Trying to have a window where the row of sevens are visible and the rest of them arent for my website as it for a slot machine and i want the rest is hidden - images are spritesheet.png in div tags. Any ideas?
here is a image of my website with containers - 1
Thanks for the help
and here is my tags i used.
<div class="outerbox">
<div class="container">
<div class="column">
<img src="images/spritesheet.png">
</div>
<div class="column">
<img src="images/spritesheet.png">
</div>
<div class="column">
<img src="images/spritesheet.png">
</div>
</div>
</div>
Related
I am trying to create a sliding tile structure in Sharepoint.
I have already succeeded in having the tile slide open once when it is clicked on the basis of a parent and child tile. Now I would like it to be able to slide open again, so three-part drop menu
<div class="tile largeTile green" onclick="DropDown(this)" Parent="tegel">
<div class="tileFront" title="S2">
<div class="title">
Tegel
</div>
</div>
</div>
<!--Start Child containers for tegel-->
<div class="tile green DocumentChild" Parent="tegel">
<div class="tileFront" title="test" onclick="window.open('link','_blank')">
<div class="title">
schuif
</div>
</div>
</div>
<div class="tile green DocumentChild" Parent="tegel">
<div class="tileFront" title="test" onclick="window.open('link','_blank')">
<div class="title">
schuif
</div>
</div>
</div>
<div class="tile green DocumentChild" Parent="tegel">
<div class="tileFront" title="test" onclick="window.open('link','_blank')">
<div class="title">
schuif
</div>
</div>
</div>
<!--End of child containers tegel-->
I tried putting a child after a child but it doesn't work, and I have no idea how to use the 'element' code. I read somewhere about an element as 3rd menu but I have no idea how to insert it in the code.
There are still 2 files, 1 .css file containing the layout of the tiles and Javascript for the operation of the tiles. I will probably need to add code to this as well.
Hopefully someone can help me with this
I'm currently building a website and have an image as the header, but when I load the page it will jump half way down the page, load the image and then jump back up. How can I make the image load in first to prevent it from jumping?
HTML:
<div class="refocus" id="hero-header">
<div class="refocus-img-bg"></div>
<div class="refocus-img focus-in">
HTML:
</div>
<div class="refocus-text-container">
<div class="t">
<div class="tc">
</div>
</div>
</div>
</div>
<div class="row">
<div class=".col-md-6">
<div id="section1">
<div id = "sub-text">
<h1>Hello</h1>
<br>
<h2>Hello</h2>
<h3><br>Hello.</h3>
</div>
<div id="image">
<img src="images/aboutme.png"/>
</div>
</div>
<div id="buttoncontainer">
<div id="totimeline">▼</div>
</div>
</div>
</div>
Here's a JSFiddle to replicate this.
Thank you in advance.
You can do one of two things for this.
1) Set the dimensions of your image inline. This is actually a recommended method of preventing the very thing you are experiencing where the page jumps around after images load in. By setting the dimensions inline, the browser will already know how tall the image needs to be and will reserve the space for it before it even finishes loading in.
Example:
<img src="http://placehold.it/350x150" height="150" width="350">
2) If you don't prefer to set the dimensions inline, it seems you could also just set the height in your styles ahead of time and that would do the trick as well.
Example:
.refocus-img{
height:150px;
}
I have the following items laid out in static blocks:
<div class="twentytwenty-wrapper twentytwenty-horizontal">
<div class="image-compare-set twentytwenty-container image-compare-1 current-slider"></div>
</div>
<div class="twentytwenty-wrapper twentytwenty-horizontal">
<div class="image-compare-set twentytwenty-container image-compare-2 current-slider"></div>
</div>
<div class="twentytwenty-wrapper twentytwenty-horizontal">
<div class="image-compare-set twentytwenty-container image-compare-3 current-slider"></div>
</div>
<div class="twentytwenty-wrapper twentytwenty-horizontal">
<div class="image-compare-set twentytwenty-container image-compare-4 current-slider"></div>
</div>
Along with a thumbnail navigation block below:
<div class="image-compare-nav owl-carousel owl-theme">
<div class="owl-wrapper">
<div class="owl-item">
</div>
<div class="owl-item">
</div>
<div class="owl-item">
</div>
<div class="owl-item">
</div>
</div>
</div>
At the moment, all of the main twentytwenty blocks appear underneath each other, but what I want to happen is that only the first one is displayed, and whena thumbnail is clicked, the relating slider div, is shown in it's place.
It's important that as each thumbnail is clicked, the slider changes from the old one, to the new one.
So far I've got this http://jsfiddle.net/96rq4vet/2/ but, when the thumbnails are clicked, the new div isn't showing up, they're staying hidden.
What am I doing wrong?
UPDATE
I'm getting closer with this fiddle: http://jsfiddle.net/96rq4vet/3/ however, I can't get only the first main div to show at first. I tried adding style:display:none; to the second-fourth one, but that doesn't make them show when the thumbnails are clicked.
