I'm struggling to understand Promise but it's really difficult for me.
it makes me crazy, I would appreciate your helps.
this is a code and I want "console.log(data)" after Recommend function finished
but the result is undefined.
What should I do?
many thanks
This is app.js
var _promise = function () {
return new Promise((resolve,reject) => {
var data = getJS.Recommend(req.query.User_id)
resolve(data)
}).then(function(data) {
console.log(data)
})
_promise();
}})
this is RecommendPost.js
exports.Recommend =(myId)=>{
var posts=[]
User.find({
User_id : myId
}).then((result)=>{
return User.find()
.select('User_id')
.where('age').equals(result[0].age)
}).then((User_id)=>{
return Promise.all(User_id.map((user,idx,arr)=>{
return Count.find()
.select('board_id')
.where('User_id').equals(user.User_id)
}))
}).then((Users_id)=>{
Users_id.forEach(items=>{
items.forEach(post=>{
posts.push(post.board_id)
})
})
}).then(()=>{
return getMax(posts);
})
}
cf. In RecommendPost.js, the posts works synchronously
//-------- I solved this problem! as some guys said, Recommend function should return Promise. So I edited, then this worked !
this is edited code. thank you for helping me :)
This is app.js
var _promise = function () {
return new Promise((resolve, reject) => {
getJS.Recommend(req.query.User_id).then((data) => {
resolve(data);
})
})
}
_promise().then((data) => { console.log(data) });
this is RecommendPost.js
exports.Recommend =(myId)=>{
return new Promise((resolve,reject)=>{
var posts=[]
User.find({
User_id : myId
}).then((result)=>{
return User.find()
.select('User_id')
.where('age').equals(result[0].age)
}).then((User_id)=>{
return Promise.all(User_id.map((user,idx,arr)=>{
return Count.find()
.select('board_id')
.where('User_id').equals(user.User_id)
}))
}).then((Users_id)=>{
Users_id.forEach(items=>{
items.forEach(post=>{
posts.push(post.board_id)
})
})
}).then(()=>{
resolve (getMax(posts));
})
})
}
It might be clearer for you with async/await that makes asynchronous code look like synchronous:
async function main() {
var data = await getJS.Recommend(req.query.User_id); // waits till its done before going to the next line
console.log(data);
}
// unimportant specific implementation details for live example:
const getJS = {
Recommend(id) {
data = "some data for user ";
return new Promise((res) => setTimeout(() => res(data + id), 1000));
}
}
const req = {
query: {
User_id: 5
}
}
main();
When you call to resolve function is mean that the function is finish and it returns to the caller.
the data object in the then doesn't exist
The Promise.resolve(value) method returns a Promise object that is
resolved with the given value. If the value is a promise, that promise
is returned; if the value is a thenable (i.e. has a "then" method),
the returned promise will "follow" that thenable, adopting its
eventual state; otherwise the returned promise will be fulfilled with
the value.
ES5 :
var _promise = function (req) {
return new Promise((resolve,reject) => {
getJS.Recommend(req.query.User_id).then((data)=>{
console.log(data)
resolve(data)
},(err)=>{
console.log(err)
reject(err);
})
})
}
_promise(req);
ES6
async function _promise(req) {
return await getJS.Recommend(req.query.User_id)
}
For your edit(The entire code):
In this case that Recommend function returns a promise, you don't need the _promise function that wraps it with another one.
and you call it direct
getJS.Recommend(req.query.User_id).then(
(data) => {
console.log(data)
});
Promises means it will always return something, either error or success.
if you resolve something then it will return from there. so your .then part will not execute.
so if you are using resolve and reject params in function then, use .catch method.
return new Promise((resolve,reject) => {
var data = getJS.Recommend(req.query.User_id)
resolve(data)
}) .catch(function (ex) { // in case of error
console.log(ex);
})
Related
Is this possible way to return resolve or reject message from one function to another?
