Develop Reference

How to add spaces to every two numbers with JavaScript?

I like to output a formatted number with a space after every two numbers, I've tried this:
function twoSpaceNumber(num) {
return num.toString().replace(/\B(?<!\.\d)(?=([0-9]{2})+(?!\d))/g, " ");
}
twoSpaceNumber(12345678) => 1 23 45 67 89 ( should start with 12 ? )
and also when it starts with 0 I had very strange output
twoSpaceNumber(012345678) => 12 34 56 78

Please consider
var s = "1234456";
var t = s.match(/.{1,2}/g);
var u = t.join(" ");
console.log(u);
which logs
12 34 45 6
and
var s = "ABCDEF";
var t = s.match(/.{1,2}/g);
var u = t.join(" ");
console.log(u);
which logs
AB CD EF
Note that s is a string.
Is that what you need?

Pass num as a string, not a number, else the leading zeros will disappear and use
function twoSpaceNumber(num) {
return num.replace(/\d{2}(?!$)/g, "$& ");
}
The regex matches two digits that are not at the end of string (in order not to add a space at the string end).
JavaScript demo
const regex = /\d{2}(?!$)/g;
function twoSpaceNumber(num) {
return num.replace(regex, "$& ");
}
const strings = ['123456789','012345678'];
for (const string of strings) {
console.log(string, '=>', twoSpaceNumber(string));
}

If you don't mind a non-regex approach:
function twoSpaceNumber(num) {
var res = '';
num += '';
for(var i = 0; i < num.length; i+=2)
{
res += num.substr(i,2) + ' ';
}
return res.trim();
}

Keep N occurrences of a single character in a string in Javascript

Let's say I have this string: "a_b_c_d_restofthestring" and I only want to keep (e.g.) 2 underscores. So,
"a_b_cdrestofthestring"
"abc_d_restofthestring"
Are both valid outputs.
My current implementation is:
let str = "___sdaj___osad$%^&*";
document.getElementById('input').innerText = str;
let u = 0;
str = str.split("").reduce((output, c) => {
if (c == "_") u++;
return u < 2 || c != "_" ? output + c : output;
});
document.getElementById('output').innerText = str;
<div id="input"></div>
<div id="output"></div>
But I'd like to know if there's a better way...

Your code seems to work fine, but here's a one-liner regular expression that replaces all but the last two underscores from the input string.
let input = "___sdaj___osad$%^&*";
let output = input.replace(/_(?=(.*_){2})/g, '');
console.log("input: " + input);
console.log("output: " + output);
This of course is not very generalized, and you'd have to modify the regular expression every time you wanted to say, replace a character other than underscore, or allow 3 occurrences. But if you're okay with that, then this solution has a bit less code to maintain.
Update: Here's an alternate version, that's fully generic and should perform a bit better:
let input = "___sdaj___osad$%^&*";
function replace(input, char = '_', max = 2, replaceWith = '') {
let result = "";
const len = input.length;
for (let i = 0, u = 0; i < len; i++) {
let c = input[i];
result += (c === char && ++u > max) ? replaceWith : c;
}
return result;
}
console.log("input: ", input);
console.log("output: ", replace(input));
See this jsPerf analysis.

You could take a regular expression which looks for an underscore and a counter of the keeping underscores and replace all others.
var string = "a_b_c_d_restofthestring",
result = string.replace(/_/g, (c => _ => c && c-- ? _ : '')(2));
console.log(result);

How can I remove the last emoji of a group of emojis in javascript?

Let's say I have this 3 emojis in a string: 😀🎃👪
There are not any spaces or any other character except emojis in the string.
How can I remove the last emoji in javascript?

The answer below doesn't use any special package and safely removes the last emoji
function safeEmojiBackspace(str)
{
let initialRealCount = fancyCount(str);
while(str.length > 0 && fancyCount(str) !== initialRealCount - 1)
{
str = str.substring(0,str.length - 1);
}
return str;
}
function fancyCount(str){
const joiner = "\u{200D}";
const split = str.split(joiner);
let count = 0;
for(const s of split){
//removing the variation selectors
const num = Array.from(s.split(/[\ufe00-\ufe0f]/).join("")).length;
count += num;
}
//assuming the joiners are used appropriately
return count / split.length;
}
Sample usage
let str = "something😀🎃👪";
str = safeEmojiBackspace(str);//"something😀🎃"

