Develop Reference

Replace class in order to replace image on click with jquery

I read a number of articles and answers here on Stack Overflow but none of them answered my question as I'm really a noob when it comes to jQuery and I'm not sure how to do this.
I have a HTML landing page on which I'm trying to show several images on which you click and they get replaced with another image and when clicked again or at another image the original one is shown.
I have this so far:
<div class="santa">
<img class="show" src="images/santa.png" alt="">
<img class="hide" src="images/bubble.png" alt="">
</div>
.hide { display: none; }
.show { display: block; }
I want to show santa.png by default and when clicked on to change it to bubble.png, meaning default class is show and when clicked on it's hide for santa and vice versa.
Thanks in advance!

The simple way to do this is to call toggle() on both the displayed and hidden images when one is clicked. This will invert the display state of both elements simultaneously:
$('.hide, .show').click(function() {
$(this).closest('div').find('.hide, .show').toggle();
})
.hide { display: none; }
.show { display: block; }
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="santa">
<img class="show" src="images/santa.png" alt="Santa">
<img class="hide" src="images/bubble.png" alt="Bubble">
</div>
<div class="santa">
<img class="show" src="images/santa.png" alt="Santa2">
<img class="hide" src="images/bubble.png" alt="Bubble2">
</div>
If you actually want to change the class values on the elements, then you can use toggleClass() instead:
$('.hide, .show').click(function() {
$(this).closest('div').find('.hide, .show').toggleClass('hide show');
})
.hide { display: none; }
.show { display: block; }
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="santa">
<img class="show" src="images/santa.png" alt="Santa">
<img class="hide" src="images/bubble.png" alt="Bubble">
</div>
<div class="santa">
<img class="show" src="images/santa.png" alt="Santa2">
<img class="hide" src="images/bubble.png" alt="Bubble2">
</div>

Since u are a beginner, my humble request is to learn vanillajs thoroughly before using libraries like jquery.
here is a pure js approach.. Cheers
let santaimg = document.getElementById('santa');
let bubbleimg = document.getElementById('bubble');
santaimg.onclick = showBubbleHideSanta;
function showBubbleHideSanta() {
santaimg.classList += " hide";
//santaimg.classList -= "show";
bubbleimg.classList -= " hide";
//bubbleimg.classList += "show";
}
.show {
display:block;
}
.hide {
display:none;
}
<img src="https://upload.wikimedia.org/wikipedia/commons/thumb/4/49/Jonathan_G_Meath_portrays_Santa_Claus.jpg/220px-Jonathan_G_Meath_portrays_Santa_Claus.jpg" id="santa" class="show"/>
<img src = "https://sophosnews.files.wordpress.com/2017/05/shutterstock_296886146.jpg?w=780&h=408&crop=1" id="bubble" class="hide"/>

Try this...if you have two images only...
HTML
<div class="santa">
<img class="show" src="http://via.placeholder.com/350x150" alt="img">
<img class="hide" src="http://via.placeholder.com/250x150" alt="img">
</div>
CSS
.show{
display:block;
}
.hide{
display:none;
}
img{
max-width:100%;
height:auto;
cursor:pointer;
}
JS
jQuery('.show, .hide').click(function() {
jQuery('.show, .hide').toggle();
});
Thanks !

If you want to show/hide an element I suggest you to use .hide() and .show()
It's pure JQuery and no need of CSS.
"The matched elements will be hidden immediately, with no animation. This is roughly equivalent to calling .css( "display", "none" ), except that the value of the display property is saved in jQuery's data cache so that display can later be restored to its initial value"
http://api.jquery.com/hide/
Here is an exemple:
HTML
<div>
<img class="santa_img" src="images/santa.png" alt="santa">
<img class="bubble_img" src="images/bubble.png" alt="bubble">
</div>
JS (JQuery)
$(".santa_img").click(function(){
$(".santa_img").hide();
$(".bubble_img").show();
})
$(".bubble_img").click(function(){
$(".bubble_img").hide();
$(".santa_img").show();
})
$(".bubble_img").hide(); //Hidden by default

Same javascript event for different images?

