Develop Reference

how to truncate output values in Nerdamer

I am using nerdamer.solve to solve roots but the roots are long and not truncated. I wanted to get truncated values upto 4 decimal places. How can I achieve this?
I am using the following code to solve and display output in html:
var r = nerdamer.solve(`1 - ${a} * x^(${p}) + ${b}`, 'x');
document.getElementById("polesAns").innerHTML= r.toString();
The folllowing is output:
[(138655807/135201312)*i+49385501/48155102,(-138655807/135201312)*i+49385501/48155102,(58886197/57419096)*i-49385501/48155102,(-58886197/57419096)*i-49385501/48155102,-560373381/386371730,172668482/119053157,(145619303/100403024)*i-5753750945848186/10000000000000000000000000000000,(-560373381/386371730)*i-5753750945848186/10000000000000000000000000000000]
There is no division performed also.
I tried the solution posted here:
How to use .toFixed() (or any alternative) on Nerdamer.solve solutions?
But how can I do this with my code? I tried the following:
var value = `1 - ${a} * x^(${p}) + ${b}`;
var toFixed = function(value, n) {
var img = Number(nerdamer.imagpart(value).text()).toFixed(n);
var real = Number(nerdamer.realpart(value).text()).toFixed(n);
// Format the number assuming i denotes imaginary in your case
var formatted = '';
if(real !== '0.0000') {
formatted += real;
}
if(img !== '0.0000') {
// Put the plus sign betweent the real and imaginary
if(img.charAt(0) !== '-' && formatted) {
formatted += '+';
}
// Assuming you're using i and not j for instance
formatted += img+'i';
}
return formatted;
};
sol_raw = this.nerdamer.solve(value,'s');
xs = this.nerdamer(sol_raw.toString()).each(function(solution) {
roundedSolutions.push(toFixed(solution, 4));
});
this.setState({
solution: roundedSolution.join(''),
equation:value})
document.getElementById("polesAns").value = solution.toString();
I don't understand the this.setState() part , should i declare sol_raw and xs as var?
Also the substitution of variable is used in the my above root equation from advice here javascript Solving equation with subsitution of variable value
thank you

How do I mask an email address between the first and the last character before the # sign?

My goal is to edit the string (which has an email) to mask the first part, like say the email is johndoe#abc.com then I should output j*****e#abc.com.
var maskPII = function(S) {
var ans = "";
if(S.includes("#")){
S = S.toLowerCase();
var parts = S.split("#");
var first = parts[0];
for(var i=0;i<parts[0].length;i++){
if(i!=0 && i!=parts[0].length - 1)
first[i] = '*';
}
ans = first +"#" +parts[1];
}else{
}
return ans;
};
However in my loop I can't change the characters to asterisks.
After execution I see value of first still same as parts[0] and has no asterisks, can some one explain why? Also, what would I need to do to modify the variable inside loop?

To answer your question... javascript allows you access values of a string using [] indexing.. but that is read only access... you cannot insert/replace values using that operator.
Ref: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String
When using bracket notation for character access,
attempting to delete or assign a value to these properties will not succeed.
The properties involved are neither writable nor configurable.
(See Object.defineProperty() for more information.)
You need to extract the values you want to keep from the existing string and build up a new string as noted in other answers...

Well, this's what you're looking for, and this will be the output j*****e#abc.com.
var ans = "";
var S = "johndoe#abc.com"; //example
S = S.toLowerCase();
var parts = S.split("#");
var first = "";
for(var i = 0; i < parts[0].length; i++){
if(i != 0 && i != parts[0].length - 1){
first += '*';
}else{
first += parts[0][i];
}
}
ans = first +"#"+ parts[1];
console.log(ans);

Here is the code with your approach:
var maskPII = function(S) {
var ans = "";
if(S.includes("#")){
S = S.toLowerCase();
var parts = S.split("#");
var first = parts[0][0];
for(var i=0;i<parts[0].length;i++){
if(i!=0 && i!=parts[0].length - 1)
first += '*';
}
ans = first + parts[0][parts[0].length - 1] +"#" +parts[1];
}else{
}
return ans;
};
But if i were you i would use:
var mail = "johndoe#abc.com";
mail = mail.replace(/(?<=.)(.+?)(?=.#)/gi, '*'.repeat(mail.split('#')[0].length - 2));
console.log(mail);

