Call javascript function in PHP file and load html file after?

Call javascript function in PHP file and load html file after? - javascript

I need to call a js function in my php but it's not working. Can someone tell me what I'm doing wrong? How can I do this in an easy way?
Thank you!
I have three files:
mail.php
Responsible for sending my $_POST stuff (it works fine). I call my javascript function to toggle a modal depending if the mail was send or not.
<?
...
$response = $sendgrid->send($email);
if ($response) {
echo '<script type="text/javascript">',
'confirmaEnvio();',
'</script>';
header('Location: /contato');
}
else {
echo '<script type="text/javascript">',
'falhaEnvio();',
'</script>';
header('Location: /contato');
}
?>
functions.js
Two functions, one toggle the modal with a text telling the mail was sent, one toggle the modal with a text telling the mail was not sent.
function confirmaEnvio () {
$("#modal").find(".modal-body").text("Mensagem enviada com sucesso!");
$("#modal").modal("show");
}
function falhaEnvio() {
$("#modal").find(".modal-body").text("Erro!");
$("#modal").modal("show");
}
view.html
Form sending data to mail.php using POST
<form name="contato" method="post" action="../php/mail.php">
<div class="form-group row">
<label for="email" class="col-sm-2 col-form-label">Email</label>
<div class="col-sm-10">
<input type="email" class="form-control" id="email" name="email" placeholder="Email" required>
</div>
</div>
<div class="form-group row">
<label for="name" class="col-sm-2 col-form-label">Nome</label>
<div class="col-sm-10">
<input type="text" class="form-control" id="name" name="name" placeholder="Nome" required>
</div>
</div>
<div class="form-group row">
<label for="msg" class="col-sm-2 col-form-label">Mensagem</label>
<div class="col-sm-10">
<textarea class="form-control" name ="msg" rows="10" id="msg" placeholder="Mensagem" required></textarea>
</div>
</div>
<div class="form-group row">
<div class="col-sm-10">
<button type="submit" name="submit" class="btn">Enviar</button>
</div>
</div>
my modal, same file, view.html
<div class="modal fade" id="modal" tabindex="-1" role="dialog" aria-labelledby="exampleModalLabel" aria-hidden="true">
<div class="modal-dialog" role="document">
<div class="modal-content">
<div class="modal-header">
<h5 class="modal-title" id="exampleModalLabel">Modal title</h5>
<button type="button" class="close" data-dismiss="modal" aria-label="Close">
<span aria-hidden="true">×</span>
</button>
</div>
<div class="modal-body">
</div>
<div class="modal-footer">
<button type="button" class="btn btn-secondary" data-dismiss="modal">Close</button>
<button type="button" class="btn btn-primary">Save changes</button>
</div>
</div>
</div>
</div>

This seems like an odd way to call a Javascript function as a result of a php call. It looks like you are calling a Javascript function, then immediately loading a new page. So even if the Javascript started to execute, it would be dumped as soon as the new page loads.
A better approach would be to call the php function from Javascript and then respond based on the response from the php function.

Related

Modal bootstrap help does not work with ajax

I have a problem with a small project for class, which does not insert the data to the database, the data I collect with a bootstrap modal and pass them to the php file using ajax. The error comes at the time of using the script, I think it is correct, but I do not execute the actions.
This is the script I use:
<script type="text/javascript">
$(document).ready(function(){
$('#confirm').click(function() {
var tk = $("#task").val();
var dt = $("#date").val();
var at = $("#amount").val();
var st = $("#status").val();
$.ajax({
type: "POST",
url: "insert.php",
data: {"task": tk, "date": dt, "amount": at, "status": st},
success: function (msg) {
$("#task").val("");
$("#date").val("");
$("#amount").val("");
$("#status").val("");
}
});
});
});
</script>
And this is the modal:
<div class="modal fade" id="exampleModal" tabindex="-1" role="dialog" aria-labelledby="exampleModalLabel" aria-hidden="true">
<div class="modal-dialog" role="document">
<div class="modal-content">
<div class="modal-header">
<h5 class="modal-title" id="exampleModalLabel">New task</h5>
<button type="button" class="close" data-dismiss="modal" aria-label="Close"><span aria-hidden="true">×</span></button>
</div>
<div class="modal-body" id="task_insert">
<div class="form-group">
<label for="recipient-name" class="form-control-label">Task:</label>
<input type="text" required class="form-control" id="task">
</div>
<div class="form-group">
<label for="recipient-name" class="form-control-label">Date:</label>
<input class="form-control" required type="text" id="date">
</div>
<div class="form-group">
<label for="recipient-name" class="form-control-label">Amount:</label>
<div class="input-group mb-2 mr-sm-2 mb-sm-0">
<input type="number" class="form-control" required id="amount">
<div class="input-group-addon">€</div>
</div>
</div>
<div class="form-group">
<label for="recipient-name" class="form-control-label">Status:</label>
<input type="text" class="form-control" id="status" >
</div>
</div>
<div class="modal-footer">
<button type="button" class="btn btn-secondary" data-dismiss="modal">Close</button>
<button type="button" id="confirm" class="btn btn-success" data-dismiss="modal">Confirm</button>
</div>
</div>
</div>
</div>
Thanks to everyone for your support

