don't use an Array for this. Arrays are for numerically-indexed lists. Just use a plain Object ({}).
What you are thinking of with the 'undefined' string is probably this:
if (typeof assoc_pagine[key]!=='undefined')
This is (more or less) the same as saying
if (assoc_pagine[key]!==undefined)
However, either way this is a bit ugly. You're dereferencing a key that may not exist (which would be an error in any more sensible language), and relying on JavaScript's weird hack of giving you the special undefined value for non-existent properties.
This also doesn't quite tell you if the property really wasn't there, or if it was there but explicitly set to the undefined value.
This is a more explicit, readable and IMO all-round better approach:
if (key in assoc_pagine)

var is a statement... so it's a reserved word... So just call it another way.
And that's a better way of doing it (=== is better than ==)
if(typeof array[name] !== 'undefined') {
alert("Has var");
} else {
alert("Doesn't have var");
}

This is not an Array.
Better declare it like this:
var assoc_pagine = {};
assoc_pagine["home"]=0;
assoc_pagine["about"]=1;
assoc_pagine["work"]=2;
or
var assoc_pagine = {
home:0,
about:1,
work:2
};
To check if an object contains some label you simply do something like this:
if('work' in assoc_pagine){
// do your thing
};

This worked for me
if (assoc_pagine[var] != undefined) {
instead this
if (assoc_pagine[var] != "undefined") {

TLDR; The best I can come up with is this: (Depending on your use case, there are a number of ways to optimize this function.)
function arrayIndexExists(array, index){
if ( typeof index !== 'number' && index === parseInt(index).toString()) {
index = parseInt(index);
} else {
return false;//to avoid checking typeof again
}
return typeof index === 'number' && index % 1===0 && index >= 0 && array.hasOwnKey(index);
}
The other answer's examples get close and will work for some (probably most) purposes, but are technically quite incorrect for reasons I explain below.
Javascript arrays only use 'numerical' keys. When you set an "associative key" on an array, you are actually setting a property on that array object, not an element of that array. For example, this means that the "associative key" will not be iterated over when using Array.forEach() and will not be included when calculating Array.length. (The exception for this is strings like '0' will resolve to an element of the array, but strings like ' 0' won't.)
Additionally, checking array element or object property that doesn't exist does evaluate as undefined, but that doesn't actually tell you that the array element or object property hasn't been set yet. For example, undefined is also the result you get by calling a function that doesn't terminate with a return statement. This could lead to some strange errors and difficulty debugging code.
This can be confusing, but can be explored very easily using your browser's javascript console. (I used chrome, each comment indicates the evaluated value of the line before it.);
var foo = new Array();
foo;
//[]
foo.length;
//0
foo['bar'] = 'bar';
//"bar"
foo;
//[]
foo.length;
//0
foo.bar;
//"bar"
This shows that associative keys are not used to access elements in the array, but for properties of the object.
foo[0] = 0;
//0
foo;
//[0]
foo.length;
//1
foo[2] = undefined
//undefined
typeof foo[2]
//"undefined"
foo.length
//3
This shows that checking typeof doesn't allow you to see if an element has been set.
var foo = new Array();
//undefined
foo;
//[]
foo[0] = 0;
//0
foo['0']
//0
foo[' 0']
//undefined
This shows the exception I mentioned above and why you can't just use parseInt();
If you want to use associative arrays, you are better off using simple objects as other answers have recommended.

if (assoc_pagine.indexOf('home') > -1) {
// we have home element in the assoc_pagine array
}
Mozilla indexOf

function isset(key){
ret = false;
array_example.forEach(function(entry) {
if( entry == key ){
ret = true;
}
});
return ret;
}
alert( isset("key_search") );

The most effective way:
if (array.indexOf(element) > -1) {
alert('Bingooo')
}
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