Bootstrap tabs are great but they have an annoying downside: content on the inactive tabs gets removed from the flow of the page. in other words when you switch to a new tab, the previous tab's display attribute sets to none (instead of setting visibility: hidden or using other methods)
In my case I have dynamically positioned elements using Masonry.js on the tab foo, whenever I switch to bar and then switch back to foo I have to re-calculate their position since they are all at top: 0px; left: 0px;
this is a costly behaviour, another example is when you have a form filled with data on the tab foo and then switch to bar, all the filled data would be lost so you have to re-enter everything back on.
what is the best workaround to keep the previous tab's state intact while switching?
This workaround works fine for me so far:
you can override these classes so the content on tab foo becomes "hidden" not totally removed from the page.
.tab-content>.tab-pane {
display: block;
height: 0;
overflow: hidden;
}
.tab-content>.active {
height: auto;
overflow: visible;
}
Note: you can also set width: 0 if you have horizontal overflow, please don't forget to reset the width attribute back to normal under .tab-content>.active{...} .
Related
I want to be able to change my navbar position on the fly adjusting remaining content accordingly.
So, I have a functiona website. There is a menu navbar on top by default. What I did is added an 'edit' button to that menu so that when you click it, you get a list of 4 checkboxes with the ability to choose if you want that menu positioned on top (default), left, right or bottom with the other content moving accordingly (e.g menu on the left, content goes slightly right, etc). So basically, I have something like this:
// css for menu positioning to the left
.navbar-left {
width: 25%;
height: auto;
}
.content-right {
position: relative;
left: 200px;
}
// css for menu positioning to the bottom
.navbar-bottom {
position: relative;
bottom: 0;
left: 0;
height: 200px;
}
.content-up {
position: relative;
bottom: 200px;
}
And in JS I do something like this
if($("#left"):checked){
$("#menu-bar").addClass("navbar-left");
$("#content").addClass("content-right");
} else if ($("#bottom"):checked){
$("#menu-bar").addClass("navbar-bottom");
$("#content").addClass("content-up");
}
Now, I have much more styling than this, but it is irrelevant to the issue at hand. The problem is when I choose 'left' it styles properly but when I change it to 'bottom' after that it still uses the styles from 'left' positioning and adds the new ones to it.
Right now I solved the issue by removing the previous classes with .removeClass() method, like that:
if($("#left"):checked){
$("#menu-bar").removeClass("navbar-bottom navbar-right").addClass("navbar-left");
$("#content").removeClass("content-up content-down").addClass("content-right");
} else if ($("#bottom"):checked){
$("#menu-bar").removeClass("navbar-right").addClass("navbar-bottom");
$("#content").removeClass("content-down").addClass("content-up");
}
Basically, right now I have about a hundred lines of just adding classes of the chosen positioning while removing all the classes of 3 other choices that I added each time.
So, finally the question: Is there any other way to strip all the classes that were used before (just set everything to initial values like when the page was loaded) instead of deleting all these classes by hand?
I haven't ever tried resetting the classes to their initial state, but you can certainly clear them all off of a single element in one line of code:
To replace all existing classes with another class, we can use .attr( "class", "newClass" ) instead.
source: https://api.jquery.com/removeclass/
You could probably combine that with the .toggleClass or another method.
If I had to sit down and do it right now, based on my understanding of your question I'd just hide the original elements and add new elements with the classes that you'd like, then to revert delete the new elements and restore the original one.
This is an issue on Firefox and IE so far that I've tested; the problem does not exist on Chrome.
I'm including two TinyMCE editors on a page with one partially off-screen to start. When I select the color picker dropdown option from the toolbar on the first TinyMCE instance, the dropdown appears where it should. But if I scroll down and select the color picker dropdown in the second instance, that dropdown appears way below the editor and typically off the page.
You can see this in action here: http://jsfiddle.net/nm6wtca3/
Without removing the html, body CSS, what can I do to have the color picker always appear in the correct position?
I've traced the problem down to setting CSS on the html, body elements.
html, body {
width: 100%;
height: 100%;
overflow-x: hidden;
}
The dropdown div has CSS applied to it that is auto-calculated by TinyMCE. It looks something like this:
z-index: 65535;
left: 641.467px;
top: 633px;
width: 162px;
height: 105px;
How it appears in FF (sometimes way worse):
How it appears in Chrome (how it should look):
You did say you don't want to remove any CSS from the html,body, but you didn't say anything about adding to it! This solution is based on the assumption that you can add to the html,body
Solution
html, body {
width: 100%;
height: 100%;
overflow-x: hidden;
position: relative; /* Line added */
}
JSFiddle Example
I hope this helps. In all reality, you really only need to apply position: relative; to the body like so body { position: relative; }
I'm not super familiar with tinymce's colorpicker, but I can see the issue, and I can replicate it reliably: your problem occurs when you have a picker open, and then you scroll. I can replicate this in chrome too. Here's a video.
When I look at the DOM, I see that tinyMCE has created two absolute-positioned divs at the end of document.body, one for each picker. When you open one, their position is updated to reflect the location of the toolbar-button at the time you clicked it, but it never gets updated when you scroll!
So, how to solve this? Well, there are a few possibilities:
Option 1: it looks like tinyMCE provides a method to bind a control to an event (here). With this, you could bind a callback to 'scroll' that repositions the box...
Huh, now that I think of it, you could simply close any open colorpickers whenever a user scrolls ... kinda feels like a cop-out but there's no denying it has the best R.O.I. ;) We'll call that Option 2!
