Develop Reference

Trigger JS function on pageload when populating select box from database

I have the following js script that triggers onChange of the select box below.
It then retrieves data from a table and returns some input fields populated with the data (using PHP code below). Then saves the data.
This part works fine.
However, if I run the script again, and it populates the selected option from DB and shows as a selected option, but it does not display the populated input fields returned from the PHP code/DB query since I am not triggering the onChange again.
I tried to add 'window.onload = showAgentOne;' under the JS for the onChange function, assuming it would see the value in (str) from the select box, but I am probably missing something as it does not work.
New to JS - I hope this makes sense.
JS:
function showAgentOne(str) {
if (str == "") {
document.getElementById("agent1").innerHTML = "";
return;
}
if (window.XMLHttpRequest) {
xmlhttp = new XMLHttpRequest();
} else {
xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange = function() {
if (xmlhttp.readyState == 4 && xmlhttp.status == 200) {
document.getElementById("agent1").innerHTML = xmlhttp.responseText;
}
}
xmlhttp.open("GET", "user_agent1.php?q=" + str, true);
xmlhttp.send();
}
window.onload = showAgentOne; // trigger function on pageload - not working
HTML:
<select name="narid" onchange="showAgentOne(this.value)" class="form-control">
<option selected="selected" disabled value="">select agent</option>
<?php
$sql = "select last_name, first_name, active, nrds_id from ft_form_2 ORDER BY last_name";
$sql_result = mysqli_query($mysqli,$sql);
while ($row = mysqli_fetch_array($sql_result)) }?>
<option value="<?php echo $row[" nrds_id "]; ?>" <?php if($narid_agent1==$ row[ "nrds_id"]) { echo ' selected '; } ?> >
<?php echo strtoupper($row["last_name"]) . ' > ' . $row["first_name"] . ' ' . $row["last_name"] . ' ['.$active.']'; ?>
</option>
<? } ?>
</select>
<div id="agent1"></div>
PHP (user_agent1.php) ------------------------- $q=$_GET["q"]; $sql="SELECT pay_to_name,nrds_id FROM ft_form_2 WHERE nrds_id = $q"; $result = mysqli_query($mysqli,$sql); while($row = mysqli_fetch_array($result)) { ?>
<input type="text" name="narid_agent1" value="<?php echo $row['nrds_id']; ?>">
<input type="text" name="pay2_agent1" value="<?php echo $row['pay_to_name']; ?>">
<?php } ?>

'window.onload = showAgentOne;' is a good try but it is expecting a str param, otherwise it returns and do nothing. That's why nothing happens.
You will have to try something like
window.onload = function (event) {
let str = 'ADD_YOUR_VALUE_HERE';
showAgentOne(str);
}
But I can't help you with what str should be.

