I am using Upload Image plugin to implement "drag drop to insert image" functionality. When I drop image into edit area, image is getting uploaded to server and then using the returned url to show preview.
But I need to show image preview in edit area without uploading to server. When I click on custom submit button I want save entire content including images to server.
Please let me know if anybody has done/any ideas on this.
Thanks in advance.
Siva
That is pretty simple. UploadWidget is a helper to create content from dropped images: http://docs.ckeditor.com/#!/api/CKEDITOR.fileTools-method-addUploadWidget
There is the definition property loadMethod which can be load - which is exactly the option you need:
http://docs.ckeditor.com/#!/api/CKEDITOR.fileTools.uploadWidgetDefinition-property-loadMethod
Then, you can overwrite the upload image widget or create your own widget, based on the fileReader example from UploadWidget.
The code should look like:
CKEDITOR.fileTools.addUploadWidget( editor, 'imageReader', {
loadMethod: 'load',
supportedTypes: /image\/(jpeg|png|gif|bmp)/,
fileToElement: function( file ) {
var img = new CKEDITOR.dom.element( 'img' );
img.setAttribute( 'src', loadingImage );
return img;
},
onLoaded: function( loader ) {
this.replaceWith( '<img src="' + loader.data + '" '>' );
}
} );
// Black rectangle which is shown before the image is loaded.
var loadingImage = 'data:image/gif;base64,R0lGODlhDgAOAIAAAAAAAP///yH5BAAAAAAALAAAAAAOAA4AAAIMhI+py+0Po5y02qsKADs=';
The only part which may not work is notification integration that listens on the upload event as far as I remember. If you need notifications, you need to add them manually.
I'm making a Chrome extension which in order to reduce bandwidth usage it stops all outcoming requests which are images.
I want to provide functionality where if the user clicks on the image (or technically a layer on top of that image) it would try to reload the image, this time not being blocked by the extension.
How can I tell the browser to retry loading the image? And if there isn't a straightforward way to do it, what would be a work around? Deleting the old image from the DOM and adding it again?
Any help is appreciated. :)
EDIT 1:
To answer #CBroe's question:
Using the chrome.webRequest.onBeforeRequest API in a background script.
To answer #jfriend00's question:
The usual placeholder "couldn't load image" icon, I guess also known as "broken file" icon:
See all those broken images?
That screenshot also illustrates the point of a layer on top of another image. Should those images not be broken, the loaded image would be there but that layer (the one in a dark grey which shows the image's dimensions) still remains there.
The desired href still exists there in the img tag:
If simply assigning the same src value to the img element is not enough¹, then create a new Image object in JavaScript, and assign the value to its src property.
¹ It might not be, if the browser just goes, “oh hey, that is the same value for the src attribute that the img already had, so I don’t have to do anything” – creating a new JS Image object however should make the browser request that resource again if he realizes he does not have it cached already.
What I would do instead is replace the URLs of the images with an image from your extension. A 1x1 pixel transparent GIF or PNG.
When you do this, add an attribute to all of the elements you replaced... something like data-yourextension-originalurl, with the URL of the original image. If the user then wants to load images, it's easy enough to go back and fix those image elements.
While I'm not too familiar with the Chrome API, a quick glance seems to suggest that there's no way to get the specific img element from each onBeforeRequest, which you'd need to know in order to figure out where to attach custom code.
This may be better accomplished with native JavaScript of some sort. For example, if Chrome lets you inject code on load, you could apply a function like the one below to all img elements after document load but before image load.
