Develop Reference

NetSuite - excluding weekends from date calculation

My scheduled script sets a field to store an accrued late fee charge for each day an invoice is overdue. I am comparing the current system time against due date to work out the number of days overdue. However, I didn't take into consideration to exclude the weekend. How can I use my existing code to do this?
var current_date = nlapiStringToDate(nlapiDateToString(new Date()));
var dd = invoice.getFieldValue('duedate');
var due_date = nlapiStringToDate(dd);
if (due_date < current_date) {
//Other Calculations
var days_overdue = DateOverdue(current_date, due_date);
}
function DateOverdue(current_date, due_date) {
var time_difference = Math.abs(due_date.getTime() - current_date.getTime());
var no_days_overdue_by = Math.ceil(time_difference / (1000 * 3600 * 24));
return no_days_overdue_by;
}

The following works. Note the extra dates are to clear issues from comparing time stamps without hours, minutes and seconds. Not strictly needed for the current_date given how you are generating it but it makes a more general function.
NOTE: I don't believe you should be able to compare dates with d1 < d2.
function daysOverdue(currentDate, dueDate){
var days = 0;
var due = new Date(dueDate.getFullYear(), dueDate.getMonth(), dueDate.getDate(), 0, 0, 0);
var fromTS = new Date(currentDate.getFullYear(), currentDate.getMonth(), currentDate.getDate(), 0, 0, 0).getTime();
if(due.getTime() >= fromTS) return 0; // not overdue
while(due.getTime() < fromTS){
if(due.getDay() !== 0 && due.getDay() != 6) days++;
due.setDate(due.getDate() + 1);
}
return days;
}

how to find difference in days between day and month irrespective of years

I want to know the difference between to two dates irrespective of year..
For Example : format date/month/year
For example difference of today date to some date lets take 01/06
The expected answer for this will be around 185 days..
I tried below example..Let me know whats wrong with this
var a = moment('06/01','M/D');
console.log(a);
var b = moment();
console.log(b);
var diffDays = b.diff(a, 'days');
alert(diffDays);
I dont want to use momet.js atmost. If it can be done with javascript its so good for me.

A nice trick could be to set the year to always the same.
var a = moment('2015/06/01','Y/M/D');
console.log(a);
var b = moment().set('year', 2015);
console.log(b);
var diffDays = b.diff(a, 'days');
alert(diffDays);
The problem about your question in general is how to deal with leap years; how the script should know the difference between 2/20 and 3/1 ? You have to consider how to solve this.

Barth Zaleweski is 100% on track with that. If you want to use straight javascript:
var today = new Date();
var otherDate = new Date(today);
otherDate.setMonth(5); // Set the month (on scale from 0 to 11)
otherDate.setDate(1); // set day
var seconds = (otherDate.getTime() - today.getTime()) / 1000;
var minutes = seconds / 60;
var hours = minutes / 60;
var days = hours / 24;
console.log(days);
There are methods for setting hour/minute/second as well, but if you don't do anything they'll be the same as the start, and you can obviously call those same methods on your start time if you don't want to use today.

Can try using this:
var str1 = '06/01', str2 = '02/28', d1, d2, diff;
function setDate(str, date) {
var date = new Date(),
dateParts = str.split('/'),
monthIndex = parseInt(dateParts[0], 10) - 1,
day = parseInt(dateParts[1], 10);
date.setMonth(monthIndex);
date.setDate(day);
return date
}
d1 = setDate(str1);
d2 = setDate(str2);
diff = Math.round(Math.abs((d1 - d2) / (24 * 60 * 60 * 1000)))
console.log(diff) // returns 93
The rounding is due to differences in daylight savings (or other locale time shifts within the year) that can cause decimal values returned.
It is probably better to use UTC for this
If current year is leap year and dates span end of February then Feb 29 would also be counted
DEMO

