What I am trying to achieve is a tooltip like positioning of an element that's inside the same contain as the element that when clicked will display a div that contains a table.
The full code can be found here:
http://jsbin.com/xihebol
When somebody clicks on .child-table-link the .child-data-table-container is supposed to be positioned relative to the clicked link.
I am doing this inside the click handler of the .child-table-link:
var _this = $(this);
$(".child-data-table-container").css({
"left": _this.offset().left - ($(this).width / 2),
"top": _this.offset().top
})
top works but left doesn't. How I do make it work? In general way to position an element relative to another element in the view-port is what I am looking for.
The problem is you are calculating the left position wrong, "left" will be the position of the left edge of the tooltip container, so if you want it to sit just to the left of your link, it only needs to be set to the negative width of the tooltip container. Check this out:
.canvas {
display: flex;
align-items: center;
justify-content: center;
}
.linkContainer {
position: relative;
background: #000;
}
.tooltip {
position: absolute;
width: 100px;
height: 100px;
background: green;
top: 0;
left: -100px;
}
<div class='canvas'>
<div class='linkContainer'>
<a href='#'>LINK</a>
<div class='tooltip'></div>
</div>
</div>
Notice how the tooltip width is 100px, and the left is set to -100px.
Related
I'm trying to replicate this overlay phone effect from this website:
https://www.beemit.com.au/
Basically, when you scroll down, the contents inside the fixed div (phone) also change.
I cannot grasp my head around the revealing effect created when you scroll down. I have only managed to create the fixed div and the various sections on the webpage.
Here's a simple version of the overlay-on-scroll.
There are 3 elements, the first image you want to be shown in the 'phone', the second image which gradually gets revealed and the footer element. They have different z-indexes so footer is behind both first and second and second is behind first.
The phone has a fixed position so it doesn't move on scrolling. The footer is placed relative to the body (or whatever container you have) just out of view at 100%.
We introduce a simple event listener on scrolling which tests whether there is an overlap between the footer and the phone. If there is then we set the height of the first image element to be its original height minus the overlap. This reveals the bottom part of the second element.
Without seeing your code I can't tell whether you need more sophistication (for example, you have to be aware of stacking contexts if your phone and footer are not in the same one).
const footer = document.querySelector('.footer');
const first = document.querySelector('.first');
const firstBottom = first.getBoundingClientRect().bottom;
const firstHeight = firstBottom - first.getBoundingClientRect().top;
function checkOverlay() {
const top = footer.getBoundingClientRect().top;
if ( top < firstBottom) {
first.style.height = firstHeight - firstBottom + top + 'px';
}
}
body {
width:100vw;
height: 100vh;
overflow-y: scroll;
overflow-x: hidden;
}
.first, .second {
position: fixed;
top: 50%;
left: 50%;
border: 1px solid black;
width: 20vmin;
height: 30vmin;
overflow:hidden;
}
.first {
background-image: linear-gradient(magenta, pink);
z-index: 0;
}
.second {
background-image: linear-gradient(cyan, lime);
z-index: -1;
}
.footer {
width: 100%;
height: 50%;
background-image: linear-gradient(red,blue);
position: relative;
top: 100%;
z-index: -2;
}
<body onscroll="checkOverlay();">
<div class="first"></div>
<div class="second"></div>
<div class="footer"></div>
</body>
I have a div that after I click an element(button1), expands its height. I then have another button appear which allows you to shrink the div(button2). After I click button1, the div expands and button2 shows at the bottom. I can then click button2 to shrink the div back to normal, but if I expand the div again, button2 is now off the edge of the screen, albeit in the same bottom location, just far left rather than centered.
I had to set the margin on button2 to -25px since the absolute positioning was kicking it off-center. And I need to use absolute positioning since it seemed it was only way to get the button to appear at the bottom of div after it had expanded.
$(".button1").on("click", function(){
$(".button1" ).fadeOut(200);
$("#block3").animate({
height: '800px'
}, 600, function() {
$(".button2").fadeIn(200);
});
});
$(".button2").on("click", function(){
$(".button2").fadeOut(200);
$("#block3").animate({
height: '400px'
}, 600,function(){
$(".button1" ).fadeIn(200);
});
});
.button2{
width: 50px;
height: 50px;
display:none;
position: absolute;
margin-left: 25px;
}
.button1{
width: 50px;
height: 50px;
margin-top: 25px;
image-rendering: auto;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="row">
<div class = "col-md-12" id = "block3">
<img src="https://placehold.it/120x80/00aaaa/fff/?text=scroll.png" class = "button1" />
<img src="https://placehold.it/120x80/00aaaa/fff/?text=scroll1.png" class = "button2" />
</div>
</div>
Uploaded the code.
https://jsfiddle.net/bs9xhe5e/2/
On the second click it changed the inline styling to display:block instead of display:inline, if you just add the display:inline into your jQuery it works;
https://jsfiddle.net/havL1z3m/
Added
$(".button2").css({display:"inline"});
The reason .button2 is showing up all the way to the left is that the absolute positioning gives it a default left of 0px.