How to execute JavaScript in PHP file executed from Ajax

I posted this earlier but it incorrectly got marked as a duplicate of Can scripts be inserted with innerHTML?, which isn't my problem. I'm not trying to run any JavaScript through using innerHTML, I'm trying to run JavaScript that is located in a PHP file called through Ajax/XmlHttp. I am using innerHTML in that JS, but I'm not writing more JS within that. So it's not a duplicate of that question and I'm trying it again now.
Not sure what's going on here. I'll explain the organization of my files first and then get into the code.
The application- Allows the user to select different attributes (i.e. year or name) and view pictures of matching results from a database.
Files- I have a gallery.php file that has a series of HTML form elements acting as selectors to get filtered results from a database. Whenever a selector is set or changed, the file sends a new request to a get.php file that uses Ajax to refresh the results without loading a new page. All that works great. My next task is to implement a modal section where I can click on an image and view a bigger version which I plan to do with JavaScript and CSS, but my intermediate goal is to just change some text at the bottom of the results from get.php again using JavaScript, just as a first step. But I can't seem to get any JavaScript written in get.php to fire.
Code-
This is gallery.php:
<?php
include_once("./../php/navbar.php");
?>
<html>
<head>
<link href="/css/siteTheme.css" rel="stylesheet">
<style>
.attributes span {
margin-right: 1rem;
}
</style>
<script>
function changeParams() {
if (window.XMLHttpRequest) {
xmlhttp = new XMLHttpRequest();
} else {
xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange = function() {
if (this.readyState == 4 && this.status == 200) {
document.getElementById("test").innerHTML = this.responseText;
}
};
year = document.getElementById("years_select").value;
nameFirst= document.getElementById("nameFirst_select").value;
/* Ton of other getElementById statements here that I'm excluding to keep things shorter */
url = "get.php?year="+year+......;
xmlhttp.open("GET", url, true);
xmlhttp.send();
} /* End function */
</script>
</head>
<body>
<div class="content">
<h1>Gallery</h1>
<form>Details:
<!-- -------------------- Year -------------------- -->
<select onchange="changeParams()" name="years" id="years_select">
<option value="All">Year</option>
<?php
include("/var/www/admin.php");
$conn = mysqli_connect($dbServername, $publicdbUsername, $publicdbPass, $dbName);
if (!$conn) {
die('Could not connect: ' . mysqli_error($conn));
}
$sql = "select year from db group by year order by year desc";
$result = mysqli_query($conn, $sql);
while ($row = mysqli_fetch_array($result)) {
echo "<option value=" . $row['year'] . ">" . $row['year'] . "</option>";
}
mysqli_close($conn);
?>
</select>
<!-- A bunch of other selectors are created here following the same pattern as above of getting results from a DB -->
<!-- -------------------- Searchbar -------------------- -->
<input type="text" size="50" onkeyup="changeParams()" name="search" id="search" placeholder="Search"></input>
</form>
<div id="test">Choose some filters to see some results!</div>
</form>
</div> <!-- Ends content div -->
</body>
</html>
This is get.php:
<html>
<head>
<style>
/* Bunch of CSS that's not relevant here */
</style>
<script type="text/javascript">
console.log(".....");
var parts = document.querySelectorAll("div.imgContainer");
console.log("Found something:", parts);
parts.addEventListener("click", function(){
document.getElementById("anID").innerHTML = "Test...";
});
</script>
</head>
<body>
<?php
include("/var/www/admin.php");
$year = $_GET['year'];
//Bunch of other variables set here following the same logic, getting data from gallery.php
$conn = mysqli_connect($dbServername, $publicdbUsername, $publicdbPass, $dbName);
if (!$conn) {
die('Could not connect: ' . mysqli_error($conn));
echo '$conn';
}
$sql = 'select * db';
/* ---------- Creating SQL statement ---------- */
$clauses = 0;
if ($year != "All") {
if ($clauses == 0) {
$sql = $sql . ' where year = "' . $year . '" and';
$clauses = $clauses + 1;
} else {
$sql = $sql . ' year = "' . $year . '" and';
}
} /* Bunch of other if statements to get set information and add to sql statement as such */
// Need to chop of the last ' and' from the sql statement
$sql = substr($sql, 0, -4);
$sql = $sql . ' order by year desc';
$result = mysqli_query($conn, $sql);
$num_results = mysqli_num_rows($result);
if ($num_results == 0 or $clauses == 0) {
echo "<p>No matches to your query. Try refining your search terms to get some results.</p>";
} else {
echo "<p>" . $num_results . " results matched your query.</p>";
echo "<div class=results>";
//echo "<div>";
echo '<script type="text/javascript">
function modalFunction() {
document.getElementById("anID").innerHTML = "test";
}
</script>';
while ($row = mysqli_fetch_array($result)) {
$pic = $row['pathToPic'];
$wwwImg = substr($pic, 13);
//echo "<span id=aCard><img src=" . $wwwImg . " height ='250px'>";
//echo "<span class=text>" . $row['fullCardInfo'] . "</span></span>";
echo "<div class=fullContainer><div class='imgContainer'><img class=image src=" . $wwwImg ."></div><p class=text>" . $row['fullInfo'] . "</p></div>";
} // End while of results
echo "</div>";// End results div//</div>";
//echo '<div class="modal"><p id="anID"></p></div>';
} // End else of "if results"
mysqli_close($conn);
?>
<script>
</script>
<div>
<p id="anID">This in a div</p>
</div>
<!--<span>
<p id="anID">This in a span</p>
</span>-->
</body>
</html>
Sorry if that was messy, I chopped out a bunch of stuff that just gets/selects/filters some data. All that works and all variables that are left in there are set in my full code.
But the issue I'm having is writing JavaScript in get.php to change the text in the <p id="anID"> tags. I've tried JS in a few different areas of get.php, from in the <head> tags, to echoing it in <script> tags in the PHP, to pure <script> tags after the PHP statements are done (I think I left them in a few different places).
Problem is that nothing I do works to change the text in the <p> tags I references. Additionally, the console.log statements in the header of get.php don't seem to get called either. They don't fire no matter where I place them in get.php. Console.log works fine in gallery.php so it's not some issue with my browser or anything.
Long term, I will be adding JS query selectors to bring up a bigger image when an image is clicked on, but for now I'm just trying to make ANY JavaScript work in get.php and I'm struggling to do so. I don't see how this is a duplicate of the suggested repeat as I'm not trying to run JavaScript through innerHTML here.

