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I have prototypes to recreate how array methods work, pop/push/shift/etc, and I would like to extend the functionality to do the following:
Push/Pop/shift/unshift multiple values
array.push(0);
array.push(1);
array.push(2);
expect(array.pop()).to.be(2);
expect(array.pop()).to.be(1);
expect(array.pop()).to.be(0);
Push/Pop/unshift/etc single values
array.push(0);
array.push(1);
expect([0,1]);
array.pop(1);
expect([0]);
My assumption is that I would need a global array variable to store the elements. Is that the right?
Here is my code:
var mainArray = []; // array no longer destroyed after fn() runs
function YourArray(value) {
this.arr = mainArray; // looks to global for elements | function?
this.index = 0;
var l = mainArray.length;
if(this.arr === 'undefined')
mainArray += value; // add value if array is empty
else
for(var i = 0; i < l ; i++) // check array length
mainArray += mainArray[i] = value; // create array index & val
return this.arr;
}
YourArray.prototype.push = function( value ) {
this.arr[ this.index++ ] = value;
return this;
};
YourArray.prototype.pop = function( value ) {
this.arr[ this.index-- ] = value;
return this;
};
var arr = new YourArray();
arr.push(2);
console.log(mainArray);
My assumption is that I would need a global array variable to store
the elements. Is that the right?
No. That is not right.
You want each array object to have its own, independent set of data. Otherwise, how can you have multiple arrays in your program?
function YourArray(value) {
this.arr = []; // This is the data belonging to this instance.
this.index = 0;
if(typeof(value) != 'undefined')) {
this.arr = [value];
this.index = 1;
}
}
////////////////////////////////////
// Add prototype methods here
///////////////////////////////////
var array1 = new YourArray();
var array2 = new YourArray();
array1.push(2);
array1.push(4);
array2.push(3);
array2.push(9);
// Demonstrate that the values of one array
// are unaffected by the values of a different array
expect(array1.pop()).to.be(4);
expect(array2.pop()).to.be(9);
It's a bit late for this party, admitted but it nagged me. Is there no easy (for some larger values of "easy") way to do it in one global array?
The standard array functions work as in the following rough(!) sketch:
function AnotherArray() {
this.arr = [];
// points to end of array
this.index = 0;
if(arguments.length > 0) {
for(var i=0;i<arguments.length;i++){
// adapt if you want deep copies of objects
// and/or take a given array's elements as
// individual elements
this.arr[i] = arguments[i];
this.index++;
}
}
}
AnotherArray.prototype.push = function() {
// checks and balances ommitted
for(var i=0;i<arguments.length;i++){
this.arr[ this.index++ ] = arguments[i];
}
return this;
};
AnotherArray.prototype.pop = function() {
this.index--;
return this;
};
AnotherArray.prototype.unshift = function() {
// checks and balances ommitted
var tmp = [];
var alen = arguments.length;
for(var i=0;i<this.index;i++){
tmp[i] = this.arr[i];
}
for(var i=0;i<alen;i++){
this.arr[i] = arguments[i];
this.index++;
}
for(var i=0;i<tmp.length + alen;i++){
this.arr[i + alen] = tmp[i];
}
return this;
};
AnotherArray.prototype.shift = function() {
var tmp = [];
for(var i=1;i<this.index;i++){
tmp[i - 1] = this.arr[i];
}
this.arr = tmp;
this.index--;
return this;
};
AnotherArray.prototype.isAnotherArray = function() {
return true;
}
AnotherArray.prototype.clear = function() {
this.arr = [];
this.index = 0;
}
AnotherArray.prototype.fill = function(value,length) {
var len = 0;
if(arguments.length > 1)
len = length;
for(var i=0;i<this.index + len;i++){
this.arr[i] = value;
}
if(len != 0)
this.index += len;
return this;
}
// to simplify this example
AnotherArray.prototype.toString = function() {
var delimiter = arguments.length > 0 ? arguments[0] : ",";
var output = "";
for(var i=0;i<this.index;i++){
output += this.arr[i];
if(i < this.index - 1)
output += delimiter;
}
return output;
}
var yaa = new AnotherArray(1,2,3);
yaa.toString(); // 1,2,3
yaa.push(4,5,6).toString(); // 1,2,3,4,5,6
yaa.pop().toString(); // 1,2,3,4,5
yaa.unshift(-1,0).toString(); // -1,0,1,2,3,4,5
yaa.shift().toString(); // 0,1,2,3,4,5
var yaa2 = new AnotherArray();
yaa2.fill(1,10).toString(); // 1,1,1,1,1,1,1,1,1,1
Quite simple and forward and took only about 20 minutes to write (yes, I'm a slow typist). I would exchange the native JavaScript array in this.arr with a double-linked list if the content can be arbitrary JavaScript objects which would make shift and unshift a bit less memory hungry but that is obviously more complex and slower, too.
