this is a code that I want to know if I want to use in some other functions, such ForEach, map, filter, or what else?
is that possible?
const val = 'Mike,Mike#mail.com,male'
const split = val.split(',')
console.log(split) //to check
const newObj = {}
newObj.name = split[0]
newObj.email = split[1]
newObj.gender = split[2]
console.log(newObj)
const val2 = 'name:John,email:John#mail.com'
const split2 = val2.split(',')
console.log(split2) //to check
const newObj2 = {}
for(var i = 0; i < split2.length; i++) {
var data = split2[i].split(':')
newObj2[data[0]] = data[1]
}
console.log(newObj2)
want to make the code more clean and short
const val = 'Mike,Mike#mail.com,male'
const [name, email, gender] = val.split(',')
console.log({name, email, gender})
const val2 = 'name:John,email:John#mail.com'
const splitByColon = term => {
const [key, value] = term.split(':')
return {[key]: value}
}
console.log(
val2
.split(',')
.reduce((acc, term) =>
({...acc, ...splitByColon(term)}), {})
)
Another way could be
const val = 'name:Mike,email:Mike#mail.com,gender:male'
const obj = {}
val.split(',')
.map(prop => prop.split(':'))
.forEach(([key, value]) => {
obj[key] = value
})
console.log(obj)
Related
I have next array with strings:
['val1=123','val2=456']
How I can split it to object with params and values?
{
val1: 123,
val2: 456,
}
const recordStrings = ['val1=123', 'val2=456']
const record = Object.fromEntries(
recordStrings.map(str => str.split('='))
)
console.log(record)
Explanation:
recordStrings.map(str => str.split('=')) returns [[val1, 123], [val2, 456]].
Object.fromEntries(entries) creates an object from an array containing [key, value] tuples.
You can try with reduce method, it's really helpful to convert an array to any others data type like an object, string, number.
const arr = ['val1=123','val2=456'];
const items = arr.reduce((total, item) => {
const [key, value] = item.split('=');
if (key) {
total[key] = value
}
return total;
}, {})
console.log(items);
Split the strings in the array and convert the array to an object:
const res = ['val1=123','val2=456'];
const result = Object.fromEntries(res.map(x => {
const [l, r] = x.split('=');
return [l, +r];
}));
console.log(result);
let obj = {};
let arr = ['val1=123', 'val2=456'];
arr.forEach(i => {
let x = i.split('=');
obj[x[0]] = parseInt(x[1]);
});
console.log(obj);
let arr = ['val1=123', 'val2=456']
let object = {}
for (let i = 0; i < arr.length; i++) {
var split = arr[i].split("=")
object[split[0]] = split[1]
}
console.log(object); // { val1: '123', val2: '456' }
let arr = ['val1=123','val2=456'];
arr.forEach(str => {
let arrStr = str.split('=');
eval(arrStr[0] + '= ' + arrStr[1] + ';');
})
console.log(val1, val2);
OR
let arr = ['val1=123','val2=456'];
arr.forEach(str => {
let arrStr = str.split('=');
window[arrStr[0]] = arrStr[1];
})
console.log(val1, val2);
I have a string "101-2000-10-102-2000-15" which I have to map as key: 101 values: {2000, 10}.
With the below code I am able to get the output as 101 => 2000 but I am unable to the one remaining value.
This is the Code:
let myString = "101-2000-10-102-2000-15"
let strArray = myString.match(/[^-]+-[^-]+-[^-]+/g);
console.log(strArray);
let compartmentMap = new Map(strArray.map(x => x.split("-")));
console.log(compartmentMap);
My input: "101-2000-10-102-2000-15"
Desired Output: {101 => {2000,10}, 102 => {2000,15}}
You need to get an array of values as well.
let myString = "101-2000-10-102-2000-15"
let strArray = myString.match(/[^-]+-[^-]+-[^-]+/g);
console.log(strArray);
let compartmentMap = new Map(strArray.map(x => {
const [k, ...v] = x.split("-");
return [k, v];
}));
console.log(Array.from(compartmentMap));
I think I'd be fairly pedestrian about it:
const result = new Map();
const rex = /(\d+)-(\d+)-(\d+)/g;
let match;
while ((match = rex.exec(myString)) !== null) {
result.set(match[1], [match[2], match[3]]);
}
That's assuming you want the 2000, 10 part as an array.