Scratch that, it actually is trying to pass JavaScript through innerHTML as the information from get.php comes from this section of gallery.php:
xmlhttp.onreadystatechange = function() {
if (this.readyState == 4 && this.status == 200) {
document.getElementById("test").innerHTML = this.responseText;
console.log("Response: ", this.responseText);
}
So it appears this is a duplicate of the question I linked after all. Apologies. However, there are not great answers to that question, so any tips would be appreciated.

This line:
document.getElementById("test").innerHTML = this.responseText;
Is simply going to add the contents of this.responseText to the element test. I'm sure you understand that much, but what you want to do is completely wrong. The scripts within the output of get.php will NOT be executed at all and you have corrupted your HTML as well by including a second <html><head> and more.
A better approach would be if get.php returned the data from you DB query as a JSON string like so:
$data;
while ($row = mysqli_fetch_array($result)) {
$data[]['pic'] = $row['pathToPic'];
$data[]['wwwImg'] = substr($row['pathToPic'], 13);
}
echo json_encode($data);
exit;
And then back on gallery.php you do something like:
if (this.readyState == 4 && this.status == 200) {
formatResult(this.responseText);
}
// ... snip ...
function confirmJson(str) {
var j = null;
if (str) {
try { j = JSON.parse(str); }
catch (e) { j = null; }
}
return j;
}
function formatResult(str) {
var data = confirmJson(str);
if (! data) {
console.log("result is not JSON");
return;
}
// do stuff with the data
var i, max = data.length;
var h = document.createElement("div");
var img;
for(i=0;i<max;i++) {
img = document.createElement("src");
img.src = data[i].wwwImg;
img.addEventListener("click",function(){ alert("pic:["+ data[i].pic +"]"); },true);
h.appendChild(img);
}
document.getElementById("test").innerHTML = h;
}

