I wanted to have an Image on 100% width, with a max-height. When scaling the window and you're reaching the max-height, the width should still be at a 100% but "cropping" the image bigger (provided image size is fitting). This means you can see more of the image sides (left and right) when its on a big scale window, and you can see less on a small sized window. I'll post my css try down, but i don'thave a clue how to do that at this point. Hope you're getting my issue, i'll attach a visualisation.
My Code, don't get confused, I wanted to do a slider but lets focus on only one picture now, so sliders out of the game for now:
.slider-inner img {
display:none;
max-width: 100%;
height: auto;
}
#main-slider {
width: 80%;
min-width: 500px;
height: 450px;
min-height: 400px;
overflow: hidden;
margin: 0 auto;
}
.slider-inner{
width: 100%;
height: 450px;
margin: 0 auto;
position:relative;
overflow: hidden;
float:left;
padding: 0px;
}
What i want (visualisation):
If I understood you correctly you want your image to maintain its height and crop the width when window size is smaller.
Check this example:
div{
height: 300px;
position: relative;
overflow: hidden;
}
div img{
position: absolute;
left: 50%;
top: 50%;
transform: translate(-50%, -50%);
}
<div>
<img src="https://images.unsplash.com/photo-1536221236547-04007cfc3d8b?ixlib=rb-0.3.5&ixid=eyJhcHBfaWQiOjEyMDd9&s=4d542ff4e10ff7de9d35d2ec8a467454&w=1000&q=80">
</div>
You do this with background image:
.box {
height:200px;
background:url(https://picsum.photos/1300/300?image=1069) center top/auto 100% no-repeat;
}
<div class="box">
</div>
Also you had "max-width:100%" and "height: auto" before. 100% is a relative unit, saying to take up 100% of the parent container's width, and auto was telling it to scale with the width while keeping aspect ratio.
Related
I'm attempting to set up a way for users to be able to hover over a small preview of an image and have a "featured" section show this image in its full size. I've managed to accomplish that with the code below.
My problem is when images are very different sizes (one landscape and one portrait It looks very bad and makes the page jump.
Goal: I'm trying to figure out a way to avoid this. I want to find a way to display the main image in a uniformed look. Aka the same size. I want to accomplish this without heavily distorting the images by changing their sizes. Any help is hugely appreciated.
Check out the JS fiddle: https://jsfiddle.net/4hrvxpe2/10/
HTML:
<img id='mainPicture' class="image-resposive" src= "https://images-na.ssl-images-amazon.com/images/I/51EG732BV3L.jpg">
<br>
<br>
<div class='smallerImages'>
<img id='imageNum1' class="small" src="http://i.huffpost.com/gen/4393678/images/o-THE-MATRIX-facebook.jpg">
<img id='imageNum2' class="small" src="https://images-na.ssl-images-amazon.com/images/I/51EG732BV3L.jpg">
</div>
CSS:
.smallerImages{
display:inline-block;
}
#mainPicture{
width: 75%;
height: 75%;
display: table; margin: 0 auto;
}
.small{
max-width: 15%;
max-height: 15%;
min-width: 15%!important;
min-height: 15%!important;
}
Jquery:
$('#imageNum1').hover(function() {
$('.small').removeClass('selectedImage')
var src = $('#imageNum1').attr('src');
$('#imageNum1').addClass('selectedImage')
$('#mainPicture').attr('src', src);
});
$('#imageNum2').hover(function() {
$('.small').removeClass('selectedImage')
var src = $('#imageNum2').attr('src');
$('#imageNum2').addClass('selectedImage')
$('#mainPicture').attr('src', src);
});
Adding a max-height and max-width makes it better.