But to the main problem, the global array. If we want to use several individual chunks of the same array we need to have information about the starts and ends of the individual parts. Example:
var globalArray = [];
var globalIndex = [[0,0]];
function YetAnotherArry(){
// starts at the end of the last one
this.start = globalIndex[globalIndex.length-1][1];
this.index = this.start;
// position of the information in the global index
this.pos = globalIndex.length;
globalIndex[globalIndex.length] = [this.start,this.index];
}
So far, so well. We can handle the first array without any problems. We can even make a second one but the moment the first one wants to expand its array we get in trouble: there is no space for that. The start of the second array is the end of the first one, without any gap.
One simple solution is to use an array of arrays
globalArray = [
["first subarray"],
["second subarray"],
...
];
We can than reuse what we already wrote in that case
var globalArray = [];
function YetAnotherArray(){
// open a new array
globalArray[globalArray.length] = [];
// point to that array
this.arr = globalArray[globalArray.length - 1];
this.index = 0;
}
YetAnotherArray.prototype.push = function() {
for(var i=0;i<arguments.length;i++){
this.arr[ this.index++ ] = arguments[i];
}
return this;
};
// and so on
But for every new YetAnotherArray you add another array to the global array pool and every array you abandon is still there and uses memory. You need to manage your arrays and delete every YetAnotherArray you don't need anymore and you have to delete it fully to allow the GC to do its thing.
That will leave nothing but gaps in the global array. You can leave it as it is but if you want to use and delete thousands you are left with a very sparse global array at the end. Or you can clean up. Problem:
var globalArray = [];
function YetAnotherArray(){
// add a new subarray to the end of the global array
globalArray[globalArray.length] = [];
this.arr = globalArray[globalArray.length - 1];
this.index = 0;
this.pos = globalArray.length - 1;
}
YetAnotherArray.prototype.push = function() {
for(var i=0;i<arguments.length;i++){
this.arr[ this.index++ ] = arguments[i];
}
return this;
};
YetAnotherArray.prototype.toString = function() {
var delimiter = arguments.length > 0 ? arguments[0] : ",";
var output = "";
for(var i=0;i<this.index;i++){
output += this.arr[i];
if(i < this.index - 1)
output += delimiter;
}
return output;
}
// we need a method to delete an instance
YetAnotherArray.prototype.clear = function() {
globalArray[this.pos] = null;
this.arr = null;
this.index = null;
};
YetAnotherArray.delete = function(arr){
arr.clear();
delete(arr);
};
// probably won't work, just a hint in case of asynch. use
var mutex = false;
YetAnotherArray.gc = function() {
var glen, indexof, next_index, sub_len;
indexof = function(arr,start){
for(var i = start;i<arr.length;i++){
if (arr[i] == null || arr[i] == undefined)
return i;
}
return -1;
};
mutex = true;
glen = globalArray.length;
sublen = 0;
for(var i = 0;i<glen;i++){
if(globalArray[i] == null || globalArray[i] == undefined){
next_index = indexof(globalArray,i);
