Let's assume I have a proper Date object constructed from the string: "Tue Jan 12 21:33:28 +0000 2010".
var dateString = "Tue Jan 12 21:33:28 +0000 2010";
var twitterDate = new Date(dateString);
Then I use the < and > less than and greater than comparison operators to see if it's more or less recent than a similarly constructed Date. Is the algorithm for comparing dates using those operators specified, or is it specifically unspecified, like localeCompare? In other words, am I guaranteed to get a more recent date, this way?
var now = new Date();
if (now < twitterDate) {
// the date is in the future
}
Relational operations on objects in ECMAScript rely on the internal ToPrimitive function (with hint number) that you can access, when it is defined, using valueOf.
Try
var val = new Date().valueOf();
You'll get the internal value of the date which is, as in many languages, the number of milliseconds since midnight Jan 1, 1970 UTC (the same that you would get using getTime()).
This means that you're, by design, ensured to always have the date comparison correctly working.
This article will give you more details about toPrimitive (but nothing relative to comparison).
Date values in Javascript are numbers, as stated in the ECMA Script specification. So the Date values are compared as numbers.
This is a demo of your code (I set twitterDate in the future).
(function(){
var dateString = "Tue Jan 12 21:33:28 +0000 2014";
var twitterDate = new Date(dateString);
var now = new Date();
if (now < twitterDate) {
document.write('twitterDate is in the future');
}
else
{
document.write('twitterDate is NOT in the future');
}
})()​
I think yes. Using if (now < twitterDate), it evaluates to if (now.valueOf()<twitterDate.valueOf()). valueOf() delivers the number of milliseconds passed since 01/01/1970 00:00:00, so the comparison of those 2 numbers is valid.
check it like this
var then = new Date("Tue Jan 12 21:33:28 +0000 2010")
,now = new Date;
console.log(then.valueOf(),'::',now.valueOf(),'::',now<then);
//=> 1263332008000 :: 1352365105901 :: false
Related
I understand that dealing with dates, in any environment, could be quite confusing, but I'm in a nightmare with a function that should be a trivial job.
I want to manipulate in different ways some dates, but I get errors or wrong results.
I report hereafter a very simple example made to test the execution; the goal here is to get the current month beginning date, just to show what happens:
function DateAdjust() {
var newdate = new Date(); //1: 2018-12-12T21:00:20.099Z
newdate = newdate.setDate(1); //2: 1543698020099
newdate=Date(newdate); //3: Wed Dec 12 2018 21:01:43 GMT+0000 (Ora standard dell’Europa occidentale)
var d = newdate.getDate(); //4: newdate.getDate is not a function
}
4 lines, 3 unexpected results (as shown by Firefox's debugger):
1. the starting date has no day-of-week and no timezone
2. setting the day, result is transformed in milliseconds (why?); I do not know if it is correct.
3. reconverting in string gives the original date, unmodified (why?) but with week day and timezone
4. trying to get the day value an error is thrown (why?)
My environment:
Win 7 32bits SP1
Firefox 63.0.3 (32 bit)
jquery-2.2.4.min.js
I know these questions are boring, but hope someone will find few minutes to clear my mind.
Regarding line 1, the Z at the end is the timezone designation for UTC in ISO 8601 (see Wikipedia).
If the time is in UTC, add a Z directly after the time without a space. Z is the zone designator for the zero UTC offset. "09:30 UTC" is therefore represented as "09:30Z" or "0930Z". "14:45:15 UTC" would be "14:45:15Z" or "144515Z".
Regarding line 2 see the MDN article on setDate (emphasis mine):
The number of milliseconds between 1 January 1970 00:00:00 UTC and the given date (the Date object is also changed in place).
So you can see the 'correct' behavior you probably expect simply by ignoring the return value:
var newdate = new Date(); //1: 2018-12-12T21:00:20.099Z
newdate.setDate(1); //2: 1543698020099
console.log(newdate); //3: 2018-12-01T21:00:20.099Z
Regarding line 3, see MDN article on Date (emphasis mine):
Note: JavaScript Date objects can only be instantiated by calling
JavaScript Date as a constructor: calling it as a regular function
(i.e. without the new operator) will return a string rather than a
Date object; unlike other JavaScript object types, JavaScript Date
objects have no literal syntax.
