I am trying to get date from JavaScript using getUTCDate().
This is giving me wrong output
var date = new Date();
var startDate = new Date(date.getFullYear(), date.getMonth() - 1, 1);
var endDate = new Date(date.getFullYear(), date.getMonth(), 0);
console.log("startDate " + startDate);
startDate = startDate.getUTCFullYear() + "-" + (startDate.getMonth() + 1) + "-" + startDate.getUTCDate();
console.log("first Date " + startDate);
This gives me 2021-4-31 but it should be 2021-4-1
Any idea.
Your startDate and endDate variables are being set to the start and end of the previous month, but in your local time.
When you console.log("startDate " + startDate) in node.js, it will output the date in UTC, which will differ from your start and end date by your current UTC offset (5 hours, 30 minutes).
If we format the date using your local timezone, you will see that it is the expected value.
var date = new Date();
var startDate = new Date(date.getFullYear(), date.getMonth() - 1, 1);
var endDate = new Date(date.getFullYear(), date.getMonth(), 0);
// Formats date variable as a local ISO (ish) string.
function formatLocal(dt) {
let result = dt.getFullYear()
result += "-" + (String(dt.getMonth() + 1).padStart(2, "0") )
result += "-" + (String(dt.getDate()).padStart(2, "0") );
result += "T" + (String(dt.getHours()).padStart(2, "0") );
result += ":" + (String(dt.getMinutes()).padStart(2, "0") );
result += ":" + (String(dt.getSeconds()).padStart(2, "0") );
return result;
}
console.log("startDate (Local):", formatLocal(startDate))
console.log("endDate (Local):", formatLocal(endDate))
console.log("startDate (UTC):", startDate.toISOString())
console.log("endDate (UTC):", endDate.toISOString())
It's because of the time zone which seems to be GMT+02:00 on your computer I guess.
The getUTCDate() method returns the day of the month(from 1 to 31) in
the specified date according to universal time.
link
const date1 = new Date('April 1, 2021 00:00:00 GMT+02:00');
const date2 = new Date('April 1, 2021 00:00:00 GMT+00:00');
console.log(date1.getUTCDate());
// expected output: 31
console.log(date2.getUTCDate());
// expected output: 1
The best solution is to use moment or Luxon library. There is a bunch of formation options. I think your problem is with time zone.
In Javascript I have Date object which I need to convert to string of format dd.mm.yyyy and dd.mm.yyyy hh24:mi:ss. How do I format the Date in Javascript?
Looks like a German locale format, so you can use Date.toLocaleDateString() and Date.toLocaleTimeString() with a German locale setting (de-DE):
const date = new Date();
const dateString = date.toLocaleDateString('de-DE');
const timeString = date.toLocaleTimeString('de-DE');
const string = `${dateString} ${timeString}`;
console.log(string);
You can use momentjs library for your requirement.
constructor( ) {
let now = moment().format("YYYY-MM-DD HH:mm:ss");
let now2 = moment().format("DD.MM.YYYY");
this.format1 = now;
this.format2 = now2;
console.log(now);
this.date = moment(this.format1, "YYYY-MM-DD HH:mm:ss");
}
https://stackblitz.com/edit/momentjs-format-date?file=app/app.component.ts
You can use methods of Date object for build your date string:
const now = new Date();
const formattedDate = now.getDate() + "." + ('0' + (now.getMonth()+1)).slice(-2) + "." + now.getFullYear();
const formattedDateTime = formattedDate + " " + now.getHours() + ":" + now.getMinutes() + ":" + now.getSeconds();
console.log(formattedDate); // 28.05.2019
console.log(formattedDateTime); // 28.05.2019 13:19:43
I have a string that looks like '1/11/2018 12:00:00 AM' and I want to reformat it to dd-mm-yyyy.
Keep in mind that the month can be double digit sometimes.
You can use libraries like moment.js. Assuming either you do not want to use any external library or can not use it, then you can use following custom method:
function formatDate(dateStr) {
let date = new Date(dateStr);
let day = date.getDate();
let month = date.getMonth() + 1;
let year = date.getFullYear();
return day + '-' + month + '-' + year;
}
console.log(formatDate('1/11/2018 12:00:00 AM'));
You can do somethink like this :
var d = new Date();
var curr_date = d.getDate();
var curr_month = d.getMonth() + 1; //Months are zero based
var curr_year = d.getFullYear();
console.log(curr_date + "-" + curr_month + "-" + curr_year);
However best way is with Moment.js,where you can Parse, Validate, Manipulate, and Display dates in JavaScript.
example:
var date= moment("06/06/2015 11:11:11").format('DD-MMM-YYYY');
function convertDate(oldDate) {
var myDate = new Date(Date.parse(oldDate)); //String -> Timestamp -> Date object
var day = myDate.getDate(); //get day
var month = myDate.getMonth() + 1; //get month
var year = myDate.getFullYear(); //get Year (4 digits)
return pad(day,2) + "-" + pad(month, 2) + "-" + year; //pad is a function for adding leading zeros
}
function pad(num, size) { //function for adding leading zeros
var s = num + "";
while (s.length < size) s = "0" + s;
return s;
}
convertDate("1/11/2018 12:00:00 AM"); //11-01-2018
Demo here
In my datepicker the date will be inserted in mm/dd/yyyy format. But after I inserted I want it to be sent in yyyy-mm-dd format. I am using JavaScript to do this. But I wasn't able to do that. So what should I do?
