Splitting String and taking out specific elements in node js - javascript

I have Sample String like this
"Organisation/Guest/images/guestImage.jpg"
I need to take out Organisation,Guest separately.
I have tried split() but can't get desired output.


var str = "Organisation/Guest/images/guestImage.jpg";
var res = str.split("/");
console.log(res[0]);
console.log(res[1]);


You can use of String.replace() along with regex
const regex = /Organisation\/|\/Organisation/;
console.log('Organisation/Guest/images/guestImage.jpg'.replace(regex, ''));
console.log('Guest/Organisation/images/guestImage.jpg'.replace(regex, ''));
console.log('Guest/images/guestImage.jpg/Organisation'.replace(regex, ''));


var yourString = "Organisation/Guest/images/guestImage.jpg";
yourString.split('/')
// this returns all the words in an array
yourString[0] // returns Organisation
yourString[1] // returns Guest and so on
When you run .split() on a string, it will return a new array with all the words in it. In the code I am splitting by the slash /
Then I save the new array in a variable. Now you should know we can access array properties like this: array[0] where 0 is the first index position or the first word, and so on.

Related

Split a single array with respect to comma in javascript

I am getting an array of single string $scope.Obj= ["Talking Spanish,Spanish food,Spanish things,Football"];
The split should be by watching ,
I need to break it down = ["Talking Spanish","Spanish food","Spanish things","Football"];
How can I do it using javascript?

You can use split
let arr = ["Talking Spanish,Spanish food,Spanish things,Football"];
let op = arr[0].split(',')
console.log(op)

You can split 0th index of $scope.Obj with , and reassign to $scope.Obj.
$scope={};
$scope.Obj= ["Talking Spanish,Spanish food,Spanish things,Football"];
$scope.Obj=$scope.Obj[0].split(",")
console.log($scope.Obj);

str.split(separator, limit)
The above is common syntax to split a array
https://medium.freecodecamp.org/how-to-make-your-react-native-app-respond-gracefully-when-the-keyboard-pops-up-7442c1535580

The split() method splits a String object into an array of strings by separating the string into substrings, using a specified separator string to determine where to make each split.
In the following example, split() looks for spaces in a string and returns the first 3 splits that it finds.
var myString = 'Hello World. How are you doing?';
var splits = myString.split(' ', 3);
console.log(splits);
This script displays the following:
["Hello", "World.", "How"]

javascript split string function not working

I am trying to split a string:
var str = "*HQ,6170930129,V1,185409,A,3132.3228,N,07424.7726,E,000.04,000,280618,FBFFBBFF,410,04,08028,40555#*HQ,6170930129,V1,185413,A,3132.3226,N,07424.7735,E,000.15,000,280618,FBFFBBFF,410,04,08028,40555"
var res = device_data.split('*');
But it's not working. it's just displaying this string
var str = "*HQ,6170930129,V1,185409,A,3132.3228,N,07424.7726,E,000.04,000,280618,FBFFBBFF,410,04,08028,40555#*HQ,6170930129,V1,185413,A,3132.3226,N,07424.7735,E,000.15,000,280618,FBFFBBFF,410,04,08028,40555"
var res = str.split('*');
console.dir(res)
,HQ,6170930129,V1,185409,A,3132.3228,N,07424.7726,E,000.04,000,280618,FBFFBBFF,410,04,08028,40555#,HQ,6170930129,V1,185413,A,3132.3226,N,07424.7735,E,000.15,000,280618,FBFFBBFF,410,04,08028,40555
Instead of creating an array with two elements.

IMHO, you want something like this:
var str = "*HQ,6170930129,V1,185409,A,3132.3228,N,07424.7726,E,000.04,000,280618,FBFFBBFF,410,04,08028,40555#*HQ,6170930129,V1,185413,A,3132.3226,N,07424.7735,E,000.15,000,280618,FBFFBBFF,410,04,08028,40555"
splitStrArr = str.split('*').filter(str => str != "")
console.log(splitStrArr)
console.log(splitStrArr[0])
console.log(splitStrArr[1])

You are getting a string with a period in the beginning because whatever you are doing leads to the result of String#split being converted to a string. String#split returns an array. An array converted to a string is of the form of element0,element1,element2 ... elements separated by commas.
The result of String#split in your case is ["",...] with 3 elements since your string begins with the character '*' you are searching, so String#split will create an empty string as the first element of the returned array. So the result is exactly as expected, and String#split is working as intended.
get rid of the first character of the string,
mystring.substr(1).split('*')
get rid of the empty strings
mystring.split('*').filter(s=>s!='')
to obtain the desired result.

You can use:
var res = str.split("#");
You can check in Javascript console in browser itself.
As a suggestion/ idea, you can always use the browser console, for example, Chrome browser, to execute simple scripts like these.
This way, you can save time, as it is easier to check your data structures, their internal data.

If you try
var res = str.split('*');
you obtain three elements:
res[0] is '' (empty string)
res[1] is 'HQ,61...'
res[2] is 'HQ,...'

Substring a part of a string using angularjs

I have a string like this string(1), I want to get substring remove the last part to obtain just string any suggestions please!!
PS.the string could be: sringggg(125).

