Get selected check boxes values from table using Java script - javascript

I was using select Person_name = $('#selectedPerson').val()
person_name.length is showing 2 if selected 2 values.
Now i have changed to check boxes which is in table. If i am using person_name= document.getElementById("selectedPerson").innerText, person_name.length is not working. It is taking length of the content. I want to count of the person and it is value which i am selecting in check-boxes.
Thanks,
Raja.

Side note: an ID should only ever be applied to one element, so you want .selectedPerson not #selectedPerson if it's going to select two things.
var people = $('.selectedPerson');
var count = people.count;
var name = people.text();

Related

To count the number of controls and print their Id into an alert box

To count the number of contols and print their Id into an alert box
I need help with my code
I am trying to count the number of contols in my webpage and display onto the alert box
Example
Textbox: 2
Buttons: 3
Radio buttons: 5
Drop down:3
Listbox: 1
I have used getElementsByTagName("INPUT") and getElementsByTagName("SELECT"). For the input fields I have no problem, but for the select I have to differentiate between for example drop down list or list box and more
i have tried this for listbox but it isnt working
var search_term = "lst"; // search term
var search = new RegExp(search_term, "i");
var arr = jQuery.grep(y, function (value) {
return search.test(value);
});
And secondly after using getElementsByTagName("INPUT") I filter again on type(text,checkbox,radio) I want to extract the Id and push it onto an array
You can use querySelectorAll method instead of getElementByTag name and use CSS selectors for selecting elements. for example Using
document.querySelectorAll('input[type="text"]')
selects all of inputs with type="text" and so on
You can get classes of a DOM element by classList method and id for getting ids
console.log(document.querySelectorAll('#foo')[0].id); // prints foo
and
console.log(document.querySelectorAll('#foo')[0].classList); // prints list of element possible classes

Create a function to hide divs

I want to display tables when a selection is made in a form and a 'Generate Factsheet' button is clicked. I've got a working code where I individually hide other divs when displaying the one I am interested in. Since I have several options in the form (and hence several corresponding divs in which the respective tables are enclosed), the final code appears bulky. I want to write a function to hide other divs whiles displaying the one I am interested in. This is the code I currently have:
var tableDivs = ['tableOPVDiv','tablePneumoDiv','tableRotaDiv'];
var selectedVaccine;
var selectedTableDiv;
function generateFactsheetFunction(){
// Selecting the vaccine chosen from the dropdown
var e = document.getElementById("selectVaccine");
selectedVaccine = e.options[e.selectedIndex].text;
console.log("selectedVaccine: ", selectedVaccine);
if (selectedVaccine=="Rotavirus Vaccine"){
selectedTableDiv='tableRotaDiv';
console.log("rotavirus selected");
hideOtherTables();
} else if (selectedVaccine=="Polio Vaccine"){
console.log("polio selected");
selectedTableDiv='tableOPVDiv';
hideOtherTables();
} else if (selectedVaccine=="Pneumococcal Vaccine"){
console.log("pneumo selected");
selectedTableDiv='tablePneumoDiv';
hideOtherTables();
}
}
function hideOtherTables(){
var testa = tableDivs.indexOf(selectedTableDiv);
console.log("tableDivs[testa]: ", tableDivs[testa]);
console.log("testa: ", testa);
testb = tableDivs[testa];
console.log("testb: ", testb);
document.getElementById(tableDivs[testa]).style.display="block";
/*var newTableDivs=tableDivs.splice(testa);*/
/*for (y=0;y<newTableDivs.length;y++){
document.getElementById(newTableDivs[y]).style.display="none";
}*/
}
The uncommented part works fine. In the commented part, I want to say that for all array elements other than selectedVaccine, I want the display to be:
document.getElementById(tableDivs[testa]).style.display="none";
I cannot splice the data because the selections are repititive (the selections are from a form). What is the way to set the visibility of tableDivs associated with other selections to be none.
Why should you change the display property of each and every division seperately? give a common class name to all the divisions and hide them all at once and then display only the required table.
$(".yourClass").hide();
document.getElementById(tableDivs[testa]).style.display="block";
You will have to use the jQuery Library too.
If you are not familiar with jQuery then use the for loop to hide all the tables first and then display only the required table.
for (y=0;y<TableDivs.length;y++){//you need not create newTableDivs
document.getElementById(TableDivs[y]).style.display="none";
}
document.getElementById(tableDivs[testa]).style.display="block";
i.e you just have to interchange the order of execution. ;)
Cannot read property 'style' of null this means that document.getElementById(tableDivs[y]) return null and can not find this element
try to write
document.getElementById("ElementId")