You can do this. It will always remove the last emoji.
function removeEmoji() {
var emoStringArray = document.getElementById('emoji').innerHTML;
var lastIndex = emoStringArray.lastIndexOf(" ");
var stripedEmoStringArray = emoStringArray.substring(0, lastIndex);
document.getElementById('emoji').innerHTML = stripedEmoStringArray;
}
<p id="emoji">
😀 🎃 👪
</p>
<button onclick="removeEmoji()">Remove</button>

I hope this is what you want.
var emoString = "😀 🎃 👪";
emoString = emoString.slice(0, -2);
However, this would work only if you have 3 emojis in total. Hence to achieve a generalised solution, you can use the underscore functions split() and javascript function join() :
var emoString = "😀 🎃 👪";
emoString = _.rest(emoString.split(' ')).join(' ')
Hope this will solve your issue.

Ok, here is how I solved it:
function deleteEmoji(emojiStr) {
let emojisArray = emojiStr.match(/([\uD800-\uDBFF][\uDC00-\uDFFF])/g);
emojisArray = emojisArray.splice(0, emojisArray.length - 1);
return emojisArray.join("");
}
let emojitext = "😀🎃👪";
console.log(deleteEmoji(emojitext));

I was actually surprised that unicode in this day an age is still not fully supported in browsers. I assume a lot of this is down to windows and it's version of UTF-16.
The OP I believe has found his own solution to the original problem, but I thought there has to be a more generic solution to surrogate pair unicode characters.
Anyway, so my solution is convert the text into a UTF-32 array, these can then be manipulated must easier, using slice etc.
After you have done what you want to the array, just convert back.
Below is an example.
Some of the code I got from -> Is it possible to convert a string containing "high" unicode chars to an array consisting of dec values derived from utf-32 ("real") codes?
and http://speakingjs.com/es5/ch24.html
function decodeUnicode(str) {
const r = [];
let i = 0;
while(i < str.length) {
let chr = str.charCodeAt(i++);
if(chr >= 0xD800 && chr <= 0xDBFF) {
var low = str.charCodeAt(i++);
r.push(0x10000 +
((chr - 0xD800) << 10) | (low - 0xDC00));
} else {
r.push(chr);
}
}
return r;
}
function toUTF16(codePoint) {
const TEN_BITS = parseInt('1111111111', 2);
if (codePoint <= 0xFFFF) { return codePoint; }
codePoint -= 0x10000;
const leadingSurrogate = 0xD800 | (codePoint >> 10);
const trailingSurrogate = 0xDC00 | (codePoint & TEN_BITS);
return String.fromCharCode(leadingSurrogate) +
String.fromCharCode(trailingSurrogate);
}
function encodeUnicode(data) {
return data.reduce((a, v) => {
a += toUTF16(v);
return a;
},"");
}
var unicode = decodeUnicode("😀🎃👪");
for (let l = 0; l < unicode.length; l ++)
console.log(encodeUnicode(
unicode.slice(0, l ? -l : unicode.length)));
console.log("pick some random ones");
let str = "";
for (let l = 0; l < 20; l ++) {
let rnd = Math.trunc(Math.random()*unicode.length);
str += encodeUnicode(unicode.slice(rnd,rnd+1));
}
console.log(str);

How to convert text to binary code in JavaScript?

I want JavaScript to translate text in a textarea into binary code.
For example, if a user types in "TEST" into the textarea, the value "01010100 01000101 01010011 01010100" should be returned.
I would like to avoid using a switch statement to assign each character a binary code value (e.g. case "T": return "01010100) or any other similar technique.
Here's a JSFiddle to show what I mean. Is this possible in native JavaScript?

What you should do is convert every char using charCodeAt function to get the Ascii Code in decimal. Then you can convert it to Binary value using toString(2):
function convert() {
var output = document.getElementById("ti2");
var input = document.getElementById("ti1").value;
output.value = "";
for (var i = 0; i < input.length; i++) {
output.value += input[i].charCodeAt(0).toString(2) + " ";
}
}
<input id="ti1" value ="TEST"/>
<input id="ti2"/>
<button onClick="convert();">Convert!</button>
And here's a fiddle: http://jsfiddle.net/fA24Y/1/