Thanks & regards,
Chiranthaka
you could also use regular expressions:
var convertDate = function(usDate) {
var dateParts = usDate.split(/(\d{1,2})\/(\d{1,2})\/(\d{4})/);
return dateParts[3] + "-" + dateParts[1] + "-" + dateParts[2];
}
var inDate = "12/06/2013";
var outDate = convertDate(inDate); // 2013-12-06
The expression also works for single digit months and days.
I did the opposite for my website, but it might help you. I let you modify it in order to fit your requierements. Have fun !
getDate
getMonth
getFullYear
Have fun on W3Schools
var d = new Date();
var curr_date = d.getDate();
var curr_month = d.getMonth() + 1; //Months are zero based
var curr_year = d.getFullYear();
if(curr_month < 10)
curr_month = "0"+curr_month;
if(curr_date < 10)
curr_date = "0"+curr_date;
var curr_date_format = curr_date+"/"+curr_month+"/"+curr_year;
Adding more to Christof R's solution (thanks! used it!) to allow for MM-DD-YYYY (- in addition to /) and even MM DD YYYY. Slight change in the regex.
var convertDate = function(usDate) {
var dateParts = usDate.split(/(\d{1,2})[\/ -](\d{1,2})[\/ -](\d{4})/);
return dateParts[3] + "-" + dateParts[1] + "-" + dateParts[2];
}
var inDate = "12/06/2013";
var outDate = convertDate(inDate); // 2013-12-06
As Christof R says: This also works for single digit day and month as well.
// format from M/D/YYYY to YYYYMMDD
Date.prototype.yyyymmdd = function() {
var yyyy = this.getFullYear();
var mm = this.getMonth() < 9 ? "0" + (this.getMonth() + 1) : (this.getMonth() + 1); // getMonth() is zero-based
var dd = this.getDate() < 10 ? "0" + this.getDate() : this.getDate();
return "".concat(yyyy).concat(mm).concat(dd);
};
var siku = new Date();
document.getElementById("day").innerHTML = siku.yyyymmdd();
I'm trying to use JS to turn a date object into a string in YYYYMMDD format. Is there an easier way than concatenating Date.getYear(), Date.getMonth(), and Date.getDay()?
Altered piece of code I often use:
Date.prototype.yyyymmdd = function() {
var mm = this.getMonth() + 1; // getMonth() is zero-based
var dd = this.getDate();
return [this.getFullYear(),
(mm>9 ? '' : '0') + mm,
(dd>9 ? '' : '0') + dd
].join('');
};
var date = new Date();
date.yyyymmdd();
I didn't like adding to the prototype. An alternative would be:
var rightNow = new Date();
var res = rightNow.toISOString().slice(0,10).replace(/-/g,"");
<!-- Next line is for code snippet output only -->
document.body.innerHTML += res;
You can use the toISOString function :
var today = new Date();
today.toISOString().substring(0, 10);
It will give you a "yyyy-mm-dd" format.
Moment.js could be your friend
var date = new Date();
var formattedDate = moment(date).format('YYYYMMDD');
new Date('Jun 5 2016').
toLocaleString('en-us', {year: 'numeric', month: '2-digit', day: '2-digit'}).
replace(/(\d+)\/(\d+)\/(\d+)/, '$3-$1-$2');
// => '2016-06-05'
If you don't need a pure JS solution, you can use jQuery UI to do the job like this :
$.datepicker.formatDate('yymmdd', new Date());
I usually don't like to import too much libraries. But jQuery UI is so useful, you will probably use it somewhere else in your project.
Visit http://api.jqueryui.com/datepicker/ for more examples
This is a single line of code that you can use to create a YYYY-MM-DD string of today's date.
var d = new Date().toISOString().slice(0,10);
I don't like modifying native objects, and I think multiplication is clearer than the string padding the accepted solution.
function yyyymmdd(dateIn) {
var yyyy = dateIn.getFullYear();
var mm = dateIn.getMonth() + 1; // getMonth() is zero-based
var dd = dateIn.getDate();
return String(10000 * yyyy + 100 * mm + dd); // Leading zeros for mm and dd
}
var today = new Date();
console.log(yyyymmdd(today));
Fiddle: http://jsfiddle.net/gbdarren/Ew7Y4/
In addition to o-o's answer I'd like to recommend separating logic operations from the return and put them as ternaries in the variables instead.