You can use the bracket notation on a string (like an array) to get the character at a specific index, but you can't use this to change characters. So first[i] = '*' in your code wont do anything.
Strings in JavaScript are immutable. This means that if you want to change a string, a new string instance will be created. This also means that when you change a string in a for-loop, it can impact performance. (Although in this case the difference wont be noticeable.
)
I would use this code:
function maskPII(str) {
const indexOfAt = str.indexOf('#');
if (indexOfAt <= 2) {
return str;
}
return str[0] + '*'.repeat(indexOfAt - 2) + str.substring(indexOfAt - 1);
}
const email = 'johndoe#abc.com';
console.log(email);
console.log(maskPII(email));
It will look for the index of the # sign. If the index is less or equal than 2, (when not found the index will be -1) it will return the original string.
Otherwise it will get the first character, calculate the amount of asterisks needed (index of the # sign -2) and repeat those and then add the rest of the original string.

Calculating 2 values from fields but it's not working properly

I am calculating 2 fields on a form with values but it seems in some cases it's not working. Here's my javascript. I am adding $oneTimeCostField and $recurringTotalCostField to get the value into the $totalRetailAmountField. Here's the result I am getting when I add say 1,555.00 + 566.00 = the value is 567.00 (?). Any idea what I'm doing wrong? In some cases it works correctly when the values are lower. Thanks, just stumped
var $recurringCostField = $('#am_attribute_campaign_addon_monthly_cost_value');
var $recurringTotalCostField = $('#am_attribute_campaign_addon_total_monthly_cost_value');
var $totalRetailAmountField = $('#am_oie_string_total_monthly_cost_value');
var $oneTimeCostField = $('#am_attribute_campaign_addon_one_time_cost_value');
function calcVal() {
var num1 = $oneTimeCostField.val();
var num2 = $recurringTotalCostField.val();
var result = parseFloat(num1) + parseFloat(num2);
if (!isNaN(result)) {
$totalRetailAmountField.val(result.toFixed(2));
}
}
calcVal();
$oneTimeCostField.on("keydown keyup", function() {
calcVal();
});
$recurringTotalCostField.on("keydown keyup", function() {
calcVal();
});

You need to remove the commas before parsing:
var result = parseFloat(num1.replace(/,/g, '')) + parseFloat(num2.replace(/,/g, ''));
similiar question on this link
Remove commas from the string using JavaScript

That is because parseFloat() converts the string "1,555.00" to the number 1.
To convert it to a proper floating point number, it needs to include a single dot only.
console.log(parseFloat("1.555"));

Similar function in JavaScript to convert string/number

I have a function in PHP that gets a number inserted into a text input and converts it to a float, with comma separator for decimals.
After that, the number is registered in the database.
Now, I need to make something with JavaScript (or jQuery), that does the same kind of convertion.
$num = $_POST['precoItem'];//get the input value
$precoAd = tofloat($num);//convert it to float
$precoFinal = number_format($precoAd, 2, ',', '');//remove any 'dots' or 'spaces'
The PHP function toFloat() is this one:
function tofloat($num) {
$dotPos = strrpos($num, '.');
$commaPos = strrpos($num, ',');
$sep = (($dotPos > $commaPos) && $dotPos) ? $dotPos :
((($commaPos > $dotPos) && $commaPos) ? $commaPos : false);
if (!$sep) {
return floatval(preg_replace("/[^0-9]/", "", $num));
}
return floatval(
preg_replace("/[^0-9]/", "", substr($num, 0, $sep)) . ',' .
preg_replace("/[^0-9]/", "", substr($num, $sep+1, strlen($num)))
);
}
For example, the final number will not have dots or spaces, only commas: Ex.: 45354,85 (45.354,85)
My JS knowledge is limited. I tried using things like:
var n = +$precoFinal;
var n = Number($precoFinal);
var n = parseFloat($precoFinal);
Why people like to downvote so much... Are you really gonna say that my question didn't had any research? Rly?