Hope this will help You
add jquery at top of page:
<script src="https://code.jquery.com/jquery-3.2.1.js"></script>
then write your ajax script and get your value in insert.php page like:
$task = $_POST['task'];
echo $task;
if still not work then take form inside modal and submit form using jquery.

How to get data from modal window?

I've a modal dialog.
<div id="myLoginModal" class="modal fade" role="dialog">
<div class="modal-dialog">
<div class="modal-content">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal">×</button>
<h4 class="modal-title">Войти в учетную запись</h4>
</div>
<div class="modal-body">
<form class="form-horizontal" method="post" action="">
<div class="form-group">
<label class="col-md-4 control-label" for="login">Логин</label>
<div class="col-md-4">
<input id="login" name="login" type="text" placeholder="" class="form-control input-md" required="">
</div>
</div>
<div class="form-group">
<label class="col-md-4 control-label" for="password">Пароль</label>
<div class="col-md-4">
<input id="password" name="password" type="password" class="form-control input-md" required="">
</div>
</div>
</form>
</div>
<div class="modal-footer">
<button type="button" id="loginBttn" class="btn btn-success" data-dismiss="modal">Войти</button>
<button type="button" class="btn btn-default" data-dismiss="modal">Отмена</button>
</div>
</div>
</div>
...and have menu.php file.
<?php
$login = $_POST['login'];
$password = $_POST['password'];
echo $login.$password;
How can I get and load in div element user's login and password from modal dialog when he is pressing submit button?
I've tried to write that, but it's not working - exception "undefined index $login and $password".
$(document).ready(function() {
$("#loginBttn").click(function() {
$("#content").load('menu.php');
});
});

You can submit the form and use the success callback:
$(document).ready(function() {
$("#loginBttn").click(function() {
$.post('menu.php', $("#myLoginModal form").serialize(), function(html){
$('#content').html(html);
}, 'html')
});
});
EDIT: Also you can check https://api.jquery.com/jquery.post/

I've just used PHP Tools for VS and I did it!
The problem was the default settings for the php interpreter v7.1 !

show the sucess popup after form submit form?