I have an image that when hover, a div with an overlay will fade in and out.
<div id="img-one">
<div id="overlay-one">
<div class="card-overlay-text">
<p>Enlarge Image<p></div>
</div>
<img src="assets/img/card_one.jpg" alt="" />
</div>
However, I have multiple images and I need to repeat this code for each of these images (assigned with different div's id). How can I get, when hover on specific image.
The code only run on individual image only?
$(function() {
$('#img-one').hover(function() {
$('#overlay-one').stop(true,true).fadeIn();
}, function() {
$('#overlay-one').stop(true,true).fadeOut();
});
});

Use general class in all the image containers div's and overlay div's, like :
<div id="img-one" class='img-container'>
<div id="overlay-one" class='overlay'>
...
</div>
</div>
Then adjust you JS code to invoke just related overlay :
$(function() {
$('.img-container').hover(function() {
$('.overlay', this).stop(true,true).fadeIn();
}, function() {
$('.overlay', this).stop(true,true).fadeOut();
});
});
Hope this helps.
$(function() {
$('.img-container').hover(function() {
$('.overlay', this).stop(true,true).fadeIn();
}, function() {
$('.overlay', this).stop(true,true).fadeOut();
});
});
.img-container{
background-color: green;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class='img-container'>
<div class='overlay'>
<div class="card-overlay-text">
<p>Enlarge Image 1<p></div>
</div>
</div>
<div class='img-container'>
<div class='overlay'>
<div class="card-overlay-text">
<p>Enlarge Image 2<p></div>
</div>
</div>
<div class='img-container'>
<div class='overlay'>
<div class="card-overlay-text">
<p>Enlarge Image 3<p></div>
</div>
</div>

You'll better use classes. Then do something like this:
$('.main-container').find('.div-class-name').forEach(function(el) {
<bind a handler for each consequent element here>
});
You'll end up with a bunch of handlers that are bound to each individual ".div-class-name" element.

It is recommended to use classes because that is what classes are for and id's are not.
If your case demands some situation where you have no control over the HTML part, you can use wildcards in attribute selectors in some cases. Like div[id^=overlay] to selects all div with id starting with overlay
$(function() {
$('div[id^=img]').hover(function() {
$('div[id^=overlay]',this).stop(true,true).fadeIn();
}, function() {
$('div[id^=overlay]',this).stop(true,true).fadeOut();
});
});
div[id^=img]{
position: relative;
height:100px;
width:100px;
border:1px solid black;
margin:2px;
}
div[id^=img] > div[id^=overlay]{
position:absolute;
background:rgba(0,0,0,.2);
top:0;
left:0;
right:0;
bottom:0;
display:none;
width:100px;
color:#fff;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="img-one">
<div id="overlay-one">
<div class="card-overlay-text">
<p>Enlarge Image 1<p></div>
</div>
<img width="100" src="https://upload.wikimedia.org/wikipedia/commons/e/ed/Raff_House.jpg" alt="" />
</div>
<div id="img-two">
<div id="overlay-two">
<div class="card-overlay-text">
<p>Enlarge Image 2<p></div>
</div>
<img width="100" src="https://upload.wikimedia.org/wikipedia/commons/e/ed/Raff_House.jpg" alt="" />
</div>

You can try with the jQuery Easy Overlay Plugin
http://eivissapp.github.io/jquery-easy-overlay/
In the code, you should assign a class to the images, and call this statement (that will work for each image):
jQuery("img.yourclass").hover(function(){
jQuery(this).easyOverlay("start");
}, function(){
jQuery(this).easyOverlay("stop");
});
If you have fontawesome in the page, then execute this before the code above (otherwhise the plugin will use the fontawesome spinner inside the overlay div):
jQuery.fn.easyOverlay.options = { spin: false }

How to make visible and hide particular divs?