You can use various options to get the desired string.
//With regular expression with split() and fetch the first element of array
console.log('sringggg(125)'.split(/\(\d+\)/)[0]);
//Using string with split() and fetch the first element of array
console.log('sringggg(125)'.split('(')[0]);
//Using substr and indexOf
var str = 'sringggg(125)'
console.log(str.substr(0, str.indexOf('(')));
References
String.prototype.split()
String.prototype.indexOf()

If string is always in same pattern and ' ( ' is a separator use split .
var string = 'string(1)'
var result = string .split('(')[0];

Try using regexp
var tesst = "string(1)"
var test = tesst.match(/^[^\(]+/);
// test = "string"

String split returns an array with more elements than expected (empty elements)

I don't understand this behaviour:
var string = 'a,b,c,d,e:10.';
var array = string.split ('.');
I expect this:
console.log (array); // ['a,b,c,d,e:10']
console.log (array.length); // 1
but I get this:
console.log (array); // ['a,b,c,d,e:10', '']
console.log (array.length); // 2
Why two elements are returned instead of one? How does split work?
Is there another way to do this?

You could add a filter to exclude the empty string.
var string = 'a,b,c,d,e:10.';
var array = string.split ('.').filter(function(el) {return el.length != 0});

A slightly easier version of #xdazz version for excluding empty strings (using ES6 arrow function):
var array = string.split('.').filter(x => x);

This is the correct and expected behavior. Given that you've included the separator in the string, the split function (simplified) takes the part to the left of the separator ("a,b,c,d,e:10") as the first element and the part to the rest of the separator (an empty string) as the second element.
If you're really curious about how split() works, you can check out pages 148 and 149 of the ECMA spec (ECMA 262) at http://www.ecma-international.org/publications/files/ECMA-ST/Ecma-262.pdf

Use String.split() method with Array.filter() method.
var string = 'a,b,c,d,e:10.';
var array = string.split ('.').filter(item => item);
console.log(array); // [a,b,c,d,e:10]
console.log (array.length); // 1

https://developer.mozilla.org/en-US/docs/JavaScript/Reference/Global_Objects/String/split
trim the trailing period first
'a,b,c,d,e:10.'.replace(/\.$/g,''); // gives "a,b,c,d,e:10"
then split the string
var array = 'a,b,c,d,e:10.'.replace(/\.$/g,'').split('.');
console.log (array.length); // 1

That's because the string ends with the . character - the second item of the array is empty.
If the string won't contain . at all, you will have the desired one item array.
The split() method works like this as far as I can explain in simple words:
Look for the given string to split by in the given string. If not found, return one item array with the whole string.
If found, iterate over the given string taking the characters between each two occurrences of the string to split by.
In case the given string starts with the string to split by, the first item of the result array will be empty.
In case the given string ends with the string to split by, the last item of the result array will be empty.
It's explained more technically here, it's pretty much the same for all browsers.

According to MDN web docs:
Note: When the string is empty, split() returns an array containing
one empty string, rather than an empty array. If the string and
separator are both empty strings, an empty array is returned.
const myString = '';
const splits = myString.split();
console.log(splits);
// ↪ [""]

Well, split does what it is made to do, it splits your string. Just that the second part of the split is empty.

Because your string is composed of 2 part :
1 : a,b,c,d,e:10
2 : empty
If you try without the dot at the end :
var string = 'a,b,c:10';
var array = string.split ('.');
output is :
["a,b,c:10"]

You have a string with one "." in it and when you use string.split('.') you receive array containing first element with the string content before "." character and the second element with the content of the string after the "." - which is in this case empty string.
So, this behavior is normal. What did you want to achieve by using this string.split?

try this
javascript gives two arrays by split function, then
var Val = "abc#gmail.com";
var mail = Val.split('#');
if(mail[0] && mail[1]) { alert('valid'); }
else { alert('Enter valid email id'); valid=0; }
if both array contains length greater than 0 then condition will true

Javascript match

Suppose this is my code
var str="abc=1234587;abc=19855284;abc=1234587;abc=19855284;abc=1234587;abc=19855284;abc=1234587;abc=19855284;abc=1234587;abc=19855284;abc=1234587;abc=19855284;abc=1234587;abc=19855284;abc=1234587;abc=19855284;abc=1234587;abc=19855284;abc=1234587;abc=19855284;";
var patt1=/abc=([\d]+)/g;
document.write(str.match(patt1));
i want the output as 1234587,19855284
this doesnt return the number but instead returns the complete string which is in the pattern
if i remove 'g' from the pattern it returns abcd=1234578,1234578 what am i doing wrong??

match() returns an array. The first entry (index 0) is always the matching string. Following that you get the matching group(s).
The toString()-logic of an array takes all elements and joins them with ", ". You can use e.g. join("-") to change that.

Try following code.
var str = "abc=1234587;abc=19855284;abc=1234587;abc=19855284;abc=1234587;abc=19855284;abc=1234587;abc=19855284;abc=1234587;abc=19855284;abc=1234587;abc=19855284;abc=1234587;abc=19855284;abc=1234587;abc=19855284;abc=1234587;abc=19855284;abc=1234587;abc=19855284;";
str = str.replace(/abc=/gi, '');
document.write(str);

If this is what you want
1234587,19855284,1234587,19855284,1234587,19855284,1234587,19855284,1234587,19855284,1234587,19855284,1234587,19855284,1234587,19855284,1234587,19855284,1234587,19855284
then try this
var str="abc=1234587;abc=19855284;abc=1234587;abc=19855284;abc=1234587;abc=19855284;abc=1234587;abc=19855284;abc=1234587;abc=19855284;abc=1234587;abc=19855284;abc=1234587;abc=19855284;abc=1234587;abc=19855284;abc=1234587;abc=19855284;abc=1234587;abc=19855284;";
var patt1=/([\d]+)/g;
document.write(str.match(patt1));
or you can use the array index as sjngm mentioned

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