Probably the easiest fix would be to remove absolute position, as well as the margin-left. Instead, to get .button2 to the bottom of the section, just set margin-top: 725px.
.button2{
width: 50px;
height: 50px;
display:none;
margin-top: 725px;
}
And then you will no longer need to use .css() to change bottom of .button2.
Check out this working fiddle: https://jsfiddle.net/gkpx7L15/
Change button2 styles like this:
.button2{
width: 50px;
height: 50px;
display:none;
position: absolute;
margin-left: -25px;
left:50%;//added style
}
https://jsfiddle.net/bs9xhe5e/3/
And everything will work fine
NOTE: Element will be positioned to the center of parent like this only when width is fixed like here. Example:
.someItem{
width: someWidth;//here we set some width to element
left: 50%; //Here we set position from the left
margin-left: -(somewidth/2);//here we set -half of the element's width for margin-left
}
I would like to display indicators for a certain div to show that it can be scrolled right or left depending on its state. To do so I would need to know if element can be scrolled to respective positions, e.g. if there is content to be seen on the right show indicator and after scrolling show another indicator on the left to indicate that users can now scroll there as well. I have a simple setup like this one: https://jsfiddle.net/udv8u596/
(You can scroll horizontally, scrollbar is hidden intentionally)
HTML:
<div class="scroll-container">
<div class="scroll-content">
Scroll Me Horizontally Scroll Me Horizontally Scroll Me Horizontally Scroll Me Horizontally Scroll Me Horizontally Scroll Me Horizontally Scroll Me Horizontally
</div>
</div>
CSS:
.scroll-container {
width: 80%;
margin: 0 auto;
background: cyan;
overflow-y: hidden;
height: 36px;
}
.scroll-content {
padding: 10px 0;
height: 50px;
white-space: nowrap;
overflow-x: scroll;
overflow-y: hidden;
}
To check if an element is overflowing along the x-axis, you can simply compare its computed width, accessible via jQuery's .width() method, and its scrollWidth, a native JS function:
var $ele = $('.scroll-content'),
overflowing = $ele[0].scrollWidth > $ele.width();
You can then check the boolean value of overflowing if the element is overflowing or not. However, note that if you want this variable to be updated if the window resizes, a little more work has to be done:
var $ele = $('.scroll-content'),
overflowing = function() {
if($ele[0].scrollWidth > $ele.width()) {
return true;
} else {
return false;
}
};
console.log(overflowing());
$(window).resize(function() {
console.log(overflowing());
});
Here's a fiddle with the above logic implemented, with some slight modifications: https://jsfiddle.net/teddyrised/udv8u596/5/
Ilya basically you need to check your element right postion. On way of achieving this is to set the inner element to have absolute oistion and get right postion with jQuery
parseInt($('.scroll-content').css('right')) >= 0
I have modified you code as: https://jsfiddle.net/udv8u596/4/
In this example before animating the element it checks if the righ position is bigger than 0.
Please not that righ position is calculated based on the parent element. Left position is set to be 0 in the css but righ postion will be calculated in this example is ~-250.
I hope this gives you an idea how to solve your problem.
