i have some problem which i can't figure out.
so
i have a div with background image.
<div class="a"></div>
and i want to make clickable some point of this background image. It's okey i can make this with adding to some div width z-index and make it clickable and positioning this with position:absolute e.g,
<div class="b">
<a class="clickablePoint" href="#"></a>
</div>
but how i can keep this clickable point on the same way when i resize the window if my background-image must be a responsive so background-size:100% auto.
maybe have some method to calculate background image height realtime when resize window ? or any other method? :(
Here's a minimal viable solution showing how to absolutely-position an element based on a full-width (background-size: 100% auto) background.
I'm setting the font-size of the element to 1vw (1/100th of the width of the viewport) and then calculating its left/top position and width/height size in em units, which become equivalent to a multiple of that 1vw.
As such, resizing this demo to any size will keep the box in the same place around the cat's nose.
body {
background: url('https://i.imgur.com/sVz3YRx.jpg');
background-size: 100% auto;
height: 50vw; /* for stack snippet height */
position: relative;
margin: 0;
}
.nose {
border: 1px solid yellow; /* for demo */
position: absolute;
font-size: 1vw;
top: 27em;
left: 59em;
width: 6em;
height: 5em;
}
<a class="nose"></a>
Related
I have a div containing some text and a YouTube video. I used CSS to give it a grey background. I also set the position to 4.4 em from the top, 1% from the left, and made it 98% wide. I want the bottom of the div to be 4.4 em from the bottom, no matter the size or zoom of the browser. How can I do this? Can I use CSS, or is Javascript required? If you give an answer containing Javascript code, please don’t use jQuery.
div {
position: absolute;
left: 1%;
width: 98%;
top: 4.4em;
background: grey;
}
body {
width: 100%;
color: white;
}
EDIT: Here is my HTML:
<div>
<h1>A Heading</h1>
YOUTUBE VIDEO HERE
</div>
You could either use a border that is transparent to simluate the 4.4em gap at the bottom, or you could use the "calc()" css function https://www.w3schools.com/cssref/func_calc.asp
Example:
height: calc(100vh - 4.4em);
What I'm trying to achieve is a div container that is responsive but the ability to overlay highlight fields that will stay in the same place based on the parent div. I want to be able to highlight certain areas of text or form fields but have the form be responsive. Here's a link to an example: http://www.codeply.com/go/nufYSSEMir
As you can see the highlight div is position: absolute; so obviously it's going to stay exactly where it's at. I've tried using percents as top and left values but it doesn't scale with the background image. I have a feeling that my two options are to either have the width as a static value and set the meta viewport to scale to the window size, or get crazy with some JS and maybe jQuery.
Thanks in advance for any and all suggestions.
As said by divix, you need to set position : relative to the parent div.
This will tell the browser that your highlight's position : absolute is absolute in reference to outerContainer.
Basically any position:absolute will look at the first parent that has a position set (whether it's relative, fixed, absolute etc) to calculate top|right|bottom|left offset. If you don't have any parent that has a position set, it will just take the body as a reference
Edit: In order the get the right responsivness try this :
body {
background-color:#ddd;
}
#outerContainer {
background: transparent url("http://scontent-ord1-1.xx.fbcdn.net/hphotos-xpl1/t31.0-8/s960x960/12605534_504076036438839_6108375615162000201_o.jpg") no-repeat scroll center top / 100% auto;
height: 960px;
margin: 0 auto;
max-width: 742px;
width: 100%;
position: relative;
}
#media only screen AND (max-width:742px){
#outerContainer {
height:0;
padding-top:129.5%;
}
}
#innerContainer {
background-color: rgba(0, 255, 0, 0.5);
border: 1px solid #000;
height: 8%;
left: 12%;
position: absolute;
top: 14%;
width: 30%;
}
Simply add position: relative; to the #outerContainer, it works for me.
I'm pretty fresh to web development and cannot figure this one out. Appreciate any help!
On re-size the fixed div moves out of the container instead of re-sizing. The site I'm working on has the nav as the fixed section and is inside of the main container.
Any help is appreciated. Thanks!