Also, use concat() to ensure safe concatenation of variables
Date.prototype.yyyymmdd = function() {
var yyyy = this.getFullYear();
var mm = this.getMonth() < 9 ? "0" + (this.getMonth() + 1) : (this.getMonth() + 1); // getMonth() is zero-based
var dd = this.getDate() < 10 ? "0" + this.getDate() : this.getDate();
return "".concat(yyyy).concat(mm).concat(dd);
};
Date.prototype.yyyymmddhhmm = function() {
var yyyymmdd = this.yyyymmdd();
var hh = this.getHours() < 10 ? "0" + this.getHours() : this.getHours();
var min = this.getMinutes() < 10 ? "0" + this.getMinutes() : this.getMinutes();
return "".concat(yyyymmdd).concat(hh).concat(min);
};
Date.prototype.yyyymmddhhmmss = function() {
var yyyymmddhhmm = this.yyyymmddhhmm();
var ss = this.getSeconds() < 10 ? "0" + this.getSeconds() : this.getSeconds();
return "".concat(yyyymmddhhmm).concat(ss);
};
var d = new Date();
document.getElementById("a").innerHTML = d.yyyymmdd();
document.getElementById("b").innerHTML = d.yyyymmddhhmm();
document.getElementById("c").innerHTML = d.yyyymmddhhmmss();
<div>
yyyymmdd: <span id="a"></span>
</div>
<div>
yyyymmddhhmm: <span id="b"></span>
</div>
<div>
yyyymmddhhmmss: <span id="c"></span>
</div>
Local time:
var date = new Date();
date = date.toJSON().slice(0, 10);
UTC time:
var date = new Date().toISOString();
date = date.substring(0, 10);
date will print 2020-06-15 today as i write this.
toISOString() method returns the date with the ISO standard which is YYYY-MM-DDTHH:mm:ss.sssZ
The code takes the first 10 characters that we need for a YYYY-MM-DD format.
If you want format without '-' use:
var date = new Date();
date = date.toJSON().slice(0, 10).split`-`.join``;
In .join`` you can add space, dots or whatever you'd like.
Plain JS (ES5) solution without any possible date jump issues caused by Date.toISOString() printing in UTC:
var now = new Date();
var todayUTC = new Date(Date.UTC(now.getFullYear(), now.getMonth(), now.getDate()));
return todayUTC.toISOString().slice(0, 10).replace(/-/g, '');
This in response to #weberste's comment on #Pierre Guilbert's answer.
// UTC/GMT 0
document.write('UTC/GMT 0: ' + (new Date()).toISOString().slice(0, 19).replace(/[^0-9]/g, "")); // 20150812013509
// Client local time
document.write('<br/>Local time: ' + (new Date(Date.now()-(new Date()).getTimezoneOffset() * 60000)).toISOString().slice(0, 19).replace(/[^0-9]/g, "")); // 20150812113509
Another way is to use toLocaleDateString with a locale that has a big-endian date format standard, such as Sweden, Lithuania, Hungary, South Korea, ...:
date.toLocaleDateString('se')
To remove the delimiters (-) is just a matter of replacing the non-digits:
console.log( new Date().toLocaleDateString('se').replace(/\D/g, '') );
This does not have the potential error you can get with UTC date formats: the UTC date may be one day off compared to the date in the local time zone.
var someDate = new Date();
var dateFormated = someDate.toISOString().substr(0,10);
console.log(dateFormated);
dateformat is a very used package.
How to use:
Download and install dateformat from NPM. Require it in your module:
const dateFormat = require('dateformat');
and then just format your stuff:
const myYYYYmmddDate = dateformat(new Date(), 'yyyy-mm-dd');
Shortest
.toJSON().slice(0,10).split`-`.join``;
let d = new Date();
let s = d.toJSON().slice(0,10).split`-`.join``;
console.log(s);
Working from #o-o's answer this will give you back the string of the date according to a format string. You can easily add a 2 digit year regex for the year & milliseconds and the such if you need them.
Date.prototype.getFromFormat = function(format) {
var yyyy = this.getFullYear().toString();
format = format.replace(/yyyy/g, yyyy)
var mm = (this.getMonth()+1).toString();
format = format.replace(/mm/g, (mm[1]?mm:"0"+mm[0]));
var dd = this.getDate().toString();
format = format.replace(/dd/g, (dd[1]?dd:"0"+dd[0]));
var hh = this.getHours().toString();
format = format.replace(/hh/g, (hh[1]?hh:"0"+hh[0]));
var ii = this.getMinutes().toString();
format = format.replace(/ii/g, (ii[1]?ii:"0"+ii[0]));
var ss = this.getSeconds().toString();
format = format.replace(/ss/g, (ss[1]?ss:"0"+ss[0]));
return format;
};
d = new Date();
var date = d.getFromFormat('yyyy-mm-dd hh:ii:ss');
alert(date);
I don't know how efficient that is however, especially perf wise because it uses a lot of regex. It could probably use some work I do not master pure js.