Regarding line 4, the above also explains this error, since newdate is now a string rather than a Date object.
For what it's worth, I agree with the other commenters. JavaScript's date functions are pretty messy compared to many other modern languages. I strongly recommend using a library like moment, luxon, or date-fns. It'll make your life much easier.
I do recommend using moment.js
But there are 2 problems with your code:
1-
newdate = newdate.setDate(1);
setDate mutates newDate in place, and return it in miliseconds, not a new Date object. If you just want to set the date, do this instead:
newdate.setDate(1);
2-
newdate=Date(newdate);
Not realy sure why you are trying to get a new Date object, but you need the new, otherwise it will just be a string
newdate= new Date(newdate);
Fixing problem 1 should eliminate the need for the code of problem 2
var newdate = new Date(); // 1
console.log(typeof newdate, newdate); // object Wed Dec 12 2018 23:00:44 GMT+0200 (Eastern European Standard Time)
newdate = newdate.setDate(1); // 2
console.log(typeof newdate, newdate); //number 1543698085383
newdate=Date(newdate); //3
console.log(typeof newdate, newdate); //string Wed Dec 12 2018 23:04:44 GMT+0200 (Eastern European Standard Time)
var d = newdate.getDate(); // 4
console.log(typeof d, d); //
Date type is assigned to the object.
number is assigned to newdate. which is ticks
returns string
string.getDate() is not defined, so undefined.
hope it helps.
I m suppose to compare two dates with Java 8 Nashorn engine. However it is not comparing dates correctly.
My Java Code:
Date start = new Date();
Calendar cal = Calendar.getInstance();
cal.add(Calendar.DATE, 1);
Date end = cal.getTime();
engine.put("start", start); // engine is ScriptEngine
engine.put("end", end);
assertTrue((boolean)engine.eval("start < end")); //This assert is failing
//if I change dates to long it is working
engine.put("start", start.getTime());
engine.put("end", end.getTime());
assertTrue((boolean)engine.eval("start < end")); //This will now work
However I don't want to convert date to long because of some other requirements. Please suggest where I am making the mistake.
Thanks
In Nashnorn, new java.util.Date() and new Date() produce completely different objects. And it makes sense, since the functionality of either object differs a lot. Nashorn internally uses jdk.nashorn.internal.objects.NativeDate.
The later, native JS, can be safely compared with < and >. For the former, the comparison will be purely by address in memory.
To work with less and greater operators, I recommend to convert Java dates to NativeDate when populating engine's global context.
One possible way of doing it would be
Date start = new Date();
ScriptObjectMirror jsDate = (ScriptObjectMirror) engine.eval("new Date();")
jsDate.callMember("setTime",start.getTime());
engine.put("start", jsDate);
engine.eval("print(start.constructor + ':' + start)");
Prints "function Date() { [native code] }:Sat Jul 23 2016 19:05:53 GMT-0400 (EDT)"
However
engine.put("javaStart", new Date());
engine.eval("print(javaStart.constructor + ':' + javaStart)");
prints "undefined:Sat Jul 23 19:05:53 EDT 2016"
Consider the following code:
var a = new Date(someDateString);
var b = new Date(someOtherDateString);
console.log(b - a); // Outputs for example 3572, number of millisecs between the dates
Why does this work? This is an arithmetic operation on two objects. It looks suspiciously like operator overloading, known from C++ and other languages, but as far as I know, JavaScript won't get that before ECMAScript 7.
One would think the JS engine would turn it into something like
console.log(b.toString() - a.toString());
but this prints "NaN", as toString on a dateobject returns a string on the format
Mon Mar 23 2015 13:21:33 GMT+0100 (CET)
So, what magic makes this arithmetic possible? Can it be implemented on custom objects?
It converts them through .valueOf() not .toString(). Internally a date is stored as a number. The toString() method just formats it using a date formatting routine.
See The Subtraction Operator in the spec.
valueOf is called to fetch the numeric primitive of the date:
function o(i) {
this.valueOf = function() { return i; }
}
var a = new o(100);
var b = new o(42);
alert(a - b); // 58
A JS Date Object is just "a number of milliseconds".