if(next_index == -1){
break;
}
else {
globalArray[i] = globalArray[next_index + 1];
globalArray[next_index + 1] = null;
sublen++;
}
}
}
globalArray.length -= sublen - 1;
mutex = false;
};
var yaa_1 = new YetAnotherArray();
var yaa_2 = new YetAnotherArray();
var yaa_3 = new YetAnotherArray();
var yaa_4 = new YetAnotherArray();
yaa_1.push(1,2,3,4,5,6,7,8,9).toString(); // 1,2,3,4,5,6,7,8,9
yaa_2.push(11,12,13,14,15,16).toString(); // 11,12,13,14,15,16
yaa_3.push(21,22,23,24,25,26,27,28,29).toString();// 21,22,23,24,25,26,27,28,29
yaa_4.push(311,312,313,314,315,316).toString(); // 311,312,313,314,315,316
globalArray.join("\n");
/*
1,2,3,4,5,6,7,8,9
11,12,13,14,15,16
21,22,23,24,25,26,27,28,29
311,312,313,314,315,316
*/
YetAnotherArray.delete(yaa_2);
globalArray.join("\n");
/*
1,2,3,4,5,6,7,8,9
21,22,23,24,25,26,27,28,29
311,312,313,314,315,316
*/
YetAnotherArray.gc();
globalArray.join("\n");
/*
1,2,3,4,5,6,7,8,9
21,22,23,24,25,26,27,28,29
311,312,313,314,315,316
*/
But, as you might have guessed already: it doesn't work.
YetAnotherArray.delete(yaa_3); // yaa_3 was 21,22,23,24,25,26,27,28,29
globalArray.join("\n");
/*
1,2,3,4,5,6,7,8,9
21,22,23,24,25,26,27,28,29
*/
We would need another array to keep all positions. Actual implementation as an exercise for the reader but if you want to implement a JavaScript like array, that is for arbitrary content you really, really, really should use a doubly-linked list. Or a b-tree. A b+-tree maybe?
Oh, btw: yes, you can do it quite easily with a {key:value} object, but that would have squeezed all the fun out of the job, wouldn't it? ;-)
Let's say we have the following js array
var ar = [
[2,6,89,45],
[3,566,23,79],
[434,677,9,23]
];
var val = [3,566,23,79];
Is there a js builtin function or jQuery one with which you can search the array ar for val?
Thanks
***UPDATE*************
Taking fusion's response I created this prototype
Array.prototype.containsArray = function(val) {
var hash = {};
for(var i=0; i<this.length; i++) {
hash[this[i]] = i;
}
return hash.hasOwnProperty(val);
}
you could create a hash.
var ar = [
[2,6,89,45],
[3,566,23,79],
[434,677,9,23]
];
var hash = {};
for(var i = 0 ; i < ar.length; i += 1) {
hash[ar[i]] = i;
}
var val = [434,677,9,23];
if(hash.hasOwnProperty(val)) {
document.write(hash[val]);
}
You can also use a trick with JSON serializing. It is short and simple, but kind of hacky.
It works, because "[0,1]" === "[0,1]".
Here is the working demo snippet:
Array.prototype.indexOfForArrays = function(search)
{
var searchJson = JSON.stringify(search); // "[3,566,23,79]"
var arrJson = this.map(JSON.stringify); // ["[2,6,89,45]", "[3,566,23,79]", "[434,677,9,23]"]
return arrJson.indexOf(searchJson);
};
var arr = [
[2,6,89,45],
[3,566,23,79],
[434,677,9,23]
];
document.body.innerText = arr.indexOfForArrays([3,566,23,79]);
function indexOfArray(val, array) {
var hash = {};
for (var i = 0; i < array.length; i++) {
hash[array[i]] = i;
}
return (hash.hasOwnProperty(val)) ? hash[val] : -1;
};
I consider this more useful for than containsArray(). It solves the same problem (using a hash table) but returns the index (rather than only boolean true/false).