Live Example:
const myString = "101-2000-10-102-2000-15"
const result = new Map();
const rex = /(\d+)-(\d+)-(\d+)/g;
let match;
while ((match = rex.exec(myString)) !== null) {
result.set(match[1], [match[2], match[3]]);
}
console.log([...result.entries()]);
Or with more meaningful names via named capture groups and destructuring:
const result = new Map();
const rex = /(?<key>\d+)-(?<value1>\d+)-(?<value2>\d+)/g;
let match;
while ((match = rex.exec(myString)) !== null) {
const {key, value1, value2} = match.groups;
result.set(key, [value1, value2]);
}
Live Example:
const myString = "101-2000-10-102-2000-15"
const result = new Map();
const rex = /(?<key>\d+)-(?<value1>\d+)-(?<value2>\d+)/g;
let match;
while ((match = rex.exec(myString)) !== null) {
const {key, value1, value2} = match.groups;
result.set(key, [value1, value2]);
}
console.log([...result.entries()]);
Or with the new matchAll and destructuring:
const rex = /(\d+)-(\d+)-(\d+)/g;
const result = new Map(
[...myString.matchAll(rex)].map(
([, key, value1, value2]) => [key, [value1, value2]]
)
);
Live Example:
const myString = "101-2000-10-102-2000-15"
const rex = /(\d+)-(\d+)-(\d+)/g;
const result = new Map(
[...myString.matchAll(rex)].map(
([, key, value1, value2]) => [key, [value1, value2]]
)
);
console.log([...result.entries()]);
One approach would be to just split the string, and then perform a reduce() operation for every three elements:
const s = '101-2000-10-102-2000-15';
const result = s.split('-').reduce((r, v, i, a) =>
i % 3 ? r : {...r, [v]: a.slice(i + 1, i + 3)}, {});
console.log(result);
Slight change to your code, use reduce instead of map.
let myString = "101-2000-10-102-2000-15";
let strArray = myString.match(/[^-]+-[^-]+-[^-]+/g);
console.log(strArray);
let compartmentMap = strArray.reduce((acc, curr) => {
const [a, b, c] = curr.split("-");
return Object.assign(acc, { [a]: [b, c] });
}, {});
console.log(compartmentMap);
Actually, I figured a better which gives out a Map with exact key-value pairs. All I need is to pass a Map and My array to it and it spits out the map with the key-values.
const myString = '101-2000-10-102-2000-15';
let strArray = myString.match(/[^-]+-[^-]+-[^-]+/g);
console.log(strArray);
const compartmentMap = (someMap, someArray) => (someArray.map(x => { console.log(x)
const [a, b, c] = x.split("-");
someMap.set(a, {b,c});
}));
const x = new Map();
compartmentMap(x, strArray);
console.log(x);
how can i turn this array to an object like below
let arr = ["key1:value1","key2,value2"]
to
{
"key1":"value1",
"key2":"value2"
}
Split by either colons or commas, then pass to Object.fromEntries:
const arr = ["key1:value1","key2,value2"];
const obj = Object.fromEntries(
arr.map(str => str.split(/[:,]/))
);
console.log(obj);
Try using reduce:
const arr = ["key1:value1","key2,value2"];
const object = arr.reduce((obj, item) => {
const colon = item.split(':');
if (colon.length === 2) {
obj[colon[0]] = colon[1];
return obj;
}
const comma = item.split(',');
if (comma.length === 2) {
obj[comma[0]] = comma[1];
return obj;
}
return obj;
}, {});
or forEach
const arr = ["key1:value1","key2,value2"];
const object = {};
arr.forEach(item => {
const colon = item.split(':');
if (colon.length === 2) {
obj[colon[0]] = colon[1];
}
const comma = item.split(',');
if (comma.length === 2) {
obj[comma[0]] = comma[1];
}
});
You can try with reduce()
let arr = ["key1:value1","key2,value2"];
var res = arr.reduce((a,c) => {
var k = c.split(/[:,]/)[0];
var v = c.split(/[:,]/)[1];
a[k] = v;
return a
},{});
console.log(res);
My input is like
var resources = ["user-john","user-doe", "students-Milan"];
I am trying to get an output as an object like below,
{
user: ["john", "doe"],
students: ["Milan"]
}
What am i doing wrong
var resources = ["user-john","user-doe", "students-Milan"];
let tempObj = {}
resources.forEach(o => {
let tempArr = o.split("-");
if(tempObj[tempArr[0]]){
tempObj[tempArr[0]] = [...tempArr[1], tempArr[1]]
}else{
tempObj[tempArr[0]] = [tempArr[1]]
}
})
console.log(tempObj)
You could deconstructure the splitted string and build an array as value.