Option 3: depending on the implementation of the colorpicker, you may be able to override where in the DOM those divs get rendered. The API method I saw that looked the most promising is here. Once you have the div inside a relative-positioned parent, you'd also have to make the colorpicker's positioning algorithm smart enough to look in the right place for x and y offset ...when I tried this by just moving the element and mashing in some css by hand in chrome-console, the algorithm still computed x and y offsets based on doc.body, so depending on where you were scrolled at click-time, everything would be out of position
It looks like this issue might be troubling other people as well... maybe they've found a solution but haven't posted anything about it?
I hope this is enough info to get you past the problem... Let me know if you have any questions!
It looks like the problem is caused by overflow-x: hidden;
It may not be the answer you want but removing that or moving it to a page wrapper will solve your problem.
Working Example
html, body {
width: 100%;
height: 100%;
padding:0;
margin:0;
}
#pagewrapper{
overflow-x: hidden;
}
Another option would be to force repositioning on scroll, but honestly this is overkill... I strongly recommend fixing the css instead.
Another working example
$('body').scroll(posfix); // when the body scrolls
$('#mceu_10').click(posfix); // when you click the top font color button
$('#mceu_35').click(posfix); // when you click the bottom font color button
function posfix() {
setTimeout(function () { // hack way to ensure it fires after the menu is shown
$('#mceu_51').css({
top: $('#mceu_10').offset().top + $('#mceu_10').height(), // set top/left based on button's position
left: $('#mceu_10').offset().left + $('#mceu_10').width() / 2
});
$('#mceu_52').css({
top: $('#mceu_35').offset().top + $('#mceu_35').height(),
left: $('#mceu_35').offset().left + $('#mceu_35').width() / 2
});
}, 1);
}
it works on firefox, and Internet Explorer fine
just remove this css code
html, body {
width: 100%;
height: 100%;
overflow-x: hidden;
}
Please take a look at this:
html,
body {
width: auto;
height: auto;
overflow-x: hidden;
}
You can simply set body width and height to auto, then there won't be any need to use position and you don't have to remove anything. I think you do not need to use height: 100% since it will be auto-calculated by TinyMCE. i hope it helped.
Update
Look at the screen shot from chrome and its same in firefox. And i didn't remove any css but just changed..and by putting 100% in css the output will be like :-
Please check this one with auto but not 100%..thank you
I currently have a list of objects (projects) that are presented to the user initially as div's that have have a 100px x 200px height/width, position absolute, and float left. This list is contained within an angular ng-repeat method (not sure that makes a difference in the overall question but figured I'd add it in just in case it does). There could be 100s of these divs on the particular project listing page. Currently, I have the page setup so that if you click one of the projects, it's details come up in a modal dialog box. This functionality is fine per the requirements for my project but I'd like to add some "umph" to it by adding in an animation that does the following:
1) If you click on one of the projects, the box expands up to fill the parent container that contains all the projects
2) As the div grows to fill the space or when it's full sized, I want to expose the details of the project itself. Essentially, when the project is unselected, it's just a title/description showing. When it is selected, the project div goes full screen, exposes all of it's details, and shows it's editable fields in the full screen version of the div.
3) When the user closes that full screen div, I'd like it to go back to it's original state in it's original position.
I'm only using the latest version of Chrome for this project so it doesn't need to be a cross browser solution. I'd prefer to keep the animation as close to pure css as possible and would prefer to leave jquery out of it.
I currently have no experience with css3 animations but got a book on it that I hope can teach me about this eventually. However, I figured I would ask in the mean time in case someone can help me out soon so I can put this functionality in while still meeting my deadline for the functionality.
Thanks in advance!
Create a second CSS class that can be added to your div element when it is selected, and removed when it is not. Something like
div {
top: 100px;
bottom: 200px;
left: 100px;
right: 300px;
transition: all 1s; /* animate changes */
}
.active {
top: 0px;
bottom:0px;
left: 0px;
right: 0px;
}
.content {
display: none; /* hide the content unless active */
}
.active .content {
display: block; /* show the content when .active class is added */
}
Make sure that the parent container fills the entire window and is itself set to positiion: absolute or position: relative. There will be a lot more details to work out as you go, but that should give you a framework to get started. You can then add or remove the .active class as needed with JavaScript.
It is hard to explain with words so here's a fiddle I made to explain the problem better: http://jsfiddle.net/j2zurbbv/1/. When the first timeout fires the container div is not 'scrolled' which is the behaviour I want. However when the input is outside of the visible part of the div (as it is with the second timeout) the container div centres about this input.
Container css:
#container {
overflow: hidden;
height: 200px;
position: absolute;
width: 200px;
}
For the record I have only tested this on Chrome 37.0
Managed to work it out. Counter the scrolling that the browser does by doing document.getElementById('container').scrollTop = 0; whenever you programatically focus on an element outside of the visible area of an overflow: hidden div AND whenever a user inputs in such an element. Demonstrative JSFiddle (without prevention of input scrolling) http://jsfiddle.net/j2zurbbv/2/.
How to get page 's scroll position change event?
I want to implement dynamic table of contents like http://bonsaiden.github.com/JavaScript-Garden/ ( In this website, with your scrolling of the webpage, It also shows the current active item)
Is it possible to implement same thing without getting current scroll-position?
I am very new to JS and web-world.
That page does use some JS trickery with its <nav> element, but it's fixing the location of the sidebar using position: fixed, that is, using CSS not JavaScript. Here's the relevant style declaration (comments mine):
nav {
position: fixed; // fix position
margin-left: 750px; // add 750 px of room to the left
top: 0; // set 0px from top of page
}