This might be the simplest you can get:
function text2Binary(string) {
return string.split('').map(function (char) {
return char.charCodeAt(0).toString(2);
}).join(' ');
}

traverse the string
convert every character to their char code
convert the char code to binary
push it into an array and add the left 0s
return a string separated by space
Code:
function textToBin(text) {
var length = text.length,
output = [];
for (var i = 0;i < length; i++) {
var bin = text[i].charCodeAt().toString(2);
output.push(Array(8-bin.length+1).join("0") + bin);
}
return output.join(" ");
}
textToBin("!a") => "00100001 01100001"
Another way
function textToBin(text) {
return (
Array
.from(text)
.reduce((acc, char) => acc.concat(char.charCodeAt().toString(2)), [])
.map(bin => '0'.repeat(8 - bin.length) + bin )
.join(' ')
);
}

Here's a pretty generic, native implementation, that I wrote some time ago,
// ABC - a generic, native JS (A)scii(B)inary(C)onverter.
// (c) 2013 Stephan Schmitz <eyecatchup#gmail.com>
// License: MIT, http://eyecatchup.mit-license.org
// URL: https://gist.github.com/eyecatchup/6742657
var ABC = {
toAscii: function(bin) {
return bin.replace(/\s*[01]{8}\s*/g, function(bin) {
return String.fromCharCode(parseInt(bin, 2))
})
},
toBinary: function(str, spaceSeparatedOctets) {
return str.replace(/[\s\S]/g, function(str) {
str = ABC.zeroPad(str.charCodeAt().toString(2));
return !1 == spaceSeparatedOctets ? str : str + " "
})
},
zeroPad: function(num) {
return "00000000".slice(String(num).length) + num
}
};
and to be used as follows:
var binary1 = "01100110011001010110010101101100011010010110111001100111001000000110110001110101011000110110101101111001",
binary2 = "01100110 01100101 01100101 01101100 01101001 01101110 01100111 00100000 01101100 01110101 01100011 01101011 01111001",
binary1Ascii = ABC.toAscii(binary1),
binary2Ascii = ABC.toAscii(binary2);
console.log("Binary 1: " + binary1);
console.log("Binary 1 to ASCII: " + binary1Ascii);
console.log("Binary 2: " + binary2);
console.log("Binary 2 to ASCII: " + binary2Ascii);
console.log("Ascii to Binary: " + ABC.toBinary(binary1Ascii)); // default: space-separated octets
console.log("Ascii to Binary /wo spaces: " + ABC.toBinary(binary1Ascii, 0)); // 2nd parameter false to not space-separate octets
Source is on Github (gist): https://gist.github.com/eyecatchup/6742657
Hope it helps. Feel free to use for whatever you want (well, at least for whatever MIT permits).

var PADDING = "00000000"
var string = "TEST"
var resultArray = []
for (var i = 0; i < string.length; i++) {
var compact = string.charCodeAt(i).toString(2)
var padded = compact.substring(0, PADDING.length - compact.length) + compact
resultArray.push(padded)
}
console.log(resultArray.join(" "))

The other answers will work for most cases. But it's worth noting that charCodeAt() and related don't work with UTF-8 strings (that is, they throw errors if there are any characters outside the standard ASCII range). Here's a workaround.
// UTF-8 to binary
var utf8ToBin = function( s ){
s = unescape( encodeURIComponent( s ) );
var chr, i = 0, l = s.length, out = '';
for( ; i < l; i ++ ){
chr = s.charCodeAt( i ).toString( 2 );
while( chr.length % 8 != 0 ){ chr = '0' + chr; }
out += chr;
}
return out;
};
// Binary to UTF-8
var binToUtf8 = function( s ){
var i = 0, l = s.length, chr, out = '';
for( ; i < l; i += 8 ){
chr = parseInt( s.substr( i, 8 ), 2 ).toString( 16 );
out += '%' + ( ( chr.length % 2 == 0 ) ? chr : '0' + chr );
}
return decodeURIComponent( out );
};
The escape/unescape() functions are deprecated. If you need polyfills for them, you can check out the more comprehensive UTF-8 encoding example found here: http://jsfiddle.net/47zwb41o

Just a hint into the right direction
var foo = "TEST",
res = [ ];
foo.split('').forEach(function( letter ) {
var bin = letter.charCodeAt( 0 ).toString( 2 ),
padding = 8 - bin.length;
res.push( new Array( padding+1 ).join( '0' ) + bin );
});
console.log( res );