If it is this year then I am getting a difference of 147 using a library that I have been working on (AstroDate) which doesn't rely on javascript's Date object, it's all done with pure math.
require.config({
paths: {
'astrodate': '//rawgit.com/Xotic750/astrodate/master/lib/astrodate'
}
});
require(['astrodate'], function (AstroDate) {
"use strict";
var diff = new AstroDate("2015","6","1").jd() - new AstroDate("2015","1","5").jd();
document.body.appendChild(document.createTextNode(diff));
});
<script src="http://requirejs.org/docs/release/2.1.8/minified/require.js"></script>
If it was next year, which is a leap year then I am getting 148
require.config({
paths: {
'astrodate': '//rawgit.com/Xotic750/astrodate/master/lib/astrodate'
}
});
require(['astrodate'], function (AstroDate) {
"use strict";
var diff = new AstroDate("2016", "6", "1").jd() - new AstroDate("2016", "1", "5").jd();
document.body.appendChild(document.createTextNode(diff));
});
<script src="http://requirejs.org/docs/release/2.1.8/minified/require.js"></script>

How to subtract a date via Datepicker?

I have an add date and I need to know how many days ago this record was added, so today - adddate. This is in mm/dd/yyyy format (10/16/2014) and I wanted to know if there is an easy way to get the difference without adding a new plugin. Thanks!
var today = $.datepicker.formatDate('mm/dd/yy', new Date());
var adddate = $('#adddate').val();
alert(today - adddate);

Assuming both values are inside inputs, this works.
var d1 = $('#adddate').datepicker('getDate');
var d2 = $('#today').datepicker('getDate');
var diff = 0;
if (d1 && d2) {
diff = Math.floor((d2.getTime() - d1.getTime()) / 86400000); // ms per day
}
alert(diff)

check if "current time" is between 2 times. But also check for nights as the day before

I have 2 times for example: 10:00 and 1:00 now i want to check if current time... is between these 2 times in javascript.
The problem is that the closing time in this case is a next day so its before the openingstime. How can i do this the proper way for some reason i can not get around this.
i hav efound that this could solve it:
var start = new Date(2012,6,20,13).getTime();
var now = new Date().getTime();
var end = new Date(2012,6,21,2).getTime();
if( (start < now ) && (now < end )) {
console.log("opened");
}
else {
console.log("closed");
}
but how can i do it with 2 string formats like 10:00 and 2:00 because i do not see a option to put a time alone
var d = new Date();
var d = new Date(milliseconds);
var d = new Date(dateString);
var d = new Date(year, month, day, hours, minutes, seconds, milliseconds);

You could use a simple function like this to convert your time to a number of minutes since 0:00:
function getMinutes(str) {
var time = str.split(':');
return time[0]*60+time[1]*1;
}
And a similar function to get the current time into the same form in order to compare:
function getMinutesNow() {
var timeNow = new Date();
return timeNow.getHours()*60+timeNow.getMinutes();
}
Then convert both opening and closing time and, if it happens that closing time is before opening time, add 24 hours to it.
var now = getMinutesNow();
var start = getMinutes('10:00');
var end = getMinutes('2:00');
if (start > end) end += getMinutes('24:00');
if ((now > start) && (now < end)) { // your code here

This is the solution I've gotten to after a bit of fiddling. At the current time of 3:24 am, it outputs the correct information. changing the now array to be [13,00] also gave the correct result of 'closed' Give it a test run through to make sure it works correctly.
Edit
jQuery included solely because I am brain dead.
Edit#2
I noticed now (9pm my time) that my conversion wasn't working, it was saying 'closed', when it shouldn't have. So far, this works for any and all numbers I've put in it to test.
var start_time = [20,00]
var end_time = [12,00]
//We've got the two start times as an array of hours/minutes values.
var dateObj = new Date(); //I just feel dirty making multiple calls to new Date().etc
var now = [dateObj.getHours(),dateObj.getMinutes()]; //Gets the current Hours/Minutes
if(end_time[0] < start_time[0] && now[0] < start_time[0]){
start_time[0] -= 24; //This is something I came up with because I do a lot of math.
}else if(start_time[0] > end_time[0]){
end_time[0]+=24;
}
var el=$('#result');
var start_string = to_hms_string(start_time); //the start string converted to a string format. Made comparisons easier.
var end_string = to_hms_string(end_time); //See Above
var now_string = to_hms_string(now); //Above
console.log(start_string, now_string, end_string);
var status = (start_string < now_string && now_string < end_string) ? "Open" : "Closed";
el.html(status);
//Function to_hms_string stands for "hour-minute-second" string. First name that came up.
function to_hms_string(timearr){
var minutes = 60+timearr[1];
var hours = "";
if(Math.abs(timearr[0]) < 10){
hours = "0";
}
hours = (timearr[0]<0) ? "-"+hours+Math.abs(timearr[0]) : hours+timearr[0];
return hours+":"+minutes;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="result">
PlaceHolder
</div>