<div class="container">
<div class="fixed"></div>
</div>
.container {
border: 1px solid;
max-width: 600px;
width: 100%;
min-height: 1600px;
}
.fixed {
max-width: 600px;
width: 100%;
height: 50px;
border: 1px solid green;
position: fixed;
}
http://jsfiddle.net/KqvQr/
When you specify position as fixed the Element, even thought it is inside a parent container, It won't behave as a child of a parent container. It won't adjust his width according to the parent width. But I can give you a solution where when user resize the page the fixed element also get resize yet it is a position fixed
.fixed {
height: 50px;
border: 1px solid green;
position: fixed;
right:0;
left:0;
}
Don't specify widths for the container. instead of that specify left and right values. so then when page is resizing css only check for the left and right margin values. by keeping those values it will adjust its inner width always.
Here is the working fiddle http://jsfiddle.net/KqvQr/5/
I don't think you can achieve what you want if you stick with that constraints. Your width and max-width will work as expected if you change your position to relative instead of fixed..
Check out this Fiddle
I just stumbled across this guys site: http://mantia.me/
He has an awesome logo that reacts to the content the site is currently showing, if you wait on his homepage the logo changes with the slide show of images. I was wondering if anyone knows how to replicate the effect. I'm guessing it's a transparent png with a rotating master background then the site is layered on top, but I'm probably wrong.
Any guesses on how to make something similiar?
Images:
It's really simple what he has. Like you mention it's a transparent PNG that matches the given background ( in this case white ) and places it on top of it with z-index. The rest is just jQuery with fadeIn and fadeOut images.
You can view the png on top of the image transitions.
So basically you just need a div with position:relative set the width the height of it; then add another div inside it which has the jQuery Slideshow (check this out: http://medienfreunde.com/lab/innerfade/), set it a z-index:0 Then add another div (which will go on top of the slider) and add it a background with z-index to something higher than 0 and you're good to go.
Here is how he does it:
HTML
<div id="content">
<div id="feature"></div>
<div id="navigation"></div>
</div>
CSS
#content {
position: relative;
width: 800px;
margin: 64px auto;
font: normal 13px/16px "myriad-pro-1","myriad-pro-2", sans-serif;
color: #404040;
}
#navigation{
position: absolute;
z-index: 1000;
top: 0;
left: 0;
width: 800px;
height: 46px;
background: transparent
url(http://mantia.me/wp- content/themes/minimalouie/img/nav.png)
no-repeat top left;
}
#feature {
width: 800px;
height: 466px;
overflow: hidden;
background-color: aqua;
}
And then he just adds an img element to #feature.
<div id="feature">
<img src="http://mantia.me/images/supermariobros_large.jpg"
alt="Super Mario Bros.">
</div>
See fiddle.
Is it possible to place 1 DIV inside another DIV and have the DIV inside have a larger width and height than the DIV it is contained within?
Sounds like a riddle....
Basically I want to have a container that the user can set the width and height of. They will have also selected and image, cropped it and resized it using jQuery. The image will be the background of the container, however due to the fact that the background image could be made bigger than the container I want it to be possible for the background to be a DIV that can expand beyond the height and width of its container - To crop the image if you like.
Do able?
Yes, if I'm understanding you correctly
the container would be relatively positioned, the div "inside" would be absolutely positioned inside it -
the absolute positioning co-ordinates and getting the image centered would be done something like this, at default,
#inner {
position: absolute;
top: 0 ;
left: 0;
right: 0;
bottom: 0;
background: url(theimage.jpg) no-repeat 50% 50%;
}
this should center the image in the user sized container
then the "cropping tool" would be able to manipulate the co-ordinates (in an equal measure I presume) either + or - those 0 values, -, negative, ones will allow it to expand outside the "outer" container
$('<div>').attr('id', 'innerdiv').appendTo($('#div'));
CSS
#div{
height: 100px;
width: 100px;
background: green;
}
#innerdiv{
height: 200px;
width: 200px;
background: red;
}
HTML
<div id="div"></div>
http://jsfiddle.net/bKetM/
A background image will be 'cropped' by default. For example, if I have a 500px by 500px div and then I put a 1000px by 1000px image as its background then it will show the top left 500px by 500px of that image as a background. I could set the background image to be centered like so:
background:transparent url(image.png) no-repeat center;