As I am writing to pass resolve message in postman whenever my task is completed or reject message when there is some error
But after after writing return it still not returning the resolve message or reject message inside Postman
any idea how this can be resolve?
async function readFile(filePath) {}
async function getAllFile(filePath) {
const paths = await readFile(filePath);
}
async function filterFiles(filePath) {
const paths = await getAllFile(filePath);
}
function addDocument(childProduct){
return new Promise((resolve, reject) => {
Document.create({
name: childProduct,
},
}).then(function (filePath) {
filterFiles(filePath);
let msg = "Document created Succesfully";
return resolve(msg);
})
.catch(function (err) {
return reject("Can't be updated please try again :) " + err);
});
});
}
function updateDoc(data){
return new Promise((resolve, reject) => {
Document.update({
name: data.name,
}
where: {
product_id: data,
},
})
}).then(function (childProduct) {
addDocument(childProduct);
let msg = "Updated Successfully";
return resolve(msg);
})
.catch(function (err) {
return reject("Can't be updated please try again :) " + err);
});
}
Product.findOne and Document.findAll return a Promise, so they can be returned and awaited directly.
You can chain await func1(); await func2(); await func3() in one try{} block, and catch any error that happens in one place :
const filterFiles = async filePath => {
const paths = await getAllFiles(filePath);
// .. Do something else here
return paths // This is a Promise because async functions always return a Promise
}
const findOneDoc = name => Product.findOne({ where: { name } }); // This func returns a Promise
const findAllDocs = product_id => Document.findAll({ // This func returns a Promise too
raw: true,
where: { product_id }
});
(async () => {
try {
const childProduct = await findOneDoc("some_name");
console.log("All good until now!");
const filePath = await findAllDocs(childProduct._id);
console.log("Still good");
const filteredFiles = await filterFiles(filePath);
console.log("All went well.");
console.log(filteredFiles);
} catch (err) {
// If any of the functions above fails, the try{} block will break and the error will be caught here.
console.log(`Error!`, err);
}
})();
There are few things I would like to mention.
When you create a promise, it should have resolve() and reject() inside it.
for ex-
function testPromise() {
return new Promise((resolve, reject) => {
// your logic
// The followin if-else is not nessesary, its just for an illustration
if (Success condition met) {
resolve(object you want to return);
}else {
reject(error);
// you can add error message in this error as well
}
});
}
// Calling the method with await
let obj = await testPromise()
// OR call with then, but its better to go with await
testPromise().then((obj)=>{
// Access obj here
})
In the method which you have written, You have applied .then() method to non promise object. You have to complete the promise block first with resolve() and reject() inside it. Then you can return that promise from a function, use it in async function Or apply .then() block on it.
Also you don't need to add return statement to resolve() and reject() statement. The system will take care of it.
You can also use try catch block inside a promise. Its better to write reject() statement in catch block, if anything goes wrong.
Im trying to use async await on a function that returns a promise but the out put im getting is Promise { <pending> }. In here im using function called convertFiletoPDF which returns a promise. I need to get the output (the path that i have mention in resolve() ).
When i use it as
convertFiletoPDF(file).then((result) => {
console.log(result);
}).catch((err)=>{
console.log(err);
});
it gives the expected result.Whats wrong with the code below? im quite new to these async await and promises.
function convertFiletoPDF(file) {
return new Promise(function(resolve, reject) {
unoconv.convert(file, "pdf", function(
err,
result
) {
if (err) {
reject(err);
}
let File = file.substring(file.lastIndexOf("/")+1,file.lastIndexOf("."));
// result is returned as a Buffer
fs.writeFile(__dirname+"/files/converted/"+File+".pdf", result, error => {
/* handle error */
if (err) reject(error);
else resolve("./files/converted/"+File+".pdf");
});
});
});
}
async function myfunc(file){
let res = await convertFiletoPDF(file);
return res;
}
let res = myfunc(file);
console.log(res);
The return value of an async function is a promise, so naturally that's what your console.log outputs. You need to either consume the result via await (within another async function) or use then/catch (within another async function).