Check out https://jsfiddle.net/4hrvxpe2/13/
Or you can encapsulate it in a div. Something like
<div class="container"><img src="img.jpg"></div>
and give dimensions to the container, as in:
.container{
height: 100px; width: 200px; overflow: hidden;
}
Check out https://jsfiddle.net/4hrvxpe2/22/
Or
In order for the image to take a fixed size always use a div and set it as its background and make it cover the div:
Check out https://jsfiddle.net/4hrvxpe2/23/
If you don't want the images to affect the rest of the elements in the document you need to take them out of the flow.
This is possible if you give the selected image a fixed position and make use of the transform property.
With that being said, here's a very rough example of how I would do it.
Responsive example (open in full screen and resize the window):
$('#imageNum1').hover(function() {
$('.small').removeClass('selectedImage')
var src = $('#imageNum1').attr('src');
$('#imageNum1').addClass('selectedImage')
$('#mainPicture').attr('src', src);
});
$('#imageNum2').hover(function() {
$('.small').removeClass('selectedImage')
var src = $('#imageNum2').attr('src');
$('#imageNum2').addClass('selectedImage')
$('#mainPicture').attr('src', src);
});
body {
position: relative
}
.smallerImages {
width: 20%;
}
#mainPicture {
max-width: 55vw;
max-height: 75vh;
margin: 0 auto;
position: fixed;
top: 50%;
left: 50%;
transform: translate(-50%, -50%)
}
.small {
width: 100%;
margin: .5em auto;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class='smallerImages'>
<img id='imageNum1' class="small" src="http://i.huffpost.com/gen/4393678/images/o-THE-MATRIX-facebook.jpg">
<img id='imageNum2' class="small" src="https://images-na.ssl-images-amazon.com/images/I/51EG732BV3L.jpg">
</div>
<img id='mainPicture' class="image-resposive" src="https://images-na.ssl-images-amazon.com/images/I/51EG732BV3L.jpg">
<br>
<br>
My best attempt so far is the following. This works okay but it does distort images that are very tall. Can anyone suggest improvements?
JSFiddle: https://jsfiddle.net/4hrvxpe2/26/
.small{
max-width: 10%;
height: 100px;
min-width: 10%!important;
}
.smallerImages{
margin: 0 auto;
}
#mainPicture{
width: 100%;
height: 600px;
display: table; margin: 0 auto;
}
I accomplished the goal by changing 15% of maximum and minimum width in .small to 15vw.
.small{
max-width: 15vw;
max-height: 15%;
min-width: 15vw!important;
min-height: 15%!important;
}
vw is for the viewport width, while % will take the content size and size it relative to that. When the image changes, because of the image size differences, that image is increasing the content width, meaning that anything using % will change to the new width.
Here's the JSFiddle.
I have a canvas in my page, and i want it to fill the page until it reaches the bottom of the page.
I have the canvas' width set to 100%, but i cannot set the height to 100% as it extends too far.
The position of the div is not 0,0 of the browser window there are other things above it, so i end up with a scroll bar because 100% height extends well below the bottom of my browser's output.
So i was wondering how can i extend the element's height to reach the bottom of the page from its current position on the web page?
<style>
.canvas{
position:absolute;
width:100%;
height:100%;
}
<style>
<div class="logo">Stuff here</div>
<div class="output">
<canvas class="canvas"></canvas>
</div>
Do i need to use JavaScript or is there a CSS method to doing this?
If you know the height of the content above the canvas, you can use top and bottom properties to take up the rest of the space:
JS Fiddle
.logo {
height: 40px;
}
.output {
position: absolute;
top: 40px; // height of above content
bottom: 0;
width: 100%;
padding: 0;
}
.canvas {
position: absolute;
width: 100%;
height: 100%;
padding: 0;
margin: 0;
}
And if you don't know the height of the above content, you can calculate it:
JQuery Example: JS Fiddle
var height = $('header').height();
$('.output').css('top', height);
this technique is also great when making resizable popups with fixed height headers and footers, but fluid height content
https://jsfiddle.net/ca5tda6e/
set the header (.logo) to a fixed height
.logo{
height: 100px;
background-color: lightGray;
position: relative;
z-index: 1;
}
then position the content (.output) absolute, with a padding-top: 100px
.output{
width: 100%;
height: 100%;
box-sizing: border-box; /* so that padding is included in width/height */
padding-top: 100px; /* padding-top should be equal to .logo height */
position: absolute;
top: 0;
left: 0;
overflow: hidden; /* there was like a pixel of something i couldnt get rid of, could have been white space */
}
I've had this problem before, in CSS, create this rule....