// Given an img element, replaces its src with a placeholder URL,
// and sets its click action to load its original src
function makePlaceholder(elem){
elem["data-oldtitle"] = elem.title;
elem["data-oldhref"] = elem.href;
elem["data-oldsrc"] = elem.src;
elem["data-oldonclick"] = elem.onClick;
elem.title = "Click to load the blocked image.";
elem.href = '';
elem.src = "http://example.com/placeholder.png";
elem.onClick = function(){
this.src = this["data-oldsrc"];
this.title = this["data-oldtitle"];
this.href = this["data-oldhref"];
this.onClick = this["data-oldonclick"];
};
}
The simple way to force reloading an image in JavaScript is:
var img = document.getElementById("myImage");
img.src = img.src.replace(/\?.+/,"") + "?" + new Date().getTime();
This adds a unique QueryString to the image which basically forces the browser to not use a cached version of the image.
<img src="img/image1.png" id="mainimage">
<p>Dog</p>
<p>Cat</p>
I am trying to use JavaScript/jQuery so that whenever a user places their mouse over any of the links with the id's pet1 & pet2 it will change the image src of the image with the id of mainimage.
var img = document.getElementById('swap');
document.getElementById('pet1').onmouseover = function(){
// manipulate the image source here.
img.src = img.src.replace(/\.jpg/, '-on.jpg');
}
The above JavaScript is a script I found here that seems to have the functionality I am looking for. The only problem is that whenever my mouse is over the link it does not display the image I want. Ok, the question I am looking for is how can I make the image with the source (img/pet1.jpg) appear?
Any help will be appreciated!
Try this more simply
$(function() {
$("#pet1")
.mouseover(function() {
var src = 'first image path';
$("#mainimage").attr("src", src);
})
.mouseout(function() {
var src2 ='Default image path';
$(this).attr("src", src2;
});
});
Similllar for second image and for shortening even this you can give a class to every link you want and then by using $(element).each() function and "data" attribute of html5 you can manage it in more cool way
This should get you started.
For all links at once we set a mouseover handler (which takes the ID of the link, turns it into a path to the image, and displays it) and a mouseout handler (which reverts the image's src to its original image).
$(document).ready(function() {
// To start with, get a reference to the image and its original src
var $mainImage = $('#mainimage'),
originalImageSrc = $mainImage.attr('src');
// Then add mouseover and mouseout handlers to all the links
$('a')
.on('mouseover', function() {
var newImageSrc = 'img/' + $(this).attr('id') + '.jpg';
$mainImage.attr('src', newImageSrc);
})
.on('mouseout', function() {
$mainImage.attr('src', originalImageSrc);
});
});
You can see it working in this JSFiddle. So that you can see it working in the JSFiddle without real images, I've used a div's text rather than an img's src, but that's just for the demo.
Of course you could always adapt it (maybe you want to be more specific than all a tags, and maybe you don't always want to use the format img/<id>.jpg – in which case you could add a data-img-src attribute to all your links and use .data('imgSrc') instead of the .attr('id')).
Hopefully this is what you're looking for.
HTML:
<img src="http://placehold.it/300x150" id="theImage">
<p>Red</p>
<p>Blue</p>
JS:
$('.yourClass').hover(function() {
var newImg = $(this).data('img');
$('#theImage').attr('src',newImg)
}, function() {
$('#theImage').attr('src','http://placehold.it/300x150')
});
JSFiddle
Title is self-explanatory, but I'll provide a step-by-step view on the matter. Hopefully I'm not the first one to have noticed this (apparently) bug on Webkit/Chrome.
I want to reset a GIF animation. All of the examples I've seen so far either simply set the src of the image to itself or set it to an empty string followed by the original src again.
Take a look at this JSFiddle for reference. The GIF resets perfectly fine on IE, Firefox and Chrome.
The issue which I have is when the image has display:none on Google Chrome only.
Check this JSFiddle. The GIF resets fine on IE and Firefox before being displayed in the page, but Chrome simply refuses to reset its animation!
What I've tried so far:
Setting the src to itself as in Fiddle, doesn't work in Chrome.
Setting the src to an empty string and restoring it to the default, doesn't work either.
Putting an wrapper around the image, emptying the container through .html('') and putting the image back inside of it, doesn't work either.