This is what you're currently doing:
function convertFiletoPDF(file) {
return new Promise(function(resolve, reject) {
setTimeout(resolve, 400, "Done");
});
}
async function myfunc(file){
let res = await convertFiletoPDF(file);
return res;
}
let res = myfunc("some file");
console.log(res);
You need to be doing either this:
function convertFiletoPDF(file) {
return new Promise(function(resolve, reject) {
setTimeout(resolve, 400, "Done");
});
}
async function myfunc(file){
let res = await convertFiletoPDF(file);
return res;
}
(async() => {
try {
let res = await myfunc("some file");
console.log(res);
} catch (e) {
// Deal with the fact there was an error
}
})();
or with then and catch:
function convertFiletoPDF(file) {
return new Promise(function(resolve, reject) {
setTimeout(resolve, 400, "Done");
});
}
async function myfunc(file){
let res = await convertFiletoPDF(file);
return res;
}
myfunc("some file")
.then(res => {
console.log(res);
})
.catch(e => {
// Deal with the fact there was an error
});
convertFiletoPDF()
This function run and returned a Promise. This is fine.
myfunc()
Lets say myfunc takes 10 seconds. Javascript starts to wait newly created thread result from libuv via event loop mechanism. So, Javascript says, "That one is async, I will not wait, when it finishes it will let me know and i will run my then callback and then I will proceed with its output."
Javascript keeps his promise. Tries to run next below lines. myFunch is still working. Output is not ready yet. Returns undefined.
let res = myfunc(file);
console.log(res);
You get undefined.
Someone might find this example from my code useful. You can wrap it in a promise and then resolve the custom promise and then call another promise to confirm the receipt of the original web3 call.
return new Promise((resolve, reject) => {
tokenContract.methods.approve(
exchangeAddress,
BIG_NUMBER_1e50
)
.send({ from })
.once('transactionHash')
.once('receipt', receipt => resolve(receipt))
.on('confirmation')
.on('error', err => reject(err))
.then( receipt => // will be fired once the receipt its mined
console.log(receipt),
);
});
Im trying to use async await on a function that returns a promise but the out put im getting is Promise { <pending> }. In here im using function called convertFiletoPDF which returns a promise. I need to get the output (the path that i have mention in resolve() ).
When i use it as
convertFiletoPDF(file).then((result) => {
console.log(result);
}).catch((err)=>{
console.log(err);
});
it gives the expected result.Whats wrong with the code below? im quite new to these async await and promises.
function convertFiletoPDF(file) {
return new Promise(function(resolve, reject) {
unoconv.convert(file, "pdf", function(
err,
result
) {
if (err) {
reject(err);
}
let File = file.substring(file.lastIndexOf("/")+1,file.lastIndexOf("."));
// result is returned as a Buffer
fs.writeFile(__dirname+"/files/converted/"+File+".pdf", result, error => {
/* handle error */
if (err) reject(error);
else resolve("./files/converted/"+File+".pdf");
});
});
});
}
async function myfunc(file){
let res = await convertFiletoPDF(file);
return res;
}
let res = myfunc(file);
console.log(res);
The return value of an async function is a promise, so naturally that's what your console.log outputs. You need to either consume the result via await (within another async function) or use then/catch (within another async function).
This is what you're currently doing:
function convertFiletoPDF(file) {
return new Promise(function(resolve, reject) {
setTimeout(resolve, 400, "Done");
});
}
async function myfunc(file){
let res = await convertFiletoPDF(file);
return res;
}
let res = myfunc("some file");
console.log(res);
You need to be doing either this:
function convertFiletoPDF(file) {
return new Promise(function(resolve, reject) {
setTimeout(resolve, 400, "Done");
});
}
async function myfunc(file){
let res = await convertFiletoPDF(file);
return res;
}
(async() => {
try {
let res = await myfunc("some file");
console.log(res);
} catch (e) {
// Deal with the fact there was an error
}
})();
or with then and catch:
function convertFiletoPDF(file) {
return new Promise(function(resolve, reject) {
setTimeout(resolve, 400, "Done");
});
}
async function myfunc(file){
let res = await convertFiletoPDF(file);
return res;
}
myfunc("some file")
.then(res => {
console.log(res);
})
.catch(e => {
// Deal with the fact there was an error
});
convertFiletoPDF()
This function run and returned a Promise. This is fine.
myfunc()
Lets say myfunc takes 10 seconds. Javascript starts to wait newly created thread result from libuv via event loop mechanism. So, Javascript says, "That one is async, I will not wait, when it finishes it will let me know and i will run my then callback and then I will proceed with its output."
