I'm trying to make use of the HTML5 <input type="email" /> validation check.
I can get it working fine doing this:
<form>
<input type="email" />
<input type="submit" />
</form>
This gets the validation to work on clicking the sumbit button. However I'd like to trigger the form to submit upon having my email field blur.
How do I trigger the form without a submit button onBlur?
Like this:
<form>
<input type="email" onBlur={/* trigger form submission */} />
</form>
Alternatively, is there a better approach to performaning the HTML5 email validation check upon input blur?
Put a ref attribute on your form and call the submit function:
<form ref="myForm">
<input type="email" onBlur={this.submitForm.bind(this)} />
</form>
Add a function:
submitForm(){
this.refs['myForm'].submit()
}
use the native checkValidity method
<form>
<input type="email" id="a" />
</form>
const a = document.querySelector('#a')
a.addEventListener('blur', e => {
const isValid = e.target.checkValidity()
console.log(isValid)
})
Related
I have a form like below:
<form action="/action_page.php" onsubmit="alert('The form was submitted');" >
Enter name: <input type="text" name="fname">
<input type="button" onclick="document.getElementsByTagName('form')[0].submit()" value="Submit">
</form>
Though I clicked the button and indeed it submitted the form, but the alert box wasn't shown. That is, the submit() method submitted the form but without triggering the onsubmit event. What happened? And how should I use submit() method to trigger the onsubmit event?
Well, the documentation for the submit method is pretty clear that it doesn't trigger onsubmit.
Since any of the following form elements cause a form submit:
<input type='submit'>
<input type='button'>
<button>
You likely don't need an onclick handler on that button at all
it seems that you can't, please check this post - https://stackoverflow.com/a/19847255/8449863
however, please try workaround with hidden submit button:
<form action="/action_page.php" onsubmit="alert('The form was submitted');" >
Enter name: <input type="text" name="fname">
<input type="button" value="Submit" onclick="document.getElementById('submit').click();" >
<input id="submit" type="submit" style="display: none;" />
</form>
I have an HTML form that has a submit button. I want this button to be disabled when it is clicked. But I also want the form to get submitted.
I am not using ajax request to submit the form. The PHP script that handles the form takes a long time. So some users just click it after a few seconds and the form gets submitted twice which leads to two rows with the same data in the database.
Here's what I tried so far
<form method="POST" action="xyz.php">
<input type="text" name="fields[]" />
<input type="text" name="fields[]" />
<input type="text" name="fields[]" />
<input type="text" name="fields[]" />
<input type="submit" onclick="$(this).attr('disabled', true);" value="Submit" />
</form>
The onclick event on submit button disables the button but it also don't let the form to be submitted. But I want the form to be submitted and also want the button to be disabled.
You May try the below code
onclick="this.disabled=true;this.form.submit();this.value='Submiting...';"
If you're using jQuery, then here's a fully-jQuery, unobtrusively handled version which would work.
If you were to give your form an ID, you could make it handle that form specifically - this example will handle all forms on your page.
$(function() {
$("form").submit(function(event) {
$(this).find('input[type="submit"]').prop("disabled", true);
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form method="POST" action="xyz.php">
<input type="text" name="fields[]" />
<input type="text" name="fields[]" />
<input type="text" name="fields[]" />
<input type="text" name="fields[]" />
<input type="submit" value="Submit" />
</form>
Note that you should use .prop() rather than .attr() to set properties such as "disabled"
(see http://api.jquery.com/attr/).
I have the following code:
<form>
<input type="email" id="login_email" required>
<input type="submit" value="Sign in" ng-click="signIn()">
</form>
The problem with above code is that signIn() method gets called even if there is an email validation error from HTML5 side. In general how to ensure that signIn() method gets called only when all the input validation of the form are successful?
Use $pristine to find out if the form is empty, and $invalid to find out if the form is populated but has invalid values (maybe an incorrect email, for example).