All div are generated dynamically, and having same class class="bucket". This div had one more div inside class="restPart" rest part, which will hide, when page load first time.
What I want, I have more than one div,
1. Each divs hides the rest part, when page load first time.
2. Each div are diving into two part, one part will always show and rest part will not show.
3. Rest part will appear only when we click the link "show more",
4. When div are fully shown It will show link "show less", when we click on it, will hide the rest part.
5. This should work only for one div on which we are clicking, other divs should be unaware.
_data_grid.html
<script language="javascript" type="text/javascript">
$(document).ready(function(){
$("#restPart").hide();
$('#grid_content').on('click','.more', function(){
//$("#restPart").show();
$("div").children("div").show();
$("#showRest").hide();
});
$('#grid_content').on('click','.less', function(){
//$("#restPart").hide();
$("#showRest").show();
$(this).closest("div").hide();
});
});
</script>
#grid_content {
overflow: hidden; clear: both;
}
#grid_content .bucket {
width: 290px; float: left; margin: 0 0 48px 20px;
border: 1px solid #262626;
background: $gray-lighter;
}
#grid_content .bucket ul {
margin: 0 0 0 0; padding: 0 0 0 10px;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.10.0/jquery.min.js"></script>
<section id="grid_content">
<!--1st -->
<div class="bucket">
... Content of visible part of bucket...
Show More.
<!--Below is the rest part when we click on the above link, Showrest it will show-->
<div class="restPart" id="restPart">
... Content of Rest Part and click on the Show Less It will hide this div...
Show Less.
</div>
</div>
<!--2nd -->
<div class="bucket">
... Content of visible part of bucket...
Show More.
<!--Below is the rest part when we click on the above link, Showrest it will show-->
<div class="restPart" id="restPart">
... Content of Rest Part and click on the Show Less It will hide this div...
Show Less.
</div>
</div>
</section>
What I want
In the like following figures, more div will be generated dynamically, previously all will hide, when I click on first div show the rest content, but rest will not show, please see the figure 2,
Figure 1
Figure 2

As noted by others, remove duplicate IDs.
Judging by your image,
your button Show more, (once clicked - reveals the content and) becomes: Show less so...
change button text (So use a single toggle button!)
toggle/slide the previous DIV
$(function() { // DOM is now ready
$("#grid_content").on("click", ".toggle", function(evt) {
evt.preventDefault(); // Prevent window following #hash / jump
var more = $(this).text() === "Show More";
$(this).text(more ? "Show Less" : "Show More").prev(".restPart").slideToggle();
});
});
.bucket {
width: 290px;
float: left;
margin: 0 0 48px 20px;
border: 1px solid #262626;
background: lightgray;
}
.restPart{
overflow:auto;
display:none; /* hide initially */
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<section id="grid_content">
<div class="bucket">
<p>Visible part....</p>
<div class="restPart">
<p>Content...</p>
</div>
Show More
</div>
<div class="bucket">
<p>Visible part....</p>
<div class="restPart">
<p>Content...</p>
</div>
Show More
</div>
</section>

First of all - your naming strategy is a bit wrong. HTML document can contain (by standards) only one object with one ID - that's the purpose of ID as such. So, you can't have many objects with id="showRest" or id="restPart" or id="showless".
Possible solution for your problem.
Design your HTML something like
<div class="bucket">
<div class="mininfo">
<div class="intro">some intro bucket 1...</div>
Show more
</div>
<div class="maxinfo" style="display: none;">
<div class="intro">Here is full content 1 of everything</div>
Show less
</div>
</div>
<div class="bucket">
<div class="mininfo">
<div class="intro">some intro bucket 2...</div>
Show more
</div>
<div class="maxinfo" style="display: none;">
<div class="intro">Here is full content 2 of everything</div>
Show less
</div>
</div>
Next, in JavaScript part you can use selectors such as:
$(".bucket .showmore").on('click', function(){
var $bucket = $(this).parents('.bucket');
$bucket.find('.mininfo').hide();
$bucket.find('.maxinfo').show();
});
$(".bucket .showless").on('click', function(){
var $bucket = $(this).parents('.bucket');
$bucket.find('.mininfo').show();
$bucket.find('.maxinfo').hide();
});
Updated 1: added two buckets to example.
Updated 2: example in JSFiddle
Updated 3: update in JSFiddle with some content kept