Here's a quick start for what you are looking for :
HTML
<div class="scroll-container">
<div class="mask">
<div class="scroll-content">
Scroll Me Horizontally Scroll Me Horizontally Scroll Me Horizontally Scroll Me Horizontally Scroll Me Horizontally Scroll Me Horizontally Scroll Me Horizontally
</div>
</div>
</div>
<div class="scrollRight">Scroll Right »</div>
<div class="scrollLeft">» Scroll Left </div>
CSS
.scroll-container {
width: 80%;
margin: 0 auto;
background: cyan;
overflow-y: hidden;
overflow-x: hidden;
height: 36px;
}
.mask{
position:relative;
overflow-x: hidden;
overflow-y: hidden;
height: 36px;
width: 100%;
}
.scroll-content {
position:absolute;
padding: 10px 0;
height: 50px;
white-space: nowrap;
overflow-x: visible;
width:auto;
}
.scrollRight, .scrollLeft{
font-size:10px;
display:none;
}
JS
var contentWidth = $(".scroll-content").width();
var containerWidth = $(".scroll-container").width();
if(contentWidth>containerWidth){
$(".scrollRight").show();
}
$("body").on("click", ".scrollRight", function(){
var scrollValue = contentWidth-containerWidth;
$(".scroll-content").animate({"margin-left":"-"+scrollValue+"px"});
$(".scrollRight").hide();
$(".scrollLeft").show();
})
$("body").on("click", ".scrollLeft", function(){
var scrollValue = contentWidth-containerWidth;
$(".scroll-content").animate({"margin-left":"0px"});
$(".scrollRight").show();
$(".scrollLeft").hide();
})
See Update JSFiddle
I have html sturcture
<div id="bg" class="layer">
<img id="trackmap" src="images/back_2416.jpg" width="1208" height="768" class=" ui-draggable map-icon" usemap="#main-map" data-zoom-image="images/background_zoom.jpg" data-big="images/background_zoom.jpg" style="position: relative; left: -439px; top: -272.6px; margin: 0px; display: inline-block; height: 1327.2px; width: 2088px;">
<div id="nav-text">LOREM IPSUM.</div>
</div>
Jquery
var windowHeight = $("#trackmap").height();
var windowWidth = $("#trackmap").width();
var text_height=((windowHeight)-(100));
$("#nav-text").css("top",windowHeight);
Css
.layer {
position: absolute;
width: 1208px;
height: 768px;
}
#nav-text{
z-index: 200;
color: white;
position: absolute;
font-size: 10px;
margin-left: 715px;
width: 310px;
height: 10px;
position: fixed;
bottom: 5px;}
I just want to fix the nav-text to the bottom right whatsoever.. Now i problem i am facing is theres zoom function on the trackmap.. which increases the height and width of the image ..so the text comes in between of the image ..intereferring with the image.. I have tried taking the image width height using jquery ..but somehow its not working
I am not sure I am following your issue here, but it sounds like you are trying to get a div to be in the bottom-right of another div no matter what size it is. That can be done by setting the parent div position to relative which you have, and the child div position to absolute. You have that set but then override it by setting the position to fixed lower in the CSS. You will also want to set the bottom to 0 and the right to 0.
This will position the child div to the bottom right of the parent div. Then you can get rid of your jQuery. Hopefully this helps.
Ok.. I am in a hurry to catch the bus.. but here's a fiddle that illustrates the idea..
basically you will need to use the scrolltop and left parameters to do so:
$(".container").on("scroll", function() {
$(".nav-text").css("top", $(this).prop("scrollTop") + 130);
$(".nav-text").css("left", $(this).prop("scrollLeft") + 120);
});
but move the scrolls first.. sorry I need to go now..
You can achieve this by not fixing the .layer width and height, using display:inline-block; to prevent the div from filling the whole container width. At that point, the .layer size will match the image size whatever it is.
Finally you just need to set the text to absolute position and bottom and right properties too.
.parent{
display:inline-block;
position:relative;
}
.children{
position:absolute;
bottom:0;
right:0;
}
Here is the fiddle explaining
And here is the proof it works even if the image size is changed(click on the image).
Fiddle 2
I'm currently coding a simple game in javascript. The game takes place in a div, called #box. And the enemy is a div called #enemy .
<div id="box">
<div id="prepend">
<div id="hero"></div>
</div>
<div id="enemy"></div>
</div>
Inside this #box the #enemy will move about using a setInterval() function generating random numbers (animating to x, y) . However, when I do this, somehow the point of origin where the coordinates start is at top left hand corner of the window when it should be in the top left hand corner in the #box. This is how I have been trying to generate random numbers to keep the #enemy inside the #box
var test = Math.floor(Math.random() * (1500 - $("#box").offset().left) + 0),
test2 = Math.floor(Math.random() * (750 - $("#box").offset().top) + 0);
But the problem I obviously have is that it keeps animating outside the #box.
CSS :
#box{
width:640px;
height:400px;
float: left;
background:url(../png/space.jpg);
margin: 0 0 0 100px;
}
#enemy {
width: 69px;
height: 50px;
position: absolute;
margin: 100px 0 0 100px;
background:url(../png/target2.png);
z-index:2;
}
The container div needs to have position: relative. Otherwise the position of the window, or the closest parent element with a relative position will be used in determining the inner div's position. By making the parent have a relative position, the child div will position itself relative to its parent as opposed to relative to the window.
You need:
position: relative;
in your #box CSS, for the absolute position on your #enemy to be relative to the box.
Add position: relative; to #box to make #enemy position relative to #box.
To make #boxes children position relative to it, you can use any of the following depending on your requirements:
#box { position: absolute; }
#box { position: relative; }
#box { position: fixed; }