"Zero time" starts at 01 January 1970 00:00:00 UTC. Everything else is a simple conversion, and adding/subtracting become very easy!
I'm creating dates like this:
var StartDate = new Date(data.feed.entry[i].gd$when[j].startTime);
When a date string is received specifying date and time in the form:
"2014-04-12T20:00:00.000-05:00"
Date() interprets this perfectly fine returning:
Sat Apr 12 2014 19:00:00 GMT-0500 (CDT)
However, when the date string is received with no time information in the form:
"2014-04-07"
then Date() is interpreting it as:
Sat Apr 05 2014 19:00:00 GMT-0500 (CDT)
Looks like Date() is taking the -07 as the time and I have no clue where is it getting the date as 05. Any idea what might be the problem?
Could it be, somehow, Date() is interpreting a different time zone because in the first string the time zone is determined at the very end but in the "all day" event there is no indication of the time zone.
Has anybody found this issue? If yes, how did you solve it?
UPDATE: After researching a little bit more this parsing issue I noticed something very weird:
The following statement:
new Date("2014-4-07")
would return Mon Apr 07 2014 00:00:00 GMT-0500 (CDT) which is correct, but the following one:
new Date("2014-04-07")
returns Sun Apr 06 2014 19:00:00 GMT-0500 (CDT) which is the wrong one. So, for whatever reason, seems like the padding zeros affect the way the date is parsed!
You're using the Date() function wrong.
It only accepts parameters in the following formats.
//No parameters
var today = new Date();
//Date and time, no time-zone
var birthday = new Date("December 17, 1995 03:24:00");
//Date and time, no time-zone
var birthday = new Date("1995-12-17T03:24:00");
//Only date as integer values
var birthday = new Date(1995,11,17);
//Date and time as integer values, no time-zone
var birthday = new Date(1995,11,17,3,24,0);
Source: MDN.
The Date() function does not accept timezone as a parameter. The reason why you think the time-zone parameter works is because its showing the same time-zone that you entered, but that's because you're in the same time-zone.
The reason why you get Sat Apr 05 2014 19:00:00 GMT-0500 (CDT) as your output for Date("2014-04-07" ) is simply because you used it in a different way.
new Date(parameters) will give the output according to the parameters passed in it.
Date(parameters) will give the output as the current date and time no matter what parameter you pass in it.
Prior to ES5, parsing of date strings was entirely implementation dependent. ES5 specifies a version of ISO 8601 that is supported by may browsers, but not all. The specified format only supports the Z timezone (UTC) and assumes UTC if the timezone is missing. Support where the timezone is missing is inconsistent, some implementations will treat the string as UTC and some as local.
To be certain, you should parse the string yourself, e.g.
/* Parse an ISO string with or without an offset
** e.g. '2014-04-02T20:00:00-0600'
** '2014-04-02T20:00:00Z'
**
** Allows decimal seconds if supplied
** e.g. '2014-04-02T20:00:00.123-0600'
**
** If no offset is supplied (or it's Z), treat as UTC (per ECMA-262)
**
** If date only, e.g. '2014-04-02', treat as UTC date (per ECMA-262)
*/
function parseISOString(s) {
var t = s.split(/\D+/g);
var hasOffset = /\d{2}[-+]\d{4}$/.test(s);
// Whether decimal seconds are present changes the offset field and ms value
var hasDecimalSeconds = /T\d{2}:\d{2}:\d{2}\.\d+/i.test(s);
var offset = hasDecimalSeconds? t[7] : t[6];
var ms = hasDecimalSeconds? t[6] : 0;
var offMin, offSign, min;
// If there's an offset, apply it to minutes to get a UTC time value
if (hasOffset) {
offMin = 60 * offset / 100 + offset % 100;
offSign = /-\d{4}$/.test(s)? -1 : 1;
}
min = hasOffset? +t[4] - offMin * offSign : (t[4] || 0);
// Return a date object based on UTC values
return new Date(Date.UTC(t[0], --t[1], t[2], t[3]||0, min, t[5]||0, ms));
}
An ISO 8601 date string should be treated as UTC (per ECMA-262), so if you are UTC-0500, then:
new Date('2014-04-07'); // 2014-04-06T19:00:00-0500
The behaviour described in the OP shows the host is not compliant with ECMA-262. Further encouragement to parse the string yourself. If you want the date to be treated as local, then:
// Expect string in ISO 8601 format
// Offset is ignored, Date is created as local time
function parseLocalISODate(s) {
s = s.split(/\D+/g);
return new Date(s[0], --s[1], s[2],0,0,0,0);
}
In your function you can do something like:
var ds = data.feed.entry[i].gd$when[j].startTime;
var startDate = ds.length == 10? parseLocalISODate(ds) : parseISOString(ds);
Also note that variables starting with a capital letter are, by convention, reserved for constructors, hence startDate, not StartDate.