ajax calling php loop with form not working on first loop only

I have a page called events.php that lists past and upcoming events, using ajax to call on pastevents.php and upcomingevents.php, which both have forms that collect users' opinions on past events and whether they will attend future events; then a handle sends it to psql db.
Everything works except the first iteration of the looped form does not submit correctly. Instead of continuing onto pastevents-handle.php, it doesn't post and returns a get on events.php; so I see the user's response in the url bar, but it never gets to the db. I made a test page that didn't use ajax by copy-pasting all the code and that works, so it's definitely something to do with ajax, but neither me or my professor could find out what.
I don't know how to use jquery yet, so please answer with plain javascript.
Here's events.php:
<script>
//show past events
function showPastEvents(str) {
document.getElementById('pastevents').style.display = "block";
document.getElementById('hideoldbutton').style.display = "block";
var xhttp;
if (str == "") {
document.getElementById("pastevents").innerHTML = "";
return;
}
xhttp = new XMLHttpRequest();
xhttp.onreadystatechange = function() {
if (this.readyState == 4 && this.status == 200) {
document.getElementById("pastevents").innerHTML = this.responseText;
}
};
xhttp.open("POST", "pastevents.php?q="+str, true);
xhttp.send();
}
function hidePastEvents() {
document.getElementById('pastevents').style.display = "none";
document.getElementById('hideoldbutton').style.display = "none";
}
//show upcoming events
function showUpcomingEvents(str) {
document.getElementById('upcomingevents').style.display = "block";
document.getElementById('hidenewbutton').style.display = "block";
var xhttp;
if (str == "") {
document.getElementById("upcomingevents").innerHTML = "";
return;
}
xhttp = new XMLHttpRequest();
xhttp.onreadystatechange = function() {
if (this.readyState == 4 && this.status == 200) {
document.getElementById("upcomingevents").innerHTML = this.responseText;
}
};
xhttp.open("POST", "upcomingevents.php?q="+str, true);
xhttp.send();
}
function hideUpcomingEvents() {
document.getElementById('upcomingevents').style.display = "none";
document.getElementById('hidenewbutton').style.display = "none";
}
</script>
<!-- page content -->
<div class="content">
<h6>Past events</h6>
<form name="postpastevents" action=""/>
<div id="pastevents"></div>
<input type="button" onClick="hidePastEvents()" id="hideoldbutton" value="Hide" style="display:none;"/>
</form>
<input type="button" onClick="showPastEvents()" id="showoldbutton" value="Show past"/>
<br>
<br>
<!-- ####### -->
<h6>Upcoming events</h6>
<form name="postupcomingevents" action=""/>
<div id="upcomingevents"></div>
<input type="button" onClick="hideUpcomingEvents()" id="hidenewbutton" value="Hide" style="display:none;"/>
</form>
<input type="button" onClick="showUpcomingEvents()" id="shownewbutton" value="Show upcoming"/>
Here is pastevents.php (it's the same code for upcomingevents.php):
<?php
$conn = pg_connect ('dbname=xxxx') or die ('Connect failed ');
$query = "SELECT eventname, eventdate, location, eventdesc FROM events WHERE eventdate < current_date ORDER BY eventdate;";
$result = pg_query($query);
while ( $row = pg_fetch_assoc($result) ) {
$i = 0;
echo "<tr>"; //table row
foreach ($row as $key => $value) {
if ($i == 0) {
$eventname = $value;
}
if ($i == 1) {
$eventdate = $value;
}
$eventinfo = $value;
echo "<td>"; //1 column each loop
echo "$eventinfo";
if ($i == 1) {
echo date(" (l, F jS)", strtotime($eventdate));
}
echo "<br><br>";
echo "</td>";
$i++;
}
echo "<td>";//1 column while same event
?>
<div>
<form name="pasteventsurvey" action="pastevent-handle.php" method="post">
What did you think of the event?
<select name="pasteventopinion">
<option value="">(Choose one)</option>
<option value="good">Loved it!</option>
<option value="okay">Liked it</option>
<option value="bad">Needs improvement</option>
<option value="time">Time conflict</option>
<option value="NA">NA</option>
</select>
<input type="hidden" name="eventname" value="<?php echo $eventname; ?>">
<input type="submit" name="enter" value="Submit"><input type="reset" name="erase" value="Clear">
</form>
</div>
<?php
echo "</td>";
echo "</tr>"; //-table row
}
pg_close($conn);
?>
Here's pastevents-handle.php:
<?php
$conn = pg_connect ('dbname=xxxx') or die ('Connect failed ');
pg_query_params("INSERT INTO eventsurveypast(eventname, opinion) VALUES ($1, $2)", array($name, $opinion));
echo "email is $idkey, eventname is $name, pastopinion is $opinion";
pg_close($conn);
?>
(I edited a bit for space, ignore anything that isn't vital)

It is illegal to have a form inside another form.
Remove the outer form and everything should work fine, except you have another problem with the code.

Using AJAX, PHP and MySQL to display table data

I would like to display one column of data, [pin], based on the [plan] and [order_id] values. plan=9 and order_id=0. Would like to load data without reloading page, using ajax.
Here is my HTML/Script:
<script>
function showPins(str) {
if (str == "") {
document.getElementById("txtHint").innerHTML = "";
return;
} else {
if (window.XMLHttpRequest) {
// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp = new XMLHttpRequest();
} else {
// code for IE6, IE5
xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange = function() {
if (xmlhttp.readyState == 4 && xmlhttp.status == 200) {
document.getElementById("txtHint").innerHTML = xmlhttp.responseText;
}
}
xmlhttp.open("GET","getPins.php?q="+str,true);
xmlhttp.send();
}
}
</script>
HTML:
<div align="center">
<h3>View PIN's</h3>
<form>
<select name="users" onchange="showPins(this.value)">
<option value="">Select Plan Type:</option>
<option value="1">Plan1</option>
<option value="2">Plan2</option>
<option value="3">Plan3</option>
</select>
</form>
<br/>
<div id="txtHint"></div>
</div>
This is my PHP file (getPins.php):
<?php
$q = intval($_GET['q']);
$con = mysqli_connect('myHost','myUsername','myPw','my_db');
if (!$con) {
die('Could not connect: ' . mysqli_error($con));
}
mysqli_select_db($con,"my_db");
$sql="SELECT * FROM attPins WHERE (order_id=0, plan=9 and id = '".$q."')";
$result = mysqli_query($con,$sql);
echo "<table>
<tr>
<th>PIN's</th>
</tr>";
while($row = mysqli_fetch_array($result)) {
echo "<tr>";
echo "<td>" . $row['pin'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysqli_close($con);
This is based off the tutorial shown here: http://www.w3schools.com/php/php_ajax_database.asp
Trying to make it work for showing the correct pins for plan type chosen.