Try this:
var str = '45.354,85';
var num = str.split(/[\s.]+/).join('');
num = parseFloat(num.replace(",","."));
console.log(num);

How to add and multiply text boxes together in google apps script?

How do I add the following text boxes together with the logic below?
oneTextBox = $120.00,
twoTextBox = .03*oneTextBox,
threeTextBox = oneTextBox + twoTextBox
I would also like the units of each text box to be in dollars ($).
function doGet(e) {
var app = UiApp.createApplication();
var VertPanel = app.createVerticalPanel().setId('VertPanel');
var oneTextBox = app.createTextBox().setText("$120.00").setId("oneTextBox").setName("oneTextBox");
var twoTextBox = app.createTextBox().setId("twoTextBox").setName("twoTextBox");
var threeTextBox = app.createTextBox().setId("threeTextBox").setName("threeTextBox");
app.add(VertPanel);
VertPanel.add(oneTextBox).add(twoTextBox).add(threeTextBox);
return app;
}

The value returned by e.parameter.oneTextBox in the handler function is a string, in your example it should be "$120.00," and what you want is a numeric value... what I'd suggest is to use a replace() to remove all non numeric characters and convert that to a number like this :
var oneTextBoxNumValue = Number(e.parameter.oneTextBox.replace(/[^0-9]/g,''));// the regex ^0-9 takes everything not between 0 and 9 (and replace by '')
Using the same process on other textBoxes you can do everything you want with math operations after this conversion.
To get the results in $, simply add a '$' to your result
getElementById('oneTextBox').setText(resultNumeric+"$")
the only tricky thing is the decimal point, you'll need to take this into account in your conversion : $120.00, will become 12000 in numeric value so don't forget to divide the result somewhere or your stuff will become very expensive ! ;-)
Also I've had some rounding errors sometimes but it's always possible to handle quite easily, for example in a similar case I had to use something like this to get the correct result : (2.00 instead of 1.99 if quant = 2 in the example below, note that I divide the integer by 100 to get value with 2 decimals)
var total = parseInt(Number(quant)*valtotal*100+0.01)/100;
Hoping it will give some ideas to start with.
EDIT : here is a small code to illustrate :
function calcTest() {
var app = UiApp.createApplication().setTitle('TextField Calculator');
var button = app.createButton('Calculate');
var handler = app.createServerHandler('calc');
button.addClickHandler(handler);
var grid = app.createGrid(5, 2);
grid.setText(0, 0, 'value1 ');
grid.setWidget(0, 1, app.createTextBox().setName('value1').setText('$ 45.00/unit'));
grid.setText(1, 0, 'value2');
grid.setWidget(1, 1, app.createTextBox().setName('value2').setText('3 units'));
grid.setText(2, 0, 'press button to calculate');
grid.setWidget(2, 1, button);
grid.setText(3, 0, 'value3 = value1*1.35');
grid.setWidget(3, 1, app.createTextBox().setId('value3').setEnabled(false));
grid.setText(4, 0,'sum value1 + value2 + value3');
grid.setWidget(4, 1, app.createTextBox().setId('sum').setEnabled(false));
handler.addCallbackElement(grid);
app.add(grid);
var ss = SpreadsheetApp.getActive();
ss.show(app);
}
function calc(e){
var app = UiApp.getActiveApplication();
var value1 = Number(e.parameter.value1.replace(/[^0-9]/g,''))/100;
var value2 = Number(e.parameter.value2.replace(/[^0-9]/g,''));
var calcvalue = parseInt(value1*1.35*100)/100
var sumcalc = calcvalue+value1+value2
app.getElementById('value3').setText('$ '+calcvalue)
app.getElementById('sum').setText(sumcalc+' without unit;)')
return app
}
EDIT 2 : here is another code, a function that I use in an application to convert string values to Euros, it is slightly different in its approach but works pretty well.
function toEuro(val){
if(val==''){temp='';return temp}
var temp = val.toString().replace(/[^\d\.-]/g,'').split('.');
if(temp[0]==''){temp[0]='0'}
if(temp.length==1){var result = temp[0]+',00 €'}
else{
var int = temp[0]
var dec = temp[1]
if(dec.length==1){var result=int+','+dec+'0 €'}else{var result=int+','+dec+' €'}
}
return result
}