Can you try this?
var ar = [
[2,6,89,45],
[3,566,23,79],
[434,677,9,23]
];
var val = [3,566,23,79];
var sval = val.join("");
for(var i in ar)
{
var sar = ar[i].join("");
if (sar==sval)
{
alert("found!");
break;
}
}
Why don't you use javascript array functions?
function filterArrayByValues(array, values) {
return array.filter(function (arrayItem) {
return values.some(function (value) {
return value === arrayItem;
});
});
}
Or if your array is more complicated, and you want compare only one property but as result return whole object:
function filterArrayByValues(array, values, propertyName) {
return array.filter(function (arrayItem) {
return values.some(function (value) {
return value === arrayItem[propertyName];
});
});
}
More about used functions: filter() and some()
You can use Array.prototype.some(), Array.prototype.every() to check each element of each array.
var ar = [
[2, 6, 89, 45],
[3, 566, 23, 79],
[434, 677, 9, 23]
];
var val = [3, 566, 23, 79];
var bool = ar.some(function(arr) {
return arr.every(function(prop, index) {
return val[index] === prop
})
});
console.log(bool);
I guess there is no such JS functionality available. but you can create one
function arrEquals( one, two )
{
if( one.length != two.length )
{
return false;
}
for( i = 0; i < one.length; i++ )
{
if( one[i] != two[i] )
{
return false;
}
}
return true;
}
The problem with this is that of object/array equality in Javascript. Essentially, the problem is that two arrays are not equal, even if they have the same values. You need to loop through the array and compare the members to your search key (val), but you'll need a way of accurately comparing arrays.
The easiest way round this is to use a library that allows array/object comparison. underscore.js has a very attractive method to do this:
for (var i = 0; i < ar.length; i++) {
if (_.isEqual(ar[i], val)) {
// value is present
}
}
If you don't want to use another library (though I would urge you to -- or at least borrow the message from the Underscore source), you could do this with JSON.stringify...
var valJSON = JSON.stringify(val);
for (var i = 0; i < ar.length; i++) {
if (valJSON === JSON.stringify(ar[i]) {
// value is present
}
}
This will almost certainly be significantly slower, however.
You can use toString convertion to compare elements
var ar = [
[2,6,89,45],
[3,566,23,79],
[434,677,9,23]
];
var val = [3,566,23,79];
s = !ar.every(a => (a.toString() != val.toString()));
console.log(s) // true
Use this instead
if (ar.join(".").indexOf(val) > -1) {
return true;
} else {
return false;
}
Use lodash isEqual
const isValIncludedInAr = ar.some(element => isEqual(element, val))
const arrayOne = [2,6,89,45];
const arrayTwo = [3,566,23,79];
const arrayThree = [434,677,9,23];
const data = new Set([arrayOne, arrayTwo, arrayThree]);
// Check array if exist
console.log( data.has(arrayTwo) ); // It will return true.
// If you want to make a set into array it's simple
const arrayData = [...data];
console.log(arrayData); // It will return [[2,6,89,45], [3,566,23,79], [434,677,9,23]]
I have a JSON array which looks like this:
var map_results = [{"Type":"Flat","Price":100.9},
{"Type":"Room","Price":23.5},
{"Type":"Flat","Price":67.5},
{"Type":"Flat","Price":100.9}
{"Type":"Plot","Price":89.8}]
This array contains about 100,000 records. I want the output to be grouped by "Type" and "Price". It should look like this:
var expected_output = [{"Type":"Flat", "Data":[{"Price":100.9, "Total":2},
{"Price":67.5, "Total":1}] },
{"Type":"Room","Data":[{"Price":23.5,"Total":1}]},
{"Type":"Plot","Data":[{"Price":89.8, "Total:1"}]}]
This has to be done in pure javascript and I cannot use libraries like undersore.js. I tried solving the problem but it had like 3 nested for loops which made the complexity as n^4. What could be a better solution for this problem??