8-bit characters with leading 0
'sometext'
.split('')
.map((char) => '00'.concat(char.charCodeAt(0).toString(2)).slice(-8))
.join(' ');
If you need 6 or 7 bit, just change .slice(-8)

Thank you Majid Laissi for your answer
I made 2 functions out from your code:
the goal was to implement convertation of string to VARBINARY, BINARY and back
const stringToBinary = function(string, maxBytes) {
//for BINARY maxBytes = 255
//for VARBINARY maxBytes = 65535
let binaryOutput = '';
if (string.length > maxBytes) {
string = string.substring(0, maxBytes);
}
for (var i = 0; i < string.length; i++) {
binaryOutput += string[i].charCodeAt(0).toString(2) + ' ';
}
return binaryOutput;
};
and backward convertation:
const binaryToString = function(binary) {
const arrayOfBytes = binary.split(' ');
let stringOutput = '';
for (let i = 0; i < arrayOfBytes.length; i++) {
stringOutput += String.fromCharCode(parseInt(arrayOfBytes[i], 2));
}
return stringOutput;
};
and here is a working example: https://jsbin.com/futalidenu/edit?js,console

Provided you're working in node or a browser with BigInt support, this version cuts costs by saving the expensive string construction for the very end:
const zero = 0n
const shift = 8n
function asciiToBinary (str) {
const len = str.length
let n = zero
for (let i = 0; i < len; i++) {
n = (n << shift) + BigInt(str.charCodeAt(i))
}
return n.toString(2).padStart(len * 8, 0)
}
It's about twice as fast as the other solutions mentioned here including this simple es6+ implementation:
const toBinary = s => [...s]
.map(x => x
.codePointAt()
.toString(2)
.padStart(8,0)
)
.join('')
If you need to handle unicode characters, here's this guy:
const zero = 0n
const shift = 8n
const bigShift = 16n
const byte = 255n
function unicodeToBinary (str) {
const len = str.length
let n = zero
for (let i = 0; i < len; i++) {
const bits = BigInt(str.codePointAt(i))
n = (n << (bits > byte ? bigShift : shift)) + bits
}
const bin = n.toString(2)
return bin.padStart(8 * Math.ceil(bin.length / 8), 0)
}

this seems to be the simplified version
Array.from('abc').map((each)=>each.charCodeAt(0).toString(2)).join(" ")

This is as short as you can get. It's based on the top-rated answer but transformed to a reduce function.
"TEST".split("").reduce(function (a, b) { return a + b.charCodeAt(0).toString(2)}, "")

const textToBinary = (string) => {
return string.split('').map((char) =>
char.charCodeAt().toString(2)).join(' ');
}
console.log(textToBinary('hello world'))

var UTF8ToBin=function(f){for(var a,c=0,d=(f=unescape(encodeURIComponent(f))).length,b="";c<d;c++){for(a=f.charCodeAt(c).toString(2);a.length%8!=0;){a="0"+a}b+=a}return b},binToUTF8=function(f){for(var a,c=0,d=f.length,b="";c<d;c+=8){b+="%"+((a=parseInt(f.substr(c,8),2).toString(16)).length%2==0?a:"0"+a)}return decodeURIComponent(b)};
This is a small minified JavaScript Code to convert UTF8 to Binary and Vice versa.

This is a solution for UTF-8-based textual binary representation. It leverages TextEncoder, which encodes a string to its UTF-8 bytes.
This solution separates characters by spaces. The individual "byte-bits" of multi-byte characters are separated by a minus character (-).
// inspired by https://stackoverflow.com/a/40031979/923560
function stringToUtf8BinaryRepresentation(inputString) {
const result = Array.from(inputString).map(
char => [... new TextEncoder().encode(char)].map(
x => x.toString(2).padStart(8, '0')
).join('-')
).join(' ');
return result;
}
// ### example usage #########################
function print(inputString) {
console.log("--------------");
console.log(inputString);
console.log(stringToUtf8BinaryRepresentation(inputString));
}
// compare with https://en.wikipedia.org/wiki/UTF-8#Encoding
// compare with https://en.wikipedia.org/wiki/UTF-8#Codepage_layout
// compare with UTF-16, which JavaScript uses for strings: https://en.wikipedia.org/wiki/UTF-16#Examples
print("TEST");
print("hello world");
print("$");
print("£");
print("€");
print("한");
print("𐍈");
print("παράδειγμα");
print("🤡");
print("👨‍👩‍👧‍👦");
print("👩🏻‍🤝‍🧑🏿");
print("🇺🇦");

use the code: 'text'.split('').map(e=>{return e.charCodeAt(0).toString(2)}) e.g.-
const text='some text';
const output=text.split('').map(e=>{return e.charCodeAt(0).toString(2)})