How to make multiple divs slidetoggle with changing arrow

I'm very new to javascript and jQuery and has now got completely stuck despite trying various options. I'm trying to create a expand/collapse section with multiple divs. I would like each div to open and close seperately, with an arrow at the side pointing up or down, depending whether the content is expanded or collapsed.
From the code I have written below, only the first div works correctly. The only thing which happen When you click on the two other divs, is that the arrow in the first div change.
Any help will be greatly appreciated.
Following is the CSS:
#header_background {
background-image: url(header-background.png);
width:748px;
height:43px;
margin-left: -17px;}
#expand_arrow {
display: inline-block;
width: 17px;
height: 18px;
float:left;
margin-left:20px;
padding-left:0px;
padding-top:11px;
background-repeat:no-repeat; }
.sub_header {
color:#204187;
font-weight:bold;
font-size:16px;
vertical-align:middle;
padding-left:4px;
padding-top:12px;
float:left;
text-decoration:none;
}
Here's the attempted javascript and jQuery:
function chngimg() {
var img = document.getElementById('expand_arrow').src;
if (img.indexOf('expand-arrow.png')!=-1) {
document.getElementById('expand_arrow').src = 'images/collapse-arrow.png';
}
else {
document.getElementById('expand_arrow').src = 'images/expand-arrow.png';
}
}
$(document).ready(function(){
$("#header_background").click(function(){
$("#section").slideToggle("slow");
});
});
And here's the HTML
<div id="header_background" >
<img id="expand_arrow" alt="" src="images/collapse-arrow.png" onclick="chngimg()">
<div class="sub_header" onclick="chngimg()">header 1</div>
</div>
<div id="section" style="display:none">
text 1
</div>
<div id="header_background" >
<img id="expand_arrow" alt="" src="images/collapse-arrow.png" onclick="chngimg()">
<div class="sub_header" onclick="chngimg()">header 2</div>
</div>
<div id="section" style="display:none">
text 2
</div>
<div id="header_background" >
<img id="expand_arrow" alt="" src="images/collapse-arrow.png" onclick="chngimg()">
<div class="sub_header" onclick="chngimg()">header 3</div>
</div>
<div id="section" style="display:none">
text 3
</div>

It's only working for the first set of elements because you're using IDs, and IDs have to be unique within the document (page). You could change to using classes and perform some simple DOM traversal to get the corresponding section based on the header that was clicked. Something like this:
$(document).ready(function() {
$('.header_background').click(function(e) {
$(this).next('.section').slideToggle('slow');
var img = $(this).find('img.expand_arrow')[0]; // the actual DOM element for the image
if (img.src.indexOf('expand-arrow.png') != -1) {
img.src = 'images/collapse-arrow.png';
}
else {
img.src = 'images/expand-arrow.png';
}
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="header_background" >
<img class="expand_arrow" alt="" src="images/collapse-arrow.png">
<div class="sub_header">header 1</div>
</div>
<div class="section" style="display:none">
text 1
</div>
<div class="header_background" >
<img class="expand_arrow" alt="" src="images/collapse-arrow.png">
<div class="sub_header">header 2</div>
</div>
<div class="section" style="display:none">
text 2
</div>
<div class="header_background" >
<img class="expand_arrow" alt="" src="images/collapse-arrow.png">
<div class="sub_header">header 3</div>
</div>
<div class="section" style="display:none">
text 3
</div>

Look for your next section of the header clicked like so. And change your id for class because ID need to be unique
$(".header_background").click(function(){
$(this).nextAll(".section:first").slideToggle("slow");
});

Center fadeIn image

I'm building a simple image gallery with jquery but running into an annoying problem. Since the images are of various sizes I have centered them all to make it look even. However the built in fadeIn/fadeOut methods throw this centering awry and I'm not completely sure what is going on. I tried manually adding the centering class again then manually adding css but cannot get the image to center once it has been turned visible. Thoughts?
css -
.center { margin: 0 auto; }
img.invisible { display: none; }
img.visible { margin: 0 auto; display: block;}
markup -
<div id="content" class="center gallery">
<img src="images/event/event_1.jpg" alt="alt-text" class="visible" />
<img src="images/event/event_2.jpg" alt="alt-text" class="invisible" />
<img src="images/event/event_3.jpg" alt="alt-text" class="invisible" />
<div id="selection" class="overlay">
<div class="select first">
<img src="images/event/event_1_small.jpg" />
</div>
<div class="select">
<img src="images/event/event_2_small.jpg" />
</div>
<div class="select">
<img src="images/event/event_3_small.jpg" />
</div>
</div>
jQuery -
function updateImage(img_num) {
var cur_img = $("#content img.visible");
var next_img = $('#content img[src^="' + img_path + img_num + '.jpg"]');
cur_img.fadeOut('600',function() {
next_img.fadeIn('600');
next_img.removeClass("invisible").addClass("visible");
cur_img.removeClass("visible").addClass("invisible");
});
}

You are adding margin: 0 auto; only to the .visible class, you need to apply that to all of your images:
.gallery img{margin:0 auto;display:none}
.gallery img.visible{display:block}

Okay well that was surprising. To fix this problem I tried using fadeTo which revealed that the problem was the images once being made visible were given display: inline; so all it took to fix this problem was.
.gallery { text-align: center; }
I thought jQuery was just changing the opacity but it appears to also change the display. Tricky.