Use all function arguments without having to enumerate them [duplicate] - javascript

This question already has answers here:
Usage of rest parameter and spread operator in javascript
(6 answers)
Closed 4 years ago.
I have functionWithManyArguments(arg1,...,arg15).
Can I log all arguments without having to enumerate them all?

Yes,
You could do something like:-
function foo(...args) {
console.log(...args);
}
foo(1, 2, "a")
...args are rest parameters.

Related

How are these methods of writing functions different? [duplicate]

This question already has answers here:
How does this object method definition work without the "function" keyword?
(2 answers)
ES6 Object Literal Syntax for Methods
(1 answer)
Closed 2 years ago.
I have code that has the following functions written:
testing: function() {
///
}
what is the difference of writing it as :
testing() {
///
}
Do they mean the same thing and have the same purpose?

What are javascript “...array” parameters? [duplicate]

This question already has answers here:
Spread Syntax ES6
(8 answers)
Closed 4 years ago.
I just started learn Javascript, I'm confused about the function parameter ...[1,2], why the function parameter like this.
function compare(a, b) {
return a - b;
}
let result = compare(...[1,2]);
console.log(result);
It's a new Es6 functionality called the spread operator, it's great for calling functions (without apply), converting arguments or NodeList to Arrays, array manipulations, and even when using the Math functions.
https://davidwalsh.name/spread-operator

Array function of JavaScript && Rest Parameter? [duplicate]

This question already has answers here:
What does this symbol mean in JavaScript?
(1 answer)
What is the meaning of "...args" (three dots) in a function definition?
(6 answers)
Closed 5 years ago.
I was reading the JavaScript Docs I found the Array function section one Example that I could not understand properly. Because I am learning Programming.
function multiply(multiplier, ...theArgs){
return theArgs.map(x=> multiplier*x);
}
var arr = multiply(2,1,2,3);
console.log(arr);
Above example is giving
2,4,6
My first question why is used 3 dots(...) before function argument name (...theArgs) for? And How did it calculate 2,4,6?
And the second Question is about rest parameter. What does the rest parameter use in Array Function?
I would be glad if anyone can give me some real-life object example to understand this Problem

Deconstructing arrays for the function arguments [duplicate]

This question already has answers here:
Passing an array as a function parameter in JavaScript
(12 answers)
Closed 6 years ago.
I have
function f(a,b,c) {}
and
const arr = [1,2,3]
What do I need to call
f(arr)
__________________________________________?
One this you can do is:
f.apply({}, arr);

Why arguments is not defined in arrow function in ES6? [duplicate]

This question already has answers here:
Official information on `arguments` in ES6 Arrow functions?
(2 answers)
Do ES6 arrow functions have their own arguments or not? [duplicate]
(4 answers)
Closed 7 years ago.
For this code
var sum = () => {console.log(arguments); ... }
sum(2, 3)
Get error Uncaught ReferenceError: arguments is not defined.
Why arguments is not defined in arrow function?

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