html, body {
margin: 0;
}
My Goal:
So I am making a webpage with a map of the USA as the "background image" and on top of that map I have about 10 markers pointing to specific location. The markers are NOT part of the picture thats just me adding them with absolute positioning and top and left with a percentage.
The Problem:
As I scale down the page or scroll up and down the markers that I have set with absolute positioning begin to move out of the spot they are suppose to be on because the background-image is getting smaller do to it displaying 100%.
The Question:
How can I achieve what I want with the markers on the map where they are suppose to be not moving as the window is being scaled down?
Now I know of only 1 solution and this solution can take a VERY LONG TIME. What I was thinking is instead of positioning the markers that I want on the map with percentage I can do it with pixels and then use a TON of media queries and keep on adjusting it. Not only is this solution going to take extremely long but it also does not seems like the correct way to go about this.
HTML:
<div class="container main-content"><!--the map background image is set here-->
<div class="row relative">
<div class="eq-content-wrap">
<div class="eq-content">
<div class="marker"></div> <!--the marker that is positioned absolute-->
</div>
</div>
</div>
CSS:
html, body{
width: 100%;
height: 100%;
margin: 0px;
padding: 0px;
background: #000;
}
body{ overflow: hidden; }
.main-content{
background: url('assets/img/map1.jpg') no-repeat top center;
background-size: contain;
height: 100% !important;
width: 100% !important;
}
.eq-content-wrap{
position: absolute;
width: 500px !important;
top: 22%;
left: 40%;
}
.marker{
height: 40px;
width: 40px;
border-radius: 100%;
background-color: red;
position: absolute;
top: 50%;
margin-top: -20px;
}
The problem is that your background image's size is set to 100%: background-size: 100%. This means that when the browser tries to scale the content, the background does not scale with it (it stays 100%).
Your best bet is to remove the background-size property completely. This allows the markers to stay in place when the page scales, however, you won't get the full-screen background effect that you currently have (unless you have a larger image).
The background will still move, however, once the browser window width is less than the image's width. This is because you have the background-position set to top center. The center is what causes it to move once the browser window width is less than the image width. Change center to left and it will fix that issue. You'll also need to set the marker's container to be based to the left as well for this to work on wider screens though. Basically, removing all center properties would help, but the screen wouldn't be centered on a wide screen.
Try substituting css :before pseudo element for .marker ; set percentage unit values utilizing calc()
html,
body {
width: 100%;
height: 100%;
margin: 0px;
padding: 0px;
background: #000;
}
body {
overflow: hidden;
}
.main-content {
background: url(http://lorempixel.com/400/300) no-repeat top center;
background-size: contain;
height: 100% !important;
width: 100% !important;
}
.eq-content-wrap {
position: absolute;
width: 500px !important;
top: 22%;
left: 40%;
}
.main-content:before {
content: " ";
height: calc(12.5%);
width: calc(5%);
border-radius: 100%;
background-color: red;
position: absolute;
top: calc(50%);
left: calc(50%);
margin-top: calc(1%);
}
<div class="container main-content">
<!--the map background image is set here-->
<div class="row relative">
<div class="eq-content-wrap">
<div class="eq-content">
<div class="marker"></div>
<!--the marker that is positioned absolute-->
</div>
</div>
</div>
jsfiddle http://jsfiddle.net/o79rpawc/
I am trying to make a light box style Jquery function. Unfortunately, the .container div that contains the image div (.lightboxbackground) I want to make pop out and enlarge has position:absolute and z-index: 10 so my pop up box and background fader only take up the width and height of that parent (.container) div eg:
Would anyone know a way around this so that my .lightboxbackground and .lightbox divs can cover the whole screen?