Javascript keeps his promise. Tries to run next below lines. myFunch is still working. Output is not ready yet. Returns undefined.
let res = myfunc(file);
console.log(res);
You get undefined.
Someone might find this example from my code useful. You can wrap it in a promise and then resolve the custom promise and then call another promise to confirm the receipt of the original web3 call.
return new Promise((resolve, reject) => {
tokenContract.methods.approve(
exchangeAddress,
BIG_NUMBER_1e50
)
.send({ from })
.once('transactionHash')
.once('receipt', receipt => resolve(receipt))
.on('confirmation')
.on('error', err => reject(err))
.then( receipt => // will be fired once the receipt its mined
console.log(receipt),
);
});
I have the following functions with promises:
const ajaxRequest = (url) => {
return new Promise(function(resolve, reject) {
axios.get(url)
.then((response) => {
//console.log(response);
resolve(response);
})
.catch((error) => {
//console.log(error);
reject();
});
});
}
const xmlParser = (xml) => {
let { data } = xml;
return new Promise(function(resolve, reject) {
let parser = new DOMParser();
let xmlDoc = parser.parseFromString(data,"text/xml");
if (xmlDoc.getElementsByTagName("AdTitle").length > 0) {
let string = xmlDoc.getElementsByTagName("AdTitle")[0].childNodes[0].nodeValue;
resolve(string);
} else {
reject();
}
});
}
I'm trying to apply those functions for each object in array of JSON:
const array = [{"id": 1, "url": "www.link1.com"}, {"id": 1, "url": "www.link2.com"}]
I came up with the following solution:
function example() {
_.forEach(array, function(value) {
ajaxRequest(value.url)
.then(response => {
xmlParser(response)
.catch(err => {
console.log(err);
});
});
}
}
I was wondering if this solution is acceptable regarding 2 things:
Is it a good practice to apply forEach() on promises in the following matter.
Are there any better ways to pass previous promise results as parameter in then() chain? (I'm passing response param).
You can use .reduce() to access previous Promise.
function example() {
return array.reduce((promise, value) =>
// `prev` is either initial `Promise` value or previous `Promise` value
promise.then(prev =>
ajaxRequest(value.url).then(response => xmlParser(response))
)
, Promise.resolve())
}
// though note, no value is passed to `reject()` at `Promise` constructor calls
example().catch(err => console.log(err));
Note, Promise constructor is not necessary at ajaxRequest function.
const ajaxRequest = (url) =>
axios.get(url)
.then((response) => {
//console.log(response);
return response;
})
.catch((error) => {
//console.log(error);
});
The only issue with the code you provided is that result from xmlParser is lost, forEach loop just iterates but does not store results. To keep results you will need to use Array.map which will get Promise as a result, and then Promise.all to wait and get all results into array.
I suggest to use async/await from ES2017 which simplifies dealing with promises. Since provided code already using arrow functions, which would require transpiling for older browsers compatibility, you can add transpiling plugin to support ES2017.
In this case your code would be like:
function example() {
return Promise.all([
array.map(async (value) => {
try {
const response = await ajaxRequest(value.url);
return xmlParser(response);
} catch(err) {
console.error(err);
}
})
])
}
Above code will run all requests in parallel and return results when all requests finish. You may also want to fire and process requests one by one, this will also provide access to previous promise result if that was your question:
async function example(processResult) {
for(value of array) {
let result;
try {
// here result has value from previous parsed ajaxRequest.
const response = await ajaxRequest(value.url);
result = await xmlParser(response);
await processResult(result);
} catch(err) {
console.error(err);
}
}
}
Another solution is using Promise.all for doing this, i think is a better solution than looping arround the ajax requests.
const array = [{"id": 1, "url": "www.link1.com"}, {"id": 1, "url": "www.link2.com"}]
function example() {
return Promise.all(array.map(x => ajaxRequest(x.url)))
.then(results => {
return Promise.all(results.map(data => xmlParser(data)));
});
}
example().then(parsed => {
console.log(parsed); // will be an array of xmlParsed elements
});
Are there any better ways to pass previous promise results as
parameter in then() chain?
In fact, you can chain and resolve promises in any order and any place of code. One general rule - any chained promise with then or catch branch is just new promise, which should be chained later.