Here i added one form with data model in codeigniter views page
<a class="handCursor " href="javascript:void(0)" id="franchise">Franchisee </a>
<!-- Modal -->
<div class="modal fade" id="franchisee_signup" tabindex="-1" role="dialog" aria-labelledby="myModalLabel" aria-hidden="true">
<div class="modal-dialog">
<div class="modal-content">
<form action="<?php echo base_url();?>general/general_form" method="POST" name="signup">
<div class="modal-header bg-primary">
<button type="button" class="close" data-dismiss="modal" aria-label="Close"><span aria-hidden="true">×</span></button>
<h4 class="modal-title" id="myModalLabel"><i class="fa fa-desktop"></i> Request For Franchisee Program</h4>
</div>
<div style="clear: both;"></div>
<div class="modal-body clearfix">
<div class="bk_lft" style="width:100%;">
<div class="bk_gr" style="width:100% !important">
<div class="contact_form2">
<div class="bk_roominfo">
<div class="clearfix"></div>
<div class="frm_clmn">
<label>First Name: <em style="color:#F00;">*</em></label>
<input name="first_name" id="txt_name" type="text">
<input name="form_type" id="company_name" type="hidden" value="franchise">
</div>
<div class="frm_clmn1">
<label>Last Name: <em style="color:#F00;">*</em></label>
<input name="last_name" id="txt_lname" type="text">
</div>
<div class="frm_clmn">
<label>Phone: <em style="color:#F00;">*</em></label>
<input name="mobile" id="txt_mobile" type="text">
</div>
<div class="frm_clmn1">
<label>Email: <em style="color:#F00;">*</em></label>
<input name="email" id="txt_email" type="text">
</div>
<div class="frm_clmn1" style="width:100%;">
<label>Message:<em style="color:#F00;">*</em></label>
<textarea name="message" id="txt_message" cols="" rows="" style="resize:none;"></textarea>
</div>
<div class="bk_bt" style="float:left; margin-top:12px;">
<button type="submit" name="send_contact_enq" id="send_contact_enq" value="Continue" style="float:left;">Send</button>
</div>
</div>
</div>
<div class="clearfix"></div>
</div>
</div>
</div>
</form>
</div>
</div>
</div>
This is the form and we add the insert query in controller
public function general_form()
{
$post = $this->input->post();
unset($post['send_contact_enq']);
$insert_id = $this->custom_db->insert_record('corporate_form_reqlist',$post);
redirect(base_url()."general/index");
}
after submitting the form while inserting into db and we redirect to front page . we need before redirect from controllers is there is any possible to show the success popup after close the popup message redirect happened .
we tried all my logic which i know but not get the correct response

try passing some value as param and give success message by checking that in redirected page..
redirect(base_url()."general/index?status=success");
and in general/index file
if(isset($_GET['status']) && $_GET['status'] == "success"){
echo "Successfull Message";
}

if($insert_id=='success'){//change success based on the returned value of the model
echo "<script>
alert('Success');
window.location.href='".base_url('general/index')."';
</script>";
}

You can use ajax function for your form that will send data to PHP to execute general_form tasks without redirecting. PHP returns true if successfully inserts record to db and javascript then triggers alert() or prompt() and windows.location = "your redirection link"

trouble sending modal form contents to PHP file with AJAX and Jquery

I'm trying to learn how to submit form data to a PHP file from a bootstrap modal. From the other questions I've seen, I thought I had it right, but I keep getting the error dialog. I must be missing something obvious.
test.php
<html>
<body>
<div class="container padding-top-10 change-width">
<div class="row padding-top-20" align="center">
<button class="btn btn-warning btn-lg" data-toggle="modal" data-target="#bandModal">Add Band(s)</button>
</div>
</div>
<div id="thanks"></div>
<div class="modal fade" id="bandModal" tabindex="-1" role="dialog" aria-labelledby="myModalLabel" aria-hidden="true">
<div class="modal-dialog modal-lg">
<div class="modal-content modal-lg">
<!-- Modal Header -->
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal">
<span aria-hidden="true">×</span>
<span class="sr-only">Close</span>
</button>
<h4 class="modal-title" id="bandModalLabel">
Add a Show
</h4>
</div>
<!-- Modal Body -->
<div class="modal-body row">
<div class="container col-md-12">
<form id="addBandForm">
<h3>Band Details<small>Enter each band name and primary contact information...</small></h3>
<div class="well" id="newBandRows">
<div class="row">
<div class="col-md-3">
<div class="form-group">
<label for "newBandName">Band Name:</label>
<input type="text" class="form-control" id="newBandName" name="newBandName" placeholder="Enter Band Name" />
</div>
</div>
<div class="col-md-3">
<div class="form-group">
<label for="primaryContact">Primary Contact:</label>
<input type="text" class="form-control" id="primaryContact" name="primaryContact" placeholder="Enter Name" />
</div>
</div>
<div class="col-md-3">
<div class="form-group">
<label for "personEmail">Primary Email:</label>
<input type="email" class="form-control" id="primaryEmail" name="primaryEmail" placeholder="Enter Email" />
</div>
</div>
<div class="col-md-3">
<div class="form-group">
<label for "personPhone">Primary Phone #:</label>
<input type="text" class="form-control" id="primaryPhone" name="primaryPhone" placeholder="Enter Phone #" />
</div>
</div>
</div>
</div>
<div id="newRowButton">
<div class="row">
<div class="col-md-1">
<button type="button" class="btn btn-success pull-left" onClick="addNewBandRow();">+</button>
</div>
<div id="remover" class="col-md-1">
</div>
<div class="col-md-7">
</div>
<div class="col-md-3 padding-top-10">
<button id="addBandSubmit" class="btn btn-primary pull-right">Submit</button>
</div>
</div>
</div>
<script src="js/newBand.js" type="text/javascript"></script>
</form>
</div>
</div>
<div class="modal-footer">
</div>
</div>
</div>
</div>
</body>
</html>
Jquery
$(function() {
//twitter bootstrap script
$("#addBandSubmit").click(function() {
$.ajax({
type: "POST",
url: "womhScripts/addBand.php",
data: $('#addBandForm').serialize(),
success: function(msg) {
$("#thanks").html(msg)
$("#bandModal").modal('hide');
},
error: function(xhr, status, error) { var err = eval("(" + xhr.responseText + ")"); alert(err.Message); }
});
});
});
addBand.php
<?php
if (isset($_POST['newBandName'])) {
$bandName = strip_tags($_POST['newBandName']);
$contact = strip_tags($_POST['primaryContact']);
$email = strip_tags($_POST['primaryEmail']);
$phone = strip_tags($_POST['primaryPhone']);
echo "bandName =".$bandName."</br>";
echo "contact =".$contact."</br>";
echo "email =".$email."</br>";
echo "phone =".$phone."</br>";
echo "<span class="label label-info" >your message has been submitted .. Thanks you</span>";
}?>