Changing the display of the image through .show() or .fadeIn() right before setting the src doesn't work either.
The only workaround which I've found so far is keeping the image with its default display and manipulating it through .animate()ing and .css()ing the opacity, height and visibility when necessary to simulate a display:none behaviour.
The main reason (context) of this question is that I wanted to reset an ajax loader GIF right before fading it in the page.
So my question is, is there a proper way to reset a GIF image's animation (which avoids Chrome's display:none "bug") or is it actually a bug?
(ps. You may change the GIF in the fiddles for a more appropriate/longer animation gif for testing)
The most reliable way to "reset" a GIF is by appending a random query string. However this does mean that the GIF will be redownloaded every time so make sure it's a small file.
// reset a gif:
img.src = img.src.replace(/\?.*$/,"")+"?x="+Math.random();
Chrome deals with style changes differently than other browsers.
In Chrome, when you call .show() with no argument, the element is not actually shown immediately right where you call it. Instead, Chrome queues the application of the new style for execution after evaluating the current chunk of JavaScript; whereas other browsers would apply the new style change immediately. .attr(), however, does not get queued. So you are effectively trying to set the src when the element is still not visible according to Chrome, and Chrome won't do anything about it when the original src and new src are the same.
Instead, what you need to do is to make sure jQuery sets the src after display:block is applied. You can make use of setTimeout to achieve this effect:
var src = 'http://i.imgur.com/JfkmXjG.gif';
$(document).ready(function(){
var $img = $('img');
$('#target').toggle(
function(){
var timeout = 0; // no delay
$img.show();
setTimeout(function() {
$img.attr('src', src);
}, timeout);
},
function(){
$img.hide();
}
);
});
This ensures that src is set after display:block has been applied to the element.
The reason this works is because setTimeout queues the function for execution later (however long later is), so the function is no longer considered to be part of the current "chunk" of JavaScript, and it provides a gap for Chrome to render and apply the display:block first, thus making the element visible before its src attribute is set.
Demo: http://jsfiddle.net/F8Q44/19/
Thanks to shoky in #jquery of freenode IRC for providing a simpler answer.
Alternatively, you can force a redraw to flush the batched style changes. This can be done, for example, by accessing the element's offsetHeight property:
$('img').show().each(function() {
this.offsetHeight;
}).prop('src', 'image src');
Demo: http://jsfiddle.net/F8Q44/266/
Just because I still need this every now and then I figured the pure JS function I use might be helpful for someone else. This is a pure JS way of restarting an animated gif, without reloading it. You can call this from a link and/or document load event.
<img id="img3" src="../_Images/animated.gif">
<a onClick="resetGif('img3')">reset gif3</a>
<script type="text/javascript">
// reset an animated gif to start at first image without reloading it from server.
// Note: if you have the same image on the page more than ones, they all reset.
function resetGif(id) {
var img = document.getElementById(id);
var imageUrl = img.src;
img.src = "";
img.src = imageUrl;
};
</script>
On some browsers you only need to reset the img.src to itself and it works fine. On IE you need to clear it before resetting it. This resetGif() picks the image name from the image id. This is handy in case you ever change the actual image link for a given id because you do not have to remember to change the resetGiF() calls.
--Nico
This solution preloads the gif and takes it out of the dom and then back in the src (thus avoiding another download)
I just tested it using jquery to remove the attribute and it works fine.