But there are no limitations. With using loops, most common solution is reduce left-side foldl, but you also can use simple let-variable with reassign with new promise.
For example, you can even design delayed promises chain:
function delayedChain() {
let resolver = null
let flow = new Promise(resolve => (resolver = resolve));
for(let i=0; i<100500; i++) {
flow = flow.then(() => {
// some loop action
})
}
return () => {
resolver();
return flow;
}
}
(delayedChain())().then((result) => {
console.log(result)
})
I'm struggling to wrap my head around a nested promise layout where one one object is returned at the end of it. My current code is as follows:
router
router.get(`/${config.version}/event/:id?`, function (req, res, next) {
var event = new Event(req, res, next);
event.getInfo(req.params.id).then((info) => {
res.send(info);
});
});
function
getInfo(id) {
db.main('events').where('id', id).select()
.then((result) => {
if(result.length > 0) {
var event = result[0];
//regular functions
event.status = this.getStatus(id);
event.content = this.getContent(id);
event.price = this.getPrice(id);
//promise functions
var users = this.getUsers(id);
var hosts = this.getHosts(id);
Promise.all([users, hosts]).then(values => {
event.users = values[0];
event.hosts = values[1];
//return whole event object to router
return event;
})
.catch((err) => {
return {
result: 'error',
error: err
};
});
} else {
return {
result: 'error',
error: "Event does not exist"
};
}
}).catch((e) => {
return {
result: 'error',
error: "Could not retrieve event info"
};
});
}
As you can see, the router initiates a call to get info about an event. The function then does a database call and gets some event data. Thereafter I need to get the users and hosts of the event from a different table, append that info to the event object as well and then return the whole object to the router to be sent to the client.
When I do this I get an error because I'm not returning a promise from the getInfo function, but I'm not sure how or which promise I'm supposed to return.
I'd appreciate some help with this. Thanks
using .then means that you are returning a promise.
function getInfo(id) {
return new Promise(function(resolve, reject) {
resolve('yay!');
})
}
getInfo().then(function(result) { //result = yay! });
to make your code work, simply replace all the returns with resolves, the errors with rejects, and wrap the whole thing with a return new Promise as i did.
getInfo(id) {
return new Promise(function(resolve, reject) {
db.main('events').where('id', id).select()
.then((result) => {
if (result.length > 0) {
var event = result[0];
//regular functions
event.status = this.getStatus(id);
event.content = this.getContent(id);
event.price = this.getPrice(id);
//promise functions
var users = this.getUsers(id);
var hosts = this.getHosts(id);
Promise.all([users, hosts]).then(values => {
event.users = values[0];
event.hosts = values[1];
//return whole event object to router
resolve(event);
})
.catch((err) => {
reject({
result: 'error',
error: err
});
});
} else {
reject({
result: 'error',
error: "Event does not exist"
});
}
}).catch((e) => {
reject({
result: 'error',
error: "Could not retrieve event info"
});
});
});
}
Just wrap your async code in Promise like this:
getInfo(id) {
return new Promise(function(resolve, reject) {
db.main('events').where('id', id).select()
.then((result) => {
//...
resolve(/* result */)
// OR
reject(/* Error */)
})
}
Note: Use resolve and reject instead return
It's a combination of several things, but the main one is that you are never returning anything from getInfo, so your router handler is calling .then on undefined.
Do not call .catch (without throwing inside it) on Promises you intend to return for a caller to consume. This makes it not possible to use .catch, because you recovered the Promise chain into a resolved one.
Whatever you return inside a .then will be merged into the promise chain, so it's not actually a "Promise that resolves with a Promise". Your whole code could be replaced with:
getInfo (id) {
return db.main('events').where('id', id).select()
.then(result => {
if (result.length == 0) {
// you can also just throw your error object thing,
// but standard Error are generally the convention
throw new Error('Event does not exist')
}
const [event] = result
event.status = this.getStatus(id)
event.content = this.getContent(id)
event.price = this.getPrice(id)
return Promise.all([this.getUsers(id), this.getHosts(id)])
.then(([users, hosts]) => {
event.users = users
event.hosts = hosts
// this is the only value that
// this.getInfo(id).then(value => {/* ... */}) will see
return event
}
})
}