I looked through your code and found quite a few errors.
In your test.php change the Submit button from a button to an actual submit button.
<input id="addBandSubmit" type="submit" class="btn btn-primary pull-right">Submit</input>
In your Jquery
Add the preventDefault() function to stop the form from submitting to the same page.
$("#addBandForm").submit(function(event) {
event.preventDefault();
$.ajax({
url: "womhScripts/addBand.php",
type: "POST",
data: $('#addBandForm').serialize(),
success: function(msg) {
$("#thanks").html(msg);
$("#bandModal").modal('hide');
},
error:function(errMsg) {
console.log(errMsg);
}
});
});
You can read about what the preventDefault function here https://developer.mozilla.org/en-US/docs/Web/API/Event/preventDefault
In your addBand.php change the double quotes around your label label-info to single quotes. You cannot have double/single quotes inside double/single quotes inside php.
echo "<span class='label label-info' >your message has been submitted .. Thanks you</span>";
Also it helps to use the console to see exactly what is being posted using the Network tab in Chrome or Firefox .
Please mark this as the answer if it works for you. Hope this helps.

How to set password and username in javascript for a form placed inside a bootstrap modal

I have put a login modal using bootstrap 3 as explained in the link
http://bootstrapvalidator.com/examples/modal/
In the JavaScript code how to set the username and password to a particular value for the login form.
I am still learning html and css. I don't know much about javascript.

$('input[name="username"]').val('user');
$('input[name="password"]').val('password')
http://jsfiddle.net/sp5fcaLm/
Although I'm not sure setting password directly is the best idea.

You can try:
HTML code:
<div class="modal fade" id="loginModal" tabindex="-1" role="dialog" aria-labelledby="myModalLabel" aria-hidden="true">
<div class="modal-dialog">
<div class="modal-content">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal" aria-hidden="true">×</button>
<h4 class="modal-title">Login</h4>
</div>
<div class="modal-body">
<!-- The form is placed inside the body of modal -->
<form id="loginForm" method="post" class="form-horizontal">
<div class="form-group">
<label class="col-sm-3 control-label">Username</label>
<div class="col-sm-5">
<input type="text" class="form-control" name="username" id="username" />
</div>
</div>
<div class="form-group">
<label class="col-sm-3 control-label">Password</label>
<div class="col-sm-5">
<input type="password" class="form-control" name="password" id="password" />
</div>
</div>
<div class="form-group">
<div class="col-sm-5 col-sm-offset-3">
<button type="submit" class="btn btn-default">Login</button>
</div>
</div>
</form>
</div>
</div>
</div>
and javascript code:
$('#loginModal').on('shown.bs.modal', function() {
$('#username').val('example#gmail.com');
$('#password').val('123456');
});
Remember include twitter-bootstrap. Its here

Develop Reference

JavaScript is the programming language of the Web.

Call javascript function in PHP file and load html file after? - javascript

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