Example:
<html>
<head>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js" type="text/javascript"></script>
<script>
$(function() {
$('.reset').click(resetGif);
function resetGif()
{
$('.img1').removeAttr('src', '');
}
});
</script>
</head>
<body>
<img class="img1" src="1.gif" />
reset gif
</body>
</html>
This seemed to work for me in Chrome, it runs each time just before I fade in the image and clears then refills the src and my animation now starts from the beginning every time.
var imgsrc = $('#my_image').attr('src');
$('#my_image').attr('src', '');
$('#my_image').attr('src', imgsrc);
I've a button with the an animated no-loop image in it. I just reload the image with some jquery and this seems to be working for me.
var asdf = $(".settings-button img").attr("src");
$(".settings-button img").attr("src", "").attr("src", asdf);
here's my hack for background images:
$(document).on('mouseenter', '.logo', function() {
window.logo = (window.logocount || 0) + 1;
var img = new Image();
var url = "/img/mylogimagename.gif?v=" + window.logocount;
var that = this;
$(img).load(function(){
$(that ).css('background-image','url(' + url + ')');
});
img.src = url;
});
I experienced problems with all of the above solutions. What finally worked was replacing the src temporarily with a transparent 1px gif:
var transparent1PxGif = 'data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7';
var reloadGif = function(img) {
var src = img.src;
img.src = transparent1PxGif;
img.offsetHeight; // triggers browser redraw
img.src = src;
};
It's been several years and I've decided to revisit this since we have a number of new options at our disposal.
The issue with my previous answer is that it forces a re-download of the GIF every single time you want to re-start it. While that's fine for small files, it's still an overhead that's best avoided if possible.
With that in mind, I've got a new solution that uses AJAX to download the GIF once, and then converts it into a data URL (via a FileReader) and uses that as the source with a random query string attached.
This way, the browser only ever downloads the image once, and can even cache it properly, and the "reset" pulls from that pre-downloaded resource.
The only catch, of course, is that you have to make sure it's properly loaded before you can use it.
Demo: http://adamhaskell.net/misc/numbers/numbers.html
Relevant code:
var url = "something.gif"; // fallback until the FileReader is done
function setup() {
var xhr = new XMLHttpRequest();
xhr.open("GET",url,true);
xhr.responseType = "blob";
xhr.onreadystatechange = function() {
if( this.readyState == 4) {
var fr = new FileReader();
fr.onload = function() {
url = this.result; // overwrite URL with the data one
};
fr.readAsDataURL(this.response);
}
};
xhr.send();
}
function getGIF() {
return url+"?x="+Math.random();
}
Reset gif animation
When the browser render img, the source specified in src attribute is cached into memory for future reuse. This allows to increase the speed of page loading/reloading, as well as reduce the load on the network. And this behavior suits mostly everyone, because in reality, this is the most optimal and demanded option.
However, as always, there are exceptions. I came up with a dataUrl-based animation update option that solves several problems.
Issues solved:
Need to display gif images with animation without a loop (loop = 1), which may have the same src. But when one such picture appears, it is necessary that it play the animation without changing the animation of other pictures with the same src. The same picture should be loaded from server only once. Stackoverflow
Reset gif animation.
Start animation on hover
Reset src attribute
If we use a solution that clears the src attribute of an image, then all images with the same source will replay their animation. Unfortunately, I still did not fully understand why this is happening, but it interferes with correct work.
Cons
Reset animation of all images with the same src.
There are problems in mobile devices
Pros
Easy and fast
Modify url with random query
This solution consists in adding a random query parameter to the end of the src attribute, so that all images will have a different source, and therefore they will animate independently of each other. There is one big fat NO: this will lead to a constant request to the server to download the picture, and therefore they will no longer be cached. And if we need to display 100 identical pictures, then there will be 100 requests to the server. Rough and tough, but it always works.
Cons
Each picture with a unique query will be reloaded from the server.
Pros
Easy and fast
Modify dataUrl (Proposed Solution)
Data URLs, URLs prefixed with the data: scheme, allow content creators to embed small files inline in documents. They were formerly known as "data URIs" until that name was retired by the WHATWG.