Simple using Buffer
const text = "TEST";
[...Buffer.from(text).values()] // [ 84, 69, 83, 84 ]
.map(byte => byte.toString(2).padStart(8, 0)) // [ '01010100', '01000101', '01010011', '01010100' ]
.join(' ') // '01010100 01000101 01010011 01010100'

The shortest and simplest solution:
"x".charCodeAt().toString(2) // 1111000
String.charCodeAt() charCodeAt(0) returns unicode: "x".charCodeAt() // 120
Object.toString() charCodeAt().toString(2) converts unicode to binary.
For multiple string characters:
[..."Tesla"].map((i) => i.charCodeAt().toString(2)).join(" ");
// 1010100 1100101 1110011 1101100 1100001
Spread syntax (...)
[..."Tesla"] // ['T', 'e', 's', 'l', 'a']
Array.map()
[..."Tesla"].map((i) => i.charCodeAt()) // [84, 101, 115, 108, 97]
Array.join() Put a space " " after each element in the array map(i) and convert the array to string.

I'm pretty sure that you can do something like this:
Returns a STRING:
const toBinary = (str)=>{
let r = []
for (let i=0; i<str.length; i++) {
r.push(str.charCodeAt(i).toString(2));
}
return r.join("");
}
Or, as an int:
const toBinary = (str)=>{
let r = []
for (let i=0; i<str.length; i++) {
r.push(str.charCodeAt(i).toString(2));
}
return parseInt(r.join(""));
}

how to parse string to int in javascript

i want int from string in javascript how i can get them from
test1 , stsfdf233, fdfk323,
are anyone show me the method to get the integer from this string.
it is a rule that int is always in the back of the string.
how i can get the int who was at last in my string

var s = 'abc123';
var number = s.match(/\d+$/);
number = parseInt(number, 10);
The first step is a simple regular expression - \d+$ will match the digits near the end.
On the next step, we use parseInt on the string we've matched before, to get a proper number.

You can use a regex to extract the numbers in the string via String#match, and convert each of them to a number via parseInt:
var str, matches, index, num;
str = "test123and456";
matches = str.match(/\d+/g);
for (index = 0; index < matches.length; ++index) {
num = parseInt(matches[index], 10);
display("Digit series #" + index + " converts to " + num);
}
Live Example
If the numbers really occur only at the ends of the strings or you just want to convert the first set of digits you find, you can simplify a bit:
var str, matches, num;
str = "test123";
matches = str.match(/\d+/);
if (matches) {
num = parseInt(matches[0], 10);
display("Found match, converts to: " + num);
}
else {
display("No digits found");
}
Live example
If you want to ignore digits that aren't at the end, add $ to the end of the regex:
matches = str.match(/\d+$/);
Live example

var str = "stsfdf233";
var num = parseInt(str.replace(/\D/g, ''), 10);

var match = "stsfdf233".match(/\d+$/);
var result = 0; // default value
if(match != null) {
result = parseInt(match[0], 10);
}

Yet another alternative, this time without any replace or Regular Expression, just one simple loop:
function ExtractInteger(sValue)
{
var sDigits = "";
for (var i = sValue.length - 1; i >= 0; i--)
{
var c = sValue.charAt(i);
if (c < "0" || c > "9")
break;
sDigits = c + sDigits;
}
return (sDigits.length > 0) ? parseInt(sDigits, 10) : NaN;
}
Usage example:
var s = "stsfdf233";
var n = ExtractInteger(s);
alert(n);

This might help you
var str = 'abc123';
var number = str.match(/\d/g).join("");

Use my extension to String class :
String.prototype.toInt=function(){
return parseInt(this.replace(/\D/g, ''),10);
}
Then :
"ddfdsf121iu".toInt();
Will return an integer : 121

First positive or negative number:
"foo-22bar11".match(/-?\d+/); // -22

javascript:alert('stsfdf233'.match(/\d+$/)[0])
Global.parseInt with radix is overkill here, regexp extracted decimal digits already and rigth trimmed string