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How to refactor this code with if statement [closed]

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I have code with if statement (below). Is it possible to refactor this code? because in this method is ugly if statement :(
getOverallAmount(estimate) {
const {installments} = estimate;
const {vipValue} = estimate;
if (installments !== 1) {
const oneInstallment = vipValue / installments;
const allWithOneInst = vipValue - (oneInstallment * installments) + 1;
return oneInstallment + allWithOneInst;
}
return vipValue;
}

Using a ternary operator instead of the if statement:
getOverallAmount(estimate) {
const {installments} = estimate;
const {vipValue} = estimate;
const oneInstallment = vipValue / installments;
const allWithOneInst = vipValue - (oneInstallment * installments) + 1;
return (installments !== 1) ? oneInstallment + allWithOneInst : vipValue;
}

Debugging small javascript with exponents [closed]

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n = 1;
while (n < 1024) {
alert(Math.pow(n, 2));
n = n + 2;
}
How can I make this display the powers of 2 from 2^0 to 2^10 inclusive i.e. (1-1024) and end once it reaches 1024 in Javascript

I would do something like this:
for(let n = 0; n <= 10; n++) {
console.log(2 ** n)
}
This logs the answer of each loop iteration. As Pointy suggested in the comment, we have to make the n value iterate from 1 to 10, since that is the variable that generates the output, whereas the 1024 is simply the output that comes from the power values. You could also use Math.pow as follows:
for(let n = 0; n <= 10; n++) {
console.log(Math.pow(2, n))
}
Implementing Secan's suggestion, here is a function which will take any number as a parameter:
function foo(x, exp) {
for(let i = 0; i <= exp; i++) {
console.log(x ** i)
}
}
So to apply this to the original answer, we would call it like this:
foo(2, 10)

Sorry for the ambuiguity with my original question. I've figured it out-
n=0;
while (n <= 10) {
alert(Math.pow(2, n));
n = n + 1;
}
Setting n=0, n<=10 in while and changing n + 1 instead of 2 resolved my issue. Thanks for your responses!

Mathematics functions by string, JS [closed]

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I'm looking for a function that return me a mathematic function following those examples:
The_Function_I_Need("x^2") = function(x) { return math.pow(x, 2) }
The_Function_I_Need("x*2+5") = function(x) { return 2*x+5 }
The_Function_I_Need("x+y") = function(x, y) { return x+y }
And more..

var The_Function_I_Need = {
"x^2": function(x) {
return Math.pow(x, 2);
},
"x*2+5": function(x) {
return 2 * x + 5;
},
"x+y": function(x, y) {
return x + y;
}
}
console.log(The_Function_I_Need["x^2"](4))
console.log(The_Function_I_Need["x*2+5"](4))
console.log(The_Function_I_Need["x+y"](2, 4))

The Javascript eval() function can evaluate a string as an expression.
To follow your example, you could just use eval("x^2").
Reference: http://www.w3schools.com/jsref/jsref_eval.asp

How to add and remove to 2 variables [closed]

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im trying to add and remove to 2 different variables in a code for a incremental game.
here is the code:
$("#autoPayCheckBuy").click(function () {
if (totalClicks >= 50) {
totalClicks -= 50;
totalMoneys += 50;
$("#total_moneys").text(totalMoneys);
$("#total_clicks").text(totalClicks);
}
});
and here is the code for the money/clicks:
var totalClicks = 0;
var totalMoneys = 100;
sorry that i cant give a exact problem, i just cant find a problem in the code :(

I can't find a problem in the code either. What exactly is your problem? Maybe you are missing the d.ready ?
var totalClicks = 0;
var totalMoneys = 100;
$( document ).ready(function() {
$("#autoPayCheckBuy").click(function () {
if (totalClicks < 50) return false;
totalClicks -= 50;
totalMoneys += 50;
$("#total_moneys").text(totalMoneys);
$("#total_clicks").text(totalClicks);
});
});

Repeat function takin previous result of this function [closed]

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var x = function (a) { return a + a/4 - 600}
I have a function that does something.
So now my goal is to repeat this function 12 times with an argument used from previous operation;
Let's say initial ammount is 5000;
So
`x(5000) = 5650;
x(5650) =6462.5;
x(6462.) =...;
and this should be repeated 12 times;
So how can this be done in code?
`

Certainly the easiest way would be to use a for loop:
var x = function(a) { return a + a/4 - 600 },
v = 5000;
for (var i = 0; i < 12; i++) {
v = x(v);
}
console.log(v);

I'd not recommend doing something like this, but instead of a loop you could use recursion:
var x = function(42.34, 12);
----
function(double a, int maxSize)
{
a = ((a + a) / (4 - 600));
if(maxSize>0){
maxSize--;
return function(a,maxSize);
}else{
return a;
}
}
(just pseudocode)