The function I have looks like this:
var reduce = function (map_results) {
var results = [];
for (var i in map_results) {
var type_found = 0;
for(var result in results){
if (map_results[i]["Type"] == results[result]["Type"]){
type_found = 1;
var price_found = 0;
for(var data in results[result]["Data"]){
if(map_results[i]["Price"] == results[result]["Data"][data]["Price"]){
price_found = 1;
results[result]["Data"][data]["Total"] +=1;
}
}
if(price_found == 0){
results[result]["Data"].push({"Price":map_results[i]["Price"], "Total":1});
}
}
}
if(type_found == 0){
results.push({"Type":map_results[i]["Type"], "Data":[{"Price":map_results[i]["Price"],"Total":1}]});
}
}
return results;
};
I have a short function that handles the first part of the requested functionality: It maps the map_results to the desired format:
var map_results = [{"Type":"Flat","Price":100.9},
{"Type":"Room","Price":23.5},
{"Type":"Flat","Price":67.5},
{"Type":"Flat","Price":100.9},
{"Type":"Plot","Price":89.8}]
var expected_output = map_results.reduce(function(obj, current){
if(!obj[current.Type]){
obj[current.Type] = {'Type':current.Type, 'Data':[]};
}
obj[current.Type].Data.push({'Price':current.Price, 'Total':1});
return obj;
},{})
Then this piece of code is required to calculate the totals, I'm afraid:
for(var type in expected_output){
var d = {};
for(var item in expected_output[type].Data){
d[expected_output[type].Data[item].Price] = (d[expected_output[type].Data[item].Price] || 0) + 1;
}
expected_output[type].Data = [];
for(var i in d){
expected_output[type].Data.push({
'Price':i,
'Total':d[i]
})
}
}
Output:
{
"Flat":{
"Type":"Flat",
"Data":[{"Price":"100.9","Total":2},
{"Price":"67.5","Total":1}]
},
"Room":{
"Type":"Room",
"Data":[{"Price":"23.5","Total":1}]
},
"Plot":{
"Type":"Plot",
"Data":[{"Price":"89.8","Total":1}]
}
}
As the Types and the Prices are unique after grouping I think a structure like {"Flat": {"100.9":2,"67.5":1}, {"Room": {"23.5": 1}}} would be easier to handle. So could do the grouping the following way:
var output = {};
map_results.map(function(el, i) {
output[el["Type"]] = output[el["Type"]] || [];
output[el["Type"]][el["Price"] = (output[el["Type"]][el["Price"]+1) || 1;
});
If you can not handle this structure you could do another mapping to your structure.
As you are iterating the Array one time this should have a complexity of n.
Look here for a working fiddle.
EDIT: So remap everything to your structure. The order of the remapping is far less then the first mapping, because the grouping is already done.
var expected_output = [];
for(type in output) {
var prices = [];
for(price in output[type]) {
prices.push({"Price": price, "Total": output[type][price]);
}
expected_output.push({"Type": type, "Data": prices});
}
Below is yet another effort. Here's a FIDDLE
For performance testing, I also mocked up a JSPerf test with 163840 elements. On Chrome(OSX) original solution is 90% slower than this one.
Few notes:
Feel free to optimize for your case (e.g. take out the hasOwnProperty check on object cloning).
Also, if you need the latest Total as the first element use unshift instead of push to add the obj the beginning of the array.
function groupBy(arr, key, key2) {
var retArr = [];
arr.reduce(function(previousValue, currentValue, index, array){
if(currentValue.hasOwnProperty(key)) {
var kVal = currentValue[key];
if(!previousValue.hasOwnProperty(kVal)) {
previousValue[kVal] = {};
retArr.push(previousValue[kVal]);
previousValue[kVal][key] = kVal;
previousValue[kVal]["Data"] = [];
}
var prevNode = previousValue[kVal];
if(currentValue.hasOwnProperty(key2)) {
var obj = {};
for(var k in currentValue) {
if(currentValue.hasOwnProperty(k) && k!=key)
obj[k] = currentValue[k];
}
obj["Total"] = prevNode["Data"].length + 1;
prevNode["Data"].push(obj);
}
}
return previousValue;
}, {});
return retArr;
}
var map_results = [{"Type":"Flat","Price":100.9},
{"Type":"Room","Price":23.5},
{"Type":"Flat","Price":67.5},
{"Type":"Flat","Price":100.9},
{"Type":"Plot","Price":89.8}];
var expected_output = groupBy(map_results, "Type", "Price");
console.dir(expected_output);
Tried something like this:
var reduce_func = function (previous, current) {
if(previous.length == 0){
previous.push({Type: current.Type, Data:[{Price:current.Price,Total:1}]});
return previous;
}
var type_found = 0;
for (var one in previous) {
if (current.Type == previous[one].Type){
type_found = 1;
var price_found = 0;
for(var data in previous[one].Data){
if(current.Price == previous[one].Data[data].Price){
price_found = 1;
previous[one].Data[data].Total += 1;
}
}
if(price_found == 0){
previous[one].Data.push({Price:current.Price, Total:1});
}
}
}
if(type_found == 0){
previous.push({Type:current.Type, Data:[{Price : current.Price ,Total:1}]});
}
return previous;
}
map_results.reduce(reduce_func,[]);
I have tag like this, how the best way to get every key and value of those attribute and populate it within an array (number of attribute will be increasing)?