MDN
The dataUrl structure from this documentation:
data:[<mediatype>][;base64],<data>
And this is how it is indicated in the specification:
dataurl := "data:" [ mediatype ] [ ";base64" ] "," data
mediatype := [ type "/" subtype ] *( ";" parameter )
data := *urlchar
parameter := attribute "=" value
If you look closely at the description of mediatype, then some strange parameter is indicated there. But, there is also a specification:
attribute := token
; Matching of attributes
; is ALWAYS case-insensitive.
value := token / quoted-string
token := 1*<any (US-ASCII) CHAR except SPACE, CTLs, or tspecials>
tspecials := "(" / ")" / "<" / ">" / "#" /
"," / ";" / ":" / "\" / <">
"/" / "[" / "]" / "?" / "="
; Must be in quoted-string,
; to use within parameter values
As can be seen, we can specify any parameter, the main thing is that it meets the requirements presented above!
Therefore, we can embed an additional attribute in the mediatype, which will not affect the image in any way, but the data url will differ from the same image.
Generalized algorithm:
We load the image through a regular request and remove the metadata from created dataUrl from blob.
fetch("https://cdn140.picsart.com/330970106009201.gif").then(async (res) => {
const blob = await res.blob();
const reader = new FileReader();
reader.onload = (ev) => {
// It would be reasonable to remove metadata to the point!
// But for simplicity, I'm using this implementation.
const dataUrl = ev.currentTarget.result.replace(
"data:image/gif;base64",
""
);
};
reader.readAsDataURL(blob);
});
Create/edit img element with src attribute "src=data:image/gif;base64;${Math.random()}${dataUrl}"
That is all!
Example Vanila JS
const url = "https://cdn140.picsart.com/330970106009201.gif";
function loadImage(src) {
fetch(src)
.then((res) => res.blob())
.then(async(blob) => {
const reader = new FileReader();
reader.onload = (ev) => {
const dataUrl = ev.currentTarget.result.replace("data:image/gif;base64", "")
const container = document.getElementById("container");
while (container.firstChild) {
container.firstChild.remove()
}
for (let i = 0; i < 6; i++) {
const img = document.createElement("img");
img.setAttribute("src", `data:image/gif;base64;gif-id=${Date.now()}${dataUrl}`)
container.appendChild(img);
img.addEventListener('click', ev => {
img.setAttribute("src", `data:image/gif;base64;gif-id=${Date.now()}${dataUrl}`)
})
}
};
reader.readAsDataURL(blob);
});
}
loadImage(url);
function updateImage() {
const newSrc = document.getElementById("image-src");
loadImage(document.getElementById("image-src").value);
}
#main {
display: flex;
flex-direction: column;
gap: 5px;
}
img {
width: 128px;
height: 128px;
padding: 5px;
}
<div id="main">
<label>Change gif url if current will become unavailable </label>
<input id="image-src" value="https://cdn140.picsart.com/330970106009201.gif"></input>
<button onclick="updateImage()">Update image source attribute</button>
<span>Click to reset!</span>
<div id="container">
</div>
</div>
Example React
import React, { useState, useRef } from "react";
function App() {
const [stars, setStars] = useState(0);
const [data, setData] = useState(null);
const ref = useRef(null);
React.useEffect(() => {
fetch("https://cdn140.picsart.com/330970106009201.gif")
.then((res) => res.blob())
.then(async (text) => {
const reader = new FileReader();
reader.onload = (ev) => {
setData(ev.currentTarget.result.replace("data:image/gif;base64", ""));
};
reader.readAsDataURL(text);
});
}, []);
return (
<React.Fragment>
<p onClick={() => setStars((s) => s + 1)}>+</p>
{data &&
new Array(stars).fill().map((s, ind) => {
return <Star src={data} key={ind}></Star>;
})}
<p onClick={() => setStars((s) => (s === 0 ? 0 : s - 1))}>-</p>
</React.Fragment>
);
}
export function Star(props) {
const [id] = useState(Math.random());
return (
<img
className="icon"
src={`data:image/gif;base64;gif-id=${id}` + props.src}
alt="animated star"
/>
);
}
export default App;
I came across this thread after searching many others. David Bell's post led me to the solution I needed.