You can do this, get current time. Then define you start time and end time based on the current time getting the year, month, date for tomorrow's date add 1 to the start's date see code below. Then you can compare the time the same fi condition you have. Good luck
var now = new Date();
var start = new Date(now.getFullYear(),now.getMonth(),now.getDate(),7).getTime();
var end = new Date(now.getFullYear(),now.getMonth(),now.getDate() + 1,2).getTime();
now = now.getTime();
if( now >= start && now < end) {
console.log("opened");
}
else {
console.log("closed");
}
***EDIT**
You can convert the current time to millis after you get the year, month and date. Then use your current if condition.

Jhecht This thing right here:
if(end_time[0] < start_time[0] && now[0] < start_time[0]){
start_time[0] -= 24;
}else if(start_time[0] > end_time[0]){
end_time[0]+=24;
}
it's brilliant. It works and this is the correct answer. Great job!

How do I change a picture during the weekends with javascript?

I want to show on our site when the chat is available. The problem is that it won't be open in the weekends. How do I exclude them? Can it be done?
<html>
<body>
<script type="text/javascript">
function chatonoff(){
var now = new Date();
var hour = now.getHours();
if (hour >=9 && hour <=18)
{
document.getElementById("chat").src = "/bilder/butik/chat-open.png";
}
}
</script>
<img id="chat" src="/bilder/butik/chat.png" onload="chatonoff()">
</body>
</html>

You could do like this
function chatonoff(){
var now = new Date();
var hour = now.getHours();
var day = now.getDay();
//Check if weekend : in this case, I assume that saturday == 6 and Sunday = 0
//It depends on your location / timezone
if(day != 6 && day != 0)
{
if (hour >=9 && hour <=18)
{
document.getElementById("chat").src = "/bilder/butik/chat-open.png";
}
}
}
EDIT
About excluding hollidays :
You should create an array with all the off dates. Then, check if the curent day is present in the array
var offDaysListArray = ['2013-01-01','2013-01-02'];
var now = new Date();
var y = now .getFullYear();
var d = (now .getDate() < 10) ? '0'+now .getDate() : now .getDate();
var m = ((now .getMonth()+1) < 10) ? '0'+(now .getMonth()+1) : (now .getMonth()+1);
//Check if it is a closed day
if(offDaysListArray.indexOf(y + '-' + m + '-' + d) != -1)
return false; //It is a close day
Be carefull with indexOf, old browser like IE8 doesn't implement this function. Check Why doesn't indexOf work on an array IE8?

This is a very simple answer, although it won't exactly work as you want it to as JavaScript is run on the client side.
This means that someone on the other side of the world will be able to see your chat on HIS FRIDAY even though it is a SATURDAY for YOU (A Sunday/Monday example also works here). Ideally you would solve this by using some server side language such as Java / .NET / PHP or whatever you are using.
Here is your quick JavaScript fix:
<html>
<body>
<script type="text/javascript">
function chatonoff(){
var now = new Date();
var hour = now.getHours();
var day = now.getDay();
if (hour >=9 && hour <=18 && day >= 1 && day <= 5)
{
document.getElementById("chat").src = "/bilder/butik/chat-open.png";
}
}
</script>
<img id="chat" src="/bilder/butik/chat.png" onload="chatonoff()">
</body>
</html>