<div class='container'>
<div class='lightboxbackground'>
<div class='lightbox'>
<img src='image.jpg'/>
</div>
</div>
</div>
.container {
position: absolute;
z-index:10;
width: 200px;
height: 200px;
}
.lightboxbackground {
background-color:#000;
opacity: 0.9;
width: 100%;
height: 100%;
position:absolute;
z-index: 11;
}
.lightbox {
width: 500px;
height: 500px;
position:absolute;
z-index: 12;
}
if you want to cover the whole screen:
.lightboxbackground {
background-color:#000;
opacity: 0.9;
width: 100%;
height: 100%;
position:fixed;
left:0;
top:0;
z-index: 11; //I would advise to change this to z-index:1000 (Note: .lightbox must also adjust to this)
}
fid: http://jsfiddle.net/uH4MF/1/
.container is their "frame of reference", so to speak. 100% width and height of the descendants of .container means 200px for them.
Also, there is a way to attain 100% height. One of them is to to explicitly define height on html and body so you can have this reference.
And so:
Place .container as a child of body
<body>
<div class="container">...
Remove .container's width and height
Add the following style:
html, body, .container {height:100%};
The problem I have is that the video always gets black bars on the sides or on the top/bottom depending on the screen size.
Any idea how to get it full screen always without showing that annoying black bars? and without using a plugin.
This is my markup:
<div id="full-bg">
<div class="box iframe-box" width="1280" height="800">
<iframe src="http://player.vimeo.com/video/67794477?title=0&byline=0&portrait=0&color=0fb0d4" width="1280" height="720" frameborder="0" webkitAllowFullScreen mozallowfullscreen allowFullScreen></iframe>
</div>
</div>
#full-bg{
width: 100%;
height: 100%;
img{
display: none;
}
.iframe-box{
width: 100%;
height: 100%;
position: absolute;
background: url(../img/fittobox.png);
left: 0 !important;
top: 0 !important;
iframe{
width: 100%;
height: 100%;
}
}
}
Try adding to your CSS
.iframe-box {
max-width: 1280px; /* video width */
max-height: 720px; /* video height */
}
This means that width: 100%; height: 100% will let the element will expand as much as it can, until it hits a maximum height or width of 720px or 1280px, respectively.
If the screen you're viewing it on has a greater resolution, the node will stop expanding and you'll not have black borders.
Further, afaik the following is not valid CSS, are you using a library or something?
#full-bg {
.iframe-box {
foo: bar;
}
}
Edit after answer accepted: I just thought of a completely different way to achieve this, but it would require you to change a lot of your CSS
.fittobox { /* give fit to box an aspect ratio */
display: inline-block; /* let it be styled thusly */
padding: 0; /* get rid of pre-styling */
margin: 0;
width: 100%; /* take up full width available */
padding-top: 56.25%; /* give aspect ratio of 16:9; "720 / 1280 = 0.5625" */
height: 0px; /* don't want it to expand beyond padding */
position: relative; /* allow for absolute positioning of child elements */
}
.fittobox > iframe {
position: absolute; /* expand to fill */
top: 0px;
left: 0px;
right: 0px;
bottom: 0px;
}
If you know the aspect ratio of your video, you shouldn't even need Javascript. You can use a percentage-based padding-top.
I could post code, but I'd recommend you read this entire article anyway.
#Paul S. 's answer works for me for the .fittobox container for 16:9 video aspect ratios but the .fittobox > iframe embed still has black bars with his CSS. Removing the right and bottom positioning fixes it for me (no need for "px" in those 0 values, of course):
.fittobox > iframe {
position: absolute;
top: 0;
left: 0;
width: 100%;
height: 100%;
}