myData = '[data attr1="value1" attr2="value2" attr3="value3"]';
and get result array :
var arr = new Array();
arr['attr1'] = "value1";
arr['attr2'] = "value2";
arr['attr3'] = "value3";
and so on...
This probably does what you want, though it assumes that tag is already in the format you have described, i.e. a singular occurrence of [data ... ].
Also, the regular expression is purely based on what I've seen in your question; not sure whether it will break on other strings.
function decode(tag)
{
var r = /(\w+)="([^"]*)"/g,
h = {};
while ((m = r.exec(tag)) !== null) {
h[m[1]] = m[2];
}
return h;
}
Since you have string key in the data, use jquery object instead of array.
var arr = {};
var str = '[data attr1="value1" attr2="value2" attr3="value3"]';
var n = str.split('[data ');
var str_arr = n[1].replace(']','').split(" ");
jQuery.each(str_arr,function(val){
var x = str_arr[val].split('=');
arr[x[0]] = x[1].replace('"','').slice(0,-1);
});
console.log(arr);
Try this code. It may help you.
Here is the DEMO
Though it can be more optimized if you put some more details about your code.
var tagRe = /\[(\w+)((?:\s+\w+="[^"]{0,50}")*)\s*]/g;
var attrRe = /\b(\w+)="([^"]*)"/g;
function parse(text) {
var result = [];
tagRe.lastIndex = 0; // reset start position
var tagMatch = tagRe.exec(text);
while (tagMatch) {
var currentTag = { 'name': tagMatch[1], 'attrs': {} };
var attrString = tagMatch[2];
attrRe.lastIndex = 0;
var attrMatch = attrRe.exec(attrString);
while (attrMatch) {
var attrName = attrMatch[1];
var attrValue = attrMatch[2];
currentTag.attrs[attrName] = attrValue;
attrMatch = attrRe.exec(attrString); // next match
}
result.push(currentTag);
tagMatch = tagRe.exec(text);
}
return result;
}
parse('[data attr1="value1" attr2="value2" attr3="value3"]');
> [{name:'data',attrs:{attr1:'value1',attr2:'value2',attr3:'value3'}}]
This works for any number of tags in the string. The name of the tag does not matter.
Let's say we have the following js array
var ar = [
[2,6,89,45],
[3,566,23,79],
[434,677,9,23]
];
var val = [3,566,23,79];
Is there a js builtin function or jQuery one with which you can search the array ar for val?
Thanks
***UPDATE*************
Taking fusion's response I created this prototype
Array.prototype.containsArray = function(val) {
var hash = {};
for(var i=0; i<this.length; i++) {
hash[this[i]] = i;
}
return hash.hasOwnProperty(val);
}
you could create a hash.
var ar = [
[2,6,89,45],
[3,566,23,79],
[434,677,9,23]
];
var hash = {};
for(var i = 0 ; i < ar.length; i += 1) {
hash[ar[i]] = i;
}
var val = [434,677,9,23];
if(hash.hasOwnProperty(val)) {
document.write(hash[val]);
}
You can also use a trick with JSON serializing. It is short and simple, but kind of hacky.