How to get values of 2 sides of jquery multiselect2side

Here's the jsfiddle for the code http://jsfiddle.net/VFskn/2/
The jquery multiselect2side has 2 parts for the list say the Available and Selected
a.To get the values of Selected portion of the I used the following code:
var multipleValues = $("#columnList").val() || [];
b. To get all values of the list I can use:
$('#columnList option').each(function() {
columns.push( $(this).attr('value') );
});
My Question is how I can obtain the Available portion of the list
If I understand your question right, you want to get the value of every option that is in the select under Available?
In the given example this select has the id "columnListms2side__sx", so that you can get the values of its options with
var multipleValues = [];
$("#columnListms2side__sx option").each(function()
{
multipleValues.push($(this).val())
});
here's the updated fiddle: http://jsfiddle.net/VFskn/3/
!important notes though: its not a good idea to mess with it, other then the functions provided by the plugin.
And I'm not sure how safe it is too assume that this select will allways get this id (e.g. if you have multiple of them in one page). It might be smarter to, build a more generic select. (the plugin seems to create a div container after the select it replaces, you want to get the first select in there)
EDIT:
this would be more generic, but less efficient:
$("#columnList").next().find("select").filter(":first").children().each(function(){...}
updated fiddle: http://jsfiddle.net/VFskn/4/

Getting the Control inside a table

I'm trying to get the control which is inside of a cell table; in my table I have different controls, labels, checkboxes, etc.
I basically need to get the control which is used in that table
var x = document.getElementById('myTable').rows[0].cells;
alert(x[0].innerText);
//alert(x[3].innerHTML);
if (x.Control == checkbox) {
x.checked = true;
}
This will be in a loop but for now I just need to be able to check the checkbox by grabbing the control and setting that control to true
Any hints/help would be great
I doesn't really understand what you exactly need is it
document.getElementById("checkbox").checked = true;
here checkbox is the id of a particular checkbox
I would put a unique id on the form element instead and use that to grab it. In this way you can change the structure in the future. Example: perhaps you no longer want to use a table grid, but a grid of divs.
When you use innerHTML you will might also grab textnodes and other things you put in the cell.
An alternative - if you really want to find a specific cell in a table - is to give each cell a unique id on the form "cell-4-5" where 4 is the row and 5 is the column.
[EDIT]
If you want to have the cell contents returned as a DOM-object then childNodes can be used:
var x = document.getElementById('myTable').childNodes[0].childNodes[0].childNodes
If you want to have the cell contents returned as a string then innerHTML can be used:
var x = document.getElementById('myTable').childNodes[0].childNodes[0].innerHTML
To check if the checkbox is checked you need to keep it as a DOM element and thus use the first version.

switching selections between two select menus

I'm trying to build some kind of currency converter and I have two select menus with the list of currencies.
I want to create a button that when clicked, it will switch the selection between the "from" select menu and the "to" select menu.
how do I implement it using the select menus I already have?
I believe you'r looking for a swap behavior.
http://jsfiddle.net/brentmn/D55Dm/
$(function(){
var $sel1 = $('#currency1');
var $sel2 = $('#currency2');
$('input[type=button]').click(function(){
var val1 = $sel1.val();
var val2 = $sel2.val();
$sel2.val(val1);
$sel1.val(val2);
//jqueryui
//$sel2.val(val1).trigger('change');
//$sel1.val(val2).trigger('change');
});
});
Something like this?
$("#button").on("click", function() {
var from = $("#from").val();
var to = $("#to").val();
$("#from").val(to);
$("#to").val(from);
});
I'd really do it with less code than that, but have done it like that for readability.
Assuming I've understood you correctly, you want a button that will swap the values of two select elements. If that's right, try something along these lines:
$("#someButton").click(function() {
var elemTo = $("#to"),
elemFrom = $("#from"),
toVal = elemTo.val();
elemTo.val(elemFrom.val());
elemFrom.val(toVal);
});
It simply gets references to the two select elements (assumed here to be #to and #from), gets the value of one of them, replaces the value of that one with the value of the other, and then replaces the value of the second with the stored value from the first.
Note that this assumes both select elements have the same option values. If an option is present in one select but not the other, it would not work.
Here's a working example.
If you dbl click on one item in 'From' section , it will get selected be appended to the 'To' section.
$("#selectFrom").dblclick(function(){
$selectTo.append($selectFrom.children(":selected"));
});
Which all functionalities you want??

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