<form name="myForm">
<input type="email" name="email" ng-model="email" required />
<button ng-click="signIn()" ng-disabled="myForm.$invalid || myForm.$pristine">Save</button>
</form>
So now your submit button will be disabled (not clickable) until your form is valid.
EDIT
In order to validate only with HTML5 validation, add a name attribute to your form and you can access the validity of it during submission:
<form name="myForm">...</form>
$scope.signIn = function(){
if ($scope.myForm.$valid){
// do sign in logic here
}
}
Maybe even inline the logic on your submit button (if it works):
<input type="submit" value="Sign in" ng-click="myForm.$valid && signIn()">
So signIn would only be called if the first part was true.
EDIT 2
Based on the information found on the AngularJS docs here, can you try the following as well?:
<form name="myForm">
<input type="email" name="email" ng-model="email" required />
<button ng-click="signIn()" ng-disabled="signIn()">Save</button>
</form>
$scope.signIn = function () {
if ($scope.myForm.email.$error.required) {
// ...
}
};
We are now following the $scope.myForm.email.$error.required syntax approach.
Try logging $scope.myForm or $scope.myForm.email and see what you get as you modify the value.
i have one form with some input text with the name = "user_name" , "mob" , "email" and inside this form i have a link for example Plans and end with submit button. Now if user click the link then i want to have all the values of the input text of the same form send to another page to pks.php and if the user click on the submit button then it will work on action confirm.php. For example Check this code
<form action="confirm.php" method ="post">
<input type ="text" name="user_name">
<input type="number" name="mob">
<input type="text" name="email">
PLANS
<input type="submit">
</form>
Can you help me out?? How can i achieve this. Thanks in advance
The simplest way is to change the link to a second submit button. You can then use the formaction attribute to change the URL the form submits to when you use this button.
<form action="confirm.php" method ="post">
<input type ="text" name="user_name">
<input type="number" name="mob">
<input type="text" name="email">
<input type="submit" formaction="pks.php" value="PLANS">
<input type="submit">
</form>
If you can't do that, you need to run Javascript when they click on the link. You can have this code change the action of the form, and then submit it.
document.getElementById('plans').addEventListener('click', function(e) {
e.preventDefault();
var form = document.getElementById('myform');
form.action = this.href;
form.submit();
});
<form id="myform" action="confirm.php" method="post">
<input type="text" name="user_name">
<input type="number" name="mob">
<input type="text" name="email">
<a id="plans" href="pks.php">PLANS</a>
<input type="submit">
</form>
You will probably want to use JavaScript to control the form if you want the action attribute to change. By default, submitting the form will cause it to post to confirm.php.
Using JQuery you can do this:
$('form').on('submit', function(e) {
// Stop the form from submitting
e.preventDefault();
// Do logic to determine what action you should do
var myAction = 'pks.php';
// assign the action to the form
$(this).attr('action', myAction);
// submit the form
$(this).submit();
});
I haven't run this script so it may not work out of the box but you should be able to adapt and fix it without too much difficulty.
I have a form on page. I want to submit a form when user click on submit button which is outside of form tag. When I am using $('#theform').submit() then submit method work perfectly but when I am doing this document.getElementById('theform').submit() then it is only refreshing my page.
Fiddle
JavaScript
$(function() {
$('input[type="submit"]').click(function() {
//$('#theform').submit()
document.getElementById('theform').submit()
})
$('#theform').submit(function(e) {
alert(0)
e.preventDefault()
})
})
html
<form id="theform">
<input type="text" id="fname" />
<input type="text" id="lname" />
<input type="text" id="country" />
</form>
<input type="submit" />
The DOM submit() method does not trigger submit events where as jQuery's does.that is the reason your form in javascript document.getElementById('theform').submit() will submit the FORM.
you can see a post here :Jquery submit vs. javascript submit
use document.forms["theform"].submit();
and define action in your form
<form id="theform" action="submit-form.php">