It works, because "[0,1]" === "[0,1]".
Here is the working demo snippet:
Array.prototype.indexOfForArrays = function(search)
{
var searchJson = JSON.stringify(search); // "[3,566,23,79]"
var arrJson = this.map(JSON.stringify); // ["[2,6,89,45]", "[3,566,23,79]", "[434,677,9,23]"]
return arrJson.indexOf(searchJson);
};
var arr = [
[2,6,89,45],
[3,566,23,79],
[434,677,9,23]
];
document.body.innerText = arr.indexOfForArrays([3,566,23,79]);
function indexOfArray(val, array) {
var hash = {};
for (var i = 0; i < array.length; i++) {
hash[array[i]] = i;
}
return (hash.hasOwnProperty(val)) ? hash[val] : -1;
};
I consider this more useful for than containsArray(). It solves the same problem (using a hash table) but returns the index (rather than only boolean true/false).
Can you try this?
var ar = [
[2,6,89,45],
[3,566,23,79],
[434,677,9,23]
];
var val = [3,566,23,79];
var sval = val.join("");
for(var i in ar)
{
var sar = ar[i].join("");
if (sar==sval)
{
alert("found!");
break;
}
}
Why don't you use javascript array functions?
function filterArrayByValues(array, values) {
return array.filter(function (arrayItem) {
return values.some(function (value) {
return value === arrayItem;
});
});
}
Or if your array is more complicated, and you want compare only one property but as result return whole object:
function filterArrayByValues(array, values, propertyName) {
return array.filter(function (arrayItem) {
return values.some(function (value) {
return value === arrayItem[propertyName];
});
});
}
More about used functions: filter() and some()
You can use Array.prototype.some(), Array.prototype.every() to check each element of each array.
var ar = [
[2, 6, 89, 45],
[3, 566, 23, 79],
[434, 677, 9, 23]
];
var val = [3, 566, 23, 79];
var bool = ar.some(function(arr) {
return arr.every(function(prop, index) {
return val[index] === prop
})
});
console.log(bool);
I guess there is no such JS functionality available. but you can create one
function arrEquals( one, two )
{
if( one.length != two.length )
{
return false;
}
for( i = 0; i < one.length; i++ )
{
if( one[i] != two[i] )
{
return false;
}
}
return true;
}
The problem with this is that of object/array equality in Javascript. Essentially, the problem is that two arrays are not equal, even if they have the same values. You need to loop through the array and compare the members to your search key (val), but you'll need a way of accurately comparing arrays.
The easiest way round this is to use a library that allows array/object comparison. underscore.js has a very attractive method to do this:
for (var i = 0; i < ar.length; i++) {
if (_.isEqual(ar[i], val)) {
// value is present
}
}
If you don't want to use another library (though I would urge you to -- or at least borrow the message from the Underscore source), you could do this with JSON.stringify...
var valJSON = JSON.stringify(val);
for (var i = 0; i < ar.length; i++) {
if (valJSON === JSON.stringify(ar[i]) {
// value is present
}
}
This will almost certainly be significantly slower, however.
You can use toString convertion to compare elements
var ar = [
[2,6,89,45],
[3,566,23,79],
[434,677,9,23]
];
var val = [3,566,23,79];
s = !ar.every(a => (a.toString() != val.toString()));
console.log(s) // true
Use this instead
if (ar.join(".").indexOf(val) > -1) {
return true;
} else {
return false;
}
Use lodash isEqual
const isValIncludedInAr = ar.some(element => isEqual(element, val))
const arrayOne = [2,6,89,45];
const arrayTwo = [3,566,23,79];
const arrayThree = [434,677,9,23];
const data = new Set([arrayOne, arrayTwo, arrayThree]);
// Check array if exist
console.log( data.has(arrayTwo) ); // It will return true.
// If you want to make a set into array it's simple
const arrayData = [...data];
console.log(arrayData); // It will return [[2,6,89,45], [3,566,23,79], [434,677,9,23]]