var resources = ["user-john", "user-doe", "students-Milan"],
result = resources.reduce(
(r, s) =>
((key, value) => Object.assign(r, { [key]: [].concat(r[key] || [], value) }))
(...s.split('-')),
{}
);
console.log(result);
You could use reduce method here with an object as a accumulator value.
var data = ["user-john", "user-doe", "students-Milan"];
var result = data.reduce((r, e) => {
let [key, value] = e.split('-');
r[key] = (r[key] || []).concat(value)
return r;
}, {})
console.log(result)
A clean, modern solution:
var resources = ["user-john","user-doe", "students-Milan"];
const output = {}
resources.forEach(item => {
const [key, value] = item.split('-')
output[key] = [...output[key] || [], value]
})
console.log(output)
Here in this part you actually need to :
resources.forEach(o => {
let tempArr = o.split("-");
if(tempObj[tempArr[0]]){
tempObj[tempArr[0]] = [...tempObj[tempArr[0]], tempArr[1]];
}else{
tempObj[tempArr[0]] = [tempArr[1]]
}
})
var resources = ["user-john","user-doe", "students-Milan"];
var tmp = {};
resources.forEach(function(e){
var a = e.split("-");
if(typeof tmp[a[0]] == "undefined"){
tmp[a[0]] = [];
tmp[a[0]].push(a[1]);
}else{
tmp[a[0]].push(a[1]);
}
});
console.log(tmp);
You can use .push method instead [...tempArr[1], tempArr[1]]
var resources = ["user-john","user-doe", "students-Milan"];
let tempObj = {}
resources.forEach(o => {
let tempArr = o.split("-");
if(tempObj[tempArr[0]]){
tempObj[tempArr[0]].push(tempArr[1])
}else{
tempObj[tempArr[0]] = [tempArr[1]]
}
})
console.log(tempObj)
Or you can use the spread syntax on the last state of your array like [...tempObj[tempArr[0]], tempArr[1]] instead [...tempArr[1], tempArr[1]]
I want to generate a dynamic object and assign value into it. Following is the code
var chunk = "INTERNATIONALISATION#LANGUAGE#DICTIONARY#EN";
var c = chunk.split('#');
var a = {};
So the output should be like this
a["INTERNATIONALISATION"]["LANGUAGE"]["DICTIONARY"]["EN"] = 10;
Tried looping through array but nothing works for now.Please advise.
Try this:
var chunk = "INTERNATIONALISATION#LANGUAGE#DICTIONARY#EN";
var c = chunk.split('#');
var a = {};
var lastKey = c.pop();
c.reduce((obj, key) => obj[key] = obj[key] || {}, a)[lastKey] = 10;
To make it more convenient you can put it in a function:
const dynamicAssign = (object, stringPath, value) => {
const path = stringPath.split('#');
const lastKey = path.pop();
const target = path.reduce((obj, key) => obj[key] = obj[key] || {}, object);
target[lastKey] = value;
};
const a = {};
dynamicAssign(a, "INTERNATIONALISATION#LANGUAGE#DICTIONARY#EN", 10);