NB: I've kept the predefined class definition but you might wanna put that in a function or a custom class as per best practices.
A little variation for the accepted answer:
function getDate_yyyymmdd() {
const date = new Date();
const yyyy = date.getFullYear();
const mm = String(date.getMonth() + 1).padStart(2,'0');
const dd = String(date.getDate()).padStart(2,'0');
return `${yyyy}${mm}${dd}`
}
console.log(getDate_yyyymmdd())
This guy here => http://blog.stevenlevithan.com/archives/date-time-format wrote a format() function for the Javascript's Date object, so it can be used with familiar literal formats.
If you need full featured Date formatting in your app's Javascript, use it. Otherwise if what you want to do is a one off, then concatenating getYear(), getMonth(), getDay() is probably easiest.
Little bit simplified version for the most popular answer in this thread https://stackoverflow.com/a/3067896/5437379 :
function toYYYYMMDD(d) {
var yyyy = d.getFullYear().toString();
var mm = (d.getMonth() + 101).toString().slice(-2);
var dd = (d.getDate() + 100).toString().slice(-2);
return yyyy + mm + dd;
}
You can simply use This one line code to get date in year
var date = new Date().getFullYear() + "-" + (parseInt(new Date().getMonth()) + 1) + "-" + new Date().getDate();
How about Day.js?
It's only 2KB, and you can also dayjs().format('YYYY-MM-DD').
https://github.com/iamkun/dayjs
Use padStart:
Date.prototype.yyyymmdd = function() {
return [
this.getFullYear(),
(this.getMonth()+1).toString().padStart(2, '0'), // getMonth() is zero-based
this.getDate().toString().padStart(2, '0')
].join('-');
};
This code is fix to Pierre Guilbert's answer:
(it works even after 10000 years)
YYYYMMDD=new Date().toISOString().slice(0,new Date().toISOString().indexOf("T")).replace(/-/g,"")
Answering another for Simplicity & readability.
Also, editing existing predefined class members with new methods is not encouraged:
function getDateInYYYYMMDD() {
let currentDate = new Date();
// year
let yyyy = '' + currentDate.getFullYear();
// month
let mm = ('0' + (currentDate.getMonth() + 1)); // prepend 0 // +1 is because Jan is 0
mm = mm.substr(mm.length - 2); // take last 2 chars
// day
let dd = ('0' + currentDate.getDate()); // prepend 0
dd = dd.substr(dd.length - 2); // take last 2 chars
return yyyy + "" + mm + "" + dd;
}
var currentDateYYYYMMDD = getDateInYYYYMMDD();
console.log('currentDateYYYYMMDD: ' + currentDateYYYYMMDD);
[day,,month,,year]= Intl.DateTimeFormat(undefined, { year: 'numeric', month: '2-digit', day: '2-digit' }).formatToParts(new Date()),year.value+month.value+day.value
or
new Date().toJSON().slice(0,10).replace(/\/|-/g,'')
From ES6 onwards you can use template strings to make it a little shorter:
var now = new Date();
var todayString = `${now.getFullYear()}-${now.getMonth()}-${now.getDate()}`;
This solution does not zero pad. Look to the other good answers to see how to do that.
I usually use the code below when I need to do this.
var date = new Date($.now());
var dateString = (date.getFullYear() + '-'
+ ('0' + (date.getMonth() + 1)).slice(-2)
+ '-' + ('0' + (date.getDate())).slice(-2));
console.log(dateString); //Will print "2015-09-18" when this comment was written
To explain, .slice(-2) gives us the last two characters of the string.
So no matter what, we can add "0" to the day or month, and just ask for the last two since those are always the two we want.
So if the MyDate.getMonth() returns 9, it will be:
("0" + "9") // Giving us "09"
so adding .slice(-2) on that gives us the last two characters which is:
("0" + "9").slice(-2)
"09"
But if date.getMonth() returns 10, it will be:
("0" + "10") // Giving us "010"
so adding .slice(-2) gives us the last two characters, or:
("0" + "10").slice(-2)
"10"
It seems that mootools provides Date().format(): https://mootools.net/more/docs/1.6.0/Types/Date
I'm not sure if it worth including just for this particular task though.
If you don't mind including an additional (but small) library, Sugar.js provides lots of nice functionality for working with dates in JavaScript.
To format a date, use the format function:
new Date().format("{yyyy}{MM}{dd}")