(I would add a comment but i don't have 50 rep yet)
See what
new Date().getTimezoneOffset()
returns, I would expect a big negative value, that would be the only reasonable explanation to your problem.
I have had some trouble with date conversions in the past, in particular with daytime saving timezones, and as work around i always set the time explicitly to midday (12:00am). Since I think you were using knockout, you could just make a computed observable that appends a "T20:00:00.000-05:00" or the appropiate time zone to all "day only" dates
I was trying to convert date object into long format (may be in milliseconds format) as we do in java.
So to fulfill my need, after some trial and error, I found below way which works for me:
var date = new Date();
var longFormat = date*1; // dont know what it does internally
console.log(longFormat); // output was 1380625095292
To verify, I reverse it using new Date(longFormat); and it gave me correct output. In short I was able to fulfill my need some how, but I am still blank what multiplication does internally ? When I tried to multiply current date with digit 2, it gave me some date of year 2057 !! does anyone know, what exactly happening ?
The long format displays the number of ticks after 01.01.1970, so for now its about 43 years.
* operator forces argument to be cast to number, I suppose, Date object has such casting probably with getTime().
You double the number of milliseconds - you get 43 more years, hence the 2057 (or so) year.
What you are getting when you multiply, is ticks
Visit: How to convert JavaScript date object into ticks
Also, when you * 2 it, you get the double value of ticks, so the date is of future
var date = new Date()
var ticks = date.getTime()
ref: Javascript Date Ticks
getTime returns the number of milliseconds since January 1, 1970. So when you * 1 it, you might have got value of this milliseconds. When you * 2 it, those milliseconds are doubled, and you get date of 2057!!
Dates are internally stored as a timestamp, which is a long-object (more info on timestamps). This is why you can create Dates with new Date(long). If you try to multiply a Date with an integer, this is what happens:
var date = new Date();
var longFormat = date*1;
// date*1 => date.getTime() * 1
console.log(longFormat); // output is 1380.....
Javascript tries to find the easiest conversion from date to a format that can be multiplied with the factor 1, which is in this case the internal long format
Just use a date object methods.
Read the docs: JavaScript Date object
var miliseconds=yourDateObject.getMiliseconds();
If You want to get ticks:
var ticks = ((yourDateObject.getTime() * 10000) + 621355968000000000);
or
var ticks = someDate.getTime();
Javascript date objects are based on a UTC time value that is milliseconds since 1 January 1970. It just so happens that Java uses the same epoch but the time value is seconds.
To get the time value, the getTime method can be used, or a mathematic operation can be applied to the date object, e.g.
var d = new Date();
alert(d.getTime()); // shows time value
alert(+d); // shows time value
The Date constructor also accepts a time value as an argument to create a date object, so to copy a date object you can do:
var d2 = new Date(+d);
If you do:
var d3 = new Date(2 * d);
you are effectively creating a date that is (very roughly):
1970 + (2013 - 1970) * 2 = 2056
You could try the parsing functionality of the Date constructor, whose result you then can stringify:
>
new Date("04/06/13").toString()
"Sun Apr 06 1913 00:00:00 GMT+0200"
// or something
But the parsing is implementation-dependent, and there won't be many engines that interpret your odd DD/MM/YY format correctly. If you had used MM/DD/YYYY, it probably would be recognized everywhere.
Instead, you want to ensure how it is parsed, so have to do it yourself and feed the single parts into the constructor:
var parts = "04/06/13".split("/"),
date = new Date(+parts[2]+2000, parts[1]-1, +parts[0]);
console.log(date.toString()); // Tue Jun 04 2013 00:00:00 GMT+0200