Any ideas?
Rather than using classes you could use data attributes. You can then grab the data attribute of the thumb that is clicked in order to associate it with the data attribute of the image you want to display.
Something like this:
<div class="twentytwenty-container" data-image-num="1">
<img />
</div>
<div class="imageSet" data-image-num="1">
<img />
</div>
$('.imageSet').click(function() {
var imageNum = $(this).attr('data-image-num');
$('.twentytwenty-container[data-image-num="' + imageNum + '"]').show();
});
JSFiddle
I have searched the knowledge base high and low, but nothing seems to give me a result.
I have attached a screenshot and code of the content I'm working on below, but what I'm needing to do is vertically align the images based on the height of the div created by the tallest image.
So, a few things. The fixed height of the container .one-edition is determined by the tallest image size - can I do this with JS?
Then, once the height is determined, the images are aligned vertically in the middle.
Hope this makes sense.
<div class="grid_3 one-edition">
<img src="images/editions/1_Right_To_Buy_295.jpg">
<div class="editions-info-text">
<p>Right To Buy</p>
<p>C-type Print</p>
</div>
</div>
<div class="grid_3 one-edition">
<img src="images/editions/2_Scorer_295.jpg">
<div class="editions-info-text">
<p>Hyperbolic Paraboloid Roof</p>
<p>Offset Print</p>
</div>
</div>
<div class="grid_3 one-edition">
<img src="images/editions/3_PL16_295.jpg">
<div class="editions-info-text">
<p>132Kv PL16</p>
<p>Offset Print</p>
</div>
</div>
<div class="grid_3 one-edition">
<img src="images/editions/4_What_We_buy_295.jpg">
<div class="editions-info-text">
<p>What We Buy</p>
<p>Publication</p>
</div>
</div>
I see many answers already but I'm still posting this, because I spent time using placekittens..
http://jsfiddle.net/7ybzp/6/
Basically, I used vertical-align: middle. I used inline-block though.
Can someone please explain the structure of this line of a script for me? Another user on here has written it as part of a function that I know want to edit and change to use elsewhere on my site.
$('#main_content .img-wrapper').empty().append($(this).find('img').clone());
This one takes an image from one div and copies it to another with the class="img-wrapper"
I want to do exactly the same but with text. I tried this
$('#main_content .text-wrapper').empty().append($(this).find('.info').clone());
where ('.info') is the class name of the div I want to copy. Its not working.
I don't fully understand the syntax as this is my first day using javascript. Please can someone explain where I'm going wrong?
This is the HTML - There are four different images and when the user clicks on each of the image I want it to load the same image and associated text in the main content div
<div class="row">
<div class="card-container">
<div class="card">
<div class="back">
<img src="images1.png" />
<div class="info" style="display: none;">This is a test for image one</div>
</div>
<div class="front" style="background-color:#cc99cc;"></div>
</div>
</div>
<div class="card-container">
<div class="card">
<div class="back">
<img src="images2.png" />
<div class="info" style="display: none;">This is a test for image one</div>
</div>
<div class="front" style="background-color:#9966cc;"></div>
</div>
</div>
<div class="card-container">
<div class="card">
<div class="back">
<img src="images3.png" />
<div class="info" style="display: none;">This is a test for image one</div>
</div>
<div class="front" style="background-color:#6666cc;"></div>
</div>
</div>
<div class="card-container">
<div class="card">
<div class="back">
<img src="images4.png" />
<div class="info" style="display: none;">This is a test for image one</div>
</div>
<div class="front" style="background-color:#3366cc;"></div>
</div>
</div>
This is the main content div
<div id="main_content">
<!-- main content -->
<div class="img-wrapper">
</div>
<div class="text-wrapper">
</div>
</div>
The javascript in question is using jQuery.
$('#main_content .img-wrapper')
returns the element(s) with class 'img-wrapper' inside the element with id 'main_content'
.empty()
empties this element (removes all it's HTML contents)
.append(
inserts the argument (the bit that comes next) into this element
$(this).find('img')
finds all 'img' tags within the element referred to by this (i.e. if this was triggered from a .click() handler then the element that was clicked)
.clone()
clones these elements so that there are two versions - one in their original location and one being inserted into the #main_content img-wrapper element.
);
Do you definitely have a #main_content .text-wrapper element?
Without seeing the html structure, my guess would be the context in which you're trying to find .info is incorrect.
I'm assuming this block of code is within an event handler like a click or mouseover or something. In that case the $(this) is referring to the element that triggered that event. So the following snippet:
$(this).find('.info')
is looking for elements with a classname of info within the element referred to by $(this).
Make sure the context is correct - change $(this) to the element that you need to search within.
Try this:
$('#main_content .text-wrapper').empty().append($(this).find('.info').html());