I thought I'd post my experience in the event that it could be useful for anyone trying to accomplish what I was after. This is for an HTML5/JavaScript/jQuery web app that will be an iPhone app via PhoneGap. Testing in Chrome.
The Goal:
When user taps/clicks button A, an animated gif appears and plays.
When user taps/clicks button B, gif disappears.
When user taps/clicks button A again, after tapping/clicking button
B, animated gif should reappear and play from the beginning.
The Problem:
On tap/click of button A, I was appending the gif to an existing div. It would play fine.
Then, on tap/click of button B, I was hiding the container div, then setting the img src of the gif to an empty string (''). Again, no problem (that is, the problem wasn't evident yet.)
Then, on tap/click of button A, after tap/click of button B, I was re-adding the path to the gif as the src.
- This did not work. The gif would show up on subsequent taps/clicks of button A...however, the more I tapped/clicked button A, the more times the gif would load and start over. That is, if I went back and forth, tapping/clicking button A then button B 3 times, the gif would appear and then start/stop/start 3 times...and my whole app started to chug. I guess the gif was being loaded multiple times, even though I had set the src to an empty string when button B was tapped/clicked.
The Solution:
After looking at David Bell's post, I arrived at my answer.
I defined a global variable (let's call it myVar) that held the container div and the image (with the source path) within.
On the tap/click function of button A, I appended that container div to an existing parent div in the dom.
In that function, I created a new variable that holds the src path of the gif.
Just like David suggested, I did this (plus an append):
$('#mainParent').append(myVar);
var imgsrc = $('#my_image').attr('src');
$('#my_image').attr('src', '');
$('#my_image').attr('src', imgsrc);
THEN, in the function for button B, I set the src to an empty string and then removed the div containing the gif:
$('#my_image').attr('src', '');
$('#mainParent').find('#my_image').remove();
Now, I can tap/click button A then button B then button A, etc., all day long. The gif loads and plays on tap/click of button A, then hides on tap/click of button B, then loads and plays from the beginning on subsequent taps of button A every time with no issues.
I worked out a complete solution for this problem. It can be found here: https://stackoverflow.com/a/31093916/1520422
My solution restarts the animation WITHOUT re-loading the image data from the network.
It also enforces the image to repaint to fix some painting artefacts that occured (in chrome).
I have a web page where lots of images called from server using image
scr attribute.
I have created a function like which is triggered by td click.
function GoToStep(stepNo) {
var imgSrc = $("#h1" + stepNo).val();
$(".img_vertical").css("background-image", "url(" + imgSrc + ")");
}
Now the problem is this. For slower connections the images come after some
moment.
Can I pre load images to avoid waiting time when user clicks
td?
I have seen some jquery function to pre load images.
Kindly give some idea how can I achieve it.
Pre-loading an image is equivalent to loading an image but never displaying it. So, you can easily do it like this:
<img src="image.png" alt="" style="display:none;"/>
Now this image will be loaded as soon as the html starts rendering. Whenever you need to use this image as a display or background, just set the address to image.png and it will automatically be fetched from browser's cache.
This can be done using some javascript functions. Quoting from another question.
function preload(arrayOfImages) {
$(arrayOfImages).each(function(){
$('<img/>')[0].src = this;
// Alternatively you could use:
// (new Image()).src = this;
});
}
// Usage:
preload([
'img/imageName.jpg',
'img/anotherOne.jpg',
'img/blahblahblah.jpg'
]);
Explanation of how javascript preloaders work (different question)
[...] The way it works is simply by creating a new Image object and setting
the src of it, the browser is going to go grab the image. We're not
adding this particular image to the browser, but when the time comes
to show the image in the page via whatever method we have setup, the
browser will already have it in its cache and will not go fetch it
again. [...]
So in your case, you should use something like
$(function() {
// Do stuff when DOM is ready
preload([
'img/bg1.jpg',
'img/bg2.jpg',
'img/bg3.jpg'
]);
});