your query would be wrong read manual where
$sql="SELECT * FROM attPins WHERE (order_id=0, plan=9 and id = '".$q."')";
It would be
WHERE (order_id=0 and plan=9 and id = '".$q."')
Or
WHERE (order_id=0 OR plan=9 and id = '".$q."')
according to your requirment

Redirection in an ajax called page

I have read quite a bit and I still am missing something.
I have a page that has a button on it. When you click the button it will call an AJAX function that will then wait and refresh every 5 seconds in waiting for a MySQL database change. Once the change in the database is made, I would like to take the user to a new page all together.
I have tested the refreshing for the database changes and they work great with echos. I have tried to use windows.location and the php header redirect. Neither are working.
I am not using jquery for the ajax call. Any help would be greatly appreciated.
Thank you
code:
index.php
<?php
session_start();
$_SESSION = array(
'player' => 0
);
?>
<!DOCTYPE HTML>
<html>
<head>
<script src="ajax.js"></script>
<title></title>
</head>
<body>
<div id="join"><button type="button" onclick="startGame()">Throwdown!</button></div>
</body>
</html>
rpsjoin.php
<?php
include("db.php");
session_start();
$lastId_q = mysqli_fetch_assoc(mysqli_query($con,'SELECT MAX(id) AS id from game'));
$lastId = $lastId_q['id'];
$gameStatus_q = mysqli_fetch_assoc(mysqli_query($con,'SELECT game.game_status FROM game WHERE game.id =' . $lastId));
$gameStatus = $gameStatus_q['game_status'];
if ($gameStatus == 2) {
mysqli_query($con, "INSERT INTO game (game_status, player1_joined) VALUES(1,1)");
$_SESSION['player'] = '1';
$playerNumber = $_SESSION['player'];
$lastId_q = mysqli_fetch_assoc(mysqli_query($con,'SELECT MAX(id) AS id from game'));
$lastId = $lastId_q['id'];
$_SESSION['lastId'] = $lastId;
} elseif ($gameStatus == 1 && $_SESSION['player'] != 1) {
mysqli_query($con, "UPDATE game SET player2_joined = 1 WHERE id = " . $lastId);
$_SESSION['player'] = '2';
$playerNumber = $_SESSION['player'];
$_SESSION['lastId'] = $lastId;
}
$player1_join_q = mysqli_fetch_assoc(mysqli_query($con,'SELECT player1_joined FROM game WHERE game.id =' . $lastId));
$player2_join_q = mysqli_fetch_assoc(mysqli_query($con,'SELECT player2_joined FROM game WHERE game.id =' . $lastId));
$player1_join = $player1_join_q['player1_joined'];
$player2_join = $player2_join_q['player2_joined'];
echo $lastId . "<BR>";
echo $gameStatus . "<BR>";
echo $player1_join . "<BR>";
echo $player2_join . "<BR>";
if ($player1_join == 1 && $player1_join == $player2_join) {
echo '<form action="rpsover.php" method="post">
<button type="submit" name="player" value="1">Rock</button>
<button type="submit" name="player" value="2">Paper</button>
<button type="submit" name="player" value="3">Scissors</button>
</form>';
} else {
echo "Locating player. Please be patient";
}
echo session_id();
?>
function startGame() {
if (window.XMLHttpRequest) {
// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp=new XMLHttpRequest();
} else { // code for IE6, IE5
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange=function() {
if (xmlhttp.readyState==4 && xmlhttp.status==200) {
document.getElementById("join").innerHTML=xmlhttp.responseText;
setTimeout('startGame()',1000);
}
}
xmlhttp.open("GET","rpsjoin.php",true);
xmlhttp.send();
}
At the end of rpsjoin.php, instead of showing a form, i want to be redirected to another page.
Yes I know